A college baseball stadium has 6,925 seats. During 12 games this season, the stadium sells out and fills every seat.

How many tickets were sold for those 12 games?

a) A and B are independent.b) B and C are independent.c) C and A are dependent.d) A, B, and C are dependent. The outcome of event C affects the probabilities of A and B, indicating a dependence among all three events.



a) Events A and B are independent because the outcome of the first flip (heads or tails) does not affect the outcome of the second flip. The probability of A (first flip is heads) is 1/2, and the probability of B (second flip is tails) is also 1/2. The joint probability of A and B is (1/2) * (1/2) = 1/4, which is equal to the product of their individual probabilities.  b) Events B and C are independent. The outcome of the second flip (tails or heads) does not affect whether both flips have the same outcome. The probability of B (second flip is tails) is 1/2, and the probability of C (both flips have the same outcome) is also 1/2. The joint probability of B and C is (1/2) * (1/2) = 1/4, which is equal to the product of their individual probabilities.

c) Events C and A are not independent. The outcome of whether both flips have the same outcome affects the probability of the first flip being heads. If both flips have the same outcome (heads or tails), then event A (first flip is heads) is certain. Therefore, the probability of A depends on the outcome of C.d) Events A, B, and C are not independent. The outcome of event C (both flips have the same outcome) affects the probabilities of events A and B. If both flips have the same outcome, events A and B are either both certain or both impossible. Therefore, the joint probability of A, B, and C is not equal to the product of their individual probabilities, indicating dependence among the three events.

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Answer:

-2

Step-by-step explanation:

-6x= 5x + 22​

-11x = 22

22/-11

-2

Answer:

x=33

Step-by-step explanation:

Answer: x=33

Step-by-step explanation:

2/3x-3=19

     +3  +3

2/3x=22

Divide by 2/3 on each side

x=33

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Answer: 440 ft^2

Explanation:

I hope this helped!

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- Zack Slocum

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Answer:

488

Step-by-step explanation:

first,you have to add both of the bases.

39+17=56

then, you have to divide it by 2

56÷2=28

lastly, you have to multiply it by the height

28×16=448

hope this helps

The value of FG is 32.

The drawing is attached with this.

Given that,

Value of EF = 11

Value of EG = 21

From the above given data we can assume that F and G be the corner points.

E is the point lie between F and G.

We have to find the value of FG. It may be a straight line.

So,

Value of FG = Value of EF + Value of EG

FG = 11 + 21

FG = 32

That is, the value of FG is 32.

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It is possible, however, that some individuals in the sample may have had heights that were close to the average, either slightly above or slightly below it.

It is unlikely that any individual in Dr. Vickers' sample (or anyone at all) would have had the exact average number of feet, as the average is typically calculated as a mathematical mean that may or may not correspond to an actual measurement.

For example, if the average (mean) number of feet in a sample of 10 people is calculated to be 6 feet, it is highly unlikely that any individual in the sample actually has a height of exactly 6 feet. Rather, the average is a statistical summary of the data that provides insight into the central tendency of the sample as a whole.

It is possible, however, that some individuals in the sample may have had heights that were close to the average, either slightly above or slightly below it.

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Answer:

As x decreases, h increases (but never touches)

As x increases, h decreases (but never touches)

Step-by-step explanation:

If you graphed the exponential, you would be able to see that it is stuck in the 3rd quadrant.

Domain: (negative infinity, 1)

Range: (negative infinity, 0)

area of the whole figure

\( = (x + 1)(2x + 3) \\ = x(2x + 3) + 1(2x + 3) \\ = 2 {x}^{2} + 3x + 2x + 3 \\ = {2x}^{2} + 5x + 3\)

area of the unshaded region

\( = x(2x) \\ = {2x}^{2} \)

area of the shaded region

\( = {2x}^{2} + 5x + 3 - {2x}^{2} \\ = ( {2x}^{2} - {2x}^{2} ) + 5x + 3 \\ = 5x + 3\)

THEREFORE,

THE AREA OF THE FRAME IS C. 5x + 3

Answer:

8

Step-by-step explanation:

8 × $70 = $560

20 × $140= $2800

$560 + $2800 = $3360

Answer:

  y = -3√(x -1) +2

Step-by-step explanation:

You want the equation of the translated, reflected, and scaled square root function in the given graph.

We can find the amount of translation by looking at the position of the point that corresponds to (0, 0) on the graph of the parent function. That end point where the slope is vertical is located at (1, 2) on the given graph.

