1. Calculation of elevations of curve every 50 feet and plotting the curve to scale and determining the maximum elevation and horizontal distance from the PVC In this question, given the following information: Positive grade of 5% intersects a grade of -3%.The length of the curve is 450 feet. VPI elevation is 100.25 feet. To plot a vertical curve using a 10:1(H: V) magnification for the vertical scale, use a 1 inch =50 feet for horizontal scale. Here is the detailed solution: First, let's find out the PVC elevation, PVI elevation, and the length of the vertical curve as: PVC Elevation: 100.25 ft Grade at PVC: 5% PVI Elevation: 100.25 + [(5/100)*450] = 123.25 ft VPI Elevation: 100.25 + [(-3/100)*450] = 86.75 ft Length of Vertical Curve: VPI to PVI = (123.25 - 86.75) = 36.50 feet Now, let's find out the elevations of the curve every 50 feet:
The horizontal distance can be calculated using the formula:
`H = (L^2)/(2f)`
where L is the length of the curve and f is the algebraic difference between the initial and final grades.
We know that L = 450 feet and f = (5 - (-3)) = 8.
So, `H = (450^2)/(2×8) = 15,937.5 ft`
We can now plot the curve using the above information. The tangent grades are shown as well as horizontal distances.
Maximum Elevation:
The maximum point on the vertical curve is the midpoint of the curve, which is 18.25 ft away from the PVI. The elevation of this point can be calculated using the formula:
`E = PVI + [(fH^2)/(8L^2)]`
So, `E = 123.25 + [(8×18.25^2)/(8×450^2)] = 124.60 ft`
The horizontal distance from the PVC to this point can be calculated as:
`Hd = H/2 + [(fL^2)/(8H)]`
So, `Hd = 15,937.5/2 + [(8×450^2)/(8×15,937.5)] = 739.06 ft`
2. Determination of the depth below the surface of the curve to the top of the pipe, station of the highest point on the curve, and elevation of the highest point on the curveA vertical curve crosses a 4-ft diameter pipe at a right angle. The pipe is located at station 110+85, and its centerline is at elevation 1091.6 ft. The PVI of the vertical curve is at station 110+00, and elevation 1098.4 ft. The vertical curve is 600 feet long and connects an initial grade of +1.20% to a final grade of -1.08%. Here is the detailed solution:First, let's find out the PVC elevation, PVI elevation, and the length of the vertical curve as:
PVC Elevation: 1098.4 + [(1.20/100)*600] = 1106.4 ft PVI Elevation: 1098.4 + [(-1.08/100)*600] = 1082.16 ft Length of Vertical Curve: VPI to PVI = 600 feetNow, let's find out the depth below the surface of the curve to the top of the pipe:
We know that the pipe is located at station 110+85 and its centerline is at elevation 1091.6 ft.
So, the distance from the PVC to the pipe can be calculated as:
`D = 85 - 00 = 85 feet`
The elevation of the curve at station 110+85 can be calculated using the following formula:
`E = PVI + [(fD^2)/(8L^2)]`
So, `E = 1082.16 + [((1.20 - (-1.08))×85^2)/(8×600^2)] = 1092.03 ft`
Therefore, the depth below the surface of the curve to the top of the pipe is:
`1091.6 - 1092.03 + 2 = 1.57 ft`
Next, let's find out the station of the highest point on the curve:
The highest point on the vertical curve is the midpoint of the curve, which is 300 feet away from the PVI. So, the station of the highest point on the curve is:
`110 + 300 = 110+30`
Finally, let's find out the elevation of the highest point on the curve:
`E = PVI + [(fH^2)/(8L^2)]`
So, `E = 1098.4 + [((1.20 - (-1.08))×(600/2)^2)/(8×600^2)] = 1100.55 ft`
Therefore, the elevation of the highest point on the curve is 1100.55 feet.
An organization has published applications on its web servers. The applications are accessible to users in the organization when they are authenticated via Active Directory.
What RAS capability will allow the organization's applications to be accessible to users outside of the organization?
Where an organization has published applications on its web servers and the applications are accessible to users in the organization when they are authenticated via Active Directory the RAS capability that will allow the organization's applications to be accessible to users outside of the organization is; "Web Application Proxy"
What is Web Application Proxy?In Windows Server Remote Access, the Web Application Proxy is a role service. It provides reverse proxy capabilities, allowing users to access corporate resources on any device from outside the corporate network.
