argon is to be compressed steadily from 120 kpa and 310 k to 700 kpa and 430 k. a heat loss of 20 kj/kg occurs during the compression process. neglecting kinetic energy changes, determine the power input required for a mass flow rate of 90 kg/min. >> pwrin b3

The concentration of the hydroxide ion in the saturated Ca(OH)₂ solution is 0.080 M.

To calculate the concentration of hydroxide ion in the saturated Ca(OH)₂ solution, we need to use the results of the titration.

Assuming that the titrant is a strong acid, the balanced chemical equation for the reaction is; H⁺ + OH⁻ → H₂O

The equivalence point of the titration is reached when all of the hydroxide ions in the saturated Ca(OH)₂ solution have reacted with the acid. At this point, the moles of H⁺ added equals the moles of OH⁻ in the original solution. Therefore, we can use the volume and concentration of the titrant, along with the volume of the saturated Ca(OH)₂ solution, to calculate the concentration of OH⁻.

Let's assume that the titrant used is 0.1 M HCl, and that it took 20.0 ml of HCl to reach the equivalence point. This means that 20.0 ml of HCl contains 0.002 moles of H⁺ ions. Since the reaction is 1:1, there are also 0.002 moles of OH⁻ ions in the original 25.0 ml of saturated Ca(OH)₂ solution.

To calculate the concentration of OH⁻ in the saturated Ca(OH)₂ solution, we can use the following equation.

OH⁻ concentration = moles of OH⁻ /volume of solution

OH⁻ concentration = 0.002 moles / 0.025 L

OH⁻ concentration = 0.080 M

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Answer:

132g

Explanation:

CH4= 12+4=16  

moles= m/Mr    moles=48/16=3 mol

CO2= Mr=44

there are the same number of moles as methane:

Mass= Mrxmoles

44x3=132g

The mass of the carbon dioxide produced by the combustion of the 48 g of methane is equal to 132 g.

Combustion reaction involves the complete oxidation of the hydrocarbon such reactions generally release only carbon dioxide and water as products.

A hydrocarbon undergoes combustion to produce carbon dioxide and water as the product. No other side products are formed in the combustion reaction.

The given combustion reaction of the methane can be written as follows:

CH₄   + 2 O₂ →  CO₂  +  2H₂O

Given the amount of methane for combustion = 48 g

The molar mass of methane = 16g/mol

The molar mass of the carbon dioxide, CO₂ = 44g/mol

16 grams of methane produce carbon dioxide = 44g

The  48 grams of methane will produce CO₂ = (44/16) ×48 = 132 g

Therefore, the mass of 132 g of carbon dioxide is produced by the combustion of 48g of methane.

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Answer:

The answer is 7 (seven)

Explanation:

Fluorine has seven of eight possible electrons in its outermost energy level, which is energy level II.

Here, the final volume can be determined using Boyle's law. The volume at 1013 mb pressure  is 8 L. Then the volume at  500 mb will be 16 L.

Boyle's law states that, at constant temperature, the volume of a gas is inversely  proportional to the pressure of the gas.

Hence, PV = a constant.

Let P1 and V1 be the initial pressure  and volume and P2 and V2  be the final pressure and volume then we can write it as,

P1 V1 = P2 V2.

Given that, P1 = 1013 mb

P2 = 500 mb

V1 = 8 l

V2 = P1 V1 / P2

V2  = 1013 mb  × 8 L /500 mb

     = 16 L.

Therefore, the volume of the gas at a pressure of 500 mb is 16 l.

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Answer:

92gm

Explanation:

Atomic mass of Mg=24g=1 mole of Mg

∴  24g =1 mole of Mg contain 6.022×10^23 atom 

∴  6gm contains 246.022×1023×6

                            =4×6.022×10^23 atoms

Now according to question, there are 6.022×1023 atoms of Na 

23gm of Na contains 6.022×10^23 atoms

∴6.022×4×10^23 atoms of Na weighs 23×6.022×10^23×4/6.022×10^23⇒92gm

The number of moles of NaF that will be produced from 3moles of Na is 3 moles.

Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, sodium reacts with fluorine as follows:

2Na+ F₂ → 2NaF

Based on the above equation, 2 moles of Na will produce 2 moles of NaF

This means that 3 moles of Na will produce 3 moles of NaF.

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Answer:

It's a chemical change

A. To calculate the moles of methyl salicylate used during the synthesis, we first need to determine the mass of methyl salicylate produced. From the balanced equation, we can see that one mole of salicylic acid produces one mole of methyl salicylate.

B. To calculate the moles of sodium hydroxide added to the reaction mixture, we need to use its volume and concentration. The balanced equation shows that one mole of salicylic acid reacts with one mole of sodium hydroxide. Therefore, the moles of sodium hydroxide added will be equal to the moles of salicylic acid used.

We can calculate the moles of salicylic acid used as described in part (a), and then use the volume and concentration of sodium hydroxide to calculate the moles of sodium hydroxide added:

moles of sodium hydroxide = volume of sodium hydroxide x concentration of sodium hydroxide

C. To calculate the moles of sulfuric acid added to the reaction mixture, we can use its volume and concentration. The balanced equation shows that one mole of salicylic acid reacts with one mole of sulfuric acid.

Therefore, the moles of sulfuric acid added will be equal to the moles of salicylic acid used.

We can calculate the moles of salicylic acid used as described in part (a), and then use the volume and concentration of sulfuric acid to calculate the moles of sulfuric acid added:

moles of sulfuric acid = volume of sulfuric acid x concentration of sulfuric acid

D. To determine the limiting reactant, we need to compare the number of moles of each reactant used to the stoichiometric coefficients in the balanced equation. The reactant that is used up completely (i.e. has the smallest number of moles relative to its stoichiometric coefficient) is the limiting reactant.

For example, if we find that we used 0.05 moles of salicylic acid and 0.08 moles of methanol, we can see from the balanced equation that salicylic acid is the limiting reactant because it has a stoichiometric coefficient of 1, while methanol has a coefficient of 0.5.

The moles of methyl salicylate produced will be equal to the moles of salicylic acid used.

Assuming that we know the mass of salicylic acid used, we can convert it to moles using its molar mass:

moles of salicylic acid = mass of salicylic acid / molar mass of salicylic acid

Once we know the moles of salicylic acid used, we can calculate the moles of methyl salicylate produced.

moles of methyl salicylate = moles of salicylic acid

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Answer:

yes true

Explanation:

MASS OF REACTANT SIDE = MASS OF PRODUCT SIDE

In the chemical equation the number of atoms of each of the elements are equal on both the sides of arrow as it follows the law of conservation.

The chemical equation is given as the reaction with the reactants reacting, resulting in the formation of the products. The stoichiometric coefficient in the balanced chemical reaction determines the moles of reactant and products involved in the reaction.

The left side of the arrow consisted of the number of reactants, and the right side of the arrow consisted of the number of products.

The balanced chemical equation follows the law of conservation, and thereby the number of products and the reactants atoms at both the side of the arrow are equal.

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Answer:

3121.95 kilogram/cubic meter

Explanation:

I used an online calculator

Hope I helped!

Answer:

ion know figure it out its you who learning ab it

Explanation:

Answer:

♡ ..This sounds like a "you" problem.. ♡

Nah I'm k i d d i n g I actually don't know .

Explanation

Explanation:

Plugging into the following equations will give you the answer (the answer is the attached image):

\(pH+pOH=14\)

\(pH=-log_{10}([H^+])\)

\(pOH=-log_{10}([OH^-])\)

\([H^+][OH^-]=10^{-14}\)

\([H^+]=10^{-pH}\)

\([OH^-]=10^{-pOH}\)

Answer:

true

Explanation:

drought is a period of unusually persistent dry weather that persists long enough to cause serious problems such as crop damage and/or water supply shortages. The severity of the drought depends upon the degree of moisture deficiency, the duration, and the size of the affected area.

Plotting the graph of activity against time for a radioactive sample with an initial activity of 4.20 kBq and a half-life of 32 minutes, with measurements taken every 5 minutes for one hour, shows a decreasing exponential curve.

The activity of a radioactive sample decreases exponentially over time according to the formula A(t) = A0 * (1/2)^(t / T), where A(t) is the activity at time t, A0 is the initial activity, t is the time elapsed, and T is the half-life.

In this case, the initial activity A0 is 4.20 kBq and the half-life T is 32 minutes. Measurements are taken every 5 minutes for one hour, which corresponds to 12 measurements in total.

To plot the graph, we calculate the activity at each time point using the given formula and plot the points on a graph. The x-axis represents the time in minutes, and the y-axis represents the activity in kBq.

Starting with t = 0 minutes, the activity is 4.20 kBq. For each subsequent measurement at intervals of 5 minutes, we calculate the activity using the formula. The resulting data points can be plotted on a graph, connecting them with a decreasing exponential curve.

Note: Since the prompt doesn't specify the unit for time, we assume minutes for consistency with the half-life given in minutes.

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Answer:

sodium

Explanation:

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the beaker that contained some water before NaOH were added means that the resulting solution in that beaker will be more dilute. When this diluted sodium hydroxide solution is added to HCl (not hci), the reaction below occurs

HCl + NaOH ⇒ NaCl + H₂O

The reaction above is a neutralization reaction. The concentration of the acid (HCl) will reduce when a base (sodium hydroxide) is added and will also reduce more because of the presence of more water (in the base) which normally reduces the concentration of ions present in an acid or a base to become more dilute.

the molar mass of the unknown acid is approximately 141.1 g/mol.

a. To find the number of moles of acid in the solid sample, we first need to calculate the number of moles of NaOH used in the titration. We can do this using the equation:

moles NaOH = M NaOH x V NaO

where M NaOH is the molarity of the NaOH solution, and V NaOH is the volume of NaOH solution used at the equivalence point.

Substituting the given values, we get

moles NaOH = 0.300 mol/L x 0.04873 L = 0.014619 mol

Since NaOH and the unknown acid react in a 1:1 mole ratio, the number of moles of acid in the sample is also 0.014619 mol.

b. To find the molar mass of the unknown acid, we can use the equation

molar mass = mass of sample / number of moles of acid

Substituting the given values, we get:

molar mass = 2.06 g / 0.014619 mol = 141.1 g/mol

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The number of moles in the acid is 0.014619 moles and the molar mass of the unknown monoprotic acid is 140.92 g/mol.

To find the number of moles of acid in the solid sample, first determine the moles of NaOH used in the titration. You can do this using the formula:

moles = volume (L) × concentration (M)
moles of NaOH = 48.73 mL × (1 L / 1000 mL) × 0.300 M = 0.014619 moles

Since it's a monoprotic acid, the moles of the acid are equal to the moles of NaOH at the equivalence point:
moles of acid = 0.014619 moles

b. To find the molar mass of the unknown acid, use the formula:

molar mass = mass of the sample (g) / moles of the acid
molar mass = 2.06 g / 0.014619 moles = 140.92 g/mol

So, the molar mass of the unknown monoprotic acid is approximately 140.92 g/mol.

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Ghosts are frequently used as metaphors for the need for justice since they are seen as supernatural echoes of a moral injustice.

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Answer:

18

Explanation:

True. The ancient Egyptians used the royal cubit as a unit of measurement for their architectural and engineering projects. The basic subunit of the royal cubit stone was the span, which measured about 22.5 centimeters.

The royal cubit was divided into seven palms, with each palm divided into four fingers. This standardized system allowed the ancient Egyptians to build massive structures like the pyramids and temples with remarkable accuracy. The span was a crucial component of this system, as it allowed the builders to measure and cut stones to precise lengths. Overall, the royal cubit and its subunits were essential tools for the ancient Egyptians in their architectural and engineering endeavors.
True. The basic subunit of the ancient Egyptians' royal cubit stone is the span. The royal cubit was a unit of measurement used by the Egyptians and was approximately 52.3 cm (20.6 inches) long. It was subdivided into smaller units called spans, each consisting of approximately 26.2 cm (10.3 inches). The span served as a convenient and consistent method for measuring distances and lengths in construction, agriculture, and other aspects of ancient Egyptian life.

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Answer:

Explanation:

The question requires us to calculate the volume (in L) of a gas under the conditions given.

The following information was provided by the question:

Initial volume of gas = V1 = 2.00 L

Initial temperature of gas = T1 = 25.0 °C

Initial pressure of gas = P1 = 1.08 atm

Final temperature of gas = T2 = 100 °C

Final pressure of gas = P2 = 1.50 atm

To solve this problem, we'll need to apply the equation of ideal gases (shown below) twice: first, to determine the number of moles of gas, and again to calculate the volume of gas under the final conditions. Note that we'll determine the number of moles of gas under the initial conditions because this amount won't change (as we're talking about the same sample of gas).

Considering the two acids and bases involved, the reverse reaction is favored.

The term reversible reaction refers to a reaction that can go either forward or backwards depending on the conditions of the reaction.

We must recall that acetic acid is a weak acid hence the equilibrium position would always lie towards the left hand side of the equation. Hence considering the two acids and bases involved, the reverse reaction is favored.

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Answer:

–1065.25 KJ of energy.

Explanation:

From the question given above, the following data were obtained:

4FeO + O₂ —> 2Fe₂O₃  ΔH = –560.66 kJ

From the balanced equation above,

The formation of 2 moles of Fe₂O₃ released –560.66 kJ of energy.

Finally, we shall determine the amount of heat energy released when 3.8 moles of Fe₂O₃ are produced. This can be obtained as follow:

From the balanced equation above,

The formation of 2 moles of Fe₂O₃ released –560.66 kJ of energy.

Therefore, the formation of 3.8 moles of Fe₂O₃ will release

= (3.8 × –560.66)/2 = –1065.25 KJ of energy.

Thus, –1065.25 KJ of energy is released from the reaction.

Answer:

 a supply of electric charges which are free to flow, some form of push to move the charges through the circuit and a pathway to carry the charges.

Explanation:

There's your answer have a good day

0.00342 can be expressed in scientific notation as \(3.42 * 10^{-3}\).

Scientific notation is a system used to express large as well as small numbers in a compact manner.  In general, a number can be expressed in scientific notation as  \(a*10^{b} \\\).

Where, a is a decimal number greater than 1 but less than 10 and b indicates the decimal power. "b" is positive for numbers greater than 1 and negative for numbers less than 1.

Scientific notation is helpful to make calculations involving very large or small numbers less complicated.

We can express 0.00342 in scientific notation as \(3.42 * 10^{-3}\).

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