A bottle has a capacity of 1.2 liters. If the density of ether is 0.74 g/mL, what mass of ether can the bottle hold?

Answer:

A. 21 J

Explanation:

Your temperature change is 10 degrees Celsius, or 10 Kelvin, it makes no difference either way.

Cp = 2.06 J/g•K

Multiply by the temperature change to just get J/g

2.06 J/g•K • 10 K = 20.6 J/g ≈ 21 J/g

21 J is the energy change per gram of ice when an iceberg composed of pure water, cp = 2.06 J/(g·K) which is heated from 25°C to 15°C. So, the correct option is A.

Heat is defined as the energy that is transferred from one body to another as a result of a difference in temperature, when two bodies at different temperatures are brought together, the energy transferred is that of the hotter body which flows towards the colder body.

In this case, according to the equation for the calculation of the heat during a heating process

\(Q= mC (T_f- T_i)\)

It is possible to calculate mass per gram of ice by dividing both sides by removing m from the equation, we plug in the given specific heat and final and initial temperatures to get:

\(Q= 2.06 \frac{J}{g degree C} [-15 Degree C- (-25 Degree C]\)

\(Q= 20.6\frac{J}{g}\) which is equals to 21° C

21 J is the energy change per gram of ice when an iceberg composed of pure water, cp = 2.06 J/(g·K) which is heated from 25°C to 15°C.

Therefore, the correct option is A.

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The ion released by alka-seltzer to change the pH of the solution is the hydroxide ion (OH-). When alka-seltzer is added to water, it undergoes a chemical reaction that releases hydroxide ions.

These hydroxide ions then react with the water molecules, resulting in an increase in the concentration of hydroxide ions in the solution. This increase in hydroxide ion concentration leads to an increase in pH, making the solution more basic. The pH scale ranges from 0 to 14, with a pH of 7 considered neutral, values below 7 acidic, and values above 7 basic.

Since the final pH of the solution after adding alka-seltzer is 8.3, it indicates that the solution has become more basic due to the release of hydroxide ions. In summary, when alka-seltzer is added to water, it releases hydroxide ions, which react with water to increase the concentration of hydroxide ions and raise the pH of the solution. When alka-seltzer is added to pure water, it dissolves and undergoes a chemical reaction. This reaction results in the release of hydroxide ions (OH-) into the solution.

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Answer:

Although all organic compounds contain carbon, and almost all have hydrogen, most of them contain other elements as well. The most common other elements in organic compounds are oxygen, nitrogen, sulfur, and the halogens.

Explanation:

I hope this helped!

First, we'll look at the ideal gas equation,

PV = nRT

The temperature and pressure are said to be constant; Additionally, R is a constant already. Along these lines, we get:

V = constant * n

The direct proportional equation is as follows: As a result, we get:

V/n = constant

V₁/n₁ = V₂/n₂

Replace V₂ with the qualities and address.

V₂ = (4 * 1.48) / 0.864

V₂ = 6.85

In the end, 6.85 Liters of gas must be present, so we must add:

6.85 - 4 = 2.85 liters

The volume of a gas is directly proportional to its mole volume at a fixed temperature and pressure.

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Q- At 4.00 L, an expandable vessel contains 0.864 mol of oxygen gas. How many liters of oxygen gas must be added at constant temperature and pressure if you need a total of 1.48mol of oxygen gas in the vessel?

Answer:

-415.5°F (-248.6°C)

Explanation:

Answer: The melting point/condensation point of neon is 24.53888889. Of course, I'm sure you can round that. The freezing point would be 521.74. All of this is in Kelvin

Answer:

#1=Heterogenous

#2=Homogenous

#3=Heterogenous

#4= Heterogenous

#5= Homogenous

#6=Homogenous

#7= Heterogenous

#8=Heterogenous

#9=Homogenous

The element which makes up the framework of organic compounds and which cycles through all ecosystems is carbon.

An organic compound is a compound that, in general, contains carbon covalently bound to other atoms, especially Carbon-Carbon (C-C) and Carbon-Hydrogen (C-H) (such as in hydrocarbons). A chemical compound refers to any substance made up of two or more elements that are chemically bonded together. Carbon is a key component of organic compounds, as it forms the basis for complex structures such as carbohydrates, proteins, lipids, and nucleic acids. It cycles through ecosystems via processes like photosynthesis, respiration, and decomposition, playing a crucial role in the carbon cycle.

