As keisha runs the generator, which best describes what should happen to the needle that measures electric current? it will move to a large positive value and stay there. it will move back and forth between 0 and a large positive value. it will move back and forth between a large positive and a large negative value. it will move to a large negative value and stay there.
Answers
The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.
What is an electric generator?An electric generator is physically equivalent to an electric motor. but it converts mechanical energy into electrical energy.The electrical field generated is dependent on the inclination of the wire with respect to magnetic field lines, and this inclination changes over time,because of that she will experience a varying electrical field, and thus a varying electric current will be zero.
The maximum positive value will occur when the wire is perpendicular to the magnetic field lines after one-fourth of rotation, and then zero.
Hence option C is correct.
The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.
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Related Questions
Which arrow represents the change of state described above? The diagram shows changes of state between solid, liquid, and gas. The atoms of a substance lose energy during a change of state. Before the change, the atoms are close together but are able to slide past one another. Ом N gas P M Ζ Ο P solid liquid
Answers
Its P path describes the change of state i.e from solid to liquid.
What is solid ?
"A solid is that state of matter which has a fixed shape, mass, and volume. It suffers very small changes in volume by changing the temperature. It can not be compressed, e.g. — Sand, Wood, Copper, Ice, etc."
What is liquid ?
"A liquid is a sample of matter that conforms to the shape of a container in which it is held, and which acquires a defined surface in the presence of gravity. The term liquid is also used in reference to the state, or condition, of matter having this property."
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A motorcycle daredevil is attempting to jump from one ramp onto another. The takeoff ramp makes an angle of 18.0o above the horizontal, and the landing ramp is identical. The cyclist leaves the ramp with a speed of 33.5 m/s. What is the maximum distance that the landing ramp can be placed from the takeoff ramp so that the cyclist still lands on it?
Answers
Therefore, the maximum distance that the landing ramp can be placed from the takeoff ramp so that the cyclist still lands on it is 75.5 m. Hence, option C is correct.
We have to find the maximum distance that the landing ramp can be placed from the takeoff ramp so that the cyclist still lands on it, given that a motorcycle daredevil is attempting to jump from one ramp onto another. The takeoff ramp makes an angle of 18.00 above the horizontal, and the landing ramp is identical. The cyclist leaves the ramp with a speed of 33.5 m/s.
Let's begin with the solution:
Consider the diagram shown below:
Here, AB = Take off ramp, BC = Landing rampθ = 18.0°, Speed of the cyclist, u = 33.5 m/s
It is given that the landing ramp is identical to the takeoff ramp.
So, the angle between the ramp and horizontal is also θ = 18.0°.
The vertical and horizontal components of velocity at point A are given by:
v_y = u sin θ and v_x = u cos θ
The time of flight of the cyclist from A to C is given by:
t = [2v_y] / g Where g is the acceleration due to gravity= 9.81 m/s²
The horizontal distance covered by the cyclist in the time of flight is given by:
x = v_x t …..(1)
The height of the landing ramp (point C) from the ground is given by:
y = BC sin θ …..(2)
The cyclist has to land on the landing ramp (point C).
Therefore, the height of the landing ramp must be equal to the height at which the cyclist leaves the takeoff ramp (point A).
Therefore, from the diagram shown above, we have:
y = AB sin θ …..(3)
From (2) and (3), we have:
AB sin θ = BC sin θ
Or
AB = BC ... (identical ramps)
From equation (1),
we have:
x = v_x
t= u cos θ [2v_y / g]... (4)
Substituting the values of u, θ, v_y and g,
we get:
x = [33.5 m/s] cos 18.0° [2 (33.5 sin 18.0°) / 9.81 m/s²]= 75.5 m (approximately)
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A commuter backs her car out of her garage with an acceleration of 1.66m/s2.
a) How long does it take her to reach a speed of 2.28m/s?
b) If she then brakes to a stop in 0.86s, what is her acceleration?
Answers
The time taken by her to reach a speed of 2.28m/s is 1.37 s whereas, the acceleration on break to stop in 0.86s is 4.47 m/s².
