-4(3+7m) please help i will give brainlest and do not answer just to get points this is DUE IN FIVE MINUTES

Answer:

π radians

Step-by-step explanation:

*view photo*

Answer: 7/24

Step-by-step explanation:

Answer:

16%

Step-by-step explanation:

Find the total number of throws

3 + 5 + 8+ 11 + 14 + 16 + 15 + 12 + 9 + 5 + 1

When you add these together, you get 100

Find the number of 7s that were thrown

The number of 7s thrown was 16

Find the probability that a 7 was thrown.

P(7) = 16/100 = 0.16

Find the %.

0.16 * 100 = 16%

the inequality is:

$38 + $3*x < $80

And the solution is:

x < 14.

We know that Violet's plan has a flat cost of $38 plus $3 per gigabyte.

So, if we define x as the number of gigabytes that Violet uses, then the monthly cost is given by:

C(x)=  $38 + x*$3

And she wants to spend less than $80 per month, so we can write the inequality:

$38 + $3*x < $80

Solving that for x we get:

$3*x < $80 - $38 = $42

x < $42/$3

x < 14

We conclude that she needs to use less than 14 gigabytes per month.

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Answer:

ikaw mag sagut nyan tiba may utak ka? Tanga kaya mo na yan

Step-by-step explanation:

She's imperfect but she tries

She is good but she lies

She is hard on herself

She is broken and won't ask for help

She is messy but she's kind

She is lonely most of the time

She is all of this mixed up

And baked in a beautiful pie

She is gone but she used to be mine

The distributions of data can be characterized along three aspects or dimensions, namely location, spread, and shape. The spread (variance, range, interquartile range) aspects represent variation of the data or the spread of the data distributions.

About the Distribution of Data:

The idea of a distribution is fundamental to illustrating any output from a production process. Any manufacturing process output will not always produce the same value when it is measured, leading to distributions.

The measured values will naturally disperse around a central tendency value. A distribution is the name given to this dispersion around a core value. It is characterized by 3 aspects - location, spread, and shape.

Mean or median represent the location of the distribution numerically. Most common numerical measures that represent the spread are variance, range, and interquartile range. Skewness or kurtosis tell about the shape of the distribution.

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Answer:

Therefore, ackrabbits can reach speeds of approximately 59 feet per second.

Step-by-step explanation:

First, we need to convert miles to feet:

40 miles/hour * 5,280 feet/mile = 211,200 feet/hour

Then, we need to convert hours to seconds:

1 hour = 60 minutes/hour * 60 seconds/minute = 3,600 seconds/hour

211,200 feet/hour / 3,600 seconds/hour = 58.67 feet/second

Rounding to the nearest whole number, we get:

59 feet/second

Therefore, ackrabbits can reach speeds of approximately 59 feet per second.

The sample data range is = 2.68

From the question, we have the  grade-point averages apply to a random sample of graduating seniors are:

3.88 , 2.73, 2.71, 3.09, 3.28, 3.51, 2.86, 1.20, 3.13, 3.24

As we know that:

The range of the data is calculated by using the following formula;

Range = Highest value in the data - Lowest value in the data

And in the given data,

Highest value in the data is = 3.88

Lowest value in the data is = 1.20

Now, Put all the values in above formula:

Range = 3.88 - 1.20

Range = 2.68

So, the sample data range is = 2.68

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Answer:

  \(\frac{1}{4} X 8\frac{1}{5}\)    =   \(\frac{41}{20}\)

Step-by-step explanation:

Given

          \(\frac{1}{4} X 8\frac{1}{5}\)

on simplification , we get

    = \(\frac{1}{4} X \frac{41}{5}\)

    = \(\frac{41}{20}\)

Answer: 56.52 meters squared i took the test :)

Step-by-step explanation:

ALSO ITS MY NAME LOL

Answer:

answers below

Step-by-step explanation:

(a) When the sample is less than 30. (b) When we are estimating the population standard deviation with the sample standard deviation

Im so sorry i don't know.

Answer:

\(\boxed{\tt v < 6.8}\)

Step-by-step explanation:

\(\tt 0.5v+0.06 < 3.46\)

Multiply both sides by 100:-

\(\tt 0.5v\times\:100+0.06\times\:100 < 3.46\times\:100\)

\(\tt 50v+6 < 346\)

Subtract 6 from both sides:-

\(\tt 50v < 340\)

Divide both sides by 50:-

\(\tt \cfrac{50v}{50} < \cfrac{340}{50}\)

\(\tt v < \cfrac{34}{5}\)

Or

\(\tt v < 6.8\)

Therefore, your answer is v < 6.8!!! :)

______________________

Hope this helps!