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Answer:Explanation:

Your tool of choice here will be the mole ratio that exists between zinc metal,

Zn

, and hydrochloric acid,

:HCl

, in the balanced chemical equation.

Zn

(s]

+

2

HCl

(aq]

→

ZnCl

2(aq]

+

H

2(g]

↑

⏐

You're dealing with a single replacement reaction in which zinc displaces the hydrogen from hydrochloric acid. The products of the reaction are aqueous zinc chloride and hydrogen gas.

Now, as you can see from the balance chemical equation, a

1

:

2

mole ratio exists between the two reactants.

This tells you that in order for the reaction to take place, you need to have twice as many moles of hydrochloric acid as you do of zinc metal.At the same time, you have a

2

:

1

mole ratio between hydrochloric acid and hydrogen gas.

This means that the reaction will always produce half as many moles of hydrogen gas as you have moles of hydrochloric acid.

Since you know that

4

moles of hydrochloric acid are taking part in the reaction, and assuming that you have enough zinc metal so that it doesn't act as a limiting reagent, you can say that the reaction will produce

4

moles HCl

⋅

1 mole H

2

2

moles HCl

=

2 moles H

2

The correct balanced chemical equation is FeCl₃(aq) + Na₂S(aq) → 3Fe₂S₃(s) + 3NaCl(aq)

To achieve a chemical equation's balance:

Fe₂S₃ (s) + NaCl (aq) FeCl₃ (aq) + Na₂2S (aq)

Let's start by balancing the atoms of iron (Fe). The iron atoms are already balanced, since there are two on the reactant side and two on the product side.

Let's now balance the atoms of sodium (Na). Two sodium atoms are present on the reactant side, hence two sodium atoms are required on the product side. By adding a coefficient of 2 in front of NaCl, we may do this:

Let's balance the sulfur (S) atoms lastly.

FeCl3(aq) + Na2S(aq) → 3Fe2S3(s) + 3NaCl(aq)

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The enthalpy change of the reaction of decane would be -6582.3 kJ/mol of decane.

The enthalpy change of a reaction can be calculated using the following equation:

ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)

We are given the standard molar enthalpy of formation of n-decane, C10H22, which is -249.4 kJ/mol.

Using the balanced chemical equation, we can identify the stoichiometric coefficients of the reactants and products:

C10H22(I) + 12.5O2(g) --> 10CO2(g) + 11H2O(g)

Reactants:

n(C10H22) = 1

n(O2) = 12.5

Products:

n(CO2) = 10

n(H2O) = 11

Now we can calculate the enthalpy change of the reaction:

ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)

ΔH = [10(-393.5 kJ/mol) + 11(-241.8 kJ/mol)] - [1(-249.4 kJ/mol) + 12.5(0 kJ/mol)]

ΔH = -6582.3 kJ/mol

The enthalpy change of the reaction is -6582.3 kJ/mol of decane.

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The formula of barium phosphite is Ba₃(PO₄)₂.

A salt that is classified as inorganic is barium phosphate. The chemical formula for barium phosphate is Ba₃(PO₄)₂. Although barium phosphate is typically thought of as a colorless solid, it does have a fading odor resembling that of acetic vinegar. The barium phosphate structure was identified by the X-ray crystallography experiment as a connection of barium ions with the phosphate, Ba₂⁺ cations connected to a polyphosphate anion. The salts or esters that are created when tetrahedral PO₄ is transformed into a polyphosphate anion (phosphate). The oxygen atom that the structural unit shares is what binds it together. One of the hydrated forms of barium phosphate is barium phosphate dihydrate.

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The statement you provided refers to the determination of the van't Hoff factor (i) for strong electrolytes. The van't Hoff factor represents the number of ions produced per mole of solute dissolved in a solution.

For example, when calcium chloride (CaCl2) dissolves, it dissociates into three ions: one Ca2+ ion and two Cl- ions. Therefore, the van't Hoff factor (i) for CaCl2 is 3 because it produces three ions per mole of solute dissolved.

Similarly, when ammonium phosphate (NH4)3PO4 dissolves, it dissociates into four ions: three NH4+ ions and one PO43- ion. Thus, the van't Hoff factor (i) for (NH4)3PO4 is 4 because it yields four ions per mole of solute dissolved.

