10. A boy of mass 55kg runs at 12m/s and hops on a 15kg skateboard that was at rest. What is thevelocity of the boy on the skateboard afterwards?

Answers

Answer 1

M = mass of the boy = 55kg

V = initial velocity of the boy = 12 m/s

m= mass of stationary skateboard = 15kg

v= velocity os stationary sketeboard= 0 m/s

V' = velocity of the boy on the skateboard after collision

Conservation of momentum:

MV + mv = (M + m) V'

Replacing:

55 kg * 12 m/s + 15 kg *0 = (55 kg+ 15 ) V'

Solve for V´'

660 = 70 V´'

660/70 = V'

V'= 9.42 m/s


Related Questions

what is the secret of a delightful pastry​

Answers

Answer:

✨ love ✨

words words words words words words words words words words words

Answer:

butter

Explanation:

Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93

Particles q +8.0 C, q2 +3.5 C, and93-2.5 C are in a line. Particles q and q2 areseparated by 0.10 m and

Answers

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)

Answers

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Three persons wants to push a wheel cart in the direction marked x in Fig. The two person push with horizontal forces F1 and F2 as F1 = 45 N 70degree And F2 = 75 N , 20 Degree (a) Find the magnitude and direction of the force that third person should exert to stop this cart. You can ignore the effects of friction. (b) If the third person exerts the force found in part (a), the cart accelerates at 200 m/S2 in the (+) x-direction. What is the weight of the cart​

Answers

Answer:

a)  F₃ = 109.5 N ,     θ₃ = 38.35,  b)   m = 0.429 kg

Explanation:

For this force addition exercise, let's decompose the forces into a coordinate system

strength 1

          cos 70 = F₁ₓ / F₁

          sin 70 = \(F_{1y}\) / F₁

          F₁ₓ = F₁ cos 70

         F_{1y} = F₁ sin 70

          F₁ₓ = 45 cos 70 = 15.39 N

          F_{1y} = 45 sin70 = 42.29 N

Strength 2

         cos 20 = F₂ₓ / F₂

         sin 20 = F_{2y} / F₂

         F₂ₓ = F₂ cos 20

         F_{2y} = F₂ sin20

         F₂ₓ = 75 cos 20 = 70.48 N

         F_{2y} = 75 sin 20 = 25.65 N

a) in the first part we are asked to find the magnitude of force 3 so that the body is in equilibrium

       

X axis

         ∑ Fₓ = 0

          F₁ₓ + F₂ₓ + F₃ₓ = 0

          F₃ₓ = - F₁ₓ - F₂ₓ

          F₃ₓ = - 15.39 - 70.48

          F₃ₓ = - 85.87 N

Y Axis

         ∑ F_{y}  = 0

         F_{1y} + F_{2y} +F_{3y}  = 0

         F_{3y} = - F_{1y} -F_{2y}

         F_{3y} = - 42.29 - 25.65

         F_{3y} = - 67.94 N

the magnitude of this force can be found using the Pythagorean theorem

         F₃ = √ (F₃ₓ² + F_{3y}^2)

         F₃ = √ (85.87² + 67.94²)

         F₃ = 109.5 N

The direction of this force can be found using trigonometry

          tan θ =  F₃ = \(F_{3y}\) / F₃ₓ

          θ₃ = Tan⁻¹ (67.94 / (85.87))

          θ₃ = 38.35º

since the two vectors are negative this angle is in the third quadrant, measured from the positive side of the x axis is

          θ₃ = 180 + 38.53

          θ₃ = 218.35º

b) I think you have an error in your statement, we have two possibilities:

1) If we eliminate the third force, what is the mass

it should say: "if we apply the third force force ...", they ask that we find the masses of the vehicle, let's use Newton's second law

X axis

       F₁ₓ + F₂ₓ = m a

       15.39 + 70.48 = m 200

        m = 85.87 / 200

        m = 0.429 kg

       

2) If the force F3 is in the first quadrant

        F1x + F2x + F3x = m a

         

        m = (15.39 + 70.48 + 85.87) / 200

        m = 0.8587 kg

Force is the amount _____ or _____ on an object



Motion is the action of _____ from one place to another place.