Equation :( a ) To find the time we use the formula,
a = Δv / Δt
where,
a is acceleration,
Δv is change in speed
Δt is time
So with this putting the given value,
We have,
1.66m/s² = 2.28m/s / Δt
Δt = 2.28m/s / 1.66m/s²
Δt = 1.37 s
( b ) Again using same formula for acceleration
a = Δv / Δt
So,
a = 2.28m/s / 1.37 - 0.86s
a = 2.28m/s / 0.51 s
a = 4.47 m/s²
What is acceleration and velocity?The rate of change of displacement is known as velocity. The rate at which velocity changes is called acceleration. Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. As the rate at which velocity changes, acceleration is also a vector quantity.
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(a)The time has taken by a commuter to reach a speed of 2.28m/s is (t)= 1.37 s. (b) If she then brakes to a stop in 0.86s,Theamount of acceleration is (a)= 2.65 m/s².
What is acceleration and velocity?The term velocity defines that how much distance a particle covered in a given time. The term acceleration defines that change in velocity in a particular time.
How can we calculate the value of acceleration and velocity?( a ) To calculate the time we use the formula, v=u+at
As the particle start from rest so, u= initial velocity would be zero.
The equation becomes, v=at
t=v/a
where, we are given
a= acceleration of the car =1.66m/s²,
v= speed of the car= 2.28m/s
We have to calculate the time=t
So now we put the given value in the above equation, We have,
t=v/a
Or, t = 2.28m/s / 1.66m/s²
Or, t = 1.37 s
According to the calculation we can say that, The time has taken by a commuter to reach a speed of 2.28m/s is (t)= 1.37 s
( b ) To calculate the acceleration we use the formula, v=u+at
As the particle start from rest so, u= initial velocity would be zero.
The equation becomes, v=at
a=v/t
where, we are given
v= speed of the car= 2.28m/s
t= The time take to break=0.86 s
We have to calculate the acceleration=a
So now we put the given value in the above equation, We have,
a=v/t
Or, a = 2.28 /0.86
Or, a = 2.65 m/s²
According to the calculation we can say that, If she then brakes to a stop in 0.86s,Theamount of acceleration is (a)= 2.65 m/s²
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Consider a single slit that produces its first minimum at 59° for 620 nm light.
Answers
The width of the slit is 482 nm. The first minimum in a single slit diffraction pattern occurs at an angle given by the equation sinθ = λ/b,
where θ is the angle between the center of the diffraction pattern and the location of the minimum, λ is the wavelength of the light, and b is the width of the slit.
In this case, we are given that the first minimum occurs at 59° for 620 nm light.
Using the equation, we can solve for the width of the slit as b = λ/sinθ. Plugging in the values, we get b = (620 nm)/(sin(59°)) = 482 nm. Therefore, the width of the slit is 482 nm.
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Mr Chichester is driving his dark blue camaro to a REO Speedwagon concert. He is driving 15 m/s when he realizes he is going to be late to his favorite band so he slams on the gas for 10s and reaches a final velocity of 45 m/s. How far did Mr. Chichesters travel during this 10s?
Answers
Answer:
300m
Explanation:
step one
given data
initial speed u= 15m/s
final speed v= 45m/s
time taken to attain final speed= 10seconds
Step two:
Let us first solve for the acceleration
a= Δv/t
a= 45-15/10
a=30/10
a= 3m/s
applying the equation of motion
\(v^2=u^2+2as\)
substituting our given data
\(45^2+15^2+2*3*s\\\\2025=225+6s\\\\\)
collect like terms
2025-225=6s
1800=6s
divide both sides by 6
s=1800/6
s=300m
What happens to the particles of an object when its temperature increases? *
The PE of the particles decreases.
The KE of the particles decreases.
The PE of the particles increases.
The KE of the particles increases.
Answers
Answer:KE
Explanation:
A car traveling at 15m/s on a flat surface turns in a circle with a radius of 25m.What is the centripetal acceleration of the car?
Answers
ANSWER
\(9m\/s^2\)EXPLANATION
To find the centripetal acceleration, we have to apply the formula for centripetal acceleration:
\(a=\frac{v^2}{r}\)where v = velocity of the vehicle
r = radius of the circular path
Therefore, the centripetal acceleration is:
\(\begin{gathered} a=\frac{15^2}{25} \\ a=9m\/s^2 \end{gathered}\)That is the answer.
