The Butterworth filter is a type of electronic filter that has a flat frequency response in the passband and falls off at a rate of -6 dB per octave in the stopband. The filter's output amplitude depends on the input amplitude of the signal and the filter's corner frequency.
1 kHz is the corner frequency of the lowpass Butterworth filter with a roll-off of 24 dB per octave in the stopband. When a 3 kHz sine wave is input into the filter and its output amplitude is 0.10 V, the output amplitude of a 20 kHz sine wave if the input amplitudes are the same is calculated as follows:To begin, we must determine the filter's attenuation rate at the output frequency, which is 20 kHz.
The stopband attenuation rate is 24 dB per octave, which means that the filter's attenuation increases by a factor of 2 for every octave increase in frequency beyond the corner frequency. As a result, at 2 kHz, the filter's attenuation will be 24 dB, and at 4 kHz, it will be 48 dB.
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A cylindrical buoy is 2m in diameter and 2.5m long and weight 22kN . The specific weight of sea water is 10.25kN/m^3 . (I) Show that buoy does not float with its axis vertical. (II). What minimum pull should be applied to a chain attached to the center of the base to keep the buoy vertical?
Answer:
\(GM<0\)
So the bouy does not float with its axis vertical
Explanation:
From the question we are told that:
Diameter \(d=2m\)
Length \(l=2.5m\)
Weight \(W=22kN\)
Specific weight of sea water \(\mu= 10.25kN/m^3\)
Generally the equation for weight of cylinder is mathematically given by
Weight of cylinder = buoyancy Force
\(W=(pwg)Vd\)
Where
\(V_d=\pi/4(d)^2y\)
Therefore
\(22*10^3=10.25*10^3 *\pi/4(2)^2y\\\\\22*10^3=32201.3247y\\\\\y=1.5m\)
Therefore
Center of Bouyance B
\(B=\frac{y}{2}=0.26m\\\\B=0.75\)
Center of Gravity
\(G=\frac{I.B}{2}=2.6m\)
Generally the equation for\BM is mathematically given by
\(BM=\frac{I}{vd}\\\\BM=\frac{3.142/64*2^4}{3.142/4*2^2*0.5215}\\\\BM=0.479m\\\\\)
Therefore
\(BG=2.6-0.476\\\\BG=0.64m\)
Therefore
\(GM=BM-BG\\\\GM=0.479m-0.64m\\\\GM=-0.161m\\\\\)
Therefore
\(GM<0\)
So the bouy does not float with its axis vertical
Hot combustion gases, modeled as air behaving as an ideal gas, enter a steady-state turbine at 145 psi, 2700oR, and exit at 29 psi and 1974oR. The power output is 74.26 hp, and heat transfer from the turbine to the surroundings occurs at a rate of 14 BTU/s.
Required:
Determine the power output of the turbine, in hp.
Hot combustion gases, modeled as air behaving as an ideal gas, enter a steady-state turbine at 145 psi, 2700oR, and exit at 29 psi and 1974oR. The power output is 74.26 hp, and heat transfer from the turbine to the surroundings occurs at a rate of 14 BTU/s.
Required:
a)Determine the power output of the turbine, in hp.
b) The Flow rate
Answer:
a) \(w=74.26hp\)
b) \(m=0.22\)
Explanation:
From the question we are told that:
Initial Pressure \(p_1= 145 psi\)
Initial Temperature \(T_1 =2700oR=>2240.33^oF\)
Final Pressure \(p_2= 29 psi\)
Final Temperature \(t_2=1974oR=>1514.33^oF\)
Output Power \(w=74.26hp\)
Heat transfer Rate \(Q=14BTU/s\)
Generally the equation for Steady flow energy is mathematically given by
\(Q-w=m(h_2-h_1)\)
Where
\(m=Flow\ rate\)
From Steam table
\(h_1=704btu/ib (at\ p_1= 145\ psi,\ T_1 =2700oR=>2240.33^oF )\)
\(h_2=401btu/ib (at\ p_2= 29psi\ t_2=1974oR=>1514.33^oF )\)
Therefore
\(-14-74.26=m(401-704)\)
\(m=\frac{-14-74.26}{(401-704)}\)
\(m=0.22\)
*WELDING*
What size arc gap is suggested with a 5/32" (4.0mm) diameter electrode?
