A 11.27-g block of solid gold at 68.23 °C is immersed in a 23.16-g pool of liquid ethanol with a temperature of 10.76 °C. When thermal equilibrium is reached, what is the temperature of the gold and ethanol?
Specific heat capacities: gold = 0.129 J/g °C; ethanol = 2.44 J/g °C

These are the oxidation and reduction reactions.

What is oxidation?

The process of oxidation occurs when a reactant loses electrons during a reaction. Reduction is the name for the process wherein a reactant picks up electrons while undergoing a reaction. This is a typical event when metals and acids interact. The process of oxidation occurs when a reactant loses electrons during a reaction.

What is reduction?

The process of obtaining electrons or lowering an element's oxidation state in a chemical reaction is known as reduction , which is the transfer of electrons between species. The number of electrons attached to a single atom or a collection of related atoms increases during a chemical reaction known as reduction.

Mg+I2=MgI2

MgI2

Mg is in +2 oxidation state

I2  is in -1 oxidation state

oxidation Mg ⇒ Mg ²⁺ + 2e⁻

Reduction I₂  + 2e⁻ ⇒ 2I⁻

Therefore, these are the oxidation and reduction reactions.

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I Gallon = 3.785 L 1 Mg = 1 mg gallon 3.785L. 3. The recommended adult dose of Elixophyllin®, a drug used to treat asthma, is 6.00 mg/kg of body mass. Calculate the dose in milligrams for a 112 lb person. (o oo Kg | K9 6.oong 112 15 = 3 04.7 - 3 2.20515 2.20516 my k.

Hope this answer will help you.

The percent error is 2.5% when the average concentration of molarity was 0.123 and the true vale was 0.120.

Given the different trails where NaOH is added in different concentrations.

Trail 1: 12.49 mL = 0.0025 mol

Molarity is calculated as number of moles per unit volume such that:

M1 = 0.0025/0.01249 = 0.2M

Trial 2: 12.32 mL = 0.0025 mol

M2 = 0.0025/0.01232 = 0.202M

Trial 3: 11.87 mL = 0.0024 mol

M3 = 0.0024/0.01187 = 0.202M

Different concentrations of HCl were used in different trails such that:

Trial 1: (20.61 mL of HCL) 0.121 M

number of moles = molarity * volume of solution

\(n1 = 0.121 * 20.61 * 10^{-3} = 0.0024mol\)

Trial 2: (20.06 ML HCl) 0.125 M

\(n2 = 0.125 * 20.06 * 10^{-3} = 0.0025mol\)

Trial 3: (19.67 mL) HCL 0.122

\(n3 = 19.67 * 10^{-3} * 0.122 = 0.0023mol\)

Given the average concentration of molarity = 0.123M

The true value is given as = 0.120

The percent error for the average molarity is = ((average - true)/true) * 100% = \((0.123 - 0.12/0.120)*100% = 2.5%\)

This means that the calculated value of 0.123M is 2.5% higher than the true value of 0.120M.

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Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

\(V_2 = \frac{P_1V_1}{P_2} \\\)

So we have

\(V_2 = \frac{5 \times 40}{1} \\ = 5 \times 40\)

We have the final answer as

Hope this helps you

Answer:

The cytoplasm of erythrocytes is rich in hemoglobin, an iron-containing biomolecule that can bind oxygen and is responsible for the red color of the cells and the blood. Each human red blood cell contains approximately 270 million of these hemoglobin molecules.

Explanation:

hope this helps(;

The choice of solution has a concentration of 1.144 mol/kg molality.

Molarity corresponds to the moles of solvent divided by the amount of solution in litres, whereas molality is equal with the moles of solvent divided by the quantity of solvent in kilogrammes.

Since 1 mole of solute is present in 1 litre for the solution, which contains both the solute and the solvent, 1 molar aqueous solutions are more concentrated than one decays aqueous solutions.

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Answer:

Kb = 1.77x10⁻⁵

Explanation:

When NH₃, a weak base, is in equilibrium with waterm the reaction that occurs is:

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

And the dissociation constant, Kb, for this equilibrium is:

Kb = [NH₄⁺] [OH⁻] / [NH₃]

To find Kb you need to find the concentration of each species. The equilibrium concentrations are:

[NH₃] = 0.950M - X

[NH₄⁺] = X

[OH⁻] = X

Where X is reaction coordinate.

