A hollow sphere of radius 0.5 m and mass 10 kg, rolls on a horizontal surface. Its centre of mass has speed 6 m/s. Magnitude of work required to stop it is

Answer:

Force:

F = 3130 N

Explanation:

Given:

m = 1500 kg

V₀ = 5 m/s

V = 25 m/s

Δt = 10.0 s

μ = 0.009

g = 9.8 m/s²

___________

F - ?

1)

Car acceleration:

a = (V - V₀) / Δt = (25 - 5) / 10.0 = 2 m/s²

2)

Friction force:

F₁ = μ*m*g

3)

According to Newton's second law:

m*a  = F - F₁

Force:

F = m*a + F₁

F = m*a + μ*m*g

F = m*( a + μ*g) = 1500*(2 + 0.009*9.8) ≈ 3130 N

Answer:

1. While boiling replace the cap and allow it to cool. Vapours inside condense and form water creating vacuum above them. Observation - The can crumbles due to air pressure from outside. This proves that air exerts pressure.

2. Measure the volume of the liquid displaced when the object is submerged. Measure the initial volume of water in graduated cylinder. Submerge the irregular object. Measure the final volume of the water.

— The difference between the initial volume and the final volume is the volume of the object.

hope can help ^_^

The magnitude of the torque exerted by the jack is equal to 16778.33 N.m.

Torque can be defined as the measurement of the force that can cause the rotation of a body about an axis. The force exerted can cause an object to accelerate, in the same way, torque causes angular acceleration. Therefore, torque can be defined as the rotational equivalent of linear force.

Given, the mass of the car, m = 1130 Kg

The length of the car, L = 3.05 m

The angle made of the car with the horizontal, θ = 8.0°

To maintain the static equilibrium of the car, we need:

\(\displaystyle \tau _{jack } =\tau _{weight}\)

\(\displaystyle \tau _{jack } =mg\times (3.05- 1.12-0.40)\times cos\theta\)

\(\displaystyle \tau _{jack } =1130\times 9.8 \times 1.53\times cos(8)\)

\(\displaystyle \tau _{jack } =16778.33 Nm\)

Therefore, the magnitude of the torque is 16778.33 Nm.

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Answer:

d: 870 Hz

Explanation:

The root mean square voltage Vrms of the circuit is 15.49 V.

The voltage of the resistor vR is 10.4 V.

The voltage of the inductor vL is 11.49 V.

The voltage of the capacitor vC is 0.035 V.

RMS voltage of the circuit is calculated as follows:

Vrms = -V₀ sin ωt = -29 * sin (260* 22* 10⁻³) = 29 * 0.534 = 15.49 V

XI = ωL = 260* 0.85 = 221 ohms

Xc = 1/ωc = 1/(260 * 5.75* 10⁻³) = 10³/1495 = 0.67 ohm

Z = √[R² +(XI - Xc)²] = √[200² + (221 - 0.67)²] = √[200² + 220.33²]

= √[ 40000 + 48545.30] = 297.56 ohm

Current flowing in the circuit is

Irms = Vrms/Z = 15.49 / 297.56 = 0.052 A

vR = Irms * R = 0.052 * 200 = 10.4 V

vL = Irms * L =  0.052 * 221 = 11.49 V

vC = Irms * C = 0.052 * 0.67 = 0.035 V

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Answer:

1500 kg is mass of car

Explanation:

F = ma

F/a = m

4500n / 3 m/s^2 = 1500 kg

The density of a cube that has a mass of 12. 6 and a measured  length of  4.1 cm is 0.18 kg/cm³

Density=mass/volume

mass=12.6

volume=68.9

density=12.6/68.9

density=0.18 kg/cm³

Density is defined as a material substance's mass per unit volume. Density is described by the equation d = M/V, where d stands for density, M for mass, and V for volume. Grams per cubic centimeter is the unit of measurement for density. For instance, compared to Earth's density of 5.51 grams, water has a density of 1 grams per cubic centimeter . Another way to express density is in kilograms per cubic meter (in meter-kilogram-second or SI units), It is easy to determine the relationship between mass and volume using density. For instance, the formula for determining a body's mass is M = Vd, while the formula for determining a body's volume is V = M/d.

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Samantha is 1.39 m tall on her eleventh birthday and 1.62 m tall on her twelfth birthday.  Percentage her height increased by approximately 16.55% from her eleventh to twelfth birthday.

To calculate the percentage increase in Samantha's height, we can use the formula:

Percentage increase = [(New value - Original value) / Original value] * 100

Samantha's height on her eleventh birthday is given as 1.39 m, and on her twelfth birthday, it is 1.62 m.

Using the formula:

Percentage increase = [(1.62 - 1.39) / 1.39] * 100

Calculating the numerator: (1.62 - 1.39) = 0.23

Calculating the denominator: 0.23 / 1.39 ≈ 0.1655

Calculating the percentage increase: 0.1655 * 100 ≈ 16.55%

Therefore, Samantha's height increased by approximately 16.55% from her eleventh to twelfth birthday.

