The empirical formula of the molecule is CH2.
To determine the empirical formula, we need to find the simplest whole-number ratio of the atoms in the molecule. We can assume 100 grams of the molecule since percentages are given by mass.
The mass of Carbon (C) in 100g of the molecule is 85.7g.The mass of Hydrogen (H) in 100g of the molecule is 14.3g.To find the ratio, we need to divide the masses of each element by their respective atomic masses and then divide the result by the smallest value obtained:
Number of moles of C = 85.7 g / 12.01 g/mol = 7.14 molNumber of moles of H = 14.3 g / 1.01 g/mol = 14.15 molThe smallest value is 7.14 mol, so we divide both values by 7.14:
C: 7.14 mol / 7.14 mol = 1H: 14.15 mol / 7.14 mol = 1.98 ≈ 2To learn more about empirical formula, here
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questions.
Which element is number 14 on the periodic table?
Answer:
silicon
Explanation:
the 14th element in the periodic table of elements.
The element number 14 on the periodic table is silicon (Si).
What is Silicon?Silicon is a chemical element with atomic number 14 and symbol Si. It is a metalloid and a member of the carbon group, located in Group 14 of the periodic table.
Silicon is the second most abundant element on Earth's crust, and it is widely used in various industries, especially in electronics and semiconductors. It is a crucial component in the production of computer chips, solar cells, and other technological applications. Silicon is known for its semiconducting properties, making it a fundamental element in modern technology.
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can anyone tell me the answer
Answer:
A. A as concentration decreases.
Explanation:
A represents a reactant and B is a product, the concentration of the latter increases at the expense of the concentration of the former. Hence, A is the reactant of the chemical reaction as its concentration decreases.
Need help with this salt chapter
For each of the given salt preparations, the method and additional reagent needed for the preparation as well as the complete equation of the reaction is given below:
(i) The soluble salt copper (II) sulfate, from the insoluble base, copper (II) oxide:
Method: add an excess of base or metal to dilute acid and remove the excess by filtration
Reagent: copper (ii) oxide and sulfuric acid
Word equation: copper (ii) oxide + sulfuric acid --> copper (ii) sulfate + water
(ii) The soluble salt, potassium chloride, from soluble base potassium hydroxide;
Method: use a burette and indicator;
Reagent: potassium hydroxide and hydrochloric acid
Symbol equation: KOH + HCl ---> HCl + H₂O
What are salts?Salts are compounds that are formed when all or some of the ionizable hydrogen of acids are replaced by metallic ions.
Depending on the nature and solubility of a salt, there are three methods of preparing salts.
Method A-- use a burette and indicator; for soluble salts
Method B----mix two solutions and obtain the salt by precipitation; for insoluble salts
Method C- add an excess of base or metal to dilute acid and remove the excess by filtration; for soluble salts.
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Why is glucose able to pass through the gut wall
Answer:
Porque las moléculas de glucosa son salvajes
Explanation:
Answer:
Glucose cannot move across a cell membrane via simple diffusion because it is simple large and is directly rejected by the hydrophobic tails. Instead it passes across via facilitated diffusion which involves molecules moving through the membrane by passing through channel proteins.
Explanation:
can i get help with this dont really get it
Answer:
Number 2 is Direction
Explanation:
The old answer for number four was incorrect
I apologize for the inconvenience but I do not have an answer that fits in the lines for number 4
qual masses of he and ne are placed in a sealed container. what is the partial pressure of he if the total pressure in the container is 6 atm?
If equal masses of He and Ne are placed in a sealed container, the partial pressure of He in the container would be 3 atm, as the total pressure is 6 atm and the partial pressure of Ne would be 3 atm as well.
The partial pressure of a gas in a container is determined by the amount of the gas present in the container and its temperature. In a sealed container, the amount of gas present is fixed, so the pressure of each gas is determined solely by its temperature. In the case of equal amounts of He and Ne, the partial pressure of He would be equal to the partial pressure of Ne, resulting in a total pressure of 6 atm.
