(a) The energy transformed from mechanical to internal as a result of friction in one revolution is 5.60 J. (b) The total number of revolutions the particle makes before stopping is 10.
(a) To find the work done, the energy transformed from mechanical to internal in the particle–hoop–floor system as a result of friction in one revolution, the following formula is used:
W = ΔK + ΔU + ΔE
The initial kinetic energy of the particle is:
(1/2)mv² = (1/2)(0.400 kg)(8.00 m/s)² = 12.8 J
The final kinetic energy of the particle is:
(1/2)mv² = (1/2)(0.400 kg)(6.00 m/s)² = 7.20 J
Therefore, the change in kinetic energy:
ΔK = Kf – Ki = 7.20 J – 12.8 J = –5.60 J.
The work done by friction is the energy transformed from mechanical to internal. Therefore, the work done is:
–W = –ΔK = –(–5.60 J) = 5.60 J.
Hence, the energy transformed from mechanical to internal in the particle–hoop–floor system as a result of friction in one revolution is 5.60 J.
(b) The work done by friction in one revolution is equal to the change in kinetic energy. Therefore, the work done by friction in n revolutions is n times the work done in one revolution.
W = –ΔK = 5.60J*n
W = 5.60 J
The final kinetic energy of the particle is zero. Therefore, the change in kinetic energy is equal to the initial kinetic energy. Hence,
(1/2)mv² = 12.8 Jv = 8.00 m/s
The time taken for the particle to stop is given by:
v = u – at
0 = 8.00 m/s – a*t
Therefore, t = 8.00 m/s/a
The distance covered by the particle before stopping is equal to the circumference of the hoop. Therefore, the distance is
2πr = 2π(0.500 m) = 3.14 m.
From the equations of motion,
s = ut + (1/2)at²
Therefore,
3.14 m = 8.00 m/s * t + (1/2) a t²
t² = 0.25*(3.14 m - 8.00 m/s*t)
t² = 0.785 – 2*t
3*t = 0.785t = 0.26 s
The acceleration of the particle is given by:
a = –F/m = –μg = –(0.200)(9.80 m/s²) = –1.96 m/s²
t = 8.00 m/s/a = 8.00 m/s/1.96 m/s² = 4.08 s
The time taken for one revolution is equal to the distance divided by the speed, which is 3.14 m/8.00 m/s = 0.3925 s.
n = t/T
n = 4.08 s/0.3925 s = 10.4 ≈ 10.
Therefore, the total number of revolutions the particle makes before stopping is 10.
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Apply 16N to move crate 4m. How much work was done?
It took 3.5 hours for a train to travel the distance between two cities at a velocity of 120 km/h. How far did the train travel between the two cities?
Answer: 420 km
Explanation:
120 per hour, 3.5 hours
120 x 3.5 = 420
A 193.1g mass is hung from a 19.4g clamp on the right side of the stick, a 183.9 mass is hung from a 12.1g clamp on the left side of the meter stick. Determine the total torque from the unknown mass
The total torque created by the two known masses is 1.848 Nm.
How to calculate the torqueWe can use the formula for torque, which is given by:
τ = F x r x sin(θ)
where τ is the torque, F is the force applied, r is the distance from the pivot point to the point where the force is applied, and θ is the angle between the force and the lever arm.
For the first mass (193.1 g), the force applied is the weight of the mass, which is:
F1 = m1 x g = 0.1931 kg x 9.81 m/s^2 = 1.893 N
The distance from the pivot point to the point where the force is applied is half the length of the meter stick, which is:
r1 = L/2 = 0.5 m
The angle between the force and the lever arm is 90 degrees, so:
θ1 = 90 degrees
Using these values, we can calculate the torque created by the first mass as:
τ1 = F1 x r1 x sin(θ1) = 1.893 N x 0.5 m x sin(90 degrees) = 0.9465 Nm
For the second mass (183.9 g), we can follow the same procedure and find:
F2 = m2 x g = 0.1839 kg x 9.81 m/s^2 = 1.803 N
r2 = L/2 = 0.5 m
θ2 = 90 degrees
τ2 = F2 x r2 x sin(θ2) = 1.803 N x 0.5 m x sin(90 degrees) = 0.9015 Nm
The total torque created by the two known masses is the sum of these individual torques, which is:
τtotal = τ1 + τ2 = 0.9465 Nm + 0.9015 Nm = 1.848 Nm
Therefore, the total torque created by the two known masses is 1.848 Nm.
