The speed of the large cart after the collision would be 0.087 m/s
Momentum problemWe can use the law of conservation of momentum to solve this problem, which states that the total momentum of a closed system remains constant before and after a collision.
The momentum before the collision is given by:
p1 = m1v1 + m2v2
where m1 = 0.2 kg is the mass of the small cart, v1 = 1.70 m/s is its velocity before the collision, m2 = 2.00 kg is the mass of the large cart, and v2 = 0 m/s is its velocity before the collision.
p1 = (0.2 kg)(1.70 m/s) + (2.00 kg)(0 m/s) = 0.34 kg m/s
The momentum after the collision is also given by:
p2 = m1v1' + m2v2'
where v1' = -0.830 m/s is the velocity of the small cart after the collision (since it recoils in the opposite direction), and we want to find v2', the velocity of the large cart after the collision.
p2 = (0.2 kg)(-0.830 m/s) + (2.00 kg)(v2')
Since momentum is conserved, we have:
p1 = p2
0.34 kg m/s = (0.2 kg)(-0.830 m/s) + (2.00 kg)(v2')
Solving for v2', we get:
v2' = (0.34 kg m/s - 0.166 kg m/s) / 2.00 kg
v2' = 0.087 m/s
Therefore, the speed of the large cart after the collision is 0.087 m/s, to three significant figures.
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True or false: financial information that is immaterial in amount or nature need not be reported in accordance with gaap.
True, financial information that is immaterial in amount or nature need not be reported in accordance with GAAP.
According to Generally Accepted Accounting Principles (GAAP), financial information that is immaterial in amount or nature does not need to be reported. Materiality is a concept used in accounting to determine the significance or importance of financial information.
If an item is considered immaterial, it means that its inclusion or exclusion from financial statements would not have a significant impact on the decision-making of users of those statements. In such cases, GAAP allows for the omission of immaterial information.
However, it is important to note that the determination of materiality is subjective and depends on the specific circumstances and professional judgment of accountants. Additionally, even if an item is deemed immaterial, it is still good practice to provide adequate disclosure and transparency to users of financial statements.
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does PNS system cause more frequent depolarizations
to the sa node?
I'm aware that it increases potassium permeability to the ECF
(-) charges outside but if theres too much (-) charges in the ecf
wou
Yes, PNS system causes more frequent depolarizations to the SA (Sinoatrial) node.
The PNS (Parasympathetic Nervous System) is responsible for decreasing the heart rate. It does so by releasing acetylcholine, which stimulates the M2 muscarinic receptors found in the SA node. When acetylcholine binds to M2 receptors, it opens potassium channels, leading to hyperpolarization of the SA node cells.As a result, the pacemaker potential threshold increases and requires more time to reach the threshold for depolarization, thus reducing the heart rate. Therefore, by decreasing the potassium ion permeability of the ECF, it slows the heart rate, resulting in fewer depolarizations in the SA node, causing a lower heart rate.
In summary, the parasympathetic nervous system (PNS) causes more frequent depolarizations to the SA node. The PNS slows down the heart rate, but this does not mean that the pacemaker potential is reduced. Instead, the pacemaker potential is hyperpolarized, increasing the threshold for depolarization. Thus, fewer action potentials reach the threshold, and heart rate is decreased. So, the decrease in potassium permeability in the ECF and an increase in the parasympathetic nervous system causes hyperpolarization of the SA node and increases the threshold for depolarization. This, in turn, leads to fewer depolarizations in the SA node, causing a slower heart rate.
Therefore, it can be concluded that the PNS system causes more frequent depolarizations to the SA node and decreases heart rate by increasing the threshold for depolarization, which is accomplished by hyperpolarizing the pacemaker potential.
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Emily is pushing her little brother Tom on a sled. Tom has a mass of 40 kg and Emily
is pushing with a force of 10 N. However, the sled is sticking to the ice because of 2
N of friction. What is Tom's final acceleration?
PLZ HELP!!!
Answer:
The answer is 5 a
Explanation:
First subtract two from ten then because of the friction. Next divide 40 kg by 8 N. When you do that you will get 5 for acceleration. Always make sure that you put the symbol next to your answer.
how far apart are the object and image produced by a converging lens with 35.5- cm focal length when the object is 45 cm from the lens?