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15. The specific heat of silver is 0.24 J/g*^ 0 C How many joules of energy are needed to warm 4.37 g of silver from 25.0C to 27.5 degrees * C ? 0.14 J 46 J 0.022 J
2.62J of energy will be required to warm a silver metal from a temperature of 25°C to 27.5°C.
How to calculate joules?The energy required in a calorimetry can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureAccording to this question, 4.37 g of silver should be heated from 25°C to 27.5°C. The heat required is as follows:
Q = 4.37 × 0.24 × (27.5 - 25)
Q = 1.0488 × 2.5
Q = 2.62J
Therefore, 2.62J of energy will be required to warm a silver metal from a temperature of 25°C to 27.5°C.
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How many moles of C2H6 in 3.754 x 1023 molecules of C2H6?
Answer:
n=N/NA
n= 3.754×10²³/6.02×10²³
n= 6.24 s
Explanation
since there is number of molecules, make use of Avogadro's constant to get number of moles.
The Cs-131 nuclide has a half-life of 30 years. After 120 years, 4.1 gremain. What is the original mass of the Cs-131 sample in grams?
From the problem, we know that:
The half-life of the nuclide is 30 years.
The time that we're going to study are 120 years.
The first thing we need to do is to find the number of half-lives that has elapsed (n). To do this, we divide the time studied by the half life:
How to determine the original mass?
We know that the amount remaining (N) is = 4.1g and the number of half-lives (n) = 4. To find the original amount (No), what we do is to use the following equation:
The original mass of Cs-131 sample was 65.6 grams.
write a balanced chemical equation that describes the double displacement reaction between these solutions. (include states-of-matter under the given conditions in your answer.)
To write a balanced chemical equation for a double displacement reaction, we need to know the reactants involved. In this case, we have two solutions that will undergo a reaction. Let's say we have solution A and solution B. To write the equation, we need to know the compounds present in each solution.
In this reaction, the silver ion (Ag+) from silver nitrate combines with the chloride ion (Cl-) from sodium chloride to form silver chloride (AgCl), which is a solid precipitate. The sodium ion (Na+) from sodium chloride combines with the nitrate ion (NO3-) from silver nitrate to form sodium nitrate (NaNO3), which remains in the aqueous state.
It's important to note that the states of matter can vary depending on the specific compounds involved in the reaction. Always check the solubility rules to determine whether a precipitate forms or if the compounds remain in the aqueous state.
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suppose 0.850 l of 0.400 m h2so4 is mixed with 0.800 l of 0.250 m koh . what concentration of sulfuric acid remains after neutralization?
The concentration of sulfuric acid that remains after neutralization is 0.056 M.
To find out what concentration of sulfuric acid remains after neutralization, you will need to use the balanced equation for the reaction:
H2SO4 + 2KOH → K2SO4 + 2H2O
First, you will need to determine the moles of each reactant in the solution.
Moles can be determined using the formula:
moles = concentration x volume
In this case:
moles of H2SO4 = 0.850 L x 0.400 M = 0.34 mol
moles of KOH = 0.800 L x 0.250 M = 0.2 mol
Since the reaction is a 1:2 ratio, you will need to determine which reactant is limiting the reaction.
To do this, compare the mole ratios of the reactants:
0.34 mol H2SO4 : 0.2 mol KOH = 1.7 : 1
Since the ratio of H2SO4 to KOH is greater than 1:2, KOH is the limiting reactant. Therefore, all of the KOH is used up in the reaction, leaving some H2SO4 unreacted.
To find the amount of H2SO4 remaining, you will need to use the mole ratio of H2SO4 to KOH.
Since 2 moles of KOH react with 1 mole of H2SO4, you can use the mole ratio:
0.2 mol KOH x (1 mol H2SO4 / 2 mol KOH) = 0.1 mol H2SO4 remaining
Finally, you can determine the concentration of the H2SO4 remaining:
concentration = moles / volume
concentration = 0.1 mol / (0.850 L + 0.800 L)
concentration = 0.056 M
Therefore, the concentration of sulfuric acid that remains after neutralization is 0.056 M.
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in a battery there is energy ...
A. light
b. hot
c. electricity
d. chemistry
Answer: D
Explanation:
Give the expected hybridization of the central atom for the following molecules or ions.(a) NO3−(b) CCl4(c) NCl3(d) NO2−
The expected hybridization of the central atom for the following molecules or ions.
