The velocity of the 50.0 kg object before the collision was 13.56 m/s.
According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion. Momentum is never generated nor destroyed inside a problem domain.
Momentum before collision = Mass × Velocity
= 50 × V
= 50V.
Momentum after collision :
Momentum of the 50 kg object = 50 kg x 6.0 m/s x cos(50°) + 50 kg x 6.0 m/s x sin(50°) i.e 50kg x 6m/s at 50° N of E
Momentum of the 60 kg object = 60 kg x 6.3 m/s x cos(38°) - 60 kg x 6.3 m/s x sin(38°) i.e 60kg x 6.3m/s at 38° S of E
According to the principle of conservation of momentum,
Total momentum before collision = Total momentum after the collision
50 x V = 50 x 6.0x cos(50°) + 50 kg x 6.0 x sin(50°) + 60 kg x 6.3x cos(38°) - 60 kg x 6.3 m/s x sin(38°)
Simplifying the equation:
50V = 417.8
V = 417.8 ÷ 50
V = 8.36m/s
Therefore, the velocity of the 50.0 kg object before the collision was 8.36m/s.
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an 8 awg gray insulated neutral conductor is installed to supply a 120-volt electrical heater.
An 8 AWG gray insulated neutral conductor is a type of wire that is commonly used in electrical systems. In this case, it is being used to supply a 120-volt electrical heater. The AWG (American Wire Gauge) refers to the thickness of the wire, and in this case, 8 AWG is a relatively thick wire that can handle a significant amount of electrical current.
The gray insulation on the wire is used to help identify it as the neutral conductor. The neutral conductor is an essential part of the electrical circuit, as it provides a path for the electrical current to return to the source. Without a neutral conductor, the circuit would not be complete, and the electrical device would not work.
Overall, the use of an 8 AWG gray insulated neutral conductor to supply a 120-volt electrical heater is a common and safe practice. It ensures that the electrical system is properly grounded and that the heater is receiving the appropriate voltage and current to operate safely and efficiently.
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Let A represent the ball moving at 2.00 m/s, and call that direction the positive direction. Let B represent the ball moving at 3.60 m/s in the opposite direction. Thus, VA =2.00 m/s and VB=-3.60 m/s. Use Eq. 7-7 to obtain a relationship between the velocities.
VA-VB=-(V’A-V’B) → V’B = 5.60 m/s+ V’A
Substitute this relationship into the momentum conservation equation for the collision, noting that MA=MB
Answer:
So the velocity of ball A after the collision is 1.80 m/s.
Explanation:
The momentum conservation equation for a collision is given by the equation:
MAVA + MBVB = MAV'A + MBV'B
Substituting in the given values, we have:
MA2.00 m/s + MB(-3.60 m/s) = MAV'A + (MB(5.60 m/s + V'A))
Since MA=MB, we can simplify the equation further:
2.00 m/s + (-3.60 m/s) = V'A + (5.60 m/s + V'A)
Solving for V'A, we get:
V'A = 1.80 m/s
So the velocity of ball A after the collision is 1.80 m/s.
What do we call the energy that is transferred to
a substance without the substance's temperature
changing?
Answer:
Latent heat
Latent heat is the heat needed to change a state without a change in temperature.
Explanation:
Hope this helps :D
Julie and Susie have a combined mass of 16kg. They have a force
of 20,000 Newtons. How fast are they accelerating?
The acceleration of julie and susie is a = 1.250 x 10³m/s².
Equation :Given in the question,
F = 20,000N
mass = 16kg
acceleration = ?
Using formula,
Force = mass x acceleration
20000 N = 16 kg x a
a = F / m
a = 20000 / 16
a = 1.250 x 10³m/s²
Force :A change that can alter an object's motion is known as a force. A mass-containing object's velocity can change, or accelerate, as a result of a force. Intuitively, a push and / or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction. Two main categories into which forces can be divided are Contact Forces and Non-Contact Forces.
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earth travels around the sun each year in an elliptical path, as opposed to a perfect circle. this means that the speed of earth and its distance from the sun change over the course of a year. what does this say about the magnitude of the centripetal acceleration of earth over the course of a year?
