The spring was originally compressed by a distance of 0.105 m.
We can solve this problem using conservation of energy. The potential energy stored in the compressed spring is transformed into kinetic energy of the glider as it moves up the slope, and then back into potential energy as the glider moves back down the slope. Neglecting friction, the total energy of the system is conserved.
The potential energy stored in the compressed spring is given by:
U = (1/2) k x²
where k is the spring constant, x is the distance that the spring is compressed from its equilibrium length, and U is the potential energy.
When the spring is released, the potential energy stored in the spring is transformed into kinetic energy of the glider. At the maximum height, all of the kinetic energy has been converted back into potential energy, so we can write:
(1/2) k x² = m g h
where m is the mass of the glider, g is the acceleration due to gravity, h is the maximum height reached by the glider, and x is the distance that the spring was compressed.
Solving for x, we get:
x = sqrt(2 m g h / k)
Substituting the given values, we get:
x = sqrt(2 × 0.0900 kg × 9.81 m/s² × 1.15 m / 648 N/m) = 0.105 m
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long-term exposure to loud noises can damage hearing. if a loud machine produces sounds with an intensity level of 110db , what would the intensity level be if the intensity were reduced by a factor of 5?
Long-term exposure to loud noises can indeed damage hearing. If a loud machine produces sounds with an intensity level of 110dB, and the intensity were reduced by a factor of 5, the new intensity level would be 92dB. It's important to protect our hearing from loud noises to prevent damage and preserve our ability to hear well.
Long-term exposure to loud noises can indeed damage hearing. If a loud machine produces sounds with an intensity level of 110 dB, and the intensity is reduced by a factor of 5, you would calculate the new intensity level as follows:
New intensity (in watts/m²) = Original intensity / 5
First, you need to convert the original 110 dB to watts/m² using the formula:
Intensity (in watts/m²) = 10^(dB/10) = 10^(110/10) = 10^11 watts/m²
Next, divide the original intensity by 5:
New intensity (in watts/m²) = 10^11 / 5 = 2 x 10^10 watts/m²
Finally, convert the new intensity back to decibels:
New intensity level (in dB) = 10 * log10(new intensity) = 10 * log10(2 x 10^10) ≈ 103 dB
So, the new intensity level would be approximately 103 dB if the intensity were reduced by a factor of 5.
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Ayla hangs a 7.5 kg bowling ball from the ceiling by a rope of negligible mass. The rope will break if the tension in the rope exceeds 115 N. What minimum force must Ayla's dog Rufus exert on the bowling ball to break the rope.
Answer: >41.5N
Explanation:
Mass of bowling ball = 7.5kg
Breaking point of rope = T > 115N
Where T = Tension on the rope
Since the bowling ball is hung by a rope :
Tension (T) = mg = 7.5 kg × 9.8m/s^2 = 73.5kgm/s^2
T = mg + ma
F = ma
T = mg + F
>115 = 73.5 + F
F = 115 - 73.5
F = 41.5N
Force >41.5N
2) the earth is 1.49x1011 m from the sun. if the earth requires 365.25 days to go once around the sun, what is the centripetal force on the earth
The centripetal force on the earth is 352.8x 10^20N if the earth is 1.49x10^11 m from the sun and requires 365.25 days to go once around the sun.
Given the distance of earth from sun is (r) = 1.49x10^11 m
Number of days the earth requires to complete one revolution (T) = 365.25
The mass of the earth (m) = 5.98x10^24 kg
We know the centripetal force = Fc = mrω^2 where ω is the angular velocity of earth to travel around the sun.
Also we know that ω = 2π/T where T is the time required for the Earth to complete one revolution around the Sun.
Fc = m x r x (2π/T)^2
T = 365.25days x 24 hrs x 60 min x 60 s
Fc = (5.98x10^24 x 1.49x10^11 x 4π^2) / (365.25 x 24 x 60 x 60)^2
Fc = 351.4 x 10^35/(31557600)^2
Fc = 111.35 x 10^28/31557600
Fc = 352.8x 10^20N
Hence the centripetal force on the earth is 352.8x 10^20N.