Solution :
The correct size of the arc of a welding process depends upon the application and the electrode. As a rule, the arc length should not be more than a diameter of the core of the electrode.
As for the electrode of diameter size of 5/32" or 4 mm, the arc length should be more than its core diameter. Also for 5/32 " diameter electrode, the welding time for the one electrode must be one minute as well as the length of the weld be the same as the length of the electrode consumed.
What is the primary goal of political parties in televised presidental debates?
to prove which party is best
to present potential candidates
to establish bipartisan agreements
to explain party platforms to voters
i believe it could be c or d, b is the wrong one edge 22
The primary goal of political parties in televised presidential debates is to: D. to explain party platforms to voters.
What is a political party?A political party can be defined as an organized group of individuals (people) who presumably share common political ideologies, aims, goals, vision, and strategies on how a country should be governed.
This ultimately implies that, a political party is an organization of people that are sharing similar political ideologies and it provides a platform for a chosen candidate to run as its sole representative in an election category.
In this context, the primary goal of political parties in televised presidential debates is to explain party platforms to the electorates or voters.
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It's D I just took the test
Edge 2023 :)
1. When jump starting a car, make sure it is in __________.
Answer:
Make sure both cars are in park or neutral with the parking brake engaged. This makes sure that all electrical functions (headlights, radios, etc.) are turned off.
When jump starting a car, make sure it is in the right distance of the cables to reach battery.
What is jump starting a car?Jump starting a car is commonly done from another car, and also it can be done from a jump battery. If we have to jump start a car in a safe way, the following steps are more necessary,Take out your jumper cables.Before the cable was taking, Make sure cars are in the right distance to have the jumper cables reach each battery.Place both vehicles in Park or Neutral and shut off the ignition in both cars.When jump-starting a car, it was must to remember jumper cables typically have two clamps, one with the label “positive” in red and “negative” in black.Attach one of the red clips to the positive terminal of your battery. Attach the other red clip to the positive terminal of the other car. The similar way do for the negative terminals.Thus, when jump-starting a car, always remember the cables are in the right position.
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A program consists of 100,000 instructions as follows:
Instruction Type Instruction Count Cycles per Instruction
Integer arithmetic 45,000 4
Data transfer 32,000 6
Floating point arithmetic 15,000 10
Control transfer 8,000 3
Determine:
a. the program execution time
b. the effective CPI for the machine
c. MIPS rate for the following processors
Answer:
Execution time is 13.65ms
CPI is 5.46
MIPS is 73.3\ MIPs
Explanation:
Given:
\(s = 40MHz\) --- processor speed [Missing from the question]
\(\begin{array}{ccc}{Instruction\ Type} & {Instruction\ Count} & {Cycles\ per\ Instruction} & {Integer\ Arithmetic} & {45000} & {4} \ \\ {Data\ Transfer} & {32000} & {6} & {Floating\ point\ arithmetic} & {15000} & {10} & {Control\ Transfer} &{8000} & {3} \ \end{array}\)
Solving (a): The program execution time
First, we solve for (b)
Solving (b): The effective CPI
This is calculated as:
\(CPI = \frac{\sum IC * CI}{\sum IC}\)
Where: IC = Instruction Count and CI = Cycles per Instruction
So, the equation becomes:
\(CPI = \frac{45000 *4 + 32000 * 6 + 15000 * 10 + 8000 * 3}{45000+32000+15000+8000}\)
