Please help.
Graph RST with vertices R(4,1), S(7,3), and T(6, 4) and its image after the glide reflection.
Translation: (x,y) →(x, y-1)
Reflection: in the y -axis.
Answer:
Points R(4,1) S(7,3) T(6,4) after translation
R(4-3, 1) S(7-3, 3) T(6-3, 4)
R'(1, 1) S'(4, 3) T'(3, 4)
Points R'(1, 1) S'(4, 3) T'(3, 4) after reflection
R''(1, -3) S''(4, -5) T''(3, -6)
Step-by-step explanation:
Answer:Step-by-step explanation:Points R(4,1) S(7,3) T(6,4) after translation R(4-3, 1) S(7-3, 3) T(6-3, 4) R'(1, 1) S'(4, 3) T'(3, 4) Points R'(1, 1) ...
find the slope of the following ^ :))
|
Answer:
m [slope] = 0
Step-by-step explanation:
When the slope is 0, x cancels out so the y value will remain the same.
There are several methods to finding slope but the easiest way to do this is by dividing the second y value - first y value by the second x value - first x value.
m = ∆y/∆x = y2-y1/x2-x1
You y2 and x2 are interchangable with y and x, because y1, and x1 are part of the starting coordinate,.
The reason you subtract the second
value from the first is because in a directly proportional relationship, y increases as x increases so the next x values will have a greater y value, this is a measure of steepness.
So the slope is:
-1 - -1 / 3 - -2 = -1 + 1 / 3 + 2 = 0 / 5 = 0.
Answer:
heres what u need
Step-by-step explanation:
\(\frac{-1}{-2} \frac{-1}{3}\)
divide top from bottom
\(-2/-1=2\)
2 is your x
\(3/-1=-3\)
-3 is your y
so your slope is (2,-3)
in a two-sample hypothesis test, d0 is equivalent to the ______ in a one-sample hypothesis test. benchmark p value test statistic level of significance
In a two-sample hypothesis test, d0 is equivalent to the benchmark in a one-sample hypothesis test. The benchmark in a one-sample test is the hypothesized value for the population mean, which is being compared to the sample mean.
In a two-sample test, d0 represents the difference between the two population means that is being tested. The p value, test statistic, and level of significance are all important factors in both types of hypothesis tests, but they do not directly relate to d0 or the benchmark. The p value is the probability of observing a test statistic as extreme as the one calculated, given the null hypothesis is true. The test statistic is a numerical value used to determine whether to reject or fail to reject the null hypothesis. The level of significance is the threshold for deciding whether to reject the null hypothesis, typically set at 0.05.
In a two-sample hypothesis test, d0 is equivalent to the benchmark in a one-sample hypothesis test. In both tests, we compare the observed data with a reference value. In a one-sample test, the reference value is the benchmark, while in a two-sample test, d0 represents the hypothesized difference between the two population means or proportions. The p-value, test statistic, and level of significance are used in both types of tests to make inferences and draw conclusions about the populations being studied.
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given a nonhomogeneous system of linear equa- tions, if the system is underdetermined, what are the possibilities as to the number of solutions?
If a nonhomogeneous system of linear equations is underdetermined, it can have either infinitely many solutions or no solutions.
A nonhomogeneous system of linear equations is represented by the equation Ax = b, where A is the coefficient matrix, x is the vector of unknowns, and b is the vector of constants. When the system is underdetermined, it means that there are more unknown variables than equations, resulting in an infinite number of possible solutions. In this case, there are infinitely many ways to assign values to the free variables, which leads to different solutions.
To determine if the system has a solution or infinitely many solutions, we can use techniques such as row reduction or matrix methods like the inverse or pseudoinverse. If the coefficient matrix A is full rank (i.e., all its rows are linearly independent), and the augmented matrix [A | b] also has full rank, then the system has a unique solution. However, if the rank of A is less than the rank of [A | b], the system is underdetermined and can have infinitely many solutions. This occurs when there are redundant equations or when the equations are dependent on each other, allowing for multiple valid solutions.
On the other hand, it is also possible for an underdetermined system to have no solutions. This happens when the equations are inconsistent or contradictory, leading to an impossibility of finding a solution that satisfies all the equations simultaneously. Inconsistent equations can arise when there is a contradiction between the constraints imposed by different equations, resulting in an empty solution set.
In summary, when a nonhomogeneous system of linear equations is underdetermined, it can have infinitely many solutions or no solutions at all, depending on the relationship between the equations and the number of unknowns.
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Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589. You must show all of your work to receive credit.
