27-12+4. Please read description.

Description:
This is kinda embarrassing to ask...but I keep getting different answers!
Some calculators say it's 19, but when I work it out, I can only get 11!.

So I add 12+4 to get 16.
Then I subtract from 27 and get ll.
Please help and explain what I'm doing wrong please help. I use PEMDAS btw

Answer:

It would i feel like its 132

Step-by-step explanation:

The balance in the fund at the end of 23 years, with monthly deposits of $1,150 and a 3.25% annual interest rate, is approximately $449,069.51. The amount of interest earned over the period is approximately $420,630.49.

a. The balance in the fund at the end of the 23-year period, considering a monthly deposit of $1,150 and an annual interest rate of 3.25% compounded annually, is approximately $449,069.51.

To calculate the balance, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where A is the accumulated balance, P is the monthly deposit, r is the annual interest rate, n is the number of compounding periods per year, and t is the number of years.

In this case, we have monthly deposits, so we need to convert the annual interest rate to a monthly rate:

Monthly interest rate = (1 + 0.0325)^(1/12) - 1 = 0.002683

Using this monthly interest rate, we can calculate the accumulated balance over the 23-year period:

A = 1150 * [(1 + 0.002683)^(12*23) - 1] / 0.002683 = $449,069.51

Therefore, the balance in the fund at the end of the 23-year period is approximately $449,069.51.

b. The amount of interest earned over the 23-year period can be calculated by subtracting the total deposits from the accumulated balance:

Interest earned = (Monthly deposit * Number of months * Number of years) - Accumulated balance

Interest earned = (1150 * 12 * 23) - 449069.51 = $420,630.49

Therefore, the amount of interest earned over the 23-year period is approximately $420,630.49.

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Answer:

6

Step-by-step explanation:

subtract 2 from2 equal zero

add 2and 4 together get six

zero divided by any non-zero number gives zero

multiply 3 times 4 gets 12

0+12/2

divide 12 by 2 equal six

0+6

zero 0 and 6 to get 6

6

The rule that could be used to find the next number in item b is given as follows:

x 3.

A geometric sequence is a sequence of numbers where each term is obtained by multiplying the previous term by a fixed number called the common ratio q.

In item b, we have that each term is the previous term multiplied by 3, hence the common ratio is given as follows:

q = 3.

Thus the rule that could be used to find the next number in item b is given as follows:

x 3.

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Answer:

The answer is 78 blue jelly beans.

Step-by-step explanation:

Since the ratio is 4:13, and there are 24 green jelly beans, 4 times 6 equals 24. If you do 13 times 6, it equals 78. Hope this helped!

Answer:

after tax is added the price would be 3.13$

Step-by-step explanation:

Answer:

$3.13

Step-by-step explanation:

4.4% of 3 = 0.132

rounded = 0.13

Answer:

what grade is this?

Step-by-step explanation:

Answer:

390 minutes I do believe.

Step-by-step explanation:

Let us assume that the decimal representation of $\frac{n}{1375}$ terminates and let $k$ be the number of digits after the decimal point.

Then, $1375 = 5^3 \cdot 11 \cdot 5$ and $n = 5^a\cdot 11^b\cdot 7^c$ , where $a,b,c$ are nonnegative integers. Therefore, $\frac{n}{1375} = \frac{5^{a-3}\cdot 11^{b}\cdot 7^c}{1}$, where $a \le 3$ and $b \le 1$ since the decimal representation of $\frac{n}{1375}$ terminates. Hence, we can consider all values of $n$ of the form $5^a\cdot 11^b\cdot 7^c$, where $a \le 3$ and $b \le 1$ to be integers between $1$ and $1000$ inclusive, whose decimal representation of $\frac{n}{1375}$ terminates. Since $a$ has four choices $(0,1,2,3)$ and $b$ has two choices $(0,1)$, the number of integer values of $n$ between $1$ and $1000$ inclusive, whose decimal representation of $\frac{n}{1375}$ terminates is $4\cdot 2 \cdot 1 = \boxed{8}.$

We want to determine the number of integer values of $n$ between $1$ and $1000$ inclusive that satisfy $\frac{n}{1375}$ has a terminating decimal representation. We use the following fact: A positive rational number has a terminating decimal representation if and only if its denominator can be expressed as $2^a5^b$, where $a$ and $b$ are nonnegative integers.Let $d = \gcd(1375, n)$. Then, $d$ is a positive divisor of $1375 = 5^3 \cdot 11 \cdot 5$. We must have $d = 5^a11^b$, where $0 \leq a \leq 3$ and $0 \leq b \leq 1$ since $d$ divides $n$.We also have that $n = d \cdot k$ for some integer $k$.Thus, the problem is equivalent to counting the number of positive divisors of $1375$ that are of the form $5^a11^b$, where $0 \leq a \leq 3$ and $0 \leq b \leq 1$.