When a function y = f(x) is translated by (h, k), it becomes ...

  y = f(x -h) +k

For (h, k) = (1, 2) the translated function is ...

  y = f(x -1) +2 = √(x -1) +2

When the function is scaled, its value is multiplied by the scale factor. If that factor is 'a', our scaled and translated function is ...

  y = a√(x -1) +2

To find the scale factor, we can use the second point on the curve: (2, -1). Using these values for x and y gives ...

  -1 = a√(2 -1) +2

  -3 = a . . . . . . . . . . subtract 2, simplify

The transformed function is ...

  y = -3√(x -1) +2

__

Additional comment

The function is scaled before it is translated, so the scale factor does not apply to the translation.

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Answer: A

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

given a quadratic equation in standard form

ax² + bx + c = 0 (a ≠ 0 )

the discriminant b² - 4ac informs us about the nature of the roots

• If b² - 4ac > 0 then roots are real and irrational

• If b² - 4ac > 0 abd a perfect square then roots are real and rational

• If b² - 4ac = 0 then roots are real and equal

• If b² - 4ac < 0 the roots are complex

4x² + 6x - 7 = 0 ← is in standard form

with a = 4, b = 6, c = - 7 , then

b² - 4ac = 6² - (4 × 4 × - 7) = 36 - (- 112) = 36 + 112 = 148

since b² - 4ac > 0 then roots are real and irrational

Answer:

16 yards gained

Step-by-step explanation:

I would add the yards that were gained first so 14 + 9

so we have 23 yards gained so far then subtract the yards loss so 23 - 7 is 16, so 16 yards were gained.

Answer:

Step-by-step explanation:

To solve this problem, we can use the formula for finding the intersection of two sets:

Intersection of Set A and Set B = Set A * Set B

Here, Set A is the set of sophomores with dogs as pets, and Set B is the set of sophomores with cats as pets among the students in Set A.

So,

Set A = 5/12 (since 5/12 of sophomores have dogs as pets)

Set B = 8/15 (since 8/15 of sophomores with dogs also have cats as pets)

Multiplying these two fractions, we get:

Set A * Set B = (5/12) * (8/15) = 2/9

Therefore, 2/9 of Washington High School sophomores have both dogs and cats as pets. The answer is 2/9.

Answer:

11

Step-by-step explanation:

I’m pretty sure. Just add it

Answer:

11

Step-by-step explanation:

Absolute value only applies to negative numbers. It will make negative numbers positive. As you can see in the problem, they are asking for the absolute value of positive numbers, so you can ignore the absolute value signs and add normally.

Hope it helps! Comment if you have any questions!

Given :

⠀

To Find :

⠀

Solution :

We know that,

\(\qquad \pmb{\bf{Area_{(Rectangle)}= Length \times width }}\)

⠀

So, Substituting the given values :

\( \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = 2 \dfrac{4}{5} \times 2 \dfrac{3}{7} }}\)

\( \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{14}{5} \times \dfrac{17}{7} }}\)

\( \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{ \cancel{14}}{5} \times \dfrac{17}{ \cancel{7}} }}\)

\( \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{2}{5} \times {17} }}\)

\( \: \qquad \dashrightarrow \sf{{Area_{(Rectangle)} = \dfrac{34}{5} }}\)

\( \: \qquad \dashrightarrow \sf{{Area _{(Rectangle)} = 6 \dfrac{4}{5} \: {mm}^{2} }}\)

Therefore,

Answer:

120

Step-by-step explanation:

5*4*3*2*1

Both statements

1. If a > 0, then a > 0.

2. If a < 0, then a - 1 < 0.

have been proven by using the properties of an ordered field.

To prove the statements:

1. If a > 0, then a > 0.

2. If a < 0, then a - 1 < 0.

We will use the properties of an ordered field F.

Assume a > 0.

Since F is an ordered field, it satisfies the property of closure under addition.

Thus, adding 0 to both sides of the inequality a > 0, we get a + 0 > 0 + 0, which simplifies to a > 0.

Therefore, if a > 0, then a > 0.

Assume a < 0.

Since F is an ordered field, it satisfies the property of closure under addition and multiplication.

We know that 1 > 0 in an ordered field.

Subtracting 1 from both sides of the inequality a < 0, we get a - 1 < 0 - 1, which simplifies to a - 1 < -1.

Since -1 < 0, and the ordering of F is preserved under addition, we have a - 1 < 0.

Therefore, if a < 0, then a - 1 < 0.