Force is the amount _____ or _____ on an object Motion is the action of _____ from one place to another

Answers

Answer:

force is the amount of work or pressure given to an object

motion is the action of moving one place to another place

The proper time between two events is measured by clocks at rest in a reference frame in which the two events: A. occur at the same time B. occur at the same coordinates C. are separated by the distance a light signal can travel during the time interval D. occur in Boston E. satisfy none of the above

Answers

The proper time between two events is measured by clocks at rest in a reference frame in which the two events occur at the same coordinates. (Option B)

In physics and astronomy, a frame of reference or reference frame refer to an abstract coordinate system whose origin, orientation, and scale are specified by a set of reference points which are geometric points whose position is identified both mathematically (with numerical coordinate values) and physically (signaled by conventional markers). Hence, the proper time between two events is measured by clocks at rest in a reference frame in which the two events occur at the same coordinates.

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a density glass both contain 44.25g of a liquid at 0°c and 42.02g of a liquid at 50°c.what is the real cubic expansivity of the liquid linear expansivity of glass is 1.0x10^_5k^_1.​

Answers

The real cubic expansivity of the liquid is 1.98 x 10^-4 K^-1.

Real cubic expansivity calculation.

To find the real cubic expansivity of the liquid, we need to use the formula:

β = (1/V) (dV/dT)

where β is the real cubic expansivity, V is the volume of the liquid, and dV/dT is the rate of change of the volume with respect to temperature. We can use the fact that the two samples have the same volume to eliminate V from the equation.

The change in mass of the liquid between 0°C and 50°C is:

Δm = 44.25 g - 42.02 g = 2.23 g

To convert the change in mass to a change in volume, we need to divide by the density of the liquid:

ρ = m/V

V = m/ρ

We can use the density of the liquid at 0°C to calculate the volume:

V = 2.23 g / (density of liquid at 0°C)

Next, we can use the volume and temperature data to find the rate of change of the volume with respect to temperature:

dV/dT = (V2 - V1) / (T2 - T1)

dV/dT = (V(50°C) - V(0°C)) / (50°C - 0°C)

Finally, we can substitute these values into the formula for β:

β = (1/V) (dV/dT)

β = (1/[(2.23 g) / (density of liquid at 0°C)]) [(V(50°C) - V(0°C)) / (50°C - 0°C)]

Simplifying this expression gives:

β = (density of liquid at 0°C) [(V(50°C) - V(0°C)) / (50°C - 0°C)] / 2.23 g

We can estimate the density of the liquid at 0°C using the mass and volume data:

density of liquid at 0°C = 44.25 g / V(0°C)

Substituting this into the expression for β gives:

β = [(44.25 g / V(0°C))] [(V(50°C) - V(0°C)) / (50°C - 0°C)] / 2.23 g

Simplifying this expression gives:

β = (V(50°C) - V(0°C)) / (50°C - 0°C) / V(0°C) x 44.25/2.23

β = (V(50°C) - V(0°C)) / (50°C x V(0°C)) x 19.8

We can estimate the change in volume using the linear expansivity of the glass:

ΔV = V(50°C) - V(0°C) = V(0°C) α ΔT

ΔV = V(0°C) (1.0 x 10^-5 K^-1) (50°C)

Substituting this into the expression for β gives:

β = [V(0°C) (1.0 x 10^-5 K^-1) (50°C)] / (50°C x V(0°C)) x 19.8

β = 1.0 x 10^-5 K^-1 x 19.8

β = 1.98 x 10^-4 K^-1

Therefore, the real cubic expansivity of the liquid is 1.98 x 10^-4 K^-1 using linear expansivity.

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When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?

Answers

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Lightning transfers charge between a charged cloud and the ground. If the voltage between the two is 1.3x108 V and 3.2 x109 J are transferred, find:A. The total charge moved between the two objectsB. The number of electrons transferred.C. The current, if the lightning strike takes 2.5x10-5 s.