The fact that the Earth travels around the sun in an elliptical path means that its distance from the sun and its speed change throughout the year.
As a result, the magnitude of the centripetal acceleration of Earth also changes over the course of a year.
Centripetal acceleration is the acceleration directed towards the center of the circular path. In this case, the centripetal acceleration of the Earth is provided by the gravitational force of the Sun, which keeps the Earth in its elliptical orbit.
When the Earth is closer to the Sun in its orbit, its speed increases and its centripetal acceleration also increases. This is because the gravitational force between the Sun and the Earth is stronger when they are closer together, resulting in a higher centripetal acceleration.
Conversely, when the Earth is farther from the Sun in its orbit, its speed decreases and its centripetal acceleration decreases. This is because the gravitational force between the Sun and the Earth is weaker when they are farther apart, resulting in a lower centripetal acceleration.
So, in summary, the magnitude of the centripetal acceleration of Earth changes over the course of a year due to the varying distance from the Sun and the corresponding changes in speed.
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A simple 15.2 cm reflecting telescope can achieve 1 second of arc resolution for visible light. Many radio telescopes study a particular radio wavelength of 21 cm. Complete parts a −d using the above information. a. Use the Raleigh criteron to determine how large a radio telescope aperature must be to achieve this resolution at 21 cm. b. Why must the aperture of a radio telescope be much larger than that of an optical telescope? c. Why is it possible to resolve two predominantly blue stars when the same telescope can not resolve two simarily separated red stars? d. In the galaxy pictures of 5 b, which photograph corresponds to the largest aperture?
a)The aperture size of the radio telescope needs to be approximately 0.27 meters b)The aperture of a radio telescope needs to be much larger than that of an optical telescope because radio waves have much longer wavelengths compared to visible light. c)the resolving power of a telescope depends on the ratio of the wavelength of light.
a. To determine the aperture size of a radio telescope to achieve a resolution at 21 cm, we can use the Rayleigh criterion, which states that the minimum resolvable separation (δθ) is given by:
δθ = 1.22 * (λ / D)
Where λ is the wavelength of the radiation and D is the diameter of the telescope's aperture.
Given that the radio wavelength is 21 cm (or 0.21 m), and we want to achieve the same resolution as the optical telescope (1 second of arc), we can rearrange the formula to solve for D:
D = 1.22 * (λ / δθ)
D = 1.22 * (0.21 m / 1 second of arc)
Calculating the result:
D ≈ 0.27 m
Therefore, the aperture size of the radio telescope needs to be approximately 0.27 meters to achieve a resolution of 1 second of arc at a wavelength of 21 cm.
b. The Rayleigh criterion tells us that the resolution of an instrument is inversely proportional to the wavelength.
Since radio waves have longer wavelengths, the telescope's aperture needs to be larger to achieve the same resolution as an optical telescope. This is because a larger aperture collects more incoming waves and allows for finer spatial detail to be resolved.
c. The ability to resolve two objects using a telescope depends on the size of the aperture relative to the wavelength of the radiation. When it comes to resolving stars, the resolving power of a telescope depends on the ratio of the wavelength of light to the size of the telescope's aperture (λ/D).
Blue light has a shorter wavelength compared to red light. Since the resolving power is directly proportional to the wavelength, a shorter wavelength of blue light allows for better resolution.
Therefore, two predominantly blue stars can be resolved because their shorter wavelength allows for finer detail to be distinguished, while the same separation between two predominantly red stars cannot be resolved due to the longer wavelength.
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Collate the electrical force between and electrons and protons in an atom that are separated by distance of 5.9 e -11m
Answer:
The electrical force between the electrons and protons in the atom is 6.62 x 10⁻⁸ N.
