The correct answer is displacement.
Average velocity differs from average speed because displacement is used to calculate average velocity.
What is displacement?
Being a vector, displacement has both magnitude and direction. In one-dimensional motion, the direction should be stated with a plus or minus sign to ensure sure the direction is right. It always occurs in a straight line between two sites. Although it is not a vector variable and lacks a direction sign, the word "distance traveled" is also used to refer to the length of the path that was taken to get from one place to another. The distance traveled is not always equal in both magnitude and direction; on occasion, it may exceed the magnitude of the displacement between the sites.
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance?
The work done on the mouse by air resistance is equal to 196 Joules.
Given the following data:
Mass = 200 grams to kg = 0.2 kg.
Distance = 100 meters.
Scientific data:
Acceleration due to gravity = 9.8 \(m/s^2\)
How to calculate work done.In Science, work done is generally calculated by multiplying force and the vertical distance or displacement experienced by an object.
Mathematically, work done is given by the formula:
\(Work\;done = force \times displacement = mgh\)
Substituting the given parameters into the formula, we have;
\(Work\;done = 0.2 \times 9.8 \times 100\)
Work done = 196 Joules.
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A normal atom is electronically ** (positive/negative/neutral) because the number of ** (protons/neutrons/electrons), each with a positive charge, equals the number of ** (protons/neutrons/electrons), each with a negative charge.
The answers to multiple choice questions are in parentheses
Answer:
(neutral)
(protons)
(electrons)
Explanation:
Electrons have a negative charge (-) while protons have a positive (+) charge.
Atoms will usually be neutral, which means that there will be no charge.
For an atom to have a neutral charge, protons and electrons must "cancel" each other out. For this to happen, you need to have the same amount of each.
Positive will "cancel" out the negative.
A rover vehicle weighs 37 N on Mars. How much would the rover weigh on Earth?
The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N
How do determine the weight of the vehicle on earth?We'll begin by obtaining the mass of the rover vehicle. This is shown below:
Weight (W) = 37 NAcceleration due to gravity on Mars (g) = 3.72 m/sMass of rover vehicle =?Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Divide both sides by g
m = W /g
m = 37 / 3.72
m = 9.95 Kg
Now, we shall determin the weight of the rover vehicle on Earth. Details below:
Mass (m) = 9.95 KgAcceleration due to gravity on Earth (g) = 10 m/s² Weight (W) = ?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 9.95 × 10
Weight = 99.5 N
Thus, we can conclude that the weight on Erath is 99.5 N
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Question 1
Simple Cubic Lattice, Part 1
Consider a simple cubic (sc) crystal in which one atom is placed at each lattice point. The lattice constant is
�
=
0.7
�
�
a=0.7nm. Calculate the volume density of atoms (i.e. number of atoms per unit volume) in unit of
�
�
−
3
cm
−3
. Values within 5% error will be considered correc
The volume density of atoms in a simple cubic crystal is 2.92 × 1021 atoms per cubic centimeter.
The lattice constant (a) of a simple cubic (SC) crystal is 0.7 nm. One atom is present at each lattice point. We have to compute the volume density of atoms (i.e. the number of atoms per unit volume) in terms of atoms per cubic centimeter.1 nm = 10-7 cm ⇒ 0.7 nm = 0.7 × 10-7 cm = 7 × 10-8 cm.
Volume of the unit cell of a SC crystal is given byV = a3= (0.7 × 10-7 cm)3= 3.43 × 10-22 cm3The unit cell has one atom, so the volume density of atoms is the same as the number of atoms per unit cell, which is1/ V = 1 / (3.43 × 10-22 cm3)= 2.92 × 1021 atoms per cubic centimeter.= 2.92 × 1023 atoms per cubic meter= 2.92 × 10-4 atoms per cubic angstrom.
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An effort of 200 N is used to lift a load of 800 N by using a lever. If the load is at a distance of 40 cm from the fulcrum then find the effort distance
The effort distance will be 160 cm.Applying the moment at the center as follows will provide the effort distance:
What is the mechanical advantage?Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of forces in levers and pulleys.
Given data;
Effort,\(\rm F_e=00 N\)
Load,\(\rm P= 400 \ N\)
Distance from the fulcrum,\(\rm d=40 \ cm\)
The effort distance is found by applying the moment at the center as;
\(\rm F_e \times d= P \times d' \\\\ 200 \ N \times d'=800 \ N \times 40 \ cm \\\\ d'=160 \ cm\)
Hence, the effort distance will be 160 cm
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what are electromagnetic waves?
please i need a good answer
Answer:
In physics, electromagnetic radiation refers to the waves of the electromagnetic field, propagating through space, carrying electromagnetic radiant energy. It includes radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays.