You can know [OH⁻] and, therefore, X, with pH of the solution, thus:

pH = -log [H⁺] = 11.612

[H⁺] = 2.4434x10⁻¹²

As 1x10⁻¹⁴ = [H⁺] [OH⁻]

1x10⁻¹⁴ / 2.4434x10⁻¹² = [OH⁻]

4.0926x10⁻³ = [OH⁻] = X

Replacing, concentrations of the species are:

[NH₃] = 0.950M - X

[NH₄⁺] = X

[OH⁻] = X

[NH₃] = 0.9459M

[NH₄⁺] = 4.0926x10⁻³M

[OH⁻] = 4.0926x10⁻³M

Replacing in Kb expression:

Kb = [NH₄⁺] [OH⁻] / [NH₃]

Kb = [4.0926x10⁻³M] [4.0926x10⁻³M] / [0.9459M]

The branch of science which deals with the chemical bond is called Chemistry.

The correct answer to the question is  \(Kb = 1.77*10^{-5\)

Explanation:

When NH₃, is acts as a  weak base it forms an equilibrium with water the reaction occurs is:

\(NH_3(aq) + H_2O(l) ---><NH_4^+(aq) + OH^-(aq)\)

The formula we gonna use is as follows:-

\(Kb = \frac{[NH_4^+] [OH^-]}{[NH_3]}\)

The data is given in the question is as follows:-

Where X stands for reaction coordinate.

After solving the ph of the compound the value is as follows:-

Putting the value in the formula.

\(Kb = \frac{[4.0926*10^{-3}M] [4.0926*10^{-3}M]}{[0.9459M]}\)

After solving the equation the value of Kb is \(1.77*10^{-5\)

Hence, the correct answer is \(1.77*10^{-5\)

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Answer:

Explanation:

The given compound is:

           KC₈H₆O₄

Mass of the compound = 25g

Molar mass of the compound

KC₈H₆O₄

   Atomic mass of K  = 39

                             C  = 12

                             H = 1

                             O = 16

Molar mass of the compound  = 39 + 8(12) + 6 (1) + 4(16)

                                                   = 205g/mol

Number of molecules of fuel there in:

Find the number of moles then convert this to number of molecules;

    Number of moles  = \(\frac{mass}{molar mass}\)  

    Number of moles  = \(\frac{25}{205}\)   = 0.12mol

1 mole of a compound contains 6.02 x 10²³ molecules

 0.12 mole of the phthalate will contain 0.12 x 6.02 x 10²³ =

              7.34 x 10²²molecules

Number of moles of Carbon

  1 mole of the phthalate contains 8 mole of carbon

  0.12 mole of the phthalate will contain 0.12 x  8  = 0.96mole of carbon

The electron configuration 1s22s22p6 corresponds to the noble gas neon (Ne), which has a completely filled valence shell.

What is Electric Configuration?

The placement of electrons around the nucleus of a specific atom or molecule is known as its electronic configuration.

Protons, neutrons, and electrons are the minuscule components that make up an atom. There are the same number of protons and electrons in a neutral atom. The quantity and location of an atom's electrons are revealed by its electronic configuration.

We say that electrons orbit the nucleus of an atom, like the rings of Saturn orbit the planet. Electrons move in orbitals that can accommodate a specific number of electrons as they circle the nucleus.

Four elements that may have ions with this electron configuration are:

Fluorine (F-) - gains one electron to achieve a noble gas configuration (1s22s22p6)

Oxygen (O2-) - gains two electrons to achieve a noble gas configuration (1s22s22p6)

Sodium (Na+) - loses one electron from the valence shell to achieve a noble gas configuration (1s22s22p6)

Magnesium (Mg2+) - loses two electrons from the valence shell to achieve a noble gas configuration (1s22s22p6)

Therefore, the symbols for these ions are:

Na+, Mg2+, F-, O2-.

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In order to test for ammonia, a moist red litmus paper should be held over the test tube containing the ammonia.  Option 3.

Ammonia is a substance that is alkaline in nature. All alkaline substances are able to turn red litmus paper to blue. This is in opposition to acidic substances that turn blue litmus paper to red.