Explanation:
Given;
distance between the electron and proton, r = 5.9 x 10⁻¹¹ m
charge of electron, q₁ = -1.6 x 10⁻¹⁹ C
charge proton, q₂ = +1.6 x 10⁻¹⁹ C
The electric force between the two particles is calculated by Coulomb's law;
\(F = \frac{k|q_1|q_2|}{r^2} \\\\F = \frac{(9\times 10^9) \times (1.6\times 10^{-19})^2}{(5.9\times 10^{-11})^2} \\\\F = 6.62 \times 10^{-8} \ N\)
Therefore, the electrical force between the electrons and protons in the atom is 6.62 x 10⁻⁸ N.
to magnify the sweetness of foods without boosting their calories, you could:
To magnify the sweetness of foods without boosting their calories, one could use natural sweeteners such as honey, agave nectar, stevia, or monk fruit extract.
These alternatives have a low glycemic index and do not result in blood sugar spikes. Another method of magnifying the sweetness of foods is by using spices such as cinnamon, nutmeg, or cardamom that can provide a warm and sweet flavour without adding any calories. Finally, one could add fruits that are naturally sweet like strawberries or bananas.
When trying to enhance the sweetness of foods without adding calories, there are several techniques to use. Natural sweeteners, including honey, agave nectar, stevia, or monk fruit extract, are one way to do it. They have a low glycemic index and won't spike blood sugar levels. So, they're an excellent alternative for individuals who want to reduce their sugar intake without sacrificing sweetness.
Spices such as cinnamon, nutmeg, or cardamom can also be used to enhance sweetness. They provide a warm, sweet flavor without adding any calories. In addition to natural sweeteners and spices, adding naturally sweet fruits, such as strawberries or bananas, is a good way to magnify the sweetness of your food.
Using artificial sweeteners is not recommended, as they may have detrimental effects on one's health. For example, artificial sweeteners like aspartame and saccharin may cause headaches and other health issues. As a result, they should be avoided. By using natural sweeteners and spices or adding fruits, one can enjoy the flavor and sweetness of food without adding calories.
In conclusion, by using natural sweeteners, spices, or fruits, one could enhance the sweetness of their food without increasing the number of calories. It's always preferable to avoid artificial sweeteners since they may have a detrimental impact on one's health.
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In three to five sentences, explain how you would conduct an experiment to investigate the relationship between the applied force and the displacement of the spring, and describe its expected results.
Hooke's law states that the applied force F equals a constant k times the displacement or change in length x.
What is Hooke's law?
The force necessary to extend or compress a spring by a certain distance scales linearly with respect to that distance, according to Hooke's law, an empirical law in physics.
Hooke's Law is a principle of physics that states that the that the force needed to extend or compress a spring by some distance.
F = K.x
A straight line passing through the origin can be drawn by plotting the spring's stretch versus the weight that has been applied to the hanger. This implies that a spring's extension is inversely proportional to the force used to stretch it.
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1. A heat engine has a cold reservoir that is 285 degrees Kelvin which accepts 370 J of heat, and a hot reservoir that is 371 degrees Kelvin which gives off 425 J of heat. Calculate the maximum and actual efficiencies of this engine.
2. A system that has a total change in entropy of 675 J/K and has received 243 J of heat energy will be at what temperature?
3. Assume that the above system maintains a constant pressure, and increases in volume by 2.5 m 3 while doing this work. What is the pressure of the system?
I can't help with this one.
The maximum efficiency of the heat engine is 23%.
The actual efficiency of the heat engine is 13%.
The temperature of the system is 273.36 ⁰C.
The pressure of the system is 607.5 Pa.
The given parameters:
Cold reservoir temperature, Tc = 285 KHeat, qc = 370 JHot reservoir temperature, Th = 371 KHeat of the hot reservoir, qh = 425 JThe maximum efficiency of the heat engine is calculated as follows;
\(\eta = 1- \frac{T_c}{T_h} \\\\ \eta = 1 - \frac{285}{371} \\\\ \eta = 0.23\\\\ \eta = 23 \ \%\)
The actual efficiency of the heat engine is calculated as follows;
\(\eta = 1 - \frac{q_c}{q_h} \\\\ \eta = 1 - \frac{370}{425} \\\\ \eta = 0.13\\\\ \eta = 13\ \%\)
The temperature of the system is calculated as follows;
\(\Delta S = \frac{\Delta H}{T} \\\\ T = \frac{\Delta H}{\Delta S}\\\\ T = \frac{243}{675} \\\\ T = 0.36 \ K\\\\ T = 273.36 \ ^0C\)
The pressure of the system is calculated as follows;
\(W = P \Delta V\\\\ P = \frac{W}{\Delta V} \\\\ P = \frac{243}{2.5} \\\\ P = 607.5 \ Pa\)
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what is the theory relativity by Einstein?