94. Determine the magnitude of the acceleration of the rock down the inclined plane if the rope breaks?A) zero m/s2B) 4.9 m/s2C) 5.7 m/s2D) 8.5 m/s2E) 9.8 m/s2
Answers
The correct option provided is option C) 5.7 m/s^2
How to find acceleration?When the rope is holding the rock, the tension force in the rope opposes the weight of the rock and the net force acting on the rock is zero. When the rope breaks, the tension force becomes zero and the weight of the rock is the only force acting on it.
The weight of the rock can be resolved into two components, one parallel to the inclined plane and one perpendicular to it. The component parallel to the inclined plane will cause the rock to accelerate down the plane.
The magnitude of the component of the weight parallel to the inclined plane is given by Wsinθ, where W is the weight of the rock and θ is the angle of the inclined plane with respect to the horizontal.
a = (Wsinθ)/m
where m is the mass of the rock.
Substituting the values, we get:
a = (10 kg) * sin(30°)/10 kg = 5 m/s^2
Therefore, the magnitude of the acceleration of the rock down the inclined plane if the rope breaks is 5 m/s^2.
The closest option provided is option C) 5.7 m/s^2.
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A car travels 100 kilo metre due east in 2 hours. it then travels 50 kilo metre south in hour. what is its average velocity?
Answers
=100-50/2-1
=50 m/s
why malleability is a useful property
Answers
What is the net force and direction the box will move in ?
Answers
Answer:
5 Newton to right direction
Explanation:
5N to the right will be vanishes with 5N to the left..... then the another 5N to right will be the force that move the box
A wave is moving at the rate of 40 cm/s. Its wavelength is 5 cm. What is the frequency of the wave? INCLUDE THE CORRECT UNIT!
Answers
Answer:
Solution given:
velocity=40cm/s
wave length=5cm
we have
frequency =velocity/wavelength=40/5=8hertz.
the frequency of the wave is 8 hertz.
A bicyclist starts from rest and accelerates along a straight path to a speed of 12.15 m/s in a time of 4.5 seconds. What is the bicyclist’s acceleration in m/s2?
a. 3.7
b. 54.7
c. 2.7
d. 6.8
Answers
The Bicyclist's Acceleration is 2.7 m/s2. Thus, Option C is the answer
The bicyclist's acceleration can be found using the equation:
acceleration = (final velocity - initial velocity) / time
In this case, the final velocity is 12.15 m/s, the initial velocity is 0 m/s (since the bicyclist starts from rest), and the time is 4.5 seconds. Plugging these values into the equation, we get:
acceleration = (12.15 m/s - 0 m/s) / 4.5 seconds
acceleration = 2.69 m/s2
Therefore, The correct answer is c. 2.7 m/s2
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13. In Section 2.2, three ways to use physical properties are
discussed. Find one example in Section 5.3 that illustrates
each use. If necessary, reread pages 48 and 50.
Answers
Physical properties are used to identify and describe matter. They include
appearance (shape, size, color, texture)boiling/melting pointdensitysolubility viscositymalleability odor29.which of the following is a benefit gained from dancing this is mapeh please answer it quickly I need it
Answers
Answer:
improved condition of your heart and lungs. increased muscular strength, endurance and motor fitness. increased aerobic fitness. improved muscle tone and strength.
Explanation:
yup
What happens to a circuit's resistance (R), voltage (V), and current (1) when
you change the thickness of the wire in the circuit?
A. V and I will also change, but R will remain constant.
B. R and I will also change, but V will remain constant.
O C. R, V, and I will all remain constant.
OD. R and V will also change, but I will remain constant.
Answers
When you change the thickness of the wire in a circuit, option B. the resistance (R) and current (I) will also change, but the voltage (V) will remain constant.
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area (thickness). As the thickness of the wire changes, the cross-sectional area changes, which in turn affects the resistance. Thicker wires have a larger cross-sectional area, resulting in lower resistance, while thinner wires have a smaller cross-sectional area, resulting in higher resistance. Therefore, changing the thickness of the wire will cause a change in resistance.
According to Ohm's Law (V = IR), the voltage (V) in a circuit is equal to the product of the current (I) and the resistance (R). If the voltage is kept constant, and the resistance changes due to the thickness of the wire, the current will also change to maintain the relationship defined by Ohm's Law. When the resistance increases, the current decreases, and vice versa.