Answers

Given data:

* The value of voltage is,

\(V=1.3\times10^8\text{ volts}\)

* The work done in transferring the charge is,

\(W=3.2\times10^9\text{ J}\)

* The time taken by the lightning to reach the ground is,

\(t=2.5\times10^{-5}\text{ s}\)

Solution:

(a). The voltage between the cloud and ground in terms of the charge transferred is,

\(V=\frac{W}{q}\)

where q is the charge transferred,

Substituting the known values,

\(\begin{gathered} 1.3\times10^8=\frac{3.2\times10^9}{q} \\ q=\frac{3.2\times10^9}{1.3\times10^8} \\ q=2.46\times10^{9-8} \\ q=24.6\text{ C} \end{gathered}\)

Thus, the amount of charge transferred between the cloud and ground is 24.6 C.

(b). The number of electrons transferred in terms of the net charge and fundamental charge is,

\(\begin{gathered} q=ne \\ n=\frac{q}{e} \end{gathered}\)

where e is the fundamental charge,

Substituting the known values,

\(\begin{gathered} n=\frac{24.6}{1.6\times10^{-19}} \\ n=15.38\times10^{19} \end{gathered}\)

Thus, the number of electrons transferred is,

\(15.38\times10^{19}\)

(c). The current stricks the ground while lightning is,

\(I=\frac{q}{t}\)

Substituting the known values,

\(\begin{gathered} I=\frac{24.6}{2.5\times10^{-5}} \\ I=9.84\times10^5\text{ A} \end{gathered}\)

Thus, the current striking the ground is,

\(\text{9}.84\times10^5\text{ A}\)

In the study of personality, what model includes different traits that underlie one’s basic tendencies

Answers

In the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

What is the Five-factor model?

The Five-factor model is a scientific theory that states traits of the personality of an individual are due to its biology and therefore they respond to adaptations, which are central in the biology field.

In conclusion, in the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

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assume that the initial speed is 25 m/s and the angle of projection is 53 degree above the hroizontal. the cannon ball leaves the uzzel of the cannon at a highet of 200 m.( the cannon is at the edge of the cliff) A: find the horizontal distance the cannon travles. B: when does the cannon ball reach the ground? C: find the maximum highet the cannon ball reaches.

Answers

Answer:

A.  xmax = 131.49 m

B.  t = 8.74 s

C.  ymax = 220.33 m

Explanation:

A. In order to find the horizontal distance which cannon travels you first calculate the flight time. The flight time can be calculated by using the following formula:

\(y=y_o+v_osin\theta-\frac{1}{2}gt^2\)      (1)

yo: height from the projectile is fired = 200m

vo: initial velocity of the projectile = 25m/s

g: gravitational acceleration = 9.8 m/s^2

θ: angle between the direction of the initial motion of the ball and the horizontal = 53°

t: time

You need the value of t when the projectile hits the ground. Then, in th equation (1) you make y = 0m.

When you replace the values of all parameters in the equation (1), you obtain the following quadratic formula:

\(0=200+(25)sin53\°t-\frac{1}{2}(9.8)t^2\\\\0=200+19.96t-4.9t^2\) (2)

You use the quadratic formula to obtain the value of t:

\(t_{1,2}=\frac{-19.96\pm\sqrt{(19.96)^2-4(-4.9)(200)}}{2(-4.9)}\\\\t_{1,2}=\frac{-19.96\pm65.71}{-9.8}\\\\t_1=8.74s\\\\t_2=-4.66s\)

You use the positive value because it has physical meaning.

Now, you can calculate the horizontal range of the projectile by using the following formula:

\(x_{max}=v_ocos\theta t\)      

\(x_{max}=(25m/s)(cos53\°)(8.74s)=131.49m\)

The cannon ball travels a horizontal distance of 131.49 m

B. The cannon ball reaches the canon for t = 8.74s

C. The maximum height is obtained by using the following formula:

\(y_{max}=y_o+\frac{v_o^2sin^2\theta}{2g}\)     (3)

By replacing in the equation (3) the values of all parameters you obtain:

\(y_{max}=200m+\frac{(25m/s)^2(sin53\°)^2}{2(9.8m/s^2)}\\\\y_{mac}=200m+20.33m=220.33m\)

The maximum height reached by the cannon ball is 220.33m

Newton’s first law explains why roller coasters? A:starts with a big hill. B: can cause damage to the human body C:need constant pulling to stay moving. D are fun.

Answers

Newton’s first law explains why roller coasters option C. need constant pulling to stay moving.

