Consider 5.00 mol of liquid water. (a) What volume is occupied by this amount of water? The molar mass of water is 18.0 g/mol. (b) Imagine the molecules to be, on average, uniformly spaced, with each molecule at the center of a sma11 cube. What is the length of an edge of each sma11 cube if adjacent cubes touch but don't overlap? (c) How does this distance compare with the diameter of a molecule?
This question involves the concepts of density, volume, and mass.
(a) The volume occupied by this amount of water is "90 m³".
(b) The length of an edge of each small cube is "83 μm".
(c) The length of the edge of each small cube is "equal" to the diameter of a molecule.
(a)
The volume can be found using the following formula:
\(V = \frac{nM}{\rho}\)
where,
V = volume occoupied = ?
n = no. of moles = 5 mol
M = molar mass = 18 g/mol
\(\rho\) = density of water = 1 g/m³
Therefore,
\(V=\frac{(5\ mol)(18\ g/mol)}{1\ g/m^3}\\\\\)
V = 90 m³
(b)
First, we will find the volume of an individual molecule:
\(V_i =\frac{V}{nN_A}\)
where,
\(N_A\) = Avogadro's number = 6.02 x 10²³ molecules/mol
Therefore,
\(V_i=\frac{90\ m^3}{5\ mol(6.02\ x\ 10^{23}\ molecules/mol)}\)
Vi = 3 x 10⁻²³ m³
This volume can be given as a volume of the sphere:
\(V_i=\frac{4}{3}\pi r^3\\\\r=\sqrt[3]{\frac{3(3\ x\ 10^{-23}\ m^3)}{4\pi}}\)
r = 4.15 x 10⁻⁷ m
Diameter = d = 2r = 2(4.15 x 10⁻⁷ m)
d = 8.3 x 10⁻⁷ m = 83 μm
since the cubes are adjacent to each other. Therefore, the diameter will be equal to the edge length.
Edge Length = L = d
L = 8.3 x 10⁻⁷ m = 83 μm
(c)
The edge length is equal to the diameter of the molecule.
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A 0.18 kg baseball moving at +21.80 m/s is slowed to a stop by a catcher who exerts a constant force of -360 N.
How long does it take this force to stop the ball?
___s
How far does the ball travel before stopping?
___m
Answer:
hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.
It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.
What is force?To find the time it takes for the catcher to stop the ball, you can use the equation:
time = distance / velocity
In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:
time = 0 / 21.80
time = 0 s
So, it takes 0 seconds for the catcher to stop the ball.
To find the distance the ball travels before stopping, you can use the equation:
distance = 1/2 * acceleration * time^2
In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:
distance = 1/2 * (-2000 m/s^2) * (0 s)^2
distance = 0 m
So, the ball travels 0 meters before stopping.
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Two tiny objects with equal charges of 7.25 μC are placed at the two lower corners of a square with sides of 0.201 m, as shown.
Find the electric field at point B, midway between the upper left and right corners. If the direction of the electric field is upward, enter a positive value. If the direction of the electric field is downward, enter a negative value. answer in N/C
The electric field at point B, located at the midpoint between the upper left and right corners of the square, can be approximated as 3.244 x \(10^6\) N/C in the upward direction.
To find the electric field at point B, we can consider the contributions from the two charges placed at the lower corners of the square. Since the charges are the same and the distance to point B is the same for both charges, the magnitudes of the electric fields produced by each charge will be equal.
First, let's calculate the magnitude of the electric field produced by one of the charges at point B using Coulomb's Law:
Electric field due to a point charge (E) = (k * q) / \(r^2\)
Where:
- k is the electrostatic constant, approximately equal to 8.99 x 10^9 \(10^9\)N \(m^2/C^2\)
- q is the charge of the object, 7.25 μC (7.25 x \(10^-^6\) C)
- r is the distance from the charge to point B, which is half the length of the square's side, 0.201 m / 2 = 0.1005 m
Plugging in the values, we have:
E = (8.99 x \(10^9 N m^2/C^2\) * 7.25 x \(10^-^6\) C) / (0.1005 \(m)^2\)
E ≈ 1.622 x \(10^6\) N/C
Since the electric fields from the two charges at the lower corners have equal magnitudes and point in the same direction (upward), the total electric field at point B is twice the magnitude of the individual electric field:
Electric field at point B = 2 * E ≈ 2 * 1.622 x \(10^6\) N/C
Electric field at point B ≈ 3.244 x \(10^6\) N/C
Therefore, the electric field at point B, midway between the upper left and right corners of the square, is approximately 3.244 x \(10^6\)N/C upward.
