a student mixes 37.0 ml of 3.34 m pb(no3)2(aq) with 20.0 ml of 0.00245 m na2so4(aq) . how many moles of pbso4(s) precipitate from the resulting solution? the sp of pbso4(s) is 2.5×10−8 .

Answer:

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Explanation:

according to the formula...

density =mass/ volume...

density =21.0/2.00=10.5 g/ cm^3

The answer is A: H₂SO4 + 2LIOH → Li2SO4 + 2H2O

Answer:

H₂SO4 + 2LIOH → Li2SO4 + 2H2O

Explanation:

The balanced equation that represents a neutralization reaction is:

H₂SO4 + 2LIOH → Li2SO4 + 2H2O

This is a neutralization reaction because the acidic hydrogen ions (H+) in sulfuric acid (H₂SO4) react with the basic hydroxide ions (OH-) in lithium hydroxide (LiOH) to form water (H2O) and a salt (Li2SO4). The resulting solution will be neutral as the acid and base have neutralized each other.

Answer:

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Explanation:

carbon fluoride is the answers

Answer:

Tetrahedral.

Explanation:

CF4, as can be seen, has only one carbon atom and four fluorine atoms. The most preferred shape of the chemical is therefore, tetrahedral.

Answer:

Elements

Explanation:

I just did this

The CEC for this soil sample is 675.2 cmol(+)/kg.

The % Base Saturation for this soil sample is approximately 136.62%.

The % Acid Saturation for this soil sample is approximately 60.55%.

To    calculate the CEC, % Base Saturation (B.S.), and % Acid Saturation for the given soil sample:

a. Calculation of CEC (Cation Exchange Capacity):

CEC is the sum of exchangeable cations in the soil. From the given results, we have:

CEC = Ca2+ + Mg2+ + K+ + Al3+

CEC = (100 mg/L + 45 mg/L + 85.5 mg/L + 94.2 mg/L) / (25 g / 1000)

CEC = 168.7 mg / (25 g / 1000)

CEC = 675.2 cmol(+)/kg

b. Calculation of % Base Saturation (B.S.):

% B.S. represents the percentage of CEC occupied by base cations. In this case, we consider Ca2+, Mg2+, and K+ as base cations. The formula to calculate % B.S. is:

% B.S. = (Ca2+ + Mg2+ + K+) / CEC * 100

% B.S. = (100 mg/L + 45 mg/L + 85.5 mg/L) / (168.7 cmol(+)/kg) * 100

% B.S. = 230.5 mg / (168.7 cmol(+)/kg) * 100

% B.S. = 136.62%

c. Calculation of % Acid Saturation:

% Acid Saturation represents the percentage of CEC occupied by acid cations, in this case, H+ and Al3+. The formula to calculate % Acid Saturation is:

% Acid Saturation = (H+ + Al3+) / CEC * 100

% Acid Saturation = (8.0 mg/L + 94.2 mg/L) / (168.7 cmol(+)/kg) * 100

% Acid Saturation = 102.2 mg / (168.7 cmol(+)/kg) * 100

% Acid Saturation = 60.55%

Please note that the given values were in milligrams per liter (mg/L), and the CEC and % Saturation values were calculated assuming a conversion from mg/L to cmol(+)/kg using the mass of the soil sample (25 g).

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Answer:

Phosphorus

Explanation:

Melting point is the exact temperature where it changes from solid to liquid. So if the temp 50°C, it is higher than 44°C meaning that the element already melted and is staying as a liquid.

Boiling point is the exact temperature where it changes from liquid to gas. So if the temp 300°C, it is higher than 28°C meaning that the element already evaporated and is staying as a gas.

1) The balanced chemical equation:

AlO₃(s) + 3NaOH(l) + 3HF(g) → Na₃AlF₆ + 3H₂O(g)

2) When 17.5 kilograms of Al₂O₃, 51.4 kilograms of NaOH, and 51.4 kilograms of HF react completely, approximately 36.02 kilograms of cryolite will be produced.

1.

