the mean number of words per minute (wpm) read by sixth graders is 89 with a standard deviation of 16 wpm. if 66 sixth graders are randomly selected, what is the probability that the sample mean would be greater than 92.25 wpm?
If 66 sixth graders are randomly selected, the probability that the sample mean would be greater than 92.25 wpm is approximately 0.2142 or 21.42%.
If the sample size is sufficient, we can apply the theorem of central limitation to determine the pattern of distribution of sample means. Since n = 66 is a big enough number in this situation, we may use a normal distribution to roughly comparable the distribution of the sample means.
The general population's mean, which is 89 wpm, is the same as the mean value of the sample means. The following formula can be used to identify the average deviation of the sample means, commonly referred to as the standard deviation or error of the mean:
Standard error is equal to standard deviation squared.(sample size) Standard deviation: 16 squared(66) standard deviation: 1.969 Using the following formula, we can now standardise the sample mean: The formula for z is (sample mean - population mean) / standard error. z = (92.25 - 89) / 1.969 z = 1.732
We may determine the probability when a standard normal random variable is greater than 1.732 using the standard normal distribution table or calculator. This likelihood is roughly 0.0429, or 4.29%. we must remember that rather than just looking for any random variable, we are seeking for the probability that a sample mean is higher than 92.25 wpm. As a result, we must use the sample mean distribution, which we roughly categorized as a normal distribution.
The z-score must then be converted using the following formula to its original units of measurement: Sample mean equals population mean plus z times the standard error. 89 + 1.732 * 1.969 is the sample mean.
92.25 is the sample mean.
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Will Mark Brainliest!!! Name the property illustrated.
Answer:
5) distributive property
7) Transitive property
8) Associative property
Step-by-step explanation:
The lengths of pregnancies in a small rural village are normally distributed with a mean of 266 days and a standard deviation of 12 days. What percentage of pregnancies last beyond 267 days? P(X>267 days = % Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. A distribution of values is normal with a mean of 96.7 and a standard deviation of 56.5. Find P51. which is the score separating the bottom 51% from the top 49%. PS1= Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact x-score or 2 -scores rounded to 3 decimal places are accepted.
The percentage of pregnancies that last beyond 267 days is approximately 15.9%. The score separating the bottom 51% from the top 49% is approximately 96.7.
To find the percentage of pregnancies that last beyond 267 days, we need to calculate the area under the normal distribution curve to the right of 267. Using the given mean (266 days) and standard deviation (12 days), we can calculate the z-score for 267 as\((267 - 266) / 12\) ≈ 0.083. By referring to the standard normal distribution table or using a calculator, we find that the area to the right of 0.083 (or z > 0.083) is approximately 15.9%. Therefore, the percentage of pregnancies that last beyond 267 days is approximately 15.9%.
For the second question, we are given a normal distribution with a mean of 96.7 and a standard deviation of 56.5. We are asked to find the score separating the bottom 51% from the top 49%. This corresponds to finding the value x such that P(X < x) = 0.51. By using the z-score formula (z = (x - mean) / standard deviation), we can find the corresponding z-score. Substituting the given values, we have\((x - 96.7) / 56.5 = 0.51.\)Solving for x, we find x ≈ \((0.51 * 56.5) + 96.7\) ≈ 123.15. Therefore, the score separating the bottom 51% from the top 49% is approximately 123.1.
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The weight, y, in pounds, of kittens was tracked for the first 8 weeks after birth where t represents the number of weeks after birth. The linear model representing this relationship is ŷ = 1. 7 + 1. 48t. Statler wanted to predict the weight of a kitten at 10 weeks. What is this an example of, and is this method a best practice for prediction?
While linear regression can be a useful tool for prediction, it is important to consider the quality of the data, assess the linearity assumption, and be cautious when extrapolating beyond the observed data range.
This is an example of using linear regression to predict the weight of a kitten at a specific time (10 weeks in this case) based on the given linear model ŷ = 1.7 + 1.48t.
Using linear regression to make predictions is a common practice and can provide reasonable estimates in many cases. However, whether it is considered a best practice for prediction depends on various factors. Here are a few considerations:
Data quality: The accuracy and reliability of the predictions heavily depend on the quality of the data used to build the linear model. If the data used for training the model is representative and accurately reflects the underlying relationship, the predictions are likely to be more reliable.
