Answer:
E = h ν = h c / λ = 6.63E-34 * 3.00E8 / 632.8E-9 m energy of 1 photon
E = 3.14E-19 joules
1 mw = 1.00E-3 j/sec 1 milliwatt of power
N = 1.00E-3 * 2.3 / 3.14E-19 = 7.32E15 photons / sec
The helium-neon laser emits photons at a rate of 2.3 x 10^6 photons per second.
This is calculated by dividing the power output of 2.3 mW (2.3 x 10^-3 W) by the energy of a single photon (hc/λ = 6.626 x 10^-34 J.s x 3 x 10^8 m/s / 632.8 x 10^-9 m = 3.9 x 10^-19 J) to get the number of photons per second.
Photons are emitted at a rate that is proportional to the power output of the laser.
To calculate the rate of photon emission, we need to divide the power of the laser (2.3 mW or 2.3 x 10^-3 W) by the energy of a single photon (E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength). This calculation results in 2.3 x 10^6 photons per second being emitted by the helium-neon laser.
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Which, if any, of the following statements concerning the work done by a conservative force is FALSE? a. It can always be expressed as the difference between the initial and final values of a potential energy function. b. It is independent of the path of the body and depends only on the starting and ending points. c. When the starting and ending points are the same, the total work is zero. d. All of the above statements are true. e. None of the above statements are true
The FALSE statement concerning the work done by a conservative force is (b) It is independent of the path of the body and depends only on the starting and ending points.
For a conservative force, work done is path-independent only for the net work done around a closed path. This is because the net work done around a closed path is zero. However, for any other path, the work done by a conservative force depends on the path taken and not just the initial and final points. This is because the force may vary at different points in the path, and the work done is the integral of the force over the path.
The other statements (a) It can always be expressed as the difference between the initial and final values of a potential energy function, and (c) When the starting and ending points are the same, the total work is zero, are both true statements concerning the work done by a conservative force.
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7
1. A 1-kilogram rock is dropped from a cliff 90 meters
high. After falling 20 meters, the kinetic energy of
the rock is approximately
The Kinetic energy of the rock is 196 J.
To calculate the Kinetic energy of the rock, we apply the formula below.
Formula:
K.E = mgh............. Equation 1Where:
K.E = Kinetic energy of the rockm = mass of the rockh = Height of fallg = acceleration due to gravity.From the question,
Given:
m = 1 kgh = 20 mg = 9.8 m/s²Substitute these values into equation 2
K.E = 1×20×9.8K.E = 196 JHence, The Kinetic energy of the rock is 196 J.
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a child rides her bicycle in her level drive way. what form of energy does she possess A. Elastic B. Nuclear C. Potential D. Kinetic
Answer:
Kinetic Energy
Explanation:
Kinetic energy is energy due to motion.
Answer:
D
Explanation:
Elastic energy is energy stored in a object when there is a strain or compression on the object.
Nuclear energy is the energy found in the nucleus of an atom.
Potential energy is energy that an object stores because of its position to other objects.
Kinetic energy is the energy that an object has due to motion.
The child is riding her bicycle, therefore the child is in motion. So, the correct answer must be D. Kinetic energy
A hair dryer with a resistance of 12.0 W and a lamp with a resistance of 125 W are connected in parallel to a 125-V source through a 1.50-W resistor in a series. Find the current through the lamp when the hair dryer is on.Question 2 options:1) 0.880 A2) 8.80 A3) 88.0 A4) 880 A
Given:
Resistance of hair dryer, R1= 12.0 Ohms
Resistance of lamp, R2 = 125 ohms
Voltage of source = 125 V
Resistance = 1.50 ohms
Let's find the curent through the lamp when the hair dryer is on.
Here, the lamp and dryer are connected in parralel. To calculate the equivalent resistance, apply the formula:
\(\begin{gathered} \frac{1}{R_p}=\frac{1}{R_1}+\frac{1}{R_2} \\ \\ R_p=\frac{R_1R_2}{R_1+R_2} \\ \\ R_p=\frac{12\ast125}{12+125} \\ \\ R_p=\frac{1500}{137} \\ \\ R_p=10.9\text{ }\Omega \end{gathered}\)Now, the Rp and the resistor are connected in series.
