A runner traveling with an initial velocity of 1.7 m/s accelerates at a constant rate of 1.2 m/s2 for a time of 6 seconds.What distance does the runner cover during this process?

Answer:

232 N

Explanation:

By Hooke's law, the force applied to a spring is proportional to the stretch of the spring, so

F = kx

Where F is the force, k is the spring constant and x is how much it is stretched.

So, replacing k by 58N/cm and x by 4 cm, we get

F = (58 N/cm)(4 cm)

F = 232 N

Therefore, the force applied is 232 N

The sub-level from which the electron is removed when the first ionisation energy of germanium is measured is the 4p² sub-level.

The first ionization energy of germanium is the energy required to remove one electron from a neutral germanium atom to form a positively charged ion.

To identify the sub-level from which the electron is removed when the first ionization energy of germanium is measured, you need to consider the electron configuration of germanium.

The electron configuration of germanium is 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p². During the first ionization process, the electron will be removed from the outermost shell with the highest energy sub-level, which is the 4p² sub-level.

So, the sub-level from which the electron is removed when the first ionization energy of germanium is measured is the 4p² sub-level.

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i) The velocity of the particle at 17 sec is 17m/s.

ii) The total distance travelled is 190 m.

iii) The total displacement is -10m.

Distance is the length of any path connecting any two places. As measured along the shortest path between any two points, displacement is the direct distance between them.

The direction is ignored when calculating distance. The direction is accounted for in the displacement calculation.

Since it solely depends on magnitude and not direction, distance is a scalar number. Since displacement varies on both magnitude and direction, it is a vector quantity.

Distance provides specific directions that must be taken when moving from one location to another. Displacement only provides a partial description of the route because it pertains to the quickest way.

Velocity of particle = Slope of the object =Δ \(\frac{y}{x}\)

Velocity = \(\frac{95-10}{20-15}\) = 17m/s

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Answer: Independent variable

Explanation: i think

The resistance of the lamp is approximately 2.857 ohms.

Ohm's law states that the current flowing through a conductor is directly proportional to the voltage across it, given a constant temperature. Mathematically, it can be expressed as V = IR, where V is the voltage, I is the current, and R is the resistance of the conductor.

To calculate the resistance of the lamp, we can use Ohm's law.
Given that the lamp is connected to a 2 V DC power supply and the current through the lamp is 0.7 A, we can plug these values into the equation:

R = V/I
R = 2 V / 0.7 A

R = 2.857 ohm

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The thermal conductivity of the metal is approximately B, 241 W/(m · K).

To find the thermal conductivity (k) of the metal, use the formula:

Q = k × A × (ΔT/Δx) × t

Where:

Q = Heat conducted by the rod (in Joules)

A = Cross-sectional area of the rod (in square meters)

ΔT = Temperature difference across the rod (in Kelvin)

Δx = Length of the rod (in meters)

t = Time (in seconds)

Given:

Q = 8.5 g of ice melted = 8.5 × Lf (latent heat of fusion of ice)

Lf = 3.34 × 10⁵ J/kg

Δx = 60 cm = 0.6 m

A = 1.25 cm² = 1.25 × 10⁻⁴ m²

t = 10 min = 600 seconds

ΔT = (100°C - 0°C) = 100 K

Substituting the given values into the formula:

8.5 × Lf = k × (1.25 × 10⁻⁴) × (100 K / 0.6 m) × 600 s

Simplifying the equation:

k = (8.5 × Lf) / [(1.25 × 10⁻⁴) × (100 K / 0.6 m) × 600 s]

Calculating the value:

k = (8.5 × 3.34 × 10⁵) / [(1.25 × 10⁻⁴) × (100 / 0.6) × 600]

k ≈ 241 W/(m · K)

Therefore, the thermal conductivity of the metal is approximately 241 W/(m · K).

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Answer:

Convert the following units, into SI units without changing their values.

2.5 km

We know that

1 km=1000 m

So, for 2.5 km:

2.5 km=2.5×1000 m

=2500 m

Explanation:

like this you can solve all your question

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Star b must be 2 light years away. The apparent brightness of a star decreases with the square of the distance. Since star a appears 1/16 as bright as star b, star b must be √16 = 4 times closer, which is 2 light years away.

