The force on the car is 8420 N to the east, and the car has a mass of 2390 kg. The car is traveling to the west at a speed of 21.6 m/s. it takes 6.124 seconds for the car to come to a stop.
The question wants to know how long it takes the car to come to a stop. In order to solve this problem, we need to use the following formula: F = ma, where F is the force, m is the mass, and a is the acceleration.Let's find the acceleration of the car using the formula: F = ma8420 = 2390aWe can solve for a by dividing both sides of the equation by 2390: a = 8420/2390a = 3.527 m/s²Now we can use the formula v = u + at to find the time it takes for the car to come to a stop. u is the initial velocity (in this case, 21.6 m/s), v is the final velocity (0 m/s, since the car has come to a stop), a is the acceleration we just found, and t is the time we want to find: 0 = 21.6 + 3.527tt = -21.6/3.527t = -6.124 sThe answer is negative because we are asking for the time it takes for the car to stop, which means it's in the opposite direction of the car's initial velocity. However, we know that time can't be negative, so we take the absolute value of our answer to get the final result: t = 6.124 s. Therefore, it takes 6.124 seconds for the car to come to a stop.
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What is the voltage drop across resistors r2 in volts
The voltage drop across resistors r2 in volts is 6.6 volts.
What is resistor?Resistor is defined as an electrical component that regulates voltage and temperature. Resistors are frequently employed in electronic circuits to reduce current flow, divide voltages, impede transmission signals, and bias active parts. The resistor controls the electron flow to prevent overly rapid current from damaging the breadboard, wires, battery,
The Voltage drop can be calculated as
Give voltage of battery = 113 V
R2 has current = 1.9 A
And resistance = 4.7 ohms
Voltage = 1.9 + 4.7
= 6.6 V
Thus, the voltage drop across resistors r2 in volts is 6.6 volts.
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An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 15 m if her initial speed is 3 m/s. what is the free-fall acceleration on the planet?
Answer:
R = V^2 sin 2 θ / g range formula
R is a maximum for θ = 45 and R = V^2 g
g = V^2 / R = 3^2 / 15 = .6 m/s^2
a mirror produces an image that is inverted and twice as tall as the object. if the image is 60 cm from the mirror, what is the radius of curvature of the mirror?
The radius of curvature of the mirror is 40 cm.
In this case, the mirror produces an inverted image, which means it is a concave mirror. We are given the object distance (u), image distance (v), and magnification (M). The magnification is -2, as the image is twice as tall and inverted. The mirror formula for concave mirrors is:
1/f = 1/u + 1/v
We can find the focal length (f) using the magnification formula:
M = -v/u
By solving for v, we get:
v = -2u
Now, we can substitute this value back into the mirror formula:
1/f = 1/u - 1/(2u)
Since the image is 60 cm from the mirror:
1/f = 1/60 - 1/(2 * 60)
1/f = 1/60 - 1/120
1/f = 2/120 - 1/120
1/f = 1/120
Thus, the focal length (f) is 60 cm / 2 = 30 cm
The radius of curvature (R) is twice the focal length:
R = 2 * f = 2 * 30 = 40 cm
Summary: The radius of curvature of the mirror is 40 cm.
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While a car travels around a circular track at a constant speed, its?
While a car travels around a circular track at a constant speed, its speed is changing with direction.
What is acceleration of an object?
The acceleration of an object is the rate of change of velocity of the object with time.
The acceleration of an object moving in a circular track is known as centripetal acceleration.
a = v²/r
where;
v is the speed of the objectr is the radius of the trackThe speed of an object is a scalar quantity without direction, but when it occurs in a circular track, the speed occurs in different direction, so acceleration for constant speed in a circular track cannot be zero.
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in what direction is the force the branch exerts on the chimpanzee?
"The direction of force that the branch exerts on the chimpanzee is towards the ground.
The force of the branch on the chimpanzee is the gravitational force. It acts downwards on the chimpanzee, and hence the direction of the force is downwards towards the earth. Let's assume that the chimpanzee is hanging on a branch of a tree and is stationary. Then, the gravitational force, also known as the weight of the chimpanzee, acts downwards on the chimpanzee. The weight of the chimpanzee is equal to the mass of the chimpanzee multiplied by the acceleration due to gravity.The force exerted by the branch on the chimpanzee is an equal and opposite reaction to the force exerted by the chimpanzee on the branch, according to Newton's Third Law of Motion. Therefore, the direction of the force exerted by the branch on the chimpanzee is towards the ground.
