A football is thrown with an acceleration of 15 m/s^2 and a force of 13 N. What is its mass?
A.150 kg
B. 0.87 kg
C. 2.0 x 105 kg
D. 0.12 kg

Answer:

100 is the frequency of wave

Explanation:

If water vapor comprises 3.5 percent of an air parcel whose total pressure is 1,000mb, the water vapor pressure would be 35mb.

The vapor pressure is the pressure exerted by the water vapor within the air parcel. Here's how to calculate it:

Step-by-step Total pressure = water vapor pressure + dry air pressure

The percentage of water vapor in the air parcel is 3.5%, which means the remaining percentage is that of dry air.

Therefore, the percentage of dry air is:100% - 3.5% = 96.5%

The dry air pressure is 96.5% of the total pressure:

96.5% × 1000mb = 965mb

Now, we can find the water vapor pressure by subtracting the dry air pressure from the total pressure:

1000mb - 965mb = 35mb

Therefore, the water vapor pressure would be 35mb.

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Write each force in component form:

v ₁ : 50 N due east   →   (50 N) i

v ₂ : 80 N at N 45° E   →   (80 N) (cos(45°) i + sin(45°) j ) ≈ (56.5 N) (i + j )

The resultant force is the sum of these two vectors:

r = v ₁ + v ₂ ≈ (106.5 N) i + (56.5 N) j

Its magnitude is

|| r || = √[(106.5 N)² + (56.5 N)²] ≈ 121 N

and has direction θ such that

tan(θ) = (56.5 N) / (106.5 N)   →   θ ≈ 28.0°

i.e. a direction of about E 28.0° N. (Just to clear up any confusion, I mean 28.0° north of east, or 28.0° relative to the positive x-axis.)

Answer:

Mass of water: 43 g

Explanation

hope it helps

The energy would be obtained if 44 g of carbon were irradiated is  5.8863 x 10^5 J.

Assume each carbon atom emits one photon. For each photon.

E=hc/lambda

Where h = Plank's constant

C = speed of light

E = (6.625×10^-34)×(3×10^8)/(7.45×10^-7)

E = 2.66819x10^-19 J

So the total energy emitted is

E = E1xn

E = (2.66819x10^-19)×(6.022x10^23)/ 1 mol of carbon atom

E = 5.8863 x 10^5 J

Black body radiation is a type of radiation in which a body is in thermodynamic equilibrium, emitted by a black body. It has a specific, continuous spectrum of wavelength. Photons are energy stored in bundles.

In above question,

Wavlength (lambda)=745nm = 7.45x10^-7m.

Mass of carbon = 44 gram

Assume each carbon atom emits one photon. For each photon.

E=hc/lambda

Where h = Plank's constant

C = speed of light

E = (6.625×10^-34)×(3×10^8)/(7.45×10^-7)

E = 2.66819x10^-19 J

So the total energy emitted is

E = E1xn

E = (2.66819x10^-19)×(6.022x10^23)/ 1 mol of carbon atom

E = 5.8863 x 10^5 J

Therefore, The energy would be obtained if 44 g of carbon were irradiated is  5.8863 x 10^5 J.

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Answer:

Explanation:

c

Since dehydration is due to lack of water, sweating excessively is Not a sign of extreme dehydration.

Dehydration is a condition in which the body lack a enough water necessary for metabolic activities.

Dehydration results in extreme physical conditions of the body such as fatigue.

Some signs of extreme dehydration include:

Therefore, sweating excessively is Not a sign of extreme dehydration.

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Answer:

the correct answer is option C , 2.0 V( volts ) !!

explanation : Total potential difference = 6 V

Total resistance = ( 3 + 4 + 5 ) ohms = 12 ohms

so , applying ohm's law to the whole circuit , we get :

V/ I = R

6/ I = 12

I = 6/ 12 = 1/2 = 0.5 ( total current ) ampere or A

now Current through 4 Ohms Resistance = 0.5 A

Resistance we know= 4 Ohms

Applying ohm's law :

V/I = R

V/0.5 = 4

V = 0.5 × 4 = 2 V

The potential difference (p.d.) across the resistor is 2.0 V.

The individual voltage drops across each resistor can be simply calculated as V = I*R where R represents the resistance value.

Total potential difference = 6 V

Total resistance = ( 3 + 4 + 5 ) ohms = 12 ohms

so, applying ohm's law to the whole circuit, we get :

V/ I = R

6/ I = 12

I = 6/ 12 = 1/2 = 0.5 ( total current ) ampere or A

Now Current through 4 Ohms Resistance = 0.5 A

The resistance we know= 4 Ohms

Applying ohm's law :

V/I = R

V/0.5 = 4

V = 0.5 × 4 = 2 V

Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.