Explanation:
What is the period of a wave with a frequency of 0.75 Hz?
Answer:
Period = 1.33 seconds
Explanation:
Period = 1/0.75
The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
If distance between particle become half, the electric force
The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.
This diagram shows the magnetic field lines near the ends of two magnets. There is an error in the diagram.
Two bar magnet with the north pole of one near the south pole of the second. field lines are leaving the north pole and bent away from the south pole of the other. Field lines are leaving the south pole of one and bending away from the north pole of the other.
Which change will correct the error in the diagram?
a)changing the N to S
b)reversing the arrows on the left to point toward the N
c)changing the S to N
d)reversing the arrows on the right to point toward the S
Answer:
changing the N to S. that's how the error will be corrected
Answer:
C is the correct answer
Explanation:
i took the test
Mountain Ecosystems Assignment Answer each question below in complete sentences.1) Identify a predator from an Ethiopian Highlands ecosystem. How else can this animal be classified in terms of feeding relationships? What is its prey? How else can its prey animal be classified in terms of feeding relationships? Identify a predator from a Himalayan Mountain ecosystem. How else can this animal be classified in terms of feeding relationships? What is its prey? How else can its prey animal be classified in terms of feeding relationships?
An example of a a predator in the Ethiopian Highlands ecosystem is the
Wolf.The wolf is a carnivore which acts as a predator to other smaller
animals in the ecosystem.
What is a Prey?Preys are mostly smaller animals in which the predators feed on for food.
They are usually herbivores and primary consumers in the ecosystem.
Examples of Preys include:
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Two forces, one four times as large as the other, pull in the same direction on a 10kg mass and impart to it an acceleration of 2.5 m/s2. If the smaller force is removed, what is the acceleration of the mass?
Answer:
The acceleration of the mass is 2 meters per square second.
Explanation:
By Newton's second law, we know that force (\(F\)), measured in newtons, is the product of mass (\(m\)), measured in kilograms, and net acceleration (\(a\)), measured in meters per square second. That is:
\(F = m\cdot a\) (1)
The initial force applied in the mass is:
\(F = (10\,kg)\cdot \left(2.5\,\frac{m}{s^{2}} \right)\)
\(F = 25\,N\)
In addition, we know that force is directly proportional to acceleration. If the smaller force is removed, then the initial force is reduced to \(\frac{4}{5}\) of the initial force. The acceleration of the mass is:
\(\frac{25\,N}{20\,N} = \frac{2.5\,\frac{m}{s^{2}} }{a}\)
\(a = 2\,\frac{m}{s^{2}}\)
The acceleration of the mass is 2 meters per square second.
A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt and add an explain please )
Explanation:
To determine the force F of interaction between the half ring and the point charge, we can use the principle of superposition, which states that the total force on a point charge due to a collection of other charges is the vector sum of the individual forces that each of those charges would exert on the point charge if it were the only charge present.
First, we need to find the electric field at the center of curvature due to the charged half ring. The electric field at a point on the axis of a uniformly charged ring is given by:
E = kqz / (z^2 + R^2)^(3/2)
where k is Coulomb's constant, q is the linear charge density, z is the distance from the center of the ring to the point on the axis, and R is the radius of the ring.
At the center of curvature of the half ring, z = R, so the electric field is:
E = kq / (2R)
Next, we can use the electric field to find the force on the point charge q:
F = qE
Substituting the given values, we get:
F = (20 x 10^-9 C) x (9 x 10^9 N·m^2/C^2) x (1/20 cm)
F = 9 x 10^-3 N
Therefore, the force of interaction between the half ring and the point charge is 9 x 10^-3 N.
This force can also be interpreted as the force required to hold the point charge at the center of curvature against the electric field due to the charged half ring. It is an attractive force because the point charge is opposite in sign to the charged half ring.
Answer:
5.65N.
Explanation:
Solution Given:
radius of R = 10 cm=10/100=0.1 m
linear density λ = 1 Mikrokulon/m= 10^-6 Coulomb/m
force F=?
q1 = 20nC=20*10^-9 C
we have
Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, this can be expressed as:
F = k*(q1*q2)/r^2
since q1 is located at the center of curvature of the half ring , so the half ring is uniformly charged with a linear density of λ= 1 μC/m.
again
equation becomes.