\(CPI = \frac{546000}{100000}\)
\(CPI = 5.46\)
Solving (c): MIPS
This is calculated as:
\(MIPS = Speed * \frac{1}{CPI} * \frac{1}{\sum IC}\)
\(MIPS = 40 * \frac{1}{5.46} * \frac{1}{100000}\)
\(MIPS = \frac{40 * 1 * 1}{5.46*100000}\)
\(MIPS = \frac{40}{546000}\)
\(MIPS = 0.00007326007\)
Convert to MIPs
\(MIPS = 73.3\ MIPs\)
Solving (a): Execution Time
This is calculated as:
\(Time = Instructions * CPI * \frac{1}{Speed}\)
\(Time = 100000 * 5.46* \frac{1}{40M}\)
\(Time = \frac{546000}{40M}\)
\(Time = \frac{546000}{40*1000000}\)
\(Time = \frac{546000}{40000000}\)
\(Time = 0.01365s\)
\(Time = 13.65ms\)
Execution time is 13.65ms
The roller coaster car having a mass m is released from rest at point A Neglect friction (Figure 1) Part A
It the track is to be designer so that car does not leave it at B determine the required height h Express your answer to three Significant figures and Include the appropriate units. Part B
Find the speed of the car when it roaches point C. Express your answer to three significant figures and include the appropriate units.
The car's speed as it approaches the spot Part B's v = 14.3 m/s and Part A's h = 8.94 metres.
What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is the distance travelled by the object divided by the duration of the period. Velocity and speed are not the same thing.
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a) If a given directional antenna can receive 15 times the power of an isotropic antenna, what is
its gain in dBi?
b) If the gain of a directional antenna is 2.15 dBi and it received 1mW of power, how much
power would have been received by an isotropic antenna?
The gain of the directional antenna is calculated based on the comparison
with an hypothetical isotropic antenna.
a) The gain in dBi of the isotropic antenna is approximately 11.76 dBib) The power received by the isotropic antenna is approximately 0.61 mWReasons:
a) The number of times the power of the directional antenna is stronger than the isotropic antenna, G = 15 times
The gain in dBi is given as follows;
\(\displaystyle G = \mathbf{10^{\dfrac{G(dBi)}{10} }}\)
Which gives;
\(\displaystyle 15 = 10^{\dfrac{G(dBi)}{10} }\)
\(\displaystyle \dfrac{G(dBi)}{10} = \frac{ln(15)}{ln(10)}\)
\(\displaystyle G(dBi)} = 10 \times \frac{ln(15)}{ln(10)} \approx 11.76\)
The power gain of the isotropic antenna, G(dBi) ≈ 11.76 dBi
b) When the gain of the directional antenna is 2.15 dBi and it received 1 mW of power, we have;
The number of times stronger the directional antenna is, is found as follows;
\(\displaystyle G = 10^{\dfrac{2.15}{10} } \approx \mathbf{1.64}\)
The 2.15 dBi directional antenna receives the signal approximately 1.64 times stronger than the isotropic antenna, therefore;
\(\displaystyle The \ power \ received \ by \ the \ isotropic \ antenna = \frac{1 \, mW}{1.64} \approx \underline {0.61 \, mW}\)Learn more here:
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Experiment: With the battery voltage set to 15 volts, measure the current in a parallel circuit with 1, 2, 3, and 4 light bulbs. (In each case, place the ammeter next to the battery.) Use Ohm’s law to calculate the total resistance of the circuit. Record results below. Is this right?
Answer:
No
Explanation:
We expect current to be proportional to the number of identical bulbs. The total resistance is the ratio of voltage to current, so will be inversely proportional to the number of bulbs.
The current readings look wrong in that the first bulb caused the current to be 1 A, but each additional bulb increased it by 2 A. If that is what happened, the bulbs were not identical. That may be OK, but we expect the point of the experiment is to let you see the result described above.
In any event, the total resistance is not calculated properly. It should be the result of dividing voltage (15 V) by current.