Linearity assumption: Linear regression assumes a linear relationship between the predictor variable (in this case, time) and the response variable (kitten weight). If the relationship is not truly linear, the predictions may be less accurate. It is important to assess the linearity assumption and consider alternative models if needed.
Extrapolation: When making predictions outside the range of the observed data (such as predicting the weight at 10 weeks when the data only goes up to 8 weeks), caution should be exercised. Extrapolating beyond the observed range can introduce more uncertainty and may lead to less accurate predictions.
In summary, while linear regression can be a useful tool for prediction, it is important to consider the quality of the data, assess the linearity assumption, and be cautious when extrapolating beyond the observed data range.
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A triangle has interior angles of (x+5) (x-5) and (2x) what is the measure of the largest interior angle?
Answer:
90
Step-by-step explanation:
interior angles of all triangles add up to 180 degrees
180=x+5+x-5+2x
180=4x
45=x
plug back in to find largest angle
2 (45) = 90
sehn ullum
can u guess what that means?
Answer:
nope
Step-by-step explanation:
blah blah blah blah
What is 4.8 as a decimal in it’s simplest term?
Answer:
it is 4.8
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
HELP ILL GIVE U A LOT OF POINTS
Answer/Step-by-step explanation:
f(6) = 3x² - 5
f(6) = 3(6)² - 5
f(6) = 3(36) - 5
f(6) = 108 - 5
f(6) = 103
(x, y) = (6, 103)
I hope this helps!
Find a unit vector that has the same direction as the given vector. ⟨32,−24⟩ What is the angle between the given voctor and the positive direction of the x-axis? (Round your arnswar to the nearest degred.) 20i+15j X 0
The unit vector has the same direction as the given vector, and the angle between the given vector and the positive direction of the x-axis is approximately 37°.
Given vector is, ⟨32,−24⟩We need to find the unit vector with the same direction as the given vector. Since the unit vector has a magnitude equal to 1, we can find it by dividing the given vector by its magnitude. The magnitude of the given vector is:
|⟨32,−24⟩| = √(32² + (-24)²)|⟨32,−24⟩|
= √(1024 + 576)|⟨32,−24⟩|
= √1600|⟨32,−24⟩|
= 40
Unit vector is: ⟨32,−24⟩/40 = ⟨8/5,-3/5⟩
Therefore, the unit vector with the same direction as the given vector is ⟨8/5,-3/5⟩. Now, we have to find the angle between the given vector and the positive direction of the x-axis. To find the angle between the vector and the positive direction of the x-axis, we need to find the dot product of the given vector with the unit vector in the positive x-axis direction. The unit vector in the positive direction of the x-axis is ⟨1,0⟩.
Dot product of vectors ⟨20,15⟩ and ⟨1,0⟩ is:
= ⟨20,15⟩.⟨1,0⟩
= (20*1) + (15*0)⟨20,15⟩.⟨1,0⟩
= 20Cosθ
= a.b/|a||b|Cosθ
= 20/25Cosθ
= 0.8θ
= Cos-1(0.8)θ
= 36.869898°
θ ≈ 37° (Nearest degree)
Therefore, the angle between the given vector and the positive direction of the x-axis is approximately 37°. Therefore, we have found the unit vector with the same direction as the given vector, and the angle between the given vector and the positive direction of the x-axis is approximately 37°.
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Graph the function with the given domain. Classify the function as discrete or continuous. Then identify the range of the function.
The graph of the function is given below.
The function is a continuous function.
The range of the function is 4, 5, 6, 7, and 8.
What is a function?A function is a relationship between inputs where each input is related to exactly one output.
Example:
f(x) = 2x + 1
f(1) = 2 + 1 = 3
f(2) = 2 x 2 + 1 = 4 + 1 = 5
The outputs of the functions are 3 and 5
The inputs of the function are 1 and 2.
We have,
y = -(1/2)x + 6
Domains = -4, -2, 0, 2, 4
Now,
y = f(x)
f(x) = -(1/2)x + 6
For x = -4, -2, 0, 2, 4
f(-4) = -(1/2) x -4 + 6 = 2 + 6 = 8
f(-2) = -(1/2) x -2 + 6 = 1 + 6 = 7
f(0) = -(1/2) x 0 + 6 = 0 + 6 = 6
f(2) = -(1/2) x 2 + 6 = - 1 + 6 = 5
f(4) = -(1/2) x 4 + 6 = - 2 + 6 = 4
The range of the function is 4, 5, 6, 7, and 8.
