a college food court surveyed students to see how many drink tea and how many drink soda. the venn diagram below shows the results. (each number gives the number of students who fall into that venn diagram category.) (a) how many of the students drink soda? (b) how many of the students drink tea or soda (or both)? (c) how many of the students do not drink both tea and soda?

Answers

Answer 1

A college food court surveyed students to see how many drink tea and how many drink soda using the Venn Diagram:

Number of student who drink soda is 197students who drink tea or soda or both 348students do not drink both tea and soda is 88.

In order to solve problems based on these sets, we may use a Venn diagram to depict the logical link between sets and their components. Although other closed figures like squares may be used, a Venn diagram commonly utilises intersecting and non-intersecting circles to indicate the relationship between sets.

A college food court surveyed 407 students to see how many drink tea and how many drink soda.

a.) The number of students who do not drink tea is

197 + 59 = 256

b.) The number of students who drink tea or soda or both is

88 + 63 + 197 = 348

c.) The number of students who drink tea but do not drink soda is 88.

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Complete question:

A college food court surveyed 407 students to see how many drink tea and how many drink soda. The Venn diagram below shows the results. (Each number gives the number of students who fall into that Venn diagram category.) -All students in the survey Drink tea Drink soda 88 63 197

(a) How many of the students drink soda ?

(b) How many of the students drink tea or soda (or both)? IS students

(c) How many of the students drink tea but do not drink soda?

A College Food Court Surveyed Students To See How Many Drink Tea And How Many Drink Soda. The Venn Diagram

Related Questions

10) Determine whether the events of rolling a fair die two times are disjoint, independent, both, or neither. A) Disjoint. B) Exclusive. C) Independent. D) All of these. E) None of these.

Answers

The answer is option (C), that is, the events of rolling a fair die two times are independent. The events are neither disjoint nor exclusive.

When rolling a fair die two times, one can get any one of the 36 possible outcomes equally likely. Let A be the event of obtaining an even number on the first roll and let B be the event of getting a number greater than 3 on the second roll. Let’s see how the outcomes of A and B are related:

There are three even numbers on the die, i.e. A={2, 4, 6}. There are four numbers greater than 3 on the die, i.e. B={4, 5, 6}. So the intersection of A and B is the set {4, 6}, which is not empty. Thus, the events A and B are not disjoint. So option (A) is incorrect.

There is only one outcome that belongs to both A and B, i.e. the outcome of 6. Since there are 36 equally likely outcomes, the probability of the outcome 6 is 1/36. Now, if we know that the outcome of the first roll is an even number, does it affect the probability of getting a number greater than 3 on the second roll? Clearly not, since A∩B = {4, 6} and P(B|A) = P(A∩B)/P(A) = (2/36)/(18/36) = 1/9 = P(B). So the events A and B are independent. Thus, option (C) is correct. Neither option (A) nor option (C) can be correct, so we can eliminate options (D) and (E).

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Which two ratios form a proprtion?
A) 6/9 and 3/1
B) 6/9 and 1/3
C) 6/9 and 2/3
D) G/9 and 3/2

Answers

I think the answer is b

Which equation represents a line which is parallel to the line y=-3/4 x -2

Answers

Answer:  Any equation that is of the form y = -3/4x + b, where b is a real number, will be parallel to y = -3/4x - 2.

Step-by-step explanation:

A parallel line has the same slope as the original line.  Therefore, if the equation of the original line is y = mx+b, m (the slope) will remain the same, while b can change.

The equation  y = -3/4x - 2 has the same slope -3/4, represents a line which is parallel to the line y=-3/4 x -2

What is a linear function?

A function that can be represented in the form of y =mx +c, is called a Linear Function. where m is the slope and c is the y-intercept.

The slope of the given line can be found as;

A parallel line has the same slope as the original line.  Thus, if the equation of the original line is y = mx+b, m (the slope) will remain the same, while b can change.

Any equation that is of the form y = -3/4x + b,

where b is a real number, will be parallel to the equation.

y = -3/4x - 2.

m = -3/4

The equation  y = -3/4x - 2 has the same slope -3/4, represents a line which is parallel to the line y=-3/4 x -2

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what would be the best first step in solving this system?​

what would be the best first step in solving this system?

Answers

Answer:

B. substitute for X in first equation

Given 4 and one tenth times negative 4 times 5 over 12, determine the product. negative 16 and 5 over 120 16 and 5 over 60 negative 6 and five sixths 6 and five sixths

Answers

The value of the expression \(4\frac{1}{10}\times-4\times\frac{5}{12}\) is \(-6\frac{5}{6}\).

