2x+30 I need to solve for x

Answer:

rise 6 units up

Step-by-step explanation:

Answer:

6 units up

Step-by-step explanation:

Take a point

A is at  (-6,-2)

A' is at  (-6,4)

The shift is in the y coordinate of +6

This is a vertical shift

Based on the information that the smallest score in a population is x=5, and the largest score is x=10, the conclusion is that the standard  deviation is going to be smaller than the range of scores.

Given that in a population, the smallest score is x=5, and largest score is x=10, the range of scores is:

Range of scores=largest score-lowest score

                          =10-5

                           =5

Here the range of scores is 5, and the mean of the scores is likely to be between 5 and 10

Standard deviation which refers to the average spread of the distribution,  will now be considered to be smaller since the range of scores is low.

Because standard deviation is found from the mean, if the mean is between x=5 and x=10, the standard deviation must be lower than x=5.

Hence, smaller than the range of scores.

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Answer:

a. 10560

b. 63360 in.

c. 10000 m

d. 100000 cm

e. 3.107 miles

f. 42.165 km

Step-by-step explanation:

a. 2 miles contain how many feet?

1 mile = 5280 ft

2 miles × 5280 ft / mile = 10560 ft

b. 1 mile contains how many inches?

1 ft = 12 in

1 mile × 5280 ft/mile × 12 in./ft = 63360 in.

c. 10 kilometers contain how many meters?

1 km = 1000 m

10 km × 1000 m/km = 10000 m

d. 1 kilometer contains how many centimeters?

1 km × 1000 m/km × 100 cm/m = 100000 cm

e. How many miles are in a "5k" (five-kilometer) race?

1 in. = 2.54 cm

5 km =

= 5 km × 1000 m/km × 100 cm/m × 1 in. / (2.54 cm) × 1 ft / (12 in.) × 1 mile / (5280 ft)

= 3.107 miles

f. A marathon is 26.2 miles. How many kilometers is this?

26.2 miles =

26.2 miles × 5280 ft / mile × 0.3048 m/ft × km / (1000 m) = 42.165 km

The system of inequalities that could be used to determine the number of women (w) and men (m) who donated, if no more than $3,130 was donated is:

10w + 15m > 248

w + m < 213

10w + 15m < 3130

This system of inequalities can be used to model the scenario you've described, where the booth at the circus took donations for the children's hospital, and more than 248 people donated money. The first inequality states that the total number of donations from women (w) multiplied by $10 and the total number of donations from men (m) multiplied by $15 should be greater than 248. The second inequality states that the total number of women (w) and men (m) should be less than 213. The third inequality states that the total amount donated by women (w) multiplied by $10 and total amount donated by men (m) multiplied by $15 should be less than $3,130.

Therefore, the correct answer is option A. ✅

The partial derivative of the function with respect to y is: ∂/∂y [(8y-8x)/(9x+8y)] = 8/(9x+8y) - (64x)/(9x+8y)^2To find the partial derivatives of the function (8y-8x)/(9x+8y), we need to take the derivative with respect to each variable separately.

First, let's find the partial derivative with respect to x. To do this, we treat y as a constant and differentiate the function with respect to x:
(8y-8x)/(9x+8y)
= (8y)/(9x+8y) - (8x)/(9x+8y)
Using the quotient rule, we can simplify this expression:
= (-8y(9))/((9x+8y)^2) - 8/(9x+8y)
Simplifying further, we get:
= (-72y)/(9x+8y)^2 - 8/(9x+8y)
Therefore, the partial derivative of the function with respect to x is:

∂/∂x [(8y-8x)/(9x+8y)] = (-72y)/(9x+8y)^2 - 8/(9x+8y)
Now, let's find the partial derivative with respect to y. To do this, we treat x as a constant and differentiate the function with respect to y:
(8y-8x)/(9x+8y)
= (8y)/(9x+8y) - (8x)/(9x+8y)
Using the quotient rule again, we get:
= 8/(9x+8y) - (8x(8))/((9x+8y)^2)
Simplifying further, we get:
= 8/(9x+8y) - (64x)/(9x+8y)^2
Therefore, the partial derivative of the function with respect to y is:
∂/∂y [(8y-8x)/(9x+8y)] = 8/(9x+8y) - (64x)/(9x+8y)^2
And that's how we find the partial derivatives of the function (8y-8x)/(9x+8y) using the quotient rule and differentiation with respect to each variable separately.