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A. -2 m/s 2
B. -1 m/s 2
C. 0 m/s 2
D. 2m/s 2
This is an AP physics problem on the subject of Conservation of Momentum
The Momentum is the product of mass and velocity.
What is the momentum?Momentum is a measure of an object's motion. It is defined as the product of an object's mass and its velocity. In physics, momentum is a conserved quantity, which means that the total momentum of a closed system remains constant unless acted upon by an external force.
Final momentum of Ax = 1 * 2 * cos 30 = 1.73 Kgm/s
Final momentum of Ay = 1 * 2 * sin 30 =1 Kg m/s
Final momentum of Bx = 1 * Vs * cos 30
Final momentum of By = 1 * Vy * sin 30
The velocity is then;
1 * 5 + 0 = (1 * 2) + (1 * vs)
5 = 2 + vs
Vs = 3 m/s
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The ball is motionless and has a mass of 3. 56 kilograms. What is the magnitude of the tension force on the string, rounded to the nearest whole number?.
The tension force on the string with a ball of mass 3.56 kg attached to it is 35 N.
What is tension force?Tension force is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.
To calculate the tension force in the string, we use the formula below.
Formula:
T = mg........... Equation 1Where:
T = Tension force in the stringm = Mass attached to the stringg = Acceleration due to gravityFrom the question,
Given:
m = 3.56 kgg = 9.8 m/s²Substitute these values into equation 1
T = 3.56×9.8T = 34.88T = 35 NHence, the tension force on the string is 35 N.
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Billy pushes a supermarket cart with a constant force F. Every time he adds groceries to the cart, the weight of the cart increases. Billy adds groceries until the cart is filled. How do the groceries affect the carts acceleration if the force billy used to push the filled cart is the same force he used to push the empty cart?
Answer:
The groceries will decrease the cart's acceleration.
Explanation:
more force is required to push the full cart than the empty cart.
Give an example of an object that has balanced forces acting on it.
Define colinear forces
Answer: Collinear forces are forces that have a common line of action, i.e. the line of action of the forces lies along a single straight line.
Explanation:
A bucket tied to a rope is moving at a constant speed of 5.0 m/s in a circle of radius
2.0 m. Calculate the approximate magnitude of the centripetal acceleration of the bucket.
The below answer choices are in m/s^2
A.) 2.5
B.) 6.2
C.) 12.5
D. None of these
Answer:
\(a=12.5\ m/s^2\)
Explanation:
Given that,
The speed of the bucket tied to a rope, v = 5 m/s
The radius of the circle, r =2 m
We need to find the magnitude of the centripetal acceleration of the bucket. The formula for the centripetal acceleration is given by :
\(a=\dfrac{v^2}{r}\\\\a=\dfrac{(5)^2}{2}\\\\a=12.5\ m/s^2\)
So, the centripetal acceleration of the bucket is \(12.5\ m/s^2\).
Why is it very hard to use the Doppler shift method of detecting planets to discover a planet like Earth
Doppler shift method cannot be used to detect a planet like earth because the mass of Earth is very less.
What is Doppler's effect?
The Doppler effect is produced when an apparent upward shift in frequency of a moving source of waves is observed by the observer towards which the source is approaching also when an apparent downward shift in frequency of observed by the observer when the source is receding.
In astronomy Doppler effect is used by observing the shift in frequency of electromagnetic waves produced by moving stars in our galaxy and beyond. This takes place in the manner:
Electromagnetic radiation emitted by stars of distant galaxies that appear to be shifted downward in frequency show a red shift. This takes place when the star is rotating in its cluster directed away from the Earth.Electromagnetic radiation emitted by stars of distant galaxies that appear to be shifted upwards in frequency show a blue shift. This takes place when the star is rotating in its cluster directed towards the Earth.The Doppler shift method is useful for greater celestial masses. The mass of earth is very less in comparison, thus the Doppler shift method cannot be used to discover a planet like Earth.
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After a massive-star supernova, what is left behind?.
Answer: A Nebula is left behind. A spectacular explosion in which a star ejects most of its mass in a violently expanding cloud of debris.
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WILL GIVE BRAINLIEST !!!
Which measurement shows the largest volume? (1 ml = 1 cm^3)
A)27 cm
B)25cm
C) 801mL
D)2L
Answer:
D) 2L. two liters......
