A box contains 100 particles of gas at room temperature. The temperature of the box is
increased. How does the motion of the particle change and affect pressure?

Answer:

The peritoneum

Explanation:

The peritoneum is the serous membrane that surrounds several organs in the abdominopelvic cavity. The tunica vaginalis is the serous membrane, which surrounds the male gonad, the testis. The two layers of serous membranes are named parietal and visceral. Between the two layers is a thin fluid filled space.

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tysm if u do ill give brainliest :D

Answer:

I think it's D

Explanation:

Answer: the asnwer would be cycle

Explanation:cycle it

Answer:

kinetic

Explanation:

hope this helps

Answer:

Kinetic energy

Explanation:

Considering the phase diagram, the state of matter that exists in area B is gas.

The correct option is A.

A phase diagram is a graphical representation that shows the conditions of temperature and pressure at which different phases or states of a substance exist.

The axes of a phase diagram typically represent temperature (usually on the horizontal axis) and pressure (usually on the vertical axis). The diagram is divided into regions that correspond to different phases, and the lines separating these regions represent phase boundaries.

The point where three phase boundaries meet is known as the triple point, which represents the temperature and pressure at which all three phases can coexist in equilibrium.

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Answer:

Explanation:

D or b

Sorry if wrong

Answer:

temporal

Explanation:

The final concentration of the solution is  0.395 M.

Concentration is the abundance of a constituent divided by way of the total extent of a combination. several types of mathematical descriptions can be outstanding: mass awareness, molar awareness, quantity attention, and volume concentration.

M₁ =1.40 M

V₁ = 66 ml = 0.066 L

M₂ = ?

V₂ = 238 ml = 0.238 L

M₁V₁=M₂V₂

M₂ = M₁V₁ / V₂

    = 1.40 × 0.066 / 0.238

    = 0.388 M

New volume V₁ = 119 ml = 0.119 L

                    V₂ = 0.117 L

M₁  = 0.388 M

M₂ =  M₁V₁ / V₂

    = 0.388 ×0.119 /0.117

     = 0.395 M

Hence, the final concentration is  0.395 M

The awareness of a substance is the quantity of solute found in a given amount of answer. Concentrations are normally expressed in phrases of molarity, defined as the number of moles of solute in 1 L of answer.

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Answer:

true

Explanation:

hydrogen and carbon make hydrocarbons

The reagents that will not react with benzene by electrophilic aromatic substitution are Sulfur trioxide (SO₃), Chlorine (Cl₂).

Electrophilic aromatic substitution is a type of organic reaction in which an electrophile (a positively charged or electron-deficient species) replaces a hydrogen atom in an aromatic ring via an electrophilic attack. This type of reaction is a characteristic feature of aromatic compounds, which are cyclic compounds that contain one or more benzene rings or similar aromatic rings.

In electrophilic aromatic substitution, the electrophile reacts with the aromatic ring in the presence of a Lewis acid catalyst (such as aluminum chloride or iron(III) chloride) to generate a positively charged intermediate called Arenium ion. The Arenium ion then undergoes a series of rearrangements to produce the final product.

There are several types of electrophilic aromatic substitution reactions, including nitration, halogenation, sulfonation, Friedel-Crafts alkylation, and Friedel-Crafts acylation. Each type of reaction involves a different electrophilic reagent and follows a unique mechanism, but all involve the initial electrophilic attack on the aromatic ring and subsequent rearrangements.

Electrophilic aromatic substitution is an important class of reactions in organic chemistry and is used in the synthesis of a wide variety of organic compounds, including pharmaceuticals, agrochemicals and materials.

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its True

Yes, burning of wood is an example of oxidation-reduction reaction.

hope it helps

To determine the universal gas constant (R), we can use the ideal gas law equation: PV = nRT, where P is the total pressure, V is the volume of gas, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

Barometric pressure of the room: To find the barometric pressure in atm, we convert 766.86 mmHg to atm by dividing it by 760 mmHg/atm, giving us 1.0089 atm.Vapor pressure of water at room temperature (PH2O).The vapor pressure of water at 23.0°C is 0.0313 atm.

Mass difference of butane lighter:The mass difference is calculated by subtracting the initial mass (54.24 g) from the final mass (54.01 g), resulting in a difference of 0.23 g.