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Answer:

the balloon is filled with the 8.5 litre of helium. temperature is 294 kelvin.

party starts at 4 p.m.

the temperature rises 305 kelvin.

the new volume = 4 litres

Answer:

Antacids.

Explanation:

Magnesium hydroxide is commonly used for sicknesses and etc.

Answer: It reduces the activation energy.

Explanation:

A catalyst is a material that, without being consumed by the process, speeds up a chemical reaction or decreases the temperature or pressure required to initiate one. The addition of a catalyst to a reaction is known as catalysis.

The bonds holding together the atoms in molecules are ruptured, altered, and repaired during a chemical reaction, recombining the atoms to form new molecules. By decreasing the activation energy, the energy hurdle that must be cleared for a chemical reaction to take place, catalysts improve the efficiency of this process. As a result, catalysts facilitate the formation of chemical bonds between atoms to create novel combinations and new compounds. Chemical processes are accelerated and become more energy-efficient when catalysts are used.

The answer to the question is 1.125  Newton

Formula for electrostatic force is F = ( K q1 q2 )/ r²

where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.

Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.

Electrostatic force between q1 and q3

r will be 0.500 + 0.500 = 1 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²

F₁₃ = 2.25  × 10⁻¹ N

Electrostatic force between q2 and q3

r will be 0.500 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²

F = (225 × 10⁻³) / (25 × 10⁻²)

F₂₃ = 9 × 10⁻¹ N

Total force on q3 will be F₁₃ + F₂₃

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 11.25  × 10⁻¹ ) N

Total force on q3 =  1.125  N

Thus after solving we got the net force on q3 as 1.125  Newton

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Answer:

Creative thinking

Explanation:

As you can see in the question above, when Mandleev needed to organize the chemical elements in a logical, organized and efficient way, he thought until he came to the conclusion of organizing them according to the atomic weight of each one. This is a clear example of creative thinking, which is the term that refers to the act of solving a problem based on thought and reasoning.

Answer:

Creative thinking

Explanation:

The Gibbs energy change (ΔG) is indeed a measure of the spontaneity of a process and the useful energy available from it.

Explanation:

1. Gibbs energy (G) is a thermodynamic potential that combines enthalpy (H) and entropy (S) to predict whether a process will be spontaneous or not at a constant temperature (T) and pressure (P).

2. The change in Gibbs energy (ΔG) is calculated using the formula: ΔG = ΔH - TΔS, where ΔH is the change in enthalpy and ΔS is the change in entropy.

3. If ΔG is negative, the process is spontaneous, meaning it will proceed on its own without the need for external energy input. A negative ΔG also indicates that the system releases useful energy.

4. If ΔG is positive, the process is non-spontaneous and will require external energy to proceed. The useful energy in this case is not available, as it must be supplied from an external source.

5. If ΔG is equal to zero, the process is at equilibrium, meaning the forward and reverse processes occur at the same rate, and there is no net change in the system.

In summary, the Gibbs energy change (ΔG) is an important parameter that helps determine the spontaneity of a process and the amount of useful energy that can be obtained from it.

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The electric field magnitude at different distances from the centre of the spheres is as follows: (a) r = 2.50 cm: E = 9.20 N/C, (b) r = 9.50 cm: E = 1.28 N/C, (c) r = 13.0 cm: E = 0.88 N/C, (d) r = 16.5 cm: E = 0 N/C

For determining the electric field magnitude at different distances from the centre of the spheres, use the principle of superposition. The electric field due to the insulating sphere is given by the equation \(E_{insulating} = (k * Q) / r^2\)

where k is the electrostatic constant, Q is the net positive charge, and r is the distance from the centre of the insulating sphere.

For the conducting spherical shell, the electric field inside the shell is zero, and outside the shell, the electric field is given by the equation

\(E_{shell} = (k * q) / r^2\)

where q is the net charge of the shell.