To find the distance between the object and image produced by a converging lens with a 35.5 cm focal length when the object is 45 cm from the lens, you can use the lens formula:
1/f = 1/do + 1/di
Where:
f = focal length (35.5 cm)
do = object distance (45 cm)
di = image distance
Step 1: Plug in the values for f and do:
1/35.5 = 1/45 + 1/di
Step 2: Subtract 1/45 from both sides:
1/35.5 - 1/45 = 1/di
Step 3: Find a common denominator and subtract:
(45 - 35.5)/(35.5 * 45) = 1/di
9.5/(35.5 * 45) = 1/di
Step 4: Take the reciprocal of both sides:
di = (35.5 * 45)/9.5
Step 5: Calculate di:
di ≈ 168.42 cm
So, the object and image produced by the converging lens with a 35.5 cm focal length when the object is 45 cm from the lens are approximately 168.42 cm apart.
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A sensor uses 2. 0 x 10-4 A of current when it is operated by a 3. 0-V battery. What is the resistance of the sensor circuit?
Answer:
1500 Ω
Explanation:
The resistance of the sensor circuit can be found using Ohm's law, R = V/I, where R is resistance, V is voltage, and I is current.
R = 3.0V / 2.0 x 10^-4 A = 1500 Ω.
So the resistance of the sensor circuit is 1500 Ω.
A certain sound signal has a frequency 8khz and wavelength 4.25cm in air; calculate the speed of sound in air.
The speed of sound in air is approximately 340 meters per second.
To calculate the speed of sound in air, we can use the formula:
Speed of sound = Frequency × Wavelength
Given:
Frequency = 8 kHz = 8,000 Hz
Wavelength = 4.25 cm = 0.0425 m
Plugging in the values:
Speed of sound = 8,000 Hz × 0.0425 m = 340 m/s
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TEST INTRO 20
The fact that a pen drops when you let it go is an example that can help explain ...
A: the hypothesis of gravity.
B: the theory of gravity.
C: the gravity of the situation.
D: the law of gravity:
Answer:
D
Explanation:
The electron drift speed in a copper wire of diameter 1.8 mm is 3.6×10−4ms−1 The number of free electrons per unit volume for copper is 8.5×1028m−3 Estimate the current in the wire.
The current in the wire is 0.00274 A.
Given, the electron drift speed in a copper wire of diameter 1.8 mm is 3.6 × 10⁻⁴ms⁻¹
The number of free electrons per unit volume for copper is 8.5 × 10²⁸m⁻³
To estimate the current in the wire we use the relation, `I = nAvq`.
Where,I is the currentn is the number of free electrons per unit volumeV is the volume of the conductorq is the charge on a single electrona is the cross-sectional area of the conductor.
The volume of the conductor is given byV = πr²LWhere,r is the radius of the wire andL is the length of the wire.
The cross-sectional area of the conductor is given bya = πr².
Substituting the values, we getV = π(0.9 × 10⁻³m)²(1m)
V = 2.54 × 10⁻⁶m³a = π(0.9 × 10⁻³m)²
a = 2.54 × 10⁻⁶m²q = 1.6 × 10⁻¹⁹C
Using the above formula, I = nAvq
I= 8.5 × 10²⁸m⁻³ × (2.54 × 10⁻⁶m³) × (3.6 × 10⁻⁴ms⁻¹) × (1.6 × 10⁻¹⁹C)
I = 0.00274 A
Therefore, the current in the wire is 0.00274 A.
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Part E Adjust the temperature at 5900 K. What is the color of a star at this temperature?
The color of the star at 5900K is close to the color of the sun, that is yellow. So the color of the star at 5900K will be yellow.
The color of light emitted by a hypothetical opaque, non-reflective body at a specific temperature expressed in kelvins is known as color temperature. Regardless of the temperature of other light sources, the color of their light is classified using the color temperature scale.
One aspect of visible light is color temperature. Lower color temperatures (2700–3000 K) are referred to as "warm colors," while color temperatures over 5000 K are referred to as "cool colors" (bluish) (yellowish).