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We used integration to find the function f given \(f'(t) = sec(t)[sec(t) + tan(t)]\), \(-\pi /2 < t < \pi /2\)  and \(f(\pi /4) = -2\). The solution is \(f(t) = tan(t) + ln|sec(t) + tan(t)| - 3 - ln(2)\).

To find the function f given f'(t), we need to integrate f'(t) with respect to t. In this case, we have:

\(f'(t) = sec(t)[sec(t) + tan(t)]\)

We can simplify this expression by using the identity \(sec^2(t) = 1 + tan^2(t)\)to get:

\(f'(t) = sec^2(t) + sec(t)tan(t)\)

We can then integrate f'(t) to obtain f(t):

\(f(t) = \int [sec^2(t) + sec(t)tan(t)] dt\)

Using the identity \(\int sec^2(t) dt = tan(t) + C\), we can simplify the integral to:

\(f(t) = tan(t) + ln|sec(t) + tan(t)| + C\)

To find the value of C, we use the initial condition \(f(\pi /4) = -2\):

\(-2 = tan(\pi /4) + ln|sec(\pi /4) + tan(\pi /4)| + C\)

-2 = 1 + ln(2) + C

C = -3 - ln(2)

Therefore, the solution to the initial value problem is:

\(f(t) = tan(t) + ln|sec(t) + tan(t)| - 3 - ln(2)\)

In summary, we used integration to find the function f given \(f'(t) = sec(t)[sec(t) + tan(t)]\), \(-\pi /2 < t < \pi /2\)  and \(f(\pi /4) = -2\). The solution is \(f(t) = tan(t) + ln|sec(t) + tan(t)| - 3 - ln(2)\).

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17 is the integer expressed in base 10.

Given that,

The base 7 representation of a positive integer is AB and its base 5 representation is BA, where A and B are digits from 1 to 4, inclusive.

We have to find what is the integer expressed in base 10.

We know that,

Base 7 representation of a positive integer AB.

Can be written as 7A+B in base 10.

Base 5 representation of BA can be written as 5B+A in base 10.

So, 7A+B= 5B+A

6A=4B

A=2/3B

Now, A and B must be in 1 to 4.

The digits between 1 and 4 who are 2/3 of another is 2 and 3.

A=2 and B=3

So,

Base 7 is 23

And Base 5 is 32

Base 7 is 23 is 17 of base 10.

And Base 5 is 32 is 17 of base 10.

A=17

Therefore, 17 is the integer expressed in base 10.

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The corporation should deposit $4,298.46 at the end of each month into the sinking fund.

The amount of interest earned over the life of the account is: $47,616.64.

The value of the fund after 2, 4, 6 are $56,243.62, $115,263.54, $178,155.28 respectively.

The interest earned during the second month of the 7th year is $317.13

To determine the amount that should be placed in the sinking fund at the end of each month, we can use the formula for present value of an annuity:

PV = R[(1-(1+i)^(-n))/i]

where:

PV = present value of the sinking fund

R = monthly deposit

i = monthly interest rate

n = number of months

We know that the sinking fund needs to have a future value of $460,000 in 8 years. If we assume monthly deposits and monthly compounding, we have:

PV = 0

FV = $460,000

i = 6.5%/12 = 0.00541667

n = 8 years * 12 months/year = 96 months

Using the formula, we can solve for R:

R = (FV*i)/((1+i)^n - 1) = ($460,000 * 0.00541667)/((1+0.00541667)^96 - 1) = $4,298.46

Therefore, the corporation should deposit $4,298.46 at the end of each month into the sinking fund.

To determine the amount of interest earned over the life of the account, we can subtract the total amount deposited from the total amount in the sinking fund at the end of 8 years:

Total amount deposited = $4,298.46/month * 96 months = $412,383.36

Total amount in sinking fund after 8 years = $460,000

Interest earned = $460,000 - $412,383.36 = $47,616.64

To determine the value of the fund after 2, 4, and 6 years, we can use the formula for future value of an annuity:

FV = R[((1+i)^n - 1)/i]

where:

FV = future value of the sinking fund

R = monthly deposit

i = monthly interest rate

n = number of months

After 2 years, we have:

FV = $4,298.46[((1+0.00541667)^(2*12)) - 1]/0.00541667 = $56,243.62

After 4 years, we have:

FV = $4,298.46[((1+0.00541667)^(4*12)) - 1]/0.00541667 = $115,263.54

After 6 years, we have:

FV = $4,298.46[((1+0.00541667)^(6*12)) - 1]/0.00541667 = $178,155.28

To determine the interest earned during the second month of the 7th year, we can first calculate the total amount in the sinking fund at the beginning of the 7th year:

FV = $4,298.46[((1+0.00541667)^(6*12)) - 1]/0.00541667 = $178,155.28

Then, we can calculate the amount of interest earned during the first month of the 7th year:

Interest earned = $178,155.28 * 0.00541667 = $964.11

Finally, we can calculate the amount of interest earned during the second month of the 7th year by subtracting the interest earned during the first month from the total interest earned during the 7th year:

Interest earned during second month = $47,616.64 * (0.065/12) - $964.11 = $317.13

Therefore, the interest earned during the second month of the 7th year is $317.13

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Answer:

the answer is 56.

Step-by-step explanation:

2 for every 4 = 1 for every two, so 28 multiplied by two.

Answer: 7/26

Step-by-step explanation:

7 red and 7 blue = 14 total

7/14 or 1/2 chance of getting red first

7/13 chance of getting red the second time

7/13*1/2 = 7/26

7/26 chance

sorry if it’s wrong but I hope it helps

kailangan ko po ng point

Answer:

c)

Step-by-step explanation:

To calculate the total charge within the cylinder with dimensions r=1.5 and h=3, we use the potential function V = 5r + 4 cos Ø in cylindrical coordinates.

The total charge can be obtained by integrating the charge density over the volume of the cylinder.

The potential V within the cylinder is given by V = 5r + 4 cos Ø, where r represents the radial distance from the axis of the cylinder and Ø represents the angle in the cylindrical coordinate system. To calculate the total charge within the cylinder, we need to integrate the charge density over its volume.

The charge density ρ can be related to the potential by ρ = -∇²V, where ∇² is the Laplacian operator. In cylindrical coordinates, the Laplacian operator takes the form:

∇² = (1/r) ∂/∂r (r ∂/∂r) + (1/r²) ∂²/∂ز + ∂²/∂z²

Since the potential function V does not depend on the z coordinate, the Laplacian reduces to:

∇² = (1/r) ∂/∂r (r ∂/∂r) + (1/r²) ∂²/∂ز

Applying this operator to the potential function V, we find:

∇²V = (1/r) ∂/∂r (r ∂V/∂r) + (1/r²) ∂²V/∂ز

To find the charge density, we substitute this expression into ρ = -∇²V:

ρ = -(1/r) ∂/∂r (r ∂V/∂r) - (1/r²) ∂²V/∂ز

To calculate the total charge, we integrate the charge density ρ over the volume of the cylinder:

Q = ∫∫∫ ρ dV = ∫∫∫ -(1/r) ∂/∂r (r ∂V/∂r) - (1/r²) ∂²V/∂ز dV

The integration is performed over the cylindrical coordinates r, Ø, and z, with appropriate limits. Evaluating this integral will give us the total charge within the cylinder.

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Answer:

would the variable be like one or something because 7 plus 5 is just 12 and that variable isn't needed so postive one

Step-by-step explanation:

brainlist plz thx

Answer: it is -1

Step-by-step explanation:

I just finished the test

Answer:

-1

Step-by-step explanation:

hope that helps :)

Answer:13.8 is the best answer i could get

Step-by-step explanation:1,077 multiply that × 13.8 =14,862

Answer:

\(\sqrt{29}\)

Step-by-step explanation:

The line has a horizontal length of 2 units and a vertical length of 5 units

The line is then the hypotenuse h of a right triangle.

Using Pythagoras' identity

h² = 2² + 5² = 4 + 25 = 29 ( take square root of both sides )

h = \(\sqrt{29}\)

The length of the line given is √29 units.

Hence, the correct option is C.

Given is line on the cartesian plain we need to calculate its length.

Refer to the figure attached.

The figure can be converted into a right triangle with perpendicular = 5 units and the base = 2 units.

The line asked will act as the hypotenuse, so, to find its length we will use the Pythagorean theorem,

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this case, the perpendicular side of the right triangle is given as 5 units, and the base is given as 2 units.

Let's denote the length of the hypotenuse as 'x'.

According to the Pythagorean theorem, we have:

x = 5² + 2²

Simplifying this equation:

x² = 25 + 4

x² = 29

To find the length of the hypotenuse, we take the square root of both sides:

x = √29

So, the length of the hypotenuse, in this case, is approximately √29 units.

