A box of clearance clothes at a shop contains 3 red shirts and 12 black shirts. what is the probability that ned will choose 2 red shirts randomly from the box?
Answers
we find that the probability that Ned will choose 2 red shirts randomly from the box is (3/15) x (2/14) = 1/35 or approximately 0.0286, which means there is a 2.86% chance of this occurring.
To find the probability that Ned will choose 2 red shirts randomly from the box, we will use the following steps:
1. Calculate the total number of shirts in the box: There are 3 red shirts + 12 black shirts = 15 shirts in total.
2. Find the probability of choosing the first red shirt: There are 3 red shirts, so the probability is 3/15 (3 red shirts out of 15 total shirts).
3. After choosing the first red shirt, there are now 2 red shirts and 14 total shirts left in the box.
4. Find the probability of choosing the second red shirt: The probability is now 2/14 (2 red shirts out of 14 total shirts).
5. Calculate the probability of both events occurring together: To do this, multiply the probabilities from steps 2 and 4: (3/15) x (2/14).
By following these steps, we find that the probability that Ned will choose 2 red shirts randomly from the box is (3/15) x (2/14) = 1/35 or approximately 0.0286, which means there is a 2.86% chance of this occurring.
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Related Questions
In what way does stress change how you experience your day?
Answers
Why does a Parallel Circuit still continue to function after a switch turns off one bulb but continues to pass through the second bulb? (please be as specific as possible)
Answers
Explanation:
In short, when we switch off a branch, the remaining branch still forms a complete circuit with the battery, so electricity still pass through the remaining branch.
Technically speaking, the voltage in each branch is the same, and the resistance of the light bulb remains unchanged (neglect effect of temp.) by V=IR, the current should remain unchanged after switching off the other branch.
A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.
Answers
Given:
The initial height of the ball, h=1.6 m
The initial speed of the ball, u=14 m/s
To find:
a) The time of flight of the ball.
b) The range of the ball.
Explanation:
As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.
Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.
The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.
a)
From the equation of motion,
\(h=u_yt+\frac{1}{2}gt^2\)Where g is the acceleration due to gravity and t is the time of flight of the ball.
On substituting the known values,
\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)b)
The range of the ball is given by,
\(R=u_xt\)On substituting the known values,
\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)Final answer:
a) The time of flight of the ball is 0.57 s
b) The range of the ball is 7.98 m
each specific wavelength of electromagnetic radiation has only one frequency corresponding to it
Answers
Each specific wavelength of electromagnetic radiation corresponds to only one frequency.
Electromagnetic radiation consists of waves that propagate through space. The wavelength of a wave is the distance between two consecutive crests or troughs, while frequency refers to the number of complete cycles of the wave that pass a given point per unit of time. The relationship between wavelength and frequency is inversely proportional, meaning that as the wavelength increases, the frequency decreases, and vice versa.
Since each specific wavelength corresponds to only one frequency, it is possible to determine the frequency of electromagnetic radiation based on its wavelength or vice versa. This relationship is fundamental in understanding the properties and behavior of electromagnetic radiation across different regions of the electromagnetic spectrum, from radio waves to gamma rays.
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How many different codons can make the amino acids Ala
Answers
Answer:
64 codons
Of the total of 64 codons, 61 encode amino acids and 3 specify termination of translation
Explanation:
Define power and discuss how to determine power worth 4 points
Answers
Power is, summarized, how fast something is done using energy. More specifically, power is the amount of energy transferred or converted per unit time.
To determine power, you use the following formula:
\(P=\frac{W}{Δt}\)
(formatting is messed up, the denominator is Δt)
P - power
W - work
Δt - elapsed time
Hope this helps, have a wonderful day :D
Find the magnitude of this
vector:
Answers
Answer: = 25. 5 m
Explanation:
2-D vectors can be solved using the Pythagorean theorem: \(a^{2} +b^{2} =c^{2}\)The hypotenuse, or longest side is not given and that is what must be solved forDirection can be omitted as the question only asks for magnitudeMagnitude: is the distance or quantity in which an object moves during motionSolve for C using Pythagorean theorem:
1. \(\sqrt{a^{2}+b^{2} }=c\)
2. \(\sqrt{22.2 m ^{2} +12.6m^{2} } =c\)
3. \(25.52646 m= c\)
round to lowest number of significant digits when dividing and multiplyingrounded to 3 significant digits∴ Magnitude of the vector is 25.5 m
True or false, the hardest working muscle in the body is the gluteus Maximus?