What is Newton's first law?

Newton's first law states that an object at rest will remain at rest and an object in motion will remain in motion with the same speed and in the same direction unless it is acted upon by an external force.

Therefore, for a roller coasters to keep moving there should be a constant pulling to stay moving. It could be concluded that the correct answer is as given above.

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(b) Figure 11.1 shows a uniform meter rule balanced horizontally on a knife-edge placed at the 58cm mark when a mass of 20g is suspended from the end. 0cm 58cm Figure 11.1 (i) Find the mass of the rule. (ii) What is the weight of the rule. (taking g = 10m/s²)? 100cm 20g [2] [2]​

Answers

The mass of the rule is 3.36 kg and the weight of the rule is 33.6 N.

A knife should be balanced somewhere, right?

The butt of the blade is designed to balance the majority of fine chef's knives. This is due to the fact that a pinch grip is used in both Western and Eastern cutting styles for improved control. Therefore it makes sense that you'd want your knife to be balanced where you'll be holding it.

To balance the meter rule, Assume the mass of the rule "M".

It is possible to determine the rule's magnitude and weight, which act downward:

weight of rule = M * g

where g = acceleration due to gravity.

weight of rule * (50 cm) = (20 g) * (100 cm - 58 cm)

M * g * (50 cm) = (20 g) * (42 cm)

M = (20 g * 42 cm) / (50 cm * g)

M = 33.6 g / g

M = 33.6 g / 10 m/s^{2}

M = 3.36 kg

(ii) The weight of the rule:

weight of rule = M * g

weight of rule = 3.36 kg * 10 m/s^{2}

weight of rule = 33.6 N

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5. Brownian motion of smoke particles a) State and explain the observation. b) State and explain what will be observed if the temperature surrounding the smoke cell is increased: What is the function of Microscope,Lens and Smoke​

Answers

(A) When an air particle bombards a smoke particles, the smoke particle moves to the same direction as the air particle that hit it. When another air particle hits the smoke particle, it changes its direction to that of the second air particle, and so on. This is called Brownian motion.

(B) If the temperature of the surroundings is increased the air particles would gain kinetic energy resulting in more frequent collisions with the smoke particles. Therefore, the smoke particles would be seen moving haphazardly.

(C) The microscope helps magnify the smoke particles for a much more better observation. The lens help in focusing. As the air particles are really small and cannot be observed; therefore, smoke particles are used as they are easy to see and observe; thus, ensuring a better experiment.

How original were Newton’s contributions to science? (In what ways did Newton depend on the mechanical view?)

Answers

Newton's new “reflecting telescope” was more powerful than ... Before Newton, scientists primarily adhered to ancient theories on ... laws of motion laid the groundwork for classical mechanics. Newton's research on motion helped give credibility to the heliocentric view. Newton also helped pioneer telescopic innovations, and he is sometimes credited with inventing the first reflecting telescope. He also conducted experiments using the prism, and developed a theory about the nature of color and light.

Example

A 1.8 m tallman stand in an elevator accelerating upward at 12 m/s?,

what is the blood pressure in the brain and foot.

Take the height difference between the heart and the brain to be

0.35 m?

13.3 x 103 Pa] & [Pblood = 1060 kg.m-3]

Note: [: P Heart

Answers

Answer:

Explanation:

From the given information; the diagram below shows a clearer understanding.

The blood pressure in the brain \(P_{brain} = P_{heart} - \delta ( a - g ) h\)

= 13300 - 1060 (12-9.81) 0.35

=  13300 -  1060 (2.19) 0.35

= 13300 - 812.49

= 12487.51  Pa

The blood pressure in the feet \(P_{feet} = P_{heart} + \delta (a + g) h\)

= 13300 + 1060 (12 + 9.81) 1.45

= 13300 + 1060( 21.81 ) 1.45

= 13300 + 33521.97

= 46821.97 Pa

ExampleA 1.8 m tallman stand in an elevator accelerating upward at 12 m/s?,what is the blood pressure

Answer:

The blood pressure in the brain = \(12487.51 pa\)The blood pressure in the feet = \(46821.97pa\)

Explanation:

\(P_brain = P_heart - y(a - g)h\\\\P_brain = 13300 - 1060 (12-9.81)0.35\\\\P_brain = 12487.51 pa\\\\\)

\(P_feet = P_heart + y(a+g)*h_r\\\\P_feet = 13300 + 1060(12+9.81)*(1.8-0.35)\\\\P_feet = 46821.97pa\)

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Describe a situation in which these two velocity vectors are different. Use complete sentences.

