8. An object of mass 4 kg moving with a speedof 29 m/s to the right collides with an objectof mass 11.5 kg moving with a speed of 18 m/sto the left. After collision, the 11.5 kg object movesto the right with a speed of 4 m/s to the right. Calculatethe velocity of the 4 kg object after collision. (1 point)A. O-53.475 m/sB. O-13.341 m/sC. O-34.25 m/sD. -19.579 m/sE. O-27.7 m/s9. An object of mass 2 kg moving with a speed

8. An Object Of Mass 4 Kg Moving With A Speedof 29 M/s To The Right Collides With An Objectof Mass 11.5

Answers

Answer 1

Given

Mass of one object, m=4 kg

Velocity of the object, u=29 m/s towards the right

Mass of the other object, m'=11.5 kg

Velocity of the other object, u'=18 m/s towards left

After collision

The object with mass 11.5 kg moves at a speed, v'=4 m/s towards right

To find

The velocity of the object with mass 4 kg after collision

Explanation

Let the direction towards right be positive

By conservation of momentum

\(\begin{gathered} mu+m^{\prime}u^{\prime}=mv+m^{\prime}v^{\prime} \\ \Rightarrow4\times29-11.5\times18=4v+11.5\times4 \\ \Rightarrow v=-34.25\text{ m/s} \end{gathered}\)

Conclusion

The velocity of the object is C.-34.25 m/s


Related Questions

A parallel-plate capacitor is constructed of two horizontal 16.8-cm-diameter circular plates. A 1.8 g plastic bead, with a charge of -4.4 nC is suspended between the two plates by the force of the electric field between them.
a. Which plate, the upper or the lower, is positively charged?
b. What is the charge on the positive plate?

Answers

Answer:

Explanation:

Given that:

diameter of the circular plates = 16.8 cm

mass of the plastic bead = 1.8 g

charge q = -4.4 nC

From above, the area of the circular plates is:

\(Area = \pi r^2\)

\(Area = \pi (\dfrac{d}{2})^2\)

\(Area = \pi (\dfrac{16.8}{2*100} m)^2 \\)

Area = 0.022 m²

Thus, as the plastic beads glide between the two plates of the capacitor, there exists a  weight acting downwards while the weight is balanced by the force of the plates acting upwards.

Hence, this can be achieved only when the upper plate is positively charged.

b)

Recall that

Force (F) = qE

where;

F = mg

mg = qE

\(E = \dfrac{mg}{q}\)

\(E = \dfrac{1.8*10^{-3}*9.8}{4.4*10^{-9}}\)

E = 4.0 × 10⁶ N/C

From the electric field;

\(E = \dfrac{\Big(\dfrac{Q}{A}\Big)}{e_o}\)

\(4.0*10^{6} = \dfrac{\Big(\dfrac{Q}{0.022}\Big)}{8.85*10^{-12}}\)

\(4.0*10^{6}*8.85*10^{-12} = {\Big(\dfrac{Q}{0.022}\Big)}{}\)

\(Q= 4.0*10^{6}*8.85*10^{-12}*0.022\)

Q = 7.788 × 10⁻⁷ C

Q = 779 nC

The heating element in an electric kettle is rated as 2.0 kW. If the water in the kettle is at 100.0 °C, what volume of water will be converted into steam in one minute? The specific latent heat of vaporization of the water is 2,257,000 J/kg and the
3 density of water is 1,000 kg/m .

Answers

Answer:

The volume is  \(V =5.32 *10^{-5} \ m^3\)

Explanation:

From the question we are told that

    The power of the heating element is \(P = 2.0 kW = 2.0 *10^3 \ W\)

    The temperature of the water in the kettle is  \(T _w = 100^oC\)

     The time to convert water to steam is t = 1 minute = 60 sec

      The specific latent heat of vaporization is \(H_v = \ 2,257,000 J/kg\)

      The density of water is \(\rho_w = 1000\ kg/m^3\)

The power of the heating element is mathematically represented as

      \(P = \frac{E}{t}\)

Where E  Energy generated by the heating element in term of heat

      \(E = Pt\)

substituting values

      \(E = 2.0 *10^{3} * 60\)

      \(E = 120000 J\)

Now

 The latent heat of vaporization is mathematically represented as

         \(H_v = \frac{E}{m}\)

Where m is the mass of water converted to steam

 So

      \(m = \frac{E}{H_v}\)

substituting values

      \(m = \frac{120000}{2257000}\)

     \(m = 0.0532\ kg\)

The volume of water converted to steam is mathematically evaluated as

    \(V = \frac{m }{\rho_w}\)

substituting values

   \(V = \frac{0.0532}{1000}\)

    \(V =5.32 *10^{-5} \ m^3\)

The cycling of the air is a natural phenomenon as shown above is the result of

The cycling of the air is a natural phenomenon as shown above is the result of

Answers

Answer:

natural convection

............

