A 4.23 g sample of an iron (III) chloride hydrate was found to contain 1.69 g of water. What is the complete formula for the hydrate

Answer:

Since AlCl3 sublimes and NaCl does not sublime sublimation process will separate the two. Heat the mixture, aluminium chloride sublimes into vapour and forms the sublimate on the cooler parts of heating tube sodium chloride will remain at the bottom of the heating tube.

Explanation:

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Primary amines can be distinguished from secondary and tertiary amines by reacting with nitrous acid (HNO2). The reaction with nitrous acid is known as the "Diazotization reaction" and is specific to primary amines.

This reaction allows for the conversion of primary amines into diazonium salts, which are highly unstable and can undergo further reactions to form various products.

In the diazotization reaction, primary amines react with nitrous acid to form a diazonium salt and water. The reaction proceeds as follows:

R-NH2 + HNO2 -> R-N2+X- + H2O

Secondary and tertiary amines do not undergo this reaction with nitrous acid because they lack the necessary hydrogen atom on the nitrogen atom to form the diazonium salt. Therefore, this reaction can be used as a distinguishing test to differentiate primary amines from secondary and tertiary amines.

The formation of the diazonium salt can be confirmed through various tests, such as the formation of colored precipitates or the coupling reactions with other compounds. These reactions are specific to primary amines and help in their identification and distinction from secondary and tertiary amines.

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In both active and closed mines, the reaction of rainwater with iron sulfide components in the rubble converts to sulfuric acid which creates acid mine drainage.

This is a highly acidic solution that can have severe impacts on water quality and aquatic life.

Acid mine drainage can also cause damage to infrastructure and ecosystems downstream, as well as pose risks to human health.

To mitigate the effects of acid mine drainage, various treatment methods can be employed, including neutralization with alkaline substances, chemical precipitation, and biological remediation.

Prevention measures, such as the use of best management practices during mining operations and the implementation of proper mine closure procedures, can also help to minimize the production and release of acid mine drainage.

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1)The new pressure by Boyles law is 316 mmHg

2) According to the Boyle's law, the pressure would decrease and you would notice an increase in volume.

3) The  new volume of the gas is 2.6 L.

4) The new pressure is  228kPa

Using the Boyles law;

P1V1 = P2V2

P2 = P1V1/V2

P2 = 750 * 0.935/2.22

= 316 mmHg

3) P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 1.25 * 2.35 * 273/1 * 308

V2 = 2.6 L

4) Using the Gay Lussac's law;

P1/T1 = P2/T2

P1T2 = P2T1

P2 = P1T2/T1

P2 = 210 * 316/291

= 228kPa

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Answer: 0.925 L

Explanation:

M=moles /L

L= moles/M

3.70/4 = 0.925 L

The answer to the above question is D. as mass transfer refers to the net transfer of mass from one place to another.

One of the fundamental concepts in the study of transport phenomena is mass transfer, which denotes the movement of mass from one location to another. In multiphase systems, mass transfer may occur within a single phase or across phase borders. Although it can also be characterised in terms of solid-phase materials, mass transfer often incorporates at least one fluid phase (gas or liquid) in engineering challenges.

The computation of mass flux in a system and the distribution of the mass of various species through time and space are both made possible by the theory of mass transfer.

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One method that may be used to replace traditional damming is the use of sub-surface dams to prevent the environmental consequences of dams while still harnessing the flowing water.

Therefore, we can confirm that the building of a sub-surface dam would result in less water being lost to evaporation, as well as the ecosystem benefits of not completely stopping the flow of water the way a traditional dam does.

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The event which was a major source of atmospheric oxygen is photosynthesis.

Green plants and other organisms use solar energy to generate nutrition from carbon dioxide and water. Plants need the green pigment chlorophyll to perform photosynthesis, which produces oxygen as a by-product.

Hence photosynthesis is the major source.

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Answer:

136 g Al₂O₃

Explanation:

Assuming you do not need to find the limiting reactant, to find the mass of Al₂O₃, you need to (1) convert grams O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles Al₂O₃ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (64.0 g).