The apparent brightness of a star is determined by its intrinsic brightness, also known as its absolute magnitude, and its distance from the observer. In this scenario, star a and star b have the same absolute magnitude, indicating that they have the same inherent brightness. However, star a appears 1/16 as bright as star b. Since apparent brightness is inversely proportional to the square of the distance, we can deduce that star b must be 1/4 times the distance of star a to maintain the same apparent brightness. Given that star a is 4 light years away, star b must be 2 light years away. This ensures that the apparent brightness of star b is 1/16 of star a, as observed.

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Answer:

Sunlight, gravitational potential, decay of radioactive isotopes, and rotation of the Earth are the major sources of energy driving physical processes on Earth. Sunlight is a source external to Earth, while radioactive isotopes and gravitational potential, with the exception of tidal energy, are internal.

The optimum ue for this mission is u_e_opt = u_e ln(m0/mu)/(1 - αP/m0).

The rocket equation in the case where the mass delivered by a rocket, mf​, is separated into useful payload mu​ and the power-producing system mass mp​ = αP, takes the form

m0mu​ = e−Δvue−2ηΔtαue2​(1−e−Δvue​),

Where Δt is the thrusting time, and η is the conversion efficiency.

This information is given in the question.

The optimum ue for this mission is the one that maximizes the payload mass mu for a given launch mass m0.

The rocket equation gives the relation between the initial mass of the rocket m0 and the final mass mf and the velocity change Δv it produces.

The rocket equation can be written as follows:

m0mf​ = e−Δvue​,

Where Δv = ue ln(m0/mf)

The mass of the rocket that is consumed in a given time interval Δt is given by mp = αP Δt

The mass of the useful payload is given by

mu = mf - mp

Substituting for mf and mp, we get

mu = (1 - αP/m0)mf

Substituting the above equation in the rocket equation, we get

m0(1 - αP/m0)mf = e^(-Δv/ue)

mf = m0 e^(-Δv/ue)/(1 - αP/m0)

Substituting for mf, we get

mu = (1 - αP/m0) m0 e^(-Δv/ue)/(1 - αP/m0)

mu = m0 e^(-Δv/ue)

Multiplying both sides of the equation by m0/mu, we get

m0/mu = m0 e^(Δv/ue)

Taking the natural logarithm of both sides of the equation, we get ln(m0/mu) = Δv/ue

ue = Δv/ln(m0/mu)

Substituting the value of Δv from the rocket equation, we get

ue = u_e_opt

    = u_e ln(m0/mu)/(1 - αP/m0)

Therefore, the optimum ue for this mission is u_e_opt = u_e ln(m0/mu)/(1 - αP/m0).

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One of the three astronomical objects that were first detected at radio wavelengths by the Groote Reber in the 1930s and 1940s was the Milky Way Galaxy.

American engineer and radio astronomer Groote Reber built the first radio astronomy parabolic radio telescope. Reber used his radio telescope to map the radio emissions from the Milky Way Galaxy, proving that astronomical objects emit radio waves. This finding was a milestone in radio astronomy and offered a new window to the cosmos beyond optical observatories.

Reber discovered radio galaxies, cosmic microwave background radiation, and the Milky Way. These discoveries changed our knowledge of the cosmos and led to radio astronomy.

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Rolanda needs to advise her friend to place the note about mass in region z and the note about charge in region x to fix the mistake in the Venn diagram. Therefore, the correct answer is option A.

Rolanda should suggest to her friend that the note about mass belongs in region z, and the note about charge belongs in region x. This correction is necessary because gravitational force depends on mass, while electrical force depends on charge.

The x in the circle on the left with infinite reach and depends on mass is incorrect because gravitational force does not have infinite reach. It only acts between objects with mass that are in close proximity to each other. The y in the intersecting area is also incorrect because there is no force that is common to both gravitational and electrical forces.

On the other hand, the z in the circle on the right with depends on charge is correct because electrical force depends on the charge of the objects involved. By suggesting that the note about mass belongs in region z and the note about charge belongs in region x, the Venn diagram will accurately represent the differences between gravitational and electrical forces.

In summary, Rolanda should suggest to her friend that the note about mass belongs in region z and the note about charge belongs in region x. Therefore, the correct answer is option A.