Answer:
No, it is not right.
Explanation:
Your table is not consistent with bulbs of the same resistance.
Current comes from a measurement, but resistance comes from a calculation.
I presume that the measured currents are correct.
Ohm's Law states that the current flowing in a circuit is directly proportional to the voltage.
We usually write it as
V/I = R
1. One bulb in circuit
\(R = \dfrac{V}{I} = \dfrac{\text{15 V}}{\text{1 A}}= \mathbf{15 \, \Omega}\)
2. Two bulbs
\(R = \dfrac{V}{I} = \dfrac{\text{15 V}}{\text{3 A}} = \mathbf{5 \, \Omega}\)
3. Three bulbs
\(R = \dfrac{V}{I} = \dfrac{\text{15 V}}{\text{5 A}} = \mathbf{3 \, \Omega}\)
4. Four bulbs
\(R = \dfrac{V}{I} = \dfrac{\text{15 V}}{\text{7 A}} = \mathbf{2.1 \, \Omega}\)
What are some of the advantages of working in preconstruction?
Alvaro designs machinery and equipment for ships. His job title is best described as . Jeanette draws maps and plans for freeway projects. Her job title is best described as . Joseph designs a new airport. His job title is best described as . Geraldine designs imaging systems that use light. Her job title is best described as .
Answer:
Alvaro designs machinery and equipment for ships. His job title is best described as Marine Engineer.
Jeanette draws maps and plans for freeway projects. Her job title is best described as Civil Drafter.
Joseph designs a new airport. His job title is best described as Transportation Engineer.
Geraldine designs imaging systems that use light. Her job title is best described as Photonics Engineer.
Hope this helps sorry I am late to respond, but anyone else who needs the answer it is here.
Based on the above, Alvaro is a Marine Engineer;
Jeanette is a Civil Drafter.Joseph is a Transportation Engineer.Geraldine is a Photonics Engineer.What is machinery and equipment?Machinery and Equipment are known to be a type of industrial tools, devices, and items that aids facilities.
Conclusively, They are said to be tangible personal property that are used as a tool for repair parts, etc. Professions in ship jobs includes, Marine Engineer, Photonics Engineer, etc.
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When a pungent odor is detected during a sealed system recovery and/or repair which of the following is most likely
Answer: A leak in the system
Explanation:
A control system that is used in elevator system
Explanation:
Elevator controller
An Elevator controller is a system to control the elevators, either manual or automatic. The controller usually tune down the voltage between 12V to 24V to the controlling system, Only the motor needs 3-phase power supply.
https://elevation.fandom.com › wiki
Elevator control system | Elevator Wiki | Fandom
Water at 15degree Celsius passes through 2cm internal diameter copper tubes at a rate of
0.55kg/s. Determine the pumping power per meter of pipe length required to maintain this flow
at the specified rate.
Answer :
Im not really sure tbh
Explanation: Water at 15°C is heated by passing it through 2-cm internal-diameter thin-walled copper tubes. Heat is supplied to the water by steam that condenses outside the copper tubes at 120°C. If water is to be heated to 65°C at a rate of 0.2 kg/s, determine (a) the length of the copper tube that needs to be used and (b) the pumping power requirement to overcome pressure losses. Assuming the entire copper tube to be at steam temperature of 120°C
Which of the following sentences correctly uses commas after prepositional phrases
Answer:
You didn't write full questions
Explanation:
Where are options? You say following but there is no any option
Draw the minheap that results from adding the following numbers 32, 44, 5, 87, 69, 31, 2, 12, 20 4. Using the solution from number 3 above, show the tree that results from performing the removeMin Operation.