To balance the equation:

AlO₃(s) + NaOH(l) + HF(g) → Na₃AlF₆ + H₂O(g)

We start by balancing the elements other than oxygen and hydrogen:

AlO₃(s) + 3NaOH(l) + HF(g) → Na₃AlF₆ + H₂O(g)

Next, we balance the oxygen atoms:

AlO₃(s) + 3NaOH(l) + 3HF(g) → Na₃AlF₆ + H₂O(g)

Finally, we balance the hydrogen atoms:

AlO₃(s) + 3NaOH(l) + 3HF(g) → Na₃AlF₆ + 3H₂O(g)

Now, the equation is balanced.

2.

To determine the amount of cryolite produced, we need to calculate the limiting reactant, which is the reactant that is completely consumed and determines the maximum amount of product formed.

The molar masses of the compounds are:

Al₂O₃: 101.96 g/mol

NaOH: 39.997 g/mol

HF: 20.01 g/mol

Na₃AlF₆: 209.94 g/mol

First, let's convert the masses of the reactants into moles:

Al₂O₃: 17.5 kg × (1000 g/kg) / (101.96 g/mol) = 171.54 mol

NaOH: 51.4 kg × (1000 g/kg) / (39.997 g/mol) = 1285.79 mol

HF: 51.4 kg × (1000 g/kg) / (20.01 g/mol) = 2570.71 mol

Looking at the balanced equation, we see that the mole ratio between Al₂O₃ and Na₃AlF₆ is 1:1. So, the number of moles of cryolite produced will be equal to the number of moles of Al₂O₃ consumed.

Hence, the amount of cryolite produced is 171.54 mol.

Finally, to determine the mass of cryolite produced, we multiply the number of moles by the molar mass:

Mass of cryolite = 171.54 mol × (209.94 g/mol) = 36,017.08 g

Therefore, 36,017.08 grams (or 36.02 kilograms) of cryolite will be produced when 17.5 kilograms of Al₂O₃, 51.4 kilograms of NaOH, and 51.4 kilograms of HF react completely.

The completed question is given as,

Cryolite, Na3AlF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide. Balance the equation.

1.) Balance the equation

- AlO3(s)+NaOH(l)+HF(g)-->Na3AlF6+H2O(g)

2.)If 17.5 kilograms of Al2O3(s), 51.4 kilograms of NaOH(l), and 51.4 kilograms of HF(g) react completely, how many kilograms of cryolite will be produced?

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Recovery = (Weight of product recovered ÷ Theoretical yield) × 100% Recovery = (0.251 g ÷ 0.27594 g) × 100% Recovery = 91.08%Therefore, the % recovery of the reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride was 91.08%.

Diels-Alder Reaction   Diels-Alder reaction is a chemical process that joins a conjugated diene with a dienophile (a compound containing a double bond) to form a six-membered ring called a cyclohexene ring. It is a chemical reaction that can be used to make new carbon–carbon bonds. The reaction was discovered by two German scientists, Otto Diels and Kurt Alder, in 1928.In the Diels-Alder reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride, the % recovery was calculated using the following data:Weight of maleic anhydride used: 185 mg = 0.185 gVolume of diene used: 0.215 mLWeight of cyclic anhydride crystals recovered: 0.251 g% Recovery:We can calculate the percent recovery using the following formula:% Recovery = (Weight of product recovered ÷ Theoretical yield) × 100The theoretical yield of the product can be calculated from the balanced chemical equation as follows:2,3-dimethyl-1,3-butadiene + Maleic Anhydride → Cyclohexene-1,2-dicarboxylic AnhydrideThe molar mass of 2,3-dimethyl-1,3-butadiene is 68 g/mol. The molar mass of Maleic Anhydride is 98 g/mol. The molar mass of Cyclohexene-1,2-dicarboxylic Anhydride is 146 g/mol.Using these values, we can calculate the number of moles of each reactant: moles of diene used = (0.215 mL)(0.788 g/mL)/(68 g/mol) = 0.00248 mol moles of maleic anhydride used = 0.185 g/98 g/mol = 0.00189 mol The theoretical yield of cyclohexene-1,2-dicarboxylic anhydride = 0.00189 mol × 1 mol/1 mol = 0.00189 molThe theoretical yield of cyclohexene-1,2-dicarboxylic anhydride = 0.00189 mol × 146 g/mol = 0.27594 gNow, we can substitute these values into the percent recovery equation:% Recovery = (Weight of product recovered ÷ Theoretical yield) × 100% Recovery = (0.251 g ÷ 0.27594 g) × 100% Recovery = 91.08%Therefore, the % recovery of the reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride was 91.08%.

