A design is required for a CS amplifier for which the MOSFET is operated at gm = 5 mA/V and has Cgs = 5pF and cgd=1 pF. The amplifier is fed with a signal source having Rsig = 1 k ohm, and RG is very large. What is the largest value of R'L for which the upper 3-dB frequency is at least 10 MHz? What is the corresponding value of midband gain and gain-bandwidth product? If the specification on the upper 3-dB frequency can be relaxed by a factor of 3, that is, to (10/3) MHz, what can AM and GB become?

Answers

Answer 1

The largest value of R'L for the CS amplifier is 318 ohms, with a midband gain of 1.59 and a gain-bandwidth product of 15.9 MHz.

If the upper 3-dB frequency is relaxed to (10/3) MHz, the midband gain AM can increase to 3.98 and the gain-bandwidth product (GB) can become 13.27 MHz.


1. Find the total capacitance, C_T = C_gs + (1+g_m*R'_L)*C_gd.


2. Calculate the required cutoff frequency, f_c = 10 MHz.


3. Rearrange the equation f_c = 1/(2*pi*R_sig*C_T) to solve for R'_L.


4. Substitute the given values and find R'_L ≈ 318 ohms.


5. Calculate the midband gain, AM = g_m*R'_L ≈ 1.59.


6. Determine the gain-bandwidth product, GB = AM*f_c ≈ 15.9 MHz.


7. If the upper 3-dB frequency is relaxed to (10/3) MHz, recalculate the midband gain and gain-bandwidth product.

To know more about midband gain click on below link:

https://brainly.com/question/15146615#

#SPJ11


Related Questions

how many molecules are in 3 moles of CO2

Answers

Answer:

1.806 x 10^24  molecules

Explanation:

1 mole of CO2 has 6.02 x 10^23 molecules

3 mole of CO2 has 3x6.02x10^23 molecuels = 1.806 x 10^24 molecules

The 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.

One mole of \(CO_{2}\) contains \(6.022*10^{23}\) molecules.

In 3 moles of \(CO_{2}\) ,

                              \(=3*6.022*10^{23}=1.8066*10^{24}\) molecules.

Hence, the 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.

Learn more:

https://brainly.com/question/22016398

Convert 0.4 cm to km.

Answers

4 x 10 (-6) or 0.000004 I think
It is 4x10-6 km= 0.000004

An automobile starts at rest and accelerates at 57 m/s after a traffic light turns green.
How far will it have gone when it is traveling at 15 m/s?

Answers

u(initial velocity)
v(final velocity)
s(displacement)
a(acceleration)
t(time)

u=0 v=15 a=57??(not sure if you meant 5.7m/s²) s=?

v ² = u ² + 2 a s
15 ² = 0 ² + 2 (57) s
225= 114 s
s= 1.97 meters

If you meant 5.7
v ² = u ² + 2 a s
15 ² = 0 ² + 2 (5.7) s
225 = 11.4 s
s = 19.74 meters

An automobile accelerates at the rate of 57 m/s² with a final velocity of 15 m/s. Then, the distance covered by the automobile will be equal to 1.97 meters.

What is Acceleration?

A moving object's speed and orientation vary over time at a certain rate, which is known as acceleration.

An object or location is considered to be accelerated when it moves more quickly or more slowly in a straight path. A circle's motion increases despite its constant speed because its direction is always changing. For all other motions, by and to velocity is used.

Because of its magnitude and direction, it is a vector quantity.

As per the given information in the question,

Acceleration, a = 57 m/s²

Final velocity, v = 15 m/s

Use the equation of motion,

v² - u² = 2as

Put the values in the equation,

15² - 0 = 2(57)(s)

s = 225/114

s = 1.97 meters.

To know more about Acceleration:

https://brainly.com/question/12550364

#SPJ2

what is the process of subduction

Answers

Answer:

Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones.

In recent years it has been possible to buy a 1. 0 F capacitor. This is an enormously large amount of capacitance. Suppose you want to build a 1. 1 Hz oscillator with a 1. 0 F capacitor. You have a spool of 0. 25-mm-diameter wire and a 4. 0-cm-diameter plastic cylinder.

