The correct option is (b) It must be between 1.52 and 1.66. A very thin film of some other liquid could appear bright by reflected light on both of the glass blocks if the index of refraction of the liquid falls within the range of 1.52 to 1.66.
According to Table 35.1, the index of refraction of flint glass is 1.66 and the index of refraction of crown glass is 1.52. We are asked if a very thin film of some other liquid could appear bright by reflected light on both of the glass blocks. Let's analyze the options:
(a) It must be less than 1.52: This statement is not necessarily true because the index of refraction of the liquid could be greater than 1.52 and still appear bright on both glass blocks.
(b) It must be between 1.52 and 1.66: This statement is correct. For the liquid film to appear bright on both glass blocks, the index of refraction of the liquid must be between the indices of refraction of the two glass blocks. Since the index of refraction of crown glass is 1.52 and the index of refraction of flint glass is 1.66, any liquid with an index of refraction between these two values would appear bright on both glass blocks.
(c) It must be greater than 1.66: This statement is not necessarily true because the index of refraction of the liquid could be less than 1.66 and still appear bright on both glass blocks.
(d) None of those statements is necessarily true: This statement is incorrect because option (b) is true. A liquid with an index of refraction between 1.52 and 1.66 would indeed appear bright on both glass blocks.
In conclusion, the correct option is (b) It must be between 1.52 and 1.66. A very thin film of some other liquid could appear bright by reflected light on both of the glass blocks if the index of refraction of the liquid falls within the range of 1.52 to 1.66.
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What is a example of analyze and interpret data?
Answer:
Data from a cross-sectional study or survey might need to incorporate weights or design effects in the analysis.The analysis plan should specify which variables are most
Explanation:
Explanation:
For example, scientists on a ship may examine SONAR data collected in real-time to determine the shape of the seafloor (Fig 2.7 A). ... Biologists might graph the number of box jellyfish over time and compare these data to the phases of the moon to look for patterns (Fig 2.7 B).
a car is driven 1.5 kilometers west in 2 minutes. what is the velocity in m/s?
Obtain expressions in component form for the position vectors having the following polar coordinates.
After transforming the position vectors from polar coordinates to cartesian coordinates, we get -
a) → r = 12.4 m , θ = 170° ↔ - 12.21 i + 2.15 j
b) → r = 4 cm , θ = 50° ↔ 2.57 i + 3.06 j
c) → r = 20 inches , θ = 210° ↔ - 17.32 i - 10 j
What does a position vector represent?A position vector is a vector that is used to represent the position of a point in the coordinate system.
Given are the polar coordinates of three points in two dimensional coordinate system.
In order to convert the polar coordinate (r, θ) into cartesian coordinates
(x, y) use the following relations -
x = r × cosθ
y = r × sinθ
a) → r = 12.4 m , θ = 170°
x = 12.4 x cos (170°) = 12.4 x -0.98480775301 = -12 .21
y = 12.4 x sin (170°) = 12.4 x 0.17364817766 = 2.15
In cartesian form → ( -12.21 i + 2.15 j )
b) → r = 4 cm , θ = 50°
x = 4 x cos (50°) = 4 x 0.64278760968 = 2.57
y = 4 x sin (170°) = 4 x 0.76604444311 = 3.06
In cartesian form → ( 2.57 i + 3.06 j )
c) → r = 20 inches , θ = 210°
x = 20 x cos (210°) = 20 x -0.86602540378 = -17.32
y = 20 x sin (210°) = 20 x -0.5= -10
In cartesian form → ( -17.32 i - 10 j )
Therefore, after transforming the position vectors from polar coordinates to cartesian coordinates, we get -
a) → r = 12.4 m , θ = 170° ↔ - 12.21 i + 2.15 j
b) → r = 4 cm , θ = 50° ↔ 2.57 i + 3.06 j
c) → r = 20 inches , θ = 210° ↔ - 17.32 i - 10 j
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Starting from rest on a level road a girl can reach a speed of 5 m/s in 10s on her bicycle. Find average speed and distance traveled in 10s.