What is a numerical expression?

A mathematical statement expressed as a string of numbers and unknowable variables is known as a numerical expression. Statements can be used to create numerical expressions.

The given, expression is \(4\frac{1}{10}\times-4\times\frac{5}{12}\).

= (41/10) × (- 4) × (5/12).

= (41×-4×5)/(10×12).

= (-820/120).

= - 82/12.

= - 41/6.

= \(-6\frac{5}{6}\).

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(this is a rhombus btw) for what value of x is the figure the given special parallelogram? HELP PLS, show work.

(this is a rhombus btw) for what value of x is the figure the given special parallelogram? HELP PLS,

Answers

Answer:

x = 2 or 3

Step-by-step explanation:

Diagonal of a rhombus bisects the vertex angles. So,

\(x^{2} =5x-6\)

\(=> x^{2} -5x + 6 = 0\)

Lets factorise the eqn.

\(=> x^{2} - 2x - 3x + 6 = 0\)

\(=> x (x - 2) -3(x-2)\)

\(=> (x-2)(x-3) = 0\)

Here x will have 2 values.

1) \(x-2=0\)

\(=> x =2\)

2) \(x - 3 = 0\)

\(=> x = 3\)

pls help!!! worth 14 points:))))

pls help!!! worth 14 points:))))

Answers

Answer:

28

Step-by-step explanation:

Answer:

28

Step-by-step explanation:

180-152=28

28 _________

express -3/6 as a rational number with denominator 20​

Answers

Answer:

20 cause when According to Sciencealert, the longest math equation contains around 200 terabytes of text. Called the Boolean Pythagorean Triples problem, it was first proposed by California-based mathematician Ronald Graham, back in the 1980s.The Navier-Stokes equation, for me is the hardest of all. This is the full Navier-Stokes equation in conservative form. It looks pretty simple, but as one will dig in, they will notice why it is the hardest one.

In the figure below, points D, E, and F are the midpoints of the sides of ABC

In the figure below, points D, E, and F are the midpoints of the sides of ABC

Answers

Answer:

DF=28 AC=64 CF=32

Step-by-step explanation:

anyone think they could help ?

anyone think they could help ?

Answers

i think its 14 or 7/2

\(2x+5\ \textless \ \frac{x+1}{4}\)

Answers

Given :-

2x + 5 < x + 1 / 4

Solution :-

>> 2x + 5 < x + 1 / 4

>> 4 (2x + 5) < x + 1

>> 4 × (2x + 5) < x + 1

>> 8x + 20 < x + 1

>> 8x - x < 1 - 20

>> 7x < 1 - 20

>> 7x < -19

>> x = -19 / 7

\(\boldsymbol{\sf{2x+5 < \dfrac{x+1}{4} }}\)

Multiply the two sides of the equation by 4. Since 4 is > 0, the direction of inequality remains the same.

          \(\boldsymbol{\sf{8x+20 < x+1 }}\)

Resta x en los dos lados.

              \(\boldsymbol{\sf{8x+20-x < 1 }}\)

Combine 8x and −x to get 7x.

                \(\boldsymbol{\sf{7x+20 < 1 }}\)

Subtract 20 on both sides.

                 \(\boldsymbol{\sf{7x < 1-20 \ \ \longmapsto \ \ [To \ subtract] }}\)

                  \(\boldsymbol{\sf{7x < -19 }}\)

Divide the two sides by 7. Since 7 is >0, the direction of inequality remains the same.

                     \(\boldsymbol{\sf{x < -\dfrac{19}{7} } }\)

As the end result, it is not simplified or divided, then

                               \(\blue{\boxed{\boldsymbol{\sf{Answer \ \ \longmapsto \ \ x < -\frac{19}{7} }}}}\)

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Calculate the perimeter of this right- angled triangle. Give your answer in metres (m) to 1 d.p. 7m 19 m ​

Answers

Answer: 46.2m

Side A = 7m

Side B = 19m

Side C = 20.2m

Side A + Side B + Side C = ABC

7 + 19 + 20.2 = 46.2m

The concessions stand manager ordered 20,280 souvenir cups. He wants to divide them evenly among the 24 concession stands that he is in charge of. How many cups will each concession stand receive?