F=k*(q1*λL)/r^2
Since the half ring is a semicircle,
we have L=πr
F=k*(q1*λ*πr)/r^2
substituting value
F=9 x 10^9 N*m^2/C^2 *(20*10^-9 C* 10^-6 m^3*π*0.1 m)/(0.1m^2)
F=5.65 N
Therefore, the force of interaction between the half ring and the point charge is 5.65N.
Let to the right be the positive direction.
A 25.8 g marble sliding to the right at 21.0
cm/s overtakes and collides with a 12.4 g
marble moving in the same direction at 13.8
cm/s. After the collision, the 12.4 g marble
moves to the right at 23.9 cm/s.
Find the velocity of the 25.8 g marble after
the collision.
Answer in units of cm/s. Answer in units
of cm/s.
The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.
What is the velocity of the 25.8 g marble after the collision?
The velocity of the 25.8 g marble after the collision is calculated as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of 25.8 g marblem₂ is the mass of 12.4 g marbleu is their initial speedsv is their final speedsThe final velocity of the 25.8 g marble after the collision is calculated as;
( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )
712.92 = 296.36 + 25.8v
25.8v = 416.56
v = 416.56 / 25.8
v = 16.15 cm/s
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What is the mass of a ball that has 29j of potential energy and is lifted 2.0m?
Answer:
1.48kg
Explanation:
Here,
potential energy (P.E) = 29j
height (h) = 2m
acceleration due to gravity(g) =
\(9.8m {s}^{ - 2} \)
mass(m) = ?
we know,
P.E = mgh
or, 29 = m×9.8×2
or, 29/19.6 = m
or,m = 1.48kg
Were is the computer located
Answer:
where u put it last time or retrace ur steps to where u last put it
EASY POINTS:Which element is magnetic? calcium chromium carbon cobalt
Answer:
D
Explaination:
I got it right on the quiz
Answer:
The answer is D. cobalt! :)
List two examples of how the land can have a dramatic change in temperature throughout the day.
Answer:
one could freeze and the second would thaw
Explanation:
sorry if its wrong
The two examples of how land can have a dramatic change in temperature
is during freezing and thawing.
Cold temperatures which is common during the winter period is
characterized by the formation of snow and freezing of smaller water
bodies.
There may be a short phase in which there is relative sunlight which melts
the frozen substances thereby forming liquids . This is usually as result of
the temperature being on the increase in the atmosphere.
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Two tiny objects with equal charges of 7.25 μC are placed at the two lower corners of a square with sides of 0.201 m, as shown.
Find the electric field at point B, midway between the upper left and right corners. If the direction of the electric field is upward, enter a positive value. If the direction of the electric field is downward, enter a negative value. answer in N/C
The electric field at point B, located at the midpoint between the upper left and right corners of the square, can be approximated as 3.244 x \(10^6\) N/C in the upward direction.
To find the electric field at point B, we can consider the contributions from the two charges placed at the lower corners of the square. Since the charges are the same and the distance to point B is the same for both charges, the magnitudes of the electric fields produced by each charge will be equal.
First, let's calculate the magnitude of the electric field produced by one of the charges at point B using Coulomb's Law:
Electric field due to a point charge (E) = (k * q) / \(r^2\)
Where:
- k is the electrostatic constant, approximately equal to 8.99 x 10^9 \(10^9\)N \(m^2/C^2\)
- q is the charge of the object, 7.25 μC (7.25 x \(10^-^6\) C)
- r is the distance from the charge to point B, which is half the length of the square's side, 0.201 m / 2 = 0.1005 m
Plugging in the values, we have:
E = (8.99 x \(10^9 N m^2/C^2\) * 7.25 x \(10^-^6\) C) / (0.1005 \(m)^2\)
E ≈ 1.622 x \(10^6\) N/C
Since the electric fields from the two charges at the lower corners have equal magnitudes and point in the same direction (upward), the total electric field at point B is twice the magnitude of the individual electric field:
Electric field at point B = 2 * E ≈ 2 * 1.622 x \(10^6\) N/C
Electric field at point B ≈ 3.244 x \(10^6\) N/C
Therefore, the electric field at point B, midway between the upper left and right corners of the square, is approximately 3.244 x \(10^6\)N/C upward.
