The length of one edge of the cube is 2 feet long whose surface area is 24 ft sq.
What is surface area?Surface area is a measure of the total area that the surface of an object occupies. In geometry, it is the sum of the areas of all the faces or surfaces of a three-dimensional object
According to question:The surface area of a cube is given by the formula 6s², where s is the length of one edge of the cube.
We are given that the surface area of the cube is 24 ft², so we can set up the equation:
6s² = 24
Dividing both sides by 6 gives:
s² = 4
When you square the two sides, you get:
s = ±2
Since the length of a side cannot be negative, the only valid solution is:
s = 2
The cube's one edge is therefore 2 feet long.
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May I please have the correct answer please? I will give you whatever you want
what is the population being studied warts
The average population being studied is people with warts. Specifically, this population includes individuals of all ages who have been diagnosed with any type of wart caused by a virus, such as common warts, plantar warts, and flat warts.
The population being studied is people with warts. Warts are caused by a virus and can occur anywhere on the body. Common warts, plantar warts, and flat warts are the most common types. Common warts are usually found on the hands and fingers, and are usually round and raised. Plantar warts are found on the soles of the feet and can be painful. Flat warts are usually found on the face, arms, and legs, and are generally flat and smooth. People of all ages can be affected by warts, and they are highly contagious and can be spread through contact with an infected person or surface. Treatment options include over-the-counter medicines and prescription medications, as well as cryotherapy and laser treatments. This population is being studied to better understand the causes, risk factors, and treatments for warts.
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The complete question is
what is the population being studied warts and the prevalence of warts in the population being studied?
Please help me with my math yes or no question
Answer:
no
Step-by-step explanation:
you have a 10 mile one way distance to commute to work. the cost of your travel time is $60/hour. weather is not a factor. which mode should you use to commute?
Driving a personal car would be the most cost-effective mode of transportation for this commute, with a total daily cost of approximately $4.60 ($3.60 for gas + $1 for travel time).
Based on the given information, the most cost-effective mode of transportation for this commute would be to drive a personal car. Taking public transportation or carpooling may be more environmentally friendly options, but they may not save as much money as driving alone.
Assuming an average speed of 60 miles per hour on the highway, the commute would take approximately 20 minutes each way, or 40 minutes round-trip. This means the total cost of travel time for each workday would be $40 ($60/hour x 2/3 hour).
Using a cost calculator such as GasBuddy, we can estimate that the cost of driving 20 miles per day (round-trip) would be around $3.60 per day, assuming an average fuel efficiency of 25 miles per gallon and a gasoline price of $2.50 per gallon.
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Three charges (-25 nC, 79.1nC, and −55.9nC) are placed at three of the four corners of a square with sides of length 22.2 cm. What must be the value of the electric potential (in V) at the empty comer if the positive charge is placed in the opposite comer?
Given that three charges (-25 nC, 79.1nC, and −55.9nC) are placed at three of the four corners of a square with sides of length 22.2 cm. We need to determine the value of the electric potential (in V) at the empty comer if the positive charge is placed in the opposite corner.
The formula for the electric potential at a point in space is given by;V = k [ (q1 / r1) + (q2 / r2) + (q3 / r3) + ….. ]where;k = Coulomb's constant (8.99 × 10^9 Nm²/C²)q1, q2, q3,…. are the charges at the cornersr1, r2, r3,…. are the distances from the corner to the point whose potential is being calculated Now we can calculate the electric potential at the empty corner as follows;The three charges can be represented as shown below:Charges at corners of a square
The distance from any corner to the opposite corner (where the positive charge is placed) is given by d = √[ (22.2 cm)² + (22.2 cm)² ] = 31.4 cmTherefore, the electric potential at the empty corner is given by;V = k [ (q1 / r1) + (q2 / r2) + (q3 / r3) ]Here, q1 = -25 nC, q2 = -55.9 nC, q3 = 79.1 nC, r1 = r2 = r3 = d = 31.4 cm = 0.314 mPlugging in the values we get;V = 8.99 × 10^9 [ (-25 × 10^-9 / 0.314) + (-55.9 × 10^-9 / 0.314) + (79.1 × 10^-9 / 0.314) ]= 8.99 × 10^9 [ -0.0795 - 0.1783 + 0.252 ]= 8.99 × 10^9 × 0.0052= 46.8 VTherefore, the value of the electric potential at the empty comer if the positive charge is placed in the opposite comer is 46.8 V.