The prime factorization of $1375$ is $5^3 \cdot 11 \cdot 5$. Thus, $1375$ has $4 \cdot 2 \cdot 2 = 16$ positive divisors. We exclude $1$ and $1375$ as possibilities for $d$. Thus, there are $14$ possibilities for $d$. Furthermore, each divisor of $1375$ can be written in the form $5^a11^b$ where $0 \leq a \leq 3$ and $0 \leq b \leq 1$.

Therefore, there are $\boxed{8}$ values of $n$ that satisfy the condition.

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About 75% of the students' scores exceeded the score mentioned in the boxplot.

In a boxplot, the box represents the interquartile range (IQR), which contains the middle 50% of the data. The lower whisker extends to the minimum value within 1.5 times the IQR below the first quartile (Q1), and the upper whisker extends to the maximum value within 1.5 times the IQR above the third quartile (Q3).

Since the boxplot does not provide specific numerical values, we can infer that the mentioned score lies within the upper whisker, which represents the top 25% of the data. Therefore, about 75% of the students' scores exceeded this score.

It's important to note that without the actual values or specific percentiles, we can only estimate the percentage based on the visual representation of the boxplot. The exact percentage may vary depending on the scale and distribution of the data. To obtain a more precise estimate, additional information such as the quartiles or a histogram of the scores would be needed.

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Answer:

The answer is A. x + 5, y - 2

Step-by-step explanation:

The answer is A because you would move the block 5 spaces to the right and 2 spaces down.

Hope this helps!

Answer:

80000 square meters

Step-by-step explanation:

perimeter + dividing fence = 800

let a = length

let b = width

let c = length of dividing fence

perimeter = 2*a + 2*b

let's say...

c is the same as the length

2a + 2b + c = 800

2a + 2b + a = 800

3a + 2b = 800

area = length*width

area = a*b

area / b = a

3*(area/b) + 2b = 800

3*(area/b) = 800 - 2b

area/b = (800 - 2b)

area = (800 - 2b)*b

To make the area large, we make the right hand side large.

800b - 2b^2

If you put in terms of x, y it looks like a downward opening parabola, so the max area is at the vertex. Half way between the roots.

y = -2x^2 + 800x

y = -x^2 + 400x

0 = x*(-x + 400)

roots are x= 0 and x = 400

vertex is at x, aka b = 200

area at b=200 is (800 - 400)*200 = 80000

and a is area/b... 80000/400 = 200

The critical region(s) on a normal curve distribution would be located in the tail(s) of the curve. In hypothesis testing, the critical region(s) refers to the area(s) of the distribution that corresponds to rejecting the null hypothesis. This region(s) is based on the significance level of the test, which is typically set at 0.05 or 0.01.

In this case, the null hypothesis would be that listening to Vance Joy does not have a significant effect on happiness levels. The alternative hypothesis, which is what the researcher is testing for, would be that there is a significant difference in happiness levels between those who listen to Vance Joy and those who do not.
Assuming a two-tailed test, where the researcher is interested in whether the effect could be positive or negative, the critical region(s) would be located in both tails of the normal curve distribution. The exact location of the critical region(s) would depend on the sample size and the significance level of the test.
If the sample size is large, the critical region(s) would be located farther from the mean, indicating a higher level of confidence in rejecting the null hypothesis. Conversely, if the sample size is small, the critical region(s) would be located closer to the mean, indicating a lower level of confidence in rejecting the null hypothesis.
Overall, the critical region(s) on a normal curve distribution represents the area(s) of the distribution that corresponds to rejecting the null hypothesis, and its location depends on the sample size and the significance level of the test.

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The population is estimated to increase by approximately 38,880 people in 1 day.

To calculate the population increase in 1 day, we first need to convert the birth and death rates to a per-day basis. Since there are 60 seconds in a minute and 60 minutes in an hour, there are 60 x 60 = 3600 seconds in an hour, and 24 x 3600 = 86,400 seconds in a day. Therefore, in a day, the population will increase by: [(9 people/2 seconds) x (86,400 seconds/day) / 2] - [(3 people/2 seconds) x (86,400 seconds/day) / 2] = 38,880 people/day.