Answers

When acceleration is equal to zero average velocity and the instantaneous velocity vectors are identical.

Types of velocity

Velocity is defined as the rate of displacement of an object with respect to time. It is measured in meter/ seconds and is a vector quantity.

Acceleration is defined as the rate at which velocity changes with time.

There are two types of velocity which includes:

Average velocity: This is the average rate of change of position of particles with respect to time over an interval.

Instantaneous velocity: This is defined as the specific rate of change of position with respect to time at a particular point.

The situation that will make the average velocity and the instantaneous velocity vectors to be equal or identical is when acceleration is equal to zero.

Steven and Candace want to create an environment for their children to help protect them from risk behaviors and emotional problems. What is the BEST thing for them to do?

Answers

For Steven and Candace to help their children against emotional issues and risk behaviors, the best thing both of them can do set high expectations for their children for their education.

What are emotional problems?

Emotional problems are those problems which affect us mentally as a result of our weakness to stand being stretched to certain life issues. We can say that a student whose admission was withdrawn from an institution due to low academic performance might deal with certain emotional issues. This will technically make them more focus, determined and take their mind off such problems.

So therefore, helping ones children to aim high in their academic pursuits can help protect them from risk behaviors and sone emotional problems.

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The radius of the circular path of an ion in a mass spectrometer is given by r=1/B √2Vaccelm/q. Use this equation to explain how a mass spectrometer is able to separate ions of different masses.

The radius of the circular path of an ion in a mass spectrometer is given by r=1/B 2Vaccelm/q. Use this

Answers

The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path

What is the mass spectrometer?

From the formula in the question;

B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.

The accelerating voltage used to move the ions is called Vaccelm.

The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.

The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.

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What happens to the mechanical advantage of a machine if the output force is less than the input force? What must happen to output distance? Give an example of a machine that does this?

Answers

a machine that put in force is a Mechanical

Two parallel wires are separated by 6.10 cm, each carrying 2.85 A of current in the same direction. (a) What is the magnitude of the force per unit length between the wires

Answers

Answer:

The force per unit length is \(2.66 \times 10^{-5} \ N/m\)

Explanation:

The current carrying by each wires = 2.85 A

The current in both wires flows in same direction.

The gap between the wires = 6.10 cm

Now we will use the below expression for the force per unit length. Moreover, before using the below formula we have to change the unit centimetre into meter. So, we just divide the centimetre with 100.

\(F/l = \frac{\mu _0i_1 i_2}{2\pi d} \\i_1 = 2.85 \\i_ 2 = 2.85 \\\mu _0 = 4\pi \times 10^{-7} \\d = 0.061 \\F/l = \frac{4\pi \times 10^{-7} \times 2.85 \times 2.85}{2 \pi \times 0.061} \\= 2.66 \times 10^{-5} \ N/m\)

Recall specific heat of water is 4186 j/kg/C. Find the specific heat of sample.
Water. Sample
Mass 109 192
Internal temperature. 21. 67
Final temperature. 30.1. 30.1

Answers

Answer:

Shown by explanation;

Explanation:

The heat of the sample = mass ×specific heat capacity of the sample × temperature change(∆T)

Assumption;I assume the mass of the samples are : 109g and 192g

∆T= 30.1-21=8.9°c.

The heat of the samples are for 109g are:

0.109 × 4186 × 8.9 =4060.84J

For 0.192g are;

∆T= 67-30.1-=36.9°c

0.192 × 4186×36.9=29656.97J

Suppose a ball is thrown vertically upward (positive direction) from an initial height LaTeX: h_0 with initial velocity LaTeX: v_0. Find the position function LaTeX: s(t) of the ball after LaTeX: t seconds assuming the gravitational acceleration LaTeX: g is a positive constant pointing downward (negative direction).