Answers

Answer: 845

Step-by-step explanation: so you divide 24 by 20,280. 24 goes into 202 how many times then from there on u get your answer

Let's now see what the distribution of statistics is actually like under Emily's model. Define the function simulation_and_statistic to take in the model_proportions array and the expected proportion of times a TT practitioner would guess a hand correctly under Emily's model. The function should simulate Emily running through the experiment 210 times and return the statistic of this one simulation

Answers

Here's a possible implementation of the function.

What is fraction?

A fraction represents a part of a whole or a ratio between two quantities. It consists of a numerator (top number) and a denominator (bottom number) separated by a fraction bar. The numerator represents the number of equal parts being considered, while the denominator represents the total number of equal parts in the whole. Fractions can be written in various forms, such as mixed numbers, improper fractions, or decimals.

Here,

The function uses NumPy's random.choice function to simulate Emily running through the experiment 210 times and recording her guesses. It then calculates the proportion of times Emily guessed a hand correctly, and uses this to compute the standard normal deviate (also known as the z-score) of the proportion, which is a measure of how many standard deviations away from the expected proportion the observed proportion is. The statistic is then simply this z-score, which we can use to test the null hypothesis that Emily's guesses are no better than chance.

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please help me out!!13p

please help me out!!13p

Answers

Answer: i believe its B

Step-by-step explanation:

thats what i would put

Alice and Bob the end the nice restaurant. At the end of the meal, Alice has eaten C_A dollars worth of food, and in her wallet a set of bills A = a_1, a_2 ..., a_n Similarly, Bob owes the restaurant c_B dollars and has bills B = {B_1, B_2, ....b_m}. Now, Alice and Bob are very calculating people, so they agree that each of them should pay their fair share (C_A and c_B, respectively). One thing they don't mind doing, however, is fairly trading bills. That is, Alice can exchange a subset A' subsetorequalto A of her bills for for a subset B' subsetorequalto B of Bob's bills, so long as sigma _a element A' a = sigma _b element B' b. Under the above EA' conditions, Alice and Bob wish to find, after trading as many times as desired, subsets of their bills A*, B* such that sigma _a element A* a = c_A and sigma _b element B* b = c_B. Show that FAIR DATE is NP-complete.

Answers

FAIR DATE is both in NP and NP-hard, we can conclude that FAIR DATE is NP-complete.

To prove that FAIR DATE is NP-complete, we need to show two things: (1) FAIR DATE is in NP, and (2) FAIR DATE is NP-hard.

1. FAIR DATE is in NP:
We can easily verify a potential solution for FAIR DATE in polynomial time. Given subsets A* and B*, we can check if the sum of the bills in A* equals c_A and the sum of the bills in B* equals c_B. This verification can be done in O(n) time for Alice's bills and O(m) time for Bob's bills, where n and m are the number of bills Alice and Bob have, respectively.

2. FAIR DATE is NP-hard:
To show that FAIR DATE is NP-hard, we need to reduce a known NP-complete problem to it. Let's choose the PARTITION problem for this reduction. In the PARTITION problem, given a set S of integers, we need to determine if there exists a subset S' of S such that the sum of the elements in S' is equal to half the sum of all elements in S.

Reduction: Given an instance of PARTITION, we can create an instance of FAIR DATE as follows:
- Let Alice's bill be the set A = S, and c_A = 1/2 * (sigma_a ∈ A, a).
- Let Bob's bill be the set B = {}, and c_B = 0.

Now, if there exists a subset A* of A such that sigma_a ∈ A* a = c_A, then this subset is the solution to the PARTITION problem as well. Conversely, if there is a solution to the PARTITION problem, then there exists a subset A* such that sigma_a ∈ A* a = c_A.

Since we can perform this reduction in polynomial time, FAIR DATE is NP-hard.


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The scale of a map is 1 in.: 17.5 mi. Find the actual distance corresponding to the map distance of 5 in.
A. 87.5 mi
B. 3.5 mi
C. 22.5 mi

Answers

Answer:

A. 87.5 mi

Step-by-step explanation:

1 in : 17.5 mi       Multiply both sides of the ratio by 5

5 in : 87.5 mi

The Air Jordan Retro 12's dropped at a popular shoe store. They were
advertised at 20% off the regular price. Then for the weekend only, the
sale price was reduced an additional 15%. A customer went in to purchase
the Retro 12's, but became confused when he did not receive 35% off the
regular price. Explain why the discount should NOT be 35%.*

Answers

Answer:

because its bad for branding the person who did that was a ldiot

Step-by-step explanation:

Which of the following is the solution set of the
problem?
O (-∞, -3)
(-∞, -3]
O
[-3,00)
O (-3,00)
DONE

Answers

The solution set of the example inequality, 2•x + 3 ≤ -3, is the option;

(-∞, -3]

How can the solution set of an inequality be found?

A possible inequality that can be used to get one of the options, (the inequality is not included in the question) is as follows;

2•x + 3 ≤ -3

Solving the above inequality, we have;

2•x + 3 ≤ -3

2•x ≤ -3 - 3 = -6

2•x ≤ -6

Therefore;

x ≤ -6 ÷ 2 = -3

x ≤ -3

Which gives;

-∞ < x ≤ -3

-∞ < x ≤ -3 in interval notation is (-∞, -3]

The solution set of the inequality, 2•x + 3 ≤ -3, is therefore the option;

(-∞, -3]

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some scientists believe that a new drug would benefit about half of all people with a certain blood disorder. to estimate the proportion of patients who would benefit from taking the drug, the scientists will administer it to a random sample of patients who have the blood disorder. what sample size is needed so that the 95% confidence interval will have a width of 0.06? group of answer choices 2056 2401 1503 748 1068

Answers

Rounding up to the nearest integer, we get a sample size of 1068. Therefore, the answer is 1068.

To find the required sample size, we need to use the formula for the margin of error of a proportion:

Margin of error = z*sqrt(p(1-p)/n)

where z is the z-score for the desired level of confidence, p is the estimated proportion, and n is the sample size.

Since we want the confidence interval to have a width of 0.06, the margin of error should be 0.03. Also, since the scientists believe that about half of all people with the blood disorder will benefit from the drug, we can estimate p as 0.5. Finally, we can use a z-score of 1.96 for a 95% confidence interval.

Substituting these values into the formula, we get:

0.03 = 1.96sqrt(0.5(1-0.5)/n)

Solving for n, we get:

n = (1.96/0.03)^20.5(1-0.5) = 1067.11

Rounding up to the nearest integer, we get a sample size of 1068. Therefore, the answer is 1068.

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points d e and f are not on a line to construct a circle through points d e a dn f begin by drawing line segments de and ef then construct the perpindicular bisectors of de and ef and name the point of intersection of the perpindicular bisectors o how do you know that point o is the center of the circle that passes through the three points.

Answers

If O is the intersection point of the perpendicular bisectors of line segments DE and EF, then O is the center of the circle that passes through the three points.  

1: Draw line segments DE and EF. Since the question states that the points D, E, and F are not on a line, we can assume that these three points form a triangle. So, we will draw line segments DE and EF as shown in the diagram below.

2: Construct the perpendicular bisectors of DE and EF.A perpendicular bisector is a line that passes through the midpoint of a line segment and is perpendicular to it. We can construct the perpendicular bisectors of line segments DE and EF using a straight edge and a compass. After constructing the perpendicular bisectors, we label the point of intersection O.

3: Explain why point O is the center of the circle that passes through the three points.Since the perpendicular bisectors of DE and EF intersect at point O, we know that point O is equidistant from points D and E, and also equidistant from points E and F. This means that O is equidistant from all three points D, E, and F.

Hence, O is the center of the circle that passes through these three points.

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The polygons are similar. Find the value of x.

The polygons are similar. Find the value of x.

Answers

Answer:

24

Step-by-step explanation:

18/3=6 6*4=24

The value of x for the similar triangles is equal to 24.

How to calculate for x for the similar triangles

The triangles are similar, this implies that the length x cm of the bigger triangle is similar to the length HJ = 18 cm of the smaller triangle

and the length DF = 16 cm of the bigger triangle is similar to the length JG = 12 cm of the smaller triangle

so;

x/18 = 16/12

12x = 18 × 16 {cross multiplication}

12x = 288

x = 288/12 {divide through by 12}

x = 24 cm

Therefore, the value of x is equal to 24 cm for the similar triangles.

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Could 7.7\text{ cm}, 4.0\text{ cm},7.7 cm,4.0 cm,7, point, 7, start text, space, c, m, end text, comma, 4, point, 0, start text, space, c, m, end text, comma and 1.7\text{ cm}1.7 cm1, point, 7, start text, space, c, m, end text be the side lengths of a triangle?

Answers

Answer:

The given three sides can not form a triangle.

Step-by-step explanation:

Given three sides:

Length of first side = 7.7 cm

Length of second side = 4.0 cm

Length of third side = 1.7 cm

To find:

Whether these three sides can possibly be the three sides of a triangle ?

Solution:

Here, we can use the property of sides of a triangle:

The sum of the lengths of any two sides must be greater than the length of third side.