The density of water in a lake is 1000 kg/m³
At a depth of 25m beneath the surface of the lake, the total pressure is 3.5×10⁵ Pa
(a) State what is meant by pressure.
(b) The gravitational field strength is 10 N/kg
. Determine:
(i) the pressure due to 25m of water
pressure =
(ii) the atmospheric pressure=____
atmospheric pressure =_____

The density of water in a lake is 1000 kg/mAt a depth of 25m beneath the surface of the lake, the total

Answers

(i) The pressure due to 25m of water is 250,000 Pa.

(ii) The atmospheric pressure is 100,000 Pa.

What is pressure?

Pressure can be defined as the force per unit area of an object.

Mathematically, the formula for pressure of an object is derived as;

P = F/A

where;

F is the applied force on the objectA is the area of the object

P = (mg) / (V/h)

P = (mgh) / V

P = (m/V)gh

where;

m is massV is volume of the objectg is acceleration due to gravityh is height or depth

Density of an object or a substance is known as mass per unit volume of the substance.

P = (ρ)gh

where;

ρ is the density

The pressure due to 25m of water is calculated as follows;

pressure = (ρ)gh

pressure = 1000 kg/m³   x   10 N/kg    x    25 m
pressure = 250,000 Pa

The atmospheric pressure is calculated as;

P(atm) = P(total) - P(water)

P(atm) = 350,000 Pa  -  250,000 Pa

P(atm) = 100,000 Pa

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An egg is thrown downward off a tall building with a velocity of 3.5 m/s. If the egg falls a
total distance of 25 m. How fast will the egg be traveling just before hitting the ground?
A.-9.8 m/s
B. 22.41 m/s
C. 502.25 m/s
D. 22.0 m/s

Answers

The velocity of the egg thrown off the tall building just before hitting the ground is 22.41m/s.

What is the final velocity of the egg just before hitting the ground?

The final velocity of the egg can be determined using the third equation of motion;

v² = u² + 2gs

Where v is final velocity, u is initial velocity, s is distance and g is acceleration due to gravity. ( g = 9.8m/s² )

Given the data in the question;

Initial velocity u  3.5m/sDistance s = 25mAcceleration due to gravity g = 9.9m/s²Final velocity v = ?

To determine the final velocity of the egg just before hitting the ground, plug the given values into the third equation of motion and solve for v.

v² = u² + 2gs

v² = (3.5)² + ( 2 × 9.8 × 25 )

v² = 12.25 + 490

v² = 502.15

Take the square root of both sides

v = √502.15

v = 22.41m/s

The velocity of the egg thrown off the tall building just before hitting the ground is 22.41m/s.

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What does it mean when work is positive?
O Velocity is greater than kinetic energy
O Kinetic energy is greater than velocity
The environment did work on an object.
O An object did work on the environment.

Answers

Answer:

d. An object did work on the environment.

Explanation:

Work is defined in many contexts. Some of these are;

i. Work is the product of force and displacement. In this case, work done is positive if the force applied on an object or body and the displacement caused by the force are in the same direction. If instead the force and displacement are in opposite direction, then the work done will be negative. If it is the case the force and the displacement are perpendicular to each other, the work done is zero.

ii. In the first law of thermodynamics, the internal energy of a system is the sum of the work done and the heat exchanged between the system and the environment. Therefore, work done is the difference between the internal energy of a system and the heat exchanged between the system and the environment.

In this case, work is said to be positive if work is done by the system (object) on the environment. It is negative if work is done by the environment on the system (object).

Answer:

its c

Explanation:

Which number represents runoff on the hydrologic cycle diagram?