:MAIN ANSWER:
determined that the laws of physics are the same for all non-accelerating observers
Explanation:
Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels, according to Wired.
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The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. What is the approximate mass of the vehicle in kg? Round your answer to the nearest kilogram
The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is 1166.67kg.
What is force ?The word "force" has a clear definition. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.
The vector sum of the forces exerted on a particle or object is known as the net force. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force.
Force ( F ) is 2100N
Acceleration ( a ) is 1.8m/s²
Mass(m)= ?
According to formula;
Force = mass × acceleration
F= m × a
2100 = m × 1.8
2100 / 1.8 = m
Therefore, m = 1166.6kg.
Thus, The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is 1166.67kg.
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Consider the Continuous-Time LTI system as follows: dy(t) - + 2y(t) = x(t) dt Analyse the output y(t) if x(t) = e-tu(t) using Fourier Transform
The output of the Continuous-Time LTI system with input x(t) = e^(-t)u(t), analyzed using Fourier Transform, is given by y(t) = (1/(s+2)) * (1/(s+1)), where s is the Laplace variable.
To analyze the output of the given Continuous-Time LTI system, we can use the Laplace transform, which is the continuous-time counterpart of the Fourier transform. The Laplace transform of the input signal x(t) = e^(-t)u(t) can be obtained as X(s) = 1/(s+1), where s is the Laplace variable.
Applying the Laplace transform to the differential equation describing the system, we have (sY(s) - y(0)) + 2Y(s) = X(s), where Y(s) is the Laplace transform of the output signal y(t) and y(0) represents the initial condition of y(t) at t=0. Since the system is assumed to be at rest initially, y(0) is zero.
Rearranging the equation and substituting X(s), we get Y(s) = 1/[(s+2)(s+1)]. This is the Laplace transform of the output signal y(t).
To find the time-domain expression for y(t), we need to inverse Laplace transform Y(s). The inverse Laplace transform of 1/[(s+2)(s+1)] can be computed using partial fraction decomposition. By decomposing the expression, we obtain Y(s) = (1/(s+2)) * (1/(s+1)).
Finally, taking the inverse Laplace transform of Y(s), we find the output signal y(t) = e^(-2t)u(t) - e^(-t)u(t).
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A block is sitting on a small platform supported by a spring and is undergoing simple harmonic oscillation with a frequency of 4.5 Hz. What is the maximum amplitude at which the block will stay on the platform
For a block undergoing simple harmonic oscillation, the maximum amplitude is mathematically given as
a=0.0749m
Generally, the equation for the maximum acceleration is mathematically given as
Ma=A*w^2
Where
A = 0.075 m
Therefore
0.075 * w^2 = 9.8
w = 11.43 rad/s
In conclusion, maximum frequency
mF=w/2pi
mF=11.43/2pi
mF= 1.82 Hz
Where
g=2\pif)^2a
a=(9.8)/4*\pi^2(1.82)^2
a=0.0749m
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A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 newtons to a height of 4 meters. if 400joules of work is done, how much force must have been applied?
If 400 joules of work is done, 100 newtons force much have been applied
In order to calculate the force required to lift an object weighing 220 newtons to a height of 4 meters with a lever having an effort arm of 10 meters and a load arm of 2 meters, we must first determine the amount of work done.
Since 400 joules of work was done, we can use the formula Work = Force x Distance to calculate the force required.
In this case, the distance is 4 meters, so the equation becomes
400 = Force x 4.
By dividing 400 by 4 we can determine that the force required is 100 newtons.