How long must your inductor be if you wrap it with 2 layers of closely spaced turns?

Answers

An oscillator is an electronic device that produces an electrical signal at a specific frequency. A capacitor is an electrical component that stores electrical energy. In recent years, it has become possible to purchase a 1.0 F capacitor. This is an incredibly large amount of capacitance.

Suppose you want to build a 1.1 Hz oscillator using a 1.0 F capacitor and a spool of 0.25-mm-diameter wire and a 4.0-cm-diameter plastic cylinder. We can calculate the required inductance value using the formula:f = 1/2π√(L*C)Where f is the desired frequency, L is the inductance value, and C is the capacitance value. Substituting the given values:

\(f = 1.1 HzC = 1.0 F\)

Plugging these values into the formula and solving for L:

1.1 Hz = 1/2π√(L*1.0 F)2π*1.1 Hz = √(L*1.0 F)6.88 Hz2 = L*1.0 F6.88 H/ F = LL = 6.88 H

\(1.1 Hz = 1/2π√(L*1.0 F)2π*1.1 Hz = √(L*1.0 F)6.88 Hz2 = L*1.0 F6.88 H/ F = LL = 6.88 H\)We need to wrap this inductance value with two layers of closely spaced turns around the plastic cylinder.

The inner diameter of the cylinder is equal to the diameter of the wire, which is 0.25 mm or 0.00025 m. Therefore:d = 0.00025 mThe outer diameter of the cylinder is 4.0 cm or 0.04 m. Therefore:D = 0.04 mPlugging these values into the formula for A:

\(A = (π/4)(0.04² - 0.00025²)A = 0.001257 m²\)

Plugging these values into the formula for L:

\(L = µn²A/lSolving for l:l = µn²A/L\)

Plugging in the given values:

\(µ = 4π x 10^-7 H/mn = 2\)

(since we want two layers)

\(A = 0.001257 m²L = 6.88 Hl = (4π x 10^-7 H/m)(2²)(0.001257 m²)/(6.88 H)l ≈ 0.0015 m\) or 1.5 mm

Therefore, the length of the inductor should be approximately 1.5 mm.

To know more about oscillator visit :

https://brainly.com/question/31835791

#SPJ11

Consider a buggy being pulled by a horse.
Which is correct?
1. The horse can pull the buggy forward only
if the horse weighs more than the buggy.
2. The force on the buggy is as strong as the
force on the horse. The horse is joined to the
Earth by flat hoofs, while the buggy is free to
roll on its round wheels.
3. The horse pulls before the buggy has time
to react so they move forward.
4. The horse pulls forward slightly harder
than the buggy pulls backward on the horse,
so they move forward.

Answers

Answer:

Option 2

Explanation:

Answer:B

Explanation:because she started of with no money and now she made her money up

A Lockheed F-117 Nighthawk stealth bomber starts at rest at the south end of a runway and undergoes a uniform acceleration of 17.98 m/s2 to the north. it takes the plane 7s to reach a velocity of 60.16 m/s to the north. How far does the plane travel along the runway

Answers

Answer:

x = 100.64 [m]

Explanation:

To solve this problem we must use the following kinematics equation.

\(v_{f} = v_{i} + (a*t)\\\)

\(v_{f} ^{2} = v_{i} ^{2} + (2*a*x)\\\)

where:

Vi = initial velocity [m/s]

Vf = final velocity = 60.16 [m/s]

a = acceleration = 17.98 [m/s^2]

t = time = 7 [s]

Now replacing the values, we have:

(60.16)^2 = 0 + (2*17.98*x)

x = 100.64 [m]

Which of the following is a true statement?

Which of the following is a true statement?

Answers

How closely packed the electric field lines are indicates the strength of the electric field (C) is the correct answer.

What is Radioactivity?​

Answers

Radioactivity is the spontaneous decay of the nucleus of the atom of an element during which it emit alpha particle, beta particle or gamma ray or a combination of any or all the three with the release of heat as energy.