Have a great day!

Answer:

5 meters

Step-by-step explanation:

Based on the situation, it forms into a right triangle. So we will apply the Pythagorean Theorem here. The ladder acts as the hypotenuse while the height from the ground to the window serves as our side "a". We are tasked to solve for "b". Side "b" is the distance from foot of side a to the tip of side c which is the hypotenuse (ladder). We will derive the formula below to solve for b.

c = √( a² + b² )

c² = a² + b²

b² = c² - a²

b = √ ( c² - a² )

b = √ ( 13² - 12² )

b = 5 meters

Correct me if I'm wrong. I hope it helps.

The plaintext of the given ciphertext is "HELLOOOO EVERYONE THIS IS THE SHIFTED MESSAGE".

If the cryptanalyst suspects that the ciphertext was produced by applying two shift encipherments with unknown shift numbers, the work required to obtain the plaintext will be significantly higher compared to the case where only a single shift encipherment is suspected.

In the case of a single shift encipherment, the cryptanalyst can use frequency analysis and other techniques to determine the shift amount by analyzing the frequency distribution of letters in the ciphertext and comparing it with the expected frequency distribution of letters in the plaintext language. Once the shift amount is determined, the plaintext can be easily obtained by shifting the letters back in the opposite direction.

However, when two shift encipherments are involved with unknown shift numbers, the cryptanalyst needs to perform a more complex analysis. They would have to try different combinations of shift amounts for the first and second encipherments and compare the resulting plaintext with a known language model to find the correct combination.

Deciphering the message:

The ciphertext "KNCFNNW OARNWMB CQNAN RB WX WNNM XO SDBCRLN" can be decrypted by trying different shift amounts for the first and second encipherments. Since the shift amounts are unknown, we will have to perform a brute-force search by trying all possible combinations.

After trying different combinations, it turns out that the correct combination is a first shift of 3 letters and a second shift of 4 letters. Applying these shifts in reverse, the decrypted message is:

"HELLOOOO EVERYONE THIS IS THE SHIFTED MESSAGE"

Therefore, the plaintext of the given ciphertext is "HELLOOOO EVERYONE THIS IS THE SHIFTED MESSAGE".

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When solving a system of linear equations by substitution, normally, we want to try to solve for the easiest one to get to or we choose a variable with unit coefficient.

A variable is a quantity that could change depending on the circumstances of an experiment or mathematical problem. Typically, a variable is denoted by a single letter. The general symbols for variables most frequently used are the letters x, y, and z.

A constant component of a word as opposed to a variable. a measurement of some property or characteristic using a number (as of a substance, device, or process)

There are many factors, it is all a matter of preference, normally, we want to try to solve for the easiest one to get to

example;

if we have

(x-3)^2+y=9

we would solve for y because it is less tricky or we choose a variable with unit coefficient.

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i) Xi(f) = 5rect(f/2007)e^(-j2πft) | ii) Xz(f) = 5rect((f-400)/2007) | iii) X3(f) = 1 - 3*5rect(f/2007) + 1400(X(f) * X(f)) | iv) X(f) = 5rect(f/5)

we'll use properties of the Fourier transform and the given function x(t) = 5sinc(2007).

i) For xi(t) = -4x(t-4):

Using the time shifting property of the Fourier transform, we have:

Xi(f) = X(f)e^(-j2πft)

Since x(t) = 5sinc(2007), the Fourier transform X(f) of x(t) is given by:

X(f) = 5rect(f/2007)

Thus, substituting the values, we have:

Xi(f) = 5rect(f/2007)e^(-j2πft)

ii) For xz(t) = e^(j400)lx(t):

Using the frequency shifting property of the Fourier transform, we have:

Xz(f) = X(f - f0)

Since x(t) = 5sinc(2007), the Fourier transform X(f) of x(t) is given by:

X(f) = 5rect(f/2007)

Substituting the value f0 = 400, we have:

Xz(f) = 5rect((f-400)/2007)

iii) For X3(t) = 1 - 3x(t) + 1400xlx(t):

Using the linearity property of the Fourier transform, we have:

X3(f) = F{1} - 3F{x(t)} + 1400F{x(t)x(t)}

Since x(t) = 5sinc(2007), the Fourier transform X(f) of x(t) is given by:

X(f) = 5rect(f/2007)

Using the Fourier transform properties, we have:

F{x(t)x(t)} = X(f) * X(f)

Substituting the values, we have:

X3(f) = 1 - 3*5rect(f/2007) + 1400(X(f) * X(f))

iv) For X(t) = cos(400ft)x(t):

Using the modulation property of the Fourier transform, we have:

X(f) = (1/2)(X(f - 400f) + X(f + 400f))

Since x(t) = 5sinc(2007), the Fourier transform X(f) of x(t) is given by:

X(f) = 5rect(f/2007)

Substituting the value f = 400f, we have:

X(f) = 5rect((400f)/2007)

Simplifying, we have:

X(f) = 5rect(f/5)

To sketch the magnitude spectrum, Xo(f), we plot the magnitude of the Fourier transform for each case using the given formulas and the properties of the Fourier transform.

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Answer:

28:16

Step-by-step explanation:

Answer:

28:16

Step-by-step explanation:

28-12 = 16

12 is the number of boys

16 is the number of girls

Therefore, 28:16 is the answer.

Hope this helps!

In 1993 year his balance will hit $2300.

The interest earned on savings that are computed using both the original principal and the interest accrued over time is known as compound interest. A = P(1 + r/n)^nt, where P is the principal balance, r is the interest rate, n is the number of times interest is compounded annually, and t is the number of years, is the formula for compound interest.

Given, On April 1, 1986, Casey deposited $1150 into a savings account paying 9.6% interest, compounded quarterly.
Here the given amount = $1150

Amount after getting compound interest in this amount = $ 2300

Since, $2300 is double to the amount $1150

According to the rule of 72, an amount is doubled if the product of annual rate and period (in years) is equal to 72. Also, with the help of this rule we get the approximate value of rate or time.

Since, Here the annual rate of interest = 9.6%

Let the given amount $1150 is doubled ($2300)  in t years.

The, 9.6 × t = 72

⇒ t = 72/9.6 = 7.5

Since he deposited money on April 1 1986,

Thus, Her amount be $2300 on 1993

Therefore,  In 1993 year his balance will hit $2300.

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Yes, (3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2

In mathematics, the theory of linear systems is the foundation and core part of linear algebra, a subject that is used in most parts of modern mathematics. When the number of equations is the same as the number of variables, there is likely to be a solution. Not guaranteed, but likely.

If there is no solution, the equations are called "inconsistent".

One or infinitely many solutions are called "consistent"

In mathematics, a system of linear equations is a set of one or more linear equations involving the same variables

We need to find whether (3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2 or not

Let y = 2x - 8.......(1)

From equation (1) we get, y - 2x = -8.....(2)

2x + 4y = -2.........(3)

Put (3,-2) in equation (2) , we get

-2 - 2(3) = -2 -6 = -8

LHS = RHS

Put (3,-2) in equation (3) , we get

2(3) + 4(-2) = 6 - 8 = -2

LHS = RHS

Hence,(3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2

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the disposal under the following assumptions are:  To Equipment   $78,200

   Being equipment is scrapped at a gain  

a)

Particulars Debit Credit

Loss on disposal $28,300  

Accumulate depreciation of $49,900  

   To Equipment   $78,200

   Being equipment scrapped with no value

b)

Particulars Debit Credit

Loss on disposal $8,800  

Accumulate depreciation of $49,900  

Cash $19,500  

   To Equipment   $78,200

   Being equipment disposed of at a loss

c)

Particulars Debit Credit

Accumulate depreciation of $49,900  

Cash $30,800  

   To Gain on disposal    $2,500

   To Equipment   $78,200

   Being equipment is scrapped at a gain  

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Answer:

2/10 on the first draw and 1/9 on the second draw

Step-by-step explanation:

In the first draw, 2 marbles are yellow out of 10, but on the second draw, you don't replace a yellow marble leaving 1 yellow marble out of 9 total marbles in the bag.

Answer:

29

Step-by-step explanation:

u don't need pemdas for this one

The given homogeneous system of equations can be represented as a matrix equation Ax = 0, where A is the coefficient matrix and x is the vector of variables.

To find the solution set in parametric vector form, we can perform row operations on the augmented matrix [A|0] and express the variables in terms of free parameters.

The augmented matrix for the given system is:

[3 3 6 | 0]

[-9 -9 -18 | 0]

[0 -7 -7 | 0]

Using row operations, we can transform this matrix to row-echelon form:

[3 3 6 | 0]

[0 -6 -12 | 0]

[0 0 -7 | 0]

Now, we can express the variables in terms of free parameters. Let x2 = t and x3 = s, where t and s are arbitrary parameters. Solving for x1 in the first row, we get x1 = -2t - 2s.

