2/5x + 1 = x + 1/2
Please give answers for this

The rotation rule used in this problem is given as follows:

90º counterclockwise rotation.

The five more known rotation rules are given as follows:

The equivalent vertices for this problem are given as follows:

Hence the rule is given as follows:

(x,y) -> (-y,x).

Which is a 90º counterclockwise rotation.

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Using the triangle inequality theorem, the largest possible whole-number length for the third side is 4.

The third side of a triangle must be shorter than the sum of the other two sides and longer than the difference between the other two sides.

So, for a triangle with sides of length 1, 4, and x (where x is the length of the third side), we have:

1 + 4 > x

4 + x > 1

1 + x > 4

Simplifying these inequalities, we get:

5 > x

x > 3

x > -3 (this inequality is always true)

The largest possible whole-number length for the third side is 4, since it is the largest integer that satisfies the above inequalities.

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Answer:

A

Step-by-step explanation:

A 95% rate of something means adding or subtracting the standard deviation twice from the answer.

Answer:

23

Step-by-step explanation:

Answer:

23

Step-by-step explanation:

Replace all Xs with 3

Answer: (x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2

Step-by-step explanation: Step by Step Solution

More Icon

STEP

1

:

Equation at the end of step 1

((((((((((((((x-4)•(x-1)•(x+2))•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

2

:

Equation at the end of step 2

(((((((((((((x-4)•(x-1)•(x+2)•(x+3))•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

3

:

Equation at the end of step 3

((((((((((((x-4)•(x-1)•(x+2)•(x+3)•(x-4))•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

4

:

Multiplying Exponential Expressions:

4.1 Multiply (x-4) by (x-4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-4) and the exponents are :

1 , as (x-4) is the same number as (x-4)1

and 1 , as (x-4) is the same number as (x-4)1

The product is therefore, (x-4)(1+1) = (x-4)2

Equation at the end of step

4

:

(((((((((((x-4)2•(x-1)•(x+2)•(x+3)•(1-x))•(x+2))•(x+3))•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

5

:

5.1 Rewrite (1-x) as (-1) • (x-1)

Multiplying Exponential Expressions:

5.2 Multiply (x-1) by (x-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-1) and the exponents are :

1 , as (x-1) is the same number as (x-1)1

and 1 , as (x-1) is the same number as (x-1)1

The product is therefore, (x-1)(1+1) = (x-1)2

STEP

7

:

Pulling out like terms

7.1 Pull out like factors :

-x - 2 = -1 • (x + 2)

Multiplying Exponential Expressions:

7.2 Multiply (x + 2) by (x + 2)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+2) and the exponents are :

1 , as (x+2) is the same number as (x+2)1

and 1 , as (x+2) is the same number as (x+2)1

The product is therefore, (x+2)(1+1) = (x+2)2

STEP

9

:

Pulling out like terms

9.1 Pull out like factors :

-x - 3 = -1 • (x + 3)

Multiplying Exponential Expressions:

9.2 Multiply (x + 3) by (x + 3)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+3) and the exponents are :

1 , as (x+3) is the same number as (x+3)1

and 1 , as (x+3) is the same number as (x+3)1

The product is therefore, (x+3)(1+1) = (x+3)

((((((((x-4)2•(x-1)2•(x+2)2•-1•(x+3)2•(x+4))•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

10

:

Equation at the end of step 10

(((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1))•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

11

:

STEP

12

:

Pulling out like terms

12.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Equation at the end of step

12

:

((((((x-4)2•(x-1)2•(x+2)2•(x+3)2•(-x-4)•(x+1)•(2-x))•(3-x))•(x+4))•(x+1))•(2-x))•(x-3)

STEP

13

:

STEP

14

:

Pulling out like terms

14.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Equation at the end of step

14

STEP

15

STEP

16

:

Pulling out like terms

16.1 Pull out like factors :

-x - 4 = -1 •

Equation at the end of step

16

:

STEP

17

:

STEP

18

:

Pulling out like terms

18.1 Pull out like factors :

-x - 4 = -1 • (x + 4)

