A skydiver weighing 219 lbf (including equipment) falls vertically downward from an altitude of 5000 ft and opens the parachute after 16 s of free fall. Assume that the force of air resistance, which is directed opposite to the velocity, is 0.74|v| when the parachute is closed and 14|v| when the parachute is open, where the velocity v is measured in ft/s. Use g = 32 ft/s^2. Round your answers to two decimal places. (a) Find the speed of the skydiver when the parachute opens. V(16) = i ______ ft/s (b) Find the distance fallen before the parachute opens. x(16) = i ______ ft (c) What is the limiting velocity vL after the parachute opens? vL = i _____ ft/s

Answer:

94.248

Step-by-step explanation:

also if you can can i have brainliest, also this is the right answer

Answer:

1:2

becuase it can be honestly

Answer:

720

Step-by-step explanation:

Out of 80 students the no. of students who sign up=48

So, out of 1200 students 48×1200÷80=720 students sign up.

Answer:

Cost Price: $2.50

Selling Price: $3.30

Profit per Cup: $0.80

Step-by-step explanation:

Cost Price:

$15/6 cups = $2.50 per cup

Selling Price:

10% profit means he had to sell the remaining cups for 1.1 * $15

So he sold them for $16.50

$16.50 / 5 cups remaining = $3.30 per cup

Profit per Cup:

3.30 - 2.5 = $0.80

Answer:

D, D, B

Step-by-step explanation:

multiply 744 by 1,000 to get your meters.

7 times the cost of each lawn, X will equal 210.

25 minus 12 is 13

this holds true for the one below also

Based on the given conditions, Jane has $31, Kevin has $25, and Hans has $50 in their wallets.

Let's solve the problem step by step.

First, let's assume that Jane has X dollars in her wallet. Since Kevin has $6 less than Jane, Kevin would have X - $6 dollars in his wallet.

Next, we're given that Hans has 2 times what Kevin has. So, Hans would have 2 * (X - $6) dollars in his wallet.

According to the information given, the total amount of money they have in their wallets is $106. We can write this as an equation:

X + (X - $6) + 2 * (X - $6) = $106

Simplifying the equation:

4X - $18 = $106

4X = $124

X = $31

Now we know that Jane has $31 in her wallet.

Substituting this value into the previous calculations, we find that Kevin has $31 - $6 = $25 and Hans has 2 * ($25) = $50.

To find the total amount they have, we sum up their individual amounts:

Jane: $31

Kevin: $25

Hans: $50

Adding these amounts together, we get $31 + $25 + $50 = $106, which matches the total amount stated in the problem.

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The complete question is:

Jane, kevin and hans have a total of $106 in their wallets. kevin has $6 less than Jane. hans has 2 times what kevin has. how much do they have in their wallets?

Answer:

c and d

Step-by-step explanation:

like saying you lost half but gained 3 quarters. you end up have 1/4 or 1 quarter left

make the mixed number an improper fraction

9/4*9/5 = 81/20

20 goes into 81, 4 times evenly with 1 left over

4 1/20

The statement is true.

When the block is in equilibrium, each spring is stretched an additional ∆x. This implies that the forces from the two springs are balanced, and the block is not experiencing any net force in the equilibrium position.

When the block is set into oscillation with amplitude a, it will pass through its equilibrium point during the oscillation. At the equilibrium point, the displacement of the block is zero, and it changes direction. At this point, the block has its maximum speed v, as it is accelerating towards the equilibrium position.

The speed of the block decreases as it moves away from the equilibrium position, reaches zero at the maximum displacement (amplitude), and then starts accelerating towards the equilibrium point again. Therefore, when the block passes through its equilibrium point, it has its maximum speed v.

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Answer:

блина я сама не

Step-by-step explanation:

The largest possible volume of the inscribed right circular cylinder is 810π \(cm^3\).

