The electric field in front of the wall will be 4.61 × 10⁹ N/C.
What is the electric field?An electrostatic force is a natural environment that covers electric polarization and acts as an attractor or repellent to all other energetic particles in the vicinity. It can also refer to a network of charged particles' test performance.
The electric field is given as,
E = σ / 2ε₀
Where σ is the charge per unit area, ε is the permeability (8.85 x 10⁻¹² N-m² / C²).
A non-conducting wall carries a charge with a uniform density of 8.15 µc / square cm.
The charge per unit area of the wall will be
σ = 8.15 × 10⁻⁶ C/cm²
σ = (8.15 × 10⁻⁶ C/cm²) × (100 cm / m)²
σ = 8.15 × 10⁻² C/m²
Then, at a distance of 2.00 cm, the electric field will be
E = 8.15 × 10⁻² / 2(8.85 x 10⁻¹²)
E = 4.61 × 10⁹ N/C.
The electric field in front of the wall will be 4.61 × 10⁹ N/C.
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Problem # 1: The temperature of a recently manufactured bolt is T(f). It sits in a room that is at temperature of 23
∘
C and cools according to Newton's Law of Cooling, beginning at a temperature of T(0)=30. Thus T
′′
=−
10
10
(T−23).T(0)=30. (a) Use Euler's method with step size h=0.5 to find the approximate value of T(3). (b) Repeat part (a), but this time with step size h=0.2. Protiem 41(a) Prevem θ1(b)= Problem #2: Solve the initial value problem in #1 above analytically (by hand). Problem 13 ? Cintaf your answer os a wintiolie futction of t as in thetil Do Nor inciude ' T ' ' in your answer.
In problem #1, the temperature of a bolt cooling in a room is given by the differential equation T'' = -10/10(T - 23), with an initial condition T(0) = 30. Part (a) asks to use Euler's method with a step size of h = 0.5 to approximate the value of T(3). Part (b) asks to repeat the approximation with a step size of h = 0.2. Problem #2 involves solving the initial value problem analytically.
(a) To approximate T(3) using Euler's method with h = 0.5, we start with the initial condition T(0) = 30 and iteratively calculate the values of T using the formula T(n+1) = T(n) + h * T'(n), where T'(n) is the derivative of T at time n. By performing the calculations for n = 0, 1, 2, and 3, we obtain an approximation for T(3).
(b) Similar to part (a), we use Euler's method with h = 0.2 to approximate T(3). We repeat the iterative process and calculate T(n+1) using the formula T(n+1) = T(n) + h * T'(n) for n = 0, 0.2, 0.4, ..., 3.
Problem #2 asks to solve the initial value problem analytically. This involves finding the general solution to the given differential equation T'' = -10/10(T - 23) and applying the initial condition T(0) = 30. The solution will be a function of t, denoted as T(t), without including T'' in the answer. The exact solution will provide a more precise result compared to the approximations obtained using Euler's method.
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A plane flies along a straight line path after taking off, and it ends up 90.0 km farther east and 200.0 km farther north, relative to where it started. In what direction did it fly on the straight line path?
27° north of east
45 ° north of east
24° north of east
66° north of east
Answer:
24° north of east
Explanation:
tan(x)=90/200 ie x=arctan(90/200)=24°
So the plane took off 24° east.
Answer:
24° north of east
Explanation:
Hope this will help
A circus truck full of monkeys has a mass of 3175 kg. The kinetic energy of the circus truck is 128,587.5 J. Calculate the speed of the truck.
Explanation:
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A circus truck full of monkeys has a mass of 3175 kg. The kinetic energy of the circus truck is 128,587.5 J. The speed of the truck is 9 m/sec
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
Kinetic Energy =(.5) Mass. (Velocity)²
K.E = 0.5 m.v²
81 = v²
v = 9 m/sec
A circus truck full of monkeys has a mass of 3175 kg. The kinetic energy of the circus truck is 128,587.5 J. The speed of the truck is 9 m/sec
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In your own words, describe in as much detail as possible, what air is made of.