To find the equivalent resistance in series, we have:
\(\begin{gathered} R_{eq}=R_p+R \\ \\ R_{eq}=10.9+1.50=12.4\text{ }\Omega \end{gathered}\)We now have a single resistor flowing through the 125 voltage source.
To find the current, apply Ohm's law:
\(V=I\ast R\)Solve for the current (I), where:
V = 125 volts
R = 12.4 Ω
Thus, we have:
\(\begin{gathered} I=\frac{V}{R} \\ \\ I=\frac{125}{12.4}=10.1\text{ A} \end{gathered}\)Since the resistor and Rp are connected in series, we have:
\(\begin{gathered} V_p_{}=I_p\ast R_p \\ \\ V_p=10.1\ast10.9=110.1\text{ V} \end{gathered}\)Since the dryer and the lamp are in parallel, the voltage through them are the same.
V(dryer) = V(lamp) = 110.1 Volts
To find the current flowing through the lamp, we have:
\(\begin{gathered} I_{\text{lamp}}=\frac{V_{lamp}}{R_{\text{lamp}}} \\ \\ I_{\text{lamp}}=\frac{110.1}{125}=0.88\text{ A} \end{gathered}\)Therefore, the current through the lamp when the hair dryer is on is 0.880 ampere.
ANSWER:
1) 0.880 A
Help!!!!
Which locations would be considered a target hazard?
mailbox unit on a highway
city baseball field
bus or train station
neighborhood playground
Answer:bus or train station is the answer of your question
hope it is helpful to you
5 V battery with metal wires attached to each end.
The figure shows two wires connected to a battery’s positive and negative terminals. These wires stop short of completing a circuit. Four points are marked on the wires. Point 1 is at the end of the wire connected to the positive terminal. Point 2 is at the negative terminal. Point 3 is at the positive terminal. Point 4 is at the end of the wire connected to the negative terminal.
What are the potential differences ΔV12=V2−V1, ΔV23=V3−V2, ΔV34=V4−V3, and ΔV41=V1−V4?
Enter your answers numerically separated by commas
The potential differences is ΔV12=V2−V1=0V
ΔV23=V3−V2=5V
ΔV34=V4−V3= 0V
and ΔV41=V1−V4=-5V
From the figure, there is no connection between the points 1 and 4 . Hence, the potential at the points 4 and 3 is same and is equal to zero.
\(\Delta V_{34} & =V_4-V_3 \\& =0\)
Similarly, the potential at the points 1 and 2 is same and is equal to zero.
\(\Delta V_{12} & =V_2-V_1 \\& =0\)
The potential difference between the points 4 and 1 is equal to potential difference between the points 3 and 2.
Given that the potential difference across the points 3 and 2 is,
\(\Delta V_{23} & =V_3-V_2 \\& =5 \mathrm{~V}\)
The potential difference between the points 4 and 1 is also 5V.
\(\Delta V_{41} & =-\Delta V_{23} \quad\left(\because \Delta V_{23}=\Delta V_{14}\right) \\& =-5 \mathrm{~V}\)
Therefore, the required answer is 0,5V, 0,-5V.
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Note:- The correct question could be,
5 V battery with metal wires attached to each end.
The figure shows two wires connected to a battery’s positive and negative terminals. These wires stop short of completing a circuit. Four points are marked on the wires. Point 1 is at the end of the wire connected to the positive terminal. Point 2 is at the negative terminal. Point 3 is at the positive terminal. Point 4 is at the end of the wire connected to the negative terminal.
What are the potential differences ΔV12=V2−V1, ΔV23=V3−V2, ΔV34=V4−V3, and ΔV41=V1−V4?
Enter your answers numerically separated by commas
A balky cow is leaving the barn as you try harder and harder to push her back in. In coordinates with the origin at the barn door, the cow walks from x = 0 to x = 6.9 m
as you apply a force with x-component Fx
= -[20.0 N
+ (3.0 N/m
) x
].
The force that pushed the cow back into the barn produced work using the formula W = -831.45 J.
What constitutes net force's components?The total vector of all applied forces to an object is known as the net force. The result of the fact that a force is a vector and that two forces of equal magnitude and opposite direction cancel each other out is the net force.