Multiplying Exponential Expressions:

18.2 Multiply (x + 4) by (x + 4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+4) and the exponents are :

1 , as (x+4) is the same number as (x+4)1

and 1 , as (x+4) is the same number as (x+4)1

The product is therefore, (x+4)(1+1) = (x+4)2

Equation at the end of step

18

:

(((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(-x-1)•(2-x)•(3-x)•(x+1))•(2-x))•(x-3)

STEP

19

:

STEP

20

:

Pulling out like terms

20.1 Pull out like factors :

-x - 1 = -1 • (x + 1)

Multiplying Exponential Expressions:

20.2 Multiply (x + 1) by (x + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+1) and the exponents are :

1 , as (x+1) is the same number as (x+1)1

and 1 , as (x+1) is the same number as (x+1)1

The product is therefore, (x+1)(1+1) = (x+1)2

Equation at the end of step

20

:

((x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)•(3-x)•(2-x))•(x-3)

STEP

21

:

21.1 Rewrite (2-x) as (-1) • (x-2)

Multiplying Exponential Expressions:

21.2 Multiply (x-2) by (x-2)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-2) and the exponents are :

1 , as (x-2) is the same number as (x-2)1

and 1 , as (x-2) is the same number as (x-2)1

The product is therefore, (x-2)(1+1) = (x-2)2

22.1 Multiply (x-3) by (x-3)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-3) and the exponents are :

1 , as (x-3) is the same number as (x-3)1

and 1 , as (x-3) is the same number as (x-3)1

The product is therefore, (x-3)(1+1) = (x-3)2

Final result :

(x-4)2•(x-1)2•(x+2)2•(x+3)2•(x+4)2•(x+1)2•(x-2)2•(x-3)2

The triangle ABC and XZY are proved to be congruent by SAS.

Congruence of triangles: Two triangles are supposed to be harmonious assuming each of the three comparing sides are equivalent and every one of the three relating angle are equivalent in measure. These triangles can be slides, pivoted, flipped and went to be seemed to be indistinguishable.

By the rule of SAS which means, Two sides are equal thhen the angle between the two sides is also equal (SAS: side, angle, side)

BC=YZ

AC=XZ

∠ACB=∠XZY

By SAS ΔABC≅ΔXYZ

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Cohen's conventions for interpreting d, this effect is small. Therefore, the correct answer is a. small.

According to Cohen's conventions for interpreting the effect size (d), the effect described in the study is considered "small." Cohen's conventions provide a general guideline for categorizing the magnitude of an effect size.

In this case, the effect size (d) is calculated to be 0.02. Cohen's conventions typically classify effect sizes as follows:

Small effect: d = 0.2

Medium effect: d = 0.5

Large effect: d = 0.8

Since the effect size of 0.02 is significantly smaller than the threshold for a small effect (0.2), it falls into the "small" category. This means that the difference in the number of words uttered per day between men and women, as reported in the study, is relatively small or negligible in practical terms.

Therefore, the correct answer is a. small.

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Answer:

Exact answer: 1/3   Decimal Form : 0.3

Step-by-step explanation:

Answer:

A = 7

Step-by-step explanation:

√50 = 7.07

approximating it will give you

= 7

The main features of a case-control study is that:
A. It is generally used for exploring the rare diseases
C. The comparison groups are those with a disease and those without the disease
D. Once the comparison groups are identified, the exposure history can be obtained easily.

The correct answers are C and D. A case-control study compares individuals with a particular disease (cases) to those without the disease (controls) and investigates the potential exposures or behaviors that may have contributed to the development of the disease.

Therefore, the comparison groups are those with the disease and those without the disease, and once these groups are identified, the exposure history is obtained. The study is not limited to health exposures and behaviors but rather focuses on any potential risk factors. Case-control studies are often used to explore rare diseases because they are more efficient in identifying potential risk factors than cohort studies.
While case-control studies can be limited in some aspects, they are valuable for examining health exposures and behaviors in relation to health outcomes, rather than being limited to only one or the other.