Answers
Answer:heart
The hardest working muscle is the heart. It pumps out 2 ounces (71 grams) of blood at every heartbeat. Daily the heart pumps at least 2,500 gallons (9,450 liters) of blood. The heart has the ability to beat over 3 billion times in a person's life.
Explanation:hope this helps
question a 2 kg mass and a 5 kg mass are connected by a massless cord suspended over a massless and frictionless pulley. if the acceleration due to gravity is g, what will be the acceleration of the masses after they are released from rest?
Answers
The masses accelerate at a speed of 3g13 m/s2 after being released from rest.
m1 is 2 kilogram, while m2 is 5 kg. Because the pulley has no friction and no mass, the tension force on both sides of the string will be the same. [An inactive state for the Law of Motion] Both masses accelerate at the same rate. Let's say it is a m/s2.
Remember that 2 kg of mass is flowing downhill while 5 kg of mass is traveling upward, or the opposite is true.
Let's begin writing equations.
m1 g - T = m1a for a mass of 2 kg.
2g - T = 2a ————— (I) For a mass of 5 kg, T - m2g = m2a
T - 5g = 5a ————— (II) By combining the two equations, we arrive at 2g - 5g = 13a a = 3g13 m/s2.
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On average, how many times a month can we see a full moon?.
Answers
Answer:
Once
Explanation:
The time between new moon and the end of the cycle of the moons is about 29.53 days, which is roughly a month
In young's double slit experiment by using a source of light of wavelength 5000×10^-10 m, the fringe width obtained is 0.6 cm. If the distance between the screen and the slit is reduced to half. What should be the wavelength of the source to get fringes 0.003m wide?
Answers
\({ \purple{ \tt{Here \: is \: your \: answer...}}}\)
Umm it's quiet difficult to understand. But let us note down the given values.
\({ \green{ \tt{given : - }}}\)
\({ \red{ \tt{ λ = 5000 \times {10}^{ - 10} m}}}\)
\({ \red{ \tt{ λ = 5 \times {10}^{ - 7}m}}} \)
\({ \red{ \tt{ \beta = 0.6cm = 6 \times {10}^{ - 3} m}}}\)
\({ \red{ \tt{D' = \frac{D}{2}}}}\)
\({ \red{ \tt{ \beta' = 0.003m = 3 \times {10}^{ - 3}m}}}\)
at what point does water in the air change from a gas (vapor) to a liquid
Answers
Answer:
Dew point.
Explanation:
As the temperature of water vapor decreases, it will reach the point at which it turns into a liquid. This point is called dew point. The change of water from its gaseous state to liquid water is called condensation. Dew point is the temperature at which condensation happens.
how much work is needed to push a 107- kg packing crate a distance of 2.75 m up an inclined plane that makes an angle of 30 o with the horizontal, when inclined plane is frictionless? tries 0/12 the coefficient of friction between the crate and the inclined plane is 0.22?
Answers
The work needed to push the 107-kg packing crate a distance of 2.75 m up the frictionless inclined plane with an angle of 30 degrees is approximately 448.18 Joules.
To calculate the work needed to push the packing crate up the inclined plane, we need to consider the forces involved and the displacement of the crate.