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Which bond(s) shown are double bonds?
Answer:
I'm pretty sure its the 2nd one.
When is a field study more appropriate that a laboratory experiment? Give a specific example.
A field study is more appropriate that a laboratory experiment when we need to know the real mining of unknown variables in a given outcome such as for example dark matter in space.
What are unknown variables in science?Unknown variables in science can be defined as variables that have yet to be identified or studied, either due to a lack of data or unknown factors.
Therefore, with this data, we can see that unknown variables in science such as the amount of Dark matter in the Universe are able to be shown by field (observational) studies.
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A sprinter accelerates from rest to 10.0 m/s in 1.35 seconds. What is their
acceleration?
Answer:
7.407 recurring m/s^2
Explanation:
Initial velocity= 0 m/s [as it starts from rest]
Final velocity= 10 m/s
Time taken= 1.35 s
Hence,
Acceleration = Final velocity - Initial velocity
Time taken
a=10
1.35
a=7.407 recurring m/s^2
A 3-kg block is observed to accelerate at a rate twice that of a 6-kg block. Is the net force acting on the 3-
kg block therefore twice as large as that acting on the 6-kg block?
No, the forces on the blocks are equal since half the mass times twice the acceleration yields the same force.
The net force is defined as the sum of all forces acting on an object. A net force can accelerate a mass. Another force acts on an object at rest or in motion. The net force is the term used in systems when there are a significant number of forces.
A mass of 10 kg and an acceleration of 3 ms2, the net force on the bowling ball can be calculated from the above equation. Therefore, a force of 30 N is required for the bowling ball to accelerate down the alley at a speed of 3 ms2. An object is accelerating if its acceleration points in the same direction as its velocity. And if the acceleration is in the opposite direction of the velocity, the object will slow down.
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Many of the rocks of the canyon wall appear as horizontal bands. What do the bands indicate about the way the rocks formed?
Given what we know, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.
What do these bands tell us about the canyon?The bands are the result of sediments being deposited as the canyon was being formed. These sediments are deposited by the running water that carves the canyon. This results in horizontal bands that can tell us much about the history of the canyon as well as the river that formed it.
Therefore, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.
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Raju completes one round of a circular track of diameter 200m in 30s. Calculate
a. The distance travelled by Raju
b. The magnitude of displacement travelled by Raju at the end of 30 s.
Explanation:
Given:
Diameter = 200 m
Radius, r = 200/2 = 100 m
Time taken, t = 30 seconds
Formula to be used:
Distance traveled, = circumference of circle = 2πr
Answer:
Putting all the values, we get
Distance traveled = 2πr
Distance traveled = 2 × 22/7 × 100 Distance traveled = 4400/7 Distance traveled = 628.57 mSo, the distance traveled by Raju is 628.57 m.
Now, magnitude of the displacement,
At the end of 30 seconds, Raju will come to starting position or initial position, so displacement is zero.
7. It has been suggested that rotating cylinders about 20 km in length and 8 km in diameter be placed in space and used as colonies. The purpose of the rotation is to simulate gravity for the inhabitants. Explain this concept for producing an effective imitation of gravity.
The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.
What is centrifugal force?when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.
It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.
The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.
To simulate gravity for the inhabitants, the concept of the centrifugal force is used.
Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.
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Tension is maintained in a string as in the
figure. The observed wave speed is 25 m/s
when the suspended mass is 3.5 kg. If the mass per length of the string is 0.05488kg/m, what is the wave speed when the suspended mass is 2.6 kg?