Answer:
It is made of 78 percent nitrogen and 22 percent oxygen
Explanation:
Find the heat given off if 1 kg of 125 degree C steam is cooled to 50 degree C water.
\(\\ \sf{:}\Rrightarrow Q=mc\Delta T\)
\(\\ \sf{:}\Rrightarrow Q=1(4184)(75)\)
\(\\ \sf{:}\Rrightarrow Q=313800J\)
\(\\ \sf{:}\Rrightarrow Q=313.8KJ\)
The Playground
A and G are at same height and where
skateboarder starts
E
A
G
ao oon
E
С
vai
OOHO
F
D
O meters
List in order from greatest to least the Kinetic energy from greatest to least.
Drag the boxes in the correct order
1
1
DDDDDD
Which vector has an x-component with a length of 3?
А. С.
B. d
C. a
D. b
Answer:
B.d
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Answer:
D. b
Explanation:
the endpoint of vector b is at 3, which means the length is 3
A 100 kg cyclist travels at 4.5 m/s. A 50 kg gorilla is dropped straight down onto her. What is the new speed of the system?
Mass of cyclist = 100 kg
Mass of gorilla = 50 kg
Initial speed = 4.5 m/s
Let Final speed = s
100 x 4.5 = (100 + 50) x s
450 = 150s
S = 450/150
S = 3
The new speed is 3m/s
A coin has a mass of 7.0g. It is made of a metal alloy of density 5.6g/cm3. Calculate the volume of the coin.
\(\text{Density,}\\\\~~~~~~~~\rho = \dfrac mV\\\\\\\implies V = \dfrac m{\rho}\\\\\\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{\tfrac{5.6 \times 10^{-3}~ \text{kg}}{ 10^{-6} ~\text{m}^3} }\\\\ \\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{5.6 \times 10^{-3} \times 10^6~~ \text{kg}~ \text{m}^{-3}}\\\\\\ \implies V = 1.25 \times 10^{-6}~ \text m^3\\\\\\\implies V =0.00000125~ \text m^3\\\\\text{Hence the volume of the coin is 0.00000125}~ \text m^3\)
Why are cells described as the "building blocks" of all living things?
-)
A)
A cell is the smallest part of the air living things need to breathe.
B)
They are found in everything tiving things teed, including water and food
o
A cell is the smallest part of a living thing that can function on its own.
D
Cells are always stacked in rows, like bricks, to build the parts of living
things.
Answer:
Explanation:
ya B is right
a horizontal pipe narrows from a radius of 0.240 m to 0.130 m. if the speed of the water is 2.00 m/s in the larger pipe, what is the speed in the smaller pipe (in m/s)?
The speed of the water in the smaller pipe is approximately 6.768 m/s.
To determine the speed of the water in the smaller pipe, we can apply the principle of conservation of mass, which states that the mass flow rate is constant in an incompressible fluid.
The mass flow rate is given by the equation:
A₁v₁ = A₂v₂,
where:
A₁ and A₂ are the cross-sectional areas of the larger and smaller pipes, respectively,
v₁ and v₂ are the velocities of the water in the larger and smaller pipes, respectively.
We are given the following values:
Radius of the larger pipe (r₁) = 0.240 m
Radius of the smaller pipe (r₂) = 0.130 m
Velocity of the water in the larger pipe (v₁) = 2.00 m/s
Using the formula A = πr² for the cross-sectional area of a pipe, we can calculate the cross-sectional areas:
A₁ = π(r₁)²,
A₂ = π(r₂)².
Let's substitute the given values into the equations:
A₁ = π(0.240 m)² ≈ 0.18096 m²,
A₂ = π(0.130 m)² ≈ 0.05351 m².
Now we can rearrange the equation A₁v₁ = A₂v₂ to solve for v₂:
v₂ = (A₁v₁) / A₂.
