An airplane moves 214 m/s as it travels around a vertical circular loop which has a radius of 1.8 km. What is the magnitude of the normal force on the 48 kg pilot of this plane at the bottom of this loop
Answers
An airplane moves 214 m/s as it travels around a vertical circular loop which has a radius of 1.8 km. The magnitude of the normal force on the pilot at the bottom of the loop is 4700 N.
To find the magnitude of the normal force on the pilot at the bottom of the loop, we need to consider the forces acting on the pilot. At the bottom of the loop, there are two main forces acting on the pilot: the gravitational force and the normal force.
The gravitational force is given by the formula F_gravity = m * g, where m is the mass of the pilot and g is the acceleration due to gravity (approximately 9.8 m/s^2).
The normal force is the force exerted by the surface (in this case, the seat) to support the weight of the pilot. At the bottom of the loop, the normal force will be directed upwards to counteract the gravitational force.
In this scenario, the pilot experiences an additional force due to the circular motion. This force is the centripetal force and is provided by the normal force. The centripetal force is given by the formula F_centripetal = m * a_c, where m is the mass of the pilot and a_c is the centripetal acceleration, which is v^2 / r, where v is the velocity of the airplane and r is the radius of the loop.
To find the normal force, we need to calculate the net force acting on the pilot in the vertical direction. At the bottom of the loop, the net force is the sum of the gravitational force and the centripetal force:
Net force = F_gravity + F_centripetal
The normal force is equal in magnitude but opposite in direction to the net force. So, the magnitude of the normal force at the bottom of the loop is:
Magnitude of normal force = |Net force| = |F_gravity + F_centripetal|
Substituting the given values, we have: m = 48 kg v = 214 m/s r = 1.8 km = 1800 m g = 9.8 m/s^2
F_gravity = m * g F_centripetal = m * (v^2 / r)
Net force = F_gravity + F_centripetal Magnitude of normal force = |Net force|
Plugging in the values and performing the calculations, we find that the magnitude of the normal force on the pilot at the bottom of the loop is 4700 N.
An airplane moves 214 m/s as it travels around a vertical circular loop which has a radius of 1.8 km The magnitude of the normal force on the 48 kg pilot at the bottom of the loop is 4700 N. This normal force is required to provide the necessary centripetal force for the pilot to move in a circular path.
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The magnitude of the normal force on the pilot at the bottom of the loop is 5275.2 N.
To determine the magnitude of the normal force on the pilot at the bottom of the loop, we need to consider the forces acting on the pilot. At the bottom of the loop, the pilot experiences two forces: the force of gravity (mg) and the normal force (N).
The force of gravity is given by the equation:
F_gravity = mg,
where m is the mass of the pilot and g is the acceleration due to gravity (approximately 9.8 m/s²).
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, it is the force exerted by the seat of the airplane on the pilot. At the bottom of the loop, the normal force will be directed upward and must be large enough to balance the downward force of gravity.
To determine the magnitude of the normal force, we need to consider the net force acting on the pilot at the bottom of the loop. The net force is the vector sum of the gravitational force and the centripetal force.
The centripetal force is provided by the normal force, given by the equation:
F_centripetal = m * v² / r,
where v is the velocity of the airplane and r is the radius of the loop.
At the bottom of the loop, the centripetal force must be equal to the gravitational force plus the normal force:
F_centripetal = F_gravity + N.
Plugging in the values, we have:
m * v² / r = mg + N.
Rearranging the equation to solve for N, we get:
N = m * v² / r - mg.
Now we can substitute the given values:
m = 48 kg (mass of the pilot),
v = 214 m/s (velocity of the airplane),
r = 1.8 km = 1800 m (radius of the loop),
g = 9.8 m/s² (acceleration due to gravity).
N = 48 kg * (214 m/s)² / 1800 m - 48 kg * 9.8 m/s².
Calculating this expression, we find:
N ≈ 5275.2 N.