PLSSS SHOW WORK <3
Answer:
x = 18
Step-by-step explanation:
First, let's find the ratios between the two triangles
We'll use AV and AC
372 ÷ 589 = 12/19
All of the sides of the smaller triangle are 12/19 of the bigger triangle
Now let's find x
We know that AU + UB = AB
So it's 20x + 108 + 273 = AB
12/19 of a bigger triangle side equals a small triangle side
(12/19)AB = AU
For this equation multiply both sides by 19/12 to isolate AB
(12/19)AB x 19/12 = AU x 19/12
AB = (19/12)AU
Now we have this
20x + 108 + 273 = (19/12)(20x + 108)
20x + 381 = (19/12)(20x + 108)
Distribute the 19/12
20x + 381 = 95/3x + 171
Move all like terms to one side
20x + 381 = 95/3x + 171
- 171 - 171
20x + 210 = 95/3x
- 20x - 20x
Don't forget about common denominators
210 = 95/3x - 60/3x
210 = 35/3x
Multiply both sides by 3
210 x 3 = 35/3x x 3
630 = 35x
Divide both sides by 35
630/35 = 35x/35
x = 18
Answer:
Step-by-step explanation:
\(\frac{20x+108}{20x+381}\) = \(\frac{372}{589}\)
589( 20x + 108 ) = 372( 20x + 381 )
11780x + 63612 = 7440x + 141732
4340x = 78120
x = 18
World War II began in the year 1939.
Let x represent any year. Write an inequality in terms
of x and 1939 that is true only for values of x that
represent years before the start of World War II.
The Inequality to represent year is x < 1939.
What is Inequality?Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
Given:
Let x represent any year.
If we want years before 1939, then x must be less than 1939.
Then, the Inequality can be
x < 1939.
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The three friends went shopping again. this time danetta spent $12 less than jan spent, but elaine spent twice as much as danetta spent. they spent $86 in all. how much did each friend spend this time?
The three friends spent:Jan spent $30.5, Danetta spent $18.5, and Elaine spent $37.
Let's denote the amount Jan spent as J. Danetta spent $12 less than Jan, so her expenditure is J - $12. Elaine spent twice as much as Danetta, so her expenditure is 2(J - $12). The total expenditure of the three friends is $86. By setting up an equation using these values, we can find the individual expenditures of each friend.
Let's denote the amount Jan spent as J. According to the given information, Danetta spent $12 less than Jan, so her expenditure can be expressed as J - $12. Similarly, Elaine spent twice as much as Danetta, so her expenditure can be expressed as 2(J - $12).
The total expenditure of the three friends is stated as $86. We can set up the equation J + (J - $12) + 2(J - $12) = $86 to represent the sum of their expenditures. Simplifying this equation, we have 4J - $36 = $86.
By rearranging the equation, we find 4J = $122, which implies J = $30.5. Therefore, Jan spent $30.5.
Using this value, we can calculate the expenditures of the other two friends. Danetta spent J - $12, which is $30.5 - $12 = $18.5. Elaine spent twice as much as Danetta, so she spent 2($18.5) = $37.
In summary, Jan spent $30.5, Danetta spent $18.5, and Elaine spent $37.
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Find the equation of the line which passes through (2,4) with a slope of 1/2
Answer: the answer is y=1/2x+3
Step-by-step explanation:
Hopes this helps !! Message me if explanation is needed !!!
The equation of the line which passes through (2,4) with a slope of 1/2 is \(y = \frac{x}{2} +3\).
What is a slope-intercept form?Y = mx + b is the slope-intercept form of the equation of a straight line. In the equation y = mx + b, m is the slope of the line and b is the intercept. X and y represent the distance of the line from x-axis and y-axis, respectively. The value of b is equal to y when x = 0, and m shows how steep the line is.
Given
Slope m = 1/2
Point (x, y) = (2, 4)
Equation of line which passes through a point (x, y) with a slope of m is
y = mx + b
Substitute the values
⇒ \(4=\frac{1}{2}(2)+b\)
⇒ 4 = 1 + b
⇒ b = 4 - 1
⇒ b = 3
Substitute m = 1/2 and b = 3 in equation (1)
\(y = \frac{1}{2}(x) +3\)
⇒ \(y = \frac{x}{2} +3\)
Hence, the equation of the line which passes through (2,4) with a slope of 1/2 is \(y = \frac{x}{2} +3\).
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Find the surface area of each prism below
The surface area of the triangular prism is 684 cm²
Now,
Using the formulas
A=2\(A_{b}\) + (a+b+c)h
\(A_{b}\) = \(\sqrt{s(s-a)(s-b)(s-c)}\)
s=a+b+c/2
s= Semi-perimeter
a, b, c = Base sides of the triangle.