The wave speed when the suspended mass is 2.6kg is
21.547m/sTension applied can be calculated by\(T = mg\\\\ T = 3.5*9.8\\\\ T = 34.3N \)
Therefore, linear density on the string is given by
m = 0.05488kg/m
If the attached mass is replaced by 2.6kg
\(T = 2.6*9.8\\\\ T = 25.48N \)
Therefore, the wave speed in the same string is
\(v = \sqrt{\frac{T}{m}}\\\\ v = \sqrt{\frac{25.48}{0.05488}}\\\\ v = 21.547m/s \)
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Hurricanes are powered by heat energy in the atmosphere and the ocean. Typically, a “small” hurricane uses an amount of heat roughly equal to 16.89 thousand atomic bombs. If just half of the excess heat built up in Earth’s atmosphere since the year 1900 went into producing hurricanes, about how many more hurricanes might we expect in the world every year?
The average number of hurricanes per globally stands at 15 hurricanes per year due to excess heat built up in Earth’s atmosphere.
What are hurricanes?Hurricanes are huge storms produced in the tropics due to large amounts of water vapor present in the atmosphere from the ocean coupled with strong winds with devastating effects on land.
The activities of man such as burning of fossil fuels have resulted in increased build of heat in the atmosphere and warming of the oceans. This is known as global warming.
Due to global warming, on average, the number of hurricanes per globally stands at 15 hurricanes per year.
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A tape diagram. 0 dollars is 0 percent. Question mark dollars is 23 percent. 52 dollars is 100 percent. Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52. Which expression can you use to find 23% of 52? 23% of $52 is $ . An easy way to check your answer is to use the friendly and divide 52 by to get .
Answer:
Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52.
Which expression can you use to find 23% of 52?
✔ 0.23 × 52
23% of $52 is $
✔ 11.96
.
An easy way to check your answer is to use the friendly
✔ 25%
and divide 52 by
✔ 4
to get
✔ 13
.
Explanation:
Which of the following are vectors?
Check all that apply.
O A. energy
B. displacement
O C. force
D. mass
E. momentum
F. speed
G. time
O H. velocity
Answer:
Displacement, force, momentum, and velocity are all vectors
Explanation:
Vectors are quantities that show direction; which all of the above do. The rest of the terms are scalar quantities
What distance will be traveled if you are going at an average speed of 420 km/hr for 45 minutes?
Answer: 12
Explanation: 34
An electric device uses 650 watts of power. If the voltage is 120 volts, what is the resistance?
The resistance of the electric device using a power of 650 watts is approximately 27.7 ohms.
How determine resistance from power and votage?Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.
Hence
V = IR
R = V/I
Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.
We need to first find the electric current I.
Note:
Power = Voltage × Current.
Hence:
Current I = Power/Votage
Plug in the values
I = 650 / 120
I = 13/3 A
Substituting the values of voltage and current intio the above formula, we can calculate the resistance:
R = V/I
R = 120 / (13/3)
R = 27.7 ohms
Therefore, the resistance is approximately 27.7 ohms.
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the fastest tennis service by a man is 246,2 km.hr-1 by Andy Roddick of the United States of America during a match in London in 2004. Calculate the ball's momentum if it has a mass of 58 g?
Answer:
Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).
Explanation:
Convert velocity to the standard units (meters per second):
\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).
Convert mass to standard units (kilograms):
\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).
When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:
\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Let's practice this process of using the position function to
determine the position at a certain time. If an object is
moving with a constant velocity of 970 cm/s and starts at
an initial position of 40 cm at t=0, what will be the
position at t= 0.2 s?
1.94 m will be the distance (position) at t= 0.2 s.
Velocity=970 cm/s
distance=?
time=0.2
distance=Velocity×time
distance=970 cm/s × 0.2
distance=194 cm= 1.94 m
Distance is the length between two locations or things, independent of direction. Since distance is a scalar property, it only takes into consideration the total magnitude and ignores the start and finish positions. Since distance is a scalar attribute, it can only have a positive or zero value; it cannot have a negative value. The most common unit of measurement for distance is the meter (m), while larger distances can also be stated in kilometers (km), while smaller distances can be expressed in centimeters (cm) or millimeters (mm). When calculating distance, the letter D is the conventional way to represent the distance traveled.