The magnitude of the normal force on the 48 kg pilot at the bottom of the loop is approximately 5275.2 N
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Related Questions
A 3.00 kg crate is pulled along a frictionless surface with a force of 55.0 N at 25.00 to the
horizontal so that it accelerates directly to the right. What is the crate's acceleration?
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plsss helpp will give brainliest!!!
here are answer choices for ALL of the blanks! :)
-flexibility
-cardiovascular fitness
-muscular fitness
Answers
Answer:
1. Flexibility.
2. Muscular Fitness
3. Cardiovascular Fitness
4. Cardiovascular Fitness
5. Flexibility
6. Muscular Fitness
7. Cardiovascular Fitness
As discussed in the text, Annie Jump Cannon and her colleagues developed our modern system of stellar classification. Why do you think rapid advances in our understanding of stars folllowed so quickly on the heels of this effort? What othet areas of science have had huge advances in understanding following an improved system of classification?
Answers
The development of the modern system of stellar classification by Annie Jump Cannon and her colleagues allowed for a standardized and systematic categorization of stars based on their spectral characteristics. This classification system provided a solid foundation for studying and understanding stars, enabling researchers to identify patterns, analyze data more effectively, and make significant discoveries more efficiently.
The development of a systematic classification system for stars provided astronomers with a framework to organize and analyze observational data. By categorizing stars based on their spectral characteristics, such as temperature, luminosity, and composition, astronomers were able to identify patterns and correlations among different types of stars. This allowed for the formulation of theories and models that could explain the observed phenomena and properties of stars.
In biology, the Linnaean system of classification, which classifies organisms into hierarchical categories based on shared characteristics, greatly advanced our understanding of the diversity and relationships among different species. This classification system laid the foundation for the study of evolutionary biology and genetics.
In chemistry, the periodic table of elements, developed by Dmitri Mendeleev, revolutionized the field by organizing elements based on their atomic number and properties. This classification system enabled scientists to predict the existence and properties of yet-to-be-discovered elements and facilitated the understanding of chemical reactions and bonding.
In taxonomy, the development of modern classification systems for plants, animals, and other organisms has led to significant advances in understanding biodiversity, evolutionary relationships, and ecological interactions.
In summary, improved systems of classification in various scientific fields have accelerated our understanding by providing a systematic framework for organizing and analyzing data, identifying patterns, and facilitating the formulation of theories and models.
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What is the difference between speed and velocity?
Answers
Answer:
speed is the rate of change in distance thus it is scalar physical quantity
while velocity is the rate of change in displacement thus it is a vector physical quantity
Explanation:
vector physical quantity: is a quantity that requires both magnitude and direction to identify
scalar quantity: requires only magnitude to identify.
HELP ASAP
What happens when the mantle melts?
Answers
It produces oceanic crust,
Partial melting is an important process in geology with respect to the chemical differentiation of crustal rocks. On the Earth, partial melting of the mantle at mid-ocean ridges produces oceanic crust, and partial melting of the mantle and oceanic crust at subduction zones creates continental crust.
Albert has an impulse of 29 newton seconds and an impact time of 12 seconds.
What is the force experienced?
Your answer
Choose to complete either the abstract or the real world problem for the following
2 problems.
Answers
The force experienced, given the data from the question is 2.42 N
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed as
Momentum = mass × velocity
What is impulse?This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final moment – Initial momentum
Impulse = force × time
With the above formula for impulse (Impulse = force × time), we can determine the force experienced by Albert. Details below:
Data obtained from the questionFrom the question given above, the following data were obtained:
Impulse = 29 NsTime (t) = 12 sForce (F) =?How to determine the force experiencedThe force experienced can be obtained as follow:
Impulse = force × time
29 = force × 12
Divide both sides by 12
Force = 29 / 12
Force = 2.42 N
Thus, the force experienced by Albert is 2.42 N
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Which is an example of an anomaly that led to a theory being overturned?
O The recognition that people use up energy, get tired, and need to rest
O The discovery that oil will cause a rolling ball to move farther
O The belief that as Earth rotates, it drags surrounding ether with it
The discovery that materials, when burned, release phlogiston
Answers
An example of an anomaly that led to a theory being overturned is: The discovery that materials, when burned, release phlogiston.