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How do I rewrite a mixed fraction as a sum?
Answer:
turn it into a decimal first
Step-by-step explanation:
Find the quotient of (25/1)
-5/3
Relevant work
I need this fast pls
tener senderos 2 preliminary look at the drawings and describe these people using an expression with tener
These expressions with "tener" can help you describe the people in the drawings based on their physical attributes or emotions.
To describe these people by having a preliminary look at the drawings using an expression with "tener," you can focus on their physical or emotional characteristics. For example, you can say:
1. "Tienen el pelo largo" (They have long hair)
2. "Tienen los ojos azules" (They have blue eyes)
3. "Tienen una sonrisa radiante" (They have a radiant smile)
4. "Tienen una mirada triste" (They have a sad look)
5. "Tienen mucha energía" (They have a lot of energy)
These expressions with "tener" can help you describe the people in the drawings based on their physical attributes or emotions.
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Exponential growth followed by a steady decrease in population growth until the population size stabilizes due to limiting environmental factors is typical of ____.
The phenomenon described, characterized by exponential growth followed by a steady decrease in population growth until stabilization, is typical of logistic growth.
Logistic growth is a concept often observed in biological populations, where the population initially experiences rapid growth due to abundant resources and favorable conditions. During this initial phase, the population size increases exponentially. However, as the population grows larger, it begins to face limiting factors such as limited food supply, competition for resources, predation, disease, and limited habitat. These factors impose constraints on the population's growth rate.
As the population approaches its carrying capacity, which is the maximum population size that the environment can sustain, the growth rate starts to decline. The population growth rate becomes more gradual until it eventually reaches zero, resulting in a stable population size. This leveling off of population growth is due to the balance between birth rates and death rates, as well as the availability of resources. In logistic growth, the population reaches an equilibrium point where it remains relatively stable over time.
The logistic growth model provides a more realistic representation of population dynamics compared to simple exponential growth models. It accounts for the influence of limiting factors on population growth and helps explain the patterns observed in many natural populations.
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can I get help with some algebra polynomial in standard form
Step-by-step explanation:
Standard form :
1. = x⁴ - 2x² + 3
2. = 5m³ - 3m² + 9m - 7
hope this will be helpful for you and plzzz mark my answer as brainlist plzzzz vote me also....
can anyone please help!!!
Answer:
Question 9
(a) The distance, Jalaj walks in one day is 4.4 km
(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8
Question 10
(b) The difference between the largest and smallest areas is 2,400 m²
Step-by-step explanation:
Question 9
(a) The distance Jalaj walks in 5 days = 22 km
Whereby Jalaj walks equal distance every day, we have;
The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day
The distance, Jalaj walks in one day = 4.4 km
(b) The amount he raises for every kilometer he walks = $1.60
The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60 = $8
Question 10
(b) The given side length of the square = 120 meters to the nearest 10 meters
Therefore;
The maximum dimension for the side length of the square = 120 + 10/2 = 125
The largest possible area of the square, \(A_l\) = 125 m × 125 m = 15,625 m²
The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m
The smallest possible area of the square, \(A_s\) = 115 m × 115 m = 13,225 m².
The difference between the largest and smallest areas, \(A_l\) - \(A_s\) = 15,625 - 13,225 = 2,400 m².
Let θ be an angle in quadrant II such that cos θ = −7/10
.
Find the exact values of csc θ and tan θ
Exact values of csc θ=10/\(\sqrt{51}\) and tan θ= \(-\sqrt{5}/7\)
Let θ be an angle in quadrant II such that cos θ = −7/10.
\((sinx^)^2 +(cosx)^2=1\)
sin θ =\(\sqrt{51/100}\)
cscθ=1/sinθ
cscθ=10/\(\sqrt{51}\)
tanθ=sinθ/cosθ
tanθ= \(-\sqrt{5}/7\)
Exact values of csc θ=10/\(\sqrt{51}\) and tan θ= \(-\sqrt{5}/7\).
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The amount of gasoline purchased per car at a large service station is normally distributed with the mean of $47 and a standard deviation of $5. A random sample of 47 is selected, describe the sampling distribution for the sample mean.
The sampling distribution for the sample mean will be normally distributed with a mean of $47 and a standard deviation of approximately $0.73.
The sampling distribution for the sample mean in this scenario would also be normally distributed, with a mean of $47 (the same as the population means) and a standard deviation of $5/sqrt(47) (the standard error of the mean).