Web Application Proxy functions in two ways. It enables enterprises to grant end users outside of the company selective access to apps running on servers within the organization. It also acts as a stumbling block between business applications and the Internet.
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Outline the course of study Brent might follow in high school if he is interested in earning an engineering degree in college.
Answer:
Science, Technology, Engineering and Mathematics courses
Explanation:
The background and foundational prerequisite and knowledge required to traverse through college education is being acquired at high school. Most of the what is going to be needed based on one's aspiring career or course of choice would have been introduced to students. This is why it is important to prepare ahead in other to keep focus.
For the pursuit of an engineering degree in college, this falls under the Science, Technology, Engineering and Mathematics curriculum. Hence, courses relating to science, technology and engineering and mathematics curriculum.
he critical buckling load of an ideal column of circular cross section can be reduced by: The critical buckling load of an ideal column of circular cross section can be reduced by: increasing the Poisson's ratio of the column material increasing the length of the column increasing the modulus of elasticity of the column material increasing the diameter of the column
The critical buckling load of an ideal column of circular cross section can be reduced by increasing the diameter of the column.
What is critical load of buckling of column?The critical load is known to be that factor that is labeled the greatest load that is one which is unable to cause lateral deflection (buckling).
Note that For loads greater than the critical load, the column will tend to decrease laterally. The critical load is known to be one that puts the column in what we call the state of an unstable form of equilibrium.
The critical buckling load is based on the shape and dimensions of beam section that is said to have constant cross sectional area.
Hence, The critical buckling load of an ideal column of circular cross section can be reduced by increasing the diameter of the column.
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The velocity field of a flow is given by V = 2x2 ti +[4y(t - 1) + 2x2 t]j m/s, where x and y are in meters and t is in seconds. For fluid particles on the x-axis, determine the speed and direction of flow
Answer:
Explanation:
The value of a will be zero as it is provided that the particle is on the x-axis.
Calculate the velocity of particles along x-axis.
\({\bf{V}} = 2{x^2}t{\bf{\hat i}} + [4y(t - 1) + 2{x^2}t]{\bf{\hat j}}{\rm{ m/s}}\)
Substitute 0 for y.
\(\begin{array}{c}\\{\bf{V}} = 2{x^2}t{\bf{\hat i}} + \left( {4\left( 0 \right)\left( {t - 1} \right) + 2{x^2}t} \right){\bf{\hat j}}{\rm{ m/s}}\\\\ = 2{x^2}t{\bf{\hat i}} + 2{x^2}t{\bf{\hat j}}{\rm{ m/s}}\\\end{array}\)
Here,
\(A = 2{x^2}t \ \ and\ \ B = 2{x^2}t\)
Calculate the magnitude of vector V .
\(.\left| {\bf{V}} \right| = \sqrt {{A^2} + {B^2}}\)
Substitute
\(2{x^2}t \ \ for\ A\ and\ 2{x^2}t \ \ for \ B.\)
\(\begin{array}{c}\\\left| {\bf{V}} \right| = \sqrt {{{\left( {2{x^2}t} \right)}^2} + {{\left( {2{x^2}t} \right)}^2}} \\\\ = \left( {2\sqrt 2 } \right){x^2}t\\\end{array}\)
The velocity of the fluid particles on the x-axis is \(\left( {2\sqrt 2 } \right){x^2}t{\rm{ m/s}}\)
Calculate the direction of flow.
\(\theta = {\tan ^{ - 1}}\left( {\frac{B}{A}} )\)
Here, θ is the flow from positive x-axis in a counterclockwise direction.
Substitute \(2{x^2}t\) as A and \(2{x^2}t\) as B.
\(\begin{array}{c}\\\theta = {\tan ^{ - 1}}\left( {\frac{{2{x^2}t}}{{2{x^2}t}}} \right)\\\\ = {\tan ^{ - 1}}\left( 1 \right)\\\\ = 45^\circ \\\end{array}\)
The direction of flow is \(45^\circ\) from the positive x-axis.
A gas is contained in a vertical, frictionless piston– cylinder device. The piston has a mass of 3.2 kg and a crosssectional area of 35 cm2. A compressed spring above the piston exerts a force of 150 N on the piston. If the atmospheric pressure is 95 kPa. Determine the pressure inside the cylinder.