Given:
Mass of the crate (m) = 107 kg
Distance moved up the inclined plane (d) = 2.75 m
Angle of the inclined plane (θ) = 30 degrees
Coefficient of friction between the crate and the inclined plane (μ) = 0.22
First, let's calculate the component of the crate's weight (mg) that acts parallel to the inclined plane. This component is given by:
F_parallel = mg * sin(θ)
F_parallel = 107 kg * 9.8 m/s^2 * sin(30 degrees)
F_parallel ≈ 514.13 N
Next, let's calculate the work done against this force while moving the crate up the inclined plane. The work done is given by:
Work = Force * Distance * cos(θ)
Since the inclined plane is frictionless, there is no additional force to overcome. Therefore, the work done against the force of gravity is equal to the work needed to push the crate up the inclined plane.
Work = F_parallel * d * cos(θ)
Work = 514.13 N * 2.75 m * cos(30 degrees)
Work ≈ 448.18 J
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How many Watts of power does a model rocket engine have if it does 66 J of work on a model rocket in 0.9 seconds?
Answers
Power developed by a model rocket engine will be 73.3 watts. Power is the ratio of the work done or the enrgy to the time period.
What is the power output?The rate of the work done is called the power output. It is denoted by P.Its unit of a watt.
The given data in the problem is;
E is the energy = 66 J
P is the power output =?
t is the time period = 0.9 sec
The power output is given as;
\(\rm P = \frac{E}{t} \\\\ \rm P = \frac{66}{0.9} \\\\ \rm P = 73.3 \ watt\)
Hence power developed by a model rocket engine will be 73.3 watts.
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Match the following terms to the correct definition:
1.law of conservation of energy:
2.thermal energy:
3.temperature:
4.kinetic energy:
5.potential energy:
A.the energy associated with the motion and positions of particles
B.the stored energy an object possess, often due to its position relative to other objects around it
C.a scientific principle that states that energy can neither be created nor destroyed by ordinary chemical or physical means.
D.the energy that an object possesses due to its motion
E.a measure of the average kinetic energy of the particles in an object due to their random motions
Answers
The terms with their correct definition is matched as follows:
The law of conservation of energy is a scientific principle that states that energy can neither be created nor destroyed by ordinary chemical or physical means.Thermal energy is the measure of the average kinetic energy of the particles in an object due to their random motions. Temperature is the energy associated with the motion and positions of particles. Kinetic energy is the energy that an object possesses due to its motion or movement. It is measured in Joules. Potential energy is the stored energy an object possess, often due to its position relative to other objects around it.Learn more at: https://brainly.com/question/18989562?referrer=searchResults
Muốn biểu diễn vectơ lực chúng ta cần phải biết các yếu tố gì
Answers
Một đại lượng vectơ là một lực. Đại lượng vectơ là đại lượng có cả độ lớn và hướng, như chúng ta đã dạy trong phần trước. Bạn phải xác định cả độ lớn (kích thước hoặc số) và hướng của lực tác dụng lên một vật thể để mô tả hoàn toàn nó.
the process of encoding low frequencies of sound is called ________ coding.
Answers
The process of encoding low frequencies of sound is called temporal coding.
Temporal coding is a mechanism used by the auditory system to encode and represent low frequencies of sound. It involves the precise timing of neural impulses or action potentials generated by the auditory nerve in response to sound stimuli.
When a low-frequency sound wave reaches the ear, it causes the basilar membrane in the cochlea (a spiral-shaped structure in the inner ear) to vibrate. This vibration is detected by specialized hair cells along the basilar membrane. The hair cells convert the mechanical vibrations into electrical signals, which are then transmitted to the auditory nerve.
In the case of low-frequency sounds, the temporal pattern of action potentials becomes particularly important for encoding. The timing of individual action potentials generated by the auditory nerve fibers carries information about the specific frequency and intensity of the sound wave.
For example, when a low-frequency sound wave repeats its cycle slowly, the auditory nerve fibers generate action potentials at regular intervals, corresponding to each cycle of the sound wave. The precise timing of these action potentials encodes the frequency of the sound wave.
The temporal coding of low-frequency sounds is based on phase locking, where the action potentials are synchronized with specific phases of the sound wave. By detecting and encoding the timing and phase relationships between the sound wave and the neural activity, the auditory system can accurately represent and discriminate different low-frequency sounds.