The Sun closely resembles a radiator with a black body. The total radiative power per square unit determines the effective temperature, which is approximately 5780 K. Over the atmosphere, sunlight has a color temperature of approximately 5900 K.
Therefore, the star with a temperature around 5900K will have a color similar to that of the sun which is yellow.
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A 19.7 kg sled is pulled with a 42.0 N force at a 43.0° angle, across ground where μ₁ = 0.130.
What is the normal force on the sled?
The following information is provided in the problem: A sled with a weight of 19.7 kg is pulled with a force of 42.0 N at an angle of 43.0° across ground where μ₁ = 0.130. We need to find out the normal force that is exerted on the sled.
Let us examine each of the forces acting on the sled.The weight of the sled is equal to its mass multiplied by the acceleration due to gravity. Therefore, the weight of the sled is:mg = 19.7 kg x 9.8 m/s² = 193.06 N.The force exerted on the sled can be divided into two components: one that is parallel to the ground and one that is perpendicular to the ground.The force parallel to the ground is:F₁ = 42.0 N x cos(43.0°) = 30.56 N.The force perpendicular to the ground is:F₂ = 42.0 N x sin(43.0°) = 28.30 N.The frictional force is equal to the coefficient of friction multiplied by the normal force. Therefore, we need to find the normal force on the sled in order to calculate the frictional force. Since the sled is not accelerating vertically, the normal force is equal to the weight of the sled plus the force perpendicular to the ground. Therefore, N = mg + F₂N = 193.06 N + 28.30 N = 221.36 N.The frictional force is:Fr = μ₁ x NFr = 0.130 x 221.36 N = 28.77 N.Thus, the normal force exerted on the sled is 221.36 N.For such more question on perpendicular
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Particle of mass 2 kg is attached to a string length of 6m. the particle is moving in a horizontal circle at an angle of 30 degrees to the vertical with angular velocity and tention. what is the radius of the circle?
The radius of the circle is equal to (Tension x 6 m) / 1,6200,000 kg x degrees^2
What is radius?Radius is a straight line extending from the center of a circle or sphere to its circumference or surface. It is a term used in geometry and is measured in length. It is half of the diameter of a circle, and is sometimes referred to as the “radius of a circle”. It is used to measure curved lines, arcs, and circles. The radius of a circle is the same as the length of a line segment from the center of the circle to a point on its circumference.
The radius of the circle can be calculated using the formula:
Radius = (Tension x Length) / (Mass x Angular Velocity^2).
In this case, the radius would be:
Radius = (Tension x 6 m) / (2 kg x (angular velocity^2))
Radius = (Tension x 6 m) / (2 kg x (angular velocity x angular velocity))
Radius = (Tension x 6 m) / (2 kg x (angular velocity^2))
Radius = (Tension x 6 m) / (2 kg x (30 degrees x 30 degrees))
Radius = (Tension x 6 m) / (2 kg x (900 degrees^2))
Radius = (Tension x 6 m) / (2 kg x 810,000 degrees^2)
Radius = (Tension x 6 m) / 1,6200,000 kg x degrees^2
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This is a worksheet on position-time & velocity-time graph.
Please answer this, I will mark for brainless for an accurate answer.
Answer like this:
1. …
2. …
So on so forth, thank you!
at what speed do a bicycle and its rider, with a combined mass of 80 kg k g , have the same momentum as a 1300 kg k g car traveling at 6.0 m/s m / s ? express your answer to two significant figures and include the appropriate units.
Answer:
97.5 m/s
Explanation:
Get:
Mc=1300 Kg - Mass of car
Vc = 6 m/s - Velocity of car
Mb = 80 Kg - Mass of bicycle with rider
Find:
Vb? - Velocity of bicycle
Solution:
p=VbMb=McVc=1300*6=7800 Kg
Vb=p/Mb=7800/80=97.5 m/s
Check me!
Water travels, in a 2km long pipeline at a maximum flow rate of 0.12 m/s. The internal diameter of the pipe is 300 mm, pipe wall thickness is 5 mm, and is manufactured from steel with a Young's modulus of 210x109 Pa. The pipeline is constructed within an excavated trench and surrounded by backfill material. A control valve on the downstream end of the pipeline uniformly closes in 12 seconds. (a) Calculate the pressure transients at the mid-point of the pipeline (b) How does friction in pipeline effect the calculated (in Q6 (a)) pressure transients
(A) The pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.