W = ∫ F(x) dx
In this instance,
Fx = -[20.0 N + 3.0 N/m]x gives the force.
The displacement of the cow is:
Δx = 6.9 m
Integrating this expression gives:
W = ∫ F(x) dx
= -∫ (3.0 N/m) x dx - ∫ 20.0 N dx
= -1.5 N/m * x² - 20.0 N * x + C
where C is the constant of integration.
W(x=0) = -1.5 N/m * 0² - 20.0 N * 0 + C = 0
Therefore, C = 0, and the work done by the force is:
W = -1.5 N/m * x² - 20.0 N * x
W = -1.5 N/m * (6.9 m)² - 20.0 N * 6.9 m
W = -831.45 J
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Question:
A balky cow is leaving the barn as you try harder and harderto push her back in. In coordinates with the origin at the barndoor, the cow walks from x = 0 tox = 6.9{rm m}as you apply a force withx-componentF_x= -[20.0{rm N}+ (3.0{rm N/m})x].
How much work does the force you apply do on the cow duringthis displacement?
How many bones does the baby have and why does the baby has more bones than the older ones
Answer:
300
Explanation:
when the baby are born then they would have 300 bones but when they grow they would have 206 cause when they grow that 94 bones would convert into different kind of proton and energy I guess
I’ll name u BRAINLIEST if u get this right
differentiate between earthworm and housefly
Answer:
Earthworm lives in the soil, eats the soil which has organic matter such as decaying vegetation or leaves and crawls. While housefly lives in dirty places, feeds on faeces and flies.
Hope I get a brainliest answer.
Calculate the reading on voltmeter v²
The reading of the voltmeter can be determined by finding the potential difference across the 2Ω resistance by using the value of current in the circuit. V=IR, here V is the potential difference across a resistance R through which a current I is flowing.
A small canon is placed on top of a fortification the cannon ball leaves the muzzle of the canon with a speed of 85 m/s
Answer:
Speed of cannonball just before it hits the ground is 90.77 m/s
Explanation:
Complete Question
A small cannon is placed on top of a fortification. the cannonball leaves the muzzle of the cannon with a speed of 85 m/s at an angle of 25°c above the horizontal. just before the cannonball hits the ground, the vertical component of velocity is 48 m/s downward. what is the speed of the cannonball just before it hits the ground? ignore air resistance.
Solution
Given
Speed = 85 m/s
The angle = 25 degrees
When it will hit the ground, then vertical velocity = 48 m/s
However, in the projectile motion, the horizontal component will not change
Vr = V cos (theta) = 85 * cos25
Speed of cannonball just before it hits the ground is
V’ = Sqrt (48^2 + (85 * cos 25)^2) = 90.77 m/s
how far must the microphone be moved to the right to find the first intensity minimum?
For your specific scenario, we need to consider the placement of the microphone relative to the two sound sources. Assuming the sources are equidistant from the microphone and are emitting identical frequencies, there will be a series of intensity maxima and minima as the microphone is moved horizontally.
To find the first intensity minimum, we need to locate the point where the path difference between the two sound waves is half of a wavelength. This can be calculated using the equation:
path difference = d * sin(theta)
Where d is the distance between the sound sources and theta is the angle between the two sources as seen from the microphone. Once we have the path difference, we can use the formula:
path difference = n * wavelength / 2
Where n is an odd integer (1, 3, 5, etc.) and wavelength is the distance between two consecutive peaks of the sound wave.
With these equations, we can determine the distance the microphone needs to be moved to the right to reach the first intensity minimum. This will vary depending on the specific values of d, theta, and wavelength, but can be calculated using the methods described above. Overall, finding the first intensity minimum requires an understanding of interference and some basic calculations using the path difference and wavelength formulas.
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Help plz..,, due tommorow
the speed of a tortoise and a hare are 1m/s and 3m/s. the mass of hare is 5kg and the tortoise is 20kg. which has greater momentum? WITH MATHEMATICAL EXPLANATION PLZ!!
Answer: tortoise
Explanation:
Given the following :
Speed of tortoise = 1m/s
Speed of hare = 3m/s
Mass of hare = 5kg
Mass of tortoise = 20kg
Momentum = product of Mass and velocity
Momentum of hare = mass of hare × Velocity of hare
Momentum of hare = 5kg × 3m/s = 15kgm/s
Momentum of tortoise = mass of tortoise × Velocity of tortoise
Momentum of tortoise = 20kg × 1m/s = 20kgm/s
Therefore, tortoise has a greater momentum than hare.