However, it's important to note that changing the thickness of the wire will not directly affect the voltage. The voltage in a circuit is determined by the power source or the potential difference applied across the circuit and is independent of the wire thickness. As long as the voltage source remains constant, the voltage across the circuit will remain constant regardless of the wire thickness. Therefore, the correct answer is option B.
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Figure 4 shows balls 1 and 2 before and after a collision.
Ball 1 initially travels with a velocity of u m/s. Ball 2 is stationary and has a mass of 0.2 kg.
Ball 1 collides with ball 2 and this collision lasts for 0.1 s. Afterwards, both balls move in
the direction of ball 1's initial velocity. Each ball has a different final velocity.
During the collision, a force of -6N is exerted on ball 1 by ball 2
Calculate the velocity of ball 2 after the collision
Answers
According to the question, the velocity of ball 2 after the collision is 30 m/s.
What is velocity?
Velocity is a vector quantity that describes the rate and direction of an object's motion. It is the displacement of an object over a period of time and is usually expressed in terms of distance (meters, feet, or kilometers) divided by time (seconds). It can also be expressed as the speed of an object in a particular direction. Velocity is a key factor in describing the motion of objects, as it accounts for both the speed and direction of an object's motion. It is an important concept in physics, and it is used to calculate forces and potential energy.
From the laws of conservation of momentum, the final velocity of ball 2 can be calculated as follows:
m1u + m2v = m1v1 + m2v2
0.2 x u + 0.2 x v = 0.2 x u + 0.2 x v2
v2 = u - (6N x 0.1s)/0.2kg
v2 = u - 30 m/s
Therefore, the velocity of ball 2 after the collision is 30 m/s.
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A ball of mass 3, point, 5, k, g,3. 5kg rolls all the way down a slope inclined at 40, degrees,40
∘
to the horizontal, with a base of length 4, point, 8, m,4. 8m. How much GPE does the ball lose?
Answers
The mass of a ball is 3.5 kg. It moves down a slope that is inclined at 40 degrees with respect to the horizontal. The base of the slope has a length of 4.8 meters.the ball loses 106.2 Joules of gravitational potential energy when it rolls down the slope.
It is required to determine how much gravitational potential energy the ball loses when it rolls down the slope.For this, we need to use the following formula:ΔPE = mghwhere m = mass of the ball = 3.5 kgg = acceleration due to gravity = 9.81 m/s2h = height from which the ball rolls downLet's analyze the situation. The ball moves down a slope. The potential energy (PE) of the ball at the top of the slope is converted into kinetic energy (KE) as it moves down the slope. The ball gains KE, and it loses PE.The height from which the ball rolls down the slope is given by the following expression:h = length of slope × sin θh = 4.8 × sin 40°h = 3.086 metersSubstitute the given values into the formula for ΔPE.ΔPE = mghΔPE = 3.5 × 9.81 × 3.086ΔPE = 106.2 JoulesTherefore, the ball loses 106.2 Joules of gravitational potential energy when it rolls down the slope.
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Suppose that the mirror is moved so that the tree is between the focus point F and the mirror. What happens to the image of the tree?
1. the image moves behind the curved mirror.
2.The image stays the same.
3.The image appears taller and on the same side of the mirror.
4. The image appears shorter and on the same side of the mirror.
Answers
When the mirror is moved so that the tree is between the focus point F and the mirror, the image appears shorter and on the same side of the mirror.This happens because of the phenomenon known as Reflection of Light. The mirror reflects light in such a way that it appears as if the light is coming from behind the mirror.
As a result, a virtual image is formed behind the mirror. This virtual image is similar in size and shape to the object being reflected.The characteristics of the image produced by a mirror depends on the location of the object relative to the mirror. There are two types of mirrors that we use to reflect light: Concave and Convex. In the case of a concave mirror, the image produced can either be real or virtual. When an object is placed between the focus point and the mirror, a virtual and erect image is produced. This image is smaller than the actual object and appears behind the mirror. The image is virtual because the light rays do not converge at the location of the image. In the case of a convex mirror, the image produced is always virtual, erect, and smaller than the actual object. As the object moves closer to the mirror, the image gets smaller. If the object is moved to a position where it is between the focus point and the mirror, the image produced will appear shorter and on the same side of the mirror.For such more question on Concave
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An object travels 40 m in 4 s and then another 50 m in 5 s .What is the average speed of the object?