It is important to note that temporal coding is just one of the mechanisms used by the auditory system to encode sounds. Higher frequencies are predominantly encoded using a different mechanism called place coding, which relies on the tonotopic mapping of different frequencies along the cochlea. Together, temporal and place coding allow the auditory system to represent a wide range of sound frequencies and enable our perception of the complex auditory world.
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A cube has length of 7 cm a width of 8 cm and a height of 2 cm. What is its volume?
If the cube has a mass of 50 grams, what is its density?
Answers
Answer:
Volume = 112cm^2
Density = 0.45 g/cm^2 (2.s.f)
Explanation:
Volume of a cube is found by multiplying its height by its length by its width.
We are given the values: l = 7cm, w = 8cm, h = 2cm, so to find the volume we just need to multiply them all together:
V=lwh
V = (7)(8)(2)
The volume of the cube = 112cm^2
Density is found by dividing mass by volume.
We are given the mass (50 grams) and we have just found the Volume (112cm^2), so we can just divide them to find the density:
p (symbol for density) = m/v
p = (50)(112)
The density of the cube is 0.45 g/cm^2 (2.s.f.)
Hope this helped!
If a ball is thrown vertically upward, what is the horizontal component of its initial velocity?
Answers
Answer:
When a projectile reaches maximum height, the vertical component of its velocity is momentarily zero (vy = 0 m/s). However, the horizontal component of its velocity is not zero.
Explanation:
Hope this helps
A ferry boat is 2.0 m wide and 4.0 m long. When a truck pulls onto it, the boat sinks 2.00 cm in the water. What is the weight of the truck?DENSITY OF WATER IS 1000 Kg/m^3
Answers
Answer:
156,800 N
Explanation:
Given: Width = 2.0 m Length = 4.0 m Depth = 2.00 cm. Density of water = 1000 Kg/m³
To find: What is the weight of the truck?
Formula: \(F = m\) × \(9.8 m/s^2\)
Solution: Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity, which is 9.8 m/s² on Earth. F is the object's weight in Newtons (N) and m is the object's mass in kilograms.
Firstly, multiply the length, width, and depth.
\(2.0\) × \(4.0\) × \(2.00\) \(= 16\)
Next, the weight of the truck is found by multiplying the density of water, the result found by multiplying the length, width, and depth, and the formula;
\(1000 kg/m^3\) × \(16\) × \(9.8m/s^2\)\(= 156,800\)
Therefore, the weight of the truck is 156,800 N
a flask of water is connected to a powerful vacuum pump. when the pump is turned on, the water begins to boil. after a few minutes, the same water begins to freeze. eventually, the ice disappears. explain what happens at each step.
Answers
The decrease in atmospheric pressure compared to vapor pressure by the vacuum pump results in water boiling.
Why does the water boils at first and freezes afterward?1. When the vacuum is turned on, the pump sucks the air from inside the flask. Due to this reason, the atmospheric pressure inside the flask falls. Water starts to evaporate and boil when the atmospheric pressure equals the vapor pressure or falls below the vapor pressure.
2. Due to the evaporation, water vapor forms which are subsequentially removed by the vacuum pump. As water vapors are removed, more liquid water is turned into water vapor and gets removed. The conversion of liquid water to water vapor is an endothermic process and the cyclical nature of the reaction brings down the temperature inside the flask. The water freezes and turns into ice.
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Use the same line to answer the questions
Q1. Use the number line above to calculate the distances and displacements for the paths listed. Don't forget to include the units.
Distance Displacement
From A to B to M to N
From C to A to G to D
From J to I to E to H
From F to B to K to F
Q2. For each of the paths from Q1, calculate the average speed and the average velocity if the path is traveled in 5.0 seconds. Don't forget to include the units. Use this Formula Reference Sheet (click this highlighted link for information) to remember the formulas you need.
