a recreational outlet has trampolines on sale. The sky bouncer trampoline's original price is $1,480.00 and is on sale for 15% off. if the sales tax rate is 7.5% what will the final price be? round to the nearest penny
Answers
The final price of the trampolines is determined as $1,352.35.
What will the final price be?The final price of the trampolines is calculated as follows;
The discount amount is calculated as follows;
Discount amount = $1,480 x 0.15
Discount amount = $222
The sale price of the trampolines is calculated as follows;
Sale price = $1,480 - $222.00
Sale price = $1,258
The sales tax is calculated as follows;
Sales tax = $1,258 x 0.075
Sales tax = $94.35
The final price of the trampolines is calculated as follows;
Final price = $1,258 + $94.35
Final price = $1,352.35
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Related Questions
i dont know
what to do here and its due by the end of class
Answers
Answer:
ur screwed but the answer is 110.88
Step-by-step explanation:
:)
please hurry. Find the area of the rectangle. 7n^2 + 3n 2n^3
Answers
Area of a rectangle = Width * Length
In our problem,
width = 2n^3
length = 7n^2 + 3n
Area = 2n^3 (7n^2 + 3n)
Distribute the 2n^3
Area = 14n^5 + 6n^4
The required, area of the given rectangle is given as 14n⁵ + 6n⁴.
What is a rectangle?The rectangle is 4 sided geometric shape whose opposites are equal in lengths and all angles are about 90°.
What is the area of the rectangle?The area of a rectangle is the product of the length and width of the rectangle.
Here,
In the question, we are given,
length = 7n² + 3n
width = 2n³
Area of the rectangle = length × width
Area of the rectangle = 7n² + 3n × 2n³
Area of the rectangle = 14n⁵ + 6n⁴
The required, area of the given rectangle is given as 14n⁵ + 6n⁴.
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Triangle BCD, with vertices B(4,-7), C(6,-8), and D(7,-2), is drawn on the coordinate
grid below.
S
Answer: A =
6
7
D
9
What is the area, in square units, of triangle BCD?
units
Submit Answer
K
Answers
Answer: The area is 6.5
In ️FGH, f=65 inches, g=48 inches and h=70 inches. find the measure of
Answers
Let's take a look at our triangle:
Using the law of cosines, we'll get that:
\(G^2=F^2+H^2-2FH\cos \angle G\)Solving for angle G, we'll get:
\(\begin{gathered} G^2=F^2+H^2-2FH\cos \angle G \\ \rightarrow2FH\cos \angle G^{}=F^2+H^2-G^2 \\ \rightarrow\cos \angle G=\frac{F^2+H^2-G^2}{2FH} \\ \\ \rightarrow\angle G=\cos ^{-1}\frac{F^2+H^2-G^2}{2FH} \end{gathered}\)This way,
\(\begin{gathered} \angle G=\cos ^{-1}\frac{65^2+70^2-48^2}{2(65)(70)} \\ \\ \Rightarrow\angle G=41 \end{gathered}\)
a vendor sells specialty shirts to sports teams for $13 each. a soccer team has $321 to spend on shirts. what is the greatest number of shirts the soccer team can purchase?
Answers
Applying division by successive subtraction method, the maximum number of shirts that can be bought is 24. Below is the solution algorithm.
Algoritmo maximumNumberOfTshirts // define variablesDefinir p,quotient,remainder Como Real
p <- 13 // T-shirt price
quotient <- 0 // Number of T-shirts
remainder <- 321 // available money
// Calculate the maximum number of T-shirts can be bought with 321$ (division by successive subtraction method)Repetir
remainder <- remainder-p
quotient <- quotient+1
Hasta Que remainder<p
// Displaying resultsEscribir 'Maximum number of T-shirts: ',quotient
FinAlgoritmo
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Problem Set A
1 a Name in all possible ways, the line containing A, R, and D.
b Name the sides of ABC.
c What side do 2 and 4 have in
common?
d Name the horizontal ray with end-point C.
e Estimate the sizes of BAD, 2, and
ABC.
f Are angles FCD and DCE different angles?
g Which angle in the figure is B?