Thus,
The graph of the function is a straight line.
So,
The function is a continuous function.
The range of the function is 4, 5, 6, 7, and 8.
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Which value is the best estimate of 26% of 259?
Answer:
67.34 is 26% of 259
Step-by-step explanation:
.................
19 less than one-half a number is-13
Answer:
Step-by-step explanation:
You are looking for 1/2 of an unknown number minus 19. It will equal -13.
1/2x - 19 = -13
Get x isolated, so add 19 on left to cancel, then add on right) +19 +19
And you now are down to 1/2 x = 6
Now, let's simplify the fraction (1/2). Since it is 1 divided by 2, you reverse division with multiplication. Multiply 1/2 by the denominator (2) and you get 1. So, you're down to 1x, or just x. Then multiply the number on the other side of the equal sign (the 6) by 2 and you get 12.
So x = 12.
Now, let's go back to our original equation and plug in the x and see if it works.
1/2x - 19 = -13
becomes 1/2 (12) - 19 = -13
becomes 6 - 19 = -13
Voila! Our missing number (x) is 12.
Discrete impulse response: Simplify the following expression (your answer should use the step function, but not the summation): y[n] = a[m]d[m + 3n] m=0
The expression \(y[n] = \Sigma_{m=0}^\infty x[m]\delta[m + 3n]\) represents the output of a system when the input is x[n] and the impulse response is \(h[n] = \delta[n+3]\), which is an impulse shifted to the left by 3 units.
To simplify this expression, we can first consider the Dirac delta function \(\delta[m + 3n]\) in the expression. The Dirac delta function is zero for all values of m, except when m = -3n. Therefore, we can rewrite the expression as:
y[n] = x[-3n] for n = 0, ±1, ±2, ...
y[n] = 0 otherwise
However, the original expression has a summation from m = 0 to infinity, which means that it includes the term \(x[0]\delta[3n]\). But, since the Dirac delta function is zero for all values of n, except when n is zero and the argument of the Dirac delta function is also zero, which happens when m = 0, the expression becomes:
y[0] = x[0]u[0], where u[0] is the unit step function that is 1 for n ≥ 0
For all other values of n, the output y[n] is zero, because the Dirac delta function is zero for all values of m, except when m = -3n.
Therefore, we can simplify the expression \(y[n] = \Sigma_{m=0}^\infty x[m]\delta[m + 3n]\) as:
y[n] = x[0]u[0] for n = 0
y[n] = 0 otherwise
And we can rewrite this expression using the step function u[n] as:
y[n] = x[0]u[n] for n ≥ 0
y[n] = 0 for n < 0
So, the output of the system when the input is x[n] and the impulse response is \(h[n] = \delta[n+3]\) the input signal x[n] multiplied by a delayed unit step function.
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Suppose grades on a business statistics exam are adequately described by a normal distribution with mean 76 and standard deviation of 6. If a professor decides to give As to those who scored 90 and above and Fs to those who scored 60 and below, what proportion of As and Fs combined would the professor be assigning. Indicate the interval below that contains this proportion i) .2000 to .2499 ii) 0.1500 to .1999 iii) .0000 to .0999 iv) .1000 to 1.499 v) .2500 to 1.000
The normal distribution with a mean of 76 and a standard deviation of 6 describes the grades on a business statistics exam. The proportion of students scoring between 90 and above (A) and 60 and below (F) is 0.0136, which falls within the interval of 0.0000 to 0.0999.
In the given context, the normal distribution refers to the statistical distribution that adequately describes the grades on a business statistics exam. It is assumed that the grades follow a normal distribution with a mean of 76 and a standard deviation of 6.
The normal distribution, also known as the Gaussian distribution or bell curve, is a continuous probability distribution characterized by a symmetric bell-shaped curve. It is widely used in statistics and probability theory due to its mathematical properties and its applicability to many real-world phenomena.
The formula for standardizing a normal variable Z is:
Z=frac{x-mu}{sigma}, where x is the raw score, μ is the mean, and σ is the standard deviation.
The proportion of grades who scored an A (90 and above) and F (60 and below) can be calculated as follows:
First, we will find the Z-score of grade 90:
Z=frac{x-mu}{sigma}=frac{90-76}{6}=2.33.