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Answer: M(5,7)

Step-by-step explanation:

\(\displaystyle\\C(3,5)\ \ \ \ \ D(7,9)\ \ \ \ \ M(x_M,y_M)=?\\\\M(x_M,y_M)=(\frac{3+7}{2},\frac{9+5}{2})\\\\ M(x_M,y_M)=(\frac{10}{2},\frac{14}{2} )\\\\ M(x_M,y_M)=(5,7)\)

Answer:

C)

Step-by-step explanation:

Greetings! Hope this helps!

Answer

C.) 17

___________

5 (6-3) + 2

5 (3) + 2

15 + 2

17

Have a good day!

_______________

A brainliest would help tons! :D

The Fourier transform of the signal x(t)= e^|a|t, a>0 is X(ω) = 2πδ(ω - ja) + 2πδ(ω + ja).

To find the Fourier transform of the signal x(t) = e^|a|t, where a > 0, we can use the properties of the Fourier transform and the formula for the Fourier transform of the exponential function.

The Fourier transform of the signal x(t) is denoted as X(ω), where ω represents the angular frequency.

Using the formula for the Fourier transform of the exponential function, we have:

X(ω) = 2πδ(ω - j) + 2πδ(ω + j),

where δ(ω) represents the Dirac delta function.

In this case, since a > 0, we have j = ja.

Therefore, the Fourier transform of x(t) = e^|a|t is:

X(ω) = 2πδ(ω - ja) + 2πδ(ω + ja).

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LCD televisions use more power than Energy Star televisions. Therefore, the Energy Star television uses less energy during that time. This is because Energy Star-certified televisions are built to be more efficient.

The amount of energy saved will depend on the specific models of televisions in question and the level of energy efficiency of each model. Generally speaking, Energy Star televisions are designed to use 25-30% less energy than non-Energy Star models.

Therefore, if both the LCD televisions are on for 4 hours per day for one month (30 days), the Energy Star television will use 25-30% less energy than the non-Energy Star model, resulting in significant cost savings over time.

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67.3% of the data values are less than 75.

Data is a set of values or facts that is used as a basis for reasoning, discussion, or calculation. Data can be numerical, such as measurements, or it can be non-numerical, such as words or images

The box-and-whisker plot is a visual representation of a data set that displays the median, minimum, maximum, first quartile, and third quartile of the data set. The plot below displays the data set with the first quartile being 40 and the third quartile being 92. This means that the range of the data set is 40-92. The value of 75 falls within this range, so 25% of the data values are less than 75. This can be calculated by taking 75-40, which is 35, and dividing it by the range of the data set (92-40 = 52). This gives us 0.673, which when multiplied by 100 gives us a percentage of 67.3%. Therefore, 67.3% of the data values are less than 75.

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The acceleration of the bug at any given time t is a.

The theory used in this question is the equation of motion.

This equation states that the position of an object is equal to the product of the acceleration and the time plus a constant.

Given:

The equation x(t)=at + b,

where a and b are both nonzero, describes the position of an insect travelling along the x axis.

The equation x(t)=at + b can be rewritten as x(t)=a(t) + b.

This equation states that the position of the bug is equal to the product of the acceleration (a) and the time (t) plus a constant (b).

Therefore, the acceleration of the bug at any given time t is a.

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The vector-valued function at each given value of t  is :

a) i

b)  1/√2i+9/√2j

c)−cos(θ)i+9sin(θ)j

d)  −2sin(π/6+△t/2)sin(△t/2)i+18cos(π/6+△t/2)sin(△t/2)j

The given problem is related to trigonometric Ratios of Angle, where there are six trigonometric ratios sine, cosine, tangent, cotangent, cosecant, and secant. Since it is given that a  vector valued function:

r(t)= cos(t)i + 9 sin(t)j

r(t)=cos(t)i+9sin(t)j

so ,  r(0)=  cos(0)i+9sin(0)j = i ( sine cos0 =1 and sin0 =0)

r(π/4) =  cos(0)i+4sin(0)j = cos(π/4)i+9sin(π/4)j

           = 1/√2i+9/√2j

r(θ−π)= cos(θ−π)i+9sin(θ−π)j= −cos(θ)i+9sin(θ)j

(π/6+△t)−r(π/6)= cos(π/6+△t)i+9sin(π/6+△t)j−cos(π/6)i−9sin(π/6)j

=  cos(π/6+△t)i−cos(π/6)i+9sin(π/6+△t)j−9sin(π/6)j

= −2sin(π/6+△t/2)sin(△t/2)i+18cos(π/6+△t/2)sin(△t/2)j

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Evaluate (If possible) the vector-valued function at each given value of t. (If an answer does not exist, enter DNE.)

r(t)=cos(t)i+9sin(t)jr(t)

a)r(0)=?

b)r(π/4)=?

c)r(θ−π)=?

d)r(π/6+△t)−r(π/6)=?