Average velocity Average speed
From A to B to M to N
From C to A to G to D
From J to I to E to H
From F to B to K to F
Answers
(a) The distance From A to B to M to N is 22 m, the displacement is 22 m, the speed is 4.4 m/s and the average velocity is 4.4 m/s.
(b) The distance From C to A to G to D is 24 m, the displacement is 2 m, the speed is 4.8 m/s and the average velocity is 0.4 m/s.
(c) The distance From J to I to E to H is 16 m, the displacement is -2 m, the speed is 3.2 m/s and the average velocity is -0.4 m/s.
(d) The distance From F to B to K to F is 32 m, the displacement is 0 m, the speed is 6.4 m/s and the average velocity is 0 m/s.
Distance traveled by the objectThe distance traveled by the object is calculated as follows;
Distance From A to B to M to N
From A to B to M to N = 3 + 18 + 1 = 22
Distance From C to A to G to D
= 5 + 13 + 6
= 24
Distance From J to I to E to H
= 1 + 8 + 7
= 16
Distance from F to B to K to F
= 8 + 16 + 8
= 32
Displacement of the objectThe displacement of the object is calculated as follows;
displacement = final position - initial position
Displacement From A to B to M to N
= 11 - (-11)
= 22
Displacement from C to A to G to D
= D - C
= - 4 - (-6)
= 2
Displacement from J to I to E to H
= H - J
= 5 - 7
= - 2
Displacement From F to B to K to F
= F - F
= 0
Speed of the objectThe speed of the object is calculated as follows;
speed = total distance/total time
Speed of the object from A to B to M to N
= 22/5 = 4.4 m/s
Speed of the object from C to A to G to D
= 24/5
= 4.8 m/s
Speed of the object from J to I to E to H
= 16/5
= 3.2 m/s
Speed of the object from F to B to K to F
= 32/5
= 6.4 m/s
Average velocity of the objectThe average velocity of the object is calculated as follows;
Average velocity from A to B to M to N
= 22/5
= 4.4 m/s
Average velocity of the object from C to A to G to D
= 2/5
= 0.4 m/s
Average velocity of the object from J to I to E to H
= -2/5
= -0.4 m/s
Average velocity of the object from F to B to K to F
= 0
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what should the crew aboard a small sailboat be briefed to do when you are towing their boat?
Answers
The crew aboard a small sailboat should be briefed to follow specific instructions when their boat is being towed.
What guidelines should the crew of a small sailboat follow when their boat is being towed?When a small sailboat is being towed, the crew should adhere to the following instructions:
Secure all loose items: The crew should secure any loose items on the boat to prevent them from shifting or falling overboard during the towing process. This includes stowing equipment, sails, and personal belongings in appropriate storage spaces.
Maintain communication: The crew should establish clear communication with the towing vessel to ensure a smooth towing operation. They should follow the instructions given by the towing crew and relay any concerns or issues promptly.
Stay alert and ready to assist: While being towed, the crew should remain vigilant and ready to assist if needed. They should be prepared to help with maneuvers, follow the towing vessel's directions, and be mindful of potential hazards in the water.
By following these guidelines, the crew of a small sailboat can contribute to a safe and successful towing operation, minimizing risks and ensuring a smooth journey.
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How much energy does a 50kg rock have if it sitting on the edge of a 15m cliff
Answers
Answer:
14715 joules
Explanation:
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car? (OP A. 100 kilometers/hour south B. 200 kilometers/hour C. 200 kilometers/hour north 100 kilometers/hour
Answers
Answer:
A
Explanation:
take note that v=d/t (velocity is distance over(divided by) time, so in this case it would be 200 (distance) divided by 2 (time)
What is the best type of study to determine if daily reading with a parent can increase the speed at which a child learns to read independently
Answers
Given what we know, we can confirm that the best type of study to determine if daily reading with a parent can increase the speed at which a child learns to read independently is an experimental study.
How do we perform an experimental study?First, one must design an experiment, in this case, it can be to allow the child to read alone for a week, then measure reading speed. Then repeat this while reading with a parent and measure the speed again. After 2 weeks, compare the results.