Answers
Answer:
use Alex formula okkkkkkkkkkkkkkkkkkkkkkkkkkk
Considering the given figure, the required answers to questions are as stated below:
The given figure has lines and angles which has some relations. The application of the principles in geometry is required to solve this question. So that the following can be deduced from the figure:
1) a. The possible ways are: AR, AD, RA, RD, DR, DA
b. Sides of <ABC are: AB and BC
c. The side that both <2 and <4 have in common is FD
d. The horizontal ray is CFEA
e. <BAD is an acute angle. So that <BAD ≅ \(60^{o}\)
<2 ≅ \(60^{o}\)
< ABC is an obtuse angle. So that <ABC ≅ \(120^{o}\)
f. <FCD and < DCE are the same in measure
i.e <FCD = <DCE
g. The angle in the figure that is <B is <D
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PLZ HELPPPPPPPPPPPPPPPPPPPPPPPP
Answers
Answer:
I think the awnser is probably b
Answer:
m=3.5h
Step-by-step explanation:
Just by looking at this, you know that it won't be either of the adding equations because it only works for the bottom input and output. So, we'll just look at the multiplying ones.
We know that multiplying should get us a bigger number (unless it's a fraction), so the equation h=3.5m won't work very well with this because h would be getting smaller not bigger.
That leaves us with m=3.5h.
To check this, I'll multiply 3.5 by 4 to see if it equals what m is on the table. Sure enough, it's 14. This also works with 2.5 and 8.75.
Find the next number in the pattern: 0.2,0.8,3.2
Answers
Answer:
Step-by-step explanation:
Argument
If you multiply 0.2 by 4, you get 0.8
If you multiply 0.8 by 4, you get 3.2
If you multply 3.2 by 4,, you get 12.8
Answer: 12.8
Please find the length of x
Answers
Answer:
26.55
Step-by-step explanation:
17.55 + 26.1 + 12 = 55.65
11.7 + 17.4= 29.1
55.65 - 29.1 = 26.55
Answer:
Step-by-step explanation:
Corresponding angles are equal.
∠J = ∠N
∠J = 23°
In similar triangles, corresponding parts are same ratio.
\(\dfrac{PM}{KL}=\dfrac{PN}{KJ}\\\\\\\dfrac{x}{12}=\dfrac{11.7}{17.55}\\\\\\x=\dfrac{11.7}{17.55}*12\)
x = 8 m
Someone Help Pls . idkvthis
Answers
Hope this helps
Line c passes through points (1, 14) and (7, 7). Line d is perpendicular to c. What is the slope of line d?
I will give brainliest!! :D
Answers
Answer:
6/7
Step-by-step explanation:
Your first step will be to find the slope of Line C. Using the slope formula of \(\frac{y_{2}-y_1 }{x_2-x_1}\), the slope of Line C is \(\frac{7-14}{7-1} = \frac{-7}{6}\).
If Line D is perpendicular to C, that means the slope is the negative reciprocal of Line C. So, that means the slope is 6/7.
if the area of the shaded region shown below is 120 square units, and the height of the line segment above the horizontal axis is 4 units, what is point a?
Answers
Point A is located at (4, 4) in the coordinate plane.With these dimensions, we can determine that Point A is located at (4, 4) in the coordinate plane.
To find the coordinates of point A, we need to consider the properties of the shaded region. The shaded region consists of a rectangle and a triangle. We know that the area of the shaded region is 120 square units, and the height of the line segment above the horizontal axis is 4 units.
The rectangle's area is given by its length multiplied by its width. Since the height of the rectangle is 4 units, we can deduce that the length of the rectangle is also 4 units. Therefore, the width of the rectangle can be found by dividing the total area of the shaded region by the length of the rectangle.
Subtracting the width of the rectangle from the total width of the shaded region will give us the base of the triangle. Since the triangle is isosceles, the base length is equal to the height of the rectangle.
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mason asked some classmates if they play video games or not. the ratio of friends who play video games to everyone he asked is . how many of his friends do not play video games?
Answers
Mason's friends do not play video games are 4.
Mason asked some classmates whether they play video games.
The ratio of friends who play video games to everyone he asked is given as some fraction or decimal value.
Let's assume that the ratio is in the form of "x:y",
"x" represents the number of friends who play video games, and "y" represents the total number of friends that Mason asked.
To find out how many of his friends do not play video games,
To subtract the number of friends who play video games from the total number of friends that Mason asked.
This is because the remaining friends who were not counted in the "x" value of the ratio must be those who do not play video games.
So, the number of friends who do not play video games can be calculated as:
Total number of friends - Number of friends who play video games = y - x
The ratio of friends who play video games to everyone he asked is 3:7,
It means that out of 7 friends, 3 play video games, and 4 do not play video games.
The number of friends who do not play video games can be calculated as:
y - x = 7 - 3 = 4
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Which graph best represents the solution set of -4x ≤ 6y − 54?