Now, we need to find the proportion of students who scored 90 and above:
P(Zge2.33)=0.0099.
Therefore, a 0.0099 proportion of students scored 90 and above.
Next, we will find the Z-score of grade 60:
Z=frac{x-mu}{sigma}=frac{60-76}{6}=-2.67.
Now, we need to find the proportion of students who scored 60 and below:
P(Zle-2.67)=0.0037.
Therefore, 0.0037 proportion of students scored 60 and below.
The proportion of students who scored between A (90 and above) and F (60 and below) is $0.0099 + 0.0037 = 0.0136.
Therefore, the professor will be assigning the proportion of 0.0136.
The interval that contains this proportion is option iii) 0.0000 to 0.0999.
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6t+4<-2 solve the inequality
Solve and classify the intersection :
x+2y+3z+4=0
x-y-3z-8 =0
x+5y+9z+16=0
The intersection is the line that passes through the points (8, -4, 0) and (12, -6, 1).
There are different methods to solve these systems of equations. One of the easiest methods is the Gaussian elimination method. Here's a solution to the given system of equations using Gaussian elimination method; Write the given system of equations in matrix form as;|1 2 3 | -4||1 -1 -3 | 8||1 5 9 | -16|The augmented matrix is written as follows;|1 2 3 -4|1 -1 -3 8|1 5 9 -16|Apply R1 = R1 - R2 and R3 = R3 - R1;|1 2 3 -4|1 -1 -3 8|0 3 6 -12|
Apply R2 = R2 - R1 and R3 = R3 - 3R2;|1 2 3 -4|0 -3 -6 12|0 0 0 0|From this form, we can deduce that;x + 2y + 3z = 4 ......(4)-3y - 6z = 12 ......(5)By simplifying equation (5);-y - 2z = 4 ..........(6)Substitute equation (6) into equation (4);x + 2y + 3z = 4x + 2(-2z - 4) + 3z = 4x - 4z - 8 = 0x = 4z + 8 ..........(7)Therefore the solution to the system of equations (1), (2), and (3) is;x = 4z + 8y = -2z - 4z = z Where z is any real number.
The solution is an infinite set of points lying on a line. Let's find two points on the line. Let z = 0 then;x = 8 y = -4 z = 0Then, the first point is (8, -4, 0)Let z = 1 then;x = 12 y = -6 z = 1Then, the second point is (12, -6, 1)Finally, the intersection is the line that passes through the points (8, -4, 0) and (12, -6, 1).
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Solve for x. Figures are not necessarily drawn to scale.
Check the picture below.
\(\cfrac{x}{10}=\cfrac{24.5}{14}\implies x=\cfrac{(10)(24.5)}{14}\implies x=\cfrac{245}{14}\implies x=17.5\)
giving brainliest help
Answer:
The first one
Step-by-step explanation:
18sses MULTIPLE CHOICE QUESTION If the total number of question is 10, how many she need to answer correctly to have an A
Answer:
Maybe 10
Step-by-step explanation:
The bears in Alaska are limited to a certain area to live due to the resources available for
food and shelter. After years, the number of bears living in the area is modeled by the function below. Using the function, find the number of bears after 17 years.
The number of bears living in the area after 17 years is; 22555
How to solve exponential functions?We are given the function;
f(t) = 103/(1 + 26e^(-0.31t))
Where f(t) is a function that models the number of bears living in the area after t period of years.
Thus, to find the number of bears living in the area after 17 years, we will just substitute 17 for t in the given function to get;
f(17) = 103/(1 + 26e^(-0.31*17))
f(17) = 103/0.00456653759
f(17) ≈ 22555 bears
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1.
What is the measure of one interior angle of a regular nonagon?
2. How many sides does a regular n-gon have if the measure of
one interior angle is 165?
3. The expressions -2x + 41 and 7x - 40 re
The measure of one interior angle of a regular nonagon (a polygon with nine sides) can be found using the formula: (n-2) * 180° / n, where n represents the number of sides of the polygon.
Applying this formula to a nonagon, we have (9-2) * 180° / 9 = 140°. Therefore, each interior angle of a regular nonagon measures 140°.
To determine the number of sides in a regular polygon (n-gon) when the measure of one interior angle is given, we can use the formula: n = 360° / x, where x represents the measure of one interior angle. Applying this formula to a given interior angle of 165°, we have n = 360° / 165° ≈ 2.18. Since the number of sides must be a whole number, we round the result down to 2. Hence, a regular polygon with an interior angle measuring 165° has two sides, which is essentially a line segment.