This will correct the error in the Venn diagram and accurately represent the differences between gravitational and electrical forces. It is important to understand these differences in order to properly understand the behavior of objects in our world.

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Two positive points charges repel each other with force 0.36 N when their separation is 1.5 meter . Then the force exerted by two charges when the distance is 1.0 meter is 0.8 N.

Calculation:

R1 = 1.5 meter

R2 = 1 meter

F1 = 0.36 N

F1/F2 = R2^2/R1^2

F2 = R1^2/R2^2 × F1

F2 = 2.25 / 1 × 0.36

F2 = 0.81

Electrostatic force is type of force which act between two charges it is  repulsive or attractive in nature.  If both charge in same type then it will be repulsive and when both are in opposite nature then it will be attractive in nature.

Mathematically,

F = k× Q1× Q2/r^2

So,

In above problems

R1 = 1.5 meter

R2 = 1 meter

F1 = 0.36 N

F1/F2 = R2^2/R1^2

F2 = R1^2/R2^2 × F1

F2 = 2.25 / 1 × 0.36

F2 = 0.81

Therefore, Two positive points charges repel each other with force 0.36 N when their separation is 1.5 meter . Then the force exerted by two charges when the distance is 1.0 meter is 0.8 N.

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The gyroscope slows from an initial rate of 29.6 rad/s at an angular acceleration of 0.54 rad/s2.

Part (a) How long does it take to come to rest in seconds? t = ?

The angular deceleration is given by the negative value of the angular acceleration; thus:

α = -0.54 rad/s2

The initial velocity is given by the value,

ω1 = 29.6 rad/s.

The final velocity, ω2 = 0 rad/s.

The formula for angular acceleration is:

ω2 = ω1 + αt,

where:

ω1 = 29.6 rad/s

ω2 = 0 rad/s

α = -0.54 rad/s

2t = ?

Substitute the values in the formula above and solve for t.

0 = 29.6 - 0.54tt = 29.6/0.54t = 54.8 seconds

Therefore, it takes 54.8 seconds to come to rest in seconds.

Part (b)The number of revolutions that the gyroscope makes before stopping is given by:

n = (ω1/2π)t,

where:

ω1 = 29.6 rad/s

t = 54.8 s

n = ?

Substitute the values in the formula above and solve for n:

n = (29.6/2π)(54.8) revolutions

n ≈ 277.4

Therefore, the number of revolutions that the gyroscope makes before stopping is approximately 277.4 revolutions.

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Answer:

1040 Kilohertz = 1.04E6 /sec

Speed of electromagnetic waves = 3.00E8 m/s

3.00E8 / 1.04E6 = 288 m  (a λ/4 antenna still requires 72 m)

Answer:

(E) it seems like the best option

Between visible light and microwave is where infrared falls. Infrared has a higher energy than radio but a lower energy than gamma rays.

The term "infrared" refers to electromagnetic waves that exist within the electromagnetic spectrum at frequencies slightly below those of red visible light and just above those of microwaves. According to the California Institute of Technology, the wavelengths of infrared radiation are longer than those of visible light (Caltech).

The majority of the radio portion of the electromagnetic spectrum (EM spectrum) is found between 1 cm and 1 km, or 30 GHz and 300 kHz in frequency. The EM spectrum's radio region is relatively vast. Astronomers usually employ wavelength in the infrared and optical spectrum.

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a) The ratio of the electric charge on each conductor to the potential difference (i.e., voltage) between them is used to express capacitance.

b) The area of the plates, the spacing between them, and the type of insulating material or dielectric between them are the three variables that have an impact on a parallel-plate capacitor's capacitance.

c) The area of each plate, the dielectric material separating the plates, and the distance between the plates all affect the capacitance of a parallel plate capacitor.

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Answer:

E = 0.437 N/C

Explanation:

Given that,

Charge, \(q=8\times 10^{-4}\ C\)

Electric force, \(F=3.5\times 10^{-4}\ N\)

Let the strength of the electric field is E. We know that, the electric force is given by :

F = qE

Where

E is the electric field strength

\(E=\dfrac{F}{q}\\\\E=\dfrac{3.5\times 10^{-4}}{8\times 10^{-4}}\\E=0.437\ N/C\)

So, the strength of the electric field is equal to 0.437 N/C.