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Answer:

hydrogen bonds are also known as electrostatic dipole interaction

what is Maximum possible products?

Although Minimum Viable Product strategies are effective for startups, they presuppose you have no limitations. However, in an MPP universe, your limitations serve to focus you rather than to thwart you. Instead than conceptualizing ideas for the future, they require you to consider how well you can meet your clients' wants inside a specific situation that now exists.

Photobox will introduce countless new product lines that are only modifications of current products. For instance, a bowl could be printed as a dog bowl or a cereal dish for kids. The tech stack doesn't need to be altered, and customization yields the highest return on investment for the product.

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So, at STP, there are around 891 grammes of nitrogen gas in every 759 litres.

The two stable isotopes of naturally occurring nitrogen (7N) are nitrogen-14 and nitrogen-15, with nitrogen-14 constituting 99.6% of all naturally existing nitrogen. Along with one nuclear isomer, 11mN, fourteen radioisotopes with atomic masses ranging from 10 to 25 are also known.

Assuming "ST" refers to standard temperature and pressure (0°C and 1 atm), we can use the ideal gas law to calculate the mass of nitrogen gas:

PV = nRT

where n is the number of moles, P is the pressure, V is the volume, and T is the temperature, and R is the gas constant.

The temperature and pressure are 273.15 K and 1 atm, respectively, at STP.

To solve for n, the number of moles, we can rearrange the ideal gas law equation as follows:

n = PV / RT = (1 atm) * (759 L) / (0.0821 L·atm/(mol·K) * 273.15 K) = 31.8 mol

Now we can calculate the mass of nitrogen gas:

mass = n * molar mass = 31.8 mol * 28.01 g/mol ≈ 891 g.

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molar heat of vaporization for liquid water is 40.6 kJ/mole. 15.54 kJ of energy is required to change 6.9 g of liquid water to steam if the water is already at 100°C.

To calculate the energy required to change 6.9 g of liquid water to steam, we need to use the formula:

q = n × ΔH_vap

where q is the energy required, n is the number of moles of water being vaporized, and ΔH_vap is the molar heat of vaporization for water, which is 40.6 kJ/mole.

First, we need to calculate the number of moles of water in 6.9 g of liquid water. We can do this using the molar mass of water, which is 18.015 g/mole:

n = m / M

n = 6.9 g / 18.015 g/mol

n = 0.383 moles

Now we can use this value of n and the molar heat of vaporization to calculate the energy required to vaporize the water:

q = n × ΔH_vap

q = 0.383 moles × 40.6 kJ/mole

q = 15.54 kJ

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Answer:

This is happened because, in water there is strong intermolecular force of attraction because of H- bonding. But, in case of HCl, the force of attraction is not so strong

The state of water at room temperature is liquid while Hydrogen chloride is a gas at room temperature. In consideration of three Van der Waals forces ( Keesom,  Debye, and London) which both Water and hydrogen chloride exhibit, Water exhibits hydrogen bonding, which Hydrogen chloride doesn't.

Since water has strong hydrogen bonds, more energy is required to boil water. Water has an electronegative O, water can form hydrogen bonds with other H20 molecules. We know that the hydrogen bond is stronger than the permanent dipole interaction in hydrogen chloride.

Since more energy is required to overcome the hydrogen bond in water.

Hence, the boiling point of water is 100°C while hydrogen chloride is -115°C.