The expressions -2x + 41 and 7x - 40 represent algebraic expressions involving the variable x. These expressions can be simplified or evaluated further depending on the context or purpose.
The expression -2x + 41 represents a linear equation where the coefficient of x is -2 and the constant term is 41. It can be simplified or manipulated by combining like terms or solving for x depending on the given conditions or problem.
The expression 7x - 40 also represents a linear equation where the coefficient of x is 7 and the constant term is -40. Similar to the previous expression, it can be simplified, solved, or used in various mathematical operations based on the specific requirements of the problem at hand.
In summary, the expressions -2x + 41 and 7x - 40 are algebraic expressions involving the variable x. They can be simplified, solved, or used in mathematical operations based on the specific problem or context in which they are presented.
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The Excel file Automobile Options provides data on options ordered together for a particular model of automobile. By examining the correlation matrix, suggest some associations.
You must count the instances of each rule and the instances of each item in each rule separately using the data in the Excel file in order to determine the support, confidence, and lift of a rule.
Open the Excel file and look for the information on the options ordered for the specific model of car. This information will probably be presented as a table or a group of columns, where each row represents a distinct order and each column a different choice.
You must count the instances of the rule's components occurring together in the data in order to calculate the support for a rule. You would need to track how frequently the fastest engine choice and the traction control option are selected together, for instance, if the rule is "If the quickest engine, then traction control." This can be accomplished by counting the number of cells in a range that satisfy a specific condition using Excel's COUNTIF function.
The confidence in a rule is calculated by dividing the total number of times the items in the premise (the "if" component of the rule) occur by the total number of times the items in the rule. The number of times the fastest engine and traction control options are selected together must be divided by the total number of times the fastest engine option is ordered, for instance, if the rule is "If the fastest engine, then traction control."
You must divide the rule's confidence by the support of the item in the rule's conclusion to determine the lift of a rule (the "then" part of the rule). You would need to divide the rule's confidence by the support for the traction control option, for instance, if the rule is "If the quickest engine, then traction control."
To calculate the support, confidence, and lift for each of the rules, you can use the Excel formulas indicated above together with any other Excel functions or tools you are familiar with.
It is crucial to keep in mind that the precise formulas and processes you will need to follow will depend on the exact data and rules you are working with, so you might need to modify the following instructions to suit your personal needs.
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Put these number in order of size, smallest to largest:
4.5 , -1 , -3 , -3.5 , 3
5 stars to the first person to answer the question!!Who can do it?(i wonder)??
Answer:
-3.5, -3, -1, 3, 4.5
Suppose the scores , x, on a college entrance examination is normally distributed with mean 550 and a standard deviation of 100. George mason university will consider for admission only applicants whose scores exceed the 90th percentile of the distribution. Find the minimum score an applicant must achieve in order to receive consideration for admission to the university.
The probability , 678 is the minimum score an applicant must achieve in order to receive consideration for admission to the university.
What is probability very short answer?
Probability refers to potential. The subject of this area of mathematics is the occurrence of random events. The range of the value is 0 to 1. To forecast how likely events are to occur, probability has been introduced in mathematics.We know that X is normally distributed , with parameters
μ = 550 σ = 100
the corresponding cumulative normal probability is equal to 0.90,
x is such that
P( Z ≤ x - μ/σ ) = 0.90
the corresponding critical value so that the cumulative standard normal probability distribution is 0.90
Zc = 1.2816
Therefore, the X- Score associated with the 0.90 cumulative probability is
x = μ + Zc * σ
= 678
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For 23 years, Janet saved $1,150 at the beginning of every month in a fund that earned 3.25% compounded annually. a. What was the balance in the fund at the end of the period? Round to the nearest cent Round to the nearest cent b. What was the amount of interest earned over the period?
The balance in the fund at the end of 23 years, with monthly deposits of $1,150 and a 3.25% annual interest rate, is approximately $449,069.51. The amount of interest earned over the period is approximately $420,630.49.
a. The balance in the fund at the end of the 23-year period, considering a monthly deposit of $1,150 and an annual interest rate of 3.25% compounded annually, is approximately $449,069.51.
To calculate the balance, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where A is the accumulated balance, P is the monthly deposit, r is the annual interest rate, n is the number of compounding periods per year, and t is the number of years.