Substituting the values we have:
v₂ = (0.18096 m² * 2.00 m/s) / 0.05351 m² ≈ 6.768 m/s.
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What is (Fnet3)x ( F n e t 3 ) x , the x-component of the net force exerted by these two charges on a third charge q3 q 3 = 50.0 nC n C placed between q1 q 1 and q2 q 2 at x3 x 3 = -1.170 m m ? Your answer may be positive or negative, depending on the direction of the force.
The x-component of the net force exerted by q1 and q2 on q3 is -\(4.72 x 10 ^- ^9\) N.
What is the value of the x-component of the net force exerted by q1 and q2 on q3?The net force exerted by two charges q1 and q2 on a third charge q3 can be calculated using Coulomb's law. In this case, the x-component of the net force is found to be \(-4.72 x 10^- ^9\)N, which means the force is directed towards the left. This value is calculated using the formula F = kq1q2 / r², where k is Coulomb's constant, q1 and q2 are the charges of the two sources, and r is the distance between them.
The direction of the force depends on the sign of the charges and their relative position.
The negative value of the x-component of the net force in this case indicates that the forces from q1 and q2 are acting in opposite directions, with q1 attracting q3 to the right and q2 repelling q3 to the left. The distance between q3 and q1 is smaller than the distance between q3 and q2, so the force from q1 dominates and results in a net force towards the left.
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(c) Another spring has a spring constant of 250 N/m.
Calculate the work done in stretching the spring by 0.30 m.
State the unit.
Use the equation
E = 12 x K x x2
a ball on a string is swung overhead in a horizontal circle with a radius of 0.66 m. what speed (in m/s) does the ball need to maintain for there to be a centripetal acceleration of 23 m/s2?
Answer:
The ball is moving in a horizontal circle.
The force acting towards the center of the circle is
F = M a = M * V^2 / R
a = V^2 / R simplifying equation
V = (a / R)^1/2 = (23 / .66)^1/2 = 5.90 m/s
The tilt of Earth's axis causes different seasons. Winter and summer depend on the earth being tilted toward or away from the sun. Earth’s axial tilt fluctuates in a cycle of
Seasons are caused by the tilt of the Earth's axis. Winter and summer are determined by the tilt of the earth towards or away from the sun. The Earth's axial tilt changes every 41,000 years.
Earth's axial tilt is the angle between the Earth's rotational axis and the plane of its orbit around the sun. The current tilt of the Earth's axis is about 23.5 degrees relative to the plane of its orbit. This tilt is responsible for the changing seasons as the Earth orbits the sun.
The axial tilt of the Earth is not constant but changes over a cycle of about 41,000 years. This cycle is known as the obliquity cycle and is caused by gravitational interactions between the Earth and other celestial bodies such as the Moon and Jupiter.
During this cycle, the tilt of the Earth's axis varies between 22.1 and 24.5 degrees, which results in a change in the amount of solar radiation received at different latitudes. This, in turn, affects the distribution of heat on the Earth's surface and influences the climate.
The effect of this cycle on the climate is relatively small compared to other factors such as greenhouse gases and ocean currents. However, it is believed to have played a role in past climate changes, including the ice ages.
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An electron and a positron are moving toward each other and each has speed 0.500c in the lab frame. (a) What is the kinetic energy of each particle
The kinetic energy of each particle is approximately 8.187 × 10⁻¹⁴ J. To find the kinetic energy of each particle, we can use the formula: KE = (γ - 1) * m * c²
γ is the Lorentz factor, m is the rest mass of the particle, and c is the speed of light.
First, let's find the Lorentz factor for each particle. The Lorentz factor is given by:
γ = 1 / √(1 - v² / c²)
where v is the velocity of the particle.
For the electron and positron in this problem, v = 0.500c, so we have:
γ = 1 / √(1 - (0.500c)² / c²) = 1.1547
Next, let's find the rest mass of each particle. The rest mass of the electron is 9.10938356 × 10⁻³¹ kg, and the rest mass of the positron is the same.