Answer:
Pressure = 51.8 x 10³ Pa = 51.8 KPa
Explanation:
First, we calculate the total force exerted on the piston:
Total Force = Force Exerted by Spring + Weight of Piston
Total Force = 150 N + (mass)(g)
Total Force = 150 N + (3.2 kg)(9.8 m/s²)
Total Force = 150 N + 31.36 N
Total Force = 181.36 N
Now, for cross-sectional area of piston:
Area = (35 cm²)(1 x 10⁻⁴ m²/1 cm²)
Area = 0.0035 m²
Now, for pressure inside the cylinder:
Pressure = Total Force/Area
Pressure = 181.36 N/0.0035 m²
Pressure = 51.8 x 10³ Pa = 51.8 KPa
Design a 3-bit binary counter using S-R flip flops.
Answer:
This is an asynchrnous 3-bit counter. Just note that this design is different and works differently than its synchronous counterpart. It's an easier design than its synchronous counterpart, and is not as reliable because it has delays.
What phase best describes the function of a thermostat?
Answer:
a formula containing arguments
Explanation:
Hopefully that's correct
What does the nec section 420. 6 (a) state that the tables are not used for?
Section 420.6(a) of the National Electrical Code (NEC) states that the tables should not be used for calculating the maximum number of conductors that can be installed in various raceway and cable types.
It is a standard of practice for the safe installation of electrical wiring and equipment in the United States. The NEC is updated every three years to reflect the most up-to-date electrical safety practices.In 2020, the latest NEC was released. The NEC contains regulations for everything from electrical wire size to electrical panel installation. Its goal is to ensure the safe installation of electrical systems in both residential and commercial settings.
Section 420.6(a) is part of Article 420 of the NEC, which covers installation standards for electrical equipment used in a hazardous (classified) location. Hazardous locations are areas where combustible gases, vapors, dusts, or fibers exist in concentrations that could cause a fire or explosion if a source of ignition were present. Section 420.6(a) of the NEC states that the tables used to determine the maximum number of conductors that can be installed in various raceway and cable types should not be used for calculating.
The tables are not a substitute for proper engineering calculations when designing an electrical system. This means that the tables should be used as a general guide, but not as the only means of determining the maximum number of conductors that can be installed.
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Which part of a machine control unit interacts with the machine tools through electric signals?=]
A machine control unit is the electronic hardware that stores information and controls the machine tools. This unit contains a data processing unit that stores and manipulates data, and a ___________ that interacts with the machine tools through electrical signals.
Answer:
control loop unit
Explanation:
Edmentum/Plato
A glass tube is inserted into a flowing stream of water with one opening directed upstream and the other end vertical. If the water velocity is 3 m/s, how high will the water rise in the vertical leg relative to the level of the water surface of the stream?
Answer:
\(h=0.46m\)
Explanation:
From the question we are told that:
Velocity of water \(V=3m/s\)
Height=?
Generally, the equation for Water Velocity is mathematically given by
\(V=\sqrt{2gh}\)
Therefore Height h is given as
\(h=\frac{v}{2g}\)
\(h=\frac{3^2}{2*9.81}\)
\(h=0.46m\)
To add refrigerant to the system through the suction service valve valve stem must be?
Answer:
Just cracked off the backseat.
Explanation:
what scale model proves the initial concept?
Answer: A prototype
Explanation:
The scale model that proves the initial concept is called a domain model.
What is a scale model?A copy or depiction of something where all parts have the same dimensions as the original. A scale model is an image or copy of an object that is either larger or smaller than the object being represented's actual size.
A domain model is a type of conceptual model that is used to depict the structural elements and conceptual constraints within a domain of interest.
A domain model will include all of the entities, their attributes, and relationships, as well as the constraints that govern the conceptual integrity of the structural model elements that comprise that problem domain.
Therefore, a domain model is the scale model that proves the initial concept.
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the dealer's coast of a car is 85% of the listed price. The dealer would accept any offer that is at least 500 dollar over the dealer's cost. design an algorithm that prmpts the user to input the list price of the car and print the least amount that the dealerr would accept for the car
The dealer would accept any offer that is at least 500 dollars over the dealer's cost The algorithms for your query are 1) Declare list Price as a double READ list Price• Declare and initialize most-0.85*list Price+500.0.
