The speed of the block (with the bullet embedded in it) immediately after the collision, in terms of the variables provided in the problem, is given by \(v = (m/(m + M)) * (2gh)^{0.5}\), where m is the mass of the bullet, M is the mass of the block, and h is the height to which the block rises.
First, we assume that the collision is perfectly inelastic, meaning that the bullet becomes embedded in the block and they move together as a single mass. In this case, the conservation of momentum equation can be written as:
\(m_{bullet} * v_{bullet} = (m_{block} + m_{bullet}) * v_{final}\)
where v_bullet is the initial velocity of the bullet, v_final is the final velocity of the block with the embedded bullet, and we have used the fact that the block and bullet move together as a single mass after the collision.
Next, we can apply conservation of energy to find the velocity of the block with the embedded bullet at the height h. Since the collision is inelastic, some of the initial kinetic energy is lost as heat and deformation. We can express the conservation of energy equation as:
\((1/2) * m_{bullet} * v_{bulle}t^2 = (m_{block} + m_{bullet}) * g * h\)
where g is the acceleration due to gravity and we have used the fact that the potential energy gained by the block-bullet system is equal to the initial kinetic energy of the bullet.
Solving for v_final in the momentum equation and substituting it into the energy equation, we get:
\((1/2) * m_{bullet} * v_{bullet}^{2} = (m_{block} + m_{bullet}) * g * h\)
\(v_{final} = v_{bullet} * (m_{bullet} / (m_{block} + m_{bullet}))^{0.5}\)
So the speed of the block with the bullet embedded in it immediately after the collision can be calculated using this equation, where we plug in the values of \(m_{bullet}, m_{block}, v_{bullet}\), and h.
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A skateboarder rolls horizontally off the top of a staircase and lands at the bottom. The staircase has a horizontal length of 12.0 with a vertical drop of 2.00. We can ignore air resistance.
Answer: 18.8 m/s
Explanation:
A skateboarder rolls horizontally off the top of a staircase and lands at the bottom. The staircase has a horizontal length of 12.0 m with a vertical drop of 2.00 m. We can ignore air resistance.
What is the skater's initial horizontal velocity?
Answer: 18.8 m
A sample of neon gas (Ne, molar mass M = 20.2 g/mol) at a temperature of 13.0∘C is put into a steel container of mass 47.2 g that’s at a temperature of −40.0∘C. The final temperature is −28.0∘C. (No heat is exchanged with the surroundings, and you can neglect any change in the volume of the container.) What is the mass of the sample of neon?
The mass of the sample of neon gas is equal to the mass of the container, which is 47.2 g.
To solve this problem, we can use the principle of conservation of energy, assuming that no heat is exchanged with the surroundings.
We'll use the equation:
Q_neon + Q_container = 0,
where Q_neon represents the heat gained or lost by the neon gas and Q_container represents the heat gained or lost by the container.
The heat gained or lost by a substance can be calculated using the equation:
Q = mcΔT,
where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Let's calculate the heat gained or lost by the neon gas:
Q_neon = m_neon × c_neon × ΔT_neon,
where m_neon is the mass of the neon gas and c_neon is its specific heat capacity.
We need to assume that the specific heat capacity of neon gas at constant volume is approximately equal to its specific heat capacity at constant pressure.For monatomic gases like neon, the molar specific heat capacity at constant volume (Cv) is (3/2)R, where R is the molar gas constant. The molar specific heat capacity at constant pressure (Cp) is (5/2)R.
Since we have the molar mass of neon, we can calculate the molar gas constant (R) as follows:
R = 8.314 J/(mol·K).
The mass of neon gas can be determined using its molar mass (M) and the number of moles (n):
m_neon = n × M.
The number of moles can be obtained from the ideal gas law:
PV = nRT,
where P is the pressure, V is the volume, T is the temperature, and R is the molar gas constant.
In this case, we are assuming no change in the volume of the container, so the volume factor cancels out. Therefore, we don't need to consider the volume in our calculations.
Now let's calculate the heat gained or lost by the container:
Q_container = m_container × c_container × ΔT_container,
where m_container is the mass of the container and c_container is its specific heat capacity.