In both cases, we have shown that the given statements hold true using the properties of an ordered field. Hence, the proof is complete.

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Answer:

$1.5

Step-by-step explanation:

So you need to subtract 25 from 13 = 12 then take 3 and 5 and add = 8 then you need to divide 12 from 8 = 1.5 so i do believe that the tubes are $1.5

I may be wrong and im sorry but pls try :3

The polynomial x² - 16 can be represented geometrically using algebra tiles. The number of zero pairs that will be added to the board is 4, as there are two pairs of x and 4 tiles that represent the squared term 16.

The equivalent factored form of x² - 16 is (x - 4)(x + 4).To represent the polynomial x² - 16 using algebra tiles, we can use square tiles to represent the squared term x² and rectangular tiles to represent the constant term -16. For x², we use a single x tile for each x, and for 16, we use four tiles to represent the magnitude.

When we add these tiles to the board, we will have two pairs of x and four tiles representing the magnitude of 16. Each pair of x and 4 tiles forms a zero pair, meaning they cancel each other out and do not contribute to the overall value.

The factored form of x² - 16 can be determined by finding the values that multiply together to give -16 and add up to zero. In this case, the factors are (x - 4) and (x + 4), as (x - 4)(x + 4) equals x² - 16.

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Answer:

80,000

Step-by-step explanation:

1/4(25%)×60,000=20,000

20,000+60,000=80,000

Your question was incomplete. Please check below the full content.

There are 8 ounces in 1 cup and 16 cups in 1 gallon.

(a) Diane brought 4.5 gallons of water to a campout. How many ounces of water did she bring? Show your work.

(b) Diane started a hike with 24 ounces of water in her backpack. What fraction of a gallon of water did she start the hike with? Show your work.

a) 576 ounces of water Diane brought.

b) 3/16 of a gallon of water did she start the hike with.

Given that there are 8 ounces in 1 cup and 16 cups in 1 gallon. 

a) Amount of water diana brought for campout = 4.5 gallons Ounce of water she brought = 4.5×16×8

= 576ounces

b) Diane started a hike with 24 ounces of water in her backpack.

The fraction of gallons in 24 ounces is calculated as follows:

The fraction of gallons in 24 ounces = 24 / (8×16)

= 3/16

Hence, a) 576 ounces of water Diane brought.

b) 3/16 of a gallon of water did she start the hike with.

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The 15 foot ramp must make an angle 19.45° with the ground to reach the same window.

Since the height of the window above ground remains constant in both cases, it follows that by means of trigonometric identity sine; we have;

10sin30° = 15sinx

sinx = 5/15 = 0.333

x = sin-¹(0.333)

x = 19.45°.

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The distance between the two planes after 4 hours is approximately 150 km.

to find out how far apart the planes are after 4 hours, we can use the concept of vectors.

Let's start by finding the positions of the two planes after 4 hours.

The first plane flies at a speed of 110 km/h in a direction of 280°. To find its position after 4 hours, we can use the formula: distance = speed × time. So, the distance traveled by the first plane is 110 km/h × 4 hours = 440 km.

To determine the position of the first plane, we need to convert the direction (280°) into components. The x-component is given by: cos(280°) × distance = cos(280°) × 440 km. The y-component is given by: sin(280°) × distance = sin(280°) × 440 km.

Similarly, for the second plane, which flies at a speed of 250 km/h in a direction of 200°, the distance traveled after 4 hours is 250 km/h × 4 hours = 1000 km. To determine its position, we need to convert the direction (200°) into components. The x-component is given by: cos(200°) × distance = cos(200°) × 1000 km. The y-component is given by: sin(200°) × distance = sin(200°) × 1000 km.

Now, let's calculate the x and y components for both planes:

For the first plane:
x-component = cos(280°) × 440 km
y-component = sin(280°) × 440 km

For the second plane:
x-component = cos(200°) × 1000 km
y-component = sin(200°) × 1000 km

the distance between the two planes, we can use the distance formula, which is given by: distance = √((x2 - x1)^2 + (y2 - y1)^2), where (x1, y1) and (x2, y2) are the positions of the first and second planes respectively.

Now, substitute the values we calculated into the distance formula:

distance = √((x2 - x1)^2 + (y2 - y1)^2)
distance = √((cos(200°) × 1000 km - cos(280°) × 440 km)^2 + (sin(200°) × 1000 km - sin(280°) × 440 km)^2)

After evaluating the above expression, the distance between the two planes after 4 hours is approximately 150 km.

