3. [-15 Points] DETAILS LARAT10 10.2.021. Evaluate the expression. 55 8 - 7 11 4. [-15 Points] DETAILS TANAPMATH7 5.R.014. Given that 1 31 3-1 2 A = -2 1 3 B C = 4 6 4 0 2] 4 15 compute the expression

Answer:

A

Step-by-step explanation:

The line on graph A isnt touching any intercepting lines, therefore it isn't proportional.

Answer:

For the linear to be proportional, it would have to go through the y-axis. It will always have to go through the y-axis.

You cannot find the slope if the line doesn't go through/start at the y-axis.

Answer:

1- Product of powers rule.

2- Quotient of powers rule.

3- Power of a power rule.

4- Power of a product rule.

5- Power of a quotient rule.

6- Zero power rule.

7- Negative exponent rule.

Step-by-step explanation:

Hope I helped! ^v^

The answer would be 8.

REMEMBER: Keep / Change / Flip

KEEP - 4/5

CHANGE - / to *

FLIP - 1/10 | 10/1

Now you have, 4/5 * 10/1. Just multiple across and you'll get 40/5. Now, divide 40 and 5 and you'll get your answer, 8.

\( \frac{ \frac{4}{5} }{ \frac{1}{10} } \)

\( \frac{4}{5} \div \frac{1}{10} \)

\( \frac{4}{5} \times \frac{10}{1} \)

\( \frac{40}{5} \)

\(8\)

Answer:

3⁶

9³

Step-by-step explanation:

We know that,

⇒ \(a^{x} *a^{y} =a^{(x+y)}\\\)

⇒ \(\frac{a^x}{a^y} =a^{(x-y)}\)

⇒ \((a^x)^y=a^x^y\)

Let us solve it now.

3⁴ × 3²

3 ⁽ ⁴ ⁺ ² ⁾

3⁶ ⇒ 729

And let us find the value of each expression which are given as answers and find the expressions which are equivalent to 729 ( 3⁶ ).

Answer:

10-15. 5-9. 34-56 78-3

The potential energy of the water in a lake is 57 trillion N × m, which is 57 trillion joules (J).

Gravitational potential energy applies in this situation. G P E = m g h is the formula for gravitational potential energy, where: mg stands for weight or mass times gravity (w). The height to which an object can fall before kinetic energy replaces potential energy is denoted by the symbol h. In the example of the lake, we first determine the amount of water using the equation for the volume of a typical cylinder in order to determine the weight of the cylinder: V cy l = π r²L , The weight density of the water per cubic foot, which is about 62 lb, can then be multiplied by this volume: W(water) = (Volume) (Density)

W (water) = (28,000,000 ft² ⋅ 40ft) ( 62 lb ÷ ft³ )

W (water) = 69,440,000,000 lb

To calculate the potential energy, multiply this weight by the height. GPE=mgh

GPE=Wh=(69,440,000,000lb)(600ft)

GPE=41,644,000,000,000ft⋅lb

matching the level of precision by rounding the response to two significant digits. 4.2X10¹³ft⋅lb , or 42 trillion ft-lb.

Because joules are measured in N × m units, multiply the result by fractional equivalencies. 42trillionft × lb × (4.45N ÷ lb) × (m ÷ 3.28ft)

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Answer:

The correct answer is 4/-6 which gets me to the same answer as-4/6 which is -2/3.

Answer:

Step-by-step explanation:

-4/6 is equivalent to 4/-6

answer is option 3

Answer:

21

Step-by-step explanation:

because jane is 5 years older and 16 + 5 eaquls 21i had mutiplule choice answers

Answer:

x = 31.3°

Step-by-step explanation:

\(cos (A) = \frac{b^{2} + c^{2} - a^{2} }{2bc} \)

here a = 8 ,  b = 11 , c = 15

using the formula:

cos(x) = (11² + 15² - 8²) / ( 2 * 11 * 15)

cos(x) = \(\frac{47}{55} \)

x = \(cos^{-1} (\frac{47}{55} )\)

x = 31.3°

The sequence type is a recursive function and the first five terms cannot be determined from the formula

From the question, we have the following parameters that can be used in our computation:

a(n-2)ᵃ⁽ⁿ ⁻ ¹⁾ + 1 where a1 = 3

The formula a(n-2)ᵃ⁽ⁿ ⁻ ¹⁾ + 1 is recursive because it defines the nth term in terms of the two previous terms a(n-2) and a(n-1).