What is an easy definition of a set of rules?A set of rules is a method used for fixing a hassle or acting a computation. Algorithms act as a specific listing of commands that behavior certain moves grade by grade in both hardware- or software-primarily based totally routines. Algorithms are broadly used during all regions of IT.
Function calculateAvg(Scores) Declare and initialize SUM as double identical to 0 • For i=1 to length(Scores) SUM=SUM+Scores.get(i).EndLoop- Return SUM/length(Scores) EndFunction- Function printBelowAvg(Names, Scores)Define and claim AVG=calculateAvg(Scores), For i=1 to length(Scores) If Scores.get(i)MAX then MAX=Scores.get(i) Endif, EndLoop.RETURN MAX-EndFunction- Function blended Perform(Names, Scores).PRINT calculateAvg(Scores), print BelowAvg(Names, Scores)PRINT highestScore(Scores), EndFunctionCall the characteristics as combinedPerform(Names, Scores)Kindly revert for any queries.Read more about the algorithm :
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What might the effect of using salt on snowy and icy roads be on Montgomery County's Water Supply?" What might the effect of using salt on snowy and icy roads be on Montgomery County's Water Supply?"
The use of salt on snowy and icy roads could have a negative effect on Montgomery County's Water Supply. The salt used on the roads for melting ice can cause a number of issues for water supplies and ecosystems, and Montgomery County is no exception.
When salt is used to melt snow and ice on the road, it can dissolve into the water and run off into streams, rivers, and lakes. The salt lowers the freezing point of water and melts ice, but it also alters the chemical makeup of the water, making it more saline. It can also damage aquatic plants, animals, and fish that rely on freshwater systems.
Therefore, it is important to take steps to minimize the use of salt or to use alternatives, such as sand or beet juice, which are less harmful to the environment and water supplies.
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Which type of wireless security generates dynamic encryption keys each time a client associates with an AP?
The type of wireless security that generates dynamic encryption keys each time a client associates with an AP is called WPA2-PSK (Wi-Fi Protected Access 2 - Pre-Shared Key) with AES (Advanced Encryption Standard) encryption.
This security protocol provides a higher level of security compared to WEP (Wired Equivalent Privacy) and WPA (Wi-Fi Protected Access) as it uses a unique encryption key for each client device and changes it regularly, making it more difficult for attackers to intercept and decrypt the wireless traffic.
TPM is a hardware chip. It is a type of module that is used to authenticate the hardware devices with the help of encryption keys (passwords). It is the short form of Trusted Platform module. The hardware devices that be authenticated through this module may include personnel computer or laptops. There are different keys, password and security codes. So, the best sentence that describes, TPM is Encryption built into hardware.
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What is the value of cos (pie/6)
Answer:
0.52359877559
Explanation:
I did the math, it was hard and I regret it, make me brainiest please.
Answer:
cos (πe/6)
Hope this helps :D
Who is responsible for shielding a welding arc to protect
the eyes and skin of all persons in the working area?
Answer:
manager and supervisor
Explanation:
3. Water is the working fluid in an ideal Rankine cycle. The condenser pressure is 10 kPa (0.10 bar), and saturated vapor enters the turbine at 18 MPa (180 bar). The net power output of the cycle is 100 MW. For this cycle determine the: a) mass flow rate of the steam, in kg/h. b) heat transfer rates for the working fluid passing through the boiler and condenser, each in kW. c) thermal efficiency of the cycle.
Answer:
a) 116.51 kg/s = 419436 kg/hour
b) for boiler ( Q 1 ) = 265547 kW
for condenser ( Q2 ) = 165639.93 kW
c) 37.65%
Explanation:
Given data:
condenser pressure ( P1 ) = 10 kPa ≈ 0.10 bar
saturated vapor pressure ( P2 ) = 18 MPa ≈ 180 bar
Net power output of cycle = 100 MW
attached below is detailed solution to the question
a) calculate mass flow rate of steam in Kg/h
applying the formula for calculating power
P = м ( h3 - h4 - h2 + h1 ) ------ ( 1 )
power ( p ) = 100 * 10^3 Kw
h3 = 2510.0
h4 = 1613.49
h2 = 230.82
h1 = 191.01
input the given values into equation 1
mass flow rate of steam ( m ) = 116.51 kg/h
b) Heat transfer rates for working fluid passing through boiler and condenser
for boiler ( Q 1 ) = 265547 kW
for condenser ( Q2 ) = 165639.93 kW
C) Determine thermal efficiency of the cycle
N = \(\frac{P}{Q2}\) = 100 / 265.547 = 0.3765 = 37.65%
Consider the following code: sub $2. $1,$3 and $12,$2,$5 or $13.$6 $2 add $14,$2 $2 sw $15,100( $2) The data hazard between the third and first instructions can be resolved using forwarding. True False
False. The data hazard between the third and first instructions cannot be resolved using forwarding alone.