To find the largest possible volume of a right circular cylinder inscribed in a cone with height 10 cm and base radius 9 cm, follow these steps:

1. Set up the problem: Let h be the height of the cylinder and r be the radius of its base. The cylinder is inscribed in the cone, so their heights and radii are proportional. Therefore, we have the relationship:

  h/10 = r/9

2. Solve for h: Multiply both sides of the equation by 10 to isolate h:

  h = 10r/9

3. Write the volume formula for a cylinder: V = π\(r^2\)h

4. Substitute h from step 2 into the volume formula:

  V = π\(r^2\)(10r/9)

5. Differentiate the volume formula with respect to r to find the critical points:

  dV/dr = d(10π\(r^3\)/9)/dr = 10πr^2

6. Set the derivative equal to zero and solve for r:

  10π\(r^2\) = 0
  r = 0 (This is not a valid solution since the radius must be greater than zero)

7. Since there's no valid critical point, the maximum volume occurs at the endpoints of the interval. In this case, the radius can be between 0 and 9, so we'll test r = 9:

  h = 10(9)/9 = 10

8. Calculate the volume with r = 9 and h = 10:

  V = π(\(9^2\))(10) = 810π \(cm^3\)

The largest possible volume of the inscribed right circular cylinder is 810π\(cm^3\).

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Answer:

19

Step-by-step explanation:

A' represents everything out A

B' represents everything out B

C' represents everything out C

So only the outside is left hope this helps

Answer:

ahah yea and its 10 by the way

Answer:

heyyyyy :)    its 10

Step-by-step explanation:

The false statement about the general exponential equation y = 600(0.85)t is:

(iv) The initial amount of 600 is decaying at a rate of 85%.

This statement is false because the exponential equation represents decay with a rate of 15% per time period, not 85%. The base of the exponential term, 0.85, represents the decay factor or the percentage of the previous value that remains after each time period.

In the given equation, the initial amount of 600 is decaying at a rate of 15%. This means that with each passing time period, the quantity decreases by 15% of its previous value. The decay factor of 0.85 indicates that the quantity is reduced to 85% of its previous value after each time period.

Statement (ii) is true because the initial amount of 600 has a decay factor of 0.85.

Statement (iii) is true as well because when t = 1, the equation becomes y = 600(0.85)^1 = 510, which is indeed 85% of the original value of 600.

It is important to note the difference between the decay rate (15%) and the decay factor (0.85). The decay rate refers to the percentage decrease in quantity per time period, while the decay factor represents the multiplier applied to the previous value to calculate the new value.

Regarding the river frogs question, it appears that the question is incomplete or unrelated to the provided information about the exponential equation. If you have any specific question or need further assistance, please provide more details.

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Answer: B. 5

Step-by-step explanation:

The distance formula is in the screenshot below. Take the point A which is (-4,0) and point C which is (-1,4). X1 is -4 and X2 is -1. Y1 is 0 and Y2 is 4. Plug those number into the formula and use a calculator to find the answer.

Answer:

the answer is (25-π) there was no figure drawn

A trending quantity is a number that is generally increasing or decreasing. When the numbers are steadily decreasing, we have a downward trend, and when the numbers are steadily increasing, we have an upward trend.

On our problem, we have a population growth/decline starting at 2004 until 2009. If we analyze the years individually, it is not perfectly clear if the ternd is downward or upward, however, analyzing the whole table it is possible to see that we have an upward trend. If we compare two distinct points not consecutive of our table, the point closer to 2009 will present a bigger population for most points in our table, which shows a rise on the population value as the years goes by. To see it properly the ideal would be to plot the points and check the slope of the trend line.

The orthogonal complement S is the set of all vectors orthogonal to the subspace S in R5 whose third and fourth components are zero. To find S, we need to find vectors such that vu = 0 for all u in S using the dot product. The orthogonal complement S has dimension three and a basis for it is f1, f2, f3, where f1 = (1,-1,0,0,0) f2 = (0,0,1,0,0) f3 = (0,0,0,1,0).

Let's begin by defining the orthogonal complement S⊥, which is the set of all vectors orthogonal to the subspace S in question. The subspace S is defined as the set of all vectors in R5 whose third and fourth components are zero. Let's go through the steps to find S⊥.

Step 1: Determine the dimensions of S The dimension of the subspace S is two. This is because the subspace consists of vectors whose third and fourth components are zero. Therefore, only the first, second, fifth components are nonzero, making up a 3D subspace. Since S is a subspace of R5, the remaining two components can also take any value and thus the dimension of S is 2.

Step 2: Determine a basis for S To determine a basis for S, we can use the fact that the subspace is defined as all vectors whose third and fourth components are zero.