Molar Mass (O₂): 32 g/mol

Molar Mass (Al₂O₃): 102 g/mol

4 Al + 3 O₂ -----> 2 Al₂O₃

64.0 g O₂           1 mole           2 moles Al₂O₃            102 g
-----------------  x  --------------  x  ------------------------  x   -------------  =  136 g Al₂O₃
                             32 g               3 moles O₂             1 mole

Answer:

Explanation:

Based of the fact that you were given 2 masses I would assume this to be a limiting reagent question. However amount on the left side both equal 2. Ignoring limiting reagents and focusing on just O2 the steps would be:

1. Make sure the equation is balanced ( already given)

2- Use given values to find the mols of O2 (mass/molar mass)

3. Mols are conserved but due to the coefficients the molar value from O2 must be divided by three and multiplied by 2 to ensure proper ratios

4. Using that amount the mass can derived using amount/molar mass

5. Use proper significant digits and units(3 in this case)

The reactivity of halogens in free radical halogenation follows the order: fluorine > chlorine > bromine > iodine. This is due to the decreasing bond dissociation energy (BDE) of the halogen-halogen bond in this order.

Therefore, in the free radical halogenation of ethane, fluorine would be the most reactive halogen and undergo the reaction most rapidly. Chlorine would be less reactive than fluorine but more reactive than bromine and iodine.

Iodine and bromine are not as reactive as fluorine and chlorine due to their large size and lower electronegativity, which results in a weaker halogen-halogen bond. As a result, the reaction between ethane and iodine or bromine would be slower than that with fluorine or chlorine.

Finally, pyridine is not a halogen and is not expected to undergo free radical halogenation with ethane.

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Answer:

Krypton.

Explanation:

By Graham's Law:

Rate 1 / Rate 2 = sqrt M2 / sqrt M1

Molecular Mass for Neon  is 20.18

so we have:

38 / 77.5  =  sqrt 20.18 / sqrt x    where x is the unkown gas.

sqrt x = 9.162

x = 83.94.

This gas is Krypton.

A sample of neon effuses from a container in 38 s. The same amount of an unknown noble gas requires 77.5 s. The unknown gas is krypton.

The noble gases are a group of chemical elements that share several characteristics. They are all monatomic, odorless, and colorless gases with relatively little chemical reactivity under normal conditions. Helium, neon, argon, krypton, xenon, and radioactive radon are the six types of noble gases that are found in nature.

Due to their filled valence shells (octets), which render them incredibly nonreactive, the noble gases (Group 18), which are found in the far right of the periodic table, were formerly known as the "inert gases."

Due to their fully filled outer electron shells and lack of propensity to react with other elements, noble gases which are most frequently found as monatomic gases rarely form compounds with other elements.

By Graham's Law ;

Rate 1 ÷ Rate 2 = sqrt M2 ÷ sqrt M1

The Molecular Mass for Neon  is 20.18

Then,

38 ÷ 77.5  =  sqrt 20.18 / sqrt x    

where x is the unknown gas.

sqrt x = 9.162

x = 83.94.

This is Krypton gas.

Thus, The unknown gas is krypton which is noble gas.

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Answer:

A. 7

(assuming the water is neutral)

Answer:

C. how many particles are in the substance

Answer:

it is how hot or cold so bassically c in my test

Explanation:

o-xylene, m-xylene, and p-xylene are structural isomers.

o-xylene, m-xylene, and p-xylene are examples of aromatic isomers, also known as ortho-, meta-, and para-xylene, respectively. These isomers are classified as aromatic because they are part of a family of compounds known as aromatic hydrocarbons, which contain a ring of six carbon atoms bonded to each other in a specific way.

o-xylene, m-xylene, and p-xylene are also examples of structural isomers. Structural isomers are compounds that have the same molecular formula but differ in the arrangement of their atoms. In the case of o-xylene, m-xylene, and p-xylene, the atoms are arranged differently around the ring of six carbon atoms.

o-xylene, m-xylene, and p-xylene are not optical isomers, which are also known as enantiomers. Optical isomers are compounds that are mirror images of each other but are not superimposable. Optical isomers are important in medicinal chemistry because they can have different biological properties even though they have the same molecular formula and structure.

o-xylene, m-xylene, and p-xylene are also not geometric isomers. Geometric isomers are compounds that have the same molecular formula and the same arrangement of atoms, but differ in the orientation of their atoms or groups of atoms in space. Geometric isomers are often found in compounds with cis-trans double bonds or ring structures.