(B) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow
(a) The pressure transients at the mid-point of the pipeline can be calculated using the water hammer equation. Water hammer refers to the sudden changes in pressure and flow rate that occur when there are rapid variations in fluid flow. The equation is given by:
ΔP = (ρ × ΔV × c) / A
Where:
ΔP = Pressure change
ρ = Density of water
ΔV = Change in velocity
c = Wave speed
A = Cross-sectional area of the pipe
First, let's calculate the change in velocity:
ΔV = Q / A
Q = Flow rate = 0.12 m/s
A = π × ((d/2)^2 - ((d-2t)/2)^2)
d = Internal diameter of the pipe = 300 mm = 0.3 m
t = Pipe wall thickness = 5 mm = 0.005 m
Substituting the values:
A = π × ((0.3/2)^2 - ((0.3-2(0.005))/2)^2
A = π × (0.15^2 - 0.1495^2) = 0.0707 m^2
ΔV = 0.12 / 0.0707 = 1.696 m/s
Next, let's calculate the wave speed:
c = √(E / ρ)
E = Young's modulus of steel = 210x10^9 Pa
ρ = Density of water = 1000 kg/m^3
c = √(210x10^9 / 1000) = 4585.9 m/s
Finally, substituting the values into the water hammer equation:
ΔP = (1000 × 1.696 × 4585.9) / 0.0707 = 1,208,277 Pa
Therefore, the pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.
(b) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow. As water moves through the pipe, it encounters frictional forces between the water and the pipe wall. This friction causes a pressure drop along the length of the pipeline.
The presence of friction results in a higher effective wave speed, which affects the calculation of pressure transients. The actual wave speed in the presence of friction can be higher than the wave speed calculated using the Young's modulus of steel alone. This higher effective wave speed leads to a reduced pressure rise during the transient event.
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What is the displacement of the object from 12 seconds to 16 seconds ?
Answer:
Displacement is the distance between an object’s initial position and its final position and is usually measured or defined along a straight line. Since this is a calculation that measures distance, the standard unit is the meter (m).
Explanation:
Under the current law on nutrition labeling, the Nutrition Facts
panel must include
a. total calories from trans fat
b. grams of monounsaturated fat
c. grams of total fat
d. total calories from satura
The Nutrition Facts panel must include the grams of monounsaturated fat, grams of total fat, and total calories from saturated fat.
a. The total calories from trans fat are not required to be included in the Nutrition Facts panel. Trans fat is listed separately under "Total Fat" and does not have its own specific calorie value.
b. The grams of monounsaturated fat are required to be included in the Nutrition Facts panel. Monounsaturated fat is a type of fat that is beneficial for health, and its quantity is provided to help consumers make informed choices.
c. The grams of total fat are required to be included in the Nutrition Facts panel. Total fat represents the sum of all types of fats present in the food product.
d. The total calories from saturated fat are required to be included in the Nutrition Facts panel. Saturated fat is a type of fat that is associated with an increased risk of certain health conditions, and providing the calorie value helps consumers monitor their intake.
Therefore, the Nutrition Facts panel must include b. grams of monounsaturated fat, c. grams of total fat, and d. total calories from saturated fat.
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One night, you see the star Sirius rise at exactly 7:36 PM. The following night it will rise
The time it takes for a star to rise again after it has crossed the meridian is approximately 23 hours and 56 minutes
which is the length of a sidereal day (the time it takes for the Earth to complete one rotation relative to the fixed stars).
However, because the Earth is also orbiting the Sun, it takes slightly longer for a star to rise at the same time each night. This is because as the Earth rotates on its axis, it also moves a short distance along its orbit around the Sun, which means that it takes slightly longer to complete a full rotation relative to the Sun. This is why we need to add an extra four minutes to the 23 hours and 56 minutes to get the length of a solar day (the time it takes for the Earth to complete one rotation relative to the Sun).Therefore, if Sirius rises at exactly 7:36 PM on one night, it will rise approximately 4 minutes later on the following night, at around 7:40 PM.