To find the first five terms of the sequence, we can use the initial value a1=3 and the recursive formula.

So, we have

a1 = 3

a2 = a(0)ᵃ¹

The second term cannot be calculated because we do not have a(0)

This means that other terms cannot be calculated with the formula

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After 35 minutes there will be 40 bacteria remaining.

The process of a constant percentage rate decrease in an amount over time is referred to as "exponential decay." The formula to calculate exponential decay is given as, \(N_t=N_0\left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}}\). Here, Nt is the quantity after time t, N0 is the initial quantity, t1/2 is the half-life, and t is time.

For the first situation, Nt=360, N0=900, t=10 minutes. Therefore, substituting the given values get the value of t1/2. So,

\(\begin{aligned}360&=900\left(\frac{1}{2}\right)^{\frac{10}{t_{1/2}}} \\\frac{360}{900}&=\left(\frac{1}{2}\right)^{\frac{10}{t_{1/2}}}\\0.4&=\left(\frac{1}{2}\right)^{\frac{10}{t_{1/2}}}\\ \ln(0.4)&=\frac{10}{t_{1/2}}\ln(0.5)\\t_{1/2}&=10\times\frac{\ln(0.5)}{\ln(0.4)}\\&=7.6\end{aligned}\)

Now, for the second situation,  Nt=40.  We have to find the time at which there will be 40 bacteria remaining. Then,

\(\begin{aligned}40&=900\left(\frac{1}{2}\right)^{t/7.6}\\0.04&=\left(\frac{1}{2}\right)^{t/7.6}\\\ln(0.04)&=\frac{t}{7.6}\ln(0.5)\\t&=7.6\times\frac{\ln(0.04)}{\ln(0.5)}\\&=7.6\times4.64\\&=35.26\\&\approx35\end{aligned}\)

The answer is 35 minutes.

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In order to calculate the slope of a line that passes through the points (-2, 6) and (8, 4), we can use the formula:

Where (x1, y1) and (x2, y2) are the points coordinates. So we have:

So the slope of the line is -1/5.

The only reasonable side length is x = 8 is "The solutions are -8 and 8, but only 8 is a reasonable side length."

The equation provided and evaluate the solutions in the context of the problem.

The equation mentioned in the problem is not explicitly provided, so we'll proceed with the given information.

Let's assume the side length of the square prism cake box is x.

The volume of a square prism can be calculated using the formula:

Volume = Length × Width × Height

Since the cake box is a square prism, the length and width are the same, so we can write:

Volume = x × x × 5.5

Given that the volume of each box must be 352 cubic inches, we can set up the equation:

x^2 × 5.5 = 352

Now, let's solve this equation to find the possible solutions for x:

x^2 = 352 / 5.5

x^2 ≈ 64

Taking the square root of both sides, we have:

x ≈ ±8

The solutions to the equation are -8 and 8.

Since we are dealing with a physical length, a negative side length doesn't make sense in this context.

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The correct statement for Linda's test is: the P-value would be less than 0.08, and H0 would be rejected if α = 0.05.

For Linda's test, she is testing the hypothesis that u1 < u2. Since Linda had reason to believe that either u1 = u2 or u1 < u2 based on an earlier study, her alternative hypothesis is one-sided.

Given that Sam's two-sample t test resulted in a P-value of 0.08 for the two-sided alternative hypothesis, we need to consider how Linda's one-sided alternative hypothesis will affect the P-value.

When switching from a two-sided alternative hypothesis to a one-sided alternative hypothesis, the P-value is divided by 2. This is because we are only interested in one tail of the distribution.

Therefore, for Linda's test, the P-value would be 0.08 divided by 2, which is 0.04. This means the P-value for Linda's test is smaller than 0.08.

Now, considering the significance level α = 0.05, if the P-value is less than α, we reject the null hypothesis H0. In this case, since the P-value is 0.04, which is less than α = 0.05, Linda would reject the null hypothesis H0: u1 = u2 in favor of the alternative hypothesis HA: u1 < u2.