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If in a container that contains hydrogen and nitrogen. the total pressure of the container is 101.6 and the pressure of nitrogen is 76.8.  The partial pressure of hydrogen in the container is 24.8 kPa.

To understand this, we need to understand the concept of partial pressure. The partial pressure of a gas is the pressure that it would exert if it alone occupied the volume of the container. In other words, it is the pressure that a gas contributes to the total pressure in a mixture of gases.  In your scenario, we have a container containing hydrogen and nitrogen gases. The total pressure of the container is 101.6 kPa. We also know that the pressure of nitrogen is 76.8 kPa. To find the partial pressure of hydrogen, we need to subtract the pressure of nitrogen from the total pressure of the container.
Partial pressure of hydrogen = Total pressure of container - Pressure of nitrogen
Partial pressure of hydrogen = 101.6 kPa - 76.8 kPa
Partial pressure of hydrogen = 24.8 kPa
Therefore, the partial pressure of hydrogen in the container is 24.8 kPa. This means that if we were to remove all the nitrogen from the container, the pressure exerted by hydrogen alone would be 24.8 kPa.  It is important to note that the partial pressure of each gas in a mixture depends on its mole fraction, or the proportion of the gas in the mixture. In this case, we do not have information about the mole fraction of each gas, so we assume that the gases are mixed uniformly throughout the container.

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A transaminase can be employed to achieve the synthesis of chiral primary amines from keto acids. Option B is correct.

Transaminases, also known as aminotransferases, are enzymes found in the body that catalyze the transfer of an amino group from an amino acid to a keto acid. There are two types of transaminases that are commonly measured in blood tests: alanine aminotransferase (ALT) and aspartate aminotransferase (AST).

ALT is primarily found in the liver, while AST is found in various tissues including the liver, heart, and skeletal muscle. Elevated levels of these enzymes in the blood can indicate damage or disease in the organ or tissue where they are primarily located.

ALT and AST levels are often measured as part of a liver function test, which may be ordered by a healthcare provider if there are concerns about liver damage or disease. Elevated levels may be seen in conditions such as hepatitis, cirrhosis, or liver cancer. However, it is important to note that elevated transaminase levels can also occur in other conditions and may not necessarily indicate liver disease.

Hence, B. is the correct option.

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--The given question is incomplete, the complete question is

"Which of the following can a transaminase be employed to achieve? A) synthesis of sugars from carbohydrates B) the synthesis of chiral primary amines C) reduction of ketones to chiral alcohols D) hydroxylation of aromatic molecules."--

The balloon's new volume is 24.6L. An arctic weather balloon being inflated using 24.6 litres of helium gas in a prep shed. The shed is seven degrees Celsius inside.

When the balloon is hauled outside, it is seven degrees Celsius outside. Any three-dimensional solid's volume is equal to how much room it occupies. One of these solids can be a cube, a cuboid, a cone, a cylinder, or a sphere. Chemical compounds are composed of a large number of comparable molecules (or molecular entities), which are composed of atoms from various elements bonded together by chemical bonds. Because of this, a molecule composed of atoms from a single element is not a compound.

v1/t1 = v2/t2

24.6/7 = v2/7

v2 = 24.6L

v1 = v2

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The adiabatically compressed system has the higher temperature at the end of the compression.

This is because, according to the ideal gas law, pressure and temperature are related by the equation:

PV^γ = constant

Where γ is the ratio of specific heat for the gas. Since the compression is adiabatic, no heat is added to the system and thus γ = 1.4 for most gases. Therefore, the pressure and temperature are related by:

\(\frac{P1}{T1} = \frac{P2}{T2}\)

Since P1 and P2 are equal (10 bar) but T2 is greater than T1, it follows that T2 must be greater than T1. Therefore, the adiabatically compressed system has a higher temperature than the isothermally compressed system.

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Answer:

salt

Explanation:

cause salt is a solid item

The purpose of the sodium bicarbonate in this experiment is to extract excess water from the ether layer.

Sodium bicarbonate is a chemical compound with the formula NaHCO3. It is a white solid that is crystalline but is also usually available in a fine powder form.