Solving for A,
A=( ah + bh + ch )+1/2\(\sqrt{-a^{4} +2(ab)^2+2(ac)^2-b^4+2(bc)^2 - c^4}\)
Substitute the values,
A = ( 12 × 16 + 9 × 16 + 15 × 16 ) + 1/2\(\sqrt{- 12^4 + 2 (12 * 9 )^2 + 2(12 * 15)^2 - 9^4 + 2(9*15)^2 - 15^4}\)
A = 684 cm².
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question set 1: one instructor believes that students take more than 2 classes per quarter on average. he randomly interviewed a class of 16 students and found out the mean number of classes per quarter is 2.3 classes and standard deviation of 0.8. assume alpha is 0.01. (a) set up the hypothesis..
We would reject the null hypothesis in favor of the alternative hypothesis.
What is the null hypothesis in this scenario?The null hypothesis (H0) is that the average number of classes per quarter for students is 2 or less. The alternative hypothesis (Ha) is that the average number of classes per quarter for students is greater than 2. We can express this as:
H0: μ ≤ 2 (mean number of classes per quarter)
Ha: μ > 2
Where μ represents the population mean. This hypothesis is based on the instructor's belief that students take more than 2 classes on average.
The significance level (alpha) is given as 0.01, which means that if the p-value of the test is less than 0.01, we would reject the null hypothesis in favor of the alternative hypothesis.
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nin
1) What is the equation of the line that passes through the point (-2,1) and has a slope of
-5/2?
Answer:
y=(-5/2)x-4
Step-by-step explanation:
Step 1: Define the equation of a line.
Equation of a line is written in the form y=ax+b where a is the slope and b is the y-intercept.
Step 2: Write the given parameters
(x1,y1)=(-2,1)
m=-5/2
Using the formula y-y1=m(x-x1)
y-1=-5/2(x-(-2))
y-1=-5/2(x+2)
y-1=(-5x-10)/2
By cross multiplication,
2(y-1)=-5x-10
2y-2=-5x-10
2y=-5x-10+2
2y=-5x-8
y=(-5x-8)/2
y=(-5/2)x-4
Coach dave has 18 golf balls to give to his players there are 3 players he gives the same number of golf balls to each player. how many golf balls does each player get
Answer: 6 golf balls
Step-by-step explanation:
If Coach Dave has 18 golf balls to give to 3 players and he wants to give the same number of golf balls to each player, we can use division to find the answer.
18 ÷ 3 = 6Therefore, each player will get 6 golf balls.
__________________________________________________________
Which step contains an error?
O step 2
O step 4
O step 6
O step 8
Answer:
C
Step-by-step explanation:
Step 6
What inscribed polygon is being constructed? Explain how you know.
With an equilateral triangle, only two circles are formed.
In geometry, what is an inscribed polygon?An inscribed polygon is one whose vertices are circle points. "In" denotes "in" and "scribed" denotes "written." Connect the points in a straight line with segments.What kind of polygon is carved into the circle?
A cyclic polygon is one that is inscribed in a circle, and the circle is its circumscribed circle or circumcircle.So, according to the given figure, we know that an equilateral triangle and only two circles are formed.Therefore, with an equilateral triangle, only two circles are formed.
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please help me solve the problem
Answer:
x = 130°
y = 50°
Step-by-step explanation:
x = 130° (Exterior alternate angles)
x + y = 180° (Angles in linear pair)
y = 180° - x
y = 180°- 130°
y = 50°
The solution to the problem in the figure attached in the question is: x = 130°, y = 50°
What are alternate angles?Alternate angles are angles that are formed in a situation whereby a line intersects two other lines, which lie on opposite sides of a transverse line and on contrasting proximate sides of the other lines.
From the given figure:
Angle x is an alternate angle to angle 130°.
Thus, x = 130°
Using the sum of angles on a straight line:
x + y = 180°
130° + y = 180°
y = 180° - 130°
y = 50°
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Sample Strength
1 11,7155
2 11,98157
3 8,043929
4 10,55816
5 14,07946
6 10,77687
7 7,86027
8 11,88967
9 11,94231
10 13,17745
11 10,56615
12 13,45536
13 7,41884
14 12,03131
15 7,776633
16 10,74894
17 10,72698
18 4,477291
19 6,80382
20 5,371892
21 10,28335
22 12,17773
23 10,55981
24 9,655187
25 8,790275
26 10,86246
27 10,37818
28 10,18805
29 11,62452
30 12,3059
31 6,903486
32 8,99011
33 6,971273
34 9,16039
35 8,678426
36 11,44383
37 10,78044
38 5,66676
39 10,77604
40 9,008765
Analyze the strength between individuals.