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keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\(y=\stackrel{\stackrel{m}{\downarrow }}{2}x+1\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{2\implies \cfrac{2}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}\)

so we're really looking for the equation of a line with a slope of -1/2 and that it passes through (4 , 6)

\((\stackrel{x_1}{4}~,~\stackrel{y_1}{6})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{- \cfrac{1}{2}}(x-\stackrel{x_1}{4}) \\\\\\ y-6=- \cfrac{1}{2}x+2\implies {\Large \begin{array}{llll} y=- \cfrac{1}{2}x+8 \end{array}}\)

Answer:

10.

tan x=51/68

x=tan-¹(51/68)=36.87

11.

cos x=72/78

x=cos-¹(72/78)=22.62

12.

sin x=24/51

x=sin-¹(24/51)=28.07

13.

sin x=21/75

x=sin-¹(21/75)=16.26

14.

sinx =16/85

x=sin-¹(16/85)=10.85

15.

sin x=48/60

x=sin-¹(48/60)=53.13

note

relationship between base and perpendicular is given by tan angle

relationship between base and hypotenuse is given by cos angle

relationship between hypotenuse and perpendicular is given by sin angle

Answer:

D. \(3\sqrt{22b}\)  

I hope this helps!

In inferential statistics, the objective is to determine the probability of the alternative hypothesis being true or the null hypothesis being true.

This involves using sample data to make inferences and draw conclusions about a larger population. By analyzing the data and performing statistical tests, we assess the likelihood of the alternative hypothesis or the null hypothesis being accurate.

The alternative hypothesis represents a claim or statement that contradicts the null hypothesis and suggests that there is a significant relationship or difference between variables. To determine its probability, statistical methods such as hypothesis testing and p-values are employed. These methods evaluate the strength of evidence against the null hypothesis and support the alternative hypothesis when the evidence is substantial.

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The solution to the recurrence relation is: aₙ = a(1)ⁿ + b * n * (1)ⁿ

= a + bⁿ

The solution to the recurrence relation with initial condition of a₁ = 2 is: aₙ  = 2

A recurrence relation is defined as an equation that recursively defines a sequence in which the next term is a function of the previous term.

The given recurrence relation is:

aₙ = 2aₙ₋₁ - aₙ₋₂

n ≥ 2

a₀ = a₁ = 2

Rewrite the recurrence relation to get:

aₙ - 2aₙ₋₁ + aₙ₋₂ = 0

Now form the characteristic equation:

x² − 2x + 1 = 0

x = 1

We therefore know that the solution to the recurrence relation will have the form:

aₙ = a(1)ⁿ + b * n * (1)ⁿ

= a + bⁿ

To find a and b , plug in n = 0 and n = 1 to get a system of two equations with two unknowns:

2 = a + b*0

2 = a

2 = a + b*1

2 = a + b

Thus:

a = 2 and b = 0

aₙ  = 2 + 0 * n = 2

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Complete question is:

a) Find all solutions of the recurrence relation aₙ = 2aₙ₋₁ - aₙ₋₂.

b. find the solution of the recurrence relation in part (a) with initial condition a₁ = 2

B. The business analysts failed to consider other factors that influence the profitability of a company.

The following conclusion can be made from the above information: B. The business analysts failed to consider other factors that influence the profitability of a company.What is the break-even point?Break-even point is that level of sales at which a company will make zero profits, so it must sell enough to cover its costs.

The break-even point is the point at which total revenue is equal to total expenses. It’s the stage where a company makes neither a profit nor a loss; all costs are covered. When a company breaks even, it signifies that it has reached a point of no profit and no loss.Business analysts claim that, after breaking-even, a 10/0 increase in sales will increase net profit by 5%.

However, many firms that broke even and demonstrated more than a 1% increase in sales also experienced a decline in net profits during the last financial year. This implies that the business analysts failed to consider other factors that contribute to the profitability of a business.