RADIOACTIVITY

The word radioactivity emanated from two words

RadiationActivity

Radiation means emission while activity is the rate at which radioactive source decay.

What is Radioactivity ?

Radioactivity is the spontaneous decay of the nucleus of the atom of an element during which it emit alpha particle, beta particle or gamma ray or a combination of any or all the three with the release of heat as energy.

Learn more about Radioactivity here: https://brainly.com/question/2320811

1 > Explain why scientists cannot watch the complete process of a star and planets forming. J​

Answers

Scientists cannot watch the complete process of a star and planets forming due to dust

Basically, formation of a star takes place after the accumulation of gas and dust. which gets collapsed due to gravitation. This whole process takes millions of years until a star is formed and starts to shine like a sun. Moreover, the leftovers of from the formed star creates planets. In the whole process of formation of stars and planets the dust makes visible light difficult to see with help of our radio telescopes. Although it is possible for us observe formation of stars by radio waves.

Hence, due to dust and leftovers of stars scientists finds it difficult to see the formation of stars and planets.

Scientists use telescopes and simulations to study the formation of stars and planets because to their long time scales, distant locations, and dense dust and gas in molecular clouds.

Scientists cannot directly watch the full formation of a star and planet since these activities take place over extraordinarily long periods of time and often in faraway and opaque parts of space. In enormous molecular clouds, dense dust and gas block most electromagnetic radiation, including visible light, allowing stars and planets to form.

Time Scales: Scientists can't directly monitor every stage of star and planet formation because it takes millions of years.

Distance: Many of these creation events occur in faraway areas of our galaxy or other galaxies. With current technology, these processes are hard to see.

Obstructions: Thick clouds of dust and gas surround the regions where stars and planets develop, making it difficult for visible light and other electromagnetic waves to penetrate and provide clear observations.

Early Stages: These dense clouds hide the first collapse of material that forms protostars and protoplanetary discs.

Despite these constraints, scientists study these phenomena with infrared, radio, and X-ray telescopes. These approaches let astronomers to see infrared emissions from young stars and protoplanetary discs through dust clouds, indicating their origin. Scientists combine observations with theoretical knowledge to study star and planet formation using computer simulations and models.

To know more about electromagnetic radiation

https://brainly.com/question/1408043

#SPJ2

joe and tom are competing in a 100 m race. partway through the race, joe is 50 m from the finish line and moving at 10 m/s and tom is 51 m from the finish line and moving at 9.75 m/s. if joe maintains his speed and tom begins accelerating, what magnitude of constant acceleration must tom have so that they finish the race in a dead heat

Answers

Tom must accelerate at a constant rate of 0.25 m/s2 in order to finish the race in a dead heat with Joe.

What is accelerate?

Accelerate is an action or process of speeding up or increasing in rate or amount. It is commonly used to describe an increase in the rate of change of velocity, or the rate of change of a variable such as time, speed, or distance. Acceleration can be generated by a variety of forces and factors, such as gravity, electrical current, centrifugal force, friction, and aerodynamic drag.

Tom must have a constant acceleration of 0.25 m/s2 in order to finish the race in a dead heat with Joe. This can be calculated using the equation for average velocity, vavg = (v1 + v2)/2, where v1 is Joe's velocity and v2 is Tom's velocity. If Joe and Tom both have the same final velocity, then their average velocity must be equal.
50 m / 10 m/s + 51 m / (9.75 m/s + a) = (10 m/s + a)
Solving for a, we get a = 0.25 m/s2. Therefore, Tom must accelerate at a constant rate of 0.25 m/s2 in order to finish the race in a dead heat with Joe.

To learn more about accelerate
https://brainly.com/question/30136274
#SPJ4

What do you mean by Tribology? Explain its significance in our daily life 2. Explain the role played by friction and wear in a tribological system 3. How do you define Wear? How it affects the properties of a surface?