Thus, the first test that can be used to determine if a substance is ammonia would be to hold a moist red litmus paper over the test tube containing the suspected substance.

Since ammonia is gas at room temperature, the substance suspected to be ammonia will diffuse from the test tube to turn the moist red litmus paper to blue.

Other methods to test for ammonia include passing a test tube containing hydrochloric acid over the test tube containing the substance. A white fume of ammonium chloride will confirm the presence of ammonia.

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Answer:

The answer it's A. transesterification

3122.0 mL of gas are present at 120.0 °C.

The volume of a gas is the amount of three-dimensional space it occupies. The volume of a gas is directly proportional to the temperature if the pressure is held constant.The force exerted perpendicularly to an object's surface in relation to its area is known as pressure. The average kinetic energy of the molecules that make up a system is measured by temperature.This means that the volume at 120°C will be the same multiple of the volume at 27°C. To calculate the multiple, we divide the final temperature by the initial temperature:

\(\frac{120.0\°C}{27.0\°C} = 4.44\)

Therefore, the volume at 120°C will be 4.44 times the volume of 700.0 mL at 27°C.

Volume at 120°C = 4.44 x 700.0 mL = 3122.0 mL

Therefore ,The volume of gas at 120.0 °C is 3122.0mL

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26.62 grams of HBr would be present in 355 mL of a 7.5% m/v HBr solution.

Concentration refers to the amount of a substance in a defined space. Another definition is that concentration is the ratio of solute in a solution to either solvent or total solution.

There are various methods of expressing the concentration of a solution.

Concentrations are usually expressed in terms of molarity, defined as the number of moles of solute in 1 L of solution.

Solutions of known concentration can be prepared either by dissolving a known mass of solute in a solvent and diluting to a desired final volume or by diluting the appropriate volume of a more concentrated solution (a stock solution) to the desired final volume.

Given,

HBr = 7.5% m/ v

This means 7.5g of HBr in 100 ml of the solution.

1 ml of the solution has 0.075g

355 ml of the solution will have = 0.075 × 355 = 26.62g of HBr

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Answer:

4.3 is your answer because it's matches

HAZWOPER training and certification recognize:

The correct option is both A and C

HAZWOPER (Hazardous Waste Operations and Emergency Response) training and certification recognize that a large number of victims (as much as 80%) in hazardous waste incidents or emergencies will self-present or be self-referred for medical treatment.

Additionally, HAZWOPER training acknowledges that victims may use any entrance they can access at a hospital, not just the emergency department entrance.

This is because individuals affected by hazardous materials may arrive at different areas of the hospital seeking medical assistance.

Therefore, option d. Both A and C are correct statements regarding the recognition of HAZWOPER training and certification.

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Answer:

Dude you need to provide an image because almost everyone is not gonna know what u talkin about.

Explanation:

Explanation:

a is the answer ok write it easily bye

Answer:

The percent by mass of N in the sample is C. 6.1%

To calculate the percent by mass of N, we need to divide the mass of N in the sample by the total mass of the sample and multiply by 100.

%N = (mass of N / total mass of the sample) x 100

%N = (6.1 g / 20.0 g) x 100 = 0.305 x 100 = 30.5%

So the answer is C. 6.1%.

Explanation:

The enthalpy on the reaction is 14.71kJ/mol

Data;

The enthalpy change of the reaction can solved using series of step.

From the equation of the reaction;

                  \(X_2 \leftrightarrow 2x\\\\\)

Initial           706    0

change         -x      +2x

equilibrium   706-x   +2x

Equilibrium partial pressure of x = 90 torr

\(90torr = 2x\\x = 45\)

\(x_2 = 705 - x = 705 - 45 = 660 torr\)

Still at equilibrium;

\(KP_1 = \frac{P_x^2}{P_x} = \frac{90^2}{660} = 12.27\)

For the second reaction;

                    \(X_2 \leftrightarrow 2x\)

Initial             778    0

Change           -x      +2x

Equilibrium       733    2x

At equilibrium pressure of x

\(\frac{513^2}{733} = 359.03\)

To solve for the change in enthalpy

\(\ln \frac{Kp_2}{Kp_1} = \frac{\delta H}{R} [\frac{T_2 - T_1}{T_2T_1} ]\\\ln \frac{359.03}{12.27} = \frac{\delta H}{8.314} [\frac{729 - 298}{758 * 298} ]\\3.376 = \frac{\delta H}{8.314} [0.01908]\\\delta H = 1471.07 J/mol\)

The enthalpy on the reaction is 14.71kJ/mol

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The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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Answer:

To convert joules to calories, you can use the conversion factor:

1 calorie = 4.184 joules

To find out how many calories are in 4,180 joules, divide the given value by the conversion factor:

4,180 joules / 4.184 joules per calorie = 0.9 calories (approximately)

Therefore, there are approximately 0.9 calories in 4,180 joules.