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we know that 76% of the specialty soaps are made with fresh herbs, and we also know that there are a total of 350 specialty soap bars, so how many are made with fresh herbs?  well, just 76% of those 350

\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{76\% of 350}}{\left( \cfrac{76}{100} \right)350}\implies 266\)

If she plays in a game in which she shoots 7 free throws, the probability that she will make all 7 = 0.0188

For given question,

a basketball player makes approximately 69% of free throws.

So, the probability of success (p) = 0.69

the probability of failure (q) = 0.31

She plays in a game in which she shoots 7 free throws.

So, n = 7

We need to find the probability that she will make all 7.

Using Binomial probability Distribution,

For x = 7,

\(P(x = 7) =~ ^7C_7\times (0.67)^7\times (0.31)^{7-7}\\\\P(x=7)= 1\times 0.0606\times 0.31\\\\P(x=7)=0.0188\)

Therefore,  if she plays in a game in which she shoots 7 free throws, the probability that she will make all 7 = 0.0188

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Answer:

0.25 liter

Step-by-step explanation:

In the given system of equations one taco costs $0.80 and one burrito costs $0.72.

An equation system is a finite collection of equations for which we searched for the common solutions. It is sometimes referred to as a set of simultaneous equations or an equation set. The classification of a system of equations is similar to that of a single equation. In modelling issues where the unknown values may be expressed in the form of variables, a system of equations finds use in everyday life.

Let us suppose the cost of one taco = x.

Let us suppose the cost of one burrito = y.

Then, for Emma we have:

3x + y = 3.65

For Cooper we have:

x + 2y = 3.30

Using elimination, multiply the first equation by 2 and subtract it from the second equation:

(2)(3x + y = 3.65)

6x + 2y = 7.30

x + 2y = 3.30

-5x = -4

x = 4/5

Substituting this value of x into either equation:

3(4/5) + y = 3.65

y = 2.15/3 ≈ 0.72

Therefore, one taco costs $0.80 and one burrito costs $0.72.

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Answer:

-6

Step-by-step explanation:

Some nasty order of operations coming up.

Firstly, deal with that squared:

-12 / 3 * (-8 + 16 - 6) + 2

Simplify the bracket:

-12 / 3 * 2 + 2

Simplify -12 / 3:

-4 * 2 + 2

Simplify -4 * 2:

-8 + 2

Simplify:

-6

Answer:

my nut is ytellow

Step-by-step explanation:

This graph is position-time graph.

The initial displacement οf the weight is 40cm

The weight first returns tο equilibrium when t = 1/2

In computer science and mathematics, a graph is a collection of vertices (also known as nodes or points) connected by edges (also known as links or lines).

Based on the given Graph, we can say that the graph represents a position-time graph of a weight attached to a spring.

The initial position of the weight is 40cm as given in tha graph,

We can determine the time at which the weight first reaches equilibrium.

Equilibrium occurs when the weight is at rest and has zero velocity.

This corresponds to the position of the weight being zero, i.e., p(t) = 1/2 cm. The problem states that we say the weight is at equilibrium when p(t) = 1/2 cm.

Therefore, the weight first reaches equilibrium at the time t when p(t) = 1/2 cm.

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Complete question:

The weight is initially positioned at a certain distance in centimeters, which is not stated in the query. To ascertain this number, we would need to examine the graph or receive additional information.

Based on the information given, we can say the following:

The graph of the function is a function, which means that each input (time value) corresponds to exactly one output (position value).

The initial position of the weight is some number of centimeters, which is not specified in the question. We would need to look at the graph or be given more information to determine this value.

The weight first reaches equilibrium when the position is 0 cm, which means that the function value is 0. We can find the time(s) when this occurs by solving the equation p(t) = 0.

For example, if the equation is  \(p(t) = 3sin(2t) - 2, we can set 3sin(2t) - 2 = 0\)   and solve for   \(t: 3sin(2t) = 2, sin(2t) = 2/3, 2t = sin^-1(2/3) + 2πn or π - sin^-1(2/3) + 2πn\) for some integer  \(n, t = (sin^-1(2/3) + 2πn)/2 or (π - sin^-1(2/3) + 2πn)/2\)  For some integer n.

