A necklace chain costs $15. Beads cost $2.75 each. You spend a total of $28.75 on a necklace and beads before tax. Type an equation that models this situation (use x as the variable).

Answer:

25

\( {15}^{2} + {20}^{2} = 625 \)

\( \sqrt{625} = 25\)

Answer 25

Explantion : 15^2+20^2=c^2 255+400=c^2

divide x625 = 25

Finite-state machines for given inputs: (a) 0s multiple of 3: 3-state machine. (b) At least four 1s: 4-state machine. (c) Exactly one 1: 2-state machine. (d) Begins with 000: 3-state machine. (e) Second is 0, fourth is 1: 4-state machine. (f) 01 pairs or 2 1s + 0s: 3-state machine. (g) Ends in 110: 3-state machine.

To construct finite-state machines that act as recognizers for the given inputs, we can follow these guidelines:

(a) For the set of all strings where the number of 0s is a multiple of 3, we can use a finite-state machine with three states. Start with the initial state, and transition to the next state whenever a 0 is encountered. After three transitions, go back to the initial state. If the machine ends in the accepting state, output 1.
(b) For the set of all strings containing at least four 1s, we can use a finite-state machine with four states. Start with the initial state, and transition to the next state whenever a 1 is encountered. If the machine enters the final state after four transitions, output 1.

(c) For the set of all strings containing exactly one 1, we can use a finite-state machine with two states. Start with the initial state and transition to the final state when the first 1 is encountered. Output 1 only if the final state is reached.

(d) For the set of all strings beginning with 000, we can use a finite-state machine with three states. Start with the initial state and transition to the next state whenever a 0 is encountered. If the machine reaches the final state after three transitions, output 1.

(e) For the set of all strings where the second input is 0 and the fourth input is 1, we can use a finite-state machine with four states. Start with the initial state and transition to the next state based on the inputs. Output 1 only if the machine reaches the final state.

(f) For the set of all strings consisting entirely of any number (including none) of 01 pairs or consisting entirely of two 1s followed by any number (including none) of 0s, we can use a finite-state machine with three states. Start with the initial state and transition based on the inputs. Output 1 only if the final state is reached.

(g) For the set of all strings ending in 110, we can use a finite-state machine with three states. Start with the initial state and transition based on the inputs. Output 1 only if the final state is reached.

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Finite-state machines (FSMs) can be constructed to act as recognizers for specific patterns in input strings. These are examples of how to construct FSMs as recognizers for different patterns in input strings. Each FSM is designed to produce an output of 1 when the input received matches the description provided.

Let's consider the given cases and construct FSMs for each one.

(a) The set of all strings where the number of Os is a multiple of 3:
To construct an FSM for this, we can keep track of the number of Os encountered so far. Initially, set the count to zero. When an O is encountered, increment the count by one. If the count becomes a multiple of 3, the FSM outputs 1; otherwise, it outputs 0. Reset the count to zero whenever a 1 is encountered.

(b) The set of all strings containing at least four 1s:
To create an FSM for this, we can keep track of the number of 1s encountered so far. Initially, set the count to zero. When a 1 is encountered, increment the count by one. If the count becomes equal to or greater than four, the FSM outputs 1; otherwise, it outputs 0.

(c) The set of all strings containing exactly one 1:
To build an FSM for this, we can have two states: a "no 1 encountered" state and a "1 encountered" state. Initially, start in the "no 1 encountered" state. Whenever a 1 is encountered, transition to the "1 encountered" state. If another 1 is encountered in the "1 encountered" state, transition to a third "more than one 1 encountered" state. In this case, the FSM outputs 0. Otherwise, if no additional 1s are encountered, the FSM outputs 1.

(d) The set of all strings beginning with 000:
To create an FSM for this, start in an initial state. When a 0 is encountered, transition to a second state. If two consecutive 0s are encountered in the second state, transition to a third state. Finally, if a third 0 is encountered in the third state, the FSM outputs 1; otherwise, it outputs 0.

