6. the color code of a resistor (from band 1 through band 4) is brown-black-orange-gold. what is the approximate value of the resistor? group of answer choices 100 kohm 100 ohms 10 kohms 1 kohm

ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

In regards to auto repair information tools, the solution that is known to be made available is the use of ShopKey® Pro with 1Search.

This is know  to be a kind of an exclusive auto repair software that helps to streamlines the search acts to bring closer a special  combination of OEM data as well as experience-based Real Fixes.

Therefore, based on the above, one can say that ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

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False, Good housekeeping eliminates accident and fire hazards. It also maintains safe, healthy work conditions; saves time, money, materials, space, and effort; improves productivity and quality; boosts morale; and reflects an image of a well-run, successful organization.

Hope it helps you❤️

Then  you go to find the system requirements are the D. None of these as none of it dictates about the  find the system requirements hen needed.

User necessities describe what the person ought to do . System necessities describe how will the person acquire person necessities while interacting with the device plus nonpurposeful necessities such as "the device ought to cope with one hundred thousand customers on the identical time". So: User requirement : The person ought to see their check results.Where is device necessities.

For packaged products, device necessities are regularly imprinted on the packaging. For downloadable products, the device necessities are regularly indicated at the download page. System necessities may be widely categorized as purposeful necessities, records necessities, pleasant necessities and constraints.

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Answer: A fly wheel having a mass of 30kg was allowed to swing as pendulum about a knife edge at inner side of the rim as shown in figure.

Explanation:

Answer:

They moved fresh water around their vast empire with aqueducts and canals.

Explanation:

Over 8 straight days of playing

200+ hours, if you're a game master

The reaction at the beam support is 6300 N, and the moment at the beam support is -25200 N·m (negative sign indicates clockwise moment).

To determine the reactions and moments at the beam supports, we can use the principles of static equilibrium. Let's go through the step-by-step explanation:

Step 1: Identify the Given Information

We are given the following information:

- Load on the beam: F = 500 N/m and Fi = 1600 N/m

- Distance between supports: 4 m

Step 2: Calculate the Total Load on the Beam

To calculate the total load on the beam, we need to find the area under the load curve. In this case, the load is linear, so we can calculate the area of the trapezoid formed by the load curve.

Total load = Area of trapezoid = (0.5 * F + Fi) * distance between supports

Total load = (0.5 * 500 + 1600) * 4

Total load = 6300 N/m

Step 3: Determine the Reaction Forces

Since the beam is in static equilibrium, the sum of the vertical forces must be zero. This allows us to calculate the reaction forces at the beam supports.

Let's assume that the left support experiences a reaction force R1, and the right support experiences a reaction force R2.

ΣFy = 0:

R1 + R2 - Total load = 0

R1 + R2 = Total load

R1 + R2 = 6300 N

Step 4: Determine the Moments at the Beam Supports

To calculate the moments at the beam supports, we can use the principle that the sum of the moments about any point must be zero.

Taking moments about the left support (point A):

ΣMA = 0:

-Total load * distance between supports + R2 * distance between supports - Moment at left support = 0

-6300 * 4 + R2 * 4 - Moment at left support = 0

Moment at left support = -6300 * 4 + R2 * 4

Step 5: Substitute Known Values and Solve

Using the information from step 3, we can substitute the known values into the equation for the moment at the left support and solve for R2.

Moment at left support = -6300 * 4 + R2 * 4

Moment at left support = -25200 + R2 * 4

Since the reaction at the left support is given as 6300 N, we can solve for R2.

6300 = -25200 + R2 * 4

R2 * 4 = 31500

R2 = 7875 N

Therefore, the reaction at the right support is R2 = 7875 N, and the moment at the left support is -25200 N·m.

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A beam and its loeding is shown where F 500 N/m. Fi 1600 N/m 4. 5.00 points Determine the reactions and moments at the beam supports. (Round the reaction to the nearest whole number and the moment to one decimal place.,) The reaction at the beam support is 6300 N The moment at the beam support is kN m.