The initial position of the weight is its position when t = 0 s, which means we need to look at the value of p(0). Again, this value is not given in the question.

Therefore, Without more information or a graph of the function, we cannot provide specific values for these unknowns.

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The given question is incomplete. The complete question is given below:

The function (p(t)) gives the position of the weight at time (t). Please complete the following sentences based on the graph of the function. The graph is a function. The initial position of the weight is __________ centimeters. The weight first reaches equilibrium when t equals __________ second(s). Note: We say that the weight is at equilibrium whenever p(t) = 0 cm, and we say that the initial position of the block is its position when t = 0 seconds.

Answer:

24/35 or 0.6857142

Step-by-step explanation:

Answer:

\( \frac{24}{35} \)

alternative form:

\( 0.685714286 \)

Step-by-step explanation:

\(1 \frac{1}{7} \times \frac{3}{5} \\ multiply \: 1 \: and \: 7 \\ \\ \frac{7 + 1}{7} \times ( \frac{3}{5} ) \\ add \: 7 \: to \: 1 \\ \\ \frac{8}{7} \times ( \frac{3}{5} ) \\ remove \: parenthesis \: and \: put \\numerator \: times \: numerator \: and \\ denominator \: times \: denominator \\ \\ \frac{8 \times 3}{7 \times 5} \\ do \: the \: multiplications \\ \\ \frac{24}{35} \)

Answer:

\(-\frac{22}{91} = x\)

Step-by-step explanation:

To solve the equation \(3x - 23 = 94x - 1\), we'll follow these steps:

Start by simplifying the equation by combining like terms. In this case, we have terms with x on both sides, as well as constants:

\(3x - 23 = 94x - 1\)

To isolate the x terms, we can subtract 3x from both sides of the equation:

\(3x - 3x - 23 = 94x - 3x - 1\)

Simplifying further, we get:

\(-23 = 91x - 1\)

Next, we want to isolate the constant term on one side of the equation. We can do this by adding 1 to both sides:

\(-23 + 1 = 91x - 1 + 1\)

Simplifying further:

\(-22 = 91x\)

Finally, we can solve for x by dividing both sides of the equation by 91:

\(-\frac{22}{91}=\frac{91x}{91}\)

Simplifying further:

\(-\frac{22}{91} = x\)

Therefore, the solution to the equation \(3x - 23 = 94x - 1\) is \(-\frac{22}{91} = x\)

It can be evaluated using the limit comparison test or by integrating 1/\(x^3\) directly to get -1/2\(x^2\) evaluated from 1 to infinity, Therefore, the integral converges to 1/2.

The integral can be written as:

∫₁^∞ 1/x³ dx

To determine whether the integral converges or diverges, we can use the p-test for integrals. The p-test states that:

If p > 1, then the integral ∫₁^∞ 1/xᵖ dx converges.

If p ≤ 1, then the integral ∫₁^∞ 1/xᵖ dx diverges.

In this case, p = 3, which is greater than 1. Therefore, the integral converges.

To evaluate the integral, we can use the formula for the integral of xⁿ:

∫ xⁿ dx = x (n+1)/(n+1) + C

Using this formula, we get:

∫₁^∞ 1/x³ dx = lim┬(t→∞)⁡(∫₁^t 1/x³ dx)

             = lim┬(t→∞)⁡[ -1/(2x²) ] from 1 to t

             = lim┬(t→∞)⁡( -1/(2t²) + 1/2 )

             = 1/2

Therefore, the integral converges to 1/2.

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To determine if this integral converges or diverges, we can use the p-test. According to the p-test, if the integral of the form ∫1∞ 1/x^p dx is less than 1, then the integral converges. If the integral is equal to or greater than 1, then the integral diverges.

In this case, p=3, so we have ∫1∞ 1/x^3 dx = lim t→∞ ∫1t 1/x^3 dx.