Therefore, a basis for S is given by {e1, e2}, where e1 = (1,0,0,0,0) and e2 = (0,1,0,0,0).

Step 3: Find the orthogonal complement S⊥ To find S⊥, we need to find all vectors orthogonal to S. This means we need to find vectors v such that v⋅u = 0 for all u in S. To do this, we can use the dot product: v⋅u = v1u1 + v2u2 + v3u3 + v4u4 + v5u5= v1u1 + v2u2 + v5u5We want this to be zero for all u in S. This implies:v1 + v2 = 0 andv5 = 0Therefore, S⊥ is given by the set of all vectors in R5 of the form (a,-a,b,c,0), where a, b, and c are arbitrary constants. The orthogonal complement S⊥ has dimension three, and a basis for it is {f1, f2, f3}, where:f1 = (1,-1,0,0,0)f2 = (0,0,1,0,0)f3 = (0,0,0,1,0)The above result gives us a complete characterization of S⊥.

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Answer:

84

Step-by-step explanation:

The population of birds to increase by 50% in 31.25 years.

The differential equation for the population of birds is:

dp/dt = 0.016P

where P is the population of birds and t is time in years.

To obtain the time it takes for the population to increase by 50%, we need to solve for t when P increases by 50%.

Let P0 be the initial population of birds, and P1 be the population after the increase of 50%.

Then we have:

P1 = 1.5P0 (since P increases by 50%)

We can solve for t by integrating the differential equation:

dp/P = 0.016 dt

Integrating both sides, we get:

ln(P) = 0.016t + C

where C is the constant of integration.

To obtain the value of C, we can use the initial condition that the population at t=0 is P0:

ln(P0) = C

Substituting this into the previous equation, we get:

ln(P) = 0.016t + ln(P0)

Taking the exponential of both sides, we get

:P = P0 * e^(0.016t)

Now we can substitute P1 = 1.5P0 and solve for t:

1.5P0 = P0 * e^(0.016t

Dividing both sides by P0, we get:

1.5 = e^(0.016t)

Taking the natural logarithm of both sides, we get:

ln(1.5) = 0.016t

Solving for t, we get:

t = ln(1.5)/0.016

Using a calculator, we get:

t ≈ 31.25 years

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A symmetrical distribution of exam scores in a college course indicates that the student's scores are evenly distributed across the entire range of scores. This suggests that about an equal number of students had relatively high and relatively low scores.

Correct answer will be b) About an equal number of students had relatively high and relatively low scores.

And that there is no single group that overwhelmingly outperformed or underperformed the others. Furthermore, it indicates that there were a substantial number of students who achieved high scores, as well as a substantial number who achieved low scores.

This type of even distribution of scores is often seen when students are equally prepared, and when the exam is designed to be neither too difficult nor too simple.

In conclusion, a symmetrical distribution of exam scores suggests that the students were similarly prepared and that the exam was appropriately challenging.

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Answer:

6 miles

Step-by-step explanation:

1 mile is 5280 feet, so the first thing we can do is convert miles into feet.

\(5280*6=31680\)

And, 1 yard is 3 feet. So we can divide 31680 by 3 to get the total amount of yards that 6 miles is.

\(31680/3=10560\)

Since 10560 is greater than 600, 6 miles is greater than 600 yards.

The solution x1(t) for the de-coupled RL-RC circuit can be found by solving the differential equation x1'(t) = A11 * x1(t), where A11 is a constant value.

To solve this differential equation, we can use separation of variables.

1. Begin by separating the variables by moving all terms involving x1(t) to one side of the equation and all terms involving t to the other side. This gives us:

x1'(t) / x1(t) = A11

2. Integrate both sides of the equation with respect to t:

∫ (x1'(t) / x1(t)) dt = ∫ A11 dt

3. On the left side, we have the integral of the derivative of x1(t) with respect to t, which is ln|x1(t)|. On the right side, we have A11 * t + C, where C is the constant of integration.

So the equation becomes:

ln|x1(t)| = A11 * t + C

4. To solve for x1(t), we can exponentiate both sides of the equation:

|x1(t)| = exp(A11 * t + C)

5. Taking the absolute value of x1(t) allows for both positive and negative solutions. To remove the absolute value, we consider two cases:

  - If x1(0) > 0, then x1(t) = exp(A11 * t + C)
  - If x1(0) < 0, then x1(t) = -exp(A11 * t + C)

  Here, x1(0) is denoted as x10.