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what body part plays a strong role in releasing power
Answer:
I think your bones, muscles, and joints your welcome :)
Explanation:
A smooth wooden block is placed on a smooth wooden table top. You find that you must exert a force of 14 N to keep the 40 N blocks moving a constant velocity.
a.) What is the coefficient of sliding friction for the block and the table?
b.) If a 20 N Brick is placed on the block, what force will be required to keep the block and brick moving at constant velocity?
The force required to keep the block and brick moving at constant velocity is 46 N.
Given data:
Force needed to keep the block moving with constant velocity = 14 N
Weight of the wooden block = 40 N
Weight of the brick = 20 N
We have to calculate:
a) Coefficient of sliding friction between the block and the table.
b) Force needed to keep the block and brick moving at constant velocity.
Calculation:
a) Coefficient of sliding friction between the block and the table:
Let μ be the coefficient of sliding friction between the block and the table and n be the normal force between the block and the table.
μ = Force of friction / Normal force
We know that normal force is equal to the weight of the block.
n = 40
N = Weight of the block
Force of friction = 14 N (as the block is moving at a constant velocity)
μ = 14 / 40
μ = 0.35
Therefore, the coefficient of sliding friction between the block and the table is 0.35.
b) Force needed to keep the block and brick moving at constant velocity:
For the block and brick to move at a constant velocity, the force required to move the block and brick together should be equal to the force of friction acting on the block and table.
Forces acting on the block and brick:
1) Weight of the block and brick acting downwards
2) Force of friction acting upwards
Net force acting on the block and brick = (Weight of the block + Weight of the brick) - Force of friction
Net force acting on the block and brick = (40 + 20) N - 14 N
Net force acting on the block and brick = 46 N
Force required to keep the block and brick moving at constant velocity = 46 N
Therefore, the force required to keep the block and brick moving at constant velocity is 46 N.
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A piano has a mass of 99 kg. What is the weight of the piano?
Explanation:
weight of the piano = mg
w = 99 x 10 =990 N
what is the color that makes purple ?
ANSWER RED)BLUE
Answer:
both
Explanation:
really you don't know something from kindergarden
12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
Please help
A ball of mass 0.32kg and a velocity of 5.1m/s collides head on with a ball of mass 0.75kg that is initially at rest. No external forced act on thr balls. After the Collison, the velocity of the ball which ews originally at rest is 2.38 m/s. What is the velocity of the 0.32kg ball after the collision.
Answer:
4.695 m/s
Explanation:
We can use the law of conservation of momentum to solve this problem. The law of conservation of momentum states that the total momentum of a closed system remains constant if there are no external forces acting on it. In this case, the two balls form a closed system.
The total momentum before the collision is:
p_before = m1v1 + m2v2
where m1 and v1 are the mass and velocity of the first ball, and m2 and v2 are the mass and velocity of the second ball.
Plugging in the values given in the problem, we get:
p_before = (0.32 kg) * (5.1 m/s) + (0.75 kg) * (0 m/s) = 1.632 kg*m/s
The total momentum after the collision is:
p_after = m1v1' + m2v2'
where v1' and v2' are the velocities of the first and second ball after the collision.
We know the velocity of the second ball after the collision:
v2' = 2.38 m/s
To find the velocity of the first ball after the collision, we can use the conservation of momentum:
p_before = p_after
m1v1 + m2v2 = m1v1' + m2v2'
Plugging in the values we know and solving for v1', we get:
v1' = (m1v1 + m2v2 - m2*v2') / m1
v1' = (0.32 kg) * (5.1 m/s) + (0.75 kg) * (0 m/s) - (0.75 kg) * (2.38 m/s) / (0.32 kg)
v1' = 6.48 m/s - 1.785 m/s
v1' = 4.695 m/s
Therefore, the velocity of the 0.32 kg ball after the collision is 4.695 m/s
The final velocity of the first ball is approximately 3.14 m/s. We can solve this physics problem using the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision, which allows us to solve for the unknown final velocity of the first ball.