(a) For r = 2.50 cm, the electric field is calculated by adding the contributions from the insulating sphere and the conducting shell. E = \(E_{insulating} + E_{shell} = (k * Q) / r^2 + (k * q) / r^2 = (9 * 10^9 * 3 * 10^{-6}) / (2.5 * 10^{-2})^2 + (9 * 10^9 * (-1) * 10^{-6}) / (2.5 * 10^{-2})^2 \approx 9.20 N/C\)

(b) For r = 9.50 cm, the electric field is calculated in the same way. E = \(E_{insulating} + E_{shell} = (k * Q) / r^2 + (k * q) / r^2 = (9 * 10^9 * 3 * 10^{-6}) / (9.5 * 10^{-2})^2 + (9 * 10^9 * (-1) * 10^{-6}) / (9.5 * 10^{-2})^2 \approx 1.28 N/C\)(c) For r = 13.0 cm, the electric field is calculated in the same way. E = \(E_{insulating} + E_{shell} = (k * Q) / r^2 + (k * q) / r^2 = (9 * 10^9 * 3 * 10^{-6}) / (13.0 * 10^{-2})^2 + (9 * 10^9 * (-1) * 10^{-6}) / (13.0 * 10^{-2})^2 \approx 0.88 N/C\)(d) For r = 16.5 cm, the distance is greater than the outer radius of the conducting shell (c = 15.0 cm), so the electric field is zero (E = 0 N/C).

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The electric field at different distances from the center of the spheres can be calculated by applying Gauss's law and using the charges and sizes of the spheres. The field varies as we move from inside the insulating sphere, to inside the conducting shell, to outside both the spheres.

To determine the magnitude of the electric field (in N/C) at various distances from the center of the spheres, we use the principles of Gauss's law and the properties of the spherical capacitor. Given the values of the radii and charges, the electric field can be represented as É = E(r)î.

We can apply Gauss's law over a closed spherical surface S of radius r that is concentric with the conducting sphere. The enclosed core for the insulating sphere with radius a=5.00 cm charge Q=3.00μC is +Q, and for the outer sphere it is -q which is the net charge. The electric field for a point within the insulating sphere, outside the insulating sphere but within the conducting shell, within the conducting shell, and outside both the spheres can be calculated by applying Gauss's law.

The electric field in any sphere is directly proportional to the distance from the center when within the insulating sphere, but in the conducting shell, it's zero because there is no charge within this volume. When the distance is further away from the spheres, the electric field decreases, following the inverse of the square of the distance from the center of the sphere.

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The correct order of density, from least to greatest, is white dwarfs < black holes < neutron stars.

White dwarfs are relatively less dense compared to black holes and neutron stars. They are the remnants of low- to medium-mass stars, where the core has collapsed and the outer layers have expanded. The density of a white dwarf is typically on the order of \(\(10^6\)\) to \(\(10^9\)\)kilograms per cubic meter.

Black holes, on the other hand, are incredibly dense objects formed from the gravitational collapse of massive stars. They have an extremely high density, where the matter is compressed to a singularity. The density of a black hole is considered infinite, as its mass is concentrated in a single point.

Neutron stars are also highly dense objects that result from the collapse of massive stars. They are composed primarily of neutrons packed together tightly. The density of a neutron star is incredibly high, typically ranging from \(\(10^{17}\)\) to \(\(10^{18}\)\) kilograms per cubic meter. Neutron stars are denser than white dwarfs but less dense than black holes, making them the middle option in terms of density.

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Answer:

a. 25.80 m

b. 4.59s

Explanation:

(refer to attached for reference)

Part a :

We are asked to find the distance the ball rises "s"

The relevant equation of motion is:

v² = u² + 2as,

Given:

Initial speed, u = 22.5 m/s

As the ball rises, we can also deduce the following:

1) the ball rises to a maximum height before it starts falling again. At the point of maximum height, for a split second, speed of the ball is zero.

Hence we can deduce that final speed, v = 0 m/s

2) the only acceleration acting on the ball as it travels is gravity acting downward. Hence the acceleration that the ball experiences is equal to negative gravitational acceleration, i.e a = - 9.81 m/s²

Simply substitute the above values into the equation above and solve for distance "s"

v² = u² + 2as

0² = 22.5² + 2(-9.81)s

19.62s = 22.5²

s = 22.5² / 19.62 = 25.80 m (answer)

Part b:

We are asked to find how long the ball takes to rise and fall again before it is caught. We are also told that the time for the ball to rise is the same as the time for the ball to fall. Hence all we need to do is find the time taken for the ball to rise and then multiply that by 2 to get our answer.

In this case, the relevant equation of motion is:

v = u + at, where t is the time taken for the ball to rise.

simple substitute the above known values into this equation and solve for t

v = u + at

0 = 22.5 + (-9.81)t

9.81t = 22.5

t = 22.5/9.81

t = 2.29 s

hence the time taken to rise AND fall = 2t = 2(2.29) = 4.59s (answer)

The ball will rise to the height of 25.8 meters and the ball will remain in air for 4.5 seconds for both rise and fall of the ball.

In the field of physics, the idea and practice of motion are crucial. Numerous words and elements are important to the motion. Such as length, breadth, depth, velocity, and so forth. Static or variable velocity is a property of moving things. Thus, if the motion is accelerating, the initial velocity and the ultimate velocity may differ. The pace at which an object's position changes in relation to time is known as its velocity.