What is a theory?A theory can be defined as an integrated set of principles and rules that can be used by a scientist to explain and predict observed events.
According to Thomas Kuhn, the process of any scientific discovery usually starts with the awareness of an anomaly and ends with making an adjustment to scientific theory in order to make a previously anomalous to become expected.
What is the phlogiston theory?The phlogiston theory can be defined as a superseded scientific theory which stated that a fire-like materials (elements) referred to as phlogiston, are found within combustible bodies and they are released when burned or during combustion.
However, the phlogiston theory is an anomaly that was later overturned by a scientists known as Antoine Lavoisier in 1772, who proved that combustion and burning of any chemical substance or materials (elements) requires a gas that has mass.
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Melissa tells her little brother that she has rice that can dance to music. melissa takes an aluminum pie pan and places a shallow layer of rice in the pan. she holds the pan of rice over a speaker on the radio and turns the radio volume up. the rice begins to dance and her little brother is amazed! she shares this during science class the next day. her teacher asks: "melissa, can you explain using the concept of sound waves what really happened to make the rice dance?
Answers
Melissa observed with the rice dancing is an interesting phenomenon called the Chladni effect.
When she placed the aluminum pie pan with a shallow layer of rice over the speaker on the radio and turned up the volume, the sound waves produced by the speaker caused the pan and the rice to vibrate.Sound waves are actually vibrations that travel through a medium, in this case, the air. When the speaker emits sound waves, they hit the pan, causing it to vibrate. These vibrations are then transferred to the rice, making it move and dance on the pan's surface.
The reason the rice gathers into patterns is due to the specific frequencies of the sound waves. Each frequency creates a unique standing wave pattern on the pan's surface. These patterns form areas of high and low vibrations, causing the rice to gather in the areas of least vibration, resulting in visible patterns.So, in simple terms, the rice dances due to the vibrations caused by the sound waves produced by the speaker. The Chladni effect helps us visualize and understand how sound waves interact with different objects and create patterns. I hope this explanation helps! Let me know if you have any further questions.
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Have All existing elements have been discovered
Answers
Answer:
Not not all of the elements have been discovered.
Which statement compares the attractive forces that hold particles together?
A. Covalent bonding and Van der Waals forces join separate
molecules together, while ionic and hydrogen bonding produce
compounds.
B. Covalent and hydrogen bonding produce compounds, while ionic
bonding and Van der Waals forces join separate molecules
together.
C. lonic and covalent bonding produce compounds, while hydrogen
bonding and Van der Waals forces join separate molecules
together.
D. Ionic and covalent bonding join separate molecules together, while
hydrogen bonding and Van der Waals forces produce compounds.
Answers
Answer:
Ionic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.
Ur welcome:)
Answer:
C) lonic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.
Explanation:
Assume that the brakes in your car create a constant deceleration of 3.9 m/s2
regardless of how fast you are driving.
Calculate the stopping distance for initial speed of 15 m/s
Answers
Answer: the stopping distance for an initial speed of 15 m/s with a constant deceleration of 3.9 m/s² is approximately 57.7 meters.
Explanation:
To calculate the stopping distance, we need to use the following equation of motion:
v² = u² + 2as
where:
v is the final velocity (in this case, it is 0 because the car stops)
u is the initial velocity (15 m/s)
a is the deceleration (-3.9 m/s²)
s is the stopping distance (what we want to find)
Substituting the given values in the equation, we get:
0² = 15² + 2(-3.9)s
Simplifying and solving for s, we get:
s = (15²) / (2 × 3.9) ≈ 57.7 meters
A progressive wave equation is represented by Y = A sin 2π (0. 15t+0. 1x) calculate the period and wavenumber
Answers
The wave's wavenumber equals 0.628 radians per meter.
The given progressive wave equation is represented by Y = A sin 2π(0.15t + 0.1x), where Y is the displacement of the wave at a point in space and time, A is the amplitude of the wave, t is the time, and x is the position of the point along the direction of wave propagation.