(e) The set of all strings where the second input is 0 and the fourth input is 1:
To construct an FSM for this, start in an initial state. When the first input is read, transition to a second state. In the second state, transition to a third state if the second input is 0. In the third state, transition to a fourth state if the third input is not 0. Finally, in the fourth state, if the fourth input is 1, the FSM outputs 1; otherwise, it outputs 0.

(f) The set of all strings consisting entirely of any number (including none) of 01 pairs or consisting entirely of two Is followed by any number (including none) of Os:
To create an FSM for this, we can have multiple states to represent different scenarios. We start in an initial state and transition to a second state when a 0 is encountered. In the second state, transition back to the initial state if a 1 is encountered. If a 1 is encountered in the initial state, transition to a third state. In the third state, transition to a fourth state if an O is encountered. Finally, if an O is encountered in the fourth state, the FSM outputs 1; otherwise, it outputs 0.

(g) The set of all strings ending in 110:
To construct an FSM for this, start in an initial state. Transition to a second state if a 1 is encountered. In the second state, transition to a third state if a 1 is encountered again. Finally, if a 0 is encountered in the third state, the FSM outputs 1; otherwise, it outputs 0.

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Answer:

4≤x<7

x€[4,7)

Step-by-step explanation:

8≤2x<x+7

=>8≤2x

=>2x<x+7

x≥4

x<7

therefore

4≤x<7

x€[4,7)

The probability of an event happening is calculated by possible events divided by total events.

From a standard deck of 52 cards, there are 13 spades.

So the possible events are 13 and the total events are 52

This will be:

prob = 13/52 = 1/4

The answer is 1/4

Answer:

B) 131°

Step-by-step explanation:

-4a + 139 = 4a + 123 because they are vertical angles

-4a + 139 = 4a + 123

reduce:

8a = 16

a = 2

4(2) + 123 = 131°

Answer:

Use M a t h w a y it helps. Trust me.

The sum of scores in quizzes of math is \(\boldsymbol{885}\).

"To understand the calculation, check below."

Mean is calculated by dividing sum of all the observations by number of observations.

For a data collection containing numbers that are close together, the mean is the best option.

Total number of quizzes in math \(=10\)

Mean scores \(=88.5\)

Therefore,

Sum of all scores \(=10 \times 88.5\) \(=\boldsymbol{885}\)

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To find the probability that the battery life is 20 hours or longer for each phone using the normcdf function on a calculator, we need the mean and standard deviation of the battery life distribution.

The normcdf function is used to calculate the cumulative probability of a given range in a normal distribution. It requires three inputs: the upper bound, the lower bound, and the mean and standard deviation of the distribution.

Assuming we have the mean (μ) and standard deviation (σ) for each phone's battery life, we can input these values along with the lower bound (20) and a large upper bound (e.g., 10^99) into the normcdf function.

The normcdf function calculates the cumulative probability from the lower bound to the upper bound of a normal distribution. In this case, we are interested in the probability of the battery life being 20 hours or longer, so we use 20 as the lower bound.

By entering the appropriate values into the normcdf  function, the calculator will provide the probability that the battery life is 20 hours or longer for each phone based on their respective mean and standard deviation.

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Around 7,000 dollars was cost the family to move from new york to florida.

Compared to multiplication, division is the opposite. When you divide 12 into three equal groups, you get four in each group if three groups of four add up to 12, which they do when you multiply.The primary objective of division is to count the number of equal groups that are created or the number of individuals in each group after a fair distribution.

Given that :A move from New York to Florida costs $0.70 per pound, according to a moving company. A family's possessions are estimated to weigh around 5 tons.

Find out how many pounds are in a ton first. One ton is equal to 2000 pounds. The price for a pound is 70 cents; to find the price for a ton, multiply that figure by 2000. You would receive $1,400. Next, divide 1,400 by 5 to get how much 5 tons would cost. It was around 7,000 dollars.

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Step-by-step explanation:

x - 1 + 5x = 23

6x - 1 = 23

6x = 23 + 1 = 24

6x = 24

x = 24/6

x = 4 ans.