The net ionic equation for the reaction would be: Zn(s) + Cu(NO3)2(aq) → Cu(s) + Zn(NO3)2(aq)

In this reaction, zinc metal (Zn) reacts with aqueous copper(II) nitrate (Cu(NO3)2) to form solid copper (Cu) and aqueous zinc nitrate (Zn(NO3)2).

Zn(s) + Cu(NO3)2(aq) → Cu(s) + Zn(NO3)2(aq)

To write the net ionic equation, we need to remove the spectator ions (ions that do not participate in the reaction and remain unchanged).

The complete ionic equation is:

Zn(s) + Cu2+(aq) + 2NO3-(aq) → Cu(s) + Zn2+(aq) + 2NO3-(aq)

The spectator ions are the two nitrate ions (NO3-), which appear on both sides of the equation. Therefore, we can eliminate them from the equation to obtain the net ionic equation:

Zn(s) + Cu2+(aq) → Cu(s) + Zn2+(aq)

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The mass of the oxygen that reacted is 70.4 g.

The reaction between iron and oxygen is called rusting and is a oxidation process. The balanced chemical equation for the reaction is:

4 Fe + 3 O2 -> 2 Fe2O3

Number of moles of iron = 168 g/56 g/mol = 3 moles

Number of moles of iron III oxide = 232 g /160 g/mol

= 1.45 moles

The mass of the oxygen that reacted is;

If 3 moles of oxygen produces 2 moles of oxide

x moles of oxygen would produce 1.45 moles ofn the oxde

x = 3 * 1.45/2

= 2.2 moles

Mass of the oxygen = 2.2 moles * 32 g/mol

= 70.4 g

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If a reaction has a negative ΔG and a positive ΔS, the reaction will be spontaneous at all temperatures.

If a reaction is spontaneous at all temperatures, it implies that the reaction will occur without the need for any external intervention, such as the addition of energy. For a reaction to be spontaneous, it must satisfy the criteria of thermodynamic favorability, which is determined by the change in Gibbs free energy (ΔG) associated with the reaction.

The relationship between ΔG, temperature (T), and the equilibrium constant (K) of a reaction is described by the equation ΔG = ΔH - TΔS, where ΔH is the change in enthalpy and ΔS is the change in entropy.

To ensure spontaneity at all temperatures, two conditions must be met:

ΔG must be negative: A negative ΔG indicates a thermodynamically favorable reaction, meaning the products have a lower Gibbs free energy than the reactants. If ΔG is negative, the reaction will proceed spontaneously in the forward direction.

ΔS must be positive: A positive ΔS signifies an increase in the overall entropy of the system. Higher entropy means more disorder, and spontaneous reactions often involve an increase in randomness. When ΔS is positive, it can compensate for the enthalpic term, ΔH, allowing the reaction to proceed spontaneously.

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Answer: plastic, wood, rubber

Explanation:

Answer:

Lots of items.

Explanation:

Fiber, mineral wool, and corks.

Answer:

Definition. Gram molecular mass is the mass in grams of one mole of a molecular substance. Gram molecular mass is the same as molar mass. The only difference is that gram molecular mass specifies the mass unit to be used. Gram molecular mass may be reported in grams or grams per mole (g/mol).

While being made from natural resources, electricity does not constitute a natural resource because it goes through several procedures to produce it.

Oil, coke, nat gas, metals, stone, or sand are examples of natural resources. Other natural resources include water, soil, sunlight, air, and so on. Natural resources have value because they enable life and provide for human needs.

Financially referred to it as land and raw materials, land resources (also known as natural resources) are found naturally within ecosystems that are mostly unaltered by civilization. A natural resource's biodiversity levels across different habitats are frequently used to describe it.

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