H0: σ< 10
Ha: σ> 10
We shall choose α=0.05
Will you accept or reject the hypotheses? Explain step by step.
Based on the given data and a one-sample chi-square test, the hypothesis test results reject the null hypothesis (σ < 10) in favor of the alternative hypothesis (σ > 10) at a significance level of 0.05. This indicates sufficient to suggest that the population standard deviation is greater than 10.
We test if the population standard deviation (σ) is less than 10 (H₀: σ < 10) or greater than 10 (Ha: σ > 10) using a significance level of 0.05.
To test this hypothesis, we can perform a one-sample chi-square test of variance, also known as the chi-square goodness-of-fit test. The test statistic is calculated as:
χ² = (n-1) * s² / σ₀²
where n is the sample size, s² is the sample variance, and σ₀ is the hypothesized population standard deviation under the null hypothesis.
Let's calculate the necessary values:
Sample size (n) = 40
Sample variance (s²) = Sum of (xi - X⁻)² / (n-1) = 129.7396
Hypothesized population standard deviation (σ₀) = 10
Now, we can calculate the test statistic:
χ² = (n-1) * s² / σ₀² = (40-1) * 129.7396 / 10² = 515.792
To test the hypothesis, we need to compare the test statistic to the critical value from the chi-square distribution with (n-1) degrees of freedom (39 degrees of freedom in this case) at the chosen significance level (α = 0.05).
The critical value for a right-tailed test with α = 0.05 and 39 degrees of freedom is approximately 56.891.
Since the test statistic (515.792) is greater than the critical value (56.891), we reject the null hypothesis (H₀). This means that there is proof to suggest that the population standard deviation is greater than 10.
Therefore, based on the given data and the performed hypothesis test, we reject the null hypothesis and conclude that there is sufficient to support the alternative hypothesis that the population standard deviation is greater than 10.
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if the area under the standard normal curve from 0 to z is .3508 and z is positive then z is: 1.04 but how did they get 1.04?
When the area under the standard normal curve from 0 to z is 0.3508 and z is positive, the value of z is approximately 1.04 which can be found by using the z-table.
To find the value of z when the area under the standard normal curve from 0 to z is 0.3508 and z is positive, you can use the z-table or a standard normal distribution table.
1. Since the area from 0 to z is 0.3508, you need to find the total area to the left of z, which is the sum of the area from the left tail to the mean (0.5) and the area from the mean to z (0.3508). So, the total area to the left of z = 0.5 + 0.3508 = 0.8508.
2. Look up the closest value to 0.8508 in the standard normal distribution table (also known as the z-table), which shows the cumulative probability (area) for a given z-score.
3. Locate the row and column that corresponds to the value closest to 0.8508. In this case, the closest value is 0.8508 itself, located at the intersection of the row with 1.0 and the column with 0.04.
4. Combine the row and column values to find the corresponding z-score. In this case, the z-score is 1.04.
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3 ft, 4 ft, 6 ft 1 5 in, 12 in, 13 in 25 cm, 31 cm, 40 cm
Which one in would make a right angle in a triangle
Answer: . . . . . . Step-by-step explanation:
Given m|n, find the value of x.
т
(6x+4)
(4X-14)
Step-by-step explanation:
Here Is Your Answer........ please Make me as brainliest
if 10 shirts cost $80, what is the unit rate (the cost of 1 shirt)?
Answer:
Each shirt is $8
Step-by-step explanation:
80÷10 = 8
Answer:
$8
Step-by-step explanation:
Form your equation, there are 10 shirts at x price, and they equal $80:
10x = $80
solve for x by dividing both sides by 10
10x/10 = $80/10
x = $8
A zebra can run at a constant speed of 0.60 miles per minute. How far can a zebra run in 30 minutes? Choose the equation that could be used to answer this question
Answer:
0.6x30=18
Step-by-step explanation:
18 miles would be how far it ran.
You didn't give us any answer choices for which equation, so I would say the equation I wrote could work.
Answer:
0.6 × 30 = 18
Step-by-step explanation:
You multiply the two values to get 18:
0.6 * 30 = 18
Hope that helps! :)
What is the maximum value of f(x) = −3 sin(5x-4)? A. 5
B. 3
C. 4
D. 1.5
E. 15
The maximum value of the function is \(\( -(-\frac{3}{2}) = \frac{3}{2} \).\)
Hence, the correct answer is D. 1.5.
To find the maximum value of the function \(\( f(x) = -3 \sin(5x - 4) \)\), we can analyze the properties of the sine function and its effect on the given equation.