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A mass of 0. 40 kg, hanging from a spring with a spring constant of 160 n/m, is set into an up-and-down simple harmonic motion. What is the speed of the mass when moving through the equilibrium point? the starting displacement from equilibrium is 0. 10 m.
Given:
\(m=0.40kg\)
\(k=160\frac{N}{m}\)
\(A=0.10m\)
We know that the velocity of a mass attached to a spring is greatest when passing through equilibrium. Using the following formulas we can compute velocity.
\(v_{max} =\pm Aw\) and \(w=\sqrt{\frac{k}{m} }\) \(\Longrightarrow v_{max} =\pm A\sqrt{\frac{k}{m} }\)
\(\Longrightarrow v_{max} =\pm A\sqrt{\frac{k}{m} }\)
\(\Longrightarrow v_{max} =\pm (0.10)\sqrt{\frac{160}{0.40} }\)
\(\Longrightarrow v_{max} =\pm (0.10)(20) }\)
\(\Longrightarrow v_{max} =\pm 2.0\frac{m}{s}\)
What is the age of the moon? Group of answer choices 4.527 million years 3.14 million years 5.025 million years 4.5 billion years
A small toy manufacturer that builds electronic toys is considering suppliers for a part they call a "gizmo. " They need to purchase 200 gizmos, and they are looking at the price and size of shipments from four suppliers. A 3-column table with 4 rows. Column 1 is labeled Supplier with entries A, B, C, D. Column 2 is labeled Number of Gizmos per Shipment with entries 20, 25, 40, 50. Column 3 is labeled Cost of One Shipment with entries 23 dollars; 30 dollars; 44 dollars; 58 dollars. Which supplier would provide the most cost-effective way for the toy manufacturer to receive 200 gizmos?
Supplier C would provide the most cost-effective way for the toy manufacturer to receive 200 gizmos with a cost per gizmo of 1.10 dollars.
To find the most cost-effective supplier for the toy manufacturer, we need to calculate the cost per gizmo for each supplier.
Supplier A ships 20 gizmos per shipment, so the manufacturer would need 10 shipments at a cost of 23 dollars per shipment, for a total of 230 dollars. The cost per gizmo is 1.15 dollars.
Supplier B ships 25 gizmos per shipment, so the manufacturer would need 8 shipments at a cost of 30 dollars per shipment, for a total of 240 dollars. The cost per gizmo is 1.20 dollars.
Supplier C ships 40 gizmos per shipment, so the manufacturer would need 5 shipments at a cost of 44 dollars per shipment, for a total of 220 dollars. The cost per gizmo is 1.10 dollars.
Supplier D ships 50 gizmos per shipment, so the manufacturer would need 4 shipments at a cost of 58 dollars per shipment, for a total of 232 dollars. The cost per gizmo is 1.16 dollars.
Therefore, Supplier C would provide the most cost-effective way for the toy manufacturer to receive 200 gizmos with a cost per gizmo of 1.10 dollars.
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PLEASE HELP!!!! What is the formula for Carbon Tetrahydride? Is this a covalent or ionic bond? How can you tell?
Answer:Ionic compounds are (usually) formed when a metal reacts with a nonmetal (or a polyatomic ion). Covalent compounds are formed when two nonmetals react with each other.
Explanation:
hope it helped
Answer:
it ccl4
Explanation:
it a covalent because it is also recognize as IUPAC
What is the volume of a box that is 3 meters long, 0.5 meters high, and 2 meters wide?
Answer:
V = 3 m³
Explanation:
V = lwh
Step 1: Define
l = 3 m
h = 0.5 m
w = 2 m
Step 2: Substitute and Evaluate
V = 3(0.5)(2)
V = 1.5(2)
V = 3 m³
Answer: 3 meters^3
Explanation: 3*2*0.5=3
A convex lens of focal length 25 cm is in contact with a concave lens of focal length 50 cm. The equivalent focal length of this combination-lenses should be Group of answer choices
The equivalent focal length of this combination-lenses should be +50 cm.