Answers

After time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The given parameters;

initial velocity of the ball, = \(v_0\)initial position of the ball, = \(h_0\)acceleration due to gravity, = g

The position function of the ball after time t, is calculated as follows;

\(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The negative sign of acceleration of due to gravity is because the ball is moving upward against gravity.

Thus, after time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

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A package is dropped from an air balloon two times. In the first trial the distance between the balloon and the surface is Hand in the second trial 4H. Compare the FINAL VELOCITY'S for the packages right as they hit the
ground (or right before)?

Answers

Answer:

The final speed of the second package is twice as much as the final speed of the first package.

Explanation:

Free Fall Motion

If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:

\(v=gt\)

And the distance traveled downwards is:

\(\displaystyle y=\frac{gt^2}{2}\)

If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:

\(\displaystyle t=\sqrt{\frac{2y}{g}}\)

Replacing into the first equation:

\(\displaystyle v=g\sqrt{\frac{2y}{g}}\)

Rationalizing:

\(\displaystyle v=\sqrt{2gy}\)

Let's call v1 the final speed of the package dropped from a height H. Thus:

\(\displaystyle v_1=\sqrt{2gH}\)

Let v2 be the final speed of the package dropped from a height 4H. Thus:

\(\displaystyle v_2=\sqrt{2g(4H)}\)

Taking out the square root of 4:

\(\displaystyle v_2=2\sqrt{2gH}\)

Dividing v2/v1 we can compare the final speeds:

\(\displaystyle v_2/v_1=\frac{2\sqrt{2gH}}{\sqrt{2gH}}\)

Simplifying:

\(\displaystyle v_2/v_1=2\)

The final speed of the second package is twice as much as the final speed of the first package.

How are the two types of power plants similar how are they different

Answers

Answer:

iIn a nuclear plant, the heat source is from the nuclear reaction whereas in a thermal power plant it is from the combustion of coal. The difference is in the inlet steam parameters to the turbine in a nuclear plant. Thermal power plants use steam at superheated conditions. ... The nuclear plant uses a 'wet steam turbine'.

Explanation:

The heat source in a nuclear power plant is the nuclear reaction, whereas the heat source in a thermal power plant is coal combustion. The difference is in the turbine's input steam characteristics.

What is a power plant?

Power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.

Nuclear power bare a form of thermal power plant. You have a reactor where fission takes place and heat is generated, a heat exchanger that transports this heat to where it is needed.

Thermal power plant equipment converts this heat into electric energy, usually via a steam turbine.

The reactor, heat exchanger, and thermal conversion technology all have different designs and technologies, but the overall architecture is quite similar to other types of thermal power plants.

The heat source in a nuclear power plant is the nuclear reaction, whereas the heat source in a thermal power plant is coal combustion. The difference is in the turbine's input steam characteristics.

Hence, the two types of power plants differ in  difference is in the turbine's input steam characteristics.

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In a Young's double-slit experiment the separation distance y between the second-order bright fringe and the central bright fringe on a flat screen is 0.0176 m, when the light has a wavelength of 425 nm. Assume that the angles are small enough so that is approximately equal to . Find the separation y when the light has a wavelength of 614 nm.

Answers

Answer:

Y = 0.0254 m = 25.4 mm

Explanation:

The formula for the fringe spacing in Young's Double-slit experiment is given by the following formula:

\(Y = \frac{\lambda L}{d}\)

where,

Y = fringe spacing = 0.0176 m

λ = wavelength = 425 nm = 4.25 x 10⁻⁷ m

L = Distance between screen and slits

d = slit separation

Therefore,

\(\frac{0.0176\ m}{4.25\ x\ 10^{-7}\ m} = \frac{L}{d}\\\\\frac{L}{d} = 41411.76\)

Now, for:

λ = 614 nm = 6.14 x 10⁻⁷ m

\(Y = (6.14\ x\ 10^{-7}\ m)(41411.76)\\\)

Y = 0.0254 m = 25.4 mm

11 A group of students are conducting an investigation about charging through the process of friction. The students rub
two neutral materials together, and there is a transfer of electrical charge from one material to the other. What is the
resulting, net electrical charge of the materials in this system?
The net electrical charge is positive as electrons are transferred from
one material to the other.
B The net electrical charge is positive as protons are transferred from
one material to the other.
The net electrical charge remains neutral as Electrons are transferred
from one material to the other.
The net electrical charge remains neutral as protons are transferred
from one material to the other.
Black. They

Answers

The resulting net electrical charge of the materials in this system is C: The net electrical charge remains neutral as electrons are transferred from one material to the other.