Answers

(1.)Tribology is the study of friction, wear, lubrication, and the design of bearings; the science of interacting surfaces in relative motion.
(2.)Tribology is particularly important in today's world because so much energy is lost to friction in mechanical components. To use less energy, we need to minimize the amount that is wasted. Significant energy is lost due to friction in sliding interfaces.
(3.) Wear can be defined as an extremely short sliding motion and is executed within a short time interval.
(Idk how it effects the properties of surface sorry )


What type of object is called the
object in motion?​

Answers

Answer: An object is in motion when its distance from another object is changing . A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving

Explanation:

A 2.90\muF capacitor is charged to 500 V and a 3.50\muF capacitor is charged to 505 V.
PART A
These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the negative plates are connected to each other. What will be the potential difference across each capacitor?
Enter your answers numerically separated by a comma.

Answers

The potential difference across each capacitor is 1797.45 V, 1797.45.

What are capacitors?

When the capacitors are disconnected from their batteries and their positive plates are connected to each other and negative plates are also connected to each other, they will form a series combination.

The equivalent capacitance of the series combination can be calculated as:

1/C = 1/C1 + 1/C2

where C1 and C2 are the capacitances of the two capacitors.

Plugging in the given values, we get:

1/C = 1/2.90 x 10^-6 + 1/3.50 x 10^-6

C = 1.57 x 10^-6 F

The total charge stored on the capacitors before they are connected in series is:

Q = C1V1 + C2V2

where V1 and V2 are the voltages across the two capacitors.

Plugging in the given values, we get:

Q = 2.90 x 10^-6 x 500 + 3.50 x 10^-6 x 505

Q = 2.8245 x 10^-3 C

Since the charge is conserved, the total charge on the capacitors after they are connected in series will also be Q.

The potential difference across each capacitor can be calculated using the formula:

V = Q/C

For the 2.90μF capacitor, we get:

V = Q/C = 2.8245 x 10^-3 / 1.57 x 10^-6 = 1797.45 V

For the 3.50μF capacitor, we get:

V = Q/C = 2.8245 x 10^-3 / 1.57 x 10^-6 = 1797.45 V

Therefore, the potential difference across each capacitor is 1797.45 V.

Answer: 1797.45, 1797.45.

Learn more about capacitors.

brainly.com/question/17176550

#SPJ11

A bus decreases its speed from 80kmhm to 60kmh in 5 seconds. find the acceleration of the bus.

Answers

Answer:

\(a = \frac{v - u}{t} \\ a = \frac{60 - 80}{5} \\ a = - 4 \: m {s}^{ - 2} \)

Answer:

Explanation:

The acceleration of an object (in this case, a bus) can be calculated by finding the difference between its final velocity (V) and initial velocity (U), and dividing that difference by the time it takes for the change to occur (t).

In this specific example, let's convert the initial velocity (U) of the bus from kilometers per hour (km/hr) to meters per second (m/sec) by multiplying it by 5/18. This gives us a value of 22.22 m/sec. Similarly, the final velocity (V) is converted to 16.67 m/sec.

Using the formula for acceleration (a = (V - U) / t), we substitute the values:

a = (16.67 - 22.22) / 5

Simplifying this equation, we get:

a = -5.55 / 5

This results in an acceleration of -1.11 m/s². The negative sign indicates that the velocity of the bus is decreasing.

Therefore, the acceleration of the bus, as it decreases its speed from 80 kilometers per hour to 60 kilometers per hour in 5 seconds, is approximately -1.11 m/s².

Hey!!
I need help in a question...

• Different types of fuels and the amount of pollutants they release.

Please help me with the question.
Thankss​

Answers

Answer: Different types of fuels have varying compositions and release different amounts of pollutants when burned. Here are some common types of fuels and the pollutants associated with them:

Fossil Fuels:

a. Coal: When burned, coal releases pollutants such as carbon dioxide (CO2), sulfur dioxide (SO2), nitrogen oxides (NOx), and particulate matter (PM).

b. Petroleum (Oil): Burning petroleum-based fuels like gasoline and diesel produces CO2, SO2, NOx, volatile organic compounds (VOCs), and PM.