1


2


3


4

Which number represents runoff on the hydrologic cycle diagram?1234

Answers

Answer:

number 3

Explanation:

3 represents runoff


Runoff is the water collected after rainfall that drains from the surface area of land. It will be tricky to choose 4 which is likely a smaller waterbody draining to a bigger waterbody


hope it helped

mega rayquaza and zygarde 100% form vs lunala, solgaleo, and red's mega charizard

Answers

Answer:

That right there is what caused the world to end my friend

Explanation:

Mr. MacDougall got his vehicle stuck in the snow. Being the nice student that you are, you stop to help Mr. MacDougall out of the snow. You exert a force of 350N on his vehicle and manage to push it 15m and completely out of the snow. How much work was done on the vehicle?

Answers

Answer:

Explanation:

work done=force*displacement

=350N*15m

=5250 joule

I heat 29.292 g of an unknown metal up to 99.9 °C. While it is heating, I weigh out 27.777 g of water, and find its initial
temperature is 22.1 "C. When I mix the metal and water in an insulated container, the temperature of the mixture rises
to 29.3 °C.
What is the most likely specific heat of the metal?
Select one:
a. 4.8 (104) cal / (g *C)
b. 9.7 (102) cal/(g*C)
c. 7.9 (10³) cal/ (g*C)
Od: 0.13 cal / (g°C)
e. 9.8 (105) cal / (g°C)

Answers

The specific heat capacity of the metal, given that 27.777 g of water at 22.1 °C was mixed with the metal is 9.7×10⁻² Cal/gºC

How do I determine the specific heat capacity of the metal?

Step 1: Obtain the heat absorbed by the water. This is shown below:

Mass of water (M) = 27.777 gInitial temperature (T₁) = 22.1 °CFinal temperature (T₂) = 29.3 °CTemperature change (ΔT) = 29.3 - 22.1 = 7.2 °CSpecific heat capacity of water (C) = 1 Cal/gºC Heat absorbed (Q) =?

Q = MCΔT

= 27.777 × 1 × 7.2

= 199.9944 Cal

Step 2: Determine the specific heat capacity of the metal using the heat absorbed by the water. Details below:

Heat absorbed by water (Q) = 199.9944 CalHeat released by metal (Q) = -199.9944 CalMass of metal (M) = 29.292 gInitial temperature (T₁) = 99.9 °CFinal temperature (T₂) = 29.3 °CTemperature change (ΔT) = 29.3 - 99.9 = -70.6 °CSpecific heat capacity of metal (C) = ?

Q = MCΔT

-199.9944 = 29.292 × C × -70.6

-199.9944 = -2068.0152 × C

Divide both sides by -2068.0152

C = -199.9944 / -2068.0152

= 9.7×10⁻² Cal/gºC

Thus, the specific heat capacity of the metal is 9.7×10⁻² Cal/gºC. None of the options are correct.

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What is an ionic bond?

Answers

A.) a bond that forms when electrons are transferred from one atom to another

Ionic bond is a bond which is formed by transfer of electronsIt forms inbetween two elements having huge electronegativity differences It usually forms inbetween metal and nonmetals

Ex:-NaCl

How can i find Air velocity??????????????

How can i find Air velocity??????????????

Answers

Answer: By dividing airflow by duct cross section.

Explanation:

In short, air velocity in the ducts is calculated by dividing airflow by duct cross-section. Airflow is expressed as a simple number. Example: Air conditioner has a max. airflow of 600 CFM.

6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]​

Answers

The mass of the picture is approximately 5.19 kilograms.

How to solve for the problem

The deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).

The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:

τ = G * γ

To find the weight of the picture, we need to calculate the shear stress first:

The cross-sectional area A of the nail is given by the formula for the area of a circle:

A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².

The shear strain γ is given by:

γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.

The shear stress τ can now be calculated by rearranging the formula:

τ = G * γ

=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²

The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:

τ = F / A

=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.

Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:

m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.

So, the mass of the picture is approximately 5.19 kilograms.

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If the half life of an isotope is 20 years, how much of the original amount will
remain after 20 years has passed?

Answers

Answer:

Half

Explanation:

If the half life of an isotope is 20 years, then half of the original amount will  remain after 20 years has passed.

That's what "half-life" means.

Similarly, after ANOTHER 20 years, 1\4 of the original amount remains.

And after ANOTHER 20 years, 1\8 of the original amount remains.

And after ANOTHER 20 years, 1\16 of the original amount remains.

And after ANOTHER 20 years, 1\32 of the original amount remains.