Answer:
The equations are both written in slope-intercept form, so I can see that the slope of one equation is 2 and the other is 8. If the slopes of lines are different, they will always intersect at a point.
Explanation:
HELP PLS The current in the flashlight is 0.50 A, and the voltage is the sum of the voltages of the three individual batteries of 1.5V. What is the power delivered to the bulb of the flashlight? . If the flashlight is left on for 3.0 min, how much electric energy is delivered to the bulb?
0.11 W & 6.9 J
2.3 W & 4.1×10^2 J
1.1 W & 14J
4.5 W & 2×10^2 J
The current in the flashlight is 0.50 A, and the voltage is the sum of the voltages of the three individual batteries of 2.3 W & 4.1×\(10^2\) electric energy is delivered to the bulb.
To calculate the power delivered to the bulb of the flashlight:
Power (P) = Current (I) * Voltage (V)
Power (P) = 0.50 A * 4.5 V
Power (P) = 2.25 W
Hence the delivered power is 2.25 W.
To calculate the electric energy delivered to the bulb, we can use the formula:
Time (t) = 3.0 min * 60 s/min
Time (t) = 180 s
Electric Energy (E) = 2.25 W * 180 s
Electric Energy (E) = 405 J
So, the electric energy delivered to the bulb is 405 J.
Thus, the correct answer is option: 2.3 W & 4.1×\(10^2\) .
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A drop in room temperature to 65of that causes the heater to turn on provides an example of a(an):_______
Answer:
stimulus
Explanation:
2
A simple circuit contains a battery and a resistor.
Over 3.0 hours, 29 000 C of charge passes through the resistor.
Calculate the current flowing through the circuit during this time.
Give your answer to two significant figures.
Answer:
Approximately \(2.69\; {\rm A}\).
Explanation:
Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:
\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).
Electric current \(I\) is the rate of flow of electric charge.
In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:
\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).
an object is located 18 cm from a concave mirror whose focal length is 6 cm. the size of the object is 3 cm. what is the position of the image
The image formed is real, inverted, and reduced in size.
As given, an object is situated 18 cm from a concave mirror with a focal length of 6 cm. The size of the object is 3 cm. To find out the position of the image, we need to follow the below-given steps:Calculation:Using the formula,
1/f = 1/u + 1/v, where f is the focal length,
u is the distance between the object and the mirror, and v is the distance between the image and the mirror.
1/f = 1/u + 1/v(1/6) = (1/18) + (1/v)1/v = 1/6 - 1/18v = -9 cm (Image is formed at 9 cm behind the mirror)Thus,
the position of the image is 9 cm from the concave mirror.To calculate the magnification of the image, use the formula:
Magnification (m) = v/u
Given that u = -18 cm (as the object is on the left-hand side),
and v = -9 cm
Magnification (m) = -9 / (-18)
= 0.5It indicates that the image formed is half the size of the object.
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The difference in electric potential between a thunder cloud and the ground is 2.13 108 V. Electrons move from the ground which is at a lower potential to the cloud which is at a higher potential. Determine the change in electric potential energy of one of the electrons that move to the cloud. 3.41*10**-11 Incorrect: Your answer is incorrect. How is the change in electric potential energy related to the charge and the potential difference
The change in electric potential energy of one of the electrons that move to the cloud is 3.41 * 10^−19 J.
The change in electric potential energy of one of the electrons that move to the cloud is 3.41 * 10^−19 J. How is the change in electric potential energy related to the charge and the potential difference?The change in electric potential energy is related to the charge and the potential difference.
The relation can be as:
ΔU = qΔV Where,ΔU is the change in electric potential energy.
q is the charge.ΔV is the potential difference.
Substitute the given values into the formula;
we get,ΔU = qΔVΔU = (−1.6 × 10^−19 C) (2.13 × 10^8 V)ΔU = −3.41 × 10^−11 J
One of the electrons that travels to the cloud experiences a change in electric potential energy related to the charge and the potential difference of 3.41 * 1019 J.