Answers
Answer:
10m/sExplanation:
Average speed is the change in distance of a body/object with respect to time. Speed is expressed by the expression;
Speed = \(\frac{change\ in\ distance}{change\ in\ time}\)
speed ΔV = ΔS/Δt
ΔV = S₂-S₁/t₂-t₁
given S₂ = 50m, S₁ = 40m, t₂ = 5s, t₁ = 4s
average speed = 50-40/5-4
average speed = 10/1
average speed = 10m/s
average speed of the object is 10m/s
in which case would you have the largest mass of gold? a. if your chunk of gold weighs 1 n on the moon. b. if your chunk of gold weighs 1 n on the earth. c. if your chunk of gold weighed 1 n on the planet jupiter.
Answers
The largest mass of gold would be in the case c. if your chunk of gold weighs 1 N on the planet Jupiter.
Mass is the quantity of matter in an object. The mass of an object is a measure of the amount of matter it contains. Mass is usually measured in grams (g) or kilograms (kg). A measure of the resistance to acceleration given by an object to any force used to modify its speed, direction or shape is referred to as mass. The following statement can be used to describe mass: “Mass is the amount of matter present in a body.”
Weight is the force with which gravity pulls on an object. Weight is not the same as mass, which is a measure of how much matter is present in an object. On the other hand, weight is the measure of the amount of gravitational force that is acting on an object.The answer to this question is "The largest mass of gold would be in the case when your chunk of gold weighs 1 N on the planet Jupiter."
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Which element most likely interacts with water the same way lithium interacts with water?
Answers
Answer:
Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)
Explanation:
A sample of 6.90 g of solid calcium hydroxide is added to 37.5 mL of 0.440 M aqueous hydrochloric acid. Write the balanced chemical equation for the reaction. Physical states are optional.
Answers
Balanced chemical equation is : Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O
The balanced chemical equation represents the reaction between solid calcium hydroxide (Ca(OH)₂) and aqueous hydrochloric acid (HCl). The equation shows that one mole of calcium hydroxide reacts with two moles of hydrochloric acid to produce one mole of calcium chloride (CaCl₂) and two moles of water (H₂O).
In the equation, the subscripts indicate the number of atoms present in each molecule. Calcium hydroxide consists of one calcium (Ca) atom, two oxygen (O) atoms, and two hydrogen (H) atoms. Hydrochloric acid contains one hydrogen (H) atom and one chlorine (Cl) atom. Calcium chloride is composed of one calcium (Ca) atom and two chlorine (Cl) atoms. Water consists of two hydrogen (H) atoms and one oxygen (O) atom.
The coefficients in the balanced equation indicate the relative amounts of each compound involved in the reaction. In this case, one mole of calcium hydroxide reacts with two moles of hydrochloric acid to produce one mole of calcium chloride and two moles of water.
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Since the gas and dust contained metals from the previous generation of stars
Answers
The presence of metals in gas and dust from a previous generation of stars.
Since the gas and dust contained metals from the previous generation of stars, these materials played a crucial role in the formation of new celestial bodies. When a star reaches the end of its life, it goes through a process called nucleosynthesis, during which heavier elements like metals are formed. These metals are then expelled into the surrounding interstellar medium through events like supernova explosions.
This enriched gas and dust will eventually form new stars, planets, and other celestial bodies. The presence of metals in these new objects is crucial, as they contribute to the chemical diversity and overall evolution of the universe. In summary, the gas and dust from a previous generation of stars are essential for the formation and composition of new celestial bodies, as they contain important metallic elements.
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Lloyd walks faster than
Ronald, with a speed of
about 0.65 m/s. The canteen
is 15 meters away from their
dassroom. How many
minutes will take her to go
to the canteen?
Answers
Answer:
Time = 2.6 minutes
Explanation:
Given the following data;
Speed = 0.65 m/s
Distance = 15 meters
To find the time to get to the canteen;
Mathematically, time is given by the formula;
Time = distance/speed
Substituting into the formula, we have;
Time = 15/0.65
Time = 23.08 seconds
To minutes = 60/23.08 = 2.6 minutes
A _ is a measure of the _ in a wave. The greater the waves _ the more _ it has.
Answers
A amplitude is a measure of the energy in a wave. The greater the waves amplitude, the more energy it has.