Moles of butane gas collected:To find the moles of butane gas, we can use the equation n = m/M, where n is the number of moles, m is the mass, and M is the molar mass of butane (58.12 g/mol). Thus, n = 0.23 g / 58.12 g/mol = 0.003959 mol.

Partial pressure of butane gas:The partial pressure of butane gas is calculated by multiplying the moles of butane gas (0.003959 mol) by the ideal gas constant (R) and the converted temperature (23.0°C + 273.15 K). Let's assume the converted temperature is 296.15 K.

Converted volume of gas collected:The volume of gas collected is given as 100.0 mL, which needs to be converted to liters by dividing it by 1000, resulting in 0.1 L.

Experimental value of R:The experimental value of R can be determined by rearranging the ideal gas law equation to solve for R: R = (P - PH2O) * V / (n * T).

Accepted value of R:The accepted value of R is 0.0821 Latm/molK.

The percent error can be calculated using the formula: (|Experimental value - Accepted value| / Accepted value) * 100.

Factors contributing to percent error could include experimental error in mass measurements, inaccurate temperature measurements, and loss of gas during collection or transfer.

If the gas had not been corrected for the partial pressure of water, the value of R would be lower because the partial pressure of water would contribute to the total pressure, resulting in a smaller value for P in the ideal gas law equation.

To increase accuracy and decrease percent error, the experiment could be repeated multiple times to obtain an average value, use more precise measuring instruments, conduct the experiment in a controlled environment, and ensure accurate calibration of equipment.

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Answer:

A. The sun's rays strike the water more directly near the equator.

Explanation:

I pass the test

If 60 grams of the substance are added to 100 g of water, the solution can be categorized as supersaturated.

The graph shows the number of grams that can be dissolved in 100 grams of water at different temperatures. In general, solubility increases with temperature.

According to the graph, at a temperature of 30°C, it is possible to dissolve a total of 48 to 49 grams of \(KNO_{3}\). This information implies that if we add 60 grams at this temperature not all the substance would be dissolved, and therefore the solution would be supersaturated.

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3CH4 refers to three molecules of a compound  and C3H12 refers to only one molecule of a compound.

3CH4 and C3H12 are actually different molecules though they contain the same number and types of atoms. Recall that both of them are hydrocarbons hence they contain only hydrogen and carbon.

3CH4 refers to three molecules of methane while C3H12 refers to one molecule of diphenyl methane. Hence 3CH4 refers to three molecules of a compound  and C3H12 refers to only one molecule of a compound.

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Answer:

nobody knows

Explanation:

maybe you'll be the one to find out

Answer:

yes. yes there is.

Explanation:

The number of atoms or molecules in the compounds are as follows;

a) 6.02 * 10^24

b) 3.7 * 10^2

c) 3.7 * 10^2

d) 2.27 * 10^23

e) 4.5 * 10^23

We know that atoms are the smallest parts of a substances that can take part in a chemical reaction. We also know that one mole of a substance must contain the Avogadro's number of atoms in the molecule.

Let us now find the number of atoms in each case;

a) 20 g/2 g/mol * 6.02 * 10^23

= 6.02 * 10^24

b) 54.30 g/88 g/mol  * 6.02 * 10^23

= 3.7 * 10^2

c)  84.6 g/106 g/mol * 6.02 * 10^23

= 4.80 * 10^23

d) 9.432 * 10^3 g/25 g/mol  * 6.02 * 10^23

= 2.27 * 10^23

e) 0.75 moles  * 6.02 * 10^23

= 4.5 * 10^23

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Answer:

See the answer below

Explanation:

The carbon will have to travel in the form of CO2 from the atmosphere to a primary producer (green plant), from there to a primary consumer (herbivorous animal), and finally to a secondary consumer.

The primary producer (a green plant) would fix the carbon in the CO2 to carbohydrate through a process known as photosynthesis. The equation of the process is as shown below:

\(6 CO_2 + 6 H_2O --> C_6H_1_2O_6 + 6 O_2\)

The carbon, now in the form of carbohydrate, would then be picked up by an animal (a primary consumer) that feeds on the green plant. The carbon would eventually get into a secondary consumer when the secondary consumer feeds on the primary consumer that fed on the green plant.

The total amount of heat generated is 207.5 J, under the condition that the given sample possess 64.2-g sample of this substance with a specific heat of 50.6 J/(kg•°C).

The heat needed to change the temperature of a substance can be evaluated applying the given formula

q = m × c × ΔT

Here

q = energy added,

m = mass of the substance,

c = specific heat capacity of the substance

ΔT = change in temperature.