Since the final temperature is the same as the initial temperature of the container, ΔT_container is zero, and there is no heat gained or lost by the container.
Returning to the conservation of energy equation:
Q_neon + Q_container = 0,
we have:
Q_neon + 0 = 0,
Q_neon = 0.
Since Q_neon is zero, it means that no heat is gained or lost by the neon gas. This implies that the initial and final temperatures of the neon gas are the same, 13.0°C.
Now, let's calculate the mass of the neon gas:
m_neon = n × M,
where n is the number of moles.
To find the number of moles, we can use the ideal gas law:
PV = nRT,
where P is the pressure and R is the molar gas constant.
Given that no pressure is specified in the problem, we assume that the pressure remains constant. Therefore, the number of moles (n) and the mass of the neon gas (m_neon) remain the same.
In conclusion, the mass of the sample of neon gas is equal to the mass of the container, which is 47.2 g.
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Despite a reasonably steady hand, a person often spills his coffee when carrying it to his seat. Discuss resonance as a possible cause of this difficulty and devise a means for preventing the spills.
Resonance can be a possible cause for the difficulty in carrying a coffee without spilling it. Resonance occurs when an object vibrates at its natural frequency due to the presence of external forces. In this case, the person's steps or movements could be causing the coffee to vibrate at its natural frequency, leading to spillage.
To prevent the spills, one solution is to introduce a dampening mechanism. This can be achieved by placing a soft material, such as a rubber or foam pad, underneath the coffee cup. The soft material will absorb the vibrations, reducing the likelihood of resonance and spillage.
Another solution is to use a coffee cup with a lid and a secure closure mechanism. The lid will prevent the coffee from splashing out, even if the cup vibrates. Additionally, a secure closure mechanism, such as a screw-on cap, will provide an extra layer of protection against spills.
By implementing these measures, the person can minimize the effects of resonance and reduce the chances of spilling their coffee while carrying it to their seat.
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A sprinter starting from rest on a straight, level track is able to achieve a speed of 12 m/s in 6.0 s. What is the sprinter's average acceleration? Answer in m/s^2 (meters per second squared)
Given that a sprinter starting from rest on a straight, level track is able to achieve a speed of 12 m/s in 6.0 s. We are supposed to find the sprinter's average acceleration in m/s^2 (meters per second squared).
Average acceleration is defined as the rate at which an object changes its velocity. It is equal to the change in velocity divided by the time taken. Average acceleration = Change in velocity ÷ Time taken
Here, the change in velocity is equal to the final velocity minus the initial velocity. The initial velocity is zero because the sprinter started from rest.
Final velocity, v = 12 m/s
Time taken, t = 6.0 s
Change in velocity = Final velocity - Initial velocity
= v - u = 12 - 0 = 12 m/s
Average acceleration = Change in velocity ÷ Time taken
= 12 ÷ 6= 2 m/s^2
Therefore, the sprinter's average acceleration is 2 m/s^2 (meters per second squared).
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the energy stored in chemical bonds *
Answer:
Chemical energy (Also considered potential energy)
Explanation:
Lars is balancing equations with his study group. He is unsure about one equation because each member of the study group came up with a different answer. Which is the proper way to balance the equation Ca(OH)2 + H3PO4 → Ca3(PO4)2 + H2O?
Follow my lead or ur answer is very wrong
An electron is accelerated through a distance of 15mm the work done on the electron is 1.2x10^-13J calculate the force on the electron
help pleaseee
An arrow can only be shot by pulling it backward. When life is dragging you back with difficulties, it means it's going to launch you into something great. So just focus, and keep aiming.
That's a great analogy!
The quote you mentioned highlights the idea that challenges and difficulties in life can sometimes serve as a precursor to achieving something remarkable or experiencing personal growth. Just like an arrow, which needs to be pulled back before it can be launched forward with speed and precision, setbacks and obstacles can provide the momentum and direction needed for progress.
During tough times, it's important to stay focused on your goals and maintain a positive mindset. Instead of allowing difficulties to discourage you, view them as opportunities for learning and development. By staying determined and persevering through adversity, you increase your chances of reaching new heights and accomplishing great things.