This means that if we were to take multiple random samples of size 47 from this population, the means of each sample would be normally distributed around $47, and the spread of the means would be smaller than the spread of the individual amounts purchased due to the central limit theorem.
Given that the amount of gasoline purchased per car at a large service station is normally distributed with a mean of $47 and a standard deviation of $5, and you have a random sample of 47 cars, we can describe the sampling distribution for the sample mean using the following information:
1. The shape of the sampling distribution: Since the original population is normally distributed, the sampling distribution of the sample mean will also be normally distributed according to the Central Limit Theorem.
2. The mean of the sampling distribution (μ_X): The mean of the sampling distribution will be equal to the mean of the population, which is $47.
3. The standard deviation of the sampling distribution (σ_X): To find the standard deviation of the sampling distribution, we need to divide the population standard deviation (σ) by the square root of the sample size (n). In this case, σ = $5 and n = 47.
σ_X = σ / √n = 5 / √47 ≈ 0.73
So, the sampling distribution for the sample mean will be normally distributed with a mean of $47 and a standard deviation of approximately $0.73.
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if f(x) = 3 - x^2, find f(-2)
Based on the function f(x) = 3 - x², the value of f(-2) include the following: f(-2) = -1.
What is a function?In Mathematics and Geometry, a function can be defined as a mathematical expression which is typically used for defining and representing the relationship that exists between two or more variables such as an ordered pair in tables or relations.
What is a domain?In Mathematics and Geometry, a domain is sometimes referred to as input value and it can be defined as the set of all real numbers for which a particular function is defined.
When the domain (input value) of the given function f(x) is -2, the output value (range) is given by;
f(x) = 3 - x²
f(x) = 3 - (-2)²
f(x) = 3 - 4
f(x) = -1
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A bottle of Gatorade costs $1, and a
box of cookies cost $2. If you have a
budget to spend on these items of $12,
what is the optimal amount of each
product to buy to maximize your utility?
To maximize utility, the optimal amounts of Gatorade and cookies you can buy are:
Gatorade = 4Cookies = 4.How are the optimal amounts determined?The optimal amount of each product to buy to maximize utility is determined using an equation.
An equation is a mathematical statement of the equality of two or more mathematical expressions.
The cost of a bottle of Gatorade = $1
The cost of a box of cookies = $2
The total spending budget = $12
Let the number of bottles of Gatorade and boxes of cookies = x
Equation:x + 2x = 12
3x = 12
x = 4
Thus, to maximize utility, you can buy 4 bottles of Gatorade and 4 boxes of cookies without exceeding your budget of $12.
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I think I’m in love with you :) need help with this ASAP
A well, whose diameter is 3 m, has been dug 21 m deep and the earth dug out is used to form an embankment 4 m wide around it. Find the height of the embankment.
Answer:
31.875 m
Step-by-step explanation:
We can begin solving the problem by using the formula for the volume of a cylinder and the volume of a cone.
The volume of the well is given by the formula for the volume of a cylinder:
V = πr^2h
where r is the radius of the well (half the diameter, which is 3/2 = 1.5 m) and h is the depth of the well (21 m).
V = π(1.5)^2(21) = 42.5π m^3
The embankment is formed by the earth that was dug out of the well, and it has the shape of a cone. The volume of the cone is given by the formula:
V = 1/3 πr^2h
where r is the radius of the base of the cone (4 m) and h is the height of the embankment.
V = 1/3π(4)^2h = 4/3πh m^3
Now we know that the volume of the embankment is equal to the volume of the well:
V = 42.5π m^3 = 4/3πh m^3
Then we can solve for h by dividing both sides by 4/3π:
h = 42.5π m^3 * 3/4π = 31.875 m
So the height of the embankment is 31.875 m.
What is the answer to the problem below
Answer:
\( 12 + 4\sqrt{6} \)
The result is irrational because \( \sqrt{6} \) is irrational.
Step-by-step explanation:
\( 3\sqrt{16} + 4\sqrt{6} = \)
\(= 3 \times 4 + 4\sqrt{6}\)
\( = 12 + 4\sqrt{6} \)
The result is irrational because \( \sqrt{6} \) is irrational.
Want MONEY answer this.
Answer:
2
Step-by-step explanation:
2 lines for each letter is the maximum.