Give a short note on amplitude?Amplitude is a measure of the energy or intensity of a wave. In physics, it is defined as the maximum deviation of a wave from its average position or equilibrium state.
In the context of sound waves, amplitude refers to the loudness of a sound. A sound with a high amplitude is louder than a sound with a low amplitude.
In the context of light waves, amplitude refers to the brightness of a light. A light with a high amplitude is brighter than a light with a low amplitude.
In the context of mechanical waves, amplitude refers to the maximum displacement of a point on the wave from its rest position.
In summary, amplitude is a measure of the energy or intensity of a wave and is represented by the maximum deviation of a wave from its average or equilibrium position.
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In an experiment in which molten naphthalene is allowed to cool, the cooling curve shown below was obtained, the temperature 80∘C is known as
A. cooling temperature
B. boiling point
C. melting point
D. vaporization point
Answers
Answer:
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Explanation:
In an experiment in which molten naphthalene is allowed to cool, the cooling cur...
Question
In an experiment in which molten naphthalene is allowed to cool, the cooling curve in fig 5 was obtained, the temperature
80
∘
C.is known as
Options
A) cooling temperature
B) boiling point
C) melting point √√√√√√√√√√※※※ ↑↑ANSWER
D) vaporization point
A dentist uses a concave mirror to examine a tooth that is 1.00 cm in front of the mirror. The image of the tooth forms 10.0 cm behind the mirror.What is the mirror’s radius of curvature?What is the magnification of the image?
Answers
Here ,
object distance (u)= -1.00 cm
image distance(v)= -10.0 cm
focal length = -f
radius of curvature =r
Using concave mirror formula
\(\begin{gathered} \frac{1}{f}=\frac{1}{u}+\frac{1}{v}; \\ \therefore\frac{1}{-f}=\frac{1}{-1}+\frac{1}{-10}; \\ \frac{1}{f}=\text{ }\frac{11}{10}; \\ \therefore f=\text{ }\frac{10}{11}; \end{gathered}\)Again we have
r= 2f
\(\begin{gathered} r=\text{ 2f } \\ \therefore r=\text{ 2}\times\frac{10}{11}\text{ =1.818 cm = 1.82cm\lparen Approx\rparen} \end{gathered}\)answer is 1.82 cm ( negative in sign)
Now magnification is
\(magnification\text{ = }\frac{v}{u}=\text{ }\frac{10}{1}\text{ = 10 }\)
Answer is radius = 1.82cm( negative in sign) & magnification =10
shows some equipotentials in the plane. (a) in what region is the electric field strongest? what are (b) the direction and (c) the magnitude of the field in this region?
Answers
a)The electric field is the strongest in the region of x=2m to x= 5m as the equipotential surfaces are most closely spaced here. b) the Direction of the field is the -ve x-axis and c) the magnitude of the electric field = 10V/m
a)The equipotential surfaces are where the electric potentials are constant or the same at all points on the surface and the work done by an electric field in moving a charge along an equipotential surface is zero. In the figure, equipotential surfaces are most closely spaced along the x-axis between x=2 and x=5. The electric field is very strong in that region as the rate of change of potentials is higher and electric field E = -dV/dr
(b) The potential decreases in the direction of the electric field because of the negative sign in the formula E=-dV/dr. E is from higher to lower levels of V. For the region mentioned previously 2 m ≤ x ≤ 5m, the direction of the electric field is in the negative x direction.
(c) The drop in potential in this region is from 40V to 10V and dr = (5-2) = 3. Thus E = -dV/dr = (40-10)/3 = -10V/m. The magnitude of the field in this region is 10V/m
The question is probably incomplete with a missing figure and the full question shows some equipotentials in the plane. (a) in what region is the electric field strongest? what are (b) the direction and (c) the magnitude of the field in this region? with the figure
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F. What force is necessary for a person to hold a 50 kg mass over their head?
Answers
Answer: 490.5 N
Explanation:
In this case, the only two forces acting on the mass are the person's strength (i.e. the force in question) and the weight of the mass.
The sum of the forces is equal to 0. This means that Force (person) = Force (weight).
Fp = Fw = m * gravity
Fp = 50 kg * 9.81 m/s^2
Fp = 490.5 (kg*m/s^2)
Fp = 490.5 N