When two neutral materials are rubbed together, friction can cause the transfer of electrons from one material to another. Electrons, which carry a negative charge, can move from one material to the other during this process. However, it is important to note that the total number of electrons in the system remains the same.

Since electrons are transferred from one material to the other, the material that gains electrons becomes negatively charged, and the material that loses electrons becomes positively charged. These charges balance each other out, resulting in a neutral net electrical charge for the overall system.

Therefore, the net electrical charge of the materials in this system remains neutral, even though there is a transfer of electrons between them. Therefore, Option C is correct.

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Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweezers is 1000 W/m2, the same as the intensity of sunlight at the surface of the Earth. (a) What is the pressure on an atom if light from the tweezers is totally absorbed

Answers

Answer:

a= 4.4×10 m/s^2

Explanation:

pressure P  = E/c

Where, E = 100 W/m^2 intensity of light

c= speed of light  = 3×10^8 m/s

P = 1000/ 3×10^8

P = 3.33×10^(-6) Pa

Force F = P×A

P is the pressure and c= speed of light

F = 3.33×10^{-6}×6.65×10(-29)

= 2.22×10^{-6}

acceleration a  = F/m = 2.22×10^{-6}/ 5.10×10^{-27}

a= 4.4×10 m/s^2

The air of an average sneeze travels around 100 miles an hour. Rebecca believes a sneeze induced by a stimulant will produce air that travels at a faster speed than the typical 100 miles per hour. She designs an experiment to induce sneezing. She subjects four participants to different stimulants: pepper, bright light, pollen, and fizzy soda. Once a sneeze is induced, Rebecca measures how fast the air traveled through the nasal passage.

Which statement WOULD NOT be an appropriate hypothesis for Rebecca's experiment?
A Induced sneezes move air at a faster speed than naturally occurring sneezes.
B There is no difference in air speed of induced versus naturally occurring sneezes.
C Using pepper as a stimulant induces more sneezing than any other stimulants.
D All sneezes move air at the same rate of speed.

Answers

Based on the study conducted by Rebecca, the statement that would not be an appropriate hypothesis for Rebecca's experiment is:

Using pepper as a stimulant induces more sneezing than any other stimulant; option C

What is a hypothesis?

A hypothesis is an explanation that is given in the form of a statement to explain an observation based on limited evidence and which serves as a starting point for further investigation.

A hypothesis may or may not be true and must be investigated to prove or disprove it.

Experiments are conducted to prove or disprove a given hypothesis.

A hypothesis is divided into a null and an alternate hypothesis.

A null hypothesis is a hypothesis that state that the treatment given to the subjects of the experiment does not produce any significant effect.

An alternate hypothesis states that the treatment given to the subjects of the experiment produces significant effects on the subjects.

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PLEASE HELP IF YOUR GOOD AT PHYSICS!!!The speed of a bullet train is measured to be 312.0 mph 3.9 mph. What is the percent
uncertainty in this measurement? A) 1.3% B) 1.25% C) 1.2% D) 0.0125%

Answers

Answer: D

Explanation:

If the speed of a bullet train is measured to be 312.0 mph ± 3.9 mph. then the uncertainty in this measurement would be 1.25 %

What is the percentage of a number?

It is the relative value that represents the hundredth part of any number for example 2% of any number represents, 2 multiplied by the 1/100th of that number.

Let us understand with help of one more example as follows

7.5 % of 100 is equal to 7.5 which means, 7.5 times the 1/100th of the 100

For the given problem we have to calculate the uncertainty in this measurement, If the speed of a bullet train is measured to be 312.0 mph ± 3.9 mph.

uncertainty in this measurement = 3.9 ×100/ 312.0

                                       = 1.25 %

Thus, If the speed of a bullet train is measured to be 312.0 mph ± 3.9 mph. then the uncertainty in this measurement would be 1.25 %

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