The data hazard between the third and first instructions cannot be resolved using forwarding. Forwarding allows data to be transferred directly from the execution stage of one instruction to the execution stage of another instruction to avoid stalls or hazards. However, in this case, the value produced by the third instruction (which is a store instruction) needs to be written back to the register file before it can be forwarded to the first instruction. Therefore, forwarding alone cannot resolve this data hazard. Instead, other techniques like stalling or reordering instructions may be required to handle the hazard and ensure correct execution.
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in the circuit of fig. P7.44, what should the value of L be at ω = 10^4 rad/s so that i(t) is in-phase with υs(t)?
The specific value of L, you will need the value of the resistance R in the circuit. Once you have R, you can substitute it into the equation to find the required inductance L.
In order for i(t) to be in-phase with υs(t) in the circuit of fig. P7.44, the value of L must be chosen such that the reactance of the inductor (ωL) is equal to the impedance of the resistor (R) at ω = 10^4 rad/s. This is because at this frequency, the circuit behaves purely resistively and the phase difference between the voltage and current should be zero.
Using the impedance formula for a series RL circuit, we have:
Z = √(R^2 + (ωL)^2)
Setting Z equal to R and solving for L, we get:
R = √(R^2 + (ωL)^2)
R^2 = R^2 + (ωL)^2
(ωL)^2 = 0
L = 0
Therefore, the value of L should be zero for i(t) to be in-phase with υs(t) at ω = 10^4 rad/s. However, it is important to note that this is not a practical value for L as it would essentially remove the inductor from the circuit. In reality, a small but non-zero value of L would be used to maintain some level of inductance while still allowing the circuit to behave purely resistively at the desired frequency.
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____ emotions can influence your driving. A. Only some B. All of your C. Only negative D. Only positive
4. a. A family purchased a 3 acre piece of land in Limuru for Kshs.30,000,000.00 fifteen years ago. They planted trees at a cost of Kshs.250,000.00 per acre. Each year they have been spending on average Kshs.25,000.00 per acre per month to take care of the trees and also to secure the property. They are now considering selling it. What is the minimum amount they should accept so as not to incur a loss bearing in mind that comparable properties have been yielding a rate of 6.5% interest per annum? (8 marks)
b. “Compulsory acquisition is the power of government to acquire private rights in land for public good without the willing consent of the owner but; in exchange for compensation”. Discuss this statement with special reference to the main considerations that ought to be made in conducting a valuation for compulsory acquisition. (12 marks)
The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.
Why should they accept this amount and why?To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.
Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.
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Help with answering questions
Simply put, the thread form is how the thread is arranged in an axial plane and is made up of the crest, root, and flanks.
What are the different types of threads?Simply put, the thread form is how the thread is arranged in an axial plane and is made up of the crest, root, and flanks.The threads' crests and roots are at their tops and bottoms, respectively, with the flanks connecting them.Six of the most popular thread types:NPT and NPTF. UN/UNF.BSPP (BSP, parallel) (BSP, parallel).metric parallel BSPT, or BSP with a taper.Measured in metric.In terms of thread form, we mean the screw thread's profile.Thread standards that specify thread form, series, class, allowance, tolerance, and designation are often published per thread form.Be aware that different standards use different methods to identify screw threads.To learn more about threads refer
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The failure time (in hours) of a pressure switch is lognormally distributed with parameters μt = 4 and σt = 0.9. (9 pts)
a. What is the MTTF for the pressure switch?
b. When should the pressure switch be replaced , if the minimum required reliability is 0.95? (3 pts)
c. What is the value of the hazard function for the time computed in b?