In this case, we have monthly deposits, so we need to convert the annual interest rate to a monthly rate:
Monthly interest rate = (1 + 0.0325)^(1/12) - 1 = 0.002683
Using this monthly interest rate, we can calculate the accumulated balance over the 23-year period:
A = 1150 * [(1 + 0.002683)^(12*23) - 1] / 0.002683 = $449,069.51
Therefore, the balance in the fund at the end of the 23-year period is approximately $449,069.51.
b. The amount of interest earned over the 23-year period can be calculated by subtracting the total deposits from the accumulated balance:
Interest earned = (Monthly deposit * Number of months * Number of years) - Accumulated balance
Interest earned = (1150 * 12 * 23) - 449069.51 = $420,630.49
Therefore, the amount of interest earned over the 23-year period is approximately $420,630.49.
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The equation for a circle is x2−8x+y2−2y−8=0 .
What is the equation of the circle in standard form?
Responses
(x−16)2+(y−1)2=25
open parenthesis x minus 16 close parenthesis squared plus open parenthesis y minus 1 close parenthesis squared equals 25
(x−4)2+(y−1)2=16
open parenthesis x minus 4 close parenthesis squared plus open parenthesis y minus 1 close parenthesis squared equals 16
(x−16)2+(y−1)2=16
open parenthesis x minus 16 close parentheses squared plus open parenthesis y minus 1 close parenthesis squared equals 16
(x−4)2+(y−1)2=25
The equation of this circle in standard form is: D. (x - 4)² + (y - 1)² = 25.
What is the equation of a circle?In Geometry, the standard form of the equation of a circle is modeled by this mathematical equation;
(x - h)² + (y - k)² = r²
Where:
h and k represent the coordinates at the center of a circle.r represent the radius of a circle.From the information provided above, we have the following equation of a circle:
x² - 8x + y² - 2y - 8 = 0
x² - 8x + y² - 2y = 8
x² - 8x + (-8/2)² + y² - 2y + (-2/2)² = 8 + (-8/2)² + (-2/2)²
x² - 8x + 16 + y² - 2y + 1 = 8 + 16 + 1
(x - 4)² + (y - 1)² = 25
(x - 4)² + (y - 1)² = 25
Therefore, the center (h, k) is (4, 1) and the radius is equal to 5 units.
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I’m confused on what number 4 means. Can someone please help?
Answer:I think you can say like the most bought music in class B is alternative and the lowest one is classical and so on
Step-by-step explanation:
Debra has two different square baking dishes.one has a side length of 8 inches, and the other has a side length of 9 inches. what is the difference in the area of Debra's two square baking dishes?
Debra's two area baking plates are 17 square inches different in size.
What distinguishes an area from a perimeter?The area surrounding a shape forms its perimeter. Area is a unit of measurement for interior space. Surface area is a measurement of a solid shape's exposed surface, whereas area is a two-dimensional measurement of the size of a flat surface (three-dimensional).
The square baking dish has the following surface area with an 8-inch side length:
Area of first square = (side length)² = 8² = 64 square inches
Similarly, the surface area of a square baking dish with 9-inch sides is:
Area of second square = (side length)² = 9² = 81 square inches
Difference in area = |Area of second square - Area of first square|
Difference in area = |81 - 64|
Difference in area = 17 square inches
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how would 4,609, 912, 073 be written in word form?
Answer: four billion six hundred nine million nine hundred twelve thousand seventy three
Step-by-step explanation:
Answer: four trillion six hundred nine million nine hundred twelve hundred thousand seventy three
Step-by-step explanation:
Determine whether each relation is a function. Explain your reasoning
Using the Vertical line Test, the functions are a and d.
Given are graphs of certain relations.
We have to find whether the graph shown are function or not.
We can find whether an graph of a relation is a function or not by Vertical Line Test.
Vertical line test is done by drawing a line vertically through the graph and find the number of intersecting points of the line with the graph.
If the line intersects at exactly one points, then it is a function.
Otherwise, it is not a function.
a) If we draw a line at any point through the graph, it will only touch one point.
So it is a function.
b) If we draw a vertical line through the graph, it will touch two points for the curve except at the vertex point.
So it is not a function.
c) Circles are clearly not a function since any vertical line will touch two points.
d) Any vertical passes through exactly one point on the curve.
So this is a function.
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