Therefore, in order to lift the object weighing 220 newtons to a height of 4 meters with a lever having an effort arm of 10 meters and a load arm of 2 meters, 100 newtons of force must have been applied.
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A steel ball with mass 44. 0 gg is dropped from a height of 1. 93 mm onto a horizontal steel slab. The ball rebounds to a height of 1. 64 mm. (a) Calculate the impulse delivered to the ball duringimpact. (b) If the ball is in contact with the slab for 2. 00 ms, findthe average force on the ball during impact
(a) The impulse delivered to the steel ball during impact is -0.082 Ns, (b) The average force on the steel ball during impact is -41.9 N.
(a) The impulse delivered to the ball during impact can be calculated using the principle of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.
Assuming that the ball was at rest before it was dropped, the initial momentum of the ball is zero. After it rebounds, its final velocity is also zero. Therefore, the change in momentum of the ball is:
Δp = mvf - mvi = -mvi
Δp = -0.044 kg × 0 m/s - (-0.044 kg × 0.0302 m/s) = 0.00133 kg m/s
The impulse delivered to the ball during impact is equal to the change in momentum, so:
J = Δp = 0.00133 Ns ≈ -0.082 Ns (since the ball rebounds in the opposite direction)
(b) The average force on the ball during impact can be found using the formula:
F = J / Δt
F = (-0.082 Ns) / (2.00 × 10⁻³ s) ≈ -41.9 N.
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Use the motion map to describe the motion of the object.
A motion map. The position line is a long black arrow pointing right, labeled x. Above the line are five dots with a vector pointing away from x that start at x, each one shorter ending in the last dot with no vector. Above that are two yellow vectors pointing toward x between the second and third and third and fourth black dot. Above that are three black dots with vectors pointing toward the origin, x, each with a larger vector. There are three yellow vectors with no black dots pointed toward x starting just above the vertical column of three dots.
Which statements describe what is occurring at
t = 5 seconds? Check all that apply.
The object sped up.
The object slowed down.
The object continued in the same direction.
The object changed direction.
The object came to a complete stop.
Answer:
The object sped up.
The object changed directions.
Explanation:
Just got the question correct.
Answer:
A & D
The object sped up
The object changed direction
Explanation:
:)
The Coulomb force between two charges q1 and q2 at separation r in air is F. If half of the separation is filled with medium of dielectric constant 9, what will be the value of new coulomb force?
Answer:
The new Coulomb force is q₁q₂/9πε₀r²
Explanation
The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².
Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.
Since we have air between q₂ and q₃, the coulomb force between them is
F' = q₂q₃/4πε₀d²
= q₂(q₁/κ)/4πε₀(r/2)²
= 4q₂q₁/κ4πε₀r²
= 4/κ(q₂q₁/4πε₀r²)
= 4/9 × (q₂q₁/4πε₀r²)
= q₁q₂/9πε₀r²
So, the new Coulomb force is q₁q₂/9πε₀r²
State mandates, known as
_____________________________________________ are the primary
drivers in the deployment of clean energy at utility-scale.
State mandates, known as renewable portfolio standards (RPS), are the primary drivers in the deployment of clean energy at utility scale.
Renewable portfolio standards (RPS) are regulations that require utilities to obtain a certain percentage of their electricity from renewable energy sources. These mandates are established at the state level and serve as a key policy tool to promote the development and deployment of clean energy technologies.
By setting specific targets for renewable energy generation, RPS create a market demand for clean power and incentivizes utilities to invest in renewable projects such as solar, wind, and hydroelectric power. This has led to significant growth in the renewable energy sector, contributing to reduced greenhouse gas emissions and a more sustainable energy mix.
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If € ₁ 4. 0 V. & 2 = 12. 0 V, R₁ = 40, R₂ = 1202, C-3 μF, Q = 18 μC, and I = 2. 5 A, what is the potential difference V, - V? b- 5. 0 V O-5. 0 V 30 V O-30 V & - 1. ³ 30
According to the given statement , the potential difference V across the resistor R is 3105 V.
To find the potential difference V, we can use Ohm's Law and the formula for the potential difference across a capacitor.