We multiply the per-second rates by the number of seconds in a day (divided by 2 since we are counting births and deaths separately) to get the per-day rates. We subtract the death rate from the birth rate to get the net population increase per day.

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Answer:

Y= -2x+4

Step-by-step explanation:

Put it in slope intercept form

y=mx+b

Now subtract 6x on both sides to get y isolated

3y=12-6x

Now divide 3 on both sides to get y by itself

y=4-2x

Now in slope intercept form is

y= -2x+4

Answer: 960 crayons

Step-by-step explanation:

From the question, we are informed that Mr Andrew bought 15 boxes of crayons at the store to share with his students and that each box contains 64 crayons.

The equation that represents ​c​, the total number of crayons that Mr. Andrew bought will be:

C = 15 × 64

= 960 crayons

Complete Question

A recipe calls for ! 3/4 ! Cup of walnuts and ! 2/3 ! Cup of pecans. Which type of nut is used more in the recipe? How much more?

Answer:

a) Which type of nut is used more in the recipe?

Cup of walnuts is used more

b) How much more?

1/12 more

Step-by-step explanation:

a) Which type of nut is used more in the recipe?

A recipe calls for

! 3/4 ! Cup of walnuts

Converting to decimal = 0.75 cup of walnuts

2/3 ! Cup of pecans.

Converting to decimal = 0.67 cup of pecans

The size of the cup of walnuts is greater than that of the pecans hence, the cup of walnuts is used more.

b) How much more?

This is calculated as:

3/4 cups - 2/3 cups

= 1/12 cups more

To calculate how much Brianne needs to save each month, we'll subtract her current savings and her monthly income from her total expenses.

1. Total expenses:

  - Airfare: $1500

  - Backpack: $150

  - Spending money: $1000

  Total expenses: $1500 + $150 + $1000 = $2650

2. Current savings: $40

3. Monthly income:

  - Job at Porto's: $50/week * 4 weeks = $200/month

  - Extra chores: $1200/month

  Total monthly income: $200 + $1200 = $1400

4. Amount needed to save each month:

  Total expenses - Current savings - Monthly income = $2650 - $40 - $1400 = $1210

Therefore, Brianne needs to save $1210 each month to reach her total expenses for the European trip leaving in 5 months.

If she wanted to leave in 3 months instead, she would have less time to save. In that case, the calculation would be as follows:

1. Total expenses: $2650

2. Current savings: $40

3. Monthly income: $1400

4. Number of months: 3

5. Amount needed to save each month:

  (Total expenses - Current savings) / Number of months

  = ($2650 - $40) / 3

  ≈ $870 / 3

  ≈ $290

Therefore, if Brianne wanted to leave in 3 months, she would need to save approximately $290 each month to reach her total expenses for the European trip.

Answer:

(-1, 1 1/4) or (-1, 1.25)

Step-by-step explanation:

Answer:

Its A

Step-by-step explanation:

The length of the arc of the curve from point P to point Q is 7√2 units.

To find the length of the arc of the curve from point P to point Q, we need to use the arc length formula:

\(L = \int a^b \sqrt{[1 + (dy/dx)^2] dx}\)

where a and b are the x-coordinates of P and Q, respectively.

First, let's find the derivative of x with respect to y:

x = y - 4

dx/dy = 1

Using the derivative, we can find (dy/dx) as:

dy/dx = 1/dx/dy = 1/1 = 1

Now, we can substitute the values into the arc length formula and integrate:

\(L = \int 1^8 \sqrt{[1 + (dy/dx)^2] dx}\)

\(= \int 1^8 \sqrt{ [1 + 1] dx}\)

\(= \int 1^8 \sqrt{2} dx\)

\(= \sqrt{2} \int 1^8 dx\)

\(= \sqrt{2} [x]1^8\)

\(= \sqrt{2} (8 - 1)\)

\(= \sqrt{2} (7)\)

= 7√2

Therefore, the length of the arc of the curve from point P to point Q is 7√2 units.

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To find the function satisfying the differential equation ƒ'(t) = ƒ(t) = -4t and the condition ƒ(1) = 6, we can solve the differential equation using an integrating factor.