Answer: yes because fish its like quick sand is will just fall apart into tiny pecies to now it want us to round to the nearst hundredth so what is 12 divide by 3 and time 1

12:3x1=4 because we are rounding to the nearst hundredth

=4

Explanation:

Based on the information, the tube thickness that should be used is 3.18 mm.

Power = Torque * Angular velocity

100 kW = Torque * (2 * pi * 36 Hz)

Torque = 2212.14 N-m

In this case, the polar moment of inertia is:

J = pi * 50⁴ / 32 = 196250 pi mm⁴

Maximum shear stress = Torque / J

Maximum shear stress = 2212.14 N-m / 196250 pi mm⁴ = 0.0499 MPa

Tube thickness = 2 * ✓(60 MPa / pi * 50²) = 3.18 mm

Therefore, the tube thickness that should be used is 3.18 mm.

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Seismic surveys involve generating and recording waves of energy.  Magnetic surveys measure variations in the Earth's magnetic field , Gravity surveys measure variations in the Earth's gravitational field Electrical surveys involve measuring the electrical properties.

(i) Seismic Survey: Seismic surveys involve generating and recording waves of energy that propagate through the subsurface. By analyzing the response of these waves, seismic surveys can provide information about the subsurface structure, rock layers, and the presence of oil and gas reservoirs. In engineering, seismic surveys are used for site investigations, assessing subsurface conditions for infrastructure projects, identifying potential geological hazards, and locating underground utilities.

(ii) Magnetic Survey: Magnetic surveys measure variations in the Earth's magnetic field caused by variations in the magnetic properties of subsurface materials. These surveys are useful in identifying magnetic anomalies associated with different rock types, mineral deposits, and geological structures. In engineering, magnetic surveys are applied to locate buried ferrous objects, mapping geological structures, and identifying potential archaeological sites.

(iii) Gravity Survey: Gravity surveys measure variations in the Earth's gravitational field caused by variations in subsurface density. They are effective in identifying variations in rock density, mapping subsurface structures, and locating potential mineral deposits. In engineering, gravity surveys are used for mapping geological formations, identifying subsurface faults, and assessing groundwater resources.

(iv) Electrical Survey: Electrical surveys involve measuring the electrical properties of subsurface materials, such as resistivity or conductivity. By studying the variations in electrical properties, these surveys can provide insights into subsurface lithology, groundwater presence, and contaminant plumes. In engineering, electrical surveys are applied in groundwater exploration, site characterization for construction projects, locating underground utilities, and assessing the stability of slopes.

Overall, these geophysical survey methods play crucial roles in engineering by providing valuable information about subsurface conditions, geological features, and potential hazards. They help engineers and geoscientists make informed decisions during the planning, design, and construction phases of various projects, ensuring the safety and efficiency of engineering endeavors.

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The value of discount rate after the execution of the given code is 0.0 and 0.04.

discountRate will have a value of 0.0. If case B matches, the discountRate changes to 0.06; if there is no break, the next case is processed; the discountRate changes to 0.04; and if there is no break, the discountRate changes to 0.0.

DiscountRate will have a value of 0.04. The second if condition checks to see if cust == 'Y', which is false, thus else is run, and this discountRate changes to 0.04 as a result.

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Following the execution of the provided code, the discount rate is between 0.0 and 0.04.

In a discounted cash flow (DCF) analysis, the discount rate is the interest rate that is used to calculate the present value of future cash flows.

The value of discountRate will be 0.0. The discountRate changes to 0.06 if case B matches; to 0.04 if there is no break; to 0.0 if there is no break. If there is no break, the next case is processed; and the discountRate remains unchanged.

DiscountRate will have a value of 0.04. The second if condition checks to see if cust == 'Y', which is false, thus else is run, and this discountRate changes to 0.04 as a result.