Explanation:
To solve this problem, we can use the principle of conservation of momentum.The preliminary momentum of the machine is identical to the very last momentum.Since the second one ball is first of all at rest, its preliminary momentum is zero. The initial momentum of the first ball is given by the product of its mass and velocity: 0.32 kg × 5.1 m/s.
Using the principle of conservation of momentum, we can set up the equation: (0.32 kg × 5.1 m/s) = (0.32 kg × v1) + (0.75 kg × 2.38 m/s), where v1 represents the final velocity of the first ball.
By solving this equation, we can find that the final velocity of the first ball is approximately 3.14 m/s.
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Why are we unable to work long without food
Answer:
Without food your not able to produce energy thats why you cannot work so long
asvab scores are entered on what service record
ASVAB scores are entered on the service record known as the Enlisted Record Brief (ERB) or the Officer Record Brief (ORB).
The Enlisted Record Brief (ERB) is used for enlisted service members, while the Officer Record Brief (ORB) is used for officers. Both records document a service member's career information, including qualifications and training. ASVAB scores, which assess a person's aptitude for various military jobs, are recorded in either the ERB or ORB to track an individual's capabilities and assist in career progression and assignment decisions.
ASVAB scores, which evaluate a person's aptitude for military job roles, are recorded in the service records of individuals. Enlisted service members have their ASVAB scores entered in the Enlisted Record Brief (ERB). The ERB is a comprehensive record containing career information, qualifications, training, and promotions for enlisted personnel. ASVAB scores are included in the ERB to provide a documented record of abilities for career development and decision-making purposes. Officers have their ASVAB scores recorded in the Officer Record Brief (ORB), which is tailored for officers and includes details such as career progression, training, qualifications, and ASVAB scores. These service records play a crucial role in assessing capabilities and determining suitable assignments and career progression within the military.
ASVAB scores are an important part of a service member's record, and they are entered in the appropriate service record, either the Enlisted Record Brief (ERB) or the Officer Record Brief (ORB), based on the individual's military status.
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A 2-kg mass placed 30-cm to the left of the fulcrum is balanced by a 2-kg mass placed ______ cm to the right of the fulcrum.
Answer:
30 cm
Explanation:
0.06 or \(\frac{1}{15}\)
What is the effort and load arm?The lever has two “arms”:
The load arm is the portion of the lever directly connected to the load.
The effort arm is the portion of the lever to which we apply the effort, or input force.
The formula of the mechanical advantage(MA) of a lever is given as
MA = load/effort.
Given,
load = 2kg , effort = 30cm
MA = \(\frac{2}{30}\) = \(\frac{1}{15}\)
MA = 0.06 cm
Therefore,
A 2-kg mass placed 30-cm to the left of the fulcrum is balanced by a 2-kg mass placed 0.06 cm to the right of the fulcrum.
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A diffraction-limited laser of length L and aperture diameter 0.50 cm generates light of wavelength 700nm . If the beam is directed at the surface and the radius of the illuminated area on the surface is approximately 45cm, how far away is the surface
The distance of the surface illuminated by the light of the given wavelength is 5,269.32 m.
Distance of the surface
The distance of the surface illuminated by the light of the given wavelength is calculated as follows;
D = (rd)/(0.61λ)
where;
r is the radius of the illuminated area = 45 cm = 0.45 md is the diameter of the diameter = 0.5 cm = 0.005 mλ is wavelength = 700 nm = 700 x 10⁻⁹ mD = (0.45 x 0.005) / (0.61 x 700 x 10⁻⁹)
D = 5,269.32 m
Thus, the distance of the surface illuminated by the light of the given wavelength is 5,269.32 m.
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FILL IN THE BLANK. Whenever you double your speed your vehicle has about _____ times the destructive power if it crashes
Whenever you double your speed, your vehicle has about four times the destructive power if it crashes.
- The destructive power of a vehicle in a crash is directly proportional to its kinetic energy.
- Kinetic energy is calculated as 1/2 * mass * \(velocity^2\).