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According to Jean Piaget, unrealistic idealism often occurs in adolescence as a result of __________. Rational thought egocentrism environmental conditions lack of education.
According to Jean Piaget, unrealistic idealism often occurs in adolescence as a result of egocentrism. The inability to distinguish between self and others is referred to as egocentrism.
What is egocentrism?The inability to distinguish between self and others is referred to as egocentrism. It is, more precisely, the incapacity to effectively assume or comprehend any viewpoint other than one's own.
Egocentrism may be present in every stage of life, including childhood, adolescence, and maturity.
Hence option B is correct. According to Jean Piaget, unrealistic idealism often occurs in adolescence as a result of egocentrism.
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Answer:
egocentrismgot it right⬇️✅
Standard Number to Scientific Notation
1) 653,000
2) 129,430
3)2,263
4) 0.0148
0.0904
Answer:
1) 6.53 × 10^5
2) 1.2943 × 10^5
3) 2.263 × 10^3
4) 1.48 × 10^-2
5) 9.04 × 10^-2
a small rocket is propelled forward by expelling gas at a rate of 3.63 kg/s. the exhaust speed is 54.6 m/s. what is the magnitude of the thrust force?
A small rocket is propelled forward by expelling gas at a rate of 3.63 kg/s and the magnitude of the thrust force of the rocket is 198.198 N.
How to calculateIn order to find the magnitude of the thrust force of a small rocket that is propelled forward by expelling gas at a rate of 3.63 kg/s and an exhaust speed of 54.6 m/s, we can use the formula for thrust force:
Thrust force = mass flow rate x exhaust velocity
Thrust force = 3.63 kg/s x 54.6 m/s
Thrust force = 198.198 N
Therefore, the magnitude of the thrust force of the rocket is 198.198 N.
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A student completes a PET experiment using chloroplasts from leaves lacking pigments that absorb in the 550 nm to 600 nm wavelength range. Which color of light should they avoid in their experiment if they want to measure activity at different wavelengths? Absorbance 360 760 460560660 Wavelength (nm) O Blue O Orange O Yellow O Red O Violet Light Absorption Spectrum of Spinach Extract
The student should avoid using yellow light if they want to measure activity at different wavelengths.
Yellow light should not be used since it lacks the pigment necessary to absorb wavelengths between 550 and 580 that will cause it to be completely ineffective.
Color Wavelength (nm)
Red 650 - 800
Orange 590 - 640
Yellow 550 - 580
Blue 460 - 480
Indigo 440 - 450
Violet 390 - 430
In physics, a periodic wave's wavelength is the length over which its form repeats. It is a characteristic of other spatial wave patterns as well as traveling and standing waves.
It is the separation between two consecutive positions on a wave that correspond to the same phase, such as two close-by crests, troughs, or zero crossings. The reciprocal of wavelength is the spatial frequency. Wavelength is usually denoted by the Greek letter lambda ().
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What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity of 5. 0 × 103 m/s? 3. 8 N 38 N 3. 8 × 105 N 3. 8 × 106 N.
The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.
What is the force exerted on the charge?Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.
when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.
Mathematically the force exerted on the charge will be
F=qvBsinα
F= force acting on the charge
v = velocity of charge
q = charge
F=qvBsinα
F=2.5×10⁻⁶×5.0×10³×3.0×10²
F=37.5 N
Hence The force acting on the charge will be 3.75 N.
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F = q V B sinα
Where F is the force applied to a moving charge.
V = charge velocity
q stands for charge.
α = angle between V and B directions
As a result, the moving charge is subjected to a force of 3.75 Newton.
relative to sphere at the speed of sphere Z is _ m/s
We are given that a sphere Z moves with a relative speed of 1 m/s with respect to sphere X which moves at 5 m/s. Let's draw the velocity vectors of the spheres:
Where:
\(\begin{gathered} v_x=\text{ velocity of sphere x} \\ v_z=\text{ velocity of sphere z} \end{gathered}\)From the relative velocity equation we have:
\(v_z=v_r+v_x\)Where:
\(v_r=\text{ velocity of z relative to x}\)Since we are given the relative velocity we can plug in the values to get the velocity of "z":
\(\begin{gathered} v_z=1\frac{m}{s}+5\frac{m}{s} \\ \\ v_z=6\frac{m}{s}_{} \end{gathered}\)Now, we do the same but now using the sphere Y:
Now, we use the relative velocity equation for these velocities:
\(v_z=v_r+v_y\)In this case, we have that:
\(v_r=\text{ velocity of z with respect to y}\)Now, we subtract the velocity of "y" from both sides:
\(v_z-v_y=v_r\)Substituting the values:
\(6\frac{m}{s}-2\frac{m}{s}=v_r\)Solving the operations:
\(4\frac{m}{s}=v_r\)Therefore, the velocity of "Z" relative to "Y" is 4 m/s.