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Answer:

m = -18

Step-by-step explanation:

6 + m/2 = -3

Subtract 6 from each side

6 + m/2 -6 = -3-6

m/2 = -9

Multiply each side by 2

m/2 * 2 = -9*2

m = -18

\(\huge\text{Hey there!}\)

\(\huge\boxed{\mathsf{6+ \dfrac{m}{2}=-3}}}\\\huge\boxed{\rightarrow\mathsf{6 + \dfrac{1}{2}m = -3}}\)

\(\huge\boxed{\rightarrow \mathsf{\dfrac{1}{2}m+ 6 = -3}}\\\\\huge\boxed{\text{SUBTRACT 6 to BOTH SIDES}}\\\huge\boxed{\mathsf{\dfrac{1}{2}m + 6 - 6 = -3 + 3}}\)

\(\huge\boxed{\mathsf{\dfrac{1}{2}m = -9}}\)

\(\huge\boxed{\text{MULTIPLY 2 to BOTH SIDES}}\)

\(\huge\boxed{\mathsf{\dfrac{1}{2}m \times 2 = 2 \times -9}}\)

\(\huge\boxed{\mathsf{m = 2\times-9}}\\\huge\boxed{\mathsf{2\times-9 = m}}\\\huge\boxed{\mathsf{2\times-9 = \bf -18}}\\\\\huge\boxed{\textsf{Therefore, your answer: \bf -18}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

~\(\huge\boxed{\frak{Amphitrite1040:)}}\)

There is no difference in height that is not sufficient to meet the slope constraint if Matt wants to start a zip line 16 feet high in one tree and end 10 feet high in the other tree is the difference in height sufficient to meet the slope constraint.

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

We know the slope can be evaluated using:

\(\rm Slope = \frac{Change \ in \ y \ axis}{Change \ in \ x \ axis}\)

Change in y-axis = difference in height

Change in y-axis = 16 - 10

                            = 10 feet

Change in x-axis = distance between tress

Since the data is not given.

So, the height difference is insufficient to keep the slope constraint.

Thus, there is no difference in height that is not sufficient to meet the slope constraint if Matt wants to start a zip line 16 feet high in one tree and end 10 feet high in the other tree is the difference in height sufficient to meet the slope constraint.

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Answer:

72

Step-by-step explanation:

This is clearly multiplication so all you have to do is multiply 24 x 3 and your answer is There are 72 subscribers in week 24

The solutions for the system are

Solution 1: (a, b) = (5, 51)

Solution 2: (c, d) = (-11, 67)

To find the value of a + b + c + d, we need to first determine the values of a, b, c, and d by solving the given system of equations:

Equation 1: x^2 - y = 1

Equation 2: x + y = 56

Let's solve the system to find the values of x and y:

From Equation 2, we can isolate y by subtracting x from both sides:

y = 56 - x

Substituting this value of y into Equation 1:

x^2 - (56 - x) = 1

x^2 - 56 + x = 1

x^2 + x - 55 = 0

Now we can factor the quadratic equation:

(x - 5)(x + 11) = 0

So we have two possible values for x:

x - 5 = 0, which gives x = 5

x + 11 = 0, which gives x = -11

For x = 5, we can substitute it back into Equation 2 to find y:

5 + y = 56

y = 51

For x = -11, we can substitute it back into Equation 2 to find y:

-11 + y = 56

y = 67

Therefore, the solutions for the system are:

Solution 1: (a, b) = (5, 51)

Solution 2: (c, d) = (-11, 67)

Finally, we can calculate a + b + c + d:

a + b + c + d = 5 + 51 + (-11) + 67

a + b + c + d = 112

Hence, the value of a + b + c + d is 112.

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Answer:

2 faces, 0 edges, and 0 vertices

Step-by-step explanation:

Answer:

what

Step-by-step explanation:

Answer: The answer is \(\frac{7-5}{4-3}\) = \(\frac{2}{1}\)=2

The formula to solve down here:

           (x1,y1)  

              (x2,y2)

Step-by-step explanation:

Answer: yes it is

Step-by-step explanation:

Answer:

−35.948187

Step-by-step explanation:

we know that

If two triangles are similar, then their corresponding angles are congruent

In this problem

we have that

First case

angle x and angle 60 are corresponding angles

angle (x+10) and angle (2x-50) are corresponding angles

so

x=60

x+10=2x-50

2x-x=10+50

x=60

is ok

Second case

angle (x+10) and angle 60 are corresponding angles

angle x and angle (2x-50) are corresponding angles

so

x+10=60

x=50

x=2x-50

2x-x=50

x=50

therefore