The van't Hoff factor is essential in various calculations related to colligative properties, such as boiling point elevation and freezing point depression, where it is used to account for the number of particles in solution.

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Sodium(Na) is the limiting reagent.

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

How do you identify a limiting reagent?

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

Start by writing the balanced chemical equation that describes this reaction

\(2Na_{(s)} + Cl_{2 (g)} -- > 2NaCl_{(s)}\)

Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.

now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.

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During the electrolysis process, a direct electric current is passed through the Cr3+ solution. This causes the Cr3+ ions to gain three electrons and form solid metallic chromium on the surface of the iron hubcap.

Now, let's move on to the second part of your question. The iron hubcap would serve as either the anode or the cathode during the electrolysis process. To determine which electrode it is, we need to consider the half-reaction.Since the Cr3+ ions are gaining electrons and being reduced to form metallic chromium, we can conclude that the iron hubcap is acting as the cathode.

In summary: The half-reaction that takes place to plate the hubcap with metallic chromium is: Cr3+ (aq) + 3e- → Cr(s The iron hubcap serves as the cathode during the electrolysis process.

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(A)This reaction does not increase the solubility of iron(II) carbonate.

(B) In this reaction it has no effect on how soluble it is.

(C) In this reaction it doesn't directly affect FeCO₃, it has no effect on how soluble it is.

(D)In this reaction it has no effect on how soluble it is.

(E)This reaction does not increase the solubility of iron(II) carbonate.

Therefore, the reaction that does not increase the solubility of iron(II) carbonate is reaction A) \(Fe^{2+\) (a q) + OH- (a q) « Fe OH+ (a q).

Let's analyze each reaction and its impact on the concentration of \(CO_(3)^{2-}\) ions:

A) \(Fe^{2+}\)(a q) + OH- (a q) « Fe OH+ (a q)

FeOH+ is produced during this reaction, although it has no direct impact on how soluble FeCO₃ is. It has nothing to do specifically with the precipitation or dissolution of FeCO₃.

B) \(CO_(3)^{2-}(a q) + H^+ (a q)\) ⇒ \(HCO^{3-}\) (a q)

In this process, \(CO_3^{2-}\) ions are changed into \(HCO^{3-}\)ions. Since it doesn't directly affect \(FeCO_3\), it has no effect on how soluble it is.

C) \(HCO^{3-} (a q) + H^+ (a q)\) « \(H_2 CO_3\) (a q)

In this process, bicarbonate ions \((HCO^{3-})\) are converted into carbonic acid \((H_2CO_3\). Since it doesn't directly affect FeCO₃, it\(H_2O\) has no effect on how soluble it is.

D) \(H_2CO_3(a q)\)« \(CO_2\) (g) + \(H_2O\) (l)

In this process, carbonic acid \((H_2CO_3\)) is transformed into water () and carbon dioxide (\(CO_2\)) gas. Since it doesn't directly affect FeCO₃, it has no effect on how soluble it is.

E) \(Fe OH^+ (a q) + OH^-\) «\(Fe(OH)_2\) (s)

This reaction involves the precipitation of \(Fe(OH)_2\) (iron(II) hydroxide) from Fe OH+ ions and OH- ions. It consumes OH- ions and reduces their concentration. It does not directly affect the concentration of \(CO_3^{2-}\)ions. Therefore, this reaction does not increase the solubility of iron(II) carbonate.

Based on the analysis, the reaction that does not increase the solubility of iron(II) carbonate is reaction A) \(Fe^{2+ }(a q) + OH^- (a q)\)« \(Fe OH^+\) (a q).

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The empirical formula for a compound which contains 53.70% iron and 46.30% sulfur is Fe₂S₃.

In any empirical formula matter, first we have to find the molar mass % of the elements in the compound. Then, change the % into grams. Next, divide all the masses by their molar masses. Continue to pick the smallest answer in moles from the previous step, and divide all the answers by that number. Last, the coefficients calculated in the previous step will become the subscripts in the chemical formula.

In this case, the moles of each element are:

Iron (Fe) = 53.70/55.86 = 0.96 moles

Sulfur (S) = 46.30/32.07 = 1.44 moles

Now, calculate the mole ratio by dividing each mole by smallest mole (0.96):

Fe = 0.96/0.96 = 1

S = 1.44/0.96 = 1.5

Next, multiply by 2 to remove decimal:

Fe = 1 * 2 = 2

S = 1.5 * 2 = 3

Thus, the empirical formula is Fe₂S₃.