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The shockwaves of released energy that radiate through Earth during an earthquake are classified as seismic waves.

An area of extremely high pressure traveling through the air, earth, or water is referred to as a shock wave. It is brought on by an earthquake, an explosion, or a fast-moving object.

Seismic waves are produced when components of the Earth move suddenly, such as when a fault slips during an earthquake. Volcanic eruptions, explosions, landslides, avalanches, and even running rivers can result in seismic waves.

When materials suddenly move within the Earth, such as when they slip along a fault during an earthquake, seismic waves are produced. Seismic waves can also be produced by volcanic eruptions, explosions, landslides, avalanches, and even swiftly flowing rivers.

Therefore, Seismic waves are the shockwaves of released energy that go through the Earth during an earthquake.

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Answer:

negative acceleration of 4m/s²

Explanation:

Given parameters:

Initial velocity  = 66m/s

Final velocity = 26m/s

Time taken = 10s

Unknown:

Description of the acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time.

It is mathematically expressed as;

    acceleration  = \(\frac{v - u}{t}\)

v is the final velocity

u is the initial velocity

t is the time taken

  Now insert the parameters and solve;

    Acceleration  = \(\frac{26 - 66}{10}\)   = -4m/s²

So, we see a negative acceleration of 4m/s²

The 1.3μm optical communication system consists of an LED source, a 15 km fiber optic cable with attenuation, splices and connectors, resulting in a total loss of 22.1 dB and a received power of \(1.43 * 10^{(-11)\) mW at the detector.

Here is a simple illustration of the 1.3μm light wave optical communication system you described:

The system consists of a light source, a fiber optic cable, and a detector. The light source is an LED with an average power of 0.2XX mW. The fiber optic cable is 15 km long and has an attenuation of 1.45 dB/km. The system has splices at every 2.5 km with a loss of 0.20 dB. The connectors have a loss of 1 dB each. The safety margin is 4 dB.

The total loss of the system is calculated as follows:

Total loss = Fiber attenuation + Splice loss + Connector loss + Safety margin

= 1.45 dB/km * 15 km + 0.20 dB/splice * 6 splices + 1 dB/connector * 2 connectors + 4 dB

= 22.1 dB

The received power at the detector is calculated as follows:

Received power = Transmitted power *\((10^{(-Loss/10)})\)

=\(0.2XX mW * (10^{(-22.1/10)})\)

=\(1.43 * 10^{(-11)} mW\)

This is a very small amount of power, but it is still enough to be detected by the detector.

The system can be improved by using a more powerful light source, a lower-loss fiber optic cable, and connectors with a lower loss. The safety margin can also be reduced, but this will increase the risk of errors.

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Your eye as well as the spider's image in the mirror are 1.28 meters apart.

A mirrors is a luminance that reflects light and creates an actual or fictitious picture. An device that returns an image is a reflector or looking glass, which reflects the image of the object when it is positioned in front of it. When focused through an eye or camera lens, light that reflects off a mirror will reveal an image of everything that was in front of it. Mirrors reflect light at an equal but opposite angle, reversing the orientation of the image.

The image distance is equal to the object distance:

Distance between the spider and mirror = 40cm

So, the image is formed 40cm inside the mirror

Distance between the person and mirror = 68cm

Distance between the image and person = 68+40= 128cm

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Answer:

this is just a black bar, I do not understand.

Explanation:

Answer:

the foiley like color doesn't absorb the heat it bounces off of it. it would be much better to have a black blanket

Spectral features that allow the differentiation of the product from the starting material can be identified using various techniques such as infrared spectroscopy and nuclear magnetic resonance spectroscopy.

The chemical structure of a substance determines its spectral features, making it possible to differentiate it from other substances. Spectroscopic techniques like nuclear magnetic resonance (NMR) and infrared (IR) spectroscopy can be used to identify different types of molecular bonds, enabling the differentiation of different types of chemicals.NMR spectroscopy enables the determination of the types of atoms in a substance by analyzing the radiation emitted by the nucleus of the atom. On the other hand, IR spectroscopy identifies the types of chemical bonds in a substance by analyzing the infrared radiation absorbed by the sample.

Spectral features that differentiate the product from the starting material can be identified using various techniques such as infrared spectroscopy and nuclear magnetic resonance spectroscopy. NMR spectroscopy can determine the types of atoms in a substance by analyzing the radiation emitted by the nucleus of the atom, while IR spectroscopy can identify the types of chemical bonds in a substance by analyzing the infrared radiation absorbed by the sample. The chemical structure of a substance determines its spectral features, enabling its differentiation from other substances.

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Answer:

B.Converts the voltage of a current source

A transformer is an electrical apparatus designed to convert alternating current from one voltage to another. It can be designed to "step up" or "step down" voltages and works on the magnetic induction principle. ... When voltage is introduced to one coil, called the primary, it magnetizes the iron core.

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

Given, Speed of the sound, v=675 m/s

The wavelength of the wave, λ=15 m

Relation between speed, wavelength, and frequency of a wave is given by

Where f is the frequency of the sound.