HOPE THIS ANSWER HELPS YOU DEAR! TAKE CARE.

To find the variance, the mean of the lengths of the rivers has to be calculated first. The variance formula is then used to calculate the variance. The variance is 1057.58. Thus, the correct option is C.

The lengths (in kilometers) of rivers on the South Island of New Zealand that flow to the  T as man Sea are given below: River Length (km)Hollyford76Cascade64Arawhata68Haast64Karangarua37Cook32Waiho32

Whataroa51Wanganui56Waitaha40Hokitika64Waimea48Motueka108Takaka72Aorere72Heaphy35

Karamea80Mokihinui56Buller177Grey121Taramakau80Arahura56The mean length of the rivers is given by `bar(x)=(76+64+68+64+37+32+32+51+56+40+64+48+108+72+72+35+80+56+177+121+80+56)/21=69.19`.The variance is calculated using the following formula: `s^2=sum_(i=1)^n (x_i-bar(x))^2/(n-1)`.

Therefore, `s^2=(76-69.19)^2+(64-69.19)^2+(68-69.19)^2+(64-69.19)^2+(37-69.19)^2+(32-69.19)^2+(32-69.19)^2+(51-69.19)^2+(56-69.19)^2+(40-69.19)^2+(64-69.19)^2+(48-69.19)^2+(108-69.19)^2+(72-69.19)^2+(72-69.19)^2+(35-69.19)^2+(80-69.19)^2+(56-69.19)^2+(177-69.19)^2+(121-69.19)^2+(80-69.19)^2+(56-69.19)^2)/(21-1)=1057.58`.

Therefore, the variance is 1057.58.

Thus, the correct option is C.

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The distributive property states that for any real numbers a, b and c, the following is true:

a(b + c) = ab + ac

To use the distributive property to write an expression that is equivalent to 6 - 9x, we can factor out the -9x from the second term:

6 - 9x = 6 - 9x + 0 - 0x = 6 - 9x + (-9x) = 6 + (-9x)

Therefore, using the distributive property, we can write an expression that is equivalent to 6 - 9x as:

6 + (-9x)

Answer:

-3 ( 3x - 2 )

Step-by-step explanation:

- 9x + 6

To find the value of x when (fog)(x) = -8, we first need to find the composition of f and g, which is given by (fog)(x) = f(g(x)). To do this, we substitute g(x) into the expression for f(x) and simplify:

f(g(x)) = f(1) when g(x) = 1

f(g(x)) = f(-2) when g(x) = -2

f(g(x)) = f(3) when g(x) = 3

f(g(x)) = f(-4) when g(x) = -4

f(g(x)) = f(4) when g(x) = 4

There is no value of x for which (fog)(x) = -8.

Using the table given in the question, we can find the values of f(g(x)) for each possible value of g(x):

f(g(x)) = f(1) = -2

f(g(x)) = f(-2) = 0

f(g(x)) = f(3) = 32

f(g(x)) = f(-4) = 8

f(g(x)) = f(4) = 4

Therefore, (fog)(x) = -8 is not possible. The closest value we can get to -8 is by setting g(x) = -4, which gives f(g(x)) = f(-4) = 8. Thus, there is no value of x for which (fog)(x) = -8.

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Answer: 8.1

Step-by-step explanation:

Therefore, () r(t) = 4 - 8t evaluated at \(t=0\) is 4, at \(t=1\) is -4, and at \(t=4\)is -28.

To evaluate the dot product ()r(t), we first need to find the coordinates of the vector :

() = ⟨2, -2, 4⟩

Then we can substitute the coordinates of r(t) into the dot product formula:

\(()r(t) = (2t^2 - 2 - 2t^2, -2t^2 - 2t^3, 4 - 6t) ⋅ ⟨2, -2, 4⟩\)

Simplifying this expression yields:

\(()r(t) = 4 - 8t\)

To evaluate () r(t) at different values of t, we substitute those values into the expression we just derived:

\(() r(0) = 4 - 8(0) = 4\)

\(() r(1) = 4 - 8(1) = -4\)

\(() r(4) = 4 - 8(4) = -28\)

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The range of the function g(x) = |x - 12| - 2 is {y | y > -2}, indicating that the function can take any value greater than -2.