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What three statements are true about the wave shown?
the atom of an element x has 21protrons and 23neutrons. What is the
(a) Electron number
(b) Mass number
(c) Neutron number
When two trains, going in opposite directions, are passing on tracks that are laid out close together, the train cars can often be seen to be leaning in toward one another where they are in proximity. How might the air passing through the narrow gap separating the two trains contribute to the observed attraction between their cars?
how often the earth magnetism change
5. Salt is often spread on roads during winter to prevent ice from forming. Do you think sugar would
work as well? Explain your answer.
Answer:
No because sugar is more sweet and it would not have the benefits of salt. Think of it like how people used to put salt on meat to preserve it. Would they put sugar on? No they would not because salt is a combination of things that sugar does not have.
Explanation
A ball thrown downward by initial speed of 3m/s. It hits the ground after 5 second.
How high is throwing point?
A crow flies forward and backward. Its motion is shown on the following graph of horizontal position x vs.
time t.
What is the instantaneous velocity of the crow at t = 9 s ?
A crow flies forward and backward. Its motion is shown on the following graph of horizontal position x vs. time t.
What is the instantaneous velocity of the crow at t = 9 s?
Answer: -0.50 m/s
A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.
From the figure, it shows that from t = 8sec to t = 12 sec the displacement is decreasing, so velocity will be the slope of the straight line.
The velocity is given by:
velocity = -Δx ÷ Δt
velocity = (-2) ÷ (12-8)
velocity = -2 ÷ 4
velocity = -0.5 m/s
Therefore, A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.
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A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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A ship travels at a velocity of 42 m/s in north-westerly direction. A man on the ship is walking at a velocity of 3,2 m/s from the back of the ship to the front of the ship.
What is the man’s resultant velocity in magnitude and direction?
The man’s resultant velocity is 4m/s in the north-westerly direction.
What exactly is relative speed?According to mathematics, the relative velocity is the vector difference between the velocities of two objects. The difference between the velocities of body A and body B determines the relative velocities between them.
What is the speed of resultant?The total of an object's component vector velocities is the resulting vector velocity. The sum of the vector forces acting on an object is equal to the scalar product of its mass and acceleration vector.
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Question 11 of 29
According to Newton's second law of motion, how much force will be required
to accelerate an object at the same rate if its mass is doubled?
A. Twice the amount of force will be required.
B. No change in the amount of force is needed.
C. Half the amount of force will be required.
D. Four times the amount of force is needed.
The force is directly proportional to the acceleration hence, at twice the amount of force will be required.
Newton's second law;The Newton's second law of motion states that the rate of change of momentum is directly proportional to the impressed force. From this law we obtain that F = ma
Since the force is directly proportional to the acceleration, at constant mass, twice the amount of force will be required.
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Consider the following debate between two students about their answer to the above question.
Student 1: I thought that whenever one object exerts a force on a second object, the second object also exerts a force that is equal in strength, but in the other direction. So even though Earth is bigger and more massive than the Moon, they still pull on each other with a gravitational force of the same strength, just in different directions.
Student 2: I disagree. I said that Earth exerts the stronger force because it is way bigger than the Moon. Because its mass is bigger, the gravitational force Earth exerts has to be bigger too. I think you are confusing Newton's third law with the law of gravity. Do you agree or disagree with either or both of the students?
Answer:
I agree with student 1
Explanation:
This is because, the magnitude of the gravitational force on both Earth and Moon depends on the product of their masses. Also, both Earth and Moon exert the same force but in opposite directions.
Student 2 is wrong because the gravitational force is the only force acting between the Earth and Moon, and from Newton's third law, it follows an action-reaction pair. But, student 2 got it wrong in the sense that the magnitude of the action and reaction forces are the same and are equal to the gravitational force.
So, the gravitational force acting on each object is the same and doesn't vary for each mass.
We should agree with the student 1.
Gravitational force:
This is to be done due to the magnitude of the force since earth and moon should be based on the masses' product. Moreover, the earth and moon exert a similar force but that should be in inverse directions. Here student 2 should be wrong because the gravitational force is that force that acted between the earth and moon. Based on this, we can say that it should be acted on each object when it is the same also it should not be changed for every mass.
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