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Neon has 8 valence electrons in the outermost shell and Methane also has 8 valence electrons in the outermost shell.

Neon ( Noble gas ) 

The atomic number is 10, 1s2, 2s2, and 2p6.

Eight total valence electrons in the outermost shell (2s2,2p6). Since neon's octet is already complete due to having 8 valence electrons in its outermost shell, it lacks the orbitals necessary to form covalent bonds and does not have any bonding pairs.

Four of its pairs are non-bonding. Since they won't form any bonds, all of the electrons will be counted as non-bonding pairs (1 pair equals 2 electrons

CH4 (Methane) (Methane)  Eight valence electrons total. It has four pairs of bonds. 0 (because there are no lone pairs) non-bonding pairs.

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Answer:

I think the answer could be 13 i hope this helps

Answer:

by mixing red and yellow

Explanation:

Answer:

Either the sun or by mixing red and yellow together because they make orange.

Explanation:

Brainliest pls

Answer:

Copper(II) chloride is the chemical compound with the chemical formula CuCl2. This is a light brown solid, which slowly absorbs moisture to form a blue-green dihydrate. Both the anhydrous and the dihydrate forms occur naturally as the very rare

Explanation:

Answer:

\(\large \boxed{1.615 \times 10^{25}\text{ molecules water}}\)

Explanation:

You must calculate the mass of the water, convert it to moles, and then calculate the number of molecules.

1. Mass of water

\(\text{Mass } = \text{499.8 mL} \times \dfrac{\text{0.967 g}}{\text{1 mL}} = \text{483.3 g}\)

2. Moles of water

\(\text{Moles of water} = \text{483.3 g water} \times \dfrac{\text{1 mol water}}{\text{18.02 g water}} = \text{26.82 mol water}\)

3. Molecules of water

\(\text{No. of molecules} = \text{26.82 mol water} \times \dfrac{6.022 \times 10^{23}\text{ molecules water}}{\text{1 mol water}}\\\\= \mathbf{1.615 \times 10^{25}}\textbf{ molecules water}\\\text{The sample contains $\large \boxed{\mathbf{1.615 \times 10^{25}}\textbf{ molecules water}}$}\)

The number of molecules of water  present in the bottle is 1.62×10²⁵ molecules.

We'll begin by calculating the mass of the water in the bottle.

Mass = Density × Volume

Mass of water = 0.967 × 499.8

Mass of water = 483.3066 g

Finally, we shall determine number of molecules of water in the bottle.

From Avogadro's hypothesis,

1 mole of water = 6.02×10²³ molecules

But,

1 mole of water = 18 g

Thus, we can say that:

18 g of water = 6.02×10²³ molecules

Therefore,

483.3066 g of water = (483.3066 × 6.02×10²³) / 18

483.3066 g of water = 1.62×10²⁵ molecules

Thus, the number of molecules of water in the bottle is 1.62×10²⁵ molecules.

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Answer:

Density, \(d=2.09\ g/cm^3\)

Explanation:

Given that,

Mass of a flask is 450 g

Volume of benzene added to the flask is 145 mL or 145 cm³

The weight of the flask and benzene is found to be 754 g.

We need to find the density of the benzene.

Weight of benzene added = total weight of flask and benzene-mass of flask

m = 754 g - 450 g

m = 304 g

Density = mass/volume

So,

\(d=\dfrac{304\ g}{145\ cm^3}\\\\d=2.09\ g/cm^3\)

So, the density of the benzene is \(2.09\ g/cm^3\).

Answer:

in an ionic bond, atoms lose valence electrons and become positively charged

Explanation:

To clarify, the atom that loses the electrons becomes a positively charged ion (cation), and the atom that gains them becomes a negatively charged ion (anion).

Dipolar molecules include acetone. Dipole-dipole interactions are therefore the main intermolecular forces acting on the acetone molecules.

Accidental intake of acetone-containing items can cause nausea, vomiting that may contain blood, and oral inflammation. Skin irritation, including dryness, redness, and inflammation, can result from persons getting acetone on their skin. Eye discomfort or injury can result from liquid or acetone vapour contact with the eyes.

Although acetone and distilled alcohol both are chemical solvents used in different cleaning and degreasing processes as well as in the manufacturing of some similar products, they are two distinct chemical substances.

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