They could be intersecting lines
What is the value of x in trapezoid ABCD?
x=15
x=20
x=45
X=60
Answer:
A. X = 15 is the correct answer.
Step-by-step explanation:
It's the only one that really makes sense.
Hope this helped :) :)
Answer:
15
Step-by-step explanation:
An angle x is chosen at random from the interval 0^0 < x < 90^0 Let p be the probability that the numbers sin^2 x, cos^2 x and sin x cos x are not the lengths of the sides of a triangle. Given that p = d/n where d is the number of degrees in arctan m and m and n are positive integers with m + n < 1000 find m + n.
Answer:
i don get it
Step-by-step explanation:
i stil don get it
Answer: 92
Step-by-step explanation:
Observe that the probability is symmetric around \(45^{\circ}\).
If \(0^{\circ} < x < 45^{\circ}\), then \(\cos^2 x > \cos x > \sin x\). By the triangle inequality, it follows that \(\cos^2 x > \sin^2 x+\sin x \cos x\).
We can now rearrange as follows:
\(\cos^2 x > \sin^2 x+\sin x \cos x\\\\\cos^2 x -\sin^2 x > \sin x \cos x\\\\\cos 2x > \frac{1}{2}\sin 2x\)
Since \(\cos 2x\) and \(\sin 2x\) are both positive for the chosen interval,
\(2 > \tan x \implies x < \frac{1}{2}\arctan 2\).
Therefore, the probability is \(\frac{\frac{1}{2} \arctan 2}{45}=\frac{\arctan 2}{90}\).
This means, \(m=2, n=90 \implies m+n=92\).
please answer this is due in 20 minutes !!!
Answer:
Non-Proportional
Hope this helps!
Take care!
Answer:
i think the answer is non- proportional
Step-by-step explanation:
In 1895 , the first a sporting event was held. The winner's prize money was $140. In 2007 , the winner's check was $1,171,000. (Do not round your intermediate calculations.) Required: (a)What was the percentage increase per year in the winner's check over this period? (b)If the winner's prize increases at the same rate, what will it be in 2040?
The percentage increase per year in the winner's check over the given period. If the winner's prize increases at the same rate, it will be $1,454,735,139.69 in 2040.
To calculate the percentage increase per year in the winner's check over the period from 1895 to 2007, we can use the following formula:
Percentage Increase = (Final Value - Initial Value) / Initial Value * 100
a. Calculating the percentage increase:
Initial Value = $140
Final Value = $1,171,000
Percentage Increase = (1,171,000 - 140) / 140 * 100 ≈ 835,714.29%
b. To estimate the winner's prize in 2040, we can assume the same annual percentage increase will continue. We need to calculate the number of years from 2007 to 2040 and apply the percentage increase to the 2007 prize.
Number of years = 2040 - 2007 = 33 years
Estimated prize in 2040 = 1,171,000 * (1 + (Percentage Increase / 100))^33
Estimated prize in 2040 = 1,171,000 * (1 + (835,714.29 / 100))^33 ≈ $1,454,735,139.69
Therefore, if the winner's prize increases at the same rate, it is estimated to be approximately $1,454,735,139.69 in 2040.
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A recent study in KZN showed that 50% of the cars traveling on highways were above the speed limit. A random sample of 9 cars on these highways is taken. Let X denote the number of speeding cars. What is the probability that the number of speeding cars is at least 9? (Rounded to 3 decimal places) What is the expected number of speeding cars, E[X]? (Rounded to one decimal place) What is the variance of the distribution of X? (Rounded to 1 decimal place) What is the standard deviation of the distribution of X? (Rounded to 1 decimal place) Suppose the average speeding fine per car is R2174. What is the expected fines generated by the next 9 cars?
Probability that the number of speeding cars is at least 9: 0.009 Expected number of speeding cars, E[X]: 4.5 Variance of the distribution of X: 2.25 Standard deviation of the distribution of X: 1.5 Expected fines generated by the next 9 cars: R19566.
To solve the given problem, we need to assume that the number of cars on the highways follows a binomial distribution with parameters n = 9 (number of trials) and p = 0.5 (probability of a car being above the speed limit).
Probability that the number of speeding cars is at least 9:
Since the probability of a car being above the speed limit is 0.5, the probability of a car not being above the speed limit is also 0.5.
To find the probability of having at least 9 speeding cars, we sum up the probabilities of having 9, 10, 11, ..., up to 9 cars. Mathematically, it can be represented as P(X ≥ 9) = P(X = 9) + P(X = 10) + P(X = 11) + ... + P(X = 9).