The twisting joint (type T) of an industrial robot has a range of 322° rotation. In order to study the mechanical errors in the joint and the input/output links, a statistical experiment was conducted by taking 10 samples, each one as follows: the joint was commanded to turn and stop at a certain addressable angle and the deviation (in degrees) from that specific angle was recorded. The results of taking 10 samples are presented in the table below: 0.176 0.04 -0.345 0.079 0.309 -0.004 -0.102 0.12 0.075 0.1 Supposing that the statistical distribution of the mechanical errors is normal, determine the number of storage bits required in the controller memory so that the accuracy of the joint is as close as possible to, but less than, its repeatability. Use six standard deviations as the measure of repeatability.
To determine the number of storage bits required in the controller memory for the twisting joint (type T) of the industrial robot, we need to calculate the repeatability, round the deviations to a reasonable precision, and then calculate the number of addressable positions based on the range of the joint and the chosen accuracy level.
First, let's calculate the repeatability of the joint. Given that the range of rotation is 322°, the repeatability can be calculated as 6 times the standard deviation. Since the standard deviation is a measure of how spread out the data is, multiplying it by 6 ensures that the accuracy of the joint is as close as possible to, but less than, its repeatability.
Next, let's analyze the given data. The 10 samples of deviations from the commanded angles are: 0.176, 0.04, -0.345, 0.079, 0.309, -0.004, -0.102, 0.12, 0.075, and 0.1.
To calculate the standard deviation of these deviations, we need to find the mean and then calculate the differences from the mean. Squaring these differences and taking the average will give us the variance, which we can then take the square root of to obtain the standard deviation.
After calculating the standard deviation, we multiply it by 6 to obtain the repeatability.
Now, to determine the number of storage bits required, we need to consider the accuracy of the joint. The accuracy depends on the precision required for representing the deviations. Assuming a reasonable level of precision, we can round the deviations to, for example, 3 decimal places.
Finally, the number of storage bits required in the controller memory can be calculated by multiplying the range of the joint (322°) by the accuracy (e.g., 0.001°, considering 3 decimal places). This will give us the number of addressable positions, which can be represented by the required number of storage bits.
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Write a one page essay on how work and power can be applied to every day life. Also reference three careers that can relate to work and power. Reference the formulas and definitions for work and power as well as provide an explanation for your reasoning.
Also provide a works cited page.
Work and power are fundamental concepts in physics that have practical applications in everyday life.
How do you write the essay?Power and work are fundamental ideas in physics that have real-world implications. Power is the pace at which work is done, and work is defined as the product of force and displacement.
To calculate the amount of force and energy needed to complete a specific operation, such as lifting bulky objects or moving materials, engineers employ the concepts of work and power.
Work = fd while power = E/t
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Line a is parallel to line b. If the
measure of 27 is 114°, what is the
measure of 41?
21
34
65
114°= 78
a
b
The measure of angle 3 is given as 114 degrees
What is an angleAn angle is a geometric figure formed by two rays or lines that share a common endpoint called the vertex. The rays or lines that form the angle are referred to as the arms or sides of the angle. Angles are typically measured in degrees (°) or radians, and the measure of an angle indicates the amount of rotation between the two arms or sides, starting from one arm and rotating around the vertex to reach the other arm.
Line a and line b are parallel.
< 7 = 114°
The value of 3 measured as
= < 7
Having similar angles, = 114°
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Through what total angle did the wheel turn between t= 0 and the time it stopped? At t = 0 a grinding wheel has an angular velocity of 22.0 rad/s. It has a constant angular acceleration of 27.0 rad/s2 until a circuit breaker trips at time t = 1.60 s. From then on, it turns through an angle 437 rad as it coasts to a stop at constant angular acceleration. Express your answer in radians. VO AXO ? 0 = rad Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B At what time did it stop? Express your answer in seconds. VO AEO ? t = S Submit Request Answer Part C What was its acceleration as it slowed down? Express your answer in radians per second squared. VALO ? a = rad/s2 Submit Request Answer
The acceleration of the wheel as it slows down is approximately -0.227 rad/s^2.
Part A: The total angle the wheel turned between t = 0 and the time it stopped can be calculated by summing the angles covered during different time intervals.
First, during the time interval from t = 0 to t = 1.60 s, we use the equation:
θ1 = ω0 * t + 0.5 * α * t^2,
where θ1 is the angle covered, ω0 is the initial angular velocity, α is the constant angular acceleration, and t is the time interval. Substituting the given values:
θ1 = (22.0 rad/s) * (1.60 s) + 0.5 * (27.0 rad/s^2) * (1.60 s)^2
θ1 ≈ 35.84 rad
During the coasting period, the wheel continues to turn with constant angular acceleration until it comes to a stop. The angle covered during this period, θ2, is given as 437 rad.
Therefore, the total angle covered is:
Total angle = θ1 + θ2
Total angle ≈ 35.84 rad + 437 rad
Total angle ≈ 472.84 rad
Part B: The wheel comes to a stop when its final angular velocity, ωf, becomes zero. To find the time it stopped, we can use the equation:
ωf = ω0 + α * t,
where ωf is the final angular velocity, ω0 is the initial angular velocity, α is the constant angular acceleration, and t is the time interval.
Substituting the given values:
0 = (22.0 rad/s) + (27.0 rad/s^2) * t_stop
Solving for t_stop:
t_stop = - (22.0 rad/s) / (27.0 rad/s^2)
t_stop ≈ -0.815 s
Since time cannot be negative, we disregard the negative sign and take the absolute value:
t_stop ≈ 0.815 s
Therefore, the wheel stopped at approximately 0.815 seconds.
Part C: The acceleration of the wheel as it slows down can be found using the equation:
ωf^2 = ω0^2 + 2αθ,
where ωf is the final angular velocity, ω0 is the initial angular velocity, α is the constant angular acceleration, and θ is the angle covered.
Since the final angular velocity is zero (ωf = 0), we have:
0 = ω0^2 + 2αθ
Solving for α:
α = - ω0^2 / (2θ)
Substituting the given values:
α = - (22.0 rad/s)^2 / (2 * 472.84 rad)
α ≈ - 0.227 rad/s^2
Therefore, the acceleration of the wheel as it slows down is approximately -0.227 rad/s^2.
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A 40 kg ball is on a 15 m ledge. If it is pushed off
the ledge.
How much kinetic energy will it have just before
hitting the ground?
The final kinetic energy will it have just before hitting the ground is 5.8755 KJ.
Mass of the ball, M = 40 kg
Height of the ledge, S = 15 m
Initial velocity, u = 0 m/s (at rest)
Using equation of motion we get,
V² = u² + 2aS
V² = 0 + 2 × 9.8 × 15
V² = 294
v = 17.14m/s
kinetic enrgy is calculated as :
E = 1/2 × mass × v²
for initial velocity (u =0) kinetic energy is
E = 1/2 × 40 × 0²
E = 0J
for final velocity (v) kinetic energy is :
E = 1/2 × 40 × (17.14)²
E = 5,875.5 J
E = 5.8755 KJ
The final kinetic energy will it have just before hitting the ground is 5.8755 KJ.
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1. A 0.1 mm diameter glass tube is inserted into a ethyl alcohol at 20 degree centigrade in a cup. How much does the Glycerin rise in the tube. The angle of alcohol with tube is 0 degree. D=0.1 mm=0.001 m 0∘ alcohol angel 20∘ ethyl alcohol η=1.1×10^−3 N⋅sec/ m^2sg=.0.79
A 0.1mm diameter glass tube is inserted into an ethyl alcohol at 20 degrees centigrade in a cup. The angle of alcohol with the tube is 0 degrees. D = 0.1 mm = 0.001m, alcohol angle is 0 degrees, ethyl alcohol
\(η=1.1×10^-3 N⋅sec/ m², s_g\)
=0.79.
We have to determine how much glycerin rises in the tube. The force that moves the liquid through the tube is the difference between the downward force of gravity on the liquid column and the upward capillary force produced by the surface tension of the liquid against the walls of the tube.
The height to which the fluid rises in a capillary tube may be measured by balancing the capillary force against the force of gravity on the column.
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There is a 5mA flowing through an 18k register. What is the voltage drop?
The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.
To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.
Given:
Current (I) = 5 mA = 5 * 10^(-3) A
Resistance (R) = 18 kΩ = 18 * 10^(3) Ω
Using Ohm's Law, we can calculate the voltage drop (V):
V = I * R
= (5 * 10^(-3) A) * (18 * 10^(3) Ω)
= 90 V
Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.
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Question 23 of 32
A truck has a mass of 9000 kg and a kinetic energy of 18,000 J. What is its
speed?
A. 4 m/s
B. 8 m/s
C. 2 m/s
D. 1.4 m/s
UBMIT
Answer:
2m/s
Explanation:
Given parameters:
Mass of truck = 9000kg
Kinetic energy = 18000J
Unknown:
Speed = ?
Solution:
Kinetic energy is the energy due to the motion of a body;
K.E = \(\frac{1}{2}\) mv²
So;
m is the mass
v is the speed
2 KE = mv²
2 x 18000 = 9000 x v²
v² = 4
v = 2m/s
When removing heavy objects that may change the center of gravity of a vehicle ________. Group of answer choices
Answer:
______________________________
use tall safety and position hoist arms
is there any location along the line between them where the electric field magnitude is zero? if so, what is the distance from the particle carrying q to that location?
No, the electric field magnitude is zero only at the midpoint between the two charges, i.e. at a distance of d/2.
In order to determine the location of the electric field zero, we set the electric fields for each point charge to be equal to one another because that is the point at which they will cancel one another out. The electric potential does not necessarily equal zero just because the electric field is zero at a certain location.
The situation of two similar charges that are spread apart is an excellent example. Even when the electric field is not zero at a given point, the electric potential can nonetheless be zero there. Because it is 0 at a point inside the solid body of the conductor, the electric field caused by induced charges at the sphere's centre is zero.
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16. Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10^24 kg, the mass of Jupiter is 1898.6 x 10^24 kg and the closest distance is abou
The gravitational force of attraction between the Earth and Jupiter is approximately 1.32 x 10²⁸ N.
The gravitational force of attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the force (F) is proportional to the product of their masses (m₁ and m₂) and inversely proportional to the square of the distance (r) between their centers. Mathematically, the formula is expressed as:
F = (G * m₁ * m₂) / r²
where G is the gravitational constant.
m₁ = 6 x 10²⁴ kg (mass of Earth)
m₂ = 1898.6 x 10²⁴ kg (mass of Jupiter)
r = 5.88 x 10¹¹ m (distance between Earth and Jupiter)
Plugging in the values into the formula, we have:
F = (6.67 x 10⁻¹¹ N m²/kg²) * (6 x 10²⁴ kg) * (1898.6 x 10²⁴ kg) / (5.88 x 10¹¹ m)²
Calculating the expression, we find:
F ≈ 1.32 x 10²⁸ N
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THE COMPLETE QUESTION IS:
Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10²⁴ kg the mass of Jupiter is 1898.6 x 10²⁴ kg and the closest distance is about 5.88 x 10¹¹
The particles of a GAS within a closed container will collide with the container walls, exerting a FORCE. The force per unit of AREA is known as what?
Answer:
Pressure
Explanation:
One of the theories propounded by the Kinetic molecular theory, and which also provides an explanation of the several gas laws, is the statement that the gas molecules in a container, travel in straight lines and are in constant collision with themselves and the walls of the container, thus exerting force. This force is the pressure which is defined as the force per unit area.
There is no loss of energy in the collisions involving the gas molecules and that is why their movement can be described as elastic. The descriptions of the behavior of gas molecules in the Kinetic Molecular Theory, give rise to Charles law, Boyle's Law, Avogadro's Laws, Dalton's Law, and Amonton's Law.
Answer:
The pressure
Explanation:
Molecules of gases are constantly in motion, colliding with the walls of their container. This constant collision impacts force on the walls of the container, which depends on the speed with which the molecules are moving. The speed with which these molecules travel depends on the average kinetic energy of the molecules, which is proportional to the temperature.
This force when exerted per unit area is the pressure the gases exert on the walls of the container.
Why does acceleration increase down a ramp?
Acceleration increase down a ramp, due to an object is free to move under the influence of gravity. That's why acceleration increases.
Acceleration is a measure of how quickly an object's velocity changes. On a ramp, an object is free to move under the influence of gravity. The gravitational force acting on an object is always directed downward, and the force of friction acting on an object is directed upward. The force acting on an object moving down a ramp is the force of gravity minus the force of friction. Since the force of gravity is greater than the force of friction, the net force acting on the object is directed downward, which causes the object to accelerate downward. The angle of the ramp affects the force of friction, as the greater the angle of the ramp, the greater the force of friction, and the less the net force acting on the object and less acceleration. Therefore, acceleration increases down a ramp because the net force acting on an object is directed downward and the angle of the ramp affects the force of friction.
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a man climbs a ladder.which quamtities can be used to calculatethe useful power of the man
Explanation:
Power is the rate at which work is done. It is expressed as:
Power = \(\frac{work done}{time taken}\)
To find the power of the man climbing the ladder, we must know the work he is doing and the duration of the work done.
Work done = force x distance
Since he climbs,
Force = weight = mg (mass x acceleration due to gravity)
distance = height = h
Power = \(\frac{mgh}{t}\)
t is the time
If we know these parameters, we can find the power.
A ball is rolling down a hill at 28 m/s2. The net force acting on the ball is 244N. What is the balls mass? ANSWER FOR BRAINLIEST!!
Explanation:
Force = Mass × Acceleration
Mass = Force/Acceleration
Mass = 244/28 = 8.71Kg