Given, Failure time (in hours) of a pressure switch is log-normally distributed with parameters
μt = 4 and σt = 0.9. (9 pts)
MTTF for the pressure switch= E(T) where T is the life of the product. From the data, we have; Mean, μt = 4 and Standard deviation, σt = 0.9.Using the relationship between lognormal and normal distribution i.e If X~ Lognormal
(μ,σ^2) then Y=ln(X)~
Normal(μ,σ^2), we can find the value of
MTTF;Y=ln(X) ln(MTTF)= μ = 4 and σ^2=0.9^2=0.81
Hence, Y~N(4, 0.81)So, E(T)=exp(μ+σ^2/2)=exp
(4+0.81/2) =exp(4.405)= 81.85
Thus, MTTF for the pressure switch = 81.85 hours. When should the pressure switch be replaced, if the minimum required reliability is 0.95?Given, Minimum required reliability = 0.95.It is required to find when the reliability of the switch falls below the minimum requirement. Let R(T) be the reliability function of the switch. Then,
R(T) =P(T > t)
where T is the life of the switch.
R(T)= P(T > t)= P(log T > log t)= P [(log T - μ)/σ > (log t - μ)/σ]= 1 - Φ [(log t - μ)/σ]
can be found by solving the above equation as follows;
0.95= R(t) = 1 - Φ [(log t - μ)/σ]Φ [(log t - μ)/σ]= 0.05
using standard normal tables, we get
Φ(1.64)= 0.95approx (log t - μ)/σ= 1.64log t= μ + σ
(1.64)log t= 4+0.9(1.64)= 5.476t= antilog (5.476)= 239.42
So, the switch should be replaced after 239.42 hours. The hazard function for the time computed in part b is given by h(t)=f(t)/R(t)where f(t) is the probability density function of T (the life of the product) and R(t) is the reliability function of the product. Thus, the value of h(t) at 239.42 hours is;
h(239.42)= f(t)/R(t)= 0.0005074/0.05= 0.01014
The value of the hazard function for the time computed in b is 0.01014.
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A cylindrical rod of brass of 20 mm in diameter is cold worked by drawing. The circular cross section will be maintained during deformation. A cold-worked tensile strength in excess of 300 MPa and a ductility of at least 10% EL are desired. Furthermore, the final diameter must be 14mm. Explain how this may be achieved.
Answer:
To meet all of the criteria raised by the question, we must first draw a wire with a diameter of 8.46 mm and then 21.5 percent CW on it.
Explanation:
the adult population can be calculated by adding the labor force and not in the labor force together.
true
false
The given statement "The adult population can be calculated by adding the labor force and not in the labor force together" is true because the adult population refers to the number of people in a particular region or country who are eligible for voting.
This demographic includes all individuals who are legally eligible to cast their ballot in any given election. To determine the adult population, it's important to note that not all adults are in the labor force. Some individuals may be out of work and not actively seeking employment, which means they are not included in the labor force.
Similarly, those who are not working due to disability or other reasons are also not included in the labor force. The adult population can be calculated by adding the labor force and not the labor force together. The labor force is the number of individuals who are employed or actively seeking employment. Those who are not in the labor force include retirees, stay-at-home parents, and individuals who are unable to work due to disability or other reasons.
So, adding the labor force and not in the labor force together can give us the total adult population of a particular region or country.
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Heat-absorbing glass was developed to block more of Solar Radiation than light. True False
Early drum brakes systems were mechanically operated by all of the
following EXCEPT:
Gears
Links
Levers
Rod
Answer:gears
Explanation:
Although mechanical brakes are equally crucial in manufacturing, material handling, and other power transmission applications, most people are only aware with vehicle brakes. Thus, option A is correct.
What drum brakes systems were mechanically operated?A rotating cylinder is slowed down by the brake pad pushing outward in mechanical drum brakes. Friction is used by the cylinder to stop. For your off-road vehicle, a mechanical brake system is a high-quality braking option. Your cars' durability and effectiveness can both be improved by mechanical drum brakes.
One of the earliest and most popular varieties of mechanical brakes is the drum brake. The brake pad is fastened to a curved bracket known as a shoe. There are typically two shoes inside the drum, and when they are engaged, they press on the interior of the drum to reduce its rotation.
Therefore, Early drum brakes systems were mechanically operated by all the Gears.