The resulting tree after removeMin operation is:
4
/ \
5 12
/ \ / \
32 44 20 31
/ \
87 69
After adding the numbers 32, 44, 5, 87, 69, 31, 2, 12, 20, and 4 to a min-heap, the min-heap tree structure will look like this:
2
/ \
5 4
/ \ / \
32 44 20 31
/ \ /
87 69 12
Now, to perform the removeMin operation, we'll remove the smallest element (2) and restructure the tree to maintain the min-heap property:
1. Replace the root with the last element in the tree (12) and remove it from its previous position.
2. Compare the new root (12) with its children (5 and 4) and swap with the smallest child (4).
3. Compare the swapped element (12) with its new children (20 and 31) - no further swaps are needed since 12 is smaller than its children.
The resulting tree after removeMin operation is:
4
/ \
5 12
/ \ / \
32 44 20 31
/ \
87 69
```
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Question 2 of 15
A healthcare start-up is using Artificial Intelligence (Al) to test the way a person speaks in order to
detect Alzheimer's disease. The algorithm interprets pauses and differences in pronunciations as
markers of the disease. The developers used a dataset that contains only speech samples from native
English speakers. What type of bias is present in this example?
The type of bias present in the above example is called "selection bias" or "sampling bias."
What is the biasSampling bias happens when the information used to teach or create something does not accurately represent all the people or things it is meant to. This selection bias means that the algorithm may not work well or give accurate results when used on people who do not speak English as their first language.
In detecting Alzheimer's disease by analyzing how people talk, this bias might cause wrong or limited results when used on people who speak different languages.
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The primary hardware component of a computer responsible for routing data and instructions to and from the various components of a computer is the?
The primary hardware component of a computer that is responsible for routing data and instructions to and from the various components of a computer is the: bus.
What is a computer hardware?A computer hardware can be defined as a physical component of an information technology (IT) or computer system that can be seen and touched.
The hardware components of a computer.Some examples of the hardware components of a computer system and these include:
Random access memory (RAM).Read only memory (ROM).Central processing unit (CPU)KeyboardMonitorMouseMotherboard bios chipBusWhat is a data bus?A data bus can be defined as a type of hardware (wire) that is designed and developed so as to enable the transfer (routing) of data across the motherboard of a computer system.
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________ is the percent of design capacity a facility is actually expected to maintain.
Utilization rate is the percent of design capacity a facility is actually expected to maintain.
What is the design capacity?The utilization rate pertains to the extent to which a facility is expected to sustain its design capacity as a percentage. It quantifies the level of efficiency with which a facility is being employed in relation to its highest possible usage.
The rate of usage is not constant and can be influenced by several factors including demand, operational limitations, and production efficacy. This offers valuable information on how effectively and efficiently a facility is using its available resources to enhance productivity.
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1. It's very kind _______ you to help us. Thanks a lot. A. for B. to C. with D. of
2
3
TIME REMAINING
54:48
In a life-cycle assessment, the impact of demolition is determined once the building has been scheduled to be
torn down.
True
False
Mark this and totum
Save and Exit
In a life cycle assessment, the impact of demolition is determined once the building has been scheduled to be torn down?
True or false
Answer:
very confusing sorry cant help........................................................................................................................................................... i think it is true if it wrong i am so sorrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrry
Explanation:
what is platform engineering
Answer:
the discipline of designing and building toolchains and workflows that enable self-service capabilities for software engineering organizations in the cloud-native era
Explanation:
Without compromising on effectiveness, security, or quality, platform engineering is a potent tool for scaling up software delivery operations.
The provisioning and management of resources are made easier and more automated, allowing developers to deliver more value to consumers faster. As we all know, DevOps leverages technologies to automate and visualize deployment, administration, and monitoring. These methods, procedures, and best practices are taken and productized by Platform Technical as reusable services and tools for use by the many engineering teams and use cases inside the company. All desktop and separate appointment activities are designed and maintained by platform developers, who also help with template installation and write scripts for all software development. In addition to managing and preparing reports for automated process deployment, they also generate reports for management presentations.