To find the range of the function g(x) = |x - 12| - 2, we need to determine the set of all possible values that the function can take.

The absolute value function |x - 12| represents the distance between x and 12 on the number line. Since the absolute value always results in a non-negative value, the expression |x - 12| will always be greater than or equal to 0.

By subtracting 2 from |x - 12|, we shift the entire range downward by 2 units. This means that the minimum value of g(x) will be -2.

Therefore, the range of g(x) can be written as {y | y > -2}, which means that the function can take any value greater than -2. In other words, the range includes all real numbers greater than -2.

Visually, if we were to plot the graph of g(x), it would be a V-shaped graph with the vertex at (12, -2) and the arms extending upward infinitely. The function will never be less than -2 since we are subtracting 2 from the absolute value.

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Answer: A' ( -1,4) , B' (-4,4), C'(  -5 ,-1), D'( -1,-5)

Im not 100% sure its correct, its hard without an image or a picture of the problem

Step-by-step explanation:

a)  A quadratic model seem appropriate, The ball has been launched from an initial height of 1 inch and has reached the highest point of 8 inches after 3 seconds. We can observe that the trajectory of the ball is in the shape of a parabola. Hence, a quadratic model seems appropriate.

b) Construct a quadratic function h(t) that gives the height of the ball t seconds after being fired. A quadratic function is defined as:h(t) = a(t - b)² + c

Where a is the coefficient of the squared term, b is the vertex (time taken to reach the highest point), and c is the initial height.

Let us find the coefficients of the quadratic function h(t):The initial height of the ball is 1 inch, which means c = 1. The maximum height reached by the ball is 8 inches at 3 seconds, which means that the vertex is at (3, 8).

So, b = 3.Let us find the value of a.

We know that at t = 0, the height of the ball is 1 inch. So, we can write:1 = a(0 - 3)² + 8

Solving for a, we get: a = -1/3Therefore, the quadratic function that gives the height of the ball t seconds after being fired is: h(t) = -(1/3)(t - 3)² + 1

Therefore, the height of the ball at any time t after being fired can be given by the quadratic function h(t) = -(1/3)(t - 3)² + 1.

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The parallel line has an equation of y = 2x - 21

The equation is given as

y = 2x + 3

The equation of a line can be represented as

y = mx + c

Where

slope = m

By comparing the equations, we have:

m = 2

The slopes of parallel lines are equal

This means that the slope of the other line is 2

i.e. m = 2

Recall that:

The equation of a line can be represented as

y = mx + c

Where

slope = m = 2

Also, we have

(x, y) = (6, -9)

So, we have

-9 = 2 * 6 + c

This gives

c = -9 - 12

Evaluate

c = -21

So, we have

y = 2x - 21

Hence, the equation of the parallel line is y = 2x - 21

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\(3793 \times {10}^{7} \\ = 37930000000\)

Answer:37930000

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

We know that Last year one gallon costs $3.00

and we also know that it costs %5 more this year.

We know that %100 is always the same which is $3.00

Then since we know $3.00 is %100, we can add %5 to %100 to get %105.

Then you multiply 105/100 by 3 then you will get 3.15 which is what B is

So that means our answer is B

The equation of the line which is perpendicular to this line would be 3x - 2y = 13.

The equation of a parallel line to the line would be 2x + 3y = 0

The slope of the line perpendicular to this would be the negative reciprocal of -2/3, which is 3/2.

So the equation of the perpendicular line is:

y - ( -2 ) = 3/2 (x - 3)

y + 2 = 3/2x - 9/2

2y + 4 = 3x - 9

3x - 2y = 13

The slope of the line parallel to the given line would be equal to the slope of the given line, which is -2/3.