(a) \(NO^{3-}\)= \(sp^2\)
(b) \(CCl_4\) = \(sp^3\)
(c) \(NCl_3\) = \(sp^3\)
(d) \(NO^{2-}\) = \(sp^2\)
(a) The central atom in \(NO^{3-}\) is nitrogen, which has a total of 5 valence electrons. To form the three N-O bonds, nitrogen uses three of its valence electrons, and there is one lone pair left. Therefore, the expected hybridization of the central atom is \(sp^2\).
(b) The central atom in \(CCl_4\) is carbon, which has a total of 4 valence electrons. To form the four C-Cl bonds, carbon uses all of its valence electrons, and there are no lone pairs left. Therefore, the expected hybridization of the central atom is \(sp^3\).
(c) The central atom in \(NCl_3\) is nitrogen, which has a total of 5 valence electrons. To form the three N-Cl bonds, nitrogen uses three of its valence electrons, and there is one lone pair left. Therefore, the expected hybridization of the central atom is \(sp^3\).
(d) The central atom in \(NO^{2-}\) is nitrogen, which has a total of 5 valence electrons. To form the two N-O bonds, nitrogen uses two of its valence electrons, and there are two lone pairs left. Therefore, the expected hybridization of the central atom is \(sp^2\).
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Which major branch of chemistry would be most concerned
with studying a series of chemical reactions in order to
measure the amount of heat being released in each one?
Physical chemistry a major branch of chemistry would be most concerned with studying a series of chemical reactions in order to measure the amount of heat being released in each one.
Understanding the physical characteristics of atoms and molecules, how chemical processes take place, and what these characteristics indicate are the main goals of physical chemists. Their findings are based on an understanding of chemical characteristics and a description of how they behave utilizing physics theories and mathematical calculations.Thermochemistry, which encompasses the study of the heat energy of chemical processes occurring during phase transitions like gas to liquid or vice versa, is one of the main examples of physical chemistry. It provides information on entropy, heat capacity, Gibbs free energy, or formation heat.For more information on chemistry kindly visit to
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Which is the correct theory about the solar system: sun-centered or Earth-centered? Why?
Answer:i dont know thats why imon her
Explanation:
What is the approximate temperature of 1.4 moles of a gas with a pressure of 3.25 atmospheres in a 4.738-liter container
Answer:
134K
Explanation:
Using the ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (Litres)
n = number of moles (mol)
R = gas constant (0.0821 Latm/Kmol)
T = temperature (K)
Based on the information provided, n = 1.4moles, P = 3.25atm, V = 4.738L, T = ?
3.25 × 4.738 = 1.4 × 0.0821 × T
15.3985 = 0.11494T
T = 15.3985/0.11494
T = 133.969
Approximately;
T = 134K
A 2.00 g sample of ammonia is mixed with 4.00 g of oxygen. Which is the
limiting reactant and how much excess reactant remains after the reaction
has stopped?
Answer:
Ammonia is limiting reactant
Amount of oxygen left = 0.035 mol
Explanation:
Given data:
Masa of ammonia = 2.00 g
Mass of oxygen = 4.00 g
Which is limiting reactant = ?
Excess reactant's amount left = ?
Solution:
Balance chemical equation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Number of moles of ammonia:
Number of moles = mass/molar mass
Number of moles = 2.00 g/ 17 g/mol
Number of moles = 0.12 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 4.00 g/ 32 g/mol
Number of moles = 0.125 mol
Now we will compare the moles of ammonia and oxygen with water and nitrogen.
NH₃ : N₂
4 : 2
0.12 : 2/4×0.12 = 0.06
NH₃ : H₂O
4 : 6
0.12 : 6/4×0.12 = 0.18
O₂ : N₂
3 : 2
0.125 : 2/3×0.125 = 0.08
O₂ : H₂O
3 : 6
0.125 : 6/3×0.125 = 0.25
The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.