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Peregrine falcons are known for their maneuvering ability. In a tight circular turn, a falcon can attain a centripetal acceleration 1.5 times the free-fall acceleration. Part A What is the radius of the turn if the falcon is flying at 30 m/s
The radius of the turn can be calculated using the centripetal acceleration formula:a_c = v^2 / rwhere a_c is the centripetal acceleration, v is the velocity of the falcon, and r is the radius of the turn.
We know that the centripetal acceleration of the falcon is 1.5 times the free-fall acceleration, which is approximately 9.8 m/s^2. Therefore, the centripetal acceleration of the falcon is:a_c = 1.5 * 9.8 = 14.7 m/s^2We also know that the velocity of the falcon is 30 m/s. Substituting these values into the centripetal acceleration formula, we get:14.7 = 30^2 / rSolving for r, we get:r = 591.8 meters (approx.)Therefore, the radius of the turn is approximately 591.8 meters.Explanation:When a falcon makes a tight circular turn, it needs to generate a centripetal force to keep it moving in a circular path. The centripetal force is generated by the centripetal acceleration, which is directed towards the center of the circle.The centripetal acceleration depends on the velocity of the falcon and the radius of the turn. The faster the falcon is flying or the tighter the turn, the greater the centripetal acceleration required.In this problem, we are given the velocity of the falcon and the centripetal acceleration it can generate. We can use the centripetal acceleration formula to find the radius of the turn.The radius of the turn tells us how tight the turn is. A smaller radius means a tighter turn, which requires a greater centripetal acceleration. In this case, the falcon is able to generate a centripetal acceleration 1.5 times the free-fall acceleration, which is quite impressive and allows it to make tight turns while hunting its prey.
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Destructive interference in a standing wave produces points with zero amplitude called nodes *
true or false
Answer
True; Destructive occurs for two interfering waves that are 180 degrees out of phase
Intermixing of particles of two different types of matter on their own is called.
The intermixing of particles of two different types of matter on their own is called diffusion.
Diffusion is the process by which particles or molecules of different substances mix or spread out spontaneously from an area of higher concentration to an area of lower concentration.
It occurs due to the random motion of particles and the inherent tendency to achieve a state of equilibrium.
In diffusion, the particles of different types of matter move and mix with each other until a uniform distribution is reached. This process is driven by the principle of maximizing entropy, where particles naturally disperse to achieve a more uniform and balanced arrangement.
Diffusion is a fundamental concept in various scientific disciplines, including physics, chemistry, and biology.
It plays a crucial role in many natural phenomena and processes, such as the movement of gases in the atmosphere, the distribution of substances in biological systems, the dissolving of solutes in a solvent, and the spreading of odors.
Overall, diffusion is the term used to describe the intermixing of particles of two different types of matter as they naturally and spontaneously move and spread out to achieve a more uniform distribution.
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How long does cooked quinoa last in the refrigerator.
Cooked quinoa can last in the refrigerator for up to three to five days.
However, it is important to properly store the quinoa in an airtight container or resealable bag to keep it fresh for as long as possible. Additionally, if you notice any unusual odor or appearance, it is best to discard the quinoa.
Cooked quinoa lasts approximately 3 to 5 days in the refrigerator. When properly stored in an airtight container, cooked quinoa can be safely kept in the refrigerator for 3 to 5 days. This helps preserve its freshness and prevents bacterial growth.