And after ANOTHER 20 years, 1\64 of the original amount remains.

And after ANOTHER 20 years, 1\128 of the original amount remains.

What happens when you pay bills using a computer

Answers

Answer:

Money is transferred from your account to creditors' accounts

Explanation:

When performing online activities that require payments of bills on a computer. The very moment you decided to pay your bills using a computer, your money will be transferred immediately from your account to creditors' accounts. This will imply that the transaction is successful and you have paid your bills.

Hence, in this case, the correct answer is "Money is transferred from your account to creditors' accounts."

Answer:

U become g**

Explanation:

Ur a**

Two charged particles, with charges q1 = q and q2 = 4q are located at a distance d = 2cm apart on the x axis A third charged particle, with charge q3 = q is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3. Find the position of charge 3 when q = 10n C

Answers

Answer:

0.667 cm

Explanation:

|F_1on3| = |F_2on3|

k×q1×q3/x^2 = k×q2×q3/(d-x)^2

q1/x^2 = q2/(d-x)^2

(d-x)^2/x^2 = q2/q1

(d-x)/x = sqrt(q2/q1)

(2 - x)/x = sqrt(4×q/q)

(2 - x)/x = 2

2 - x = 2x

2 = 3x

x = 2/3

x= 0.667 cm

For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is 28.0 cmcm long) after reflecting from the first mirror

Answers

This question is incomplete, the complete question is;

Two plane mirrors intersect at right angles. A laser beam strikes the first of them at a point 11.5 cm from their point of intersection, as shown in the figure.

For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is 28.0 cmcm long) after reflecting from the first mirror

Answer: angle of incidence is 39.4°

Explanation:

Given that;

two plain mirrors intersect at right angle (90°)

distance d = 11.5 cm

S = 28.0 cm

Now the angle that the reflection ray males with first the mirror equal theta  (∅)

so

tan∅ = (S/2) / d

tan∅ = (28/2) / 11.5

tan∅ = 14 / 11.5

tan∅ = 1.2173

∅ = tan⁻¹ (1.2173)

∅ = 50.6°

so angle of incidence = 90° - ∅

= 90° - 50.6°

= 39.4°

Therefore angle of incidence is 39.4°

For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror

: Consider a man standing on a scale which is placed in an elevator. When the elevator is stationary, the scale reading is his weight W. Scale Find S, the scale reading when the elevator 1 is moving upward with acceleration a = 69.

Answers

S= 1.167W Due to the fact that the scale reads W when the elevator is stationary, the real weight of a man is (W = mg) acting downward. Apply Newton's second equation of motion to the elevator now traveling upward with an acceleration of a = g/6.

Explain the principles of acceleration:

Acceleration is the rate at which the speed and direction of a moving object change over time. A point or item is moving ahead in a straight line whether it is moving faster or slower.

Describe acceleration with an example:

An item has positive acceleration if it is accelerating and travelling in the right direction. Positive acceleration was demonstrated in the first case by the fast automobile. The automobile is speeding up and moving forward in a good way.

S= ma + W

S = m*g/6 + W

S = mg/6 +W

S = W/6 + W

S = 7W/6

S = 1.167W

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When, how and where are questions asked during critical inquiry?*
1 p
True
False

Answers

Answer:

true

Explanation:

Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal. How long is it in the air?

Answers

Given :

Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal.

To Find :

How long is it in the air.

Solution :

We know, the formula of time of flight is :

\(T = \dfrac{2usin\ \theta}{g}\\\\T = \dfrac{2\times 30\times sin\ 30^o}{9.8}\\\\T = 3.06\ seconds\)

Therefore, the ball is in air for 3.06 seconds.

A gas in a cylinder is held at a constant pressure of 1.8×105 Pa and is heated and expanded from 1.2 m3 to 1.7 m3. What is the work done by (or on) the gas?


a. 5.2×105 J done by the system
b. 9.0×104 J done on the system
c. 9.0×104 J done by the system
d. 5.2×105 J done on the system

Answers

Answer:

\(W_{by}=9.00 \times 10^4 \ J\\\\W_{on}=-9.00 \times 10^4 \ J\)

Option (c) is correct.