Using the binomial probability formula, P(X = k) = (n choose k) * p^k * (1 - p)^(n - k), we can calculate the probabilities for each value of k and then sum them up:
P(X ≥ 9) = P(X = 9) + P(X = 10) + P(X = 11) + ... + P(X = 9)
= [C(9, 9) * 0.5^9 * 0.5^(9 - 9)] + [C(9, 10) * 0.5^10 * 0.5^(9 - 10)] + [C(9, 11) * 0.5^11 * 0.5^(9 - 11)] + ...
Evaluating this expression, we find that P(X ≥ 9) ≈ 0.009 (rounded to 3 decimal places).
Expected number of speeding cars, E[X]:
The expected value of a binomial distribution is given by the formula E[X] = n * p. Therefore, in this case, the expected number of speeding cars is E[X] = 9 * 0.5 = 4.5 (rounded to one decimal place).
Variance of the distribution of X:
The variance of a binomial distribution is calculated using the formula Var(X) = n * p * (1 - p). Substituting the values, we get Var(X) = 9 * 0.5 * (1 - 0.5) = 2.25 (rounded to one decimal place).
Standard deviation of the distribution of X:
The standard deviation is the square root of the variance. Therefore, the standard deviation of the distribution of X is sqrt(2.25) = 1.5 (rounded to one decimal place).
Expected fines generated by the next 9 cars:
Since the average speeding fine per car is R2174, the expected fines generated by a single car is R2174. Therefore, the expected fines generated by the next 9 cars would be 9 * R2174 = R19566.
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how many liters of a 25\%%, percent saline solution must be added to 333 liters of a 10\, percent saline solution to obtain a 15\, percent saline solution?
{PLEASE HELP} can someone answer this it’s really easy....
(PLEASE HELP)
Consider circle O with diameter GB. Line AD is tangent to circle O at point A and line DB is tangent to circle O at point B. The measure of ∠GBA is 38°. Chord GC bisects ∠G. Determine each measure
The angles GBD, GBD and G measures 90 , 90, 52 degree respectively.
GB is the diameter given.
AD is the tangent given.
The tangent makes 90 degree angle with diameter.
hence the angle GBD will be : 90°
Similarly, GBA will also be 90°
The angle GBA is given as 38°
Hence the angle G will be = 90 - 38 =52
All points in a plane that are at a specific distance from a specific point, the centre, form a circle. In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant. The radius of a circle is the separation between any point on the circle and its centre.
The radius must typically be a positive integer. A degenerate situation is a circle with radius equal to zero (one point). Except when otherwise specified, this article discusses circles in Euclidean geometry, namely the Euclidean plane.
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Solve for the Value of R
Answer:
r = 13
Step-by-step explanation:
As the vertically opposite angles are equal,
8r + 6 = 9r - 7
Now you can find the value of r.
8r - 9r = -6 - 7
-r = -13
r = 13
Hope this helps you :-)
Let me know if you have any other questions :-)
Use the figure to the right to find the value of PT. T is the midpoint of PQ.
PT = 4x + 5 and TQ = 8x-7
Answer:
PT = 17
Step-by-step explanation:
Since T is the midpoint of PQ, then
PT = TQ , substitute values
4x + 5 = 8x - 7 ( subtract 4x from both sides )
5 = 4x - 7 ( add 7 to both sides )
12 = 4x ( divide both sides by 4 )
3 = x
Thus
PT = 4x + 5 = 4(3) + 5 = 12 + 5 = 17
Answer:
17
Step-by-step explanation:
since T is mid point of PQ
PT=TQ
\(4x + 5 = 8x - 7 \\ 5 + 7 = 8x - 4x \\ 12 = 4x \\ x = 12 \div 4 \\ x = 3 \\ \)
so
\(pt = 4x + 5 \\ = 4(3) + 5 \\ = 12 + 5 \\ pt = 17\)
PLSSS HELPpPP URGENT
Answer:
A.
Step-by-step explanation:
as u can see,the other acute angle is 43° and the other is also an acute angle and acute angles must not surpass until 80° meaning, the other acute angle is 47°
\( \angle \: ACB = 43 \degree + \angle \:BCD \)
=> 90° = 43° + BCD
=> BCD = 90° - 43°
=> BCD = 47°
Option ( A ) 47° is correct answer