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A small bag of sand is released from an ascending hot‑air balloon whose constant, upward velocity is 0=2.95 m/s. Knowing that at the time of the release the balloon was 37.8 m above the ground, determine the time it takes for the bag to reach the ground from the moment of its release. Use =9.81 m/s2.
The time taken is approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.
To determine the time it takes for the bag of sand to reach the ground, we can use the kinematic equation for vertical motion. The equation is given as:
h = ut + (1/2)gt^2
Where:
h = height (37.8 m)
u = initial velocity (0 m/s)
g = acceleration due to gravity (-9.81 m/s^2, considering downward motion)
t = time
Since the balloon is ascending with a constant upward velocity of 2.95 m/s, the initial velocity of the bag is also 2.95 m/s in the upward direction. Therefore, we need to consider the initial velocity as negative.
Substituting the known values into the equation, we have:
37.8 = (-2.95)t + (1/2)(-9.81)t^2
Simplifying the equation further, we get:
-4.905t^2 - 2.95t + 37.8 = 0
Solving this quadratic equation for time, we find two solutions: t = 2.08 s and t = -3.61 s. Since time cannot be negative, we discard the negative value.
Therefore, it takes approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.
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Barbara's teacher wants her to design an oven that can be powered by a renewable resource. Which of the following energy sources could Barbara use?
A
coal
B
gasoline
C
uranium
D
sunlight
Barbara's teacher wants her to design an oven that can be powered by a renewable resource. Barbara can use D) sunlight to power an oven .
A renewable resource can replenish itself at the rate it is used, a renewable resource of energy can be regenerate itself naturally , while a nonrenewable resource has a limited supply as it can extinct .
Coal , gasoline and uranium generate high energy , hence are used where there is a need of more energy . As far as sunlight is concerned , it can be concentrated and can be used to generate power for small used such as heating an oven or cooker which are called solar oven and solar cooker . Solar ovens trap light particles, called photons, to generate heat.
hence , correct option is
D) sunlight
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Select the correct answer. Which graphs show the correct relationship between kinetic energy and mass? A. Graph representing a relationship between mass on the x-axis and kinetic energy on the y-axis. the line starts at the origin and increases upwards B. Graph representing the relationship between mass on the x-axis and kinetic energy on the y-axis. the curve starts at the origin and keeps on increasing C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis D. Graph representing a relationship between mass on the x-axis and kinetic energy on the y-axis. the line starts at the origin and increases as it goes with a small bend Reset Next
C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.
What is kinetic energy?
Kinetic energy is the energy possessed by a body due to its motion.
K.E = ¹/₂mv²
where;
m is mass of the objectThe kinetic energy of a body is directly proportional to the mass of the object.
Thus, the correct relationship between kinetic energy and mass is Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.
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A spacecraft has a momentum of 20,000 kg-m/s, and a mass of 250 kg. What is the magnitude of its velocity?
A. 80 m/s
B. 800 m/s
C. 400 m/s
D. 40 m/s SUBMIT
Answer:
A. 80 m/sExplanation:
The velocity of the spacecraft can be found by using the formula
\(v = \frac{p}{m} \\ \)
p is the momentum
m is the mass
From the question we have
\(v = \frac{20000}{250} = \frac{2000}{25} \\ \)
We have the final answer as
80 m/sHope this helps you
Which statement places events during the Space Race in the correct order from the earliest to the most recent?
1.NASA was established, US satellite Explorer launched, first man walked on the moon, first man orbited the Earth
2.first man walked on the moon, first man orbited the Earth, NASA was established, US satellite Explorer launched
3.US satellite Explorer launched, NASA was established, first man orbited the Earth, first man walked on the moon
4. first man orbited the Earth, first man walked on the moon, US satellite Explorer launched, NASA was established
Answer:
3,1,4,2
Explanation:
Answer:C
Explanation:
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.50 km/s in the +x-direction experiences a force of 2.25 \times 10^{-16} N2.25×10 −16 N in the +y-direction, and an electron moving at 4.75 km/s in the -z-direction experiences a force of 8.50 \times 10^{-16} \mathrm{N}8.50×10 −16 N in the +y-direction.
(a) What are the magnitude and direction of the magnetic field?
(b) What are the magnitude and direction of the magnetic force on an electron moving in the -y-direction at 3.20 km/s?
Answer:
a) B = 0.9375 T -z, b) B = 1.54 T
Explication
a) The magnetic force is
F = q v x B
f = q v B sin θ
bold indicates vectors
For direction let's use the right hand rule.