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Answer:

a) 4160 V

b) 12 kW and 81 kVAR

c)  54 kW and 477 kVAR

Explanation:

1) The phase voltage is given as:

\(V_p=\frac{3810.5}{\sqrt{3} }=2200 V\)

The complex power S is given as:

\(S=560.1(0.707 +j0.707)+132=660\angle 36.87^o \ KVA\)

\(where\ S^*\ is \ the \ conjugate\ of \ S\\Therefore\ S^*=660\angle -36.87^oKVA\)

The line current I is given as:

\(I=\frac{S^*}{3V}=\frac{660000\angle -36.87}{3(2200)} =100\angle -36.87^o\ A\)

The phase voltage at the sending end is:

\(V_s=2200\angle 0+100\angle -36.87(0.4+j2.7)=2401.7\angle 4.58^oV\)

The magnitude of the line voltage at the source end of the line (\(V_{sL}=\sqrt{3} |V_s|=\sqrt{3} *2401.7=4160V\)

b) The Total real and reactive power loss in the line is:

\(S_l=3|I|^2(R+jX)=3|100|^2(0.4+j2.7)=12000+j81000\)

The real power loss is 12000 W = 12 kW

The reactive power loss is 81000 kVAR = 81 kVAR

c) The sending power is:

\(S_s=3V_sI^*=3(2401.7\angle 4.58)(100\angle 36.87)=54000+j477000\)

The Real power delivered by the supply = 54000 W = 54 kW

The Reactive power delivered by the supply = 477000 VAR = 477 kVAR

Answer:

Explanation:

be confident

Studies of surface water are not typically used to explore groundwater.

Option C is the correct answer.

We have,

Exploring groundwater involves investigating and assessing the presence, availability, and characteristics of groundwater resources beneath the Earth's surface.

Groundwater refers to the water stored underground in spaces between soil particles, and rocks, and within underground aquifers.

Here are some commonly used approaches:

Geologic Field Studies

Gravity Surveys

Studies of Surface Water:

Drilling

Thus,

Studies of surface water are not typically used to explore groundwater.

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Answer:

we can conclude that  91.04% population of shafts are usable

Explanation:

Given that;

X\(_{min}\) = 37.50 mm

X\(_{max}\) = 38.20 mm

mean μ = 37.80

standard deviation σ = 0.20 mm

This problem is based on normal probability distribution so, to get the probability, we must calculate; z = x-μ / σ

so;

Z\(_{min}\) = (X\(_{min}\) - μ) / μ = (37.50 - 37.80) / 0.20 =  -1.5

Z\(_{max}\) = (X\(_{max}\) - μ) / μ = (38.20 - 37.80) / 0.20 =  2

Hence;

P( 37.50 < X < 38.20 ) = P( -1.5 < Z < 2 )

P( 37.50 < X < 38.20 ) = P( 0 < Z < 1.5 ) + P( 0 < Z < 2 )

from the standard normal table table;

P( 37.50 < X < 38.20 ) = 0.4332 + 0.4772

P( 37.50 < X < 38.20 ) = 0.9104 = 91.40%

Hence, we can conclude that  91.04% population of shafts are usable

Using the Newton's second law of motion we will see that the acceleration is  0.0875 m/s^2.

The acceleration of a vehicle is determined by the force acting on it and its mass, as described by Newton's second law of motion:

F = m * a

where F is the force acting on the object, m is the mass of the object, and a is the resulting acceleration.

In this case, the force acting on the vehicle is 0.07 N, and the mass of the vehicle is 0.8 kg. Substituting these values into the equation above, we get:

0.07 N = 0.8 kg * a

Solving for a, we get:

a = 0.07 N / 0.8 kg

a = 0.0875 m/s^2

Therefore, the acceleration of the 0.8 kg vehicle powered by 0.07 N of force is 0.0875 m/s^2.

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The  option that has the correct order or sequence of events are;

1) Scan host.

2) Add host to subscription.

3) Use host as report source.

Host assets are known to be a kind of IP addresses in a person's account. This type of assets is one that can be used as a kind of  scan, map and also to report targets.

A person can view the hosts in their account by going the  Assets panel to  the Host Assets. One can add new hosts by the use of the New menu. The person can also only carry out actions like scanning, mapping and reporting on one's hosts.

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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Additionally, your calculated experimental specific heat capacity would be lower than the real specific heat capacity when you plug your calculated temperature change into the specific heat capacity calculation.