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The required percentage of regular grade gasoline are;

a) 34%

b) 95.5%

c)4.5%

(a) To determine the percentage of regular grade gasoline sold between $3.25 and $3.65 per gallon, we need to find the proportion of the data that falls within this range. Assuming a bell-shaped distribution, we can use the standard deviation and mean to find the z-scores for these two prices, and then look up the cumulative probability in a standard normal table.

$3.25$ is $1$ standard deviation below the mean and $3.65$ is $0.5$ standard deviation above the mean.

Using a standard normal table, we find that approximately 68% of the data falls within one standard deviation of the mean, and approximately 34% falls between $-0.5$ and $0.5$ standard deviations.

Therefore, approximately 34% of regular grade gasoline is sold between $3.25 and 3.65 per gallon.

(b) To find the percentage of regular grade gasoline sold between $3.25 and $3.85 per gallon, we need to find the cumulative probability for the range $3.25$ to $3.85$.

$3.85$ is $1.5$ standard deviations above the mean.

Using a standard normal table, we find that approximately 95.5% of the data falls within $1.5$ standard deviations of the mean.

Therefore, approximately 95.5% of regular grade gasoline is sold between $3.25 and $3.85 per gallon.

(c) To find the percentage of regular grade gasoline sold for more than $3.85 per gallon, we need to find the cumulative probability for values greater than $3.85$.

Using a standard normal table, we find that approximately 100% - 95.5% = 4.5% of the data falls above $1.5$ standard deviations from the mean.

Therefore, approximately 4.5% of regular grade gasoline is sold for more than $3.85 per gallon.

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The radius of the centre of an atom of element x is 1.2 x \(10^{-14\) m.

Given that the radius of an atom of element x is 1.2 x 10^-10 m and the radius of the centre of the atom is 1/10000 the radius of the atom. We can calculate the radius of the centre of the atom using the formula:

Radius of the centre of the atom = 1/10000 x radius of the atom

Substituting the values, we get:

Radius of the centre of the atom = 1/10000 x 1.2 x \(10^{-10\) m

Simplifying this expression, we get:

Radius of the centre of the atom = (1.2/10000) x \(10^{-10\) m

Radius of the centre of the atom = 1.2 x \(10^{-14\) m

Therefore, the radius of the centre of an atom of element x is 1.2 x \(10^{-14\) m in standard form.

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Answer:

Mikhail is 50 old why because Gabrielle and they said the sum of their age is 58 so that mean Mikhail is older 58-8=50

Step-by-step explanation:

The integral ∫∫ r √4 −x2−y2da where r = {(x, y) : x2 y2≤ 4, x ≥ 0} conversion to polar coordinates the value of the integral is (4/3)π.

To convert the integral to polar coordinates, we need to express the limits of integration in terms of the polar coordinates.

Recall that in polar coordinates, x = r cosθ and y = r sinθ, where r is the radial distance from the origin and θ is the angle measured counterclockwise from the positive x-axis to the line connecting the origin to the point (x, y).

In this case, the region r is defined by \(x^2 + y^2\) ≤ 4 and x ≥ 0. In polar coordinates, this corresponds to the region 0 ≤ r ≤ 2 and 0 ≤ θ ≤ π/2. To see why, note that x ≥ 0 implies 0 ≤ θ ≤ π/2, and \(x^2 + y^2 = r^2\), so r ≤ √4 = 2.

So we have:

∫∫ r √4 −x2−y2da = ∫(θ=0 to π/2) ∫(r=0 to 2) r√(4-\(r^2\)) dr dθ

To evaluate this integral, we can use the substitution u = 4 - \(r^2\), du = -2r dr, which gives:

∫∫ r √4 −x2−y2da = ∫(θ=0 to π/2) ∫(u=4 to 0) -1/2 √u du dθ

Now we can evaluate the inner integral:

∫(u=4 to 0) -1/2 √u du = [-1/3 u^(3/2)](u=4 to 0) = (1/3)(8 - 0) = 8/3

Substituting this back into the original integral, we have:

∫∫ r √4 −x2−y2da = ∫(θ=0 to π/2) (8/3) dθ = (8/3) (π/2 - 0) = (4/3)π

Therefore, the value of the integral is (4/3)π.

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Answer

A plane intersects only one nappe of a double-napped cone, and the plane is not parallel to the generating line of the cone.

Step-by-step explanation:

Parabola is a symmetrical open plane bend framed by the crossing point of a cone with a plane parallel to its side. The way of a shot affected by gravity in a perfect world takes after a bend of this shape.