Evaluating the integral, we get ∫1t 1/x^3 dx = [-1/(2x^2)]1t = -1/(2t^2) + 1/2.

Taking the limit as t approaches infinity, we get lim t→∞ [-1/(2t^2) + 1/2] = 1/2.

Since 1/2 is less than 1, we can conclude that the given improper integral converges.

Therefore, the value of the integral is ∫1∞ 1/x^3 dx = 1/2.
To determine whether the improper integral converges or diverges, we need to evaluate the integral and see if it results in a finite value. Here's the given integral:

∫(1 to ∞) (1/x^3) dx

1. First, let's set the limit to evaluate the improper integral:

lim (b→∞) ∫(1 to b) (1/x^3) dx

2. Next, find the antiderivative of 1/x^3:

The antiderivative of 1/x^3 is -1/2x^2.

3. Evaluate the antiderivative at the limits of integration:

[-1/2x^2] (1 to b)

4. Substitute the limits:

(-1/2b^2) - (-1/2(1)^2) = -1/2b^2 + 1/2

5. Evaluate the limit as b approaches infinity:

lim (b→∞) (-1/2b^2 + 1/2)

As b approaches infinity, the term -1/2b^2 approaches 0, since the denominator grows without bound. Therefore, the limit is:

0 + 1/2 = 1/2

Since the limit is a finite value (1/2), the improper integral converges. Thus, the integral evaluates to:

∫(1 to ∞) (1/x^3) dx = 1/2

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So on solving the provided question we cans say that factors of  4y^2=81 are - y = +9/4 and - 9/4

Any natural number other than 1 with just itself and the number 1 as its divisors is considered a prime factor. Actually, 2, 3, 5, 7, 11, and so on are some of the first prime numbers. an amount that has been multiplied to produce another amount. By dividing 15 by 3 and 5, for instance, we get 3 5 = 15. main elements: Prime factors include all factors that are prime but are not composite. A few prime factors of 30 are 2, 3, and 5. Only 2 and 3 are prime factors of 12, so listing 2 twice as 2 2 3 (or 22 3) is necessary to factorize 12. The sum of 2 + 3 is not 12.

factors of  4y^2=81

are -

y = +9/4 and - 9/4

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Step-by-step explanation:

Hey there!

Here;

The given points are; (6,5) and (9,p).

Slope (m)= -4

Use slope formula;

\(m = \frac{y2 - y1}{x2 - x1} \)

Put all values.

\( - 4 = \frac{p - 5}{9 - 6} \)

Simplify it to get answer.

\( - 4 = \frac{p - 5}{3} \)

\( - 12 + 5 = p\)

Therefore, p= -7.

Hope it helps...

Answer:

.

Step-by-step explanation:

............................

Answer:

your answer is 25.9 units

Step-by-step explanation:

I just did this and got 100%. Have a good day!

Answer:

26

Step-by-step explanation:

1/6 of 36 is 6

1/9 of 36 is 4

6+4=10

36-10= 26

Answer:

26 cakes

Step-by-step explanation:

36 divided by 6 = 6

30 - 6 = 24

36 divided by 9 = 4

6 + 4 = 10

36 - 10 = 26

Hopefully this helps you :)

pls give me brainlest  ;)

Answer:

∠A = 120° (180°-60°)

∠W = 60° (b/c ∠W=∠X)

∠Y = 100° (b/c 180°-80°)

∠X = 60° (180°-120°)

∠Z = 120° (180-60°)

Step-by-step explanation:

im unsure about A and W

Answer:

1/10

Step-by-step explanation:

she ran 1 mile per 10 minutes so its 1/10

Answer:

1/3

Step-by-step explanation:

\(g(f(x))=x \\ \\ g'(f(x))f'(x)=1 \\ \\ g'(f(x))=\frac{1}{f'(x)} \\ \\ g'(f(x))=\frac{1}{\cos x+2} \\ \\ g'(f(0))=\frac{1}{\cos(0)+2} \\ \\ g'(1)=\frac{1}{3}\)