The sine function is a periodic function that oscillates between -1 and 1. The coefficient in front of the sine function, -3, affects the amplitude of the function.
Amplitude:
The amplitude of a sine function is half the distance between the maximum and minimum values. In this case, the amplitude is given by \(\( \frac{1}{2} \times (-3) = -\frac{3}{2} \).\)
Horizontal shift:
The expression inside the sine function, 5x - 4, indicates a horizontal shift to the right by \(\( \frac{4}{5} \)\)units. This shift does not affect the amplitude or the maximum value of the function.
Since the amplitude is negative, the graph of the function is reflected over the x-axis. This means that the maximum value will be the negation of the amplitude.
Therefore, the maximum value of the function is \(\( -(-\frac{3}{2}) = \frac{3}{2} \).\)
Hence, the correct answer is D. 1.5.
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The table below shows a pattern in the cost of renting a car based on the number of days rented. Car Rentals Number of Days (d) Cost in Dollars (c) 4 161 5 195 6 229 7 263 The pattern continues. Which equation describes the pattern in the cost of renting a car? A. c = 68d + 25 B. c = 34d + 127 C. c = 68d + 43 D. c = 34d + 25
The linear equation that describes the pattern in the cost of renting a car is given by:
D. c = 34d + 25What is a linear function?A linear function is modeled by:
\(y(x) = mx + b\)
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1. b is the y-intercept, which is the value of y when x = 0.In this problem:
For each day, the cost of renting a car increases by 34, hence, the slope is of 34, and the equation is:\(c(d) = 34d + b\)
When d = 4, c = 161, and this is used to find b.
\(c(d) = 34d + b\)
\(161 = 34(4) + b\)
\(b = 25\)
Hence, the equation is c = 34d + 25, and option D is correct.
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Is 8.39 > -1.46. Please can you help me answer this question.
Answer:
yes because a positive is more than a negative
Step-by-step explanation:
Describe the nature of the roots of this equation . 2x ^ 2 - x + 1 = 0 A. Two real, rational roots B. Two real, irrational roots C. Two non- real roots C. One real, double root
Step-by-step explanation:
b²-4ac
(-1)²-4(2×1)
1-8
-7
Now -7<0 therefore it has two complex roots or nonreal roots
Find the perimeter.
Answer:
22v^2 + 5v - 4
Step-by-step explanation:
5v^2 + 9v - 11 + v - 7 + 17v^2 -5v +14
22v^2 + 5v - 4
Lynn has a watering can that holds 32 cups of water, and she fills it a quarter full. Then she waters her 21 plants so that each plant gets the same amount of water. How many cups of water will each plant get?
Answer:
2.625 cups per plant
Step-by-step explanation:
Find a quarter of 32 which is 8
Divide 21 plants by 8 cups
2.625 cups per plant
Answer:
The answer is 0.381
Step-by-step explanation:
1. A quarter of the watering can is 8 cups.
2. If 21 plants get watered, we divide 8 by 21.
3. The answer is 0.38095238095, which we can simplify to 0.381.
\((x +3)^{2} + 10x \leqslant 21\)
Step-by-step explanation:
\( {(x + 3)}^{2} + 10x\leqslant 10 \\ {x}^{2} + 6x + 9 + 10x \leqslant 10 \\ {x}^{2} + 16x + 9 \leqslant 10 \\ {x}^{2} + 6x + 9 \leqslant 0 \\ the \: value \: of \: x \: that \: makes \: it \: exist \\ x = - 3\)
The city treasury began with $1,100,000 at the beginning of the year. Each day
since, tax revenues have come in at a rate of $12,500 per day. Expenditures
each day average $15,000 per day. The treasury now has less than $1,000,000.
How many days, d, has it been since the beginning of the year?
Net daily change is revenue - expenditures, 12500 - 15000 = -2500.
The overall change in the treasury's funds is 1.1Mil - 1Mil = 100K. To find out how many days, we divide the overall change by the net daily change in revenue: 100K / 2500 = 40 days.
a researcher recorded reaction time to respond to a sound. if the data of the research subjects are presented in a frequency distribution graph, what type of graph should be used?
If the data of the research subjects are presented in a frequency distribution graph, a histogram-type graph should be used.
If the data are presented in a frequency distribution graph, then the type of graph that should be used is a histogram. A histogram is a type of bar graph that displays the distribution of a continuous variable by dividing the range of values into intervals, and bins, and counting the number of observations that fall within each bin.
If the academic majors were nominal a bar graph could also be used to display the frequency of each major. In a bar graph, each category would be plotted on the horizontal axis, and the frequency of students in each category would be plotted on the vertical axis.
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