- Therefore, if you double your speed (velocity), the kinetic energy of your vehicle increases by a factor of \(2^2\) (or 4).
- This means that your vehicle will have about four times the destructive power in a crash if you double your speed.
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10
A student is given two pieces of iron and told
to determine if one or both of the pieces are
magnets. First, the student touches an end of
one piece to one end of the other. The two
pieces of iron attract. Next, the student reverses
one of the pieces and again touches the ends
together. The two pieces attract again. What
does the student definitely know about the
initial magnetic properties of the two pieces of
iron? [1] has tautube
The fact that the two pieces of iron were drawn to each other in both trials demonstrates that one is a magnet and the other is iron.
What is magnetism?
The phrase "magnetism" refers to a set of phenomena caused by magnets, which generate fields that repel and attract other things. It is the general property of the electromagnetic force.
The learner can deduce that both pieces of iron are magnets based on his observations.
When the two pieces of iron were initially touched end-to-end and attracted, it suggested that at least one of them was a magnet, because non-magnetic materials would not display any magnetic attraction.
When one of the pieces was turned around and attracted to the other, it was clear that both were magnets. If one of the pieces was not a magnet, inverting it would cause the two pieces to resist rather than attract.
As a result, the fact that both trials produced attraction between the two pieces of iron suggests that both are magnets.
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Just answer the first one at least
Answer:
D
Explanation: That is the lowest point in a cycle
Answer:
I just had a question the same as this.
The answer is: Points (B) & (F)!
Hope it helps! :D
Why are the voice of men women and children different??
We each have a unique voice because so many factors work together to produce that voice. As air passes over them, the vocal cords vibrate very quickly to produce sounds. The higher the rate of vibration, called frequency, the higher the pitch will be.
can plz anyone solve this
Answer:
1 Ohm
Explanation:
Resistance: Voltage/Current
R: 1.5/ 1.5 = 1 Ohm
Which of the following statements is true?
If a hypothesis is proven false, a mistake has been made in the experiment.
The independent variable is what changes as a result of the dependent variable.
Changes in the independent variable cause changes in the dependent variable.
Once a hypothesis is proven true, it becomes a theory and cannot be disproved.
Answer:
\(Changes \: in \: the \: independent \: variable \: cause \\ changes \: in \: the \: dependent \: variable.\)
Two 10.-ohm resistors have an equivalent resistance of 5.0 ohms when connected in an electric circuit with a source of potential difference. Using circuit symbols found below, draw a diagram of this
circuit.
The resistors are connected in parallel between the terminals of a battery.
Note: If those resistors are connected in parallel, then their equivalent resistance is already 5 ohms, even if they're still in the drawer or in a box on the shelf. They don't have to be connected to a source of voltage for that to happen.
Hamid is going to heat sodium chloride and water in a beaker. How can he carry out his experiment as
safely as possible?
[4 marks]
Answer:
he can wear gogles lab coat and gloves
Explanation:
What is the acceleration of the object in this graph?
Answer: 6 and 0.75
Explanation:
because you look how far up it goes and just use the graph
which atomic particle has no charge?
A. Electron
B. Neutron
C. Nucleus
D. Proton
Answer:
B. Neutron has no charge
Answer:
B. Neutron
Explanation:
Firstly, the nucleus is what contains the protons and electrons, so it is not an atomic particle. The electron has a negative charge, and the proton has a positive charge (you can remember this by looking at its prefix 'pro'). This means the neutron has no charge (think of it as neutral).
1. A 10-kg medicine ball is thrown at a velocity of 15 km/hr to a 50-kg skater who is at rest on ice. The skater catches the ball and subsequently slides with the ball across the ice. Consider the skater and the ball as two separate parts of an isolated system. (no external forces)
The medicine ball starts out with a momentum of 150 kgkm/h (10 kg x 15 km/h). Because the skater is at rest, the system's starting momentum is just 150 kg/km/hr.