To prolong the shelf life of cooked quinoa, it's essential to cool it completely before transferring it into an airtight container or resealable plastic bag. Storing it in the refrigerator at a temperature of 40°F (4°C) or below will help maintain its quality and prevent spoilage during this 3 to 5 day period.
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i. What is the initial velocity of the car?
ii. What is the maximum velocity attained by the car?
iii. Which part of the graph represents zero acceleration?
Answer:
I. 0 m/s
II. 20 m/s
III. Part BC
Explanation:
I. Determination of the initial velocity.
From the diagram given above,
The motion of the car starts from the origin. This implies that the car start from rest and as such, the initial velocity of the car is 0 m/s
II. Determination of the maximum velocity attained.
From the diagram given above, we can see clearly that the maximum velocity is 20 m/s.
III. Determination of the part of the graph that represents zero acceleration.
It important that we know the meaning of zero acceleration.
Zero acceleration simply means the car is not accelerating. This can only be true when the car is moving with a constant velocity.
From the graph given above, the car has a constant velocity between B and C.
Therefore, part BC illustrates zero acceleration.
an object of mass 0.2kg is thrown vertically upwards with a speed of 0.2 m/s. calculate potential energy at the highest point where h=10 and the kinetic energy under the same condition
Answer:
the potential energy is 19.6J
the kinetic energy is 0.0.004J
Explanation:
using the formulas
P.E = mgh while
K.E =mv²/
one significant method for assessing body fat distribution is measurement of ______ circumference.
One significant method for assessing body fat distribution is measurement of waist circumference.
Waist circumference is a widely used method for assessing body fat distribution and is an important indicator of central obesity. It involves measuring the circumference of the waist at a specific anatomical landmark, typically at the level of the narrowest point between the ribs and the iliac crest.
The measurement of waist circumference provides valuable information about the distribution of body fat. Excess fat accumulation in the abdominal region, also known as central obesity or android obesity, is associated with a higher risk of various health conditions, including cardiovascular diseases, type 2 diabetes, and metabolic syndrome.
By measuring waist circumference, healthcare professionals can evaluate an individual's body fat distribution and assess their risk for developing obesity-related health problems.
The measurement of waist circumference is relatively simple and non-invasive, making it a practical method for assessing body fat distribution in clinical and research settings. It is often used in conjunction with other anthropometric measurements, such as body mass index (BMI), to provide a comprehensive evaluation of an individual's body composition and health status.
Regular monitoring of waist circumference can help track changes in body fat distribution over time and guide interventions aimed at reducing central obesity and improving overall health.
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During sublimation and deposition, this state of matter is skipped:
A) Solid
B) gas
C) liquid
The manager of a Canadian pension fund knows that the fund must make a lump-sum payment of C$5 million 10 years from now. She wants to invest an amount today in a GIC so that it will grow to the required amount. The current interest rate on GICs is 6 percent a year, compounded monthly. How much should she invest today in the GIC
The amount manager should invest today in GIC to have C$5 million in 10 years is C$2,775,633.
To find the amount the manager should invest today in a GIC, we can use the future value formula:
FV = PV(1 + r/n)^(nt)
Where FV is the future value, PV is the present value, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the number of years.
In this case, FV = C$5 million, r = 6% (0.06), n = 12 (compounded monthly), and t = 10 years. We need to solve for PV.
Rearrange the formula to solve for PV:
PV = FV / (1 + r/n)^(nt)
Now, plug in the given values:
PV = 5,000,000 / (1 + 0.06/12)^(12*10)
PV ≈ C$2,775,633
The manager should invest approximately C$2,775,633 in the GIC today to have C$5 million in 10 years.
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Cuestión 1 (2 points)
1
Is it true that Air bags save lives becluse they give you more time to slow down during a crash?
Answer:
Even though cars are designed to crumple up and absorb impacts, their energy still poses a major risk to the driver and passengers. ... Airbags help your body stop more slowly, reducing the risk of injury and death.
Explanation:
Which of the following are produced by the process of cellular respiration? A. Sugar and carbon dioxide B. Carbon dioxide and water C. Light energy and water D. Carbon dioxide and oxygen
Answer:
B carbon dioxide and water
Your answer should be
B
because of life-sustaining activities
What are the elements in silk?