First, let's calculate the current flowing through the circuit. We are given that I = 2.5 A.
Next, we can calculate the total resistance in the circuit using the formula R = R₁ + R₂. Given that R₁ = 40 Ω and R₂ = 1202 Ω, we can calculate the total resistance:
R = 40 Ω + 1202 Ω = 1242 Ω
Now, we can calculate the charge stored in the capacitor using the formula Q = C * V, where Q is the charge, C is the capacitance, and V is the potential difference across the capacitor. We are given that Q = 18 μC and C = 3 μF. Plugging these values into the formula, we can solve for V:
18 μC = 3 μF * V
V = 18 μC / 3 μF
V = 6 V
Finally, we can calculate the potential difference V across the resistor R. Using Ohm's Law, we can use the formula V = I * R:
V = 2.5 A * 1242 Ω
V = 3105 V
So, the potential difference V across the resistor R is 3105 V.
In conclusion, the potential difference V across the resistor R is 3105 V.
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Based on Newton's law of motion, which combination of rocket bodies and engine will result in the acceleration of 40 m/s ^2 at the start of the launch?
The question is incomplete. The complete question is :
The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.
A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.
Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?
Body 3 + Engine 1
Body 2 + Engine 2
Body 1 + Engine 2
Body 1 + Engine 1
Solution :
Given :
Body Mass (gram) Engine Force (newtons)
1 500 1 25
2 1500 2 20
3 750 3 30
The body 1 has a mass of 500 gram which is equal to 0.5 kg
And engine 2 has a force of 20 newtons.
We know that according to Newton's laws of motion,
Force = mass x acceleration
20 = 0.5 x acceleration
Acceleration \($=\frac{20}{0.5}$\)
\($=\frac{200}{5}$\)
\($= 40 \ m/s^2$\)
Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of \($ 40 \ m/s^2$\) at the start of the launch.
celeration and Newton's 3 laws:
I
1. A car is traveling at 28 meters per second north; 10 seconds later the car is
traveling 15 meters per second north. What is the car's acceleration?
The car's acceleration is -1.3 meters per the second square
To solve this, use the first equation of motion v=u+at
where, v = final velocity(meters per second )
u = initial velocity(meters per second )
a = acceleration(meters per second square)
t = time (seconds)
According to the question,
Initial velocity(u) of the car = 28 meters per second
Final velocity(v) of the car = 15 meters per second
Time (t) = 10 seconds
Acceleration of the car(a) =?
Substituting the values in equation v =u+at
v= u+at
15 = 28 + ax10
15-28 = 10a
-13 = 10a
a = -13/10
a = -1.3 meters per second square
The car's acceleration is = -1.3 meters per second square
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The acceleration of this car is equal to -1.3 meters per seconds square (m/s²).
How to calculate the acceleration of this car?Mathematically, the acceleration of this car can be calculated by using this mathematical expression:
a = (V - U)/t
Where:
a represents the acceleration measured in meters per seconds square (m/s²).V represents the final velocity measured in meters per seconds (m/s).U represents the initial velocity measured in meters per seconds (m/s).t represents the time measured in seconds.Substituting the given parameters into the acceleration formula, we have;
Acceleration, a = (15 - 28)/10
Acceleration, a = -13/10
Acceleration, a = -1.3 m/s².
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You use an inclined plane to move furniture into a truck.
You perform 224 kJ of work, but only do 91 kJ of useful
work. What is the efficiency of the inclined plane?
A. 12.8%
B. 40.6%
C. 68.2%
D. 246.1%
Answer:B. 40.6%
Explanation:
un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en los 13 segundos
Answer:
Acceleration = 5.77 m/s²
Distance cover in 13 seconds = 487.56 meter
Explanation:
Given:
Final velocity of mobile device = 75 m/s
initial velocity of mobile device = 0 m/s
Time taken = 13 seconds
Find:
Acceleration
Distance cover in 13 seconds
Computation:
v = u + at
75 = 0 + (a)(13)
13a = 75
a = 5.77
Acceleration = 5.77 m/s²
s = ut + (1/2)(a)(t²)
s = (0)(t) + (1/2)(5.77)(13²)
Distance cover in 13 seconds = 487.56 meter
Who's going thru depression? My science teacher said that it's not good to hold that in but sometimes I don't feel like he get's me. What do I do?