Now, let us try to verify this property.

Length of first side + Length of second side = 7.7 + 4.0 = 11.7 cm which is greater than the length of third side i.e. 1.7 cm

Length of first side + Length of third side = 7.7 + 1.7 = 9.4 cm which is greater than the length of second side i.e. 4.0 cm

Length of second side + Length of third side = 4.0 + 1.7 = 5.7 cm which is not greater than the length of first side i.e. 7.7 cm

Therefore, the property does not hold true.

It can be concluded that, the given three sides can not form a triangle.

Answer:

isyllus is correct

they can not from a triangle

Step-by-step explanation:

Find the median, Q1, Q3, interquartile range (IQR), and list any outliers. 2) 74, 63, 69, 62, 33, 79, 70, 60, 107, 119

Answers

Answer:

Since the sample size is n=10 we can find the first quartile taking in count the first 5 observations from the data set ordered and we have this:

33  60  62  63  69

\( Q_1 =62\)

We can find the third quartile taking in count the last 5 observations from the data set ordered and we have this:

70  74  79 107 119

\( Q_3 =79\)

And finally the median can be calculated with the average of the two moddlie values and we got:

\( Median= \frac{69+70}{2} =69.5 \)

And the IQr would be:

\( IQR = 79-62= 17\)

Step-by-step explanation:

Assuming that 2 is not part of the data we have:

74, 63, 69, 62, 33, 79, 70, 60, 107, 119

We can sort the values on increasing order and we got:

33  60  62  63  69  70  74  79 107 119

Since the sample size is n=10 we can find the first quartile taking in count the first 5 observations from the data set ordered and we have this:

33  60  62  63  69

\( Q_1 =62\)

We can find the third quartile taking in count the last 5 observations from the data set ordered and we have this:

70  74  79 107 119

\( Q_3 =79\)

And finally the median can be calculated with the average of the two moddlie values and we got:

\( Median= \frac{69+70}{2} =69.5 \)

And the IQr would be:

\( IQR = 79-62= 17\)

Question 3 The Schwarzschild metric is given by 2M 2M ds² -(₁-²M) di² + (1-²¹)- 1- dr² +r² (d0² + sin² 0 dó²). There are Killing vectors associated with time invariance and angular momen- tum invariance in the direction in this geometry leading to the conserved quantities e = (1-2) and l= r² sin² 0 dr From this one can derive an analog to the radial energy equation in Newtonian mechanics by orienting the coordinates so that the orbits are confined to the equatorial plane where 0 = π/2 and u = 0. One finds 2 1 dr + Veff (r) = E 2 dr (e²_ -1) where E = and Veft(r) = - + 2/²/²2 - Mp³². Further, for circular orbits one can show that M | [₁ + √/₁−12 (+1)]. r+= | 2M Finally, for circular orbits of radius R do 1/2 M dt R³ (a) Which value of r corresponds to the Schwarzschild radius of stable circular orbits: r or r? Justify your answer. [3 marks] (b) Show that for circular orbits of radius R do 1/2 M -1/2 3M (²) ¹² (1-³) dT R³ R where is the proper time. [6 marks] (c) A free particle is moving in a circular orbit around a spherical source of curvature of mass M. The Schwarzschild radius of the orbit is 8M. Use the equivalence principle to argue that the period as measured at infinity should be larger than that measured by the particle. [4 marks] (d) Find the period of the orbit as measured by an observer at infinity. Find the period of the orbit as measured by the particle. [7 marks] M

Answers

(A) Circular orbits of stable particles are possible at radii greater than three times the Schwarzschild radius for the non-rotating spherically symmetric mass.

This represents the radius of a black hole's event horizon, within which nothing can escape. The Schwarzschild radius is the event horizon radius of a black hole with mass M.

M can be calculated using the formula: r+ = 2Mwhere r+ is the radius of the event horizon.

(B)  1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ R. This is the required expression.

Tau is the proper time of the particle moving around a circular orbit. Hence, by making use of the formula given above:1/2 M -1/2 3M (²) ¹² (1-³) dT = R³ dt.

(C) Time passes differently in different gravitational fields, and it follows that the period as measured at infinity should be larger than that measured by the particle.

The principle of equivalence can be defined as the connection between gravitational forces and the forces we observe in non-inertial frames of reference. It's basically the idea that an accelerating reference frame feels identical to a gravitational force.

(D) The period of the orbit as measured by an observer at infinity is 16π M^(1/2) and the period of the orbit as measured by the particle is 16π M^(1/2)(1 + 9/64 M²).