Answer:
Average speed = 2.5 mph
Distance = 22.352 meters
Explanation:
Calculate speed, distance or time using the formula d = st, distance equals speed times time.
Calculate speed, distance or time using the formula d = st, distance equals speed times time.
You can use this formula for any question like this
Which piece of evidence suggests that the inner planets were formed from the same rotating cloud of gas and dust?
The piece of evidence that suggests that the inner planets were formed from the same rotating cloud of gas and dust is that the planets orbit the sun in the same direction and in the same plane
Smaller planets like Mercury, Venus, Earth, and Mars are considered inner planets. Mercury is thought to be the smallest inner planet, with Earth being the largest. The vastly larger outer planets, such as Jupiter, Saturn, Uranus, and Neptune, are the opposite.
A route that an object or planet in space follows around another body is referred to as an orbit. Moons are satellites that orbit many planets. A man-made satellite is also possible, such as the International Space Station.
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What are forces? (Check all that apply)
-Push or pull
-An action that has the ability to change potion
-Actions that can increase or decrease the speed of a moving object
-Actions that can change the direction in which an object is moving
-Gravity
-Electromagnetic
-Strong Nuclear Force
-Weak Force
-Matter
Answer:
Push or Pull
Gravity
Strong Nuclear Force
Weak Force
Explanation:
why are some small jovian planet moons geologically active?
Answer:
tidal heating and/or their composition
Explanation:
7. Explore how frequency affects wavelength. Use the following settings and measure the approximate
wavelength. Pause the simulation after a few waves pass and use the ruler.
Amplitude
Wavelength
0.75 cm
0.75 cm
0.75 cm
0.75 cm
Frequency
1.40 Hz
1.80 Hz
2.10 Hz
2.40 Hz
Based on the information, as the frequency increases, the wavelength decreases.
How to explain the informationAs the frequency increases, the wavelength decreases. This is because the frequency of a wave is the number of waves that pass a given point in a given time.
The wavelength is the distance between two consecutive crests or troughs of a wave. So, if the frequency increases, the number of waves that pass a given point in a given time increases, and the distance between the waves decreases.
You can also see this relationship mathematically. The equation for the wavelength of a wave is:
wavelength = speed of wave / frequency
The speed of a wave is constant, so if the frequency increases, the wavelength must decrease.
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A team of scientists wants to conduct a study on an endangered animal inthe wild. Which rule should the study follow in order to be considered ethical?
A. The scientists will promote the study on their personal websites.
B. The animals will not be harmed during the study.
C. The study will gather data over a long period of time.
D. The study will answer a question that has never been investigated.
Answer:
imma have to say C I'm not sure tho
A 25.0 kg door is 0.925 m wide. A customer
pushes it perpendicular to its face with a 19.2
N force, and creates an angular acceleration
of 1.84 rad/s2. At what distance from the axis
was the force applied?
[?] m
Hint: Remember, the moment of inertia for a panel
rotating about its end is I = mr².
The distance from the axis of the force applied is 2.05 m.
What is the distance from the axis of the force applied?The distance from the axis of the force applied is calculated as follows;
The formula for torque;
τ = Fr
where;
F is the applied forcer is the distance from the axis of the force appliedAnother formula for torque is given as;
τ = Iα
where;
I is the moment of inertia of the doorα is the angular acceleration;τ = (mr²)α
τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)
τ = 39.36 Nm
The distance is calculated as;
r = τ/F
r = ( 39.36 Nm ) / (19.2 N)
r = 2.05 m
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if the north pole of one magnetic is brought near the south pole of another magnet, the poles will
Answer: Heyo Kenji Here! Here's your answer-If the north pole of a magnet is brought near the south pole of another magnet, they will get attracted towards each other.
Explanation: Hope this helps!
Have a nice day!