Now we can use the formula for kinetic energy to find the energy of each particle. Plugging in the values we have:
KE = (γ - 1) * m * c²
KE_electron = (1.1547 - 1) * 9.10938356 × 10⁻³¹ kg * (299792458 m/s)² = 8.187 × 10⁻¹⁴ J
KE_positron = (1.1547 - 1) * 9.10938356 × 10⁻³¹ kg * (299792458 m/s)² = 8.187 × 10⁻¹⁴ J
So the kinetic energy of each particle is approximately 8.187 × 10⁻¹⁴ J.
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Bob’s mass is 100 kg. Bob can teleport to different planets, fill in this chart.
Based on the information in the graph, it can be inferred that the force that Bob exerts with his weight is 980 N on Earth, 160 N on the moon, 2,590 N on Jupiter, 61 N on Pluto, 373 N on Mercury, and 80 Not in pampering
How to calculate the force that Bob exerts with his mass on different planets?To calculate the force that Bob exerts with his mass on different planets we must carry out the following formula.
P = force of gravity * massIn this formula we must substitute the values of force of gravity and mass to find the values on each planet. According to the above, the N on each planet would be:
980 N on Earth.160 N is the Moon.2,590 N on Jupiter.61 N on Pluto.373 N on Mercury.80 N at Mimas.Learn more about newtons in: https://brainly.com/question/13549064
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Billy jumps upward with a velocity of 4.2 m/s off a 6m high diving board. how long does it take for Billy to hit the water?l
Billy jumps upward with a velocity of 4.2 m/s off a 6m high diving board. . Billy will take 0.43 sec to hit the water
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics.
using equation of kinematics
v = u + g*t
sign convention
positive y direction (upward) = +
negative y direction ( downward ) = -
v = u - g*t
0 = 4.2 - ( 9.8 * t )
t = 4.2 / 9.8
t = 0.43 sec
Billy will take 0.43 sec to hit the water
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If a force of 20 N is applied to a mass of 5 kg, what is the acceleration?
Answer:
4 m/s^2
Explanation:
To get the acceleration you are going to use the acceleration formula which is
Acceleration= Force/Mass.
You then do the math which is 20/5, which equals 4
Therefore you get a value of 4. You may be asking what the units are. The units of acceleration are m/s^2 (meters per second squared)
So your final answer is 4 m/s^2
A circular coil of wire has 300 turns and an average radius of 2:00 cm. The coil is placed at a 60° angle to the uniform magnetic field between the two poles of a large electromagnet. The strength of the field changes at a rate of -0.300 T/s. What is the magnitude of the resulting induced emf?
A circular coil of wire has 300 turns and an average radius of 2:00 cm. The coil is placed at a 60° angle to the uniform magnetic field between the two poles of a large electromagnet. The strength of the field changes at a rate of -0.300 T/s. The magnitude of the resulting induced emf in the circular coil is zero.
To calculate the magnitude of the resulting induced electromotive force (emf) in the circular coil, we can use Faraday's law of electromagnetic induction, which states that the emf induced in a circuit is equal to the rate of change of magnetic flux through the circuit.
The magnetic flux (Φ) through a coil of wire is given by the product of the magnetic field strength (B), the area of the coil (A), and the cosine of the angle (θ) between the magnetic field and the normal to the coil:
Φ = B * A * cos(θ)
In this case, the magnetic field strength (B) is changing at a rate of -0.300 T/s, the area of the coil (A) can be calculated using the formula for the area of a circle (A = π *\(r^2\)), and the angle (θ) is 60 degrees.