The period of orbit as measured by an observer at infinity can be calculated using the formula: T = 2π R³/2/√(M). Substitute the given values in the above formula: T = 2π (8M)³/2/√(M)= 16π M^(1/2).The period of the orbit as measured by the particle can be calculated using the formula: T = 2π R/√(1-3M/R).

Substitute the given values in the above formula: T = 2π (8M)/√(1-3M/(8M))= 16π M^(1/2)(1 + 9/64 M²).

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Sketch the following and then find the sum of the vertex
angles.
a. A hexagon
b. An octagon
c. A dodecagon.

Answers

To find the sum of the vertex angles in various polygons, we need to sketch the polygons and then calculate the sum. For a hexagon, octagon, and dodecagon, the sums of the vertex angles are 720°, 1,080°, and 1,800°, respectively.

a. Hexagon: A hexagon is a polygon with six sides. To find the sum of the vertex angles, we can divide the hexagon into triangles. Since each triangle has an interior angle sum of 180°, the hexagon can be divided into four triangles. Therefore, the sum of the vertex angles in a hexagon is 4 * 180° = 720°.

b. Octagon: An octagon is a polygon with eight sides. Similar to the hexagon, we can divide the octagon into triangles. Dividing it into six triangles, each with an interior angle sum of 180°, the sum of the vertex angles in an octagon is 6 * 180° = 1,080°.

c. Dodecagon: A dodecagon is a polygon with twelve sides. Dividing it into ten triangles, each with an interior angle sum of 180°, the sum of the vertex angles in a dodecagon is 10 * 180° = 1,800°.

Therefore, the sum of the vertex angles in a hexagon is 720°, in an octagon is 1,080°, and in a dodecagon is 1,800°.

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Find the sum of the vertex angles of the following polygons---

a. A hexagon

b. An octagon

c. A dodecagon.

10) Seven people sit in a circle and begin counting clockwise starting from 1.Each person in the group is keeping track of the numbers she is saying (e.g. 1,8, 15...) If they continue in this way, counting on and on, until they reach 1000, which person will get to say the last number

Answers

The person who gets to say the last number, 1000, will be Person 6.

In this scenario, we have seven people sitting in a circle and counting clockwise. The goal is to determine which person will say the last number when they reach 1000. To solve this problem, we can use the concept of modular arithmetic.

When dividing 1000 by the total number of people (7), we get a quotient of 142 and a remainder of 6 (1000 = 142*7 + 6). This means that after completing 142 full rounds of counting, the group will have reached the number 994 (142*7). In the next round, they will continue counting from 995 to 1000.

Since the remainder is 6, it indicates that the last number (1000) will be spoken by the person sitting 6 positions after the first person in the circle (clockwise). In other words, Person 1 says numbers 1, 8, 15, and so on, while Person 6 will say 6, 13, 20, and so on.


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the 3px, 3py, and 3pz orbitals look the same, but they point in different directions. T/F?

Answers

True. The 3px, 3py, and 3pz orbitals are similar in shape but differ in their orientation or direction.

The p orbitals are one type of orbital that corresponds to the angular momentum number l = 1. These p orbitals are designated as 3px, 3py, and 3pz to indicate their orientations along the x, y, and z axes, respectively.

The p orbitals have a  shape with a node at the nucleus. They consist of two lobes of electron density, one on either side of the nucleus, separated by a region of zero electron density. The lobes are oriented along the designated axes. The 3px orbital points along the x-axis, the 3py orbital points along the y-axis, and the 3pz orbital points along the z-axis. Although they have different orientations, their shapes and sizes are the same.

So, while the 3px, 3py, and 3pz orbitals differ in their orientation in space, they share the same overall shape and size.

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Plss help !!!!!!!!!!!!!!!!

Plss help !!!!!!!!!!!!!!!!

Answers

Answer: C (324)

Step-by-step explanation:

He is making $54 a day working 6 hours a day. 54 x 6 = 324 meaning in 6 days he would make $324.

Answer:

C. 324 thats the answer my cousin solved this

How many solutions does this equation have? d − 3 = –3 + d

Answers

It has an infinite amount of solutions.

Explanation:
d-3 = -3+d which can be arranged as: d-3=d-3
Since they are equal to each other, no matter what number you input, your solution will be the same which means that there are an infinite amount of solutions. Let’s put this to the test and put in 5 for d. 5-3=5-3 is 2=2. They are equal to each other which means: infinite solution.
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