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1. Which one of the following is correct about DSS (decision Support Systems)? A. Supports non-routine decision making, uses internal information as well as TPS and MIS data and serves top management B. OSS serves middle ® management. uses external information as well as TPS and MIS data and supports routine decision making. C. None of the given choices are correct about the DSS. D. Supports routine decision making. uses internal information as well as TPS and MIS data and serves Middle management. 2. Information system to develop strong ties and loyalty with customers and supplies is part of A. Customer and supply intimacy B. Supply chain C. Managing strategic transitions D. Sustaining competitive advantage 3. Data which is converted into unreadable text or unreadable code in the Encryption process is called...... A. Decryption B. Cipher text C. Public key D. Privet key 5. Which one of the following is not related to growing importance of collaboration? A. Changing scope of the firm B. Changing nature of work C. Mission of the organization D. Changing culture of work 7. Responding to customers and suppliers in real time is part of? A. Customers and suppliers intimacy B. Improve decision-making C. No nothing given choices D. Competitive advantage 8. According to the management information system which one of the following should be the head of the information system department? A. Note of the given B. CKO (cheif knowledge office) C. CPO (chief Privacy officer Privacy officer) D. CEO ( chief executive officer) 9. Which one of the following is correct about DSS decision A. DSS search middle management users external information as well as TPS and MIS data and supports routine decision making B. support to change decision making uses Internet internal information C. support non-routine decision-making uses until internal information as well as TPS and MIS data and serves top management D. none of the given choices are correct about the DSS 10. In an information system a message used to help organization to evaluate and make correction is known as process? A. True B. False 11. The purpose of supply chain management is to transport huge to amount of products to destination was high amount of time and lowest cost true A. True B. False 12. Set of elements that interact to accomplish a specific goal is known as A. Output 13. According to Michael Portillo there are A. 5 B. 2 C. 3 D. 4 14. Use of digital technology and went to the intranet to drive major in business process is known E-business a. True b. False
1. The correct option about DSS is A. DSS (Decision Support Systems) supports non-routine decision-making, uses internal information as well as TPS and MIS data, and serves top management.
2. The option A is correct. Customer and supply intimacy is an information system to develop strong ties and loyalty with customers and supplies.3. The correct term for data converted into unreadable text or unreadable code in the encryption process is Cipher text.5. Mission of the organization is not related to the growing importance of collaboration.7. Responding to customers and suppliers in real-time is part of customer and suppliers intimacy.8. The correct option according to the management information system, should be the head of the information system department is CEO (chief executive officer).9. The correct option about is that it supports non-routine decision-making, uses internal information as well as TPS and MIS data, and serves top management.10. The given statement is False. A message used to help the organization to evaluate and make corrections is known as Feedback.11. The given statement is True.12. The correct option is Output.13. According to Michael Portillo, there are 2.14. The given statement is True.
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In the AC resistor circuit of Figure Q2.1, the voltage of the AC power source is
U = 100 sin(120pi x t) V .
what are
(a) the peak voltage of the AC power source
(b) the frequency of the alternating current in the circuit
(c) the instantaneous voltage of the power source at t = 20 ms
(d) the peak voltage across each resistor
(e) the instantaneous resistor voltages at t = 20 ms,
(f) to sketch the waveform of voltage in the first two periods
Answer:
(a) 100 V
(b) 60 Hz
(c) 95.106 V
(d) 25 V, 75 V
(e) 23.776 V, 71.329 V
(f) see attached
Explanation:
(a)The peak value of the sine function is 1, so the peak value of U is ...
100·1 = 100 V.
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(b)The argument of the sine function is 2πft, so f = 120πt/(2πt) = 60 Hz.
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(c)When t=0.020, the voltage is ...
U = 100sin(120π·0.020) = 100 sin(2.4π) ≈ 95.106 V
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(d)The resistors are in the ratio of 1 : 3, so divide the source voltage in that ratio.
The peak voltage across the 5Ω resistor is 1/4 of 100 V, or 25 V.
The peak voltage across the 15Ω resistor is 3/4 of 100 V, or 75 V.
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(e)The same fractions as in (d) apply to the instantaneous voltage.
The voltage on the 5Ω resistor is 1/4·95.106 V ≈ 23.776 V
The voltage on the 15Ω resistor is 3/4·95.106 V ≈ 71.329 V
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(f)See attached.