Therefore, the solution x1(t) for the de-coupled RL-RC circuit, starting at t=0, is given by either x1(t) = exp(A11 * t + C) or x1(t) = -exp(A11 * t + C), depending on the initial condition x10.

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The gravitational potential energy of the stone-Earth system can be calculated before the stone is released, after it reaches the bottom of the well, and the change in gravitational potential energy during the process.

Gravitational potential energy is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

(a) Before the stone is released, it is held 11 m above the top edge of the well. The mass of the stone is 0.25 kg, and the acceleration due to gravity is approximately 9.8 m/s². Using the formula, the gravitational potential energy is calculated as PE = (0.25 kg)(9.8 m/s²)(11 m).

(b) After the stone reaches the bottom of the well, its height is 7.3 m. Using the same formula, the gravitational potential energy at this point is given by PE = (0.25 kg)(9.8 m/s²)(7.3 m).

(c) The change in gravitational potential energy can be determined by subtracting the initial potential energy from the final potential energy. The change in gravitational potential energy is equal to the gravitational potential energy after reaching the bottom of the well minus the gravitational potential energy before the stone was released.

By calculating these values, we can determine the specific numerical values for (a), (b), and (c) based on the given data.

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y = mx + b

The product of slopes of perpendicular lines is -1.  The slope of the given line is 2, so the slope of the perpendicular line is -1/2.

y = (-1/2)x + b

Now use the given point to find b and finish from here.

-5 = (-1/2)(2) + b

b = ?

The equation of the line in point-slope form is y-1 = 3 ( x + 1)

Equation of a line:

The equation of a line, in point-slope form, is designated  using:

y-y0= m( x - x0)

In which the point is given by(x0,y0)  and m is the slope.

Slope of the line below is 3 (given in the question).

This means that m = 3

(-1,1)

This means x= -1 and y =1

equation of the line

y - y0 = m( x- x0)

y-1 =m(x-(-1))

y-1=m(x + 1)

substituting the value of m is 3

y-1= 3 ( x + 1)

Therefore, The equation of the line in point-slope form is y-1= 3 (x + 1)

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The depth of the water in the cone-shaped tank is increasing at a rate of approximately 1.385 meters per second.

To determine the rate at which the depth of the water is changing, we can use related rates. Let's denote the depth of the water as h(t), where t represents time. We are given that dh/dt (the rate of change of h with respect to time) is 12 m/sec, and we want to find dh/dt when h = 18 meters.

To solve this problem, we can use the volume formula for a cone, which is V = (1/3)πr^2h, where r is the base radius and h is the depth of the water. We can differentiate this equation with respect to time t, keeping in mind that r is a constant (since the base radius does not change).

By differentiating the volume formula with respect to t, we get dV/dt = (1/3)πr^2(dh/dt). Now we can substitute the given values: dV/dt = 12 m/sec, r = 26 meters, and h = 18 meters.

Solving for dh/dt, we have (1/3)π(26^2) (dh/dt) = 12 m/sec. Rearranging this equation and solving for dh/dt, we find that dh/dt is approximately 1.385 meters per second. Therefore, the depth of the water in the tank is increasing at a rate of about 1.385 meters per second.

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-2.05 is the critical value for the left-tailed test .

What is critical z value?

The -1.96 and +1.96 standard deviations are the essential z-score values when adopting a 95 percent confidence level.

                               With a 95 percent confidence level, the uncorrected p-value is equal to 0.05.The critical value for a two-sided test is Z 1-/2, while for a one-sided test, it is Z 1.

                      You reject the null hypothesis if the absolute Z-value is higher than the crucial value. If not, you have not successfully ruled out the null hypothesis.

Given that,

α = 0.02.

left tailed test

Zα = 0.02 = -2.05

critical value = -2.05

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Answer:

Given:

radius of bigger half circle[R]=(7+7+14)/2=14cm

radius of smaller half circle [r]=14/2=7cm

Area of shaded region =1/2[πR² -πr²]

=1/2×22/7×[14²-7²]=231cm²

Area of shaded region=231cm²