- Kenji ^^
Answer:
If the north end of a magnet is brought near the south end of another magnet, they will get attracted towards each other. Remeber oppsites attrcat. The same repeal.
Explanation:
Hope This Helps
Have A Great Day
~Zero~
All of the following are basic components of a masonry woodburning fireplace except
A)
a throat.
B)
a heat circulator.
C)
a smoke shelf.
D)
a damper.
tartaric acid is present in spinach true or false
Answer:
falseExplanation:
because Oxalic acid is present in spinach
MARK ME AS BRAINLISTWhich statement is TRUE? Question 5 options: Waves travel at different speeds through different materials. Wave speed depends on the amplitude of the wave. Light waves and sound waves travel at a constant speed; the type of material they travel through does not affect the speed. None of the above are true.
Answer:
Waves move through different vmaterials
A: Waves travel at different speeds through different materials.
How much energy (in joules) does a photon of wavelength 757.7 nm have? (Enter your answ 1.23 x 10-4, you would enter 1.23e-4).
What is the frequency (in Hz) of light that has a wavelength of 110.9 nm
Answer:
E = h ν = h c / λ
E = (6.63E-34 J-s * 3.00E8 m/s) / 757.7E-9 m
E = 2.62E-19 J
Note 1 eV = 1.60E-19 J
ν = c / λ = 3.00E8 / 110.9E-9 = 2.71E15 / sec
How much energy (in joules) does a photon of wavelength 757.7 nm have.The energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. The energy of a photon is given by the formula: E = hc/λwhere E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.
Substituting the given values, we get: E = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(757.7 x 10^-9 m)E = 2.61 x 10^-19 JTherefore, the energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. What is the frequency (in Hz) of light that has a wavelength of 110.9 nm The frequency of light with a wavelength of 110.9 nm is 2.70 x 10^15 Hz. The frequency of light is given by the formula:f = c/λwhere f is the frequency, c is the speed of light, and λ is the wavelength of the light.
Substituting the given values, we get:f = (3.00 x 10^8 m/s)/(110.9 x 10^-9 m)f = 2.70 x 10^15 Hz Therefore, the frequency of light with a wavelength of 110.9 nm is 2.70 x 10^15 Hz. How much energy (in joules) does a photon of wavelength 757.7 nm have.The energy of the photon with a wavelength of 757.7 nm is 2.61 x 10^-19 J. The energy of a photon is given by the formula: E = hc/λwhere E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.
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Drag each label to the correct location on the table. Sort the sentences based on whether they describe radio waves, visible light waves, or both. They have colors. They can travel in a vacuum. They have energy. They’re used to learn about dust and gas clouds. They’re used to find the temperature of stars. They’re invisible.
Based on the given sentences, let's sort them into the correct categories: radio waves, visible light waves, or both.
Radio waves:
- They're used to learn about dust and gas clouds.
Visible light waves:
- They have colors.
- They're used to find the temperature of stars.
Both radio waves and visible light waves:
- They can travel in a vacuum.
- They have energy.
- They're invisible.
Sorted table:
| Radio Waves | Visible Light Waves | Both |
|----------------------|----------------------|----------------------|
| They're used to learn about dust and gas clouds. | They have colors. | They can travel in a vacuum. |
| - | They're used to find the temperature of stars. | They have energy. |
| - | - | They're invisible. |
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A cart is pushed on a frictionless floor with 29.6 Newtons of force along a distance of 5.9 meters in 8.1 seconds. How much power is exerted
during this time period?
Answer:
Power = 21.6 Watts
Explanation:
Power = \(\frac{W}{t}\)
Where W = work and t = time.
W = Fs
Where F is force and s is displacement.
29.6N(5.9m) = 174.64J
W = 174.64J
Power = \(\frac{174.64J}{8.1s}\)
Power = 21.6 Watts
10. John has borrowed his parents car without permission and is driving without a license. He
sees them out walking and realizes that they will be home in about 45 seconds. He is 500 m
from home and driving 25 m/s. Will he get to the driveway before they do?
What does it mean to be in equilibrium? What must be true?
What process causes water to move from earth's surface to the atmosphere during the water cycle?
The process that causes water to move from Earth's surface to the atmosphere during the water cycle is called evaporation.
Evaporation is the process by which water molecules absorb energy from the surrounding environment, typically in the form of heat, and transform from a liquid state to a gaseous state (water vapor). The water molecules then rise up into the atmosphere, where they can form clouds and participate in other processes in the water cycle, such as condensation, precipitation, and surface runoff. Evaporation occurs primarily from bodies of water, such as oceans, lakes, and rivers, but also from soil, plants, and other surfaces that contain moisture.
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Determine the molar mass of a gas if the volume of 0.05 g of the gas is 50cc at 27°c and 76 cm Hg pressure.
A car is stationary. It accelerates at 0.8 ms^2
for 10 s and then at 0.4 ms^2
for a further 10 s. Use
the equations of motion to deduce the car’s final displacement. You will have to split the journey
into two parts, since the acceleration changes after 10 s.
Answer:
the car’s final displacement is 60 m
Explanation:
Given;
initail velocity of the car, u = 0
acceleration of the car, a = 0.8 m/s²
time of motion, t = 10 s
The first displacement of the car:
\(x_1 = ut + \frac{1}{2} at^2\\\\x_1 = 0 + \frac{1}{2} (0.8)(10)^2\\\\x_1 = 40 \ m\)
The second displacement of the car;
acceleration, a = 0.4 m/s², time of motion, t = 10 s
\(x_2 = ut + \frac{1}{2} at^2\\\\x_2 = 0 + \frac{1}{2} (0.4)(10)^2\\\\x_2 = 20 \ m\)
The final displacement of the car;
x = x₁ + x₂
x = 40 m + 20 m
x = 60 m
Therefore, the car’s final displacement is 60 m
Define ELASTIC LIMIT, YIELD POINT AND ULTIMATE TENSILE STRENGTH?
\( \green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}} \)
ELASTIC LIMIT, YIELD POINT AND ULTIMATE TENSILE STRENGTH.
\( \orange{\underline{\huge{\bold{\textit{\green{\bf{TOPIC}}}}}}} \)
Mechanical Properties Of Solid.
\( \huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}\)
\( \bold{ \green{PART \: \: (1):-}} \\ \bold \green {{ ELASTIC \: \: LIMIT}}\)
It is also called yield point
In this limit, energy provided to the material to cause deformation when removed then the material returns to its own shape and size.
In this limit each body shows elastic nature
\( \bold{ \red{PART \: \: (2):-}} \\ \bold \red {{YIELD \: \: STRENGTH}}\)
It is the fix amount of the energy which causes fixed permanent set of deformation.
In this body shows plastic deformation.
The level of stress that corresponds to the yield point is referred to as the yield strength of the material.
\(\bold{ \purple{PART \: \: (3):- \:ULTIMATE }} \\ \bold \purple {{TENSILE \: \: STRENGTH}}\)
It is the amount of the stress which causes permanent set of deformation after the yield point.
Body show perfect plastic deformation.
This shows a permanent set of deformation.
\( \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star\)
In Concept Simulation 10.2 you can explore the concepts that are important in this problem. Astronauts on a distant planet set up a simple pendulum of length 1.20 m. The pendulum executes simple harmonic motion and makes 100 complete oscillations in 370 s. What is the magnitude of the acceleration due to gravity on this planet
The magnitude of the acceleration due to gravity on this planet is 3.470 m/s².
The time period for a simple pendulum performing simple harmonic motion is given by
T = 2π√(l/g)
where T = time period in s,
l = length of the string of simple pendulum, and
g = acceleration due to gravity at the place of the simple pendulum
Given: the length of the pendulum, l = 1.20 m.
the time period of the pendulum, T = 370/100 s= 3.7 s
using the equation of time period, acceleration due to gravity
g = l/(T/2π)² = 1.20/(3.7/2π)² = 3.470 m/s²
Therefore, the magnitude of the acceleration due to gravity on this planet is 3.470 m/s².
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A ballet dancer whose weight is 60 kg performs a move on one foot during which she
applies a pressure of 1,500,000 Pa on the ground. Is she likely to be standing with her foot
flat on the ground, or is she on tiptoe?
She is likely to have tip toed as the pressure applied is high.
What is pressure?Pressure is a force per unit area, typically measured in units of Pascal (Pa), atmospheres (atm), or pounds per square inch (psi). It is the result of the force exerted by a gas or liquid against a surface.
We have to note that the pressure that has a value of about 1,500,000 Pa is quite a large pressure and we can only have such a pressure when we have a small surface area upon which the pressure have been applied.
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The cart and its load have a total mass of 100 kg and center of mass at G. Determine the acceleration of the cart and the normal reactions on the pair of wheels at A and B. Neglect the mass of the wheels 100 N 1.2 m 0.5 m 0.3 m 0.4m 0.6 m The 100 kg wheel has a radius of gyration about its center O of ko-500 mm. If the wheel starts from rest, determine its angular velocity in t-3s.
The acceleration of the cart is 1.962 m/s^2, and the angular velocity of the wheel after 3 seconds is 11.772 rad/s.
To solve this problem, we need to find the net force acting on the cart and its acceleration using the principle of linear momentum. Then, we can use the principle of angular momentum to find the angular velocity of the wheel.
First, we find the center of mass of the cart and its load. Using the formula for the center of mass,
xG = (m1*x1 + m2*x2 + m3*x3 + m4*x4 + m5*x5) / (m1 + m2 + m3 + m4 + m5)
= (100*0 + 100*1.2 + 100*0.5 + 50*0.3 + 50*0.4) / 300
= 0.7 m
Next, we can find the net force acting on the cart by analyzing the forces acting on it. We have the weight of the system acting downwards, and the normal forces at A and B acting upwards. Since the cart is not accelerating vertically, the net force in the y-direction must be zero. Therefore, the normal forces at A and B are equal to the weight of the system, which is:
N = 1000 N
To find the net force in the x-direction, we use the principle of linear momentum:
F_net = m*a_G
= 100*a_G
where a_G is the acceleration of the center of mass. Since the forces acting in the x-direction are the force of friction acting backwards, and the force of tension in the rope acting forwards, we have:
F_net = T - f
where T is the tension in the rope, and f is the force of friction. Since the wheel is rolling without slipping, we have:
f = (1/2)*m*g
where g is the acceleration due to gravity. Also, the tension T is equal to:
T = m*a
where a is the linear acceleration of the wheel.
Using the principle of rotation, we have:
I*alpha = T*r
where I is the moment of inertia of the wheel about its center of mass, alpha is the angular acceleration, and r is the radius of the wheel. Since the wheel starts from rest, its initial angular velocity is zero, and we can use the equation:
omega = alpha*t
to find the angular velocity after time t.
Substituting the given values, we have:
I = m*k^2
= 100*(0.5)^2
= 25 kg*m^2
r = 0.5 m
f = (1/2)*m*g
= (1/2)*100*9.81
= 490.5 N
T = m*a
F_net = T - f
= m*a - (1/2)*m*g
F_net = m*a_G
= 100*a_G
I*alpha = T*r
omega = alpha*t
Substituting T and alpha from the above equations, we get:
m*a*r = m*a - (1/2)*m*g
I*alpha = m*a*r
omega = alpha*t
Solving these equations, we get:
a = 1.962 m/s^2
alpha = a/r = 3.924 rad/s^2
omega = alpha*t = 11.772 rad/s
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The cart and its load have a total mass of 100 kg with the center of mass at G. To determine the acceleration of the cart and the normal reactions on the pair of wheels at points A and B, we need to consider the forces acting on the system.
Since the cart's total weight is 100 kg and the gravitational force acting on it is 9.81 m/s², the weight W can be calculated as W = mass × gravity, which is W = 100 kg × 9.81 m/s² = 981 N. This force is acting vertically downwards at the center of mass G. Next, we need to consider the normal reactions on the pair of wheels at A and B. Let NA and NB represent the normal reactions at points A and B, respectively. These forces act vertically upwards, and for the cart to be in equilibrium, the sum of the forces in the vertical direction should be zero. Thus, NA + NB = W = 981 N. To determine the acceleration of the cart, we would need additional information about the forces acting in the horizontal direction, such as friction or an applied force. Without this information, it's not possible to calculate the acceleration of the cart. Regarding the 100 kg wheel with a radius of gyration (kO) of 500 mm, if it starts from rest, we need to determine its angular velocity after 3 seconds (t = 3s). However, we cannot calculate the angular velocity without knowing the torque or angular acceleration acting on the wheel. Additional information is needed to solve this part of the problem.
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A standardized biological microscope has an 4.0-mm-focal-length objective. What focal-length eyepiece should be used to achieve a total magnification of 200X? Express your answer to two significant figures and include the appropriate units..
The focal-length eyepiece should be used to achieve a total magnification of 200 is -5 cm.
focal length of object f₀ = 4 × 10⁻³ m
focal length of eyepiece fe
length L= 160 × 10⁻³ m
distance of closest distinct vision ( D=usually 250 mm)
magnification M = 200
fe= (-L / f₀ ) × (D/M)
=(-160 × 10⁻³ / 4× 10⁻³) × (250 × 10⁻³ /200)
fe = -0.05m = - 5cm
Focal Length eyepiece:An eyepiece focal length is the distance from its principal plane to a single point where parallel light rays converge. At the point when being used, the central length of an eyepiece, joined with the central length of the telescope or magnifying instrument objective, to which it is connected, decides the amplification.
What effects does eyepiece focal length have?An image with a shorter focal length will be smaller, while an image with a longer focal length will be larger. The image is then magnified using the eyepiece, just like a microscope. A bigger picture to begin with will permit the eyepiece to deliver a higher amplification.
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What is the effect of increase in heat on:
1. Plastic
2. Iron
Explanation:
1.Plastic
Thermal Degradation – Plastic materials subjected to prolonged exposure to high temperatures will lose strength and toughness, becoming more prone to cracking, chipping, and breaking, at a rate in proportion to the temperature and time of exposure.
2.Iron
At room temperature, the iron atoms are in an unusual loosely packed open arrangement; as iron is heated past 912 degrees Celsius, the atoms become more closely packed before loosening again at 1,394 degrees Celsius and ultimately melting at 1,538 degrees Celsius
what is the formula for converting frequency to approximate wavelength in meters?
The formula for converting frequency (f) to approximate wavelength (λ) in meters is given by:
λ ≈ c / f
where:
λ is the wavelength in meters,
c is the speed of light in meters per second (approximately 3 x 10^8 m/s), and
f is the frequency in hertz (Hz).
This formula relates the wavelength of a wave to its frequency and the speed at which the wave propagates. The speed of light in a vacuum is a constant value, so as the frequency increases, the wavelength decreases, and vice versa.
It's important to note that this formula provides an approximation and assumes that the wave is traveling through a vacuum or a medium with a constant refractive index. In different mediums, the speed of light may vary, which would affect the precise relationship between frequency and wavelength.
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Calculate the total displacement of a mouse walking along a ruler, if it begins at the location x = 5 m, and then does the following:
- It walks to x = 12 m
- It then walks a displacement of -8 m (NOT the same as x = -8 m)
- Lastly, it walks to the location x = 7 m
Answer:
18
Explanation:
12 - 5 + 8 = 15
12 - 8 = 4
7 - 4 = 3
15 + 3 = 18