Remember, success often comes after overcoming obstacles, and setbacks can provide valuable lessons and insights that contribute to personal and professional growth. So, keep your aim steady, embrace challenges as stepping stones, and maintain your focus on the target you're striving to achieve.
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A particle moves in a circle with radius 10 cm and with a uniform speed 1. 3 m/s. What is the centripetal acceleration of this particle?.
Centripetal acceleration is = 10π^2 cm/s.
Centripetal acceleration is = r×(W)^2.
The radius of the circular path is 0.1 m or 10 cm.
Centripetal acceleration is = r×(W)square.
Area=0.1×(π)square cm/s square.
Area=10π^2 cm/s square.
In one-dimensional kinematics, objects with a constant speed have zero acceleration. However, in two- and three-dimensional kinematics, even if the speed is a constant, a particle can have acceleration if it moves along a curved trajectory such as a circle.
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in research, a concept (a thought or notion that is challenging to measure) is termed a(n)
In research, a concept that is challenging to measure or define precisely is called a "construct." Constructs are abstract ideas or concepts that are often used in research to represent phenomena that cannot be directly observed, measured, or quantified.
Constructs are often defined by a set of indicators or measures that are used to operationalize the concept and make it measurable. For example, the construct of "intelligence" is challenging to measure directly, but researchers might use measures of IQ, academic achievement, or problem-solving ability as indicators of intelligence.
Constructs are an essential component of research, particularly in the social sciences, where many of the concepts being studied are abstract and difficult to quantify. By defining and operationalizing constructs, researchers can create more precise and rigorous methods for studying these concepts, which can lead to a deeper understanding of the phenomena being studied.
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MULTIPLE CHOICE QUESTION
Principal axis or optical axis is a virtual line that passes through
the center of the lens
the lower part of the lens
Principal axis or optical axis is a virtual line that passes through
the center of the lens.
What is lens?A lens is a transmissive optical tool that employs refraction to focus or disperse a light beam. A compound lens is made up of numerous simple lenses that are often aligned along a common axis, as opposed to a simple lens, which is made up of a single transparent piece.
Principal axis the line between the optical center and the centers of curvature of a lens's or a curved mirror's faces. Any one of three axis that are mutually perpendicular and around which a body has its greatest moment of inertia.
Principal axis or optical axis is a virtual line that passes through
the center of the lens.
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Are the units of the formula a = dv/dx, where v is velocity, x is position, and a acceleration, dimensionally consistent? select the single best answer.
Therefore, the units of acceleration, a, are dimensionally consistent and can be expressed as 1/time.
The units of the formula a = dv/dx, where v is velocity, x is position, and a is acceleration, are dimensionally consistent.
To understand why, let's break down the units of each variable.
Velocity, v, is measured in units of distance divided by time (e.g., meters per second, miles per hour).
Position, x, is measured in units of distance (e.g., meters, feet).
Acceleration, a, is measured in units of distance divided by time squared (e.g., meters per second squared, feet per second squared).
Now, let's substitute the units into the formula a = dv/dx:
- The numerator, dv, has units of (distance divided by time) because it represents the change in velocity.
- The denominator, dx, has units of distance because it represents the change in position.
When we divide (distance divided by time) by distance, we end up with units of (distance divided by time divided by distance), which simplifies to (1 divided by time).
In conclusion, the formula a = dv/dx is dimensionally consistent, with acceleration having units of 1/time.
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In 3 seconds a car moving in a straight line increases its speed from 22.4 m/s to 29.1 m/s while a truck increases its speed from 0 mph to 6.7m/s in the same amount of time. What is the acceleration of the truck in m/s? *
SHOW ALL WORK
An electron (rest mass 9.11x10^(-31) kg, charge is 1.60x10^(-19) C) is moving opposite to an electric field of magnitude E = 5x10^5 N/C. All other forces are negligible in comparison to the electric field force. What is the magnitude of the force on electron F = qE
a. 8x10-24N
b. 8x10-19N
c. 8x10-14N
d. 8x10-15N
The force exerted on the electron has the magnitude of \(8\times10^{-14} N\). The force on an electric charge q in an electric field E is given by the formula F = qE.