Then we can proceed by calculating the heat required to change its temperature from 180.0 °C to 244.0 °C by converting the mass of the substance from grams to kilograms

m = 64.2 g = 0.0642 kg

Then, we can evaluate the change in temperature

ΔT = (244.0 °C - 180.0 °C)

= 64.0 °C

Lastly, we can apply the formula above to evaluate the heat required

q = m × c × ΔT

= (0.0642 kg) × (50.6 J/(kg•°C)) × (64.0 °C)

= 207.5 J

Hence, 207.5 J of heat is required to change the temperature of this substance from 180.0 °C to 244.0 °C.

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Answer:

9.6x10⁹ mg

Explanation:

In order to solve this problem we need to convert 9600 kg into mg.

First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:

9600 kg * \(\frac{1000g}{1kg}\) = 9.6x10⁶ g

Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:

9.6x10⁶ g * \(\frac{1000mg}{1g}\) = 9.6x10⁹ mg

The mass of milk miligrams is 9.6x10⁹.

Answer: Under what condition an object having density greater than water will float on water?

If an object is more dense than water it will sink when placed in water, and if it is less dense than water it will float. Density is a characteristic property of a substance and doesn't depend on the amount of substance.

If a teacher showed an animal to students on a field trip. The  tool will allow the students to best see the animal up close is the hand lens.

Option D is correct.

A hand lens is known as a magnifying glass  which is a convex lens that is used to produce a magnified image of an object. The lens is usually mounted in a frame with a handle.

A hand lens  has two essential properties which are its focal length and its diameter.

The students will therefore require a hand lens to look up the animal close.

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#complete question:

A teacher showed this animal to students on a field trip. Which tool will allow the students to best see the animal up close? O A Tape measure O B Graduated cylinder O c. Notebook O D. Hand lens

Answer: is a substance that accepts hydrogen ions.

Answer: SiO2 has more electrons and stronger London dispersion forces.  

Answer:

water/d

Explanation:

Answer:

This question is incomplete, the complete question is:

Nancy and Hiyang are training for a race. They entered some of their training notes in a chart. Which information should be added to the chart in order find out who ran a greater distance?

The answer is C). the units used to measure distance each day

Explanation:

According to the question, Nancy and Hiyang are training for a race that involves them recording the distance they ran in a chart. Distance, as a quantity, is measured using different S.I units like metres, kilometers, miles, centimeters, etc.

However, in order to accurately discover whether Nancy or Hiyang ran a greater distance as recorded in their chart, the units used to measure distance each day must be included. This is because the unit of a quantity determines how big or small it is in comparison to another. For example, 20metres is not the same as 20centimetres.

If the unit they used in measuring their distance is not included, it will be impossible to tell what is being measured, talkless of who ran a greater distance

the units used to measure distance each day

Answer:

If n = 4, then the possible values of 1 and m depend on the equation or expression being used. Without more information, it is impossible to determine what the possible values of 1 and m might be. Can you please provide more context or information about the problem you are trying to solve?

A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.

A cylindrical weight with a mass (m) of 3 kg is dropped, that is, its initial velocity (u) is 0 m/s and travels 10 m (s). Assuming the acceleration (a) is that of gravity (9.8 m/s²). We can calculate the velocity (v) of the weight in the instant prior to the collision with the piston using the following kinematic equation.

\(v^{2} = u^{2} + 2as = 2 (9.8 m/s^{2} ) (10m) \\\\v = 14 m/s\)

The object with a mass of 3 kg collides with the piston at 14 m/s, The kinetic energy (K) of the object at that moment is:

\(K = \frac{1}{2} m v^{2} = \frac{1}{2} (3kg) (14m/s)^{2} = 294 J\)

The kinetic energy of the weight is completely converted into heat transferred into the gas cylinder. Thus, Q = 294 J.

Given all the process is at 250 K (T), we can calculate the change of entropy of the gas using the following expression.

\(\Delta S_{gas} = \frac{Q}{T} = \frac{294 J}{250K} = 1.18 J/K\)

The change in the entropy of the environment, has the same value but opposite sign than the change in the entropy of the gas. Thus, \(\Delta S_{env} = -1.18 J/K\)

A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.

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Answer:

[Ar]3d4 is the ground-state electron configuration for the Mn4 ion

but i don't know whether it is paramagnetic or daimagnetic