Natural Gas:

Natural gas, which primarily consists of methane (CH4), is considered a cleaner-burning fuel compared to coal and oil. It releases lower amounts of CO2, SO2, NOx, VOCs, and PM.

Biofuels:

Biofuels are derived from renewable sources such as plants and agricultural waste. Their environmental impact depends on the specific type of biofuel. For example:

a. Ethanol: Produced from crops like corn or sugarcane, burning ethanol emits CO2 but generally releases fewer pollutants than fossil fuels.

b. Biodiesel: Made from vegetable oils or animal fats, biodiesel produces lower levels of CO2, SO2, and PM compared to petroleum-based diesel.

Renewable Energy Sources:

Renewable energy sources like solar, wind, and hydropower do not produce pollutants during electricity generation. However, the manufacturing, installation, and maintenance of renewable energy infrastructure can have environmental impacts.

It's important to note that the environmental impact of a fuel also depends on factors such as combustion technology, fuel efficiency, and emission control measures. Additionally, advancements in clean technologies and the use of emission controls can help mitigate the environmental impact of burning fuels.

If scientists could bore though Earth's interior, what change would they most likely notice as they passed from the lithosphere to the asthenosphere?

Answers

Answer:

It gets hotter and hotter and it would start to be a liquid lava

Explanation:

The gravitational force between a satellite and Earth’s moon is 324 N. The mass of the moon is 7.3 × 1022 kg.

If the distance from the moon to the satellite is 2.6 × 106 m, what is the mass of the satellite?

1.7 × 10–4 kg
2.2 × 10–3 kg
230 kg
450 kg

Answers

Answer:

450 kg

Explanation:

In the picture above. Goodluck

The gravitational force between a satellite and Earths moon is 324 N. The mass of the moon is 7.3 1022

Answer:

The correct answer is D :)

Explanation:

Got it right edge 2021

LR 125 ml/hr via gravity flow using tubing calibrated at 15 gtt/ml. Calculate the flow rate. A. 8 gtt/min B. 15 gtt/min C. 25 gtt/min D. 31 gtt/min.

Answers

The calculated flow rate is 31.2 gtt/min, which indicates a fractional value. Depending on the precision of the measurement, rounding may be necessary. So among the choices, option D. 31 gtt/min is correct.

To calculate the flow rate in drops per minute (gtt/min), we need to consider the volume infused per unit of time and the calibration of the tubing.

Given:

Infusion rate: 125 ml/hr

Tubing calibration: 15 gtt/ml

To convert the infusion rate from ml/hr to ml/min, we divide by 60 (since there are 60 minutes in an hour):

125 ml/hr ÷ 60 min/hr = 2.08 ml/min

Now, to find the flow rate in gtt/min, we multiply the infusion rate in ml/min by the tubing calibration factor:

2.08 ml/min × 15 gtt/ml = 31.2 gtt/min

The calculated flow rate is 31.2 gtt/min.

Among the answer choices, D. 31 gtt/min is the closest value to the calculated flow rate. However, it is important to note that the calculated flow rate is 31.2 gtt/min, which indicates a fractional value. Depending on the precision of the measurement, rounding may be necessary.

To learn more about, flow rate, click here, https://brainly.com/question/27880305

#SPJ11

PLEASE HELP ME I NEED THE ANSWER FAST 1 A diver diving into a pool has
a. no energy b. potential energy c. kinetic energy

Answers

Answer:

C

Explanation:

A diver diving into a pool has kinetic energy when they hit the water, and that energy transfers and is given to the water, which splashes.

the question is confusing ​

the question is confusing

Answers

Alpha particles have highest mass.

Alpha particles are most ionising.

Gamma particles are the most penetrating.

Beta particles are negatively charged.

Gamma particles have the highest speed.