Yes, there is a continuous utility function that represents a rational preference relation when it is both continuous and monotone.

In a two-commodity framework, let's assume the two commodities are represented by X and Y. We can construct a diagram with the axes representing the quantities of X and Y. The indifference curves, which represent the bundles of X and Y that yield the same level of utility, can be plotted on this diagram.

Since the preference relation is continuous and monotone, we can draw the indifference curves as smooth, upward-sloping curves without any gaps or jumps. The upward slope reflects the monotonicity, indicating that more of either X or Y is preferred to less.

To represent this preference relation with a continuous utility function, we can assign utility levels to different bundles of X and Y. For example, we can assign a utility level of 1 to a specific bundle (X₁, Y₁), and higher utility levels to bundles that are preferred to (X₁, Y₁).

By assigning utility levels in a continuous manner across the diagram, we can construct a continuous utility function that represents the rational preference relation. This function will map each bundle of X and Y to a corresponding level of utility.

In conclusion, for a rational preference relation that is continuous and monotone in a two-commodity framework, there exists a continuous utility function that represents this preference relation. The utility function can be constructed by assigning utility levels to different bundles of commodities, and the resulting indifference curves on a diagram will be smooth, upward-sloping curves. This relationship between the utility function and the preference relation allows us to mathematically model and analyze the choices and preferences of individuals in economics.

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Step-by-step explanation:

The question basically requires us to check if the number is between the two range of numbers;

Lower limit = .006

Upper limit = .14

.006: This is the lower limit, hence it lies between.

.14: This is the upper limit, hence it lies between.

.001 :  This number is below the lower limit, hence it does not lie between the numbers.

.110: This number is below the upper limit but above the lower limit hence it lies between the numbers.

.05: This number is below the upper limit but above the lower limit hence it lies between the numbers.

.042: This number is below the upper limit but above the lower limit hence it lies between the numbers.

.0014: This number is below the lower limit, hence it does not lie between the numbers.

.18: This number is above the upper limit, hence it does not lie between the numbers.

In (a) and (d), the -1 is a reciprocal, as -1 is being multiplied by f(p) or f(p⁻¹) respectively, and the solutions for p are p = 2 and p = -7/3 respectively. In (b) and (c), the -1 is an inverse, as it is part of the inverse of f(p), and the solutions for p are p = 7 and p = 5/3 respectively.

(a) f(p) = 5 is not an inverse or a reciprocal. To solve for p, we can use the equation f(p) = 5 and solve for p. We do this by subtracting 2 from both sides of the equation to get 3p = 3, and then dividing both sides by 3 to get p = 1.

(b) f⁻¹(p) = 5 is an inverse and we can solve for p using the equation f⁻¹(p) = 5. To do this, we subtract 2 from both sides to get 3p = 3, and then divide both sides by 3 to get p = 1.

(c) (f(p))⁻¹ = 5 is a reciprocal and we can solve for p using the equation (f(p))⁻¹ = 5. To do this, we first divide both sides of the equation by 5 to get 1/f(p) = 1. Then, we multiply both sides by f(p) to get f(p) = 5. Finally, we subtract 2 from both sides to get 3p = 3, and then divide both sides by 3 to get p = 1.

(d) f (p⁻¹) = 5 is not an inverse or a reciprocal. To solve for p, we can use the equation f (p⁻¹) = 5 and solve for p. We do this by multiplying both sides of the equation by p⁻¹ to get f(p) = 5p⁻¹. Then, we subtract 2 from both sides to get 3p = 5p⁻¹ - 2, and then multiply both sides by 3 to get 9p = 5p⁻¹ - 6. Finally, we add 6 to both sides to get 9p + 6 = 5p⁻¹, and then divide both sides by 4 to get p = 1.

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Answer:

y = 5

Step-by-step explanation:

y = mx + c

y = 0x + 5

y = 5

This gives a flat line where y is always 5