Given:
Focal length of convex lens, f₁ = +25 cm
Focal length of concave lens, f₂ = -50 cm
Calculation:
We know that the power of a lens is given as:
P = 1 / f
where, f is the focal length of lens
Now, the power of convex lens can be calculated as:
P₁ = 1/f₁
= 1/(25×10⁻² m)
= 100/25
= +4 D
Similarly, the power of concave lens can be calculated as:
P₂ = 1/f₂
= (1/-50×10⁻² m)
= -100/50
= -2 D
Thus, the power of the combined lenses can be calculated as:
P₍₁₊₂₎ = P₁ + P₂
= +4 D - 2 D
= +2 D
Now, the combined focal length of the lens can be calculated as:
f₍₁₊₂₎ = 1 / P₍₁₊₂₎
= 100 / 2 D
= +50 cm
Therefore, the equivalent focal length of this combination-lenses will be +50 cm.
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Two long parallel wires carry currents of 20 a and 5. 0 a in opposite directions. the wires are separated by 0. 20 m. what is the magnetic field midway between the two wires? group of answer choices
The magnetic field will be given by the formula B=B1+B2.
Between two wires, the magnetic field has the formula B=B1+B2.
We must first calculate the magnetic field caused by each wire before adding the two vectors to find the net magnetic field halfway between the two wires. We must subtract the two vectors in order to find the total magnetic field because the electric current flows in the opposite direction via both cables.
The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is traveling through a magnetic field.
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Calculate the force with which the moon pulls every kilogram of water in Kamali river given that the moon is 3×10^5km away from Nepal and mass of moon is 7x 10^22kg,
The moon pulls each kilogram with water in the Kamali River with a force of 5.19 x 10-5 N, or strength or energy used or brought to bear.
In science, what exactly is a force?The term "force" has a clear definition in science. It is quite acceptable to refer to a force of this level as a push or perhaps a pull. An object does not "have in it" or "contain" a force. One thing is subject to a force from another. There is no distinction between living and non-living things in the concept of a force.
r3 = 105 kilometers x 10 m 3 x 108m
1 kmF=G.M.mp2
6.67 x 10-11 N kg 2. m2 X 7 × 1022 kg X 1 kg\s(3 x 108 m) (3 x 108 m) 2\s5.19 x 10-5 N
What is a good illustration of force?A push that has the potential to accelerate something is called a force. A physical push could be used to move a large furniture item around a room. It might be less concrete, like depressing a gas pedal in such a car. J
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This passage describes an example of cultural diffusion through
A country has recently made high-speed Internet available
to its citizens. As a result, people are able to connect with
others around the world. Some people are using social
networks to make friends in other countries. Others are
learning about how other countries deal with social issues
like discrimination.
A. migration
B. trade
C. communication
оо
D. war
Answer:
C is the correct answer
Explanation:
I got it right on my test
Answer:
Communication
Explanation:
See how the people are using the internet
They are socially connectedThey are connected with other countries affairsThey are communicating among themselves in society and furtherSo option C is correct
If 1000 droplets of water of surface tension 0. 07N/m,having same radius 1mm each,combine to form a single drop. In the process the released surface energy is
Surface energy released when 1000 droplets of water of surface tension 0.07 N/m, each with a radius of 1 mm, combine to form a single drop is approximately \(8.82 * 10^-7 J.\)
When the 1000 droplets of water combine to form a single drop, the surface area of the resulting drop decreases. As a result, the surface energy of the drop decreases because the surface tension of water is a measure of the energy required to increase the surface area of the water.
The surface area of the combined droplets can be calculated using the formula for the surface area of a sphere:
A = \(4pi*r^2\)
where A is the surface area, and r is the radius of the individual droplets.
Substituting the known value of the radius, we get:
A =\(4pi*(0.001 m)^2\)
A ≈ \(1.26 * 10^-5 m^2\)
The surface energy of the combined droplets can be calculated using the formula:
E = σA
where E is the surface energy, and σ is the surface tension of water.
Substituting the known values, we get:
E = \((0.07 N/m) * (1.26 * 10^-5 m^2)\)
E ≈\(8.82 * 10^-7 J\)
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An airplane accelerates with a constant rate of 3.0 m/s2
starting at a velocity of 21 m/s. If the final velocity is 60 m/s,
what is the displacement during this period?