Explanation:

\(\boxed{\left\begin{array}{ccc}\text{\underline{Work done on/by a gas:}}\\W_{by}=P \Delta V \ or \ \int\limits^{V_f}_{V_0} {P} \, dV \\W_{on}=-P\Delta V \ or \ -\int\limits^{V_f}_{V_0} {P} \, dV \end{array}\right }\)

Given:

\(P=1.8 \times 10^5 \ Pa\\\\V_0=1.2 \ m^3\\\\V_f=1.7 \ m^3\)

Find:

\(W_{by}=?? \ J\\\\W_{on}=?? \ J\)

(1) - Calculating the change in volume

\(\Delta V= V_f-V_0\\\\\Longrightarrow \Delta V=1.7-1.2\\\\\therefore \boxed{\Delta V=0.5 \ m^3}\)

(2) - Calculating the work done by the gas

\(W_{by}=P \Delta V\\\\\Longrightarrow W_{by}=(1.8 \times 10^5)(0.5)\\\\\therefore \boxed{\boxed{W_{by}=9.00 \times 10^4 \ J}}\)

(3) - Calculating the work done on the gas

\(W_{on}=-P \Delta V\\\\\Longrightarrow W_{on}=-(1.8 \times 10^5)(0.5)\\\\\therefore \boxed{\boxed{W_{on}=-9.00 \times 10^4 \ J}}\)

Options (a) and (d) can be eliminated. Option (b) can be eliminated since there is no negative in front of the answer. This leaves the correct answer being option (c).

An object has a mass of 450g. What is the gravitational force of the object by earth?

Answers

Answer:

4.41N or 4.5N (check explanation)

Explanation:

450g = 0.45kg

F = ma

Using 10m/s² = 10(0.45) = 4.5N

Using 9.8m/s² = 9.8(0.45) = 4.41N

Suppose the width of your fist is 5.3 inches and the length of your arm is 26.0 inches. Based on these measurements, what will be the angular width (in degrees) of your fist held at arm’s length?

Answers

Answer:

the suppose the widtge frist is 6.5 inches and the lenth of your arm is 320 and 500

how to find potential energy

Answers

Answer:

The formula for potential energy depends on the force acting on the two objects.

Hanna tosses a ball straight up with enough speed to remain in the air for several seconds.

A: What is the velocity of the ball when it reaches its highest point?

B: What is its velocity 1 s before it reaches it’s highest point?

C: What is the change in its velocity during this 1-s interval?

D: What is its velocity 1 s after it reaches its highest point ?

E: What is the change in velocity during this 1 s interval?

F: What is the change in velocity during the two second interval?

G: what is the acceleration of the ball during any of these time intervals and the moment the ball has zero velocity?

Answers

Answer:

In the free fall motion we have that the acceleration is constant and produced by gravity, this acceleration has a magnitude of 32 ft/s2 or 9.8 m/s2 depending on the units you are working with. This means that every second the speed changes a magnitude of 32 ft/2, the velocity will depend of whether the ball is going upward (positive) or downward (negative).

A) At the highest point the ball stops to start the descend, here v=0 ft/s

B) +32 ft/s. The vector is going up, in the next second the velocity is going to be 0 (negative acceleration)

C) V=vf-vo=0-32=-32 ft/s is the constant change in velocity in projectile motion

D) -32 ft/s. The vector is pointing downward

E) V=vf-vo=-32-0=-32 ft/s is the constant change in velocity in projectile motion, 32 ft/s per second

F) Delta V=vf-vo=-32-32=-72 ft/s

g) gravity acceleration is constant 32 ft/s2 (pointing downward vector)

5j-Tj=6j+3 Tj
Determine the value of T from the given vector

Answers

-1/4

Solve for j and Tj than you have
-j=4Tj
4T=-j/j
4T=-1
T=-1/4

PLEASE HELP NO LINKS NEED HELP FAST
Use the scenario to answer the question.

An astronomer discovers a new galaxy using a telescope. The astronomer wants to investigate how the galaxy is moving relative to the Milky Way galaxy.

In one or two sentences, make a hypothesis about the movement of the galaxy and explain at least one way to test the hypothesis.

Answers

Answer:

The galaxies outside of our own are moving away from us, and the ones that are farthest away are moving the fastest. This means that no matter what galaxy you happen to be in, all the other galaxies are moving away from you

Explanation:

The hypothesis about the movement of the galaxy is that galaxies are moving far from each other continuously.

What is the milky way galaxy?

