a mixture of 14.0 grams of h2, 84.0 grams of n2, and 64.0 grams of o2 are placed in a flask. the partial pressure of the o2 is 78.00 torr. what is the total pressure in the flask? what are the partial pressures of the remaining gases, h2

Answer:

ammonia molecules. Similar factors may be derived for any pair of substances in any chemical equation. Example 4.8. Moles of Reactant Required in a Reaction.

Explanation:

Answer:

B. Group 17

Explanation:

The element is Bromine. Its electron configuration is:

1s2 2s2p6 3s2p6d10 4s2p5  

You can see that its last orbital is 4p^5 for 5 electrons in the 4p orbital.

The amount of dry NH₄HCl needed to prepare a buffer solution that has a pH of 8.56 is 188.29 grams.

To prepare the buffer solution with a pH of 8.56, first, we need to calculate the concentration of NH₄⁺ ions using the Henderson-Hasselbalch equation:

pH = pKa + log([NH₄⁺]/[NH₃])

Since we have pH and [NH₃], we need to find pKa using Kb for ammonia:

Kb = 1.8 × 10⁻⁵
Kw = 1 × 10⁻¹⁴ (ion product of water)

Ka = Kw / Kb = 1 × 10⁻¹⁴ / 1.8 × 10⁻⁵ = 5.56 × 10⁻¹⁰
pKa = -log(Ka) = 9.26

Now, we can use the Henderson-Hasselbalch equation:

8.56 = 9.26 + log([NH₄⁺]/(0.800))

Rearranging to find [NH₄⁺]:

[NH₄⁺] = 0.800 * 10^(9.26 - 8.56) = 0.800 * 10^(0.70) = 1.6 M

Now, we can calculate the grams of NH₄Cl needed to achieve this concentration:

1.6 mol/L * 2.20 L = 3.52 mol of NH₄Cl

Finally, convert moles to grams using the molar mass of NH₄Cl (53.49 g/mol):

3.52 mol * 53.49 g/mol = 188.29 g

So, you need to add 188.29 grams of dry NH₄Cl to the 2.20 L of 0.800 M NH₃ solution to prepare the buffer with a pH of 8.56.

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Cells in many-celled organisms can look the same or different, depending on the type of organism and the function of the cells.

In general,multi-cellular(many-celled) organisms have specialized cells that perform specific functions, such as muscle cells, nerve cells, and blood cells. These cells are different in structure and function, but they all work together to maintain the organism's health and survival.

For example, in humans:

Therefore, cells in many-celled organisms can look the same or different, depending on the function of the cells. While many-celled organisms have specialized cells, some cells have the same structure and function.

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The sample volume of propane, a component of lp gas at STP, is 37.12L.

The combined gas law combines the principles of Gay-Lussac, Boyle, and Charles.

According to the combined gas equation, P1×V1/T1 = P2×V2/T2

Assuming the gas is an ideal gas will help us solve this problem. We can then apply the combined gas equation, P1×V1/T1 = P2×V2/T2.

Where,

P1 = initial pressure of the gas = 922 torr = 1.213 atm

P2 = final pressure of the gas at STP = 1 atm

V1 = initial volume of the gas = 35.3 L

V2 = at STP final volume of the gas  =?

T1 = initial temperature of the gas = 315 K

T2 = final temperature of the gas at STP = 273 K

By using the following equation and putting the given values, we obtain:

P1×V1/T1 = P2×V2/T2

Hence, V2 = P1×V1×T2 / T1×P2

V2 = 1.213×35.3×273 / 315×760

Therefore, the volume of the gas at STP is, 37.12 L

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Yes, there is a relationship between the height equivalent to a theoretical plate (HETP) and the identity of the distilland.

HETP is a measure of the efficiency of a distillation column, and it represents the height of a theoretical plate that would give the same separation as the real column. It is affected by several factors, including the type of packing material used in the column, the flow rate of the distillate, and the properties of the distilland, such as its boiling point, molecular weight, and volatility.

The identity of the distilland can significantly affect the HETP. For example, if the distilland is a mixture of compounds with different boiling points, the HETP may be higher for the components with lower boiling points as they are more difficult to separate. Similarly, if the distilland has a low molecular weight or is highly volatile, it may tend to vaporize more easily, leading to a lower HETP.

In the case of a stainless steel sponge packed column, the HETP may vary depending on the identity of the distilland, but it would also be influenced by the other factors mentioned above. The type of sponge used, the size of the pores, and the way it is packed can all affect the HETP.