The period of a wave is the time it takes for one complete cycle of the wave to occur. In the given equation, the coefficient of t in the argument of the sine function is 0.15. This means that the wave completes one cycle in (1/0.15) = 6.67 seconds.
Therefore, the period of the wave is 6.67 seconds.
The wavenumber of a wave is the number of waves that occur in a given distance. In the given equation, the coefficient of x in the argument of the sine function is 0.1. This means that the wave completes one cycle in a distance of (1/0.1) = 10 meters.
Therefore, the wavenumber of the wave is (2π/10) = 0.628 radians per meter.
In summary, the period of the given wave is 6.67 seconds and the wavenumber is 0.628 radians per meter. These values can be used to calculate other properties of the wave, such as its frequency and velocity, using the relevant formulas.
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How do organisms give off carbon dioxide?
Use the word bank to answer the question.
^ Abiotic matter
^ Biotic matter
^ Carbon
^ Carbon dioxide
^ Cellular respiration
^ Consumer
^ Decomposer
^ Ecosystem
^ Energy storage molecules
^ Producer
Answers
Cellular respiration is the way that organisms give off carbon dioxide
How organisms give off carbon dioxideThe carbon dioxide that organisms contain are usually given off by the process that is called cellular respiration.
During the process of cellular respiration, energy is released through the breaking down of glucose in order to release energy.
Biotic matter such as the producers, consumers, and decomposers are the ones that would carry out this process.
Then the carbon dioxide would be released back into the environment or ecosystem
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someone please help
Answers
\(w = F * S\)
\(F = 20\\S = 10\\F * S = 20 * 10 = 200\) Joules <- 1st answer
\(w = F * S\)
\(1234 = F * 100\)
\(F = \frac{1234}{100}\)
\(F = 12.34 N\) <- 2nd answer
A baseball player hits a 0. 15 kg 0. 15kg0, point, 15, start text, k, g, end text baseball that is initially at rest, changing its momentum by 11 kg ⋅ m s 11 s kg⋅m 11, start fraction, start text, k, g, end text, dot, start text, m, end text, divided by, start text, s, end text, end fraction
Answers
The velocity of baseball that was initially at restand changing momentum by 11 kgm/s is 73.3m/s.
How to calculate velocity?We can find the velocity of the player.
Momentum = mass * velocity
Given
Mass = 0.15kg
Momentum = 11kgm/s
Get the velocity
Velocity = Momentum/Mass
Velocity = 11/0.15
Velocity = 73.3m/s
Hence the velocity of the player is 73.3m/s
What is velocity?The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.For more information on momentum kindly visit to
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This question is about device scaling.
Given: W, L, tox to scale by 1/S, where S >1.
VDD and Vt to scale by 1/X, where X >1.
Determine the scaling factor for:
(a) device channel area W • L, (b) per-unit-area gate capacitance Cox, (c) k'n and K'p, (d) Cgate,
(e) tp (intrinsic), (f) energy per switching cycle C • VDD^2,
(g) dynamic power Pdyn , (h) power density Pdyn/ (channel-area)
Answers
(a) The scaling factor for device channel area W • L is 1/S.
(b) The scaling factor for per-unit-area gate capacitance Cox is S.
(c) There is no scaling factor for k'n and K'p.
(d) The scaling factor for gate capacitance Cgate is 1.
(e) The scaling factor for intrinsic delay tp is S.
(f) The scaling factor for energy per switching cycle C • VDD² is 1/X².
(g) The scaling factor for dynamic power Pdyn cannot be determined.
(h) The scaling factor for power density Pdyn/(channel-area) cannot be determined.
(a) The scaling factor for the device channel area W • L can be determined by multiplying the scaling factors for the width (W) and length (L) separately. Since W is not scaled and L is scaled by 1/S, the scaling factor for W • L would be 1/S.
(b) The per-unit-area gate capacitance Cox is inversely proportional to the oxide thickness (tox). So, if tox is scaled by 1/S, the scaling factor for Cox would be S.
(c) The values of k'n (n-channel MOSFET transconductance parameter) and K'p (p-channel MOSFET transconductance parameter) are not directly affected by scaling. Therefore, there is no scaling factor for k'n and K'p.
(d) The gate capacitance Cgate is directly proportional to the per-unit-area gate capacitance Cox and the device channel area W • L. Since we already determined the scaling factor for Cox as S in part (b), and the scaling factor for W • L as 1/S in part (a), the scaling factor for Cgate would be S * (1/S) = 1.
(e) The intrinsic delay tp is dependent on the device channel length (L) and the effective mobility (μeff). Since L is scaled by 1/S, the scaling factor for tp would be S.
(f) The energy per switching cycle C • VDD^2 is dependent on the gate capacitance Cgate and the power supply voltage VDD. Since we determined that the scaling factor for Cgate is 1 in part (d), and the scaling factor for VDD is 1/X, the scaling factor for C • VDD² would be 1 * (1/X)² = 1/X².
(g) The dynamic power Pdyn is given by the formula Pdyn = C • VDD^2 • f, where f is the frequency of operation. Since we determined the scaling factor for C • VDD² as 1/X² in part (f), and the frequency f is not mentioned in the question, we cannot determine the scaling factor for Pdyn.
(h) The power density Pdyn/(channel-area) is dependent on the dynamic power Pdyn and the device channel area W • L. Since we cannot determine the scaling factor for Pdyn in part (g) and the scaling factor for W • L is 1/S in part (a), we cannot determine the scaling factor for Pdyn/(channel-area).
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When a skydiver falls towards the Earth, the force of gravity from Earth pulls her towards the
Earth and she is obviously accelerating towards the Earth.
Can the reverse (the force of gravity pulls the Earth towards her and the Earth is accelerating
towards her) be true? Explain.
Answers
Answer:
yes
true
Explanation:
because earth is rotation
HELP PLEASE!!!
Gravity helps us watch television, talk on the phone, and use the Intemet.
Explain whether this statement is true or false.
Support your answer with evidence from the text.
Answers
Answer:
Technically yes, it does help those objects not to float away, but that is false. gravity is not the factor that lets us watch tv, talk on the phone etc.
Gravity helps us watch television, talk on the phone, and use the Internet. This is true statement.
What is the process of satellite orbiting?The goal of satellites is to achieve balance. They rotate around the globe quickly enough to avoid being entirely drawn down into the planet's center of gravity, yet slowly enough to avoid drifting out into space.
When a satellite is travelling at the right speed, the earth's gravitational attraction is just strong enough to keep it in place. A satellite must move quicker to maintain orbit the nearer it is to the earth's surface. Additionally, satellites' orbits are circular or elliptical due to the continual pull of the curved surface of the planet.
Therefore, gravity plays a crucial role in our daily lives, whether it's keeping us anchored to the planet's surface or keeping the satellites we use to communicate and learn more about our environment in orbit.
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Plz help me!!!!!!!! I will give you brainliest
Answers
What is all cells in a body that arent formed in a reproductive organ???
Answers
Explanation:
An organ is made of several types of tissue and therefore several types of cells. For example, the heart contains muscle tissue that contracts to pump blood, fibrous tissue that makes up the heart valves, and special cells that maintain the rate and rhythm of heartbeats.
A mouse eats 20 kJ of energy. The mouse uses 8 kJ of energy moving around. What would most of the leftover energy be turned into? ant is the leftover energy useful or wasted?
Answers
Answer:
to be turned into glycogen not wasted
Explanation:
Since the body has a lot of energy left it will turn that energy into glycogen which is a storage form of glucose which will when neccassary will be converted into glucose from the horomone glucagon and be given to the body to be used as energy so the energy is never wasted
Consider the causal LTI system with impulse response h(t) = u(t). Prove that this system is an integrator, i.e., the output of the system is the integral of the input. X(t) 1 2 t t(2-t) 0 h(t) 1 b 1 21 Figure 1: Input function and impulse response
Using the input and impulse response given in Fig.1, find and sketch the output calculating x(t) * h(t). You can either use the integral definition of the convolution or the Reflect-and-Shift approach.
Answers
The impulse response of the LTI system is h(t) = u(t).Let's find the output for the given input and impulse response using the integral definition of the convolution, given as follows:x(t) h(t) = ∫x(τ)h(t-τ)dτWe have to consider two cases when t < 0 and t ≥ 0.
Case 1:
When t < 0x(t) h(t) = ∫x(τ)h(t-τ)dτWhen t < 0, h(t - τ) = u(t - τ) = 0 for all τ > t. Therefore, for this range of t, x(t) h(t) = 0.Case 2:
When t ≥ 0x(t) h(t) = ∫x(τ)h(t-τ)dτ= ∫x(τ)u(t-τ)dτSince u(t - τ) = 1 for τ ≤ t and u(t - τ) = 0 for τ > t, we can split the integral into two parts:x(t) h(t) = ∫x(τ)u(t-τ)dτ= ∫x(τ)u(t-τ)dτ + ∫x(τ)u(τ-t)dt= ∫x(τ)u(t-τ)dτ + ∫x(t-τ)u(τ)dτ= ∫0tu(τ)x(t-τ)dτ + ∫t∞u(τ)x(t-τ)dτ= ∫0tx(t-τ)dτAs the function x(t) is given,we can evaluate the integral:
x(t) h(t) = ∫0tx(t-τ)dτ= ∫0t(2-τ)dτ= 2t - t²/2Let's plot the graph of the output function using the given input and impulse response:Graph of the output functionAbout Impulse ResponseIn signal processing and control theory, the impulse response, or impulse response function, of a dynamic system is its output when presented with a brief input signal, called an impulse. More generally, the impulse response is the reaction of any dynamic system in response to some external change.
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a merry-go-round has a radius of 2.0 m and a moment of inertia of 300 kgm2 . a boy of mass 50 kg runs tangent to the rim at 4.0 m/s and jumps on. if the merry-go-round is initially at rest, what is the angular velocity after the boy jumps on?
Answers
The angular velocity after the boy jumps on is -0.133 rad/s
To solve this problem, we can use the principle of conservation of angular momentum.
The initial angular momentum of the merry-go-round is zero, since it is at rest. The final angular momentum is given by:
L_final = I * w
where I is the moment of inertia of the merry-go-round and w is the angular velocity.
When the boy jumps on, he adds his own angular momentum to the system. The angular momentum of the boy is given by:
L_boy = m * r * v
where m is the mass of the boy, r is the radius of the merry-go-round, and v is the velocity of the boy tangent to the rim.
The total angular momentum after the boy jumps on is the sum of the initial and final angular momentum:
L_total = L_final + L_boy
Since angular momentum is conserved, we can set L_total equal to zero:
0 = I * w + m * r * v
Solving for w, we get:
w = -m * r * v / I
Plugging in the given values, we get:
w = -(50 kg) * (2.0 m) * (4.0 m/s) / (300 kg\(m^2\))
w = -0.133 rad/s
The negative sign indicates that the direction of the angular velocity is opposite to the initial direction of the boy's motion.
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why are fuels from crude oil so widely used for transportation
Answers
What was the rate of reaction in trial 3? select the closest answer. A. 9. 55×10−6 m⋅s−1 b. 4. 86×10−6 m⋅s−1 c. 7. 33×10−6 m⋅s−1 d. 6. 58×10−6 m⋅s−1
Answers
Unfortunately, the information about trial 3 and the rate of reaction is missing in the given question. Without specific data or context,
The given question asks for the rate of reaction in trial 3 but does not provide the necessary information to calculate it. In order to determine the rate of reaction, specific data such as the change in concentration or the time taken for the reaction needs to be provided. Without this information, it is not possible to accurately determine the rate of reaction. The rate of reaction is a measure of how quickly reactants are converted into products and is influenced by factors such as temperature, concentration, and the presence of catalysts. Therefore, without the relevant data for trial 3, it is not possible to calculate or provide an answer regarding the rate of reaction in that specific trial.
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Which has more momentum: a 20,000 kg cement truck traveling at 5 m/s or a 1000 kg race car traveling at 90 m/s
Answers
Hi there!
Recall the equation for momentum:
\(\large\boxed{p = mv}\)
p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)
We can calculate each object's momentum and compare.
Cement truck:
\(p = 20000 \cdot 5 = 100000kg\frac{m}{s}\)
Race car:
\(p = 1000 \cdot 90 = 90000 kg\frac{m}{s}}\)
Since 100,000 > 90,000, the cement truck has the greater momentum.
A 0. 001 kg bullet is fired with a velocity of 800 m/s into a soft wood of mass 1 kg, resting on a smooth surface. What is the impulse of the bullet?
Answers
The impulse of a bullet is the product of the force and the time for which it is applied to the object. The impulse of a bullet can be calculated using the equation.The impulse of the bullet is 0.8 Ns.
Impulse = Force x Time.The given question states that a 0.001 kg bullet is fired with a velocity of 800 m/s into a soft wood of mass 1 kg, resting on a smooth surface. To calculate the impulse of the bullet, we need to determine the force applied to the wood by the bullet during the time of impact.First, let us find the initial momentum of the bullet, which is:Initial momentum = mass x velocity = 0.001 kg x 800 m/s = 0.8 kg m/sWhen the bullet hits the wood, it comes to rest. Therefore, the final velocity of the bullet is 0 m/s. To find the force exerted on the wood, we can use the law of conservation of momentum.
The total momentum of the system before the collision is equal to the total momentum of the system after the collision, which is:Initial momentum of bullet = Final momentum of bullet + Momentum of wood0.8 kg m/s = 0 + (mass of wood) x (final velocity of wood)We know that the mass of wood is 1 kg and the final velocity of wood is unknown. Solving for final velocity of wood gives:Final velocity of wood = 0.8 m/sSo, the change in velocity of the wood is:Δv = final velocity - initial velocity = 0.8 m/s - 0 m/s = 0.8 m/sThe time of impact can be calculated using the equation:Time = Δv / aWhere, a is the acceleration of the wood, which can be found using the equation:F = maF = mΔv / tTherefore,a = F / m = (mΔv / t) / m = Δv / tSubstituting the given values, we get:a = 0.8 m/s / 0.001 s = 800 m/s²The time of impact is:Time = Δv / a = 0.8 m/s / 800 m/s² = 0.001 sTherefore, the force exerted on the wood by the bullet is:F = ma = 1 kg x 800 m/s² = 800 NThe impulse of the bullet can be calculated using the equation:Impulse = Force x Time= 800 N x 0.001 s= 0.8 NsAnswer: The impulse of the bullet is 0.8 Ns.
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A dump truck is moving at a constant velocity of 30 m/s.
Which of the following statements accurately describes the truck?
Answers
Answer: According to Newton’s 1st law, the truck must be in equilibrium.
In order to estimate the average electric usage per month, a sample of 64 houses was selected and the electric usage was determined. Assume a population standard deviation of 320 kilowatt-hours. The standard error of the mean is a. 400.
b. 40.
c. 320.
d. 64
Answers
Answer: b
Explanation: 320/the square root of 64
1. how long does it take light to travel from a. the moon to the earth? (data: earth-moon distance = 384,000 km) b. the sun to the earth? (data: earth-sun distance = 149,600,000 km)
Answers
The time taken by the light to travel from the moon to the earth is 1.28 s and from the sun to the earth is 499.01 s.
We know that, speed of light is constant everywhere.
Its value is 299,792,458 m/s.
Converting into km/s, we have,
⇒ 299,792,458/1000 = 299,792.458 km/s
As the distance between moon and earth is 384000 km.
The time taken by light to travel the above distance is,
⇒ 384000/299,792.458 = 1.28 s
The sun and the earth are separated by 149600000 kilometres.
The time taken by light to travel the above distance is,
⇒ 149600000/299,792.458 = 499.01 s
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