Comparing the three types of ionizing radiation-alpha particles have the greatest mass. Alpha particles have approx 4 times the mass of a proton or neutron and 8,000 times the mass of a beta particle. Ionising power of alpha particle is very high due to double positive charge, large mass as compared to a beta particle. Alpha particles can cause multiple ionisations within a very small distance. Beta radiation is more penetrating than alpha radiation. beta radiation can pass through the skin, but it is absorbed by a few cm of tissue of the body or a few mm of aluminum. Gamma radiation is the most penetrating of the three radiations. Alpha particles are positively charged, while beta particles are negatively charged, and gamma radiation is electrically neutral. Gamma rays are similar to visible light but they have higher energy. Gamma rays are emitted along with alpha or beta particles during radioactive decay.

learn more about gamma rays here:

https://brainly.com/question/2399890

#SPJ10

A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?

Answers

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

For more such questions on time, click on:

https://brainly.com/question/26046491

#SPJ8

A vector
of magnitude 5 units and another vector ū of magnitude 3 units point in directions
differing by 60°. Find out (a) the scalar product of the two vectors and (b) the vector product of the two vectors​

Answers

Answer:

7.5 units

13 units

Explanation:

\(|v|=5\ \text{units}\)

\(|u|=3\ \text{units}\)

\(\theta\) = Angle between the vectors = \(60^{\circ}\)

Scalar product is given by

\(u\cdot v=|u||v|\cos\theta\\ =3\cdot 5\cdot \cos60^{\circ}\\ =7.5\ \text{units}\)

The scalar product of the vectors is 7.5 units.

Vector product is given by

\(u\times v=|u||v|\sin\theta\\ =3\times 5\sin60^{\circ}\\ =13\ \text{units}\)

The vector product of the vectors is 13 units.

The force pulling the moon toward Earth depends on the mass of the two bodies and which factor?.

Answers

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects.

Consider two points in an electric field. The potential at point 1, V1, is 23 V. The potential at point 2, V2, is 185 V. An electron at rest at point 1 is accelerated by the electric field to point 2. A. Write an equation for the change of electric potential energy ΔU of the electron. B. Find the numerical value of the change of the electric potential energy in electron volts (eV). C. Express v2, the speed of the electron at point 2. In terms of ΔU, and the mass of the electron me. D. Find the numerical value of v2 in m/s

Answers

The electric potential energy change is described by the equation U = U2 - U1, and the quantity of work performed by the electric force is -2.68 x 10-17 J.

U1 = kqQ / r

Where U1 is the change in electrical potential energy and k is a constant,

• Charge = Q

• r = separation from the charge point

V = kQ / r, therefore U1 = V1 q.

U₁ = 23q

U2 = V2q is the electrical potential energy at position P2.

U2 = 185 x q

The following equation represents the change in electric potential energy:

ΔU = U₂- U1

(b)

Solving the equation, we have:

ΔU = 185 - 23

ΔU = 162 eV

Since the charge in the change in potential difference is positive, the work produced by the electric force when the proton is in motion is negative.

i.e.

ΔUE = q(162)

ΔUE (-e) (162) V

ΔUE = -162 eV

where;

• ΔUE denotes the work done by the electric force.

Recall that:

• 1 electron volt = 1.66 x 10-19 Joules

ΔUE = -162 x 1.66 x 10-19 J

ΔUE = -2.68 x 10-17 J

This leads us to the conclusion that the electric potential energy change is described by the equation U = U2 - U1, and the quantity of work performed by the electric force is -2.68 x 10-17 J.

To learn more about electric field from given link

https://brainly.com/question/14869213

#SPJ1

(d) 10 s
13. An object in motion has a displacement of +50 m. The average velocity is +25 m/s. Whats the time taken

Answers

The time taken to travel 50 m ina 25 m/s average velocity is 2 sec.

What is Velocity?

The directional speed of an item in motion, as measured by a specific unit of time and viewed from a certain point of reference, is what is referred to as velocity.

An object's position changes if it moves in relation to a reference frame, such as when a passenger travels to the back of an airliner or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.

When anything moves in connection to a reference frame, such when a passenger moves to the back of an airplane or a lecturer walks to the right in relation to a whiteboard, the location of the item changes. This locational change is described as displacement.

The displacement is = 50 m

The average velocity = 25 m /sec

The time taken is = displacement/ average Velocity  = 50/25 = 2 sec.