The milky way galaxy is a galaxy that contains over a hundred billion stars and it also includes our solar system.  Its name describes its appearance when viewed from the earth. All the individual stars in the whole sky are a portion of the Milky Way Galaxy, the term "Milky Way" is because of the band of light.

The astronomer has discovered a new galaxy which means our universe is continuously expanding. This is because the universe encloses everything that exists.

Galaxies are moving in space and since the universe space is continuously expanding so the galaxies continuously move from each other. The farther the galaxy is from the milky way which is an observable part, the faster will be moving the galaxy and the closer the galaxy is to the milky way, the slower will be movement of the galaxy.

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Using what you already know about newton’s law’s explain how the force applied to the ball by the pitcher and the force applied to the ball by the bat will impact yours ability ti hit a home run

Answers

An item at rest will remain at rest, and an object in motion will continue to move in a straight path at a constant speed, according to the first law of motion, commonly known as the law of inertia.

How is baseball impacted by Newton's first law?

Newton's laws of motion govern how a baseball moves as a result of being thrown or struck. According to Newton's first law, a moving ball will continue to move in a straight line until other forces are acting on it.

What happens when a baseball bat strikes a ball?

The ball is severely distorted by the enormous force the bat applies to it ball being struck. The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there!

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On the image at right, the two magnets are the same. Which paper clip would be harder to remove?

Answers

Answer:B

Explanation: The book is thinner making magnets attraction stronger, making the paper clip harder to move

A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Find 2 numbers if their difference is 16 and their ratio is 5:7 A mass is placed at the end of a spring. It has starting velocity of V & allowed to oscillate freely. If the mass has a starting velocity of 2V, what would the period be? Half as long, remains constant, 1/4 as long , 4 times as long, or 2 times as long? in scene 1, who seems happier, scrooge or fred? what message do u think the authors want to convey with this scene? under the allowance method, when a year-end adjustment is made for estimated uncollectible accounts question 28 options: total assets decrease. total assets are unchanged. net income is unchanged. liabilities decrease. 14) What are the x-intercept and the y-intercept of the equation, 2x + y = 13? Describe how to graph this line using the intercepts. 10.5. Which of the following would you not find in ananimal cell?a. Phospholipidsb. Endoplasmic reticulumc. Nucleoidd. Mitochondria can you please solve this for me I'll make sure to give the best review Demonstrative adjectives are "point out" nouns. In other words, they are used to say how close or how far away a noun is. Select one: O True O False The states of stress and 0,2) at two different points in a body are given as follows: 10 0 3 3 3 0 0 0 3 0 mpa o2) = 0 -7 0 0 mpa 3 02 0 -5 determine which state is more critical to yielding if the following criteria of yielding are used: 0 a. octahedral normal stress, oost b. octahedral shear stress, toct c. maximum shear stress, t maks Reason why ussr became involved involved in the angolan war true or false. protein primary structure cannot be used to predict protein secondary structure. brenda purchases stock and plans to hold on to it for a number of years. she could be considered to be using a Which of the following did the Maya and the Mesopotamians have in common? Both societies practiced religious tolerance. Both organized around major rivers. Both were monotheistic societies. Both were polytheistic societies. for "old work" (remodels), it is common to install cables behind the finished surface by the cable from one access point to another. Sukhi needs to insert a container into her form to collect a particular type of information.Which object should she insert? we should definitely adopt your course of action"" is an example of what type of speech act? meredith chapman works as a retail clerk at a children's clothing store. when a customer returns an item for a cash refund, meredith enters an amount greater than the actual refund into the register, pays the customer the amount owed for the returned merchandise, and keeps the excess cash for herself. what type of scheme is meredith committing? NEED HELP ASAP!Which activity requires speed?A. Walking on a balance beamB. Hitting a baseballC. Climbing over and under thingsD. Running a race Find the internal rates of return on a cash flow with deposit amounts of A0 = 40, A1 = 120, A2 = 290, and withdrawal amounts of B0 = 240, B1 = 20, B2 = 10, at times t = 0, t = 1, t = 2, respectively. (please show every step). tech solutions is a consulting firm that uses a job-order costing system. its direct materials consist of hardware and software that it purchases and installs on behalf of its clients. the firms direct labor includes salaries of consultants that work at the clients job site, and its overhead consists of costs such as depreciation, utilities, and insurance related to the office headquarters as well as the office supplies that are consumed serving clients.