Answers
Answer:
a
Step-by-step explanation:
if its the same one i saw, the answer is a :)
Which expression matches this algebraic expression after using Distributive
property a(b+cq - bd).
abcq - abd
ab+ acq - abd
ab + acq -bd
ab + cq -bd
Answers
Find the average value of the function f(x)=60-12x^2 over the
interval -2(
interval for which the function equals its average value.
Answers
The average value of the function f(x) = 60 - 12x² over the interval [-2, 2] is 59.33.
To find the average value of a function over a given interval, we need to calculate the definite integral of the function over that interval and then divide it by the length of the interval. In this case, the interval is [-2, 2].
The definite integral of f(x) = 60 - 12x² over the interval [-2, 2] can be evaluated as follows: ∫[-2,2] (60 - 12x²) \(dx = [60x - 4x^3/3] [-2,2]\)
Plugging in the upper and lower limits into the antiderivative, we get:
\([60(2) - 4(2)^3/3] - [60(-2) - 4(-2)^3/3]\)
= [120 - 32/3] - [-120 + 32/3]
= 120 - 32/3 + 120 - 32/3
= 240 - 64/3
= 712/3
The length of the interval [-2, 2] is 2 - (-2) = 4.
Therefore, the average value of f(x) over the interval [-2, 2] is: (712/3) / 4 = 178/3 ≈ 59.33
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( NO LINKS ) If x=7, is this equation true? 7 + 9x > 73 *
option 1: Yes
option 2: No
Answers
Answer:
This is FALSE. Choose Option 2
Step-by-step explanation:
Substituting 7 for x, we get
7 + 9(7) > 73, or 70 73. This is FALSE. Choose Option 2
x-7=7-x find solution
Answers
Answer:
7
Step-by-step explanation:
x-7=7-x
2x-7=7
2x=14
x=7
Answer:
x = 7
(Hope this helps! Btw, I am the first to answer. Brainliest pls! :D)
Let A and B be two events such that P(A)=0.29, P(B)=0.3 and P(A|B)=0.3. Let A' be the complement of A, and B' be the complement of B.
(give answers to TWO places past decimal)
a) [1pt] Compute P(A').
Submit Answer Tries 0/99
b) [1pt] Compute P (Au B).
Submit Answer Tries 0/99
c) [2pts] Compute P (B | A).
Submit Answer Tries 0/99
d) [2pts] Compute P (A'n B). [
Submit Answer Tries 0/99
e) [1pt] Are events A and B independent?
Yes
No
Submit Answer Tries 0/99
f) [1pt] Are events A and B disjoint?
Yes
No
Submit Answer Tries 0/99
Answers
.Answer: a)\($0.71$, b) $0.5$, c) $10.34$, d) $0.21$, e) No, f) No.\)
Given,\($P(A)=0.29, P(B)=0.3, P(A|B)=0.3$\) and let $A'$ be the complement of A and \($B'$\)be the complement of B.a) \($P(A')=1-P(A)=1-0.29=0.71$\)Therefore, \($P(A') = 0.71$\) (to two decimal places)b) \($P(A\cup B)=P(A)+P(B)-P(A\cap B)$\)
We know that, \($P(A|B)=\frac{P(A\cap B)}{P(B)}$\)Putting the values, we get \($0.3=\frac{P(A\cap B)}{0.3}$\)Therefore, \($P(A\cap B)=0.3×0.3=0.09$\)
Now, \($P(A\cup B)=P(A)+P(B)-P(A\cap B)$$=0.29+0.3-0.09=0.5$Therefore, $P(A \cup B) = 0.5$ (to two decimal places)c) We know that, $P(B|A)=\frac{P(A\cap B)}{P(A)}$\)
Putting the values, we get\($P(B|A)=\frac{0.3}{0.29}$\)Therefore, \($P(B|A)=\frac{300}{29}=10.34$Therefore, $P(B|A) = 10.34$ (to two decimal places)d) $P(A'\cap B)=P(B)-P(A\cap B)=0.3-0.09=0.21$\)
Therefore, \($P(A' \cap B) = 0.21$\)(to two decimal places)e) As \($P(A\cap B)=P(A)\cdot P(B)$\)is not true.
Hence, the events A and B are dependent.f) As \($P(A\cap B) = 0.09 \neq 0$,\) hence the events A and B are not disjoint.