Here, the charge on the electron is \(q = 1.60\times 10^{-19} C\), and the electric field is \(E = 5\times10^5 N/C\).
the electron's Magnitude of force is given by :\(F = (1.60\times10^{-19} C)(5\times10^5 N/C) = 8\times10^{-14} N\)
This force is directed opposite to the direction of the electric field because the electron has a negative charge. Since all other forces acting on the electron are negligible in comparison to the electric field force, we can assume that the electron moves with a constant acceleration given by F = ma. The acceleration of the electron can be determined by using the formula a = F/m.
Substituting the values, we get
\(a = \frac{8\times10^{-14} N)}{(9.11\times10^{-31} kg)} = 8.78\times10^{16} m/s^2.\)
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what is the force constant of spring which is streched
a.2mm by a force of 4N
b.4cm by a mass of 200g
c.2cm by a mass of 1kg
Explanation:
a. F=kx
4=k (2×10^-3)
k= 2000 N/m
b. mg=kx
0.2 ×10 = k (4×10^-2)
2/(4×10^-2) =k
k=50 N/m
c. mg=kx
1×10 = k (2×10^-2)
½ × 10² =k
k=50N/m
how much effort you put into your exercises
The amount of effort put into exercises is an important factor in determining their effectiveness.
The more effort you put into your exercises, the more likely you are to see positive results such as improved strength, endurance, and overall fitness level. Effort can be measured in various ways, including the amount of weight lifted, the number of repetitions completed, and the intensity of the exercise.
It is important to challenge yourself with your exercises and push yourself to work harder in order to see progress. However, it is also important to listen to your body and avoid overexertion or injury. Finding the right balance of effort and rest is key to achieving your fitness goals and maintaining a healthy lifestyle. Regular exercise and consistent effort can lead to long-term health benefits and improved quality of life.
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Melissa was putting on her makeup when she accidentally ran into a stopped car at a red light, 11. 01 m in front of her. Melissa's 1,219 kg car was moving at 8. 133 m/s and came to a complete stop in 0. 3994 seconds. What is the magnitude of the force that stopped Melissa's car?
a
2. 970E4 N
b
1. 535E4 N
c
1. 934E4 N
d
4. 550E4 N
e
4. 295E4 N
f
3. 400E4 N
g
3. 821E4 N
h
2. 482E4 N
The required magnitude of the force that stopped Melissa's car is 118608.7 N.
What are 1st 2nd and 3rd laws of motion?According to the first law, unless a force acts on an object, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.
According to question:An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.
Given,
speed=8.133 m/s
final velocity=0 (due to impact)
time=0.3994 seconds
distance=11.01m
Then,
S = ut + (at^2)/2
a = 2(s - ut)t^2
a = 97.3 m/s^2
So,
Force = ma
Force = 1219(97.3)
Force = 118608.7 N
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Your GPS shows that your friend’s house is 10. 0 km away. But there is a big hill between your houses and you don’t want to bike there directly. You know your friend’s street is 6. 0 km north of your street. How far do you have to ride before turning north to get to your friend’s house?
You have 8.66 kilometres to bike before you turn north and arrive at your friend's house The Pythagorean theorem allows us to calculate the following distance from your starting point to your friend's street:
\(d = √[(10.0 km)^2 - (6.0 km)^2] = 8.66 km\)
This is the length of a right triangle's hypotenuse, with the horizontal leg being 6.0 km (the distance to your friend's street in the north) and the vertical leg being the remaining distance to ride before making a northward turn. To determine the length of the vertical leg, we can apply trigonometry:
\(opposite/hypotenuse = sinsin = 8.66 kilometres of vertical legsin = horizontal leg / d(vertical leg / d) = sin1(6.0 km / 8.66 km) = sin (1θ = 37.13°\)
You must therefore cycle a distance equal to:
\(d sin = 8.66 km sin 37.13° = 5.35 km vertical leg\)
The distance you must cycle in total Adding the distance to the turn and the distance from the turn to your friend's street will get you to your friend's house.
Distance total: 5.35 km plus 6.05 km equals 11.35 km
However, keep in mind that this distance is greater than the 10.0 km straight distance between your starting place and your friend's house, so if you want to reduce the amount of bicycling you do, you might want to think about finding an alternative route that completely avoids the hill.