Answer:527 m
Explanation:
The displacement or distance travelled by the airplane during the given period is 526.5m
Given the data in the question;
constant acceleration; \(a = 3.0m/s\)
Initial velocity; \(u = 21m/s\)
Final velocity; \(v = 60m/s\)
Displacement or distance; \(s = ?\)
To find the displacement or distance the plane has travelled during the given period, we use the Third Equation of Motion:
\(v^2 = u^2 + 2as\)
Where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.
Lets make "s" the subject of the formula
\(s = \frac{v^2-u^2}{2a}\)
We substitute our given values into the equation
\(s = \frac{(60m/s)^2 - (21m/s)^2}{2 \ *\ 3m/s^2} \\\\s = \frac{(3600m^2/s^2) - (441m^2/s^2)}{6m/s^2}\\\\s = \frac{3159m^2/s^2}{6m/s^2}\\\\s = 526.5m\)
Therefore, The displacement or distance travelled by the airplane during the given period is 526.5m
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If the answer to your calculation has units of kg ∙ m2/s, what type of quantity could it be? (There could be more
than one correct choice).
A) force
B) work
C) angular momentum
D) linear momentum
E) power
F) rotational kinetic energy
G) moment of inertia
H) torque
The answer using kg/m2/s units denotes angular momentum. (option C).
The following are the units for the specified quantities:
A) Newtons of force (N)
B) Joules of Work (J)
C) The kilogram-meter-squared per second (kgm2/s) is unit of angular momentum
D) Linear momentum, expressed in kilograms per second (kg/s).
E) Watts (W) Power
F) Joules (rotational kinetic energy)
(G) Moment of inertia expressed in kilograms per square meter (kg/m2)
H) Newton-meters (Nm) of torque.
The quantity must have been momentum since the response had the units (kgm/s).
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an insulated, rigid tank whose volume is 0.5 m3 is connected by a valve to a large vessel holding steam at 40 bar, 500 oc. the tank is initially evacuated. the valve is opened only as long as required to fill the tank with steam to a pressure of 20 bar. determine the final temperature of the steam in the tank, in oc, and the final mass of the steam in the tank, in kg.
The final temperature of the steam in the tank is 685.869°C , in oc, and the final mass of the steam in the tank is 2.274 kg.
Applying mass balance
m+m1 = m2
0+m, = m.
mi = m2
By applying energy equation m1u1+mihi = m2u2,
0+m/h = mu2
hi = u2
At p1 = 40 bar and T = 500°C from superheated water tables hi=3445.3kJ/kg
Therefore
hi = ui =3445.3kJ/kg
At p2 = 20bar and u2 = 3445.3 kJ/kg from superheated water tables
T2 = 640 + (700-640)(3470.9-3362.2 / 3445.3-3362.2)
T2 = 685.869°C
v2=0.2091 (0.2232 -0.2091)(3445.3-3362.2 / 3470.9-3362.2)
v2=0.2198 m3/kg
Final mass
m2=V / v2
= 0.5 / 0.2198
m2 = 2.274 kg
Temperature is a measure of the degree of hotness or coldness of an object or a substance. It is a fundamental physical quantity and is commonly measured using a thermometer. The temperature of an object or substance is determined by the average kinetic energy of its molecules.
In the Celsius temperature scale, the freezing point of water is defined as 0 degrees Celsius (°C), while its boiling point is defined as 100°C at standard atmospheric pressure. In the Fahrenheit temperature scale, the freezing point of water is defined as 32 degrees Fahrenheit (°F), and its boiling point is defined as 212°F at standard atmospheric pressure. Temperature is an important parameter in many fields of science, including physics, chemistry, and biology. It affects the behavior of matter, the rate of chemical reactions, and the growth and survival of living organisms.
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Complete Question: -
An insulated, rigid tank whose volume is 0.5 m^3 is connected by a valve to a large vessel holding steam at 40 bar, 500 C. the tank is initially evacuated, the value is opened only as long as required to fill the tank with steam to a pressure of 20 bar. determine the final temperature of the steam in the tank, in C, and the final mass of the steeam in the tank, in Kg.