IF NOT THEN SORRY :)

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#you can see the formula in pic for more detail writting

Mg2+ + Cl- -> MgCl2

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The correct answer is SO2.

Sulfur dioxide, sometimes known as SO2, is a colorless, odorless gas or liquid. It is created by combusting fossil fuels (coal and oil) and smelting sulfur-containing mineral ores (aluminum, copper, zinc, lead, and iron). Sulfur dioxide is easily dissolved in water and turns into sulfuric acid. The sulfur oxidation state in SO2 is +4. The manufacture of sulfuric acid, sulfur trioxide, and sulfites are its main uses. Additionally, sulfur dioxide is employed as a cleanser, disinfectant, refrigerant, reducing agent, and food preservative, particularly in dried fruits. The skin and mucous membranes of the eyes, nose, throat, and lungs get irritated by sulfur dioxide.

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8.00 moles is the total moles of \(4.82 * 10^2^4\) atoms of helium gas. So, the correct option is (D).

The mole is defined as the amount of matter of a system containing as many elementary elements as atoms in 0.012 kg of carbon 12; Its symbol is "Mol". It consists of the amount of a substance which is \(6.022 * 10^2^3\) units like particle, atom, ion, molecule etc. of the given substance where a mole measures the number of atoms, ions or molecules.

\(Number of moles= \frac{Number of molecules}{Avogadro's number}\)

For above given information,

\(Number of moles=\frac{4.82 * 10^2^4}{6.023* 10^2^3}\)

                         = 0.8002*10= 8.002 moles

Thus, 8.00 moles is the total moles of \(4.82 * 10^2^4\) atoms of helium gas. So, the correct option is (D).

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The total moles of 4.82 x 10²⁴ atoms of helium gas is  8 moles . Hence, option (D) is correct.

The Avogadro constant is a proportionality factor that compares the number of constituent particles (typically molecules, atoms, or ions) in a sample to the amount of substance in that sample.

1 mole of Helium gas has 6.02 × 10²³.

Hence, 4.82×10²⁴ atoms of  Helium gas  refers =  ( 4.82×10²⁴ ÷  6.02 × 10²³) moles of  helium gas

= 8 moles of  helium gas.

The total moles of 4.82 x 10²⁴ atoms of helium gas is  8 moles .

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For every one mole of glucose, there are six moles of carbon dioxide.

We have the balanced equation (without state symbols):

6H₂O + 6CO₂ → C₆H₁₂O₆ + 6O₂

Thus, 6 moles of carbon dioxide are required to fully produce 1 mole of glucose.

Here, we got 2.75g of carbon dioxide, and we need to convert it into moles.

Carbon dioxide has a molar mass of 44 g/mol.

So here, there exist

2.75g ÷ 44g/mol = 0.0625mol

Since there are two moles of CO₂, we can produce 2/6⋅1 = 1/3 moles of glucose (C₆H₁₂O₆).

We need to find the mass of glucose formed, so we multiply the number of moles of glucose by the molar mass.

Glucose has a molar mass of 180.156g/mol.

So here, the mass of glucose produced is:

1/3mol × 180.156 g/ mol ≈ 60g to the nearest whole number.

So, approximately 60 grams of glucose will be produced.

Complete Question:

6H2O + 6CO2 --> C6H12O6 + 6O2 How many grams of Glucose are made if you start with 2.75g of CO2?

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Answer: option (b) phosphorus

Explanation: Valence electrons are the total number of electrons that an snippet can partake to form bonds.

Phosphorus is the element that has the same number of valence electrons as nitrogen with both of them having 5 valence electrons.

Carbon has a aggregate of 4 valence electrons.