Answer: \(a) $0.71$, b) $0.5$, c) $10.34$, d) $0.21$, e) No, f) No.\)
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ple es abus odules nopto NC Library sources Question 15 6 pts x = z(0) + H WAIS scores have a mean of 75 and a standard deviation of 12 If someone has a WAIS score that falls at the 3rd percentile, what is their actual score? What is the area under the normal curve? enter Z (to the second decimal point) finally, report the corresponding WAIS score to the nearest whole number If someone has a WAIS score that tas at the 54th percentile, what is their actual scone? What is the area under the normal curve? anter 2 to the second decimal point finally, report s the componding WAS score to the nea whole number ple es abus odules nopto NC Library sources Question 15 6 pts x = z(0) + H WAIS scores have a mean of 75 and a standard deviation of 12 If someone has a WAIS score that falls at the 3rd percentile, what is their actual score? What is the area under the normal curve? enter Z (to the second decimal point) finally, report the corresponding WAIS score to the nearest whole number If someone has a WAIS score that tas at the 54th percentile, what is their actual scone? What is the area under the normal curve? anter 2 to the second decimal point finally, report s the componding WAS score to the nea whole number
Answers
WAIS score at the 3rd percentile: The actual score is approximately 51, and the area under the normal curve to the left of the corresponding Z-score is 0.0307.
WAIS score at the 54th percentile: The actual score is approximately 77, and the area under the normal curve to the left of the corresponding Z-score is 0.5636.
To calculate the actual WAIS scores and the corresponding areas under the normal curve:
For the WAIS score at the 3rd percentile:
Z-score for the 3rd percentile is approximately -1.88 (lookup in z-table).
Using the formula x = z(σ) + μ, where z is the Z-score, σ is the standard deviation, and μ is the mean:
x = -1.88 * 12 + 75 ≈ 51.44 (actual WAIS score)
The area under the normal curve to the left of the Z-score is approximately 0.0307 (lookup in z-table).
For the WAIS score at the 54th percentile:
Z-score for the 54th percentile is approximately 0.16 (lookup in z-table).
Using the formula x = z(σ) + μ, where z is the Z-score, σ is the standard deviation, and μ is the mean:
x = 0.16 * 12 + 75 ≈ 76.92 (actual WAIS score)
The area under the normal curve to the left of the Z-score is approximately 0.5636 (lookup in z-table).
Therefore,
The corresponding WAIS score for the 3rd percentile is 51.
The corresponding WAIS score for the 54th percentile is 77.
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A parabola-shaped hill can be modeled by equation
y=-2(x - 3)2 +6, where x and y are measured in
kilometers.
How wide is the bottom of the hill? Assume the r -axis is
ground level. Round to the nearest tenths.
kilometers
Answers
Answer:3.46 km
Step-by-step explanation:
Given
shape of hill \(y=-2(x-3)^2+6\)
at the bottom y=0 i.e.
\(0=-2(x-3)^2+6\\(x-3)^2=3\\x-3=\pm\sqrt{3}\\x=3\pm\sqrt{3}\)
width of the bottom
\(3+\sqrt{3}-[3-\sqrt{3}]=2\sqrt{3}\ km\ or\ 3.46\ km\)
a bus stops 5 people get off. then 11 people get on a bus now there are 19 people on the bus
Answers
Answer:
13 people
Step-by-step explanation:
If you're looking for how many people were on the bus before the most recent stop.
19-11 = 8
8 + 5 = 13
is the line through points p(-8,-10) and q(-5,-12) perpendicular to the line through points r(9,-6) and s(17,-5)
Answers
we dunno, hmmm let's check for the slope for PQ
\(P(\stackrel{x_1}{-8}~,~\stackrel{y_1}{-10})\qquad Q(\stackrel{x_2}{-5}~,~\stackrel{y_2}{-12}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-12}-\stackrel{y1}{(-10)}}}{\underset{\textit{\large run}} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{-12 +10}{-5 +8} \implies \cfrac{ -2 }{ 3 } \implies - \cfrac{2 }{ 3 }\)
keeping in mind that perpendicular lines have negative reciprocal slopes, then if both are truly perpendicular, then line RS will have a slope of
\(\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ \cfrac{-2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-2} \implies \cfrac{3}{ 2 }}}\)
let's see if that's true
\(R(\stackrel{x_1}{9}~,~\stackrel{y_1}{-6})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{-5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-5}-\stackrel{y1}{(-6)}}}{\underset{\textit{\large run}} {\underset{x_2}{17}-\underset{x_1}{9}}} \implies \cfrac{-5 +6}{8} \implies \cfrac{ 1 }{ 8 } ~~ \bigotimes ~~ \textit{not perpendicular}\)
Answer:
Step-by-step explanation:
No they are not perpendicular.