First, let's calculate the area of the coil:
A = π * \(r^2\)
A = π *\((0.02 m)^2\)
A =\(0.0012566 m^2\)
Next, let's calculate the rate of change of magnetic flux:
dΦ/dt = B * dA/dt * cos(θ)
dΦ/dt = (-0.300 T/s) * (0) * cos(60°) (since the area does not change with time)
Finally, the induced emf (ε) is equal to the negative of the rate of change of magnetic flux:
ε = -dΦ/dt
ε = -0
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) a 62-kg person riding a bike puts all her weight on each pedal when climbing a hill. the pedals rotate in a circle of radius 17 cm. (a) what is the maximum torque she exerts? (b) how could she exert more torque?
When the 62-kg person is riding a bike and putting all her weight on each pedal, she is applying a force on the pedals. This force creates a torque, which is the rotational force that turns the pedals. To calculate the maximum torque she exerts, we need to multiply the force she applies by the distance from the center of the pedals to the point where the force is applied. In this case, the radius of the circle that the pedals rotate on is 17 cm, so the distance from the center of the pedals to the point where the force is applied is also 17 cm.
(a) The maximum torque she exerts is therefore:
Torque = Force x Distance = (62 kg x 9.81 m/s^2) x 0.17 m = 105.06 Nm
(b) To exert more torque, she could apply more force or increase the distance from the center of the pedals to the point where the force is applied. However, it is important to note that exerting too much torque can put a strain on the bike and the rider's muscles, and can even cause injury. It is important to use proper technique and pacing when riding a bike to avoid overexertion.
Hello! I'd be happy to help you with your question.
a) To calculate the maximum torque exerted by the person on the pedals, we use the formula:
Torque = Force x Radius x sin(θ)
where:
- Force is the person's weight (62 kg * 9.81 m/s²)
- Radius is 0.17 meters (17 cm converted to meters)
- θ is the angle between the force and the radius (90 degrees, since maximum torque occurs when force is perpendicular to the radius)
First, calculate the person's weight:
Force = 62 kg * 9.81 m/s² ≈ 608 N
Next, find the torque exerted:
Torque = 608 N * 0.17 m * sin(90°)
Torque ≈ 103.36 Nm
So, the maximum torque she exerts is approximately 103.36 Nm.
b) To exert more torque, she could:
1. Apply more force on the pedals by pushing harder or increasing her weight.
2. Increase the radius of the circle by using longer pedals or adjusting her foot position farther from the pedal's rotation axis.
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Un clavadista salta del trampolín de 2.8 m con una velocidad inicial de 3.2 m/s.
a. Determina la altura máxima:
b. El tiempo para llegar a la altura máxima:
c. El tiempo para tocar el agua:
d. La velocidad al tocar el agua.
The maximum height achieved by the body is 2.645 meters.
What is the maximum height achieved by the body when thrown upwards with velocity {v}?The maximum height achieved by the body when thrown upwards with velocity {v} is -
h{max} = v²/2g
Given is to find the maximum height achieved by the body.
The maximum height achieved by the body is -
h{max} = v²/2g
h{max} = (2.3)²/20
h{max} = (2.3)²/20
h{max} = 2.645 meters
Therefore, the maximum height achieved by the body is 2.645 meters.
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{A diver jumps off the 2.8 m springboard with an initial velocity of 3.2 m/s.
to. Determine the maximum height.}
Light waves can be easily blocked but ______ waves pass through all substances? ( fill in the blank)
PLEASE HELPPPPPPPPPPPPPPPPPPPP
The first: 1,026m
The second: decreases
The third: 7.9 mya
hope i helped some :))
An object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm. The image height is
Since the magnification is equal to 1, the image height is the same as the object height which is 5 cm
What is Optical Magnification ?Magnification is when the ratio of the size of the image to the size of the object is greater than 1
Given that an object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm.
The object distance u = 20 cmThe object height h = 5 cmFocal length f = 10 cmThe image distance v = ?The image height H = ?To find the image height, let us first find the image distance by using the formula below
1/f = 1/u + 1/v
Substitute all the parameters
1/10 = 1/20 + 1/v
1/v = 1/10 - 1/20
1/v = (2 - 1)/20
1/v = 1/20
v = 20 cm
Magnification = v/u = H/h
20/20 = H/5
H = 5 cm
Therefore, the image height is the same as the object height which is 5 cm
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The variables for Part I of this experiment include whether or not the car hits the barrier and the distance that the washers travel. Use the drop-down menus to identify the independent and dependent variables.