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A 2.0 g ball with a +0.05 C charge is moved from the negative plate to the positive plate, and then is released. The potential difference between the plates is 12.0V. When the ball strikes the (–) plate its velocity is most nearly equal to
Answer:
24.5 m/s
Explanation:
Since the work done by the electric field on the charge equals the kinetic energy of the ball, then
qV = 1/2mv²
and v = √(2qV/m)
where q = charge = + 0.05 C, V = potential difference = 12.0 V, m = mass of ball = 2.0 g = 0.002 kg
Substituting the values into v, we have
v = √(2 × + 0.05 C × 12.0 V/0.002 kg)
= √(1.2 CV/.002 kg)
= √(600 CV/kg)
= 24.5 m/s
3 Below, someone is trying to balance a plank with stones. The plank has negligible weight. a Calculate the moment of the 4 N force about O. b Calculate the moment of the 6 N force about O. - 2 m * 2 m-* 4 m Р 1 4N 6N
Answer:
Moment of the 4N force = 16Nm
Moment of the 6N force = 12Nm
Explanation:
Find the diagram attached.
Moment of a force is the product of the force and the perpendicular distance from the point of application
For the 4N force
Distance of the force from O is 4m
Moment of the 4N force = 4N * 4m
Moment of the 4N force = 16Nm
For the 6N force
Distance of the force from O is 2m
Moment of the 6N force = 6N * 2m
Moment of the 6N force = 12Nm
Describe the techniques radio astronomers use to obtain a resolution comparable to what astronomers working with visible light can achieve.
Radio astronomers use interferometry techniques to obtain a resolution comparable to what astronomers working with visible light can achieve.
Astronomers use electromagnetic radiation to study space. The electromagnetic spectrum ranges from radio waves to gamma rays, with visible light being only a small part of it. Radio waves have a much longer wavelength than visible light, making it difficult to obtain the same level of resolution as visible light. This means that radio telescopes have a lower resolution than optical telescopes of the same size.
Radio telescopes are larger, and astronomers use a technique called interferometry to combine the signals from multiple telescopes to get a higher resolution. By measuring the differences in arrival times of the signal at each of the telescopes, the interferometer can use the data to build a much more detailed picture of the source. Interferometry is the process of combining signals from multiple telescopes to produce an image with much greater detail than a single telescope could produce.
This technique can also be used with visible light telescopes to produce images with much higher resolution. Interferometry is a powerful tool that has enabled astronomers to see details in space that were previously invisible.
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1. Plot the equation y = x + 1. Use the values shown for x to determine y.
how do I answer this question for you?
where is the button
A copper atom has an atomic number of 29 and an atomic mass of 64. What
is the structure of this atom?
A. It has a central nucleus composed of 35 protons and 29 neutrons,
surrounded by an electron cloud containing 29 electrons.
B. It has a central nucleus composed of 29 protons and 29 neutrons,
surrounded by an electron cloud containing 35 electrons.
C. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
D. It has a central nucleus composed of 29 protons and 64 neutrons,
surrounded by an electron cloud containing 29 electrons.
Answer:
The answer is B. It has a central nucleus composed of 29 protons and 35 neutrons, surrounded by an electron cloud containing 29 electrons.
hope it helped fond
A container of rocks is brought back from the Moon's surface where the acceleration due to gravity is 162 meters per second if the total mass of the container of rocks is 650 kilograms, what is its weight on
Earth's surface
Answer:
6318 N
Explanation:
From the question given above, the following data were obtained:
Acceleration due to gravity of the moon (gₘ) = 1.62 m/s²
Mass (m) of container = 650 kg
Weight (W) of container on the earth =.?
Next, we shall determine the acceleration due to gravity of the earth. This can be obtained as follow:
Acceleration due to gravity of the moon (gₘ) = 1.62 m/s²
Acceleration due to gravity of the earth (gₑ) =.?
gₘ = 1/6 × gₑ
1.62 = 1/6 × gₑ
1.62 = gₑ /6
Cross multiply
gₑ = 1.62 × 6
gₑ = 9.72 m/s²
Finally, we shall determine the weight of the container on the earth as follow:
Mass (m) of container = 650 kg
Acceleration due to gravity of the earth (gₑ) = 9.72 m/s²
Weight (W) of container on the earth =.?