In the experiment mentioned, the sodium bicarbonate is being used to extract the sulfuric acid from the ether layer.

Sulfuric acid is a strong acid that can be hazardous to work with, and it is also an impurity that could interfere with the purity of the desired product. To extract the sulfuric acid from the ether layer, sodium bicarbonate is added to the mixture. The sodium bicarbonate reacts with the sulfuric acid to produce carbon dioxide, water, and sodium sulfate.

The carbon dioxide gas is released, and the sodium sulfate dissolves in the aqueous layer, leaving the sulfuric acid behind in the ether layer. The ether layer is then separated from the aqueous layer, and the sulfuric acid can be discarded or treated appropriately.

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Answer:cool kid

Explanation:cool kid

Answer:

4.70 grams of NH4Cl is needed to prepare 350 mL of a 0.25 M ammonium chloride solution.

We need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

To determine the mass of NH4Cl needed to prepare the solution, we us use the formula:

m=M x V x MM ... (i)

where,

m= mass in grams

M=molarity of solution

MM= molar mass of compound

V= volume in litres

The number of moles of NH4Cl needed can be calculated using:

  Moles = Molarity x Volume ...(ii)

  Moles = 0.25 mol/L x 0.350 L

  Moles = 0.0875 mol

Hence we can replace M x V with number of moles in equation i.

The molar mass of NH4Cl is :

  Molar mass of NH4Cl = (1 x 14.01 g/mol) + (4 x 1.01 g/mol) + (1 x 35.45 g/mol)

  Molar mass of NH4Cl = 53.49 g/mol

We have all the variables

Putting them in equation i.

Hence,

  Mass (g) = Moles x Molar mass

  Mass (g) = 0.0875 mol x 53.49 g/mol

  Mass (g) = 4.68 g

Therefore, you would need approximately 4.68 grams of NH4Cl to prepare a 0.25 M ammonium chloride solution with a volume of 350 mL.

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Answer:

flow of electrons between the electrolytes and the electrodes

Answer:

To determine the classification of the second solution, we need to compare the amount of solid dissolved in it to the amount that can be dissolved in water at that temperature.

From the first solution, we know that 36.8 g of the solid can dissolve in 200 mL of water. To convert this to g/mL, we divide 36.8 g by 200 mL to get 0.184 g/mL.

Using this value, we can calculate the maximum amount of solid that can dissolve in 100 mL of water:

0.184 g/mL x 100 mL = 18.4 g

Since the second solution was made by dissolving 19.1 g of the solid in 100 mL of water, it is a supersaturated solution.

The success of dislodging electrons from a metal surface depends on the energy of the photons that hit it. Photons of violet light have a higher energy than photons of red light.

The energy of photons is directly proportional to their frequency, and the frequency of violet light is higher than that of red light. Therefore, violet light photons are more successful in dislodging electrons from a metal surface. This is because when the photons hit the metal surface, they transfer their energy to the electrons, which get excited and are dislodged from the surface. The greater the energy of the photon, the greater the probability of it being absorbed by the metal surface and dislodging an electron.

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To make up 1 L of a 0.5 M solution of EDTA starting with the free acid, the pH must be adjusted to 7.0. EDTA is a weak acid with a pKa of 2.0, 2.67, 6.16, and 10.26 for the four acetic acid groups.

At a pH of 7.0, EDTA will exist in a buffered state, meaning that it will be partially protonated and partially deprotonated.

To adjust the pH of the EDTA solution to 7.0, an alkali solution such as 10 M NaOH must be added. The amount of NaOH required can be calculated using the Henderson-Hasselbalch equation:

pH = pK a + log([base]/[acid])

where [base] is the concentration of the deprotonated form of EDTA and [acid] is the concentration of the protonated form of EDTA.

At a pH of 7.0, the acid-base equilibrium of EDTA will be:

[EDTA-] = [HEDTA]

At this pH, the buffer capacity is high. Since the pKa of EDTA is close to the desired pH, the buffer will resist changes in pH caused by added acids or bases.

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