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Answer: The thermodynamic favorability of a chemical reaction can be determined by comparing the change in free energy (ΔG) between the reactants and products. A negative value of ΔG indicates that the reaction is thermodynamically favored, meaning that it is energetically favorable for the reaction to proceed in the forward direction. Conversely, a positive value of ΔG indicates that the reaction is not thermodynamically favored, and the reverse reaction is energetically favorable.

If the ΔG of the forward reaction is negative, the forward reaction will be thermodynamically favored, and the reverse reaction will not be. If the ΔG of the forward reaction is positive, the reverse reaction will be thermodynamically favored, and the forward reaction will not be. If the ΔG of the forward reaction is zero, the reaction is at equilibrium and neither the forward nor the reverse reaction is thermodynamically favored.

Therefore, whether the forward or reverse reaction is thermodynamically favored depends on the magnitude and sign of ΔG for that reaction.

Explanation:

Answer:

d

Explanation:

from you know the atomic number it should be easy to find

To determine the molar mass of an element, one must know the element's atomic number​. Therefore, option D is correct.

An element's atomic number (Z) is the number of protons in the nucleus of each atom of that element. This means that the number of protons is the feature that distinguishes each element from all others. Elements differ based on their atomic number.

Because the combined masses of protons and neutrons account for nearly all the mass of a given atom, the atomic mass of a single atom can be calculated by adding the total number of protons and neutrons of that particular isotope.

The atomic mass of any element on the periodic table can be used to calculate its molar mass.

Thus, option D is correct.

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symbol ...................

If you lost 2.0 lbs of water during volleyball practice through sweating, and all of it evaporated, the amount of energy absorbed by the water from your body would be approximately 2053.652 kJ.

When water evaporates from the skin, it absorbs heat energy from the body, leading to cooling of the body. To calculate the amount of energy absorbed by the water, we can use the equation:

Q = mL

where Q is the heat absorbed or released, m is the mass of water evaporated, and L is the heat of vaporization of water, which is 40.7 kJ/mol.

First, we need to convert the mass of water lost from pounds to grams, as well as calculate the moles of water lost. 1 lb = 453.592 g, so 2.0 lbs is equivalent to 907.185 g. The molar mass of water is 18.015 g/mol, so 907.185 g is equivalent to 50.36 moles of water.

Next, we can use the equation:

n(H₂O) = n(H₂O) x L

where n(H₂O) is the number of moles of water lost and L is the heat of vaporization of water. Substituting the values, we get:

Q = (50.36 mol) x (40.7 kJ/mol) = 2053.652 kJ

Therefore, the water absorbed approximately 2053.652 kJ of heat energy from the body.

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Answer:

28

Explanation:

it states that the atom is neutral, meaning the number of electrons and protons are the same. so if there are 13 electrons, there are 13 protons. And the mass number is neutrons plus protons. So 13+15 is 28

I think the answer is c if not then try a

Answer: B

Explanation:

3.4 moles of carbon tetrachloride is equivalent to 523.6g.

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows:

mass = no. of moles × molar mass

According to this question, 3.4 moles of carbon tetrachloride is given. The mass can be calculated thus;

molar mass of carbon tetrachloride = 154g/mol

mass = 3.4 moles × 154g/mol

mass = 523.6g

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The relative abundance of isotopes is the number of atoms of a particular isotope divide by the total number of atoms of all isotopes of that element, multiplied 100 percent.

The relative abundance of an isotope is the percentage of atoms with a specific atomic mass found in a naturally occurring sample of an element.

Also relative abundances refers to the relative proportions of the stable isotopes of each element. They are most often quoted as atom percentages

To calculate the percent abundance of each isotope in a sample of an element,  the number of atoms of a particular isotope is usually divide by the total number of atoms of all isotopes of that element and then multiply the result by 100 since it is expressed in percentage.

Mathematically, the formula for relative abundance is given as;

R.A = ( number of atoms of isotope / total number of atoms ) x 100%

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Answer:

hope it helps and thank you for the points

Answer:

A). half, higher

Explanation:

The Formal charge is elaborated as the 'allocated charge to a molecules' atom' on the basis of the assumption that the electrons present in the chemical bond are equally split among the atoms. It is estimated by 'halving the no. of bonding electrons that encircle the atom.

While Oxidation number is characterized as the 'hypothetical charge of an atom that is present within a molecule.' It is also defined as 'the actual number of lost or gained electrons or the rate at which the electrons are gained or lost by an atom to develop a chemical bond along with the other atom.' It is calculated by allocating or sharing the electrons having the higher electronegativity belonging to a specific bond with the other. Thus, option A is the correct answer.

Answer:

A. Logic

Explanation:

Answer:

Logic. When interepreting scientific information you have to always use logic

Explanation:

When a stock solution is diluted, the number of moles of solute (NaNO3 in this case) remains constant. Therefore, we can use the following equation to find the final molarity of the diluted solution:

M1V1 = M2V2

where M1 is the initial molarity (0.275 M), V1 is the initial volume (15.00 mL), M2 is the final molarity (what we want to find), and V2 is the final volume (100.0 mL).

First, we need to convert the initial volume from milliliters to liters:

V1 = 15.00 mL = 0.01500 L

Next, we can substitute the given values into the equation:

(0.275 M) × (0.01500 L) = M2 × (0.1000 L)

Solving for M2, we get:

M2 = (0.275 M × 0.01500 L) ÷ 0.1000 L

M2 = 0.04125 M

Therefore, the final molarity of the NaNO3 solution is 0.04125 M.

Answer:

The answer should be that a constant pressure is applied to both cylinders and they are balanced chemical equations for the reaction between nitrogen oxygen.

Explanation:

This equation represents the solid iron (Fe) reacting with the aqueous copper(II) nitrate (Cu(NO3)2) solution to produce aqueous iron(II) nitrate (Fe(NO3)2) and solid copper (Cu).

In this situation, a chemical reaction does occur between iron (Fe) and copper(II) nitrate (Cu(NO3)2). The iron reacts with the copper(II) ions in the solution to form iron(II) ions and copper metal.

The balanced chemical equation for the reaction is:

Fe(s) + Cu(NO3)2(aq) → Fe(NO3)2(aq) + Cu(s)

This equation represents the solid iron (Fe) reacting with the aqueous copper(II) nitrate (Cu(NO3)2) solution to produce aqueous iron(II) nitrate (Fe(NO3)2) and solid copper (Cu).

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Answer:

Physical dependence is characterized by tolerance and withdrawal. Drug or substance dependency is psychological.

From the structure of SF4 shown, the molecular geometry of the molecule is trigonal bipyramidal.

The term molecular geometry has to do with the arrangement of the electron pairs in a molecule.

The arrangement of electron pair in a molecule is based on the valence shell electron pair repulsion theory.  From the structure of SF4 shown, the molecular geometry of the molecule is trigonal bipyramidal.

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In the gas mixture containing methane and oxygen gases at a total pressure 828mm Hg with 2.55 grams oxygen, 5.65 grams of methane are present.

According to Dalton's law, the total pressure is the sum of individual pressures.

i.e P(total)= P(methane) + P(oxygen)

Here, P(total)=total pressure of all the gases= 828 mmHg

P(oxygen) = partial pressure of oxygen = 258mm Hg

The gas mixture contains 2.55 g of oxygen.

∴ 828 = 258 + P(methane)

⇒P(methane) = 828-258

⇒P(methane) = 570

We need to find the grams of methane present.

P(methane)= x(methane) × P(total)

Since, the mixture contains 2.55 g oxygen

no of moles of oxygen = given mass/molar mass

                                      = 2.55g/16gmol⁻¹

                                      = 0.16 mol

x(methane) = mole fraction of methane

⇒moles of methane/total moles= y/y+0.16 mol

⇒570 =  y/y+0.16 mol × 828

⇒ 828y=570y +91.2

⇒828y-570y= 91.2

⇒258y=91.2

⇒y= 91.2/258

⇒y=0.35

∴mass of methane

= no. of moles× molar mass

= 0.35  mol× 16g/mol

=5.65g

Thus, 5.65 grams of methane are present.

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An object whose density is 1.98 x 10³ kg/m³ has a mass of 35.4 g, it has  17.878 \(m^{3}\)cubic.

We can calculate what materials will float and sink whenever placed in a liquid using the concept of density, which is a crucial idea. As long as an object's density is lower than that of the liquid's density, it will often float.

Density is the ratio of mass as well as volume. It will be denoted by the symbol d.

Given data:

Density = 1.98 × \(10^{3}\) kg/m³.

Mass = 35.4 g

Volume = ?

Volume can be determined by the formula:

Density = mass / volume

Volume = mass / density

Now, put the values of mass and density in above equation.

Volume = 35.4 g/ 1.98 × \(10^{3}\) kg/m³.

Volume = 17.878 \(m^{3}\).

Therefore, the cubic will be  17.878 \(m^{3}\).

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Answer:

A

Explanation:

Caus it makes sense

Salt and water will lead to a homogeneous mixture.

A homogeneous mixture is a type of mixture in which the components are evenly distributed throughout the mixture, resulting in a uniform composition and appearance.

Salt and water will result in a homogeneous mixture because the salt particles will dissolve in the water, leading to an even distribution of salt throughout the mixture.

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Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

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