Amount of oxygen left:
NH₃ : O₂
4 : 3
0.12 : 3/4×0.12= 0.09
Amount of oxygen react = 0.09 mol
Amount of oxygen left = 0.125 - 0.09 = 0.035 mol
Metric prefixes 9th grade level
Answer:
A metric prefix is a unit prefix that precedes a basic unit of measure to indicate a multiple or submultiple of the unit. All metric prefixes used today are decadic. Each prefix has a unique symbol that is prepended to any unit symbol.What is the correct formula (IUPAC) for sodium iodide
Answer:
The correct formula is...
Nal
What is the mass of 3.5 moles of silver acetate
[AgCH,COo]?
What is the melting point of Alcohol?
Answer:
-173.5°F
Explanation:
such a weird question lol
Answer:
Explanation:
What is the melting and boiling point of alcohol?
For example, ethanol, with a molecular weight (MW) of 46, has a boiling point of 78 °C (173 °F), whereas propane (MW 44) has a boiling point of −42 °C (−44 °F).
Which pair of elements is most likely to form an ionic compound with each other?
sulfur and carbon
barium and chlorine
oxygen and fluorine
calcium and sodium
If you have 12 atoms of hydrogen before a chemical reaction, how many atoms of hydrogen will be present after the chemical reaction?
Answer:
it is 12
Explanation:
because matter can put be created or destroyed
in a redox reaction, reduction means ________, and oxidation means ________.
In a redox reaction, reduction means gain of electrons, and oxidation means loss of electrons.
Redox reactions, also known as oxidation-reduction reactions, include reactions in which there is a transfer of electrons between atoms or ions. In such a reaction, there are two half-reactions, one for oxidation and one for reduction. Oxidation is the process in which an atom or ion loses electrons, resulting in an increase in oxidation state, while reduction is the process in which an atom or ion gains electrons, resulting in a decrease in oxidation state.
In simpler terms, reduction means gain of electrons, while oxidation means loss of electrons. For instance, if zinc oxide is reduced with carbon, carbon is oxidized as it gains oxygen and zinc is reduced as it loses oxygen. The reaction can be represented by the following half-reactions:
ZnO → Zn + O₂ (reduction)
C + O₂ → CO₂ (oxidation)
Hence, zinc oxide is reduced while carbon is oxidized.
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at room temperature which reaction would be expected to have the fastest reaction rate?
1) Pb2+(aq) + S2-(aq) --> Pb S(s)
2) 2H2(g) + O2(g) --> 2H2O(l)
3) N2(g) + 2O2(g) --> 2NO2
4) 2KClO3(s) --> 2KCl(s) + 3O2(g)
At room temperature, the reaction with the fastest reaction rate would likely be option 3) N2(g) + 2O2(g) --> 2NO2. This is because this reaction involves the breaking of a relatively weak triple bond between the two nitrogen atoms, allowing them to form bonds with oxygen atoms to create NO2 molecules.
In contrast, options 1) and 2) involve the formation of relatively strong covalent bonds, which would require more energy to break and therefore have slower reaction rates. Option 4) involves the decomposition of KClO3, which requires a high activation energy to break the bond between the K and ClO3 ions, and so would also have a slower reaction rate than option 3).
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Nitrogen gas (N2) and hydrogen gas (H2) combine to form ammonia (NH3).
Which equation correctly represents this reaction?
Responses
N2 + 3H2 → 2NH3
upper case N subscript 2 end subscript plus 3 upper case H subscript 2 end subscript rightward arrow 2 upper case N H subscript 3 end subscript,
N + H → NH
upper case N plus upper case H rightward arrow upper case N H,
2NH → N + 3H2
2 upper case N H rightward arrow upper case N plus 3 upper case H subscript 2 end subscript,
2N2 + H2 → 3NH3
2 upper case N subscript 2 end subscript plus upper case H subscript 2 end subscript rightward arrow 3 upper case N H subscript 3 end subscript,
The equation is 2N2 + H2 → 3NH3 ,2 upper case N subscript 2 end subscript plus upper case H subscript 2 end subscript rightward arrow 3 upper case N H subscript 3 end subscript.
What is balanced equation ?A chemical equation that is balanced conserves mass and has an equal number of atoms of each element on both sides of the equation.