The quantity of heat energy needed to raise the temperature of 1 kg of a material by 1 K is measured as specific heat capacity.

The amount of heat required to increase the temperature of 1 gram of a substance by 1 degree Celsius (°C) is known as specific heat. Since water has a higher specific heat than other substances, it requires more energy to raise its temperature.

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Answer: straight blade and locking

Explanation: Electrical receptacles come in straight blade and locking varieties.

Answer:

1) 4.41 * 10^-4 kw

2) 2.20 * 10^-4 kw

Explanation:

Given data:

Filter = 500 m^3/min

dust velocity = 3g/m^3

bag ; length = 3 m , diameter = 0.13 m

change in pressure = 1 kPa

efficiency = 60%

1) Calculate the Fan power

First :

Calculate the total dust loading = 3 * 500 = 1500 g

To determine the Fan power we will apply the relation

\(n_{o} = \frac{\frac{p}{eg*Q*h} }{1000}\)    = \(\frac{\frac{p}{(3*10^{-3})* 981*( 500/60) *3 } }{1000}\)

fan power ( \(n_{0}\) ) = 4.41 * 10^-4 kw

2) calculate power drawn

change in P = 6 atm = 6 * 10^5 pa

efficiency compressor = 50%

hence power drawn = 4.41 * 10^-4 kw  * 50% = 2.20 * 10^-4 kw

Answer:

Copper and Aluminum

Explanation:

The missing term in the presented paragraph is environmental.

In recent years the effects of climate change have been strongly manifested around the world causing:

Therefore, many companies have begun to investigate productive alternatives to reduce their environmental impact. In the case of the car industry, companies have deepened their research on other sources of energy such as:

One of them is Toyota, the Japanese brand that has developed cars that work hybrid, that is, with gasoline and electric power. This will reduce the emissions of CO2 and other harmful gases into the atmosphere.

Therefore, it is possible to infer that the missing term in the paragraph is Environmental.

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Answer:

Here is a Python function to calculate the sum of squares of a list of numbers:

python

Copy code

def sum_of_squares(numbers):

 return sum([x**2 for x in numbers])

You can use this function by passing a list of numbers as an argument:

scss

Copy code

numbers = [1, 2, 3, 4, 5]

result = sum_of_squares(numbers)

print(result) # Output: 55 (1^2 + 2^2 + 3^2 + 4^2 + 5^2)

Explanation:

Answer:

These formal systems state exactly what work is to be done, where and when. In many organisations, people doing the actual work are required to sign a permit to work document to confirm that they have understood all processes and guidelines of the system. Permits also serve as a means of communication between site workers and the organisation’s management.

However, they should not be mistaken as a replacement for robust risk assessment, which should happen simultaneously. Having a permit to work systems as part of organisational operations reduces the risks of losses or damage due to unsafe activities in a non-trivial work atmosphere.

These systems ensure that the correct jobs are entrusted to appropriate individuals and review or audit of conditions are also undertaken by experts or authorised personnel who have proven capabilities of undertaking the respective responsibilities. Permit to work systems also confirms that work is completed safely and the workplace is restored to its safe, original form for normal operations to commence.

Answer:

Carpenter's square

Explanation:

The most common hand tool used to measure or set angles with its application extending to setting angles of roofs and rafters. Another name of a Carpenter's square is a framing square.

Other hand tools that are used to measure angles are;

The total voltage in a series circuit is the sum of each of the circuit's individual voltage drops. In a series circuit, a difference in potential is created across each resistor as current flows through them.

The instantaneous voltage drop across an inductor is inversely correlated with the rate at which the current through the inductor changes. V = L (di/dt) represents the mathematical relationship. Instrument transformers of the voltage transformer (VT) and potential transformer (PT) variety are parallel-connected. They are made to put a minimal load on the supply being measured and have a precise voltage ratio and phase relationship to allow for precise secondary connected metering.

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Answer:

True

Explanation:

Because the Electric Magnetic Field is the work done per unit charge where other forms of energy is tranferred to electrical energy