According to the question, the given values are :

Initial Speed, u = 22.5 m/s

Final Speed, v = 0 m/s

Acceleration, a = -9.8 m/s²

Use equation of motion :

v = u + at

0 = 22.5 + (-9.8)(t)

t = 22.5 / 9.8

t = 2.2 seconds.

(a) The height rise of the ball will be :

s = ut + 1/2 at²

s = 22.5(2.2) + 1/2(-9.8)(2.2)²

s = 49.5 - 23.71

s = 25.8 meters.

(b) The time that the ball remain in the air :

2(t) = 2 (2.2)

= 4.4 seconds.

Hence, the ball will cover a distance of 25.8 meters and the time it will be in the air is 4.4 seconds.

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Answer:

my middle school life was horrible and still is sadly ); could you please do my recent brainless <333

Explanation:

My middle school life was eh.i allways got assumed that i was a elementry kid when i was and 6 and 7 grade.until 8th when i hit my grow spurt.my voice end up getting really deep in 8th grade too.tho in 8th i got sent to a certain  type of scholl for kids who did bad because of some dum teacher who lied that i hit her when i actually just went to her desk to get my phone sence she saw it in my pocket and took it away.i got sent there for 3 months and was worst thing ever.the treated us like prisoners in that school and made us tacky uniforms that i refused to where.i believe it was a school for 7th-12th.after my expierence at that school my expierence in 8th grade was almost done.i end up being popular at school for being that kid who hit the teacher.ofc that was like 2 years ago im 10th now.i dont really remember my 6th and 7th grade year.only thing i rember is i was a trouble maker and still am a trouble maker.

hope that helped you:)

please make my answer brainiest as im trying get 4 brainiest answers

The correct answer to the question is D) None of the given; all colors emerge at the same time when the beam of white light is incident on a thick glass plate with parallel sides at an angle of 0° with the normal.

When white light enters a thick glass plate, it undergoes refraction, which means the light waves change direction and speed as they move through the glass. This causes the different colors of the spectrum to separate, with red being the least refracted and violet being the most refracted.

The angle at which the light enters the glass plate determines how much it is refracted, with greater angles causing more refraction. As a result, the color that emerges first from the other side of the glass plate will depend on the angle of incidence.

At an angle of 0°, the light will not be refracted at all and all colors will emerge at the same time. As the angle increases, the colors will start to separate and the order in which they emerge will be: red, orange, yellow, green, blue, indigo, and violet.

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The answer is B) violet. When white light enters a thick glass plate at an angle, it undergoes refraction and separates into its constituent colors. This is because different colors have different  violets and Wavelength therefore bend at different angles. The color with the shortest wavelength, which is violet, bends the most and emerges first from the other side of the glass plate.
B) violet

When a beam of white light is incident on a thick glass plate at an angle between 0° and 90° with the normal, the light is refracted, and colors separate due to dispersion. Violet light has the shortest wavelength and is refracted more than the other colors, causing it to emerge from the other side of the glass first.

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There are some general trends that can be observed in the changes in the rankings of events from the original Holmes and Rahe (1967) scale to the new weighting schema.

Firstly, some of the events that were considered to be the most stressful in the original scale, such as "death of a spouse" and "divorce", continue to be ranked high in the new scale.

However, some events that were ranked lower in the original scale, such as "business readjustment" and "change in financial state", have moved up significantly in the new scale. This suggests that changes in financial circumstances have become more significant stressors over time.

In addition, some events that were not included in the original scale, such as "trouble with boss" and "minor violations of the law", are now included in the new scale and have been given relatively high rankings. This suggests that changes in work-related stressors and legal issues have become more significant stressors in modern times.

Overall, the new weighting schema reflects some changes in the nature of stressors over time and provides a more up-to-date ranking of events that are most likely to cause stress in people's lives.

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Answer:

the temperature and volume

Answer:

50 N ---->

Explanation:

Opposing sides get subtracted so~

25-25 cancels out to zero so there is 0N

100 -50 equals 50 N ->

Along vertical direction, net force is 0N and along horizontal direction, the net force is 50N directed towards right.

To determine the answer, we need to know about how to calculate the net force.

To determine the net force along any direction, we have to sum all the forces that are directed along that direction.

Forces that directed along vertical direction are

Net force = 25 N (vertically upward) + 25 N (vertically downward)

                = 25 N - 25N = 0N

Here, we take '+ sign' for upward direction and '- sign' for downward direction.

Forces that directed along horizontal direction are

Net force= 100 N towards right + 50 N towards left

               = 100N - 50N

               = 50 N (towards right)

Here, we take '+ sign' for horizontally right direction and '- sign' for horizontally left direction.

Thus, we can conclude that 0 N is the net force along vertical direction and 50 N is the net force along horizontal direction.

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Answer:

false

Explanation:

Answer:

The answer is B false

Explanation:

Gamma radiation is not composed of both neutrons and protons.

a) To raise the elevator at 35.0 cm/s, the disk must turn at approximately 0.044 rpm.

b) To accelerate the elevator at 18g, the angular acceleration of the disk must be approximately 141.4 rad/s^2.

c) The angle through which the disk has turned when it has raised the elevator 2.55 m between floors is approximately 2.04 radians.

To find the rpm of the disk required to raise the elevator at a speed of 35.0 cm/s, we can start by finding the speed at which the cable is moving over the disk. The circumference of the disk is

C = πd = π(2.50 m) = 7.85 m

The distance traveled by the cable in one revolution of the disk is equal to the circumference of the disk. Therefore, the speed of the cable is

v = C × rpm

To find the rpm required to raise the elevator at 35.0 cm/s, we can solve for rpm

35.0 cm/s = 0.35 m/s

0.35 m/s = 7.85 m × rpm

rpm = 0.35 m/s ÷ 7.85 m = 0.044 rpm

Therefore, the disk must turn at approximately 0.044 rpm to raise the elevator at a speed of 35.0 cm/s.

To accelerate the elevator at 18g, we need to find the force required:

F = ma = (18g)(m)

where m is the mass of the elevator. We can rearrange this equation to solve for m

m = F ÷ (18g)

To find the angular acceleration of the disk required to accelerate the elevator, we can use the equation

α = a ÷ r

where α is the angular acceleration, a is the linear acceleration, and r is the radius of the disk. The radius of the disk is half the diameter, or 1.25 m.

α = (18g) ÷ (1.25 m)

α ≈ 141.4 rad/s^2

Therefore, the angular acceleration of the disk must be approximately 141.4 rad/s^2 to accelerate the elevator at 18g.

To find the angle through which the disk has turned when it has raised the elevator 2.55 m between floors, we can use the equation

θ = s ÷ r

where θ is the angle in radians, s is the distance traveled by the cable, and r is the radius of the disk.

The distance traveled by the cable is equal to the difference in height between the floors, or 2.55 m.

θ = 2.55 m ÷ 1.25 m

θ ≈ 2.04 radians

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The correct realistic problem for the given equation is problem 1 in which the electric field strength of the disc is half its value at the center of the disk.

We know that,

Electric field of a charged disc at a distance along its axis is given by,

E = σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) )

Electric field at the centre of a charged disc is given by,

\(E_{c}\) = σ / 2 ε ( Since at centre, x = 0 )

Distance along the axis of a charged disk, where electric field strength's value is half its value at the center of the disk.

\(E_{x}\) = \(E_{c}\) / 2

σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) ) =  ( σ / 2 ε ) / 2

x / √ ( \(x^{2}\) + \(r^{2}\) ) = 1 / 2

4 \(x^{2}\) = \(x^{2}\) + \(r^{2}\)

3 \(x^{2}\) = \(r^{2}\)

x = r / √ 3 ,which is the correct distance, when magnitude is half its value from centre.

Electric field is a field that surrounds electrically charged particles that exerts force on other charged particles in the field.

Therefore, the given equation is suitable for Electric field of a charged disc at a distance along its axis where electric field strength's value is half its value at the center of the disk.

The given question is incomplete. The completed question is

You are given the following equation to solve a problem:

σ / 2 ε ( 1 - x / √ ( \(x^{2}\) + \(r^{2}\) ) ) = \(E_{c}\) = σ / 2 ε

Choose the most realistic problem for which this could be the correct equation.

1 ) At what distance along the axis of a charged disk is the electric field strength half its value at the center of the disk? Give your answer in terms of the disk's radius R.

2 ) At what distance along the axis of a charged disk is the electric field strength double its value at the center of the disk? Give your answer in terms of the disk's radius R.

3 ) At what distance along the axis of a charged square is the electric field strength double its value at the center of the square? Give your answer in terms of the square's side R.

4 ) At what distance along the axis of a charged square is the electric field strength half its value at the center of the square? Give your answer in terms of the square's side R.

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Answer:

 its not long dummy, its your imagination

Explanation:

Answer:

1. Size

2. Shape

3. Color

Explanation:

Sorry if this is no help

Resistance(R) of a device is given by

Final answer is :- 2.67 ohm