Answer:Silk emitted by the silkworm consists of two main proteins, sericin and fibroin, fibroin being the structural center of the silk, and serecin being the sticky material surrounding it. Fibroin is made up of the amino acids Gly-Ser-Gly-Ala-Gly-Ala and forms beta pleated sheets.
Explanation:
Silk emitted by the silkworm consists of two main proteins, sericin and fibroin, fibroin being the structural center of the silk, and serecin being the sticky material surrounding it. Fibroin is made up of the amino acids Gly-Ser-Gly-Ala-Gly-Ala and forms beta pleated sheets.
Answer:
it is sericin and fibroin
Since the moon orbits the earth approximately every 27 days, there is a lunar eclipse approximately every 27 days.
True
False
Answer:
No ! its False
Explanation:
We all know , we dont have lunar eclipse in every 27 days . They do not happen every month because the Earth's orbit around the sun is not in the same plane as the Moon's orbit around the Earth.
Answer:
False
Explanation:
Yes, the moon orbits the Earth every 27 days, actually, it's precisely 27.3, but that does not mean that there is a lunar eclipse every 27 days. A lunar eclipse only happens when the full moon is directly in Earth's shadow. The moon does not pass through Earth's shadow often because of the Earth's axis. Earth only sees a couple of lunar eclipses a year.
which one of the following descriptions is not correct for the hexagon pattern on saturn? a. the hexagon pattern is in the polar region of the northern hemisphere. b. the hexagon pattern was first discovered by the observations from the cassini spacecraft. c. the area inside the hexagon has a complicate structure. d. the hexagon pattern has a lifetime shorter than 10 earth years.
The description that is not correct for the hexagon pattern on Saturn is d. the hexagon pattern has a lifetime shorter than 10 Earth years.
Explanation:
The hexagon pattern is indeed in the polar region of the Northern Hemisphere
(a), was first discovered by the observations from the Voyager spacecraft, not Cassini
(b), and the area inside the hexagon has a complicated structure
(c). However, the hexagon pattern has been observed for more than 30 Earth years, indicating that its lifetime is longer than 10 Earth years(d).
What is hexagon pattern?Saturn's hexagon pattern is a persistent cloud pattern in the planet's atmosphere that has been observed for several decades. The hexagon is a six-sided polygonal shape, and the sides of the hexagon are each about 13,800 km in length, which is greater than the diameter of Earth. The hexagon is located at the planet's north pole and is thought to be a standing wave pattern in the planet's atmosphere.
The hexagon was first discovered in images sent back by the Voyager 1 and 2 spacecraft in the 1980s, and has since been observed by other spacecraft such as the Cassini-Huygens mission, which orbited Saturn from 2004 to 2017. The hexagon is thought to be a result of the interaction between Saturn's atmosphere and its rotation. It is believed that the hexagon is created by a jet stream that flows around the planet's north pole, and that the shape is maintained by the rotation of the planet.
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Finally: Create your own problem, show your math work solving for it, and compare Force acting upon a
mass(kg) given two different speeds(time in seconds) in which a collision takes place:
Pick a mass in
kilograms
Pick a Velocity in
meters per second to
decelerate from
Calculate initial
momentum of the
object
Pick a fast
deceleration
Pick a slower
deceleration
What Force acts on
the mass in the faster
deceleration? (Show
your work and include
correct final units)
What Force acts on
the mass in the slower
daralaration? (Show
E.g. I have a mass of about 82.0kg, a
new popular cell phone has a mass of
0.204kg.
E.g. I'm going 55m/h which equals 24.6
m/s
P=mv
P=82kg x 24.6 m/s
P=2020 kg*m/s
E.g. I'm NOT wearing my seatbelt and I
crash into a wall coming to 0 m/s in just
0.20 seconds
E.g. I am wearing my seatbelt and my
velocity changes over 0.91 seconds.