Answer: 50°

Explanation:

Given the following :

Initial Velocity of bullet (U) = 87m/s

Time of travel (t) = 13.6s

Horizontal Distance traveled (S) = 760m

Therefore, the horizontal angle of projection of the bullet :

Using the second equation of motion:

S = ut + 0.5at^2

Where a = g = acceleration due to gravity, S = distance traveled, t= time taken and U = Initial Velocity.

The Angle of projection along the horizontal is represented as cosΘ

Acceleration due to gravity after the bullet has hit the ground = 0

Therefore, rewritten the equation :

S = ucosΘ * t + 0.5at^2

760 = 87 * Cosθ * 13.6 + 0.5(0)(13.6)^2

760 = 1183.2 * Cosθ + 0

Cosθ = 760 / 1183.2

Cosθ = 0.6423

Θ = cos^-1(0.6423)

Θ = 50.036460

Θ = 50°

Answer:

35

Explanation:

total magnification = eyepiece lens x objective lens

TM = 10X x 25X

TM = 250X

Answer:

However, if you add a thousand neutrons, you will be creating one super-radioactive atom. Neutrons play a major role in the mass and radioactive properties of atoms. You may have read the page on isotopes. Isotopes are created when you change the normal number of neutrons in an atom.

Explanation:

The neutron is a subatomic particle, symbol n or n⁰, which has a neutral (not positive or negative) charge and a mass slightly greater than that of a proton. Protons and neutrons constitute the nuclei of atoms. Since protons and neutrons behave similarly within the nucleus, and each has a mass of approximately one atomic mass unit, they are both referred to as nucleons. Their properties and interactions are described by nuclear physics.

Answer:

The Lambda-CDM model contains a cosmological constant, denoted by a lambda (λ), which is associated with dark energy and cold dark matter.

^Also works for Plato users.

Answer:

"cold dark matter"

Explanation:

other person is correct!!!

38.5% C to 101.3 F is a conversion factor. The measurement method, your age, your activity, the time of day, and other factors will all affect how you take it.

On the Fahrenheit temperature scale, the freezing point of water is 32°, while the boiling point is 212°, which is separated by an identical 180°.

Generally speaking, the definition of room temperature is 70 degrees Fahrenheit. However, before a comfortable degree of satisfaction can be expected, some acclimatization is likely required.

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Answer:

Every rock is somewhere in the rock cycle. The story of the rock is the story of rock cycle: where the rock is now on the rock cycle, the path it took on the rock cycle to get to where it is now, and the path on the rock

Explanation:

This is the answer i put it and it worked if it didn't work for you that's because you lesson or teacher was doing it in a different way.

Answer:

The rock cycle, illustrated in Figure below, depicts how the three major rock types – igneous, sedimentary, and metamorphic - convert from one to another. Arrows connecting the rock types represent the processes that accomplish these changes.

Explanation:

Answer:

Option D. 4.4 m/s²

Explanation:

The following data were obtained from the question:

Velocity (v) = 21 m/s

Radius (r) = 100 m

Centripetal acceleration (a) =.?

The centripetal acceleration of the car can be obtained as follow:

Centripetal acceleration (a) = Velocity square (v²) / radius (r)

a = v²/r

a = 21²/100

a = 441/100

a = 4.41 ≈ 4.4 m/s²

Therefore, the centripetal acceleration of the car is 4.4 m/s².

The initial potential energy of the swing is 0 J. The final potential energy of the swing is 345.35J. The change in potential energy of the swing is 345.35J. And the work done is 345.35J.

The initial potential energy of the swing is given by:

PE_i = mgh_i

PE_i = 35 kg * 9.81 m/s^2 * 0 m

PE_i = 0 J

where m is the mass of the tire, g is the acceleration due to gravity, and h_i is the initial height of the tire.

The final potential energy of the swing is given by:

PE_f = mgh_f

PE_f = 35 kg * 9.81 m/s^2 * 1.0 m

PE_f = 343.35 J

where h_f is the final height of the tire.

The change in potential energy is:

ΔPE = PE_f - PE_i

ΔPE = 343.35 J - 0 J

ΔPE = 343.35 J

Therefore, the work done on the tire is:

W = ΔPE

W = 343.35 J

So it would take 343.35 J of work to move the tire a vertical distance of 1.0 m at a constant speed of 1 m/s.

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