Neon has a aggregate of 8 valence electrons.

Oxygen has a aggregate of 6 valence electrons

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Answer:

Carbon dioxide, when present in sufficient amounts, will bind with water to form carbonic acid, which is capable of dissociating into bicarbonate and hydrogen ions.

Explanation:

With the help of carbonic anhydrase which further catalyzes the reaction to convert carbonic acid back into carbon dioxide and water. The carbon dioxide is then expelled from the lungs.

2. The interaction involved in the B⁺-decay is known as beta decay.

3.  The conserved quantities in the reaction are:

The quark flavor is not a conserved quantity in the given reaction of B⁺-decay.

The B⁺-decay is a type of beta decay, specifically beta plus decay. In beta plus decay, a proton (p) decays into a neutron (n), emitting a positron (e+) and an electron neutrino (νe):

p → n + e⁺ + νe

2. The interaction involved in the B⁺-decay is the weak nuclear force. The weak force is responsible for processes involving the transformation of particles, such as the conversion of a proton into a neutron in this case.

The interaction involved in the B⁺-decay is known as beta decay. Specifically, the B⁺-decay refers to the decay of a positively charged (B⁺) meson, which is a type of subatomic particle.

3. The conserved quantities in the reaction are:

Conservation of electric charge: The total charge on both sides of the reaction is conserved. The proton (p) has a charge of +1, while the neutron (n) has no charge. The positron (e⁺) has a charge of +1, which balances out the charge.

Conservation of lepton number: The total lepton number is conserved in the reaction. The lepton number of the proton and neutron is 0, while the lepton number of the positron and electron neutrino is also 0. Hence, the lepton number is conserved.

Conservation of baryon number: The baryon number is conserved in the reaction. The baryon number of the proton is 1, and the baryon number of the neutron is also 1. Therefore, the total baryon number is conserved.

Regarding quark flavor, it is not conserved in the B⁺-decay. The decay process involves the transformation of a up-type quark (u) in the proton to a down-type quark (d) in the neutron. This change in quark flavor is allowed by the weak force.

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The dissociation constant for ammonia (Kb) is a measure of the extent to which ammonia, NH3, dissociates in aqueous solution to form the ammonium ion NH4+ and the hydroxide ion OH-.

For given equilibrium concentrations of NH4+ and OH–, each 2 x 10^–3 M, and a concentration of NH3, 0.2 M, the value of Kb can be calculated using the expression Kb = [NH4+][OH]/[NH3 ].

After completing the given values, Kb = (2 x 10^–3 M)(2 x 10^–3 M)/(0.2 M) = 8 x 10^–7 M. The dissociation constant for ammonia is therefore Kb = 8 x 10^–7 M.

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Answer:

Although amino acids may have other formulas, those in protein invariably have the general formula RCH(NH2)COOH, where C is carbon, H is hydrogen, N is nitrogen, O is oxygen, and R is a group, varying in composition and structure, called a side chain.

Explanation:

(⁠◕⁠ᴗ⁠◕⁠✿⁠)(⁠◕⁠ᴗ⁠◕⁠✿⁠)(⁠◕⁠ᴗ⁠◕⁠✿⁠)

Answer: 1.079 kg/m3

Explanation:

The formula for the density is as follows as; Here, D is the density, m is the mass and V is the volume. Density is inversely proportional to the volume and it is directly proportional to the mass. It is given in the problem that density of an object is 700 kg having volume .

The nuclear decay of polonium-211 (Po-211) involves the emission of an alpha particle.

An alpha particle consists of two protons and two neutrons, which is equivalent to a helium nucleus. The equation for the nuclear decay of polonium-211 can be represented as follows:

Po-211 → He-4 + X

In this equation, Po-211 decays into an alpha particle (He-4) and a resulting nucleus represented by "X." The resulting nucleus can be another element or isotope depending on the specific decay process.

It's important to note that the equation provided represents the type of decay (alpha decay) and the products involved. The identity of the resulting nucleus ("X") would depend on the specific decay chain or the decay series Polonium-211 is part of.

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