A medicine ball is a weighted workout ball that is used for building core strength, endurance, and power. They range in size and weight from 1 kg to 10 kg, respectively. Typically fashioned of leather, rubber, or plastic, they contain sand or a sand-and-water mixture. When performing workouts like abdominal twists, sit-ups, push-ups, lunges, and squats, people frequently use medicine balls. The additional weight makes the activity more difficult and resistant, making it a more tough workout. They are a flexible and powerful tool for enhancing conditioning, strength, and general fitness.
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a charged particle is immersed in a uniform magnetic field coming out of the page and is moving along a circular path in the counter-clockwise direction. what is the charge of the particle in this situation?
The charge of the particle in this situation is positive. When a charged particle is immersed in a uniform magnetic field, it experiences a force known as the Lorentz force, which is given by the equation:
F = q(v × B)
Where F is the Lorentz force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.
In this case, the particle is moving along a circular path in the counter-clockwise direction, which means that the force acting on the particle is directed towards the center of the circle. This force is known as the centripetal force, and it is given by the equation:
F = mv^2/r
Where m is the mass of the particle, v is the velocity of the particle, and r is the radius of the circle.
Since the Lorentz force and the centripetal force are equal in magnitude and opposite in direction, we can equate the two equations to get:
q(v × B) = mv^2/r
Rearranging the equation and solving for q gives:
q = mv^2/(rB)
Since the particle is moving in the counter-clockwise direction, the velocity vector v is directed tangentially to the circle, and the magnetic field vector B is directed out of the page. The cross product of these two vectors is directed towards the center of the circle, which means that the charge of the particle must be positive in order for the Lorentz force to be directed towards the center of the circle.
Therefore, the charge of the particle in this situation is positive.
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La motocicleta que tiene el récord mundial de aceleración es una motocicleta eléctrica, llamada "Killacycle" la cual permite pasar de 0 Km/h a 100 km/h en tan solo 1.5 s ¿Cuál es la aceleración media de esta motocicleta?
Answer:
\(a=18.51\ m/s^2\)
Explanation:
Given that,
Initial speed, u = 0 km/h
Final speed, v = 100 km/h = 27.77 m/s
Time, t = 1.5 s
We need to find the average acceleration of this motorcycle. It is equal to the rate of change of velocity and it is given by :
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{v}{t}\\\\a=\dfrac{27.77\ m}{1.5\ s}\\\\a=18.51\ m/s^2\)
So, the acceleration of the motorcycle is \(18.51\ m/s^2\).
The statement “Heavy objects fall faster than light objects” is an example of a(n) _______.
A. Hypothesis
B. Question
C. Conclusion
D. Theory
Answer:theory
Explanation:
I WILL GIVE BRAINLIEST TO THE FIRST PERSON WHO ANSWERS MY QUESTION!
Explain what we know about the center of the universe.
“There is no centre of the universe! According to the standard theories of cosmology, the universe started with a "Big Bang" about 14 thousand million years ago and has been expanding ever since. Yet there is no centre to the expansion; it is the same everywhere”.
Answer:
There is no center of the universe.
Explanation:
According to scientists, the universe started with a "Big Bang" millions of years ago and has been expanding ever since.
You are standing on a moving bus, facing forward, and you suddenly fall forward. You can imply form this that the bus’s
A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air? Part 1 of 2 The speed of the plane in still air is Part 2
The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.
Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.
The distance traveled with the wind in 3 hours is 408 miles.
Therefore, we can write the equation as:
3(x + y) = 408
Divide both sides by 3:
x + y = 136 .... (1)
The distance traveled against the wind in 4 hours is also 408 miles.
Therefore, the equation can be written as:
4(x - y) = 408
Divide both sides by 4:
x - y = 102 .... (2)
Now we can solve these two equations using the elimination method.
Add equations (1) and (2):
x + y + x - y = 136 + 1022x = 238x = 119 mph
Therefore, the speed of the plane in still air is 119 mph.
Now, substitute this value of x in equation (1):
119 + y = 136y = 17 mph
Therefore, the speed of the wind is 17 mph.
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The correct question is:
A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?