A chemical equation that is balanced has equal masses for the reactants and products, contains the same amount of atoms of each element on both sides of the equation.
Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Different elements' atom counts in the reactants and products of unbalanced chemical equations are different.
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Please select the following statement that is NOT true about diazonium salts. a. Aryldiazonium salts are used in the synthesis of commercially available dyes through coupling reactions between activated aromatic compounds. b. Alkyldiazonium salts are likely to decompose and give a variety of products because N2 is far more stable than R-N2, where R is an alkyl group. c. Aryldiazonium salts are moderately stable in water at 0 °C because the System of the aromatic ring stabilizes the п system of the N2+, the diazonium ion. d. Diazotization and coupling reactions must be performed at least 1 suppress the hydrolysis of the diazonium salt.
The statement that is NOT true about diazonium salts is option C, which says that aryldiazonium salts are moderately stable in water at 0 °C because the system of the aromatic ring stabilizes the п system of the N2+, the diazonium ion.
In reality, diazonium salts are highly reactive compounds that can easily undergo hydrolysis, which results in the release of nitrogen gas and the formation of an aryl or alkyl cation. Therefore, it is important to suppress the hydrolysis of diazonium salts during diazotization and coupling reactions.
Aryldiazonium salts are commonly used in the synthesis of commercially available dyes through coupling reactions with activated aromatic compounds. These salts are relatively stable and can be stored at low temperatures, but they should still be handled with caution because they can be explosive under certain conditions.
On the other hand, alkyl diazonium salts are highly unstable and are likely to decompose when exposed to heat, light, or moisture. This is because N2 is far more stable than R-N2, where R is an alkyl group. When alkyl diazonium salts decompose, they can give a variety of products, including alkenes, alkanes, and alkyl radicals.
In summary, diazonium salts are important intermediates in organic synthesis, but they are highly reactive and should be handled with care. Diazotization and coupling reactions must be performed under controlled conditions to prevent hydrolysis and other side reactions. Aryldiazonium salts are more stable than alkyl diazonium salts, but both types of compounds require careful handling and storage.
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unlike a mixture, a compound has a chemical formula that is always the same. T/F
A compound always has a chemical formula that remains the same, distinguishing it from a mixture. The chemical formula of a compound represents the fixed ratio and types of elements present within it.
A compound is formed through a chemical reaction where different elements combine in a specific ratio to create a new substance with distinct properties. The resulting compound has a consistent chemical formula that represents the elemental composition of the compound. This formula remains the same regardless of the source or quantity of the compound.
For example, water (H2O) is a compound with a fixed ratio of two hydrogen atoms to one oxygen atom. It will always have this ratio, whether it is derived from a natural source or synthesized in a laboratory. On the other hand, a mixture is a physical combination of substances without undergoing a chemical reaction.
Mixtures can have varying compositions and can be separated into their individual components through physical means such as filtration or distillation. Unlike compounds, mixtures do not have a fixed chemical formula and can exhibit different properties depending on the relative amounts of the substances involved.
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Calculate the pH if the pOH = 0.59.
Answer:
pH = 13.41
Explanation:
You can calculate the pH using the following formula:
pH + pOH = 14
You can plug the given pOH into the equation and simplify to find the pH.
pH + pOH = 14
pH + 0.59 = 14
pH = 13.41
The following equation represents a laboratory preparation for oxygen gas: ____KClO3 → ____KCl + ____O2 (not balanced) How many moles of O2 form if 33.0 mol of KClO3 are totally consumed?
33.0 mol of KClO3 are totally consumed, approximately 49.5 moles of O2 will be formed.
To determine the number of moles of O2 formed when 33.0 mol of KClO3 are consumed, we can use the balanced equation for the reaction:
2KClO3 → 2KCl + 3O2
From the balanced equation, we can see that the stoichiometric ratio between KClO3 and O2 is 2:3. This means that for every 2 moles of KClO3 consumed, 3 moles of O2 are formed.
Given that we have 33.0 mol of KClO3, we can set up a proportion to find the number of moles of O2 formed:
(33.0 mol KClO3) x (3 mol O2 / 2 mol KClO3) = 49.5 mol O2
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