Fet=P-P₁/t
F=(0 kg*m/s-2020 kg*m/s)/0.2s
F=-2020 kg*m/s +0.20s
Force =-10,000 Newtons (or
kg*m/s)
Fret=Pr-P₁/t
F=(0 kg*m/s-2020 kg*m/s)/0.91s
C-30306/001
Problem:
A mass of 10 kg is moving at a velocity of 5 m/s. The mass undergoes a deceleration of 10 m/s^2, resulting in a collision. Calculate the force acting upon the mass in the collision.
Solution:
First, we need to calculate the initial momentum of the object before the collision. Momentum is defined as the product of an object's mass and its velocity, so the initial momentum of the mass is 10 kg * 5 m/s = 50 kg*m/s.
Next, we can use the formula for force, which is defined as the product of an object's mass and its acceleration. In this case, the force acting upon the mass in the collision is 10 kg * 10 m/s^2 = 100 N.
To compare the force acting upon the mass in a faster deceleration, we can assume that the mass undergoes a deceleration of 20 m/s^2 instead of 10 m/s^2. In this case, the force acting upon the mass would be 10 kg * 20 m/s^2 = 200 N, which is twice as large as the force in the original scenario.
Similarly, in a slower deceleration of 5 m/s^2, the force acting upon the mass would be 10 kg * 5 m/s^2 = 50 N, which is half as large as the force in the original scenario.
T/F: The length of the repeat unit of a microsatellite is longer than the length of the repeat unit of the minisatellite.
Given statment "The length of the repeat unit of a microsatellite is longer than the length of the repeat unit of the minisatellite"is true. Because the length of the repeat unit of a microsatellite is shorter than that of a minisatellite.
True. Microsatellites and minisatellites are both types of tandem repeats, which are repeating sequences of DNA that occur one after another in a particular location on a chromosome. However, the main difference between the two lies in the length of their repeat units.
Microsatellites have shorter repeat units consisting of 1-6 nucleotides, whereas minisatellites have longer repeat units consisting of 10-60 nucleotides. This means that the length of the repeat unit of a microsatellite is shorter than that of a minisatellite.
Another difference between the two types of tandem repeats is their location on the chromosome. Microsatellites are generally located in the non-coding regions of DNA, whereas minisatellites are found in both coding and non-coding regions.
The difference in the length and location of these tandem repeats makes them useful for different types of genetic analysis. Microsatellites are commonly used for forensic analysis, paternity testing, and population genetics studies, while minisatellites are used for studying genetic variation and mutation rates.
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Diamond is the one mineral in the world that cannot be scratched by any other mineral. Therefore, we refer to diamond as the ____________ mineral.
A. hardest
B. purest
C. densest
D. lustrous
A,B,C,D pick a answer
Answer:
hardest
Explanation:
Diamonds are known as the hardest naturally occurring substance known.
Answer:
A. hardest
Explanation:
A telescope is used to take two images, one magnified 100x and the other magnified 400x. In which image would you be able to see the most detail and why?.
We can see the image in most detail that having 400x magnification as compared to 100x.
What is magnification?Magnification is the process in which the size of an object is enlarging but not physical size of something. Those instruments having high magnification power can shows us the image larger and due to which we can see that image clearly.
So we can conclude that we can see the image in most detail that having 400x magnification.
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Three structures that attached to the hair follicle
a child with a mass of 30 kg is standing on a spring scale in an elevator. if the spring scale reads 360 n, what are the magnitude and direction of the acceleration of the elevator at this time? the acceleration due to gravity is 10 m/s2 .
The acceleration of the elevator at this time was 2m/s² and the elevator was accelerating the upward direction.
The mass of the child standing on a spring scale in an elevator is 30 kg the elevator is showing a reading of 360 Newtons.
The reading note by the elevator is given by radiation,
W = M(g+a)
Where w is the reading of the spring scale,
M is the mass of the child,
g is the gravitational acceleration which is given to be 10m/s² and a is the acceleration of the elevator.