To learn more about Velocity refer to :

https://brainly.com/question/29620915

#SPJ1


If m=120kg and a=15m/s2, what is the force

Answers

Answer:

F= 1800N

Explanation:

the equation for force is F= ma

so plug in the numbers: F= (120)(15)

solve this to get F= 1800N

tip: don't forget to add the units when writing your answer :)

Driving in a car down Main Street,
Tanner hit the breaks and accelerates at
-5.2 m/s^2. After 3.00 seconds he is
moving at 20.0 m/s. What was his initial
speed?

Answers

Tanner's initial speed was 35.6 m/s

We can use the following kinematic equation to solve the problem:

v = u + at

Here given information is:

v = final velocity (20.0 m/s)

u = initial velocity

a = acceleration ( -5.2 m/s^2) (negative sign indicates deceleration)

t = time (3.00 seconds)

Substituting the given values into the equation:

20.0 = u - 5.2 x 3.00

Simplifying and solving for u:

u = 20.0 + 15.6

u = 35.6

Therefore, Tanner's initial speed was 35.6 m/s before he hit the brakes and decelerated at -5.2 m/s^2 for 3.00 seconds.

For more reference to kinematic energy please refer to:

https://brainly.com/question/16888003

How does a volcanic eruption benefit the surrounding area? a. the surrounding soil can become very fertile. b. the surrounding rock is destroyed. c. volcanic eruptions prevent earthquakes from happening. d. lava and ash bury animal habitats.

Answers

A volcanic eruption can benefit the surrounding area is a. the surrounding soil can become very fertile

When a volcano eruption, it releases ash and other materials rich in nutrients that are beneficial for plant growth. As these materials settle on the ground, they mix with the soil, resulting in highly fertile land, this fertility can lead to increased agricultural productivity in the affected area, promoting the growth of diverse plant species and supporting vibrant ecosystems. It is important to note that not all aspects of volcanic eruptions are positive. The surrounding rock may be destroyed, and animal habitats could be buried by lava and ash.

Additionally, volcanic eruptions do not prevent earthquakes from occurring; in some cases, they may even be triggered by seismic activity. However, focusing on the positive outcomes, the enhanced fertility of the soil due to volcanic eruptions can provide long-term benefits to the surrounding area by supporting healthy ecosystems and agricultural productivity. So therefore the correct answer is a. the surrounding soil can become very fertile.

Learn more about volcano eruption

https://brainly.com/question/143597

#SPJ11

What is the acceleration due to gravity?
А
B
9.2
12.3
С
8.83
D
9.81

Answers

Correct answer:

D) 9.81

Other Questions
2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26. What is the sum of the digits of the number 2^1000? Write a program in Java. Introduction to discrete structures question "consider the following algorithm segment. assume that n is a positive integer. for i: = 1 to n for j: = floor((i+1)/2) to n x:= i * j next j next i a) what is the actual number of elementary operations(additions, subtractions, multiplications, divisions, and comparisons) that are performed when the algorithm segment is executed? for simplicity, count only comparisons that occur within if-then statements, and ignore those implied by for-next loops. express your answer in terms of n. for odd n the number of operations is ? for even n the number of operations is ? " Joey buys a home for $123,020. His home is predicted to increase in value 6% each year. What is the predicted value of his home in 25 years? Round answer to the nearest whole number. Do not include units. Evaluate Why did the powers denied Congress lead to a weak government? a cell phone plan costs $50 per month for 1,000 minutes and $0.30 per minute for each additional minute after 1,000. what is the marginal cost of the 1st minute? Find the value of x so that the function has the given value. Are Cannon's total sales increasing at a faster rate when the amount of money spent on advertising is $80,000 or $130,000? one of the ways that spam is able to propagate is by taking advantage of servers that will accept email from anyone; these are known as factors associated with the initiation and retention of patients with lupus in the chronic disease self-management program Laurice Co. is a public entity whose shares are traded in the over-the-counter market. At December 31, 2020. Lorraine Co. 3,000,000 authorized ordinary shares of which 1,000,000 shares were issued and outstanding. The equity accounts at December 31, 2020 had the following balances: Ordinary share capital 10,000,000.00 Share premium 3,750,000.00 Retained Earnings 3,250,000.00 Transactions during 2021 and other information relating to the equity accounts were as follows: On January 2, 2021. Laurice Co. issued at Php 54 per share, 50.000 shares of Php 30 par value, 9% cumulative convertible preference shares. Each preference share is convertible into two ordinary shares. Laurice Co. had 300,000 authorized shares of preference shares. The preference shares have a liquidation value equal to the par value. On February 1, 2021. Laurice Co. reacquired 10,000 ordinary shares for Php 16 per share. On April 30, 2021, Laurice Co. sold 200,000. Php 10 par value, ordinary shares (previously unissued) to the public at Php 17 per share On June 15, 2021, Laurice Co. wanted to raise its working capital. After analysis of the available options, the company decided to issue 6.000 shares at Php 30 par, preference shares with detachable warrants. The package of shares and warrants sells for Php 120. The warrants enable the holders to purchase 6,000 shares of Php 10 ordinary shares at Php 40 per share. Immediately following the issuance of the shares, the share warrants are selling at Php 10 per share and the market value of the preference shares is Php 90. On November 10, 2021, Laurice Co. sold 5,000 treasury shares for Php 21 per share. 1. Determine the amount to be reported under preference share capital 2. Compute for 2021 treasury shares balance 3. Compute for total share premium to be reported in 2021 statemen of financial position 4. Compute for the ordinary share capital if 80% of the warrants are exercised. 5. Setting aside the exercise of warrants and the shareholders rather converted the 50,000 convertible shares, how much will be the total share premium to be reported in the 2021 financial statements? 6. Compute for the total ordinary share capital to be reported in the 2021 Statement of Financial Position if in addition to the transactions in 27, the following occurred: 1. 80% of the warrants were exercised; 2.50,000 of the convertible preference shares were converted; 3. The remaining unissued treasury shares were retired. On november 8, it sold 14 units for $42 each. using the lifo perpetual inventory method, what was the amount recorded in the cost of goods sold account for the 14 units sold? A Health Psychologist Is Interested In The Effectiveness Of A New Exercise On Reducing The Rate Of Heart Attacks Because The Exercise Requires No Equipment And, Therefore, Can Be Done Without Cost. A. What Is The Research Hypothesis? B. What Is The Null Hypothesis? C. What Is The Comparison Distribution For This spesific example (we draw this out every time?) the decision about where to use control charts should focus on aspects of the process that . multiple choice question. have a tendency to go out of control, and affect product or service characteristics have the lowest cost of inspection, and require the least time to collect samples are visible to the customer, and can be automated The task environment includes Multiple Choice a. the wide-ranging global, technological, soclocultural, and political forces that affect organizations. b. the forces that have the least immediate effect on managers and their decisions. c. opportunities and threats that are harder to identify than those in the general environment. d. a framework of environmental policies that dictate the CSR policies of global organizations. e. the set of forces that originate with global suppliers, distributors, customers, and competitors. Nautilus Clothing's stock has a 60% chance of producing a 15%return, a 20% chance of producing a 20% return, and a 20% chance ofproducing a -7% return.What is the stock's expected return? Why did Samuel Adams' contemporaries refer to him as the "Patriarch ofLiberty"?O A. He was the father of John Adams and grandfather of John Quincy Adams.O B. He was the mastermind of the Articles of Confederation and Constitution.O C. His fiery rhetoric and organizational skills fanned the flames of rebellion.O D. He used his banking Connections to help fund the war for independence. What is the arc length of a circle that has a 6 inch radius and a central angle that is 85 degrees? Equity investors in a private company usually plan to realize a return on their investment by selling their stock when that company is acquired by another firm or sold in the public in a public offering....TRUE OR FALSE?????? 3+5h-14 word phrase Calculate the equilibrium concentrations of reactant and products when 0.363 moles of cocl2(g) are introduced into a 1.00 l vessel at 600 k.