If the charge is positive
the flea in the direction of velocity, toward + x
the fingers extended in the direction of B
the palm the direction of the force + and
therefore the magnetic field goes in the direction of -z
F = q v B
2.25 10-16 = 1.6 10-19 1.50 103 B
B = 2.25 10-16 / 2.4 10-16
B = 0.9375 T -z
b) now an electron
thumb speed direction, -z
opposite side of palm force + y
therefore the direction of the magnetic field is + x
B = F / qv
B = 8.5 10-16 / 1.16 10-19 4.75 103
B = 1.54 T
How does a real image differ from a virtual image?
Answers:
A real image is always upright and never inverted.
A real image is formed by extending the rays back to where they appear to come from.
A virtual image is always smaller than the object.
Light rays actually pass through a real image.
Answer:
Real images are obtained using a converging lens or a concave mirror. The size of the real image depends upon the placement of the object. A virtual image is an upright image that is achieved where the rays seem to diverge. A virtual image is produced with the help of a diverging lens or a convex mirror.
Answer:
Light rays actually pass through a real image.
Explanation:
Option C is somehow correct but the hurdle is that it's only for convex mirror
The concave mirror always produce a virtual image larger than object
So option D is correct
Consider an object moving in the plane whose location at time t seconds is given by the parametric equations:
x(t)=4cos(?t)
y(t)=3sin(?t).
Assume the distance units in the plane are meters.
(a) The object is moving around an ellipse (as in the previous problem) with equation:
x^2/a^2 + y^2/b^2 = 1
where a= ______ and b= .___________
The object moves around an ellipse with values of a=4 and b=3.
The object is moving around an ellipse with the parametric equations:
x(t) = 4cos(?t) and y(t) = 3sin(?t).
To find the values of a and b, we can compare the parametric equations with the equation of the ellipse:
x²/a² + y²/b² = 1
We can see that the coefficient of cos(?t) in the parametric equation for x(t) corresponds to the value of 'a' in the equation of the ellipse, and the coefficient of sin(?t) in the parametric equation for y(t) corresponds to the value of 'b' in the equation of the ellipse.
Therefore, the values of a and b are:
a = 4 and b = 3
So the equation of the ellipse is:
x²/4² + y²/3² = 1
The object is moving around an ellipse with the equation:
x²/16 + y²/9 = 1
where a = 4 and b = 3.
Therefore, the object is moving around an ellipse with equation x²/a² + y²/b² where a=4 and b=3.
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through which material does the light travel the fastest?
Describe two 'beneficial' aspects from the last 10,000 years of humanity, as well as two 'dis-advantageous' aspects. Agriculture should be your guiding point here.
Answer:
Two beneficial aspects of the last 10,000 years of mankind have been the development of writing and the development of civilized communities.
Thus, writing has allowed the recording of the different historical events that have taken place during the development of humanity, setting precedents for subsequent generations, allowing documenting the progress that humanity has been achieving. On the other hand, the development of civilized communities around urban systems has allowed for greater economic and social development on the part of human groups, which through cooperation have been acquiring an increasingly higher quality of life.
On the other hand, two negative aspects of these years have been the world overpopulation and the pollution of the planet.
Thus, the amount of the world's population has been getting closer and closer to the limit of our planet's carrying capacity, which could lead humanity to a point where resources are definitely scarce, causing famines and various catastrophes. On the other hand, the pollution arising from the development of industrial societies has notably undermined the health of individuals and has damaged their standard of living, while causing irreparable damage to the natural environment.
forms of energy are those a system possess as a whole with respect to some outside reference frame, such as kinetic and potential energies.
Total energy is preserved as potential energy is converted to kinetic energy.In contrast to kinetic energy, which an item possesses as a result of its motion, potential energy is the energy that an object possesses as a result of its height, position, or arrangement.
An object's mechanical energy is equal to the product of its potential energy and kinetic energy.
When we compress a spring, the energy from our hand is stored there as the spring's potential energy, which is what holds the spring in that certain position. Its whole potential energy is there at that point. The spring has a tendency to extend outside and bounce outwards as soon as we release it. It implies that it gains kinetic energy. As a result, we may infer that potential energy is changing into kinetic energy.
Additionally, the spring will receive the identical quantity of kinetic energy that is being lost as potential energy, maintaining a constant total mechanical energy. It implies that the spring's whole energy has been saved.
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