Putting values,
360 = 30(10+a)
12 = 10+a
a = 2m/s²
As you can see from the above result that the acceleration of the lift is 2m/s² and because it is positive it means that the elevator is accelerating in the upward direction.
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A 2400W electric toaster is connected to a standard 120 V wall outlet. A family
measured their monthly toaster usage to be 6.5 hrs.
1) How much electrical energy (in kilowatt hours - kWh) did the toaster dissipate
during the measured month? (round to 1 decimal place & do not include units)
2) If the local power company charges $0.13/ kWh, then calculate (in $) the monthly
total cost of this toaster. (round to 2 decimals & do not include units)
Answer:
1) energy = 15.6 kWh, 2) total_cost = $ 2.03
Explanation:
1) The energy dissipated is the product of the power and the time of use In a month it was used t = 6.5 h and the power of the toaster is
P = 2400 W = 2,400 kW
energy = P t
energy = 2,400 6.5
energy = 15.6 kWh
using rounding to a decimal
energy = 15.6 kWh
2) The cost of energy is unit_cost = $ 0.13 / kWh
so the total cost
total_cost = energy unit_cost
total_cost = 15.6 0.13
total_cost = $ 2.028
rounding to two decimal places
total_cost = $ 2.03
An object moving with uniform acceleration has a velocity of 11.0 cm/s in the positive x-direction when its x-coordinate is 2.76 cm. If its x-coordinate 2.25 s later is −5.00 cm, what is its acceleration?
Given:
The initial velocity is
\(v_i=\text{ 11 cm/s}\)The initial position is x1 = 2.76 cm
The final position is x2 = - 5 cm
The time will be t = 2.25 s
To find the acceleration.
Explanation:
The acceleration can be calculated by the formula
\(\begin{gathered} \Delta x=v_it+\frac{1}{2}at^2 \\ \frac{1}{2}at^2=\Delta x-v_it \\ a=\frac{2(\Delta x-v_it)}{t^2} \end{gathered}\)Here, the displacement is
\(\begin{gathered} \Delta x=x2-x1 \\ =-5-2.76 \\ =-7.76\text{ cm} \end{gathered}\)On substituting the values, the acceleration will be
\(\begin{gathered} a=\frac{2(-7.76-11\times2.25)}{(2.25)^2} \\ =\text{ -12.84 cm/s}^2 \end{gathered}\)Final Answer: The acceleration is -12.84 cm/s^2
The FIGURE 5 shows a string wound around a wheel with the free end of the string tied to the ceiling. The mass of the wheel is 0.500 kg and its radius is 40.0 cm. When the wheel is released, it will fall downwards and, at the same time, rotate. If the moment of inertia of the wheel about its axis of rotation is 0.200 kg m². Calculate the linear acceleration of the wheel and the tension of the string.
The 0.500 kg wheel of radius and moment of inertia of 40 cm and 0.200 kg•m² has an acceleration of approximately 2.803 m/s², and a tension of 3.5035 N
What is the moment of inertia of an object?The moment of inertia of a body determines the torque that produces a specified angular acceleration.