Therefore, with an experimental study, one can test the reading speed of the child and determine if it increases when reading with a parent.
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tom the cat is chasing jerry the mouse across the surface of a table 1.2 m above the floor. jerry steps out of the way at the last second, and tom slides off the edge of the table at a speed of 6.0 m/s. where will tom strike the floor?
Answers
Tom will strike the floor at a distance of 3.6 meters from the edge of the table.
1. First, we need to find the time it takes for Tom to fall 1.2 meters to the floor. We can use the following equation for free-fall motion:
\(h = 0.5 * g * t^{2]\)
where h is the height (1.2 m), g is the acceleration due to gravity (approximately \(9.8 m/s^{2}\)), and t is the time.
\(1.2 = 0.5 * 9.8 * t^{2}\)
\(t^{2} = \frac{ (1.2 * 2) }{9.8}\)
\(t = \sqrt{ (0.2449)} = 0.495 seconds\) (approximately)
2. Now that we know the time it takes for Tom to fall, we can find the horizontal distance Tom travels during that time:
Horizontal Distance = Horizontal Speed * Time
Horizontal Distance = 6.0 m/s * 0.495 s
Horizontal Distance = 2.97 m (approximately)
Tom will strike the floor at a distance of approximately 2.97 meters from the edge of the table.
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What is the amount of charge a capacitor can store per volt of potential difference?
A) permittivity
B) dielectric constant
C) capacitance
D) electric potential energy
Answers
Capacitance is the amount of charge a capacitor can store per volt of potential difference.
What is capacitance?Capacitance is defined as the capacitors ability to store an electrical charge on its plates. Capacitance is derived from capacity which means ability to store.
So we can conclude that Capacitance is the amount of charge a capacitor can store per volt of potential difference.
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The amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.
What is the capacitance?The capacitance has to do with the amount of charge that is stored by a capacitor. We know that a capacitor is a device that can be used to store electric charges. We have in it, two capacitors separated by a dielectric material.
Hence, the amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.
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what is the weight of a 45kg box
____ N
Answers
The weight of a \(45 kg\) box is \(441.45 N\).
Weight refers to the measure of the force exerted on an object due to the gravitational pull of the Earth.
Given the mass of the box is \(m=45 kg\).
The weight of an object (\(W\)) can be found by multiplying the mass of the object (\(m\)) by the acceleration due to gravity (\(g\)).
So, \(W=mg\).
It is known that acceleration due to gravity, \(g=9.81 m/s^2\).
Hence, the weight of the box, \(W=(45kg)\times (9.81 m/s^2)\).
\(\Rightarrow W=441.45 (kg\cdot m/s^2)\\\Rightarrow W=441.45 N\)
Therefore, the weight of the box is \(441.45 N\).
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The velocity of a small ladybug that's sitting on the edge of a rotating disk (like an old vinyl album) increases as the lady bug walks _____________.
a. to the the outer edge of the disk
b. along a circular path at a constant radius
Answers
The velocity of a small ladybug that's sitting on the edge of a rotating disk (like an old vinyl album) increases as the lady bug walks along a circular path at a constant radius.
Explanation: The acceleration experienced by the ladybug is due to centripetal acceleration, which is always perpendicular to the ladybug's velocity. Because acceleration is a vector quantity, the centripetal acceleration vector constantly changes direction as it points toward the rotation axis. To comprehend why the ladybug's velocity varies as it moves around the disc, consider two distinct locations on the ladybug's path. The first location is at the top of the circle, and the second location is halfway down the circle. Because of the centripetal acceleration, the ladybug moves in a circle. As a result, it must have a net force toward the centre of the circle. The ladybug's direction of motion is perpendicular to the force acting on it. So, the ladybug accelerates toward the centre of the circle, and its speed varies. The ladybug is initially stationary when it begins its journey around the circle. When it moves along the circle path at a constant radius, its velocity grows due to centripetal acceleration. It is said that the velocity of the ladybug increases as it travels along a circular path with a constant radius. So, the correct answer is option b.
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