Let's start by rearranging the equation:

ƒ'(t) - ƒ(t) = -4t

Now, we can rewrite the equation in the form:

dƒ(t)/dt - ƒ(t) = -4t

The integrating factor (IF) is given by the exponential of the integral of the coefficient of ƒ(t), which in this case is -1:

IF = e^(-t)

Now, we multiply both sides of the equation by the integrating factor:

e^(-t) * dƒ(t)/dt - e^(-t) * ƒ(t) = -4t * e^(-t)

The left side of the equation can be simplified using the product rule of differentiation:

d/dt [e^(-t) * ƒ(t)] = -4t * e^(-t)

Integrating both sides of the equation with respect to t gives:

∫ d/dt [e^(-t) * ƒ(t)] dt = ∫ -4t * e^(-t) dt

Integrating the right side and simplifying, we have:

e^(-t) * ƒ(t) = -4 ∫ t * e^(-t) dt

To evaluate the integral on the right side, we can use integration by parts:

Let u = t --> du = dt

Let dv = e^(-t) dt --> v = -e^(-t)

Using the formula for integration by parts:

∫ u dv = uv - ∫ v du

We can substitute the values:

-4 ∫ t * e^(-t) dt = -4 (t * (-e^(-t)) - ∫ (-e^(-t)) dt)

= -4 (-t * e^(-t) + ∫ e^(-t) dt)

= -4 (-t * e^(-t) - e^(-t))

= 4t * e^(-t) + 4e^(-t)

Substituting this result back into the previous equation:

e^(-t) * ƒ(t) = 4t * e^(-t) + 4e^(-t)

Now, divide both sides by e^(-t):

ƒ(t) = 4t + 4

Therefore, the function that satisfies the differential equation ƒ'(t) = ƒ(t) = -4t and the condition ƒ(1) = 6 is ƒ(t) = 4t + 4.

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Answer:

56º

Step-by-step explanation:

So you can figure out inner angle A because the inner angle will make 180º

180º - 116º = 64º = Angle A

Now add angle A and angle C

64º + 60º = 124º

Subtract this from 180º

180º - 124º = 56º

Therefore the measure of angle X is 56º

Answer:

2.6 x 10 ^4

Step-by-step explanation:

Answer:

2.6 x 10 to the power of 4

Step-by-step explanation:

hope this helps! :)

Answer:

the answer is 133.33

Step-by-step explanation:

hope this helps

Answer:

15) already in slope-intercept form

16) y=-6+1/3x

17) y=-7/3x-3

18)y=-1/3x+0

Step-by-step explanation:

15) is already in slope intercept form

16) first you subtract x on both sides so x-3y=18 will be

-3y=18-x

then you divide by -3 on both sides to isolate y so -3y=18-x will be

\(y=-6+\frac{1}{3}x\\\) and thats the final answer

17) y=-7/3x-3

find the slope by counting rise over run and the y intercept is when x is zero so -3

18)y=-1/3x+0

Answer:

Domain: (-infinite, -8) U (-8, 2) U (2, +infinite)

Step-by-step explanation:

The graphs never intersect with the lines x=-8 and x=2 so -8 and 2 cannot be included in the domain.

Use "[]" for included and "()" for excluded.

The domain will go from far left to -8 => (-infinite, -8).

Then, the domain will go from -8 to 2 => (-8, 2).

Last, the domain will go from 2 to +infinite => (2, +infinite).

The quadratic equation is y = 1/2x^2 - 3x + 4

A quadratic equation is represented as:

y = ax^2 +bx + c

Using the values on the table, we have:

a(0)^2 + b(0) + c = 4 ---- when x = 0

a(2)^2 + b(2) + c = 0 ---- when x = 2

a(4)^2 + b(4) + c = 0 ---- when x = 4

Evaluate these equations

c = 4

4a + 2b + c = 0

16a + 4b + c = 0

Substitute c = 4

4a + 2b + 4 = 0

16a + 4b + 4 = 0

Divide through by 2 and 4

2a + b + 2 = 0

4a + b + 1 = 0

Subtract both equations

2a -1 = 0

Solve for a

a= 1/2

Substitute a= 1/2 in 4a + b + 1 = 0

4 * 1/2 + b + 1 = 0

Evaluate

2 + b + 1 = 0

Solve for b

b = -3

So, we have:

y = ax^2 +bx + c

This gives

y = 1/2x^2 - 3x + 4

Hence, the quadratic equation is y = 1/2x^2 - 3x + 4

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