Perpendicular lines have slopes that are negative reciprocals of each other.
PQ slope = -12 - -10/-5 --8 = -2/3
RS slope = -5 - -6/17 -9 = 1/8
Slope are not negative reciprocals - the lines are not perpendicular.
Slope formula is m = y2 - y1/x2 - x1
Use this to determine slope.
For example if the the slope of RS was 3/2 - the lines would be perpendicular.
Two altitudes of a triangle have lengths $12$ and $15$. What is the longest possible integer length of the third altitude
Answers
Let ABC be the given triangle. We can construct two triangles PAB and PBC such that they share the same height from P to AB and P to BC, respectively. We can label the side lengths of PAB and PBC as x and y, respectively. The total area of the triangle ABC is the sum of the areas of PAB and PBC:
Area_ABC = Area_PAB + Area_PBC We can write the area of each of the sub-triangles in terms of x and y by using the formula for the area of a triangle: Area_PAB = (1/2)(12)(x) = 6xArea_PBC = (1/2)(15)(y) = (15/2)y Setting the areas equal to each other and solving for y yields: y = (4/5)x Substituting this into the equation for the area of PBC yields:
Area_PBC = (1/2)(15/2)x = (15/4)x The area of ABC can also be written in terms of x by using the formula: Area_ABC = (1/2)(AB)(PQ) = (1/2)(12)(PQ) + (1/2)(15)(PQ) = (9/2)(PQ) Setting the areas equal to each other yields:(9/2)(PQ) = 6x + (15/4)x(9/2)(PQ) = (33/4)x(9/2)(PQ)/(33/4) = x(6/11)PQ = x(6/11)Thus, we can see that the longest possible integer length of the third altitude is $\boxed{66}$.
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Pls solve with all steps
Answers
The results of the expressions involving logarithms are listed below:
Case 1: 1 / 2
Case 2:
Subcase a: 0
Subcase b: 11 / 2
Subcase c: - 11 / 2
How to simplify and evaluate expressions involving logarithmsIn this problem we have a case of an expression involving logarithms that must be simplified and three cases of expressions involving logarithms that must be evaluated. Each case can be solved by means of the following logarithm properties:
㏒ₐ (b · c) = ㏒ₐ b + ㏒ₐ c
㏒ₐ (b / c) = ㏒ₐ b - ㏒ₐ c
㏒ₐ cᵇ = b · ㏒ₐ c
Now we proceed to determine the result of each case:
Case 1
㏒ ∛8 / ㏒ 4
(1 / 3) · ㏒ 8 / ㏒ 2²
(1 / 3) · ㏒ 2³ / (2 · ㏒ 2)
㏒ 2 / (2 · ㏒ 2)
1 / 2
Case 2:
Subcase a
㏒ [b / (100 · a · c)]
㏒ b - ㏒ (100 · a · c)
㏒ b - ㏒ 100 - ㏒ a - ㏒ c
3 - 2 - 2 + 1
0
Subcase b
㏒√[(a³ · b) / c²]
(1 / 2) · ㏒ [(a³ · b) / c²]
(1 / 2) · ㏒ (a³ · b) - (1 / 2) · ㏒ c²
(1 / 2) · ㏒ a³ + (1 / 2) · ㏒ b - ㏒ c
(3 / 2) · ㏒ a + (1 / 2) · ㏒ b - ㏒ c
(3 / 2) · 2 + (1 / 2) · 3 + 1
3 + 3 / 2 + 1
11 / 2
Subcase c
㏒ [(2 · a · √b) / (5 · c)]⁻¹
- ㏒ [(2 · a · √b) / (5 · c)]
- ㏒ (2 · a · √b) + ㏒ (5 · c)
- ㏒ 2 - ㏒ a - ㏒ √b + ㏒ 5 + ㏒ c
- ㏒ (2 · 5) - ㏒ a - (1 / 2) · ㏒ b + ㏒ c
- ㏒ 10 - ㏒ a - (1 / 2) · ㏒ b + ㏒ c
- 1 - 2 - (1 / 2) · 3 - 1
- 4 - 3 / 2
- 11 / 2
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Nicole is a wedding organiser. The guests sit at a circular table with a diameter of 180cm each guest needs 7cm around the cicumference of the table. Their are 18 tables at the venu. There is a toptal of 145 guests. Are their enoughb tables
Answers
From the given data of Nicole's wedding organization, 18 tables at the venue is sufficient for the total 145 arriving guest.