On substituting the known values,

Which gives us,

Therefore the frequency of the sound in the given medium is 45 Hz.

Answer:

If you are traveling with a relativity constant velocity, then you will interpret your reference frame as being at rest. Since you are moving faster than the other train, the other train is moving backwards relative to you. Seeing the other train go past your window from front to rear makes it look like the train is going backwards

Explanation:

Answer:

75g

Explanation:

Given parameters

Mass of product  = 375g

Mass of reactant X  = 300g

Unknown:

Mass of reactant Y  = ?

Solution:

To solve this problem, we need to understand the law of conservation of mass. The law states that "matter is neither created nor destroyed in a chemical reaction".

So;

      Mass of X + Mass of Y   =  Mass of product

            Mass of Y = Mass of product  - Mass of X

           Mass of Y  = 375  - 300  = 75g

A pendulum bob with a mass of 0.15 kg and a speed of 3 m/s has a kinetic energy at the low point of its swing of 0.675 J.

Kinetic energy is the energy that an item has as a function of motion. A force must be applied to an object in to accelerate it. We must engage considerable efforts in order to apply a force. After the task is finished, energy is transferred to the item, which then moves at a new, constant speed.

For calculation:

kinetic energy at low point,

kinetic energy = mass in kg / velocity in m/s

now,

putting the value in given formula,

kinetic energy = 0.15 / 33

                         =0.675J

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In the speed-time graph of a car in the figure, the correct statement is, the distance traveled by car is 75 m. Thus, option C is correct.

Speed is the distance traveled by an object per unit of time. In the graph, speed is taken in the Y axis, and time in the X axis. In the speed-time graph, the acceleration of an object and the distance traveled by an object can be determined. In the speed-time graph, the acceleration is obtained by taking the slope. From the figure, the speed of the car decreases, and it is called deceleration. If the car has a constant speed, the graph has a line parallel to the X-axis.

The distance traveled by car is obtained by determining the area of the figure.  The area of the figure is a triangle.

Distance = Area of the triangle = 1/2 (base×height)

                                                    = (15×10) /2

                                                    = 75m

The distance traveled by car is 75m. The ideal solution is C.

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The duration of the light pulse measured by the pilot of the spaceship is approximately 34.0 μs.

What is light pulse?

A light pulse refers to a brief and localized disturbance or packet of electromagnetic radiation that propagates through space. It is a short-duration burst or wavefront of light energy.

Light pulses can be produced by rapidly changing or modulating a light source, such as a laser. By controlling the duration and intensity of the light emission, one can generate pulses of light with specific characteristics.

According to the theory of special relativity, time dilation occurs when an observer is in relative motion with respect to another observer.

The time dilation factor is given by γ = 1 / √(1 - (v²/c²)), where v is the relative velocity between the observers and c is the speed of light.

In this scenario, the spaceship is moving past Mars with a speed of 0.985c relative to the planet's surface. Since the signal light blinks on and off while the spaceship is directly overhead, the duration of the light pulse observed by the pilot can be calculated using the time dilation formula.

Given that the duration of the light pulse measured by the observer on Mars is 70.0 μs, we need to divide it by the time dilation factor to obtain the duration measured by the pilot:

Δt' = Δt / γ = 70.0 μs / (1 / √(1 - (0.985)²)) ≈ 34.0 μs

Therefore, the duration of the light pulse measured by the pilot of the spaceship is approximately 34.0 μs.

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Answer:

x = 1.6 + 1.7 t^2      omitting signs

a) at t = 0     x = 1.6 m

b) V = d x / d t = 3.4 t

at t = 0     V = 0

c) A = d^2 x / d t^2 = 3.4     (at t = 0  A = 3.4 m/s^2)

d)  x = 1.6 + 1.7 * (4.4)^2 = 34.5    (position at 4.4 sec = 34.5 m)

Answer:

A form of punctuation that marks the end of a sentence, statement, etc.

Explanation:

. is a period.

It can be used in a sentence, such as this one.

not sure what period you mean, but if you mean in history n stuff: it means a certain era/time something happened. like the "golden age" it's called that because it didn't last forever/ it was just a phase yknow?

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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It will take approximately 31.11 seconds for a 2000-watt motor to lift a 370-kg piano to a sixth-story window 17.0  meters above the ground.

A 2000-watt motor is used to lift a 370-kg piano to a sixth-story window 17.0 meters above the ground. To calculate the time it takes, we first need to find the work done and then divide it by the power of the motor.

Work done (W) can be calculated using the formula W = m * g * h, where m is the mass (370 kg), g is the gravitational acceleration (approximately 9.8 m/s²), and h is the height (17.0 m). So, W = 370 kg * 9.8 m/s² * 17.0 m = 62,218 J (joules).

Now we have the work done and the power of the motor, which is 2000 watts (W). Time (t) can be calculated using the formula t = W / P, where P is the power. So, t = 62,218 J / 2000 W = 31.11 seconds.

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(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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Answer:

ok?

Explanation: