add each element in origlist with the corresponding value in offsetamount. print each sum followed by a space. ex: if origlist

Answer:

4.2019 mts , 4.598 mts

Explanation:

center of flotation = 2 m fwd.

MCTC = 120 tonnes

Determine the position of  200 t of cargo to be loaded

first step : determine the change trim = trimming moment / MCTC

                                                              = 134 * 1 / 120 = 0.11 mts

∴ бtf = 0.11 * ( 2/100 ) = 0.0022 mts ( given that the ship trims forward )

бtf = - 0.0022 mts

also ; бTa = 0.0019 mts (  + due to increase in draught )

determine the Final position

Ta = 4.2 ( draught at AP )  + бTa

     = 4.2 +  0.0019

     = 4.2019 mts

T\(_{f}\) = 4.6 ( draught at Fp )  + бtf

                                = 4.6 + ( - 0.0022 )  = 4.598 mts

Answer:

Total distributed load on BE = 5 m²

Explanation:

The first process is to get the value for the Dead load (DL) on the slab;

This is determined by using the formula:

DL = ρ × t

DL = 23.6 kK/m³ × 0.2 m

DL = 4.72 kN/m²

From table 1.4 which relates to the office buildings, we derive the value for the minimum live load (LL) = 2.40 kN/m³

Hence the total load TL = Dead Load DL) + Live loaf (LL)

DL = (4.72 + 2.40) kN/m³

DL = 7.12 kN/m³

Now; from the imaginative view of the information given; the member BE which get the load from half area of the panel BEDC & half the area of BEFA panel parallel to member BE; then the tributary area on member BE can be calculated as;

\(A_{BE} = ( \dfrac{a}{2}+\dfrac{a}{2}) \times width\)

\(A_{BE} = ( \dfrac{2}{2}+\dfrac{2}{2}) \times 1\)

\(A_{BE} =2\times 1\)

\(A_{BE} =2 m^2/m\)

The total distributed load acting on BE is:

\(Total \ load = TL \times A_{BE}\)

\(Total \ load = 7.12 \ \dfrac{kN}{m^2 }\times (2 \times \dfrac{m^2}{m})\)

Total load = 2.5 × 2

Total load = 5 m²

The control used to change the shape of the output wave is called an oscillator.

Within an oscillator, there are various types of controls that can be used to manipulate the output waveform. For example, a potentiometer can be used to adjust the resistance in the oscillator circuit, which can affect the amplitude and shape of the output wave. Additionally, capacitors can be used to alter the frequency and shape of the output waveform by changing the rate at which the oscillator circuit charges and discharges. Overall, the specific control used to change the shape of the output wave depends on the type of oscillator circuit being used and the desired waveform characteristics.

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Companies like Tesla use key performance indicators (KPIs) to quantify whether individuals are on the right track for achieving strategic objectives. So, option C is accurate.

Key performance indicators are measurable metrics that organizations use to evaluate and monitor progress towards their goals. These indicators provide valuable insights into the performance and effectiveness of different aspects of the business. By defining and tracking KPIs, companies like Tesla can assess the performance of individuals and teams, identify areas for improvement, and ensure alignment with strategic objectives.

While advanced data analytics and frequent meetings may also play a role in evaluating performance and progress, key performance indicators are specifically designed to provide a quantifiable and objective measure of success. They allow companies to assess performance consistently and make data-driven decisions to drive improvement and achieve strategic objectives.

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The horizontal sections of a steel frame are known as the B: i-beams.

I-beam is a kind of structural steel used in buildings, also called H, W, wide, universal beam, or roll beam. I-beams play an important role as the supporting links of the structure. These beams can withstand different types of loads.

I-beams are frequently utilized to build beams and columns in a range of dimensions and specifications. It is vital for civil engineers and foremen to understand the necessity of i-beams in steel structures.

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Answer:

Get ready and comfortable.

List all of the tasks you need to accomplish over the next week. .

Next schedule everything.

Get a planner/calender.

Cut those tasks that do not fit into your

The distance to the highest point of the vertical curve (from the BVC) is 25 m and the elevation at that point is 403.33 m.

1. The following information is given: Angle of intersection between the tangents = 30°Design speed = 100 km/hPI = station(524+12)e = 0.06f = 0.15Whole stations are located at 30-m intervals. To determine the stations at PC and PT:Using the horizontal alignment formula, we can calculate the radius as follows:R = V²/127eR = 100²/127*0.06R = 1042.91 mNow, using the station formula, we can determine the station at PC as follows:Δ = 30/cos 30° = 34.64 mStation at PC = 524+12 - Δ/2 = 523+54.68/2 = 523+27.34 = 523+27.3 mSimilarly, we can calculate the station at PT as follows:Station at PT = 524+12 + Δ/2 = 525+54.68/2 = 525+27.34 = 525+27.3 mTo determine the first and second deflection angles and the length between the PC and the first whole station:Using the following formulas, we can calculate the first deflection angle:θ1 = 180°/π * Δ/Rθ1 = 180/π * 34.64/1042.91θ1 = 1.17°Similarly, we can calculate the second deflection angle as follows:θ2 = 180°/π * Δ/Rθ2 = 180/π * 34.64/1042.91θ2 = 1.17°Finally, we can calculate the length between the PC and the first whole station as follows:L = R * tan(θ1/2)L = 1042.91 * tan(1.17/2)L = 10.32 m2. The following information is given:Length of the crest vertical curve = 200 mGradient at the BVC = +5%Gradient at the EVC = -3%Elevation at the BVC = 420 mTo find the elevations of the PVI and EVC:Using the following formulas, we can calculate the elevations of the PVI and EVC:Δ = L/2 * (G2 - G1)/1000Δ = 200/2 * (-3 - 5)/1000Δ = -0.8 mPVI = BVC + ΔPVI = 420 - 0.8PVI = 419.2 mEVC = PVI + L * G2/100EVC = 419.2 + 200 * (-3)/100EVC = 413.2 mTo calculate the distance to the highest point of the vertical curve (from the BVC) and the elevation at that point:Using the following formula, we can calculate the elevation at the highest point of the vertical curve:Δy = L² * (G2 - G1)/24L = 200, G1 = 5%, and G2 = -3%Δy = 200² * (-3 - 5)/24Δy = -1666.67 m Elevation at the highest point = BVC + ΔyElevation at the highest point = 420 - 1666.67/100Elevation at the highest point = 403.33 m Using the following formula, we can calculate the distance to the highest point of the vertical curve:Δx = L² * f/24Δx = 200² * 0.15/24Δx = 25 m

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Answer:

10 ohms Ω

Explanation:

V = IR

120 = I(12)

120/12 = 10Ω

Assuming that cell B5 contains the sales amount for the first salesperson, the IFS function to determine the commission rate in cell C5 is:

=IFS(B5>35000, 0.05, B5>25000, 0.04, B5>0, 0.02)

This formula checks the sales amount in B5 against each threshold amount in descending order (starting with $35,000), and returns the corresponding bonus rate if the sales amount is greater than that threshold. If the sales amount is less than or equal to zero, it returns a bonus rate of 0%.

To fill the formula down through cell C8, select cell C5 and drag the fill handle down to cell C8. This will copy the formula to the other cells in the group, adjusting the cell references as needed.

Based on the use of the moral principle of Immanuel Kant and deontology, the way that the mother lie in court for the sake of love is one that is not morally justified or right.

Kant's moral philosophy is said to be one that capitalizes on the principle of universalizability, and it is one that states that we as humans need to only act based to principles that we can overtime will to be universal laws.

In conclusion, I can say that the action of the mother when she lie in court for the sake of love is very wrong and morally justified or right when viewed in Kant's moral philosophy or deontology.

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For displaying two or three quantities related to material properties and plotting each quantity along an axis, a three-dimensional scatter plot would be suitable.

A three-dimensional scatter plot allows for the visualization of data points in a three-dimensional space, with each quantity represented along its corresponding axis. In this case, the team can plot one quantity on the x-axis, another on the y-axis, and if necessary, a third quantity on the z-axis.

By using a three-dimensional scatter plot, the team can observe the relationships and patterns between the material properties across multiple dimensions. It provides a more comprehensive view of the data by incorporating the additional quantity along the z-axis, which adds depth to the plot.

This type of plot is particularly useful when there is a need to analyze the interactions and dependencies between multiple material properties simultaneously. It allows for a better understanding of how the variables relate to each other in a three-dimensional space.

Additionally, the team can explore various visualization techniques within the three-dimensional scatter plot, such as color-coding or size-adjustment of the data points, to represent additional information or attributes related to the material properties.

It's important to note that the suitability of a scatter plot depends on the specific characteristics of the data and the research questions being addressed. The team should carefully consider the nature of their data and the insights they want to extract to determine if a three-dimensional scatter plot is the most appropriate visualization method for their specific needs.

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ANSWER :

325

Explanation:

313 + 12 = 325

A modern fire pump must be able to run at 150% of its rated flow while maintaining a minimum of 65% of its rated pressure in order to comply with the NFPA standard for fire pumps, specifically NFPA 20.

This fire pump's capacity must be sufficient to defend these areas when two jets of water from fire hoses with 19 mm nozzles are supplied simultaneously at a minimum pressure of 0.5 MPa.

A typical home pipe system operates between 30 and 80 psi. Although you don't want the psi to be too high, it is against the law to have it above 80. Instead, you should strive for a psi of 60 to 70.

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The values are:

1. Gain with feedback (A_f) = 20

2. Output voltage (V_out) = 1V

3. Feedback factor (B_f) = 0.008

4. Feedback voltage (V_f) = 0.008V

To calculate the values in the given negative feedback amplifier, we can use the following formulas:

1. Gain with feedback (A_f):

  A_f = A / (1 + A * B)

  A_f = 100 / (1 + 100 * 0.04)

  A_f = 100 / (1 + 4)

  A_f = 100 / 5

  A_f = 20

2. Output voltage (V_out):

  V_out = A_f * V_1

  V_out = 20 * 50mV

  V_out = 1V

3. Feedback factor (B_f):

  B_f = B / (1 + A * B)

  B_f = 0.04 / (1 + 100 * 0.04)

  B_f = 0.04 / (1 + 4)

  B_f = 0.04 / 5

  B_f = 0.008

4. Feedback voltage (V_f):

  V_f = B_f * V_out

  V_f = 0.008 * 1V

  V_f = 0.008V

Therefore, the values are:

1. Gain with feedback (A_f) = 20

2. Output voltage (V_out) = 1V

3. Feedback factor (B_f) = 0.008

4. Feedback voltage (V_f) = 0.008V

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Thus external torque is -146.76 Nm and it is clockwise

Scalar moment = load × moment arm

Load acting on the body is due to HAT and object

External torque on joint is

[(HAT load) × (HAT moment arm)] + [(object load) × (object moment arm)]

(both moments are in clockwise direction)

Or external torque = -[(333 × 0.22) + (245 × 0.3)] = -146.76 Nm

Thus external torque is -146.76 Nm and it is clockwise.

This is so because the force and speed of the pistons' motion determine the torque. High levels of this torque force can be produced by the fastest cars at relatively low rpm. This enables speedy acceleration of the vehicle. The definition of torque is rF=rFsin(r). In other terms, torque is the cross product of the force vector and the distance vector, where 'a' is the angle between r and F. The distance vector represents the distance from the pivot point to the place where force is applied.

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When the acceleration is zero or the speed is constant, instantaneous and average velocities can both be equal. This is because all instantaneous velocities will be equal in this situation.

After the control filter and display filter have been applied, the filtered value that remains is known as the Actual Velocity. The Actual Velocity (Unfiltered) status register provides the unfiltered value, and the Actual Velocity (Control) value provides the first filtered value.

To calculate the velocity, multiply the distance travelled by the time needed to traverse that distance, then add direction. If one's position doesn't change, their velocity is zero.

Velocity is essentially a vector quantity. It is the rate of change in distance. The displacement change rate is the issue. A moving object can never move more slowly than it is moving. An object in motion can move at zero velocity.

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C. Capacity: The rate at which a process can serve customers per a given time period

Many small manufacturers are not aware of their true output capacity. They frequently have a rough estimate but cannot offer any supporting information. This is troubling because a lot of important business decisions are influenced by the company's manufacturing capacity. Decisions based on estimations, however, are never as good as those based on straightforward facts.

The greatest output that a manufacturing business is capable of creating is measured by its production capacity, which is stated in units of output per period. You can deliver more accurate lead times, improve production planning and scheduling, and forecast your cash flow by being aware of your production capacity.

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Answer:

answer is B

Explanation:

Answer:

When two fair dice are rolled, 6×6=36 observations are obtained.

P(X=2)=P(1,1)=

36

1

​

P(X=3)=P(1,2)+P(2,1)=

36

2

​

=

18

1

​

P(X=4)=P(1,3)+P(2,2)+P(3,1)=

36

3

​

=

12

1

​

P(X=5)=P(1,4)+P(2,3)+P(3,2)+P(4,1)=

36

4

​

=

9

1

​

P(X=6)=P(1,5)+P(2,4)+P(3,3)+P(4,2)+P(5,1)=

36

5

​

P(X=7)=P(1,6)+P(2,5)+P(3,4)+P(4,3)+P(5,2)+P(6,1)=

36

6

​

=

6

1

​

P(X=8)=P(2,6)+P(3,5)+P(4,4)+P(5,3)+P(6,2)=

36

5

​

P(X=9)=P(3,6)+P(4,5)+P(5,4)+P(6,3)=

36

4

​

=

9

1

​

P(X=10)=P(4,6)+P(5,5)+P(6,4)=

36

3

​

=

12

1

​

P(X=11)=P(5,6)+P(6,5)=

36

2

​

=

18

1

​

P(X=12)=P(6,6)=

36

1

​

Therefore, the required probability distribution is as follows.

Then, E(X)=∑X

i

​

⋅P(X

i

​

)

=2×

36

1

​

+3×

18

1

​

+4×

12

1

​

+5×

9

1

​

+6×

36

5

​

+7×

6

1

​

+8×

36

5

​

+9×

9

1

​

+10×

12

1

​

+11×

18

1

​

+12×

36

1

​

=

18

1

​

+

6

1

​

+

3

1

​

+

9

5

​

+

6

5

​

+

6

7

​

+

9

10

​

+1+

6

5

​

+

18

11

​

+

3

1

​

=7

E(X

2

)=∑X

i

2

​

⋅P(X

i

​

)

=4×

36

1

​

+9×

18

1

​

+16×

12

1

​

+25×

9

1

​

+36×

36

5

​

+49×

6

1

​

+64×

36

5

​

+81×

9

1

​

+100×

12

1

​

+121×

18

1

​

+144×

36

1

​

=

9

1

​

+

2

1

​

+

3

4

​

+

9

25

​

+5+

6

49

​

+

9

80

​

+9+

3

25

​

+

18

121

​

+4

=

18

987

​

=

6

329

​

=54.833

Then, Var(X)=E(X

2

)−[E(X)]

2

=54.833−(7)

2

=54.833−49

=5.833

∴ Standard deviation =

Var(X)

​

=

5.833

​

=2.415

Answer:

sorry di ko alam

Explanation:

️‍♀️️‍♀️

Answer:

Make sure both cars are in park or neutral with the parking brake engaged. This makes sure that all electrical functions (headlights, radios, etc.) are turned off.

When jump starting a car, make sure it is in the right distance of the cables to reach battery.

Thus, when jump-starting a car, always remember the cables are in the right position.

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The fence height, additional structures, and architectural design are generally categorized under covenants.

The primary private land-use control is known to be a form of a deed restrictions, that hinders what a person can do on the property as regards to the owner.

Note that in the case above, the fence height, additional structures, and architectural design are generally categorized under covenants.

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The pace at which a material heat up by conduction via a certain unit area is known as thermal conductivity. In general, the rate of heat transfer increases with increasing thermal conductivity and vice versa.

The property of a substance that directly relates to its capacity to transport heat is known as thermal conductivity (). Conduction is the process of transferring energy within a substance without the material itself moving.

Therefore, A crucial factor is thermal conductivity, since it determines temperature gradients both during material growth and inside of devices.

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The correct answer is b. When traffic volumes are highest.

A tunnel requires its highest level of lighting when traffic volumes are highest to ensure safe passage for drivers. This is because high traffic volumes lead to reduced visibility due to the buildup of exhaust fumes, dust, and other pollutants in the tunnel. These pollutants can absorb or scatter the light, making it difficult for drivers to see clearly. Therefore, a higher level of lighting is required to compensate for the reduced visibility and ensure safe driving conditions.
However, it is important to note that lighting requirements may vary depending on the specific location, length, and design of the tunnel. Factors such as the width of the tunnel, curvature, gradient, and the presence of other structures or obstacles can affect lighting needs. For example, a shorter tunnel with minimal curves and gradients may require lower lighting levels than a longer tunnel with more complex design features.

In summary, the highest level of lighting in a tunnel is required when traffic volumes are highest to ensure safe passage for drivers. However, lighting requirements may vary depending on specific tunnel characteristics.

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Answer:

SpaceX

Explanation:

SpaceX successfully launches 60 more Starlink satellites as it continues towards 2020 service debut. SpaceX has launched another big batch of Starlink satellites, the low Earth orbit spacecraft that will provide connectivity for its globe-spanning high-bandwidth broadband internet network.

Based on the maximum applied load, the factor of safety, and the distance between the loadbearing points, the minimum allowable bar diameter is 18.6 mm.

The diameter is included in the following formula:

Maximum stress / Factor of safety = (16 x Maximum applied load x distance between loadbearing points x 10⁻¹⁰) / (π x diameter³)

Solving gives:

(490 x 10⁶) / 2.25 = (16 x 5,000 x 55.0 x 10⁻¹⁰) / (π x diameter³)

217,777,777.78 = 0.00044 /  (π x diameter³)

diameter = 18.6 mm

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Answer:

A hammer and a wrench

Explanation:

Let's start by redrawing the circuit and annotating the resistors with voltage polarities.

Voltage, also known as electric potential difference, it is a measure of electric potential energy per unit charge in anelectric circuit. It represents the force that drives the flow of electric charge in a circuit. Voltage is typically measured in volts (V), and is denoted by the symbol "V".

 10V

     +

     |

    R1

     |

     +-------+----- va

     |       |

    R2      R3

     |       |

     +-------+----- vb

     |

    R4

     |

     -

     0V

Since there is a voltage source connected to the circuit, we will choose the negative terminal of the voltage source as our reference node and assign it a voltage of 0V. The node voltages for nodes va and vb will be defined as V_a and V_b, respectively.

10V

     +

     |

    R1

     |

     +-------+----- V_a

     |       |

    R2      R3

     |       |

     +-------+----- V_b

     |

    R4

     |

     -

     0V

we will use Ohm's Law and the fact that the current flowing through a resistor is proportional to the voltage across it.

At node va, there are three currents to consider: the current flowing through R1, the current flowing through R2, and the current flowing out of va towards vb. Using Ohm's Law and the fact that the current flowing through a resistor is proportional to the voltage across it, we can write:

I_R1 = (V_a - 10) / R1

I_R2 = V_a / R2

I_out = (V_a - V_b) / R3

At node vb, there are also three currents to consider: the current flowing through R3, the current flowing through R4, and the current flowing into vb from va. We can write:

I_R3 = (V_b - V_a) / R3

I_R4 = V_b / R4

I_in = V_b / R3

we can write KCL at each unknown node using the equations for the current we determined in part c. At node va, the sum of currents going into the node must equal the sum of currents going out of the node:

I_R1 + I_R2 + I_out = 0

Substituting the expressions we derived for each current, we get:

(V_a - 10) / R1 + V_a / R2 + (V_a - V_b) / R3 = 0

Similarly, at node vb, we have:

I_R3 + I_R4 + I_in = 0

Substituting the expressions we derived for each current, we get:

(V_b - V_a) / R3 + V_b / R4 + V_b / R3 = 0

Finally, we can simplify the equations and solve for the node voltages. Multiplying each term by the least common multiple of the denominators to eliminate fractions, we get:

(R2*R3*(V_a-10) + R1*R3*V_a + R1*R2*(V_a-V_b)) / (R1*R2*R3) = 0

and

(V_a*R4*R3 + V_b*R4

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