W = m × gₑ
W = 650 × 9.72
W = 6318 N
Therefore, the weight of the container on earth is 6318 N
To win the game, a place kicker must kick a
football from a point 25 m (27.34 yd) from
the goal, and the ball must clear the crossbar,
which is 3.05 m high. When kicked, the ball
leaves the ground with a speed of 17 m/s at
an angle of 42.2◦ from the horizontal.
The acceleration of gravity is 9.8 m/s2.
By how much vertical distance does the ball
clear the crossbar?
Answer in units of
he figure below shows three rotating, uniform disks that are coupled by belts. one belt runs around the rims of disks a and c. another belt runs around a central hub on disk a and the rim of disk b. the belts move smoothly without slippage on the rims and hub. disk a has radius r; its hub has radius 0.4400r; disk b has radius 0.2700r; and disk c has radius 1.600r. disks b and c have the same density (mass per unit volume) and thickness. what is the ratio of the magnitude of the angular momentum of disk c to that of disk b?
The difference between disc C's and disc B's angular momentum is equal to 308.29, Both vector and scalar values use magnitude as a common factor.
Linear momentum's rotating equivalent is angular momentum, often known as moment of momentum or angular momentum. It is a conserved quantity, meaning that in a closed system, the total angular momentum stays constant, making it a significant physical quantity. In physics, magnitude is referred to as an object's maximal size and direction. Both vector and scalar values use magnitude as a common factor. We know that scalar quantities are those that have magnitude and nothing else by definition.
LC/ LB = (1/2)ρπRC2 h RC2ωC / (1/2)ρπRB2 h RB2ωB =1024
LC/ LB = ( 1.600R)4 /4(0.2700R)4
LC/ LB = 6.5536 / 0.02125764
= 308.29
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in a certain city, electricity costs $0.10 per kw⋅h. what is the annual cost for electricity to power a lamppost for 7.00 h per day with a 100. w incandescent light bulb versus an energy efficient 25 w fluorescent bulb that produces the same amount of light? assume 1 year
The annual cost for electricity to power a lamppost for 7.00 h per day with a 100 W incandescent light bulb versus an energy efficient 25 W fluorescent bulb is $25.55 and $6.3875 respectively.
The Power is the amount of Energy produced per unit time.
The general formula for the annual cost can be written as:
\(Cost = P\cdot t\cdot d\)
where. P is power, t is time in hours per day, and d is the total days.
Using the formula:
The cost of a 100 W incandescent light bulb:
\(Cost=(0.1)(7)(365)(0.10)=\$25.5\)
Similarly,
The cost of a 25 W fluorescent light bulb:
\(Cost=(0.025)(7)(365)(0.10)=\$6.3875\)
Hence, the annual cost is $25.55 and $6.3875 respectively.
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1. A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N
opposing the motion. Calculate the acceleration of the object.
The acceleration of the block is 6.4 m/s².
To calculate the acceleration of the block, we need to consider the forces acting on it.
The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.
The frictional force opposing the motion is 8 N.
The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).
The net force is the difference between the applied force and the frictional force:
40 N - 8 N = 32 N.
Now, we can plug the values into Newton's second law:
32 N = 5 kg × a.
Solving for the acceleration (a), we get
a = 32 N / 5 kg
a = 6.4 m/s².
Therefore, the acceleration of the block is 6.4 m/s².
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An orange dropped from a tree and had a velocity of 8 m/s just before it hits the ground. How far is the ground from orange's starting position?
The orange was at a height of 3.26 m above the ground.
State third equation of motion.The third equation of motion is
v² - u² = 2aS
Given is an orange dropped from a tree and had a velocity of 8 m/s just before it hits the ground.
We can write -
[v] = 8 m/s
[a] = 9.8 m/s²
[u] = 0 m/s
Using third equation of motion, we get -
v² - u² = 2aS
64 - 0 = 2 x 9.8 x S
64 = 19.6 x S
S = 3.26 m
Therefore, the orange was at a height of 3.26 m above the ground.
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What forces cause acceleration?
Answer:
friction, should be correct i think!