Using the linear and rotational form of Newton's second law of motion, we have;
\( \sum F_{x} = m \cdot \: a_{x}\)
\( \sum F_{y} = m \cdot \: a_{y}\)
\( \sum \tau_{z} = I_z \cdot \: a_{z}\)
From the above equations, we have;
\( \sum F_{x} = m \cdot \: a_{x}\)
Which gives;
T - m•g = -m•a
Where;
T = The tension of the string
m = The mass of the wheel
g = Acceleration due to gravity
a = The linear acceleration of the wheel
\( \sum \tau_{z} = I_z \cdot \: a_{z}\)
\(R \cdot T = I\cdot \alpha _{cm}\)
\(\alpha _{cm} = \frac{a}{R} \)
Which gives;
\(R \cdot T = I\cdot \frac{a}{R}\)
Where;
I = The moment of inertia of the wheel
R = The radius of the wheel
\( \alpha _{cm}\) = The rotational acceleration of the wheel
The given parameters are;
Mass of the wheel, m = 0.500 kg
Radius of the wheel, R = 40 cm = 0.4 m
Moment of inertia of the wheel, I = 0.200 kg•m²
Which gives;
T - m•g = -m•a
T = m•g - m•a
\( T = I\cdot \frac{a}{R^2}\)
Which gives;
\( I\cdot \frac{a}{R^2} = m \cdot g - m\cdot a \)
\( I\cdot \frac{a}{R^2} + m\cdot a = m \cdot g \)
\( a \cdot \left(\frac{I}{R^2} + m \right) = m \cdot g \)
Therefore;
\( a = \frac{m \cdot g}{ \left(\frac{I}{R^2} + m \right)} \)
Which gives;
\( a = \frac{0.5 \times 9.81}{ \left(\frac{0.2}{0.4^2} + 0.5 \right)} \approx 2.803 \)
The linear acceleration of the wheel, a ≈ 2.803 m/s²The tension, T = m•g - m•a
Which gives;
T ≈ 0.5 × 9.81 - 0.5 × 2.803 ≈ 3.5035
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7. Charges flow through wires because of differences in electric
Charges flow through wires because of differences in electric potential, also known as voltage.
What is electric potential?When two points in a circuit have different electric potentials, such as when a battery is connected to a wire, the higher potential at one end of the wire produces an electric field. The electric charges are forced to travel in the direction of lower potential by the force of this electric field. Electrons, which are the most common charges, pass across the wire to produce an electric current.
The force that propels the charges is the electric potential difference, or voltage. It may be described as the "pressure" or "push" that causes the charges to flow through the circuit. The larger the potential difference and voltage, the more force is applied to get the charges to flow.
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Mental and emotional health can be improved through exercise true or false
Answer:
True
Explanation:
It can help relax your brain
Which one of the following is an accurate statement about light?
a) When light strikes a surface at Brewster's angle, only the reflected light is 100% polarized.
b) When light strikes a surface at Brewster's angle, the reflected and transmitted light are both 100% polarized.
c) When light strikes a surface at the critical angle, all the light passes through the surface.
d) When light strikes a surface at Brewster's angle, it is completely reflected at the surface.
e) When light strikes a surface at the critical angle, only the reflected light is 100% polarized.
The accurate statement about light is: a) When light strikes a surface at Brewster's angle, only the reflected light is 100% polarized.
Your question is about which statement about light is accurate, including the terms "accurate", "light", and "Brewster's angle". The correct answer is:
a) When light strikes a surface at Brewster's angle, only the reflected light is 100% polarized.
Brewster's angle is the angle of incidence at which light, when striking a surface, is completely polarized in the reflected light. At this angle, the reflected light is polarized perpendicular to the plane of incidence, while the transmitted light is not polarized. This is because, at Brewster's angle, the reflected light is polarized parallel to the surface, while the transmitted light is not completely polarized.
Therefore, option a) correctly states that only the reflected light is 100% polarized at Brewster's angle.
Learn more about Brewster's angle at https://brainly.com/question/29428017
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A cube measures 3cm on each side has a mass of 25 grams. what it its density and relative density.
Answer:
Density= 2.78 g/cm³
Relative density=2.8
Explanation:
To calculate the density of the cube we have to use the formula ρ=mass/volume
ρ stands for density.
So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³
3³= 9 cm³
Now plug in the values. ρ= 25 g/9 cm³
ρ= 2.78 g/cm³
To find the relative density, we have to use the formula ρsample/ρH20
The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.
Now we have to make the units same so you change the unit of the density of cube to kg/m³
So, 25/1000= 0.025 kg
9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)
=0.000009 m³
The new density= 0.025 kg/ 0.000009 m³
= 2777.78 kg/m³
Now plug the values into the formula:
relative density= 2.777.78 kg/m³ / 997 kg/m³
=2.8
There is no unit since kg/m³ and kg/m³ cancels