The independent variable, the one that is intentionally manipulated, is
.
The dependent variable, the one that you measure the response in, is
.
The independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.The dependent variable, the one that you measure the response in, is the distance that the washers travel.
The independent variable in an experiment is the variable that is manipulated by the researcher. It is the variable that is intentionally changed by the researcher to examine the impact of this change on the dependent variable.The dependent variable, on the other hand, is the response that is measured by the researcher.
It is the variable that is being influenced by the independent variable in an experiment. Thus, in the given experiment, the car's hitting the barrier is the independent variable while the distance that the washers travel is the dependent variable.
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If a train approaches you (sitting in the bench ) at a velocity of 35 m/s, what frequency will you hear as it sounds its whistle at 188 Hz? speed of sound= 345 m/sA) 188 HzB) 170.7 HzC) 209.2 HzD) 202.7 Hz
Given:
The speed of the train is,
\(v_s=35\text{ m/s}\)The actual frequency of the whistle is,
\(f=188\text{ Hz}\)The speed of sound in air is,
\(v=345\text{ m/s}\)To find:
The frequency heard by the observer
Explanation:
The apparent frequency when the train approaches the observer is given by,
\(\begin{gathered} f_{apparent}=f\frac{v}{v-v_s} \\ =188\times\frac{345}{345-35} \\ =188\times\frac{345}{310} \\ =209.2\text{ Hz} \end{gathered}\)Hence, the frequency heard by you is 209.2 Hz.
How does electromagnetic induction in a moving loop of wire cause an
electric generator to produce an electric current?
A. Mechanical energy flows out of the magnets and into the electric
charges in the loop of wire.
B. Charged particles flow within the wire because they are pushed by
the magnetic field of the magnets.
C. Charged particles flow when the loop of wire is attracted by the
magnetic field of the magnets.
O D. Electrons flow from the magnets into the loop of wire and
continue to flow within the wire.
Answer: Just took it!
Explanation:
Mechanical energy flows out of the magnets and into the electric charges in the loop of wire. Therefore, the correct option is option A among all the given options.
What is electric current?A current is the movement of particles (electrons) across wires and components. It is the charge flow rate. If an electric charge passes through a conductor, scientists say the conductor has an electric current. Electrons form a charge flow in circuits that use metallic conductors.
Electromagnetic induction in a moving loop of wire cause an electric generator to produce an electric current by mechanical energy flows out of the magnets and into the electric charges in the loop of wire cause.
Therefore, the correct option is option A among all the given options.
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camel have humps why
Answer:
camels have humps to store fat which is then converted to energy when food is scarce ( the humps are not used for storing water )
Answer: camels have humps to store fat which is then converted to energy when food is scarce ( the humps are not used for storing water )
a charged particle is moving in a uniform, constant magnetic field. Which one of the following statements concerning the magnetic force exerted on a particle is false? a. It does no work on the particle. b. It can act only on a particle in motion. c. It increases the speed of the particle. d. It changes the velocity of the particle. e. It does not change the kinetic energy of the particle.
The false statement concerning the magnetic force exerted on a charged particle moving in a uniform, constant magnetic field is: c. It increases the speed of the particle.
The magnetic force is always perpendicular to the velocity of the charged particle, causing it to change its direction but not its speed. Therefore, it does no work on the particle (a), can act only on a moving particle (b), changes the velocity (d), and does not change the kinetic energy (e). This is because the magnetic force is perpendicular to the velocity of the particle, so it does not do any work on the particle and thus does not increase its kinetic energy. Therefore, the speed of the particle does not increase due to the magnetic force.
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