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what is the purpose of the fast fourier transform? a. it allows you to look at the trajectory of the device. b. it allows you to fit the plot with a trendline. c. it takes the signal from the position domain and represents it in the frequency domain instead. d. it allows you to plot the velocity v. the position instead of velocity v. time.
The purpose of the fast Fourier transform is it takes the signal from the position domain and represents it in the frequency domain instead, and it allows you to plot the velocity. The correct options are c and d.
What is the fast Fourier transform?
FFT stands for "Fast Fourier Transform," which is an important measurement method. In the process, it dissects a signal into its individual spectral components and provides frequency information about the signal.
The output of the FFT is a complex vector that includes information about the signal's frequency content. The magnitude reflects the relative strength of the frequency components in comparison to other components.
Therefore, the correct options are c and d.
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What type of pattern should be used when tightening lug nuts?
Answer:
Cross pattern, according to the internet
Which type of boot authentication is more secure?
The type of boot authentication that is more secure is Unified Extensible Firmware Interface
Unified Extensible Firmware Interface help to provide a computer booting that is more secured.
Unified Extensible Firmware Interface is a computer software program that work hand in hand with an operating system, it main function is to stop a computer system from boot with an operating system that is not secured.
For a computer system to boot successfully it means that the Operating system support the Unified Extensible Firmware Interface because it secured.
Inconclusion The type of boot authentication that is more secure is Unified Extensible Firmware Interface
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what direct current polarity flows from the electrode across the arc to the work
The direct current (DC) polarity that flows from the electrode across the arc to the work is called the electrode negative (DCEN) polarity.
In welding, the polarity of the DC power source is an important factor that affects the properties of the welding arc and the resulting weld. DC welding power sources can be set to either DCEN or electrode positive (DCEP) polarity.
In DCEN polarity, the negative terminal of the power source is connected to the welding electrode, while the positive terminal is connected to the workpiece. This means that electrons flow from the electrode to the workpiece, creating a high-heat, low-penetration welding arc.
DCEN polarity is typically used for welding processes that require deep penetration, such as welding thick materials or making welds that penetrate all the way through the joint. This polarity also results in less electrode erosion, longer electrode life, and less spatter.
In contrast, DCEP polarity has the opposite polarity configuration, with the positive terminal connected to the electrode and the negative terminal connected to the workpiece. This polarity creates a high-penetration, low-heat welding arc and is typically used for welding thin materials or making cosmetic welds.
Overall, the choice of DC polarity depends on the welding process, the thickness of the materials being welded, and the desired properties of the resulting weld.
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Before you attempt to change a tire yourself, you should _____.
A. put on a pair of gloves
B. read your vehicle owner's manual for any special directions or warnings.
C. always call for emergency assistance first
D. let the remaining air out of the flat tire
Answer: read your vehicle owner's manual for any special directions or warnings.
Answer:
B. read your vehicle owner's manual for any special directions or warnings.
Explanation:
A. A solidified lava flow containing zircon mineral crystals is present in a sequence of rock layers that are exposed in a hillside.A mass spectrometer analysis was used to count the atoms of uranium-235 and lead-207 isotopes in zircon samples from thelava flow. The analysis revealed that 71% of the atoms were uranium-235, and 29% of the atoms were lead-207. Refer toFIGURE 8.11 to help you answer the following questions.1. About how many half-lives of the uranium-235to lead-207 decay pair have elapsed in the zircon crystals? ______________2. What is the absolute age of the lava flow based onits zircon crystals? Show your calculations.3. What is the age of the rocklayers above the lava flow? _______________4. What is the age of the rocklayers beneath the lava flow? _______________B. Astronomers think that Earth probably formed at the same time as
Answer:
1. 0.494
2. = 352.299 million years
3. It is between 0 years to 352.299 million years
4. greater than the 352.299 million years.