for each of the following scenarios, determine whether or not the energy of the given system remains constant between the initial and final states indicated. vertical and horizontal spring a block is hung from a vertical spring that is connected to the ceiling. the block is made to oscillate vertically. call the initial state when the block is at its highest position and the final state when the block is at its equilibrium position. for which of the following systems does the energy remain constant? click for a hint a. system: block earth b. system: block c. system: block ceiling ( spring) earth d. none of the above. a block on a table (friction between the table and the block is not negligible) is attached to a wall via a horizontal spring. you give the block a brief push so that the block travels horizontally. call the initial state when the spring first reaches its maximum stretch in the initial direction of motion. the final state is when the spring first reaches its zero stretch length. for which of the following systems does the energy remain constant? click for a hint a. system: table b. system: block wall ( spring) table c. system: block d. system: block wall ( spring) e. system: block table f. none of the above.
For the vertical and horizontal spring scenario, the energy remains constant for the system: block ceiling (spring), and earth The correct answer is (option c).
For the block on a table with a horizontal spring scenario and considering friction, the energy does not remain constant for any of the given systems. The correct answer is option f.
For the first scenario with the vertical spring, the energy of the system remains constant between the initial and final states since the system is conservative.
At the highest position, the block has gravitational potential energy, and at the equilibrium position, the block has only kinetic energy. The total mechanical energy of the system remains constant, neglecting any energy losses due to friction or air resistance. Therefore option c is correct
For the second scenario with the horizontal spring, the energy of the system does not remain constant between the initial and final states since there is friction between the block and the table.
The system is not conservative, and some energy is lost due to friction. Therefore, the energy of the system decreases between the initial and final states, and none of the options given accurately describes the system. Therefore option f is correct.
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What kind of boundary is shown in the image below?
Convergent
Divergent
Collisional
Transform
Answer:
ambt kaon✌️jhrhriekeieieieiei
Explanation:
iwuejejwiowksj
What does it mean when the wave
crests of a transverse wave move
closer together?
A. The amplitude is getting bigger.
B. The amplitude is getting smaller.
C. The wavelength is getting smaller.
D. The wavelength is getting bigger.
When the wave crests of a transverse wave move closer together it means the wavelength is getting smaller.
Briefing :The wavelength of a transverse wave is the distance from one peak to the next or from one dip to the next. The wavelength gets shorter as the crests or troughs get closer together. The wavelength increases as the distance between the crests and troughs increases.
How wavelength affect a transverse wave?One way to gauge the size of waves is by their wavelength. It is the separation of two matching waves' neighboring points. In a transverse wave, the medium's particles vibrate up and down perpendicular to the wave's path of propagation. A longitudinal wave's wavelength can be calculated as its length. A crest and a trough make up a transversal. The largest upward displacement is at the crest, while the maximum downward displacement is at the dip.
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Answer:
C. The wavelength is getting smaller.
Explanation:
A dishwasher has a power rating of 1200 W. Work out how long it would take to transfer 480 kJ of energy.
The dishwasher would need to transfer 480 kJ of energy for 400 seconds, or 6 minutes and 40 seconds.
How are power and force related?Power is determined by the product of force, velocity, and distance traveled (in the force's direction). For those looking to enter the teaching profession in the state of Uttar Pradesh, this is a fantastic opportunity. Voltage and current together produce electrical power P=VXI.
time = energy / power
480 kJ = 480,000 J
time = energy / power
time = 480,000 J / 1200 W
time = 400 seconds
Hence, for the dishwasher to transfer 480 kJ of energy, it would take 400 seconds, or 6 minutes, 40 seconds.
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