So the equation of the parallel line is:

y - (-2) = -2/3 (x - 3)

y + 2 = -2/3x + 2

y = -2/3x

2x + 3y = 0

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Answer:

where is your 15 points

Step-by-step explanation:

this answer is 8points

ase logo ko pagal mat banaya karo

The value of the interquartile range of the numbers is,

⇒ IQR = 23

We have to given that,

Data set is,

⇒ 7, 29, 14, 2, 34, 6, 11

Now, We can find the first and third quartile of data set as,

Firstly we can arrange the data set in ascending order,

⇒ 2, 6, 7, 11, 14, 29, 34

Take first half for first quartile,

⇒ 2, 6, 7,

First quartile = 6

Take last half for second quartile,

⇒ 14, 29, 34

Second quartile = 29

Thus, The value of the interquartile range of the numbers is,

⇒ IQR = 29 - 6

⇒ IQR = 23

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Answer: H

Step-by-step explanation:

the given equation is

8.3z - 4.1z + 4 = 14.5

4.2z + 4 = 14.5

4.2z = 14.5 - 4 = 10.5

4.2z = 10.5

z = 10.5/4.2

z= 2.5

so the answer is z = 2.5

is it given in the question

to inverse this ?

because i can only see the expression

so i solved according that

Answer: an experiment

Answer:

The answer is B

Acellus Sux

Step-by-step explanation:

the limit is less than 1, the series is convergent according to the Root Test.

To use the Root Test, we first need to identify the term a_n. In this case, a_n is:

a_n = ((n^2 + 4)/(5n^2 + 7))^n

Now, we can apply the Root Test by finding the limit of the nth root of a_n as n approaches infinity:

lim (n -> ∞) ((n^2 + 4)/(5n^2 + 7))^(1/n)

Since the degrees of the numerators and denominators are the same, we can divide the coefficients to find the limit:

lim (n -> ∞) (1/5)^(1/n)

As n approaches infinity, the limit will equal 1/5, because any positive constant raised to the power of (1/n) approaches 1 as n approaches infinity. Since the limit is less than 1, the series is convergent according to the Root Test.

The Root Test is used to determine whether a series converges or diverges.

What does the Root Test say about converging and diverging series?

The Root Test can be used to decide whether a series converges or diverges. The root test states that if:lim_n to inf |a_n|^(1/n) < 1, then the series is absolutely convergent. And if:lim_n to inf |a_n|^(1/n) > 1, then the series is divergent. And if:

lim_n to inf |a_n|^(1/n) = 1,

then the series might be divergent, convergent or divergent to infinity.

Therefore, we can now apply the Root Test to the given series by substituting the values into the formula and solving.

The series given is:(infinity)

[left ( {n^2+4} over {5n^2+7} right )^(n)] n=1

The following expression must be evaluated to use the Root Test for this series:

lim_n to inf |a_n|^(1/n)Let an = (n2+45n2+7​)/n

The formula for the limit is as follows:

lim_n to inf |(n2+45n2+7​)/n|^(1/n)

After simplification, this formula reduces to the following:

lim_n to inf |(1+(45/n) + (7/n^2))  / (5+(7/n^2))|^(1/n)

This formula can be further reduced by dividing the numerator and denominator by n^2 as follows:

lim_n to inf |(1/n^2+(45/n^3)+(7/n^4))/(5/n^2+(7/n^4))|^(1/n)

Now we take the limit of this expression as n approaches infinity.

We get: lim_n to inf |(0+0+0)/(0+0))|^(1/n)

This gives us lim_n to inf |0/0)|^(1/n)

The limit in this case is an indeterminate form.

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Answer:11

Step-by-step explanation:14-3=11

By Applying the segment addition postulate, the numerical length of WX is 11.

According to the segment addition postulate, point W, point V, and point X are collinear, therefore the following equation is true;

VW + WX = VX.

We are given the following:

VX = 14

VW = 3

We need to find the length WX​

Substitute the values into VW + WX = VX

3 + WX = 14

Subtract 3 from both sides

3 + WX - 3 = 14 -3

WX = 11

Therefore, the measure of length of WX is 11.

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