Explanation:
Given
Uranium 235 ———— lead 207( zircon sample)
t= 0 100%. 0%
t= t. 71%. 29%
1)- half lives elapsed = n
(1/2)n = 0.71
By taking log and solving n = 0.494
No of half lives = 0.494
2) Calculating the age of the larva
- age of lava flow = half life of uranium 235 x n
= 713 x 0.494
= 352.299 million years
3)- The rock layers was created above this lava flow is of later occurrence so the age will be lower than that of the age of the lava flow so the age of rock over the lava flow will lower than the 352.299 million years it will be in between 0 years to 352.299 million years.
4)- The rock layers created underneath this lava flow is of earlier occurrence so its age is more than that of the age of the lava flow so the age of rock will more than the lava flow is greater than the 352.299 million years.
B. The astronomers think the earth was created as all of the other rock materials in our solar system, including the oldest meteorites. The oldest meteorites ever found on Earth contain nearly equal amounts of both Uranium-238 and Lead-206.
The number of half-lives of the uranium-235to lead-207 decay pair have elapsed in the zircon crystals is; 0.494
What is the number of half lives?We are given;
The atoms of Uranium-235 and lead-207 which made up the zircon sample.
At t = 0; Uranium-235 is 100% while lead-207 is 0%
At t = t; Uranium-235 is 71% while lead-207 is 29%
1) Let the half lives that elapsed be n. Thus;
(¹/₂)ⁿ = 0.71
n*log0.5 = log 0.71
n = (log 0.71)/(log 0.5)
n = 0.494
Thus;
Number of half lives = 0.494
2) Formula to get the absolute age of the larva is;
Absolute age age of lava flow = half life of uranium-235 * n
The half life of uranium-235 is 713 million years. Thus;
Absolute age age of lava flow = 713 * 0.494
Absolute age of lava flow = 352.22 million years
3) The rock layers above the lava flow were created after the lava flow and so the age will be lower than that of the age of the lava flow. Thus, it's age will be between 0 years and 352.299 million years.
4) A: The rock layers beneath the lava flow were in existence earlier than the lava flow and as such, the age of rock layers beneath the lava flow will be greater than 352.22 million years.
B; The astronomers think the earth was created as all of the other rock materials in our solar system.
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If you were able to capture that kinetic energy as electricity at the head (point of entry) of the treatment facility using a hydraulic turbine with an 75% efficiency, how much electricity could you generate.
Answer:
none
Explanation:
because it doesnt turn kinetic energy into electricity a
Kinetic energy turbines, also called free-flow turbines, generate electricity from the kinetic energy present in flowing water rather than the potential energy from the head. The systems can operate in rivers, man-made channels, tidal waters, or ocean currents. Because kinetic systems utilize a water stream's natural pathway, they do not require diversion of water through man-made channels, riverbeds, or pipes, although they might have applications in such conduits. Kinetic systems do not require large civil works because they can use existing structures, such as bridges, tailraces, and channels. so it doesnt
Applied stresses are amplified to a greater degree when a material has small cracks rather than large cracks. Group of answer choices True
True, applied stresses are amplified to a greater degree when a material has small cracks.
Do small cracks in a material amplify applied stresses?When a material contains small cracks, the applied stresses experienced by the material are indeed amplified to a greater extent compared to when the cracks are larger. This phenomenon occurs due to the concentration of stress at the tips of the cracks, where the stress is highest.
Small cracks act as stress concentrators, causing the stress field to intensify in their vicinity. This concentration of stress leads to a localized increase in stress magnitude, making the material more susceptible to failure under applied loads.
As the size of cracks decreases, the stress concentration at their tips increases, resulting in a higher likelihood of crack propagation and material fracture.
Understanding the behavior of cracks and their influence on applied stresses is crucial in materials science and engineering. It allows engineers to assess the structural integrity of materials and design strategies to prevent or mitigate crack growth and failure.
Techniques such as fracture mechanics and non-destructive testing are employed to evaluate the presence and characteristics of cracks, ensuring the safety and reliability of various structures and components.
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