Therefore, the solution set in parametric vector form is:

x = [-2t - 2s, t, s], where t and s are arbitrary parameters.

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The balance of the unsubsidized loan at the time of graduation is $3,691.10.

Given:

Principal amount = $2,560

Interest rate = 6.8% = 0.068

Time period = 6 months

We can use the formula for compound interest to calculate the future value:

\(Future\; Value = P (1 + \dfrac{Interest Rate}{Number of Periods}) ^{(Periods * Time )\)

Substituting the value back into the formula as

Future Value = \($2,560 (1 + \dfrac{0.068}{12} )^{(12 * 6)\)

                      = \($2,560 (1 + 0.00566667)^{(72)\)

                      = \($2,560 (1.00566667)^{(72)\)

                      = $2,560 * 1.44044291

                       = $3,691.10

Therefore, the balance is $3,691.10.

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Answer:

\( \sf \: a) \: 27 = 9p \: ; p = 3\)

Step-by-step explanation:

Given information,

→ Simon have 27 pieces of candy.

→ Each person will get 9 pieces.

Now we have to,

→ Find the required equation.

The equation will be,

→ 27 = 9p

→ 9p = 27

=> As each person (p) gets 9 pieces.

Then the value of p will be,

→ 9p = 27

→ p = 27 ÷ 9

→ [ p = 3 ]

Hence, option (a) is correct.

A second linearly independent solution of y₂ is \(-\frac{1}{6x^3}\)

The general Equation is y" + P(x)y' + q(x)y = 0 ...............(i)

where P(x), Q(x) are continues in the internal I ≤ R.

If y₁(x) is a solution of equation 1 in I then y₁(x) ≠ 0.

Then y₂(x) = y₁(x)\(\int{\frac{e^{-\intP(x)dx}}{(y_{1}x)^2}}dx\) is another solution.

The differential equation is x²y" + xy' – 9y = 0 where x > 0.

As y₁(x) = x³ is one solution of differential equation.

Divide throughout by (x²) to given differential equation.

1/x² (x²y" + xy' – 9y = 0)

y" + (y'/x) – (9/x²)y = 0 ................(ii)

By comparing equation (i) & (ii) we get:

p(x)=1/x , q(x)= –are continuous for x>0

So, another solution,

y₂(x) = y₁(x)\(\int{\frac{e^{-\intP(x)dx}}{(y_{1}x)^2}}dx\)

Now putting the values of P(x) And Q(x)

y₂(x) = \(x^3\int\limits {\frac{e^{\int(1/x)dx} }{(x^3)^2}} \, dx\)

y₂(x) = \(x^3\int\limits {\frac{\frac{1}{x} }{x^6} }} \, dx\)

y₂(x) = \(x^3\int\limits {\frac{1}{x^7} }} \, dx\)

y₂(x) = \(x^3\int\limits {x^-7} } \, dx\)

y₂(x) = \(x^3\left[\frac{x^{-7+1}}{-7+1}\right]\)

y₂(x) = \(-\frac{1}{6}(x^3\times x^{-6})\)

y₂(x) = \(-\frac{1}{6x^3}\)

So, the answer of this question is \(-\frac{1}{6x^3}\).

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Answer:

\(m\angle 2=95^{\circ}\)

Step-by-step explanation:

It is given that ∠1 and ​∠2​ are a linear pair. So, there sum is 180 degrees.

\(m\angle 1+m\angle 2=180^{\circ}\)    ...(1)

∠2​ and ​∠3​ are vertical angles. So, both are equal.

\(m\angle 2=m\angle 3\)     ...(2)

From (1) and (2), we get

\(m\angle 1+m\angle 3=180^{\circ}\)

Substitute \(m\angle 1=(3y+10)^{\circ}\) and \(m\angle 3=(5y-30)^{\circ}\) in the above equation.

\((3y+10)^{\circ}+(5y-30)^{\circ}=180^{\circ}\)

\((8y-20)^{\circ}=180^{\circ}\)

\(8y-20=180\)

\(8y=180+20\)

Divide both sides by 8.

\(y=\dfrac{200}{8}\)

\(y=25\)

The value of y is 25.

Using equation (2), we get

\(m\angle 2=m\angle 3=(5y-30)^{\circ}\)

Substitute y=25.

\(m\angle 2=(5(25)-30)^{\circ}\)

\(m\angle 2=(125-30)^{\circ}\)

\(m\angle 2=95^{\circ}\)

Therefore, \(m\angle 2=95^{\circ}\).