Write a reflect on how you could use an interest survey or reading survey to inform your use of cooperative learning strategies, workshop model, and differentiated instruction with students
Using an interest survey or reading survey can be highly valuable in informing the use of cooperative learning strategies, workshop models, and differentiated instruction with students. These surveys provide valuable insights into students' preferences, strengths, and areas of improvement, allowing educators to tailor their instructional approaches accordingly.
An interest survey can reveal students' passions, hobbies, and preferred learning styles. This information can be used to create cooperative learning groups where students with similar interests or learning styles can collaborate effectively, enhancing engagement and motivation. For example, students who enjoy hands-on activities can be grouped together to work on a project, while those who prefer independent work can be given individual tasks within a cooperative setting.
A reading survey helps identify students' reading levels, interests, and areas of challenge. This data can inform the implementation of a workshop model, where students receive differentiated instruction based on their specific needs. For instance, during small group or individualized reading workshops, teachers can provide targeted interventions, such as guided reading or strategy instruction, to support students' growth in areas they struggle with while incorporating books and topics aligned with their interests.
By using interest and reading surveys, educators can foster a student-centered learning environment that takes into account students' preferences, abilities, and needs. This approach promotes engagement, fosters collaboration, and facilitates differentiated instruction, ultimately enhancing students.
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Which of the following would cause a fan cart to accelerate the least?
- doubling the speed of the fan
- pointing the fan exhaust downward
- tripling the speed of the fan
- pointing the fan exhaust upward
Answer:
The correct option is;
-Pointing the fan exhaust upward
Explanation:
The fan cart transfers reaction force from the jet of air it blows through the exhaust into motion in the opposite direction of the jet. By pointing the fan exhaust upwards, the direction of motion of the cart is therefore, into the ground. Due to the solid nature of the ground the motion is resisted, and by Newton's first law of motion, a body will remain in motion unless resisted by a force. In the case of the question, the ground is resisting the motion of the cart and the cart will remain at rest and having zero acceleration.
The basic function of an electromotive force in a circuit is to do which of the following? O Convert electrical energy into some other form. O Convert some other form of energy into electrical. O Both choices (a) and (b) are valid. O None of the above choices are valid.
The correct answer to the question is (b) Convert some other form of energy into electrical.
The basic function of an electromotive force in a circuit is to convert some other form of energy into electrical energy. This is achieved through the movement of charged particles, such as electrons, which create a flow of current in the circuit. Electromotive force is commonly represented by the symbol "EMF" and is measured in volts.
An EMF can be generated by various sources, including batteries, generators, and solar cells. In each case, the EMF converts some form of energy (chemical, mechanical, or radiant) into electrical energy that can be used to power devices or perform work.
It is important to note that an EMF does not create energy, but rather it converts energy from one form to another. For example, a battery does not create energy, but instead it converts chemical energy into electrical energy. Similarly, a generator converts mechanical energy into electrical energy.
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If a violin string vibrates at 430 hz as its fundamental frequency, what are the frequencies of the first four harmonics?
If a violin string vibrates at 430 hz as its fundamental frequency,then the frequencies of the harmonics are 880, 1320, 1760
The frequency in physics is the number of waves passing a fixed location in a unit of time. It also indicates how many cycles or vibrations a body in periodic motion experiences in a given unit of time.
How frequently something occurs is what is meant by the word frequency. A person blinking their eyelids 47 times in a minute is an example of frequency. the quality or state of happening frequently.
Integer (whole-number) multiples of the fundamental frequency are used to define harmonics, which are voltages or currents that function at certain frequencies. This means that for a waveform with a fundamental frequency of 50 Hz, the second harmonic frequency would be 100 Hz (2 x 50 Hz), the third harmonic would be 150 Hz (3 x 50 Hz), etc.
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if a tree falls in the wood and no won sees it dose it exist