To determine whether there are enough tables for the guests, we need to calculate the total circumference required for all the guests and compare it to the total circumference of the available tables. The circumference of a circle is given by the formula C = πd, where C is the circumference, d is the diameter, and π is the constant pi, approximately equal to 3.14.
For the circular table with a diameter of 180cm, the circumference is:
C = πd
= π x 180cm
= 565.2cm
Each guest needs 7cm around the circumference of the table, so the total circumference required for one guest is 7cm.
For 145 guests, the total circumference required is:
Total circumference required
= 145 guests x 7cm per guest
= 1015cm
Now, we can calculate the total circumference of all the tables available:
Total circumference of all tables
= 18 tables x 565.2cm per table
= 10,174.4cm
Since the total circumference required for the guests (1015cm) is less than the total circumference of all the available tables (10,174.4cm), we can conclude that there are enough tables for the guests. Therefore, there are enough tables at the venue for the 145 guests.
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i need the volume, the numbers put into the volume and the answer :))
Answers
The volume of the triangular prism on top is:
\(\begin{gathered} V1=(\frac{b\cdot h}{2})\cdot l \\ where\colon \\ b=20ft \\ h=25ft \\ l=22ft \\ V1=\frac{20\cdot25}{2}\cdot22 \\ V1=5500ft^3 \end{gathered}\)The volume of the rectangular prism underneath is:
\(\begin{gathered} V2=l2\cdot w\cdot h2 \\ where\colon \\ l2=22ft \\ w=20ft \\ h2=10ft \\ so\colon \\ V2=22\cdot20\cdot10 \\ V2=4400ft^3 \end{gathered}\)Therefore, the total volume will be:
\(\begin{gathered} V=V1+V2 \\ V=5500ft^3+4400ft^3 \\ V=9900ft^3 \end{gathered}\)Fuel costs have risen quickly during recent years as consumption, refining and production costs have risen sharply. Supply and demand conditions in the perfectly competitive domestic crude oil market are: QS = -250 + 7P (Supply) QD = 260 - 7P (Demand) where Q is quantity in millions of barrels per day, and P is price per barrel. Find the market equilibrium price. Note: To be at equilibrium, QS must equal QD
Answers
Answer:
The market equilibrium price is approximately $36.43 per barrel.
Step-by-step explanation:
To find the market equilibrium price, we need to set the quantity supplied (QS) equal to the quantity demanded (QD) and solve for the price (P).
Given:
QS = -250 + 7P
QD = 260 - 7P
Setting QS equal to QD:
-250 + 7P = 260 - 7P
Now, let's solve for P:
Add 7P to both sides:
-250 + 7P + 7P = 260 - 7P + 7P
Combine like terms:
14P - 250 = 260
Add 250 to both sides:
14P - 250 + 250 = 260 + 250
Simplify:
14P = 510
Divide both sides by 14:
14P/14 = 510/14
Simplify:
P = 36.43
The market equilibrium price can be found by setting the quantity supplied (QS) equal to the quantity demanded (QD) and solving for the price (P) that satisfies this condition.
In the given scenario, the supply function is QS = -250 + 7P, and the demand function is QD = 260 - 7P. To find the equilibrium price, we set QS equal to QD:
-250 + 7P = 260 - 7P
Simplifying the equation, we get:
14P = 510
Dividing both sides by 14, we find:
P = 36.43
Therefore, the market equilibrium price is approximately $36.43 per barrel. At this price, the quantity supplied and quantity demanded will be equal, resulting in a state of equilibrium in the perfectly competitive domestic crude oil market.
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State whether the data described below are discrete or continuous, and explain whyThe numbers of voters that are registered with a certain political party in different regionsChoose the correct answer below:A. The data are continuous because the data can take on any value in an interval.B. The data are discrete because the data can take on any value in an interval.C. The data are continuous because the data can only take on specific values.D. The data are discrete because the data can only take on specific values.
Answers
Given: The numbers of voters that are registered with a certain political party in different regions
This can't be continous because we can't figure out how many people are registered with a certain political party.
It is like tracking how many push ups you can do. You can only do a certain amount and it varies. One day you can do 10 another 6 and another day 12. It is easier to make a chart of the people in a political party than to make a graph so that eliminates A and C.
And it can't be B because it is describing continuous data so it has to be D.
Answer:
D. The data are discrete because the data can only take on specific values.
plz help i will mark you brainlist this is due in 5 minutes
Answers
Answer: ion know help ur self
Step-by-step explanation: