BeCO3 is soluble or insoluble in water​

Question id : 33544103

Answer:

To calculate the maximum β-energy in the decay of carbon-14 (14C) to nitrogen-14 (14N), we need to use the mass difference between the initial and final nuclei. The β-decay process involves the conversion of a neutron into a proton, emitting a β-particle (electron) and an electron antineutrino.

The mass difference (∆m) between 14C and 14N is given by:

∆m = mass(14C) - mass(14N)

= 14.003241u - 14.003074u

= 0.000167u

The β-energy (Eβ) is related to the mass difference (∆m) by Einstein's mass-energy equivalence equation: E = ∆mc^2, where c is the speed of light.

Eβ = ∆m * c^2

Now, we need to convert the mass difference (∆m) from unified atomic mass units (u) to kilograms (kg) before using it in the equation. The conversion factor is approximately 1.66053906660 × 10^−27 kg/u.

∆m_kg = ∆m * (1.66053906660 × 10^−27 kg/u)

Next, we'll calculate the β-energy by substituting the values into the equation:

Eβ = ∆m_kg * c^2

The speed of light (c) is approximately 2.998 × 10^8 m/s.

Eβ = ∆m_kg * (2.998 × 10^8 m/s)^2

Let's perform the calculations:

∆m_kg = 0.000167u * (1.66053906660 × 10^−27 kg/u)

≈ 2.77273363362 × 10^−29 kg

Eβ = (2.77273363362 × 10^−29 kg) * (2.998 × 10^8 m/s)^2

≈ 2.49344368869 × 10^−13 J

The maximum β-energy in the decay of 14C to 14N is approximately 2.493 × 10^−13 Joules.

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The solutions are as follows:

Solution A (2.78% NaCl): Crenation will occur. The concentration of NaCl is higher than the normal physiological concentration inside the red blood cells, leading to a hypertonic environment. As a result, water will move out of the cells, causing them to shrink and undergo crenation.

Solution B (2.63% glucose): Neither crenation nor hemolysis will occur. The glucose concentration is similar to that inside the red blood cells, resulting in an isotonic environment. Therefore, there will be no net movement of water into or out of the cells, and they will maintain their normal shape.

Solution C (distilled water): Hemolysis will occur. Distilled water is hypotonic compared to the internal environment of the red blood cells. Water will move into the cells, causing them to swell and eventually burst, resulting in hemolysis.

Solution D (8.04% glucose): Neither crenation nor hemolysis will occur. The high concentration of glucose creates a hypertonic environment, similar to Solution A, causing water to move out of the cells. However, the presence of glucose balances the osmotic pressure, preventing significant changes in cell shape.

Solution E (5.0% glucose and 0.9% NaCl): Neither crenation nor hemolysis will occur. The presence of both glucose and NaCl in near physiological concentrations creates an isotonic environment, where the osmotic pressure is balanced, resulting in no significant changes in red blood cell shape.

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Answer:

Plastic pollution are harmful on land because;

The temperature (in k) is 469.4 .The average speed of hydrogen molecules at typical conditions of temperature and pressure is 1.70 103 ms1.

Explanation:

F = 243(9/5) + 32

  = 437.4 + 32

  = 469.4.

The temperature (in k) is 469.4 .

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Answer:

When the nucleus is in radiation, the nuclei will become unstable and will decay overtime.

Answer:c

Explanation: the proportions of components can vary

Answer:

S + HNO3 = H2SO4 + NO2 + H2O

Explanation:

Answer:

Based on stoichiometry HNO3 to H2O is 6:2

Use 9 grams to find the moles of HNO3

9 grams/63g/mol=0.143 moles of HNO3

HNO3:H2O

6:2

0.143*2/6=0.048

H2O moles is 0.048moles

Mass of water =0.048moles*18g/mol=0.864g

To the nearest tenth=0.9grams

Explanation:

I think this is right

The total mass of 4 tin is in grams is 580 grams and in kg is 0.58kg.

One tin of chopped tomatoes weight is 145 grams

and we have to calculate it for 4

so for 4

145*4 =580 grams

and we have to change it into kilograms so

580 /1000  = .58kg

By 1,000, divide the number of grams.

To convert from grams to kilograms, simply divide by 1,000 because there are 1,000 grams in every kilogram. If necessary, construct the equation using fractions. Put the number of grams over 1 and divide it by the conversion factor, which is 1 kg / 1,000 g. Your answer in kilograms will result from the cancellation of the grams. Remember to use the appropriate units to mark your response.

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The molar mass of the osmotic pressure of a 2.10 mL solution containing 0.181 g of protein dissolved in water is determined to be 18.30 torr at 22° C is 234.89 g/mol.

To solve for the molar mass of the protein, we need to use the formula:

π = MRTi

Where:

First, we need to calculate the molarity of the solution. We can use the formula:

M = n/V

Where:

We can calculate the number of moles of the protein by dividing its mass by its molecular weight:

n = m/MW

Where:

Plugging in the given values:

We can solve for M by rearranging the formula for π:

M = π / (RT)

Plugging in the values:

M = (18.30 torr) / (0.08206 L·atm/mol·K × 295.15 K)

M = 0.771 mol/L

Now, we can solve for the molecular weight (MW) by rearranging the formula for M:

MW = m / n

Plugging in the values:

MW = (0.181 g) / (0.771 mol/L)

MW = 234.89 g/mol

Therefore, the molar mass of the protein is 234.89 g/mol.

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Answer:

4.1143797572516005

Explanation:

I think this is what you're asking, I'm not sure

The number of grams in a mole is determined by the substance. To calculate it, multiply the atomic or molecular mass of your substance by the number of moles you have.

Moles are in 100. mg of   C26 H23 N7 O2  = 2.15 ×  \($10^{-4}\) mole

Therefore,

mole concept establishes a standard for determining reaction stoichiometry.

molecular weight = 465.5 g

100. mg = .1 g.

moles are in 100. mg of    C26 H23 N7 O2  = 2.15 × \($10^{-4}\)   mole

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The moles of oxygen gas occupy a 300 ml container at 2.0 atm and 125 degrees Celsius is 0.018 moles.

To calculate the number of moles of oxygen gas occupying a 300 ml container at 2.0 atm and 125 degrees Celsius, we can use the ideal gas law equation:

PV = nRT

P is the pressure of the gas (in atmospheres)

V is the volume of the gas (in liters)

n is the number of moles of the gas

R is the ideal gas constant (0.0821 L atm/(mol K))

T is the temperature of the gas (in Kelvin)

First, let's convert the given temperature from Celsius to Kelvin:

T = 125 degrees Celsius + 273.15 = 398.15 K

Next, we need to convert the volume from milliliters to liters:

V = 300 ml / 1000 ml/L = 0.3 L

Now we can rearrange the ideal gas law equation to solve for the number of moles (n):

n = (PV) / (RT)

Substituting the given values:

n = (2.0 atm * 0.3 L) / (0.0821 L atm/(mol K) * 398.15 K)

n = 0.018

Therefore, the number of moles of oxygen gas occupying the 300 ml container at 2.0 atm and 125 degrees Celsius is approximately 0.018 moles.

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Answer:

\(2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}\)

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

\(2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}\)

Best regards!

Can you please add a picture of the case??

The rate at which N\(_{2}\) disappears is 0.016 M/s, while the rate at which H\(_{2}\) disappears is 0.0213 M/s.

In the balanced chemical equation N\(_{2}\)(g) + 3 H\(_{2}\) (g) → 2NH\(_{3}\)(g), the stoichiometric coefficients represent the mole ratios between the reactants and products.

Since the reaction rate is given for NH\(_{3}\), we can determine the rates of disappearance of  N\(_{2}\) and H\(_{2}\) by comparing their stoichiometric ratios in the reaction.

The stoichiometric ratio between  N\(_{2}\) and NH\(_{3}\) is 1:2, meaning for every mole of  N\(_{2}\) consumed, 2 moles of NH\(_{3}\) are produced. Therefore, the rate of disappearance of  N\(_{2}\) is half of the rate of formation of NH\(_{3}\).

Similarly, the stoichiometric ratio between H\(_{2}\) and NH\(_{3}\) is 3:2. This means that for every 3 moles of H\(_{2}\) consumed, 2 moles of NH\(_{3}\) are produced. Therefore, the rate of disappearance of  H\(_{2}\) is (2/3) times the rate of formation of NH\(_{3}\).

Given the rate of formation of NH\(_{3}\) as 0.032 M/s, the rate of disappearance of  N\(_{2}\) would be 0.016 M/s (0.032 M/s ÷ 2), and the rate of disappearance of  H\(_{2}\) would be approximately 0.0213 M/s (0.032 M/s × 2/3).

Therefore, the rate of disappearance of  N\(_{2}\) is 0.016 M/s, and the rate of disappearance of  H\(_{2}\) is 0.0213 M/s.

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The total charge on the right-hand side is 94-1=93, so the atomic number is 93.

The total mass on the right-hand side is 239+0=239, so the mass number is 239.

The temperature of the system in equilibrium is 301.96 K.

The equilibrium temperature of the system depends on the heat released from both gold and water. The total heat received by the system will equal to total heat released by objects. It should follow

Q released = Q received

The heat can be defined by

Q = m . c . ΔT

where Q is heat, m is mass, c is the specific heat constant and ΔT is the change in temperature.

The given parameters are

m1 = 62.5 g = 0.0625 kg

T1 = 650 K

m2 = 165 g = 0.165 kg

T2 = 298 K

c1 = 126 J/kgK

c2 = 4200 J/kgK

Lets assume that the value of equilibrium temperature is T. Hence,

Q released = Q received

m1 . c1 . ΔT1 = m2 . c2 . ΔT

0.0625 . 126 . (T1 - T) = 0.165 . 4200 . (T - T2)

0.0625 . 126 . (650 - T) = 0.165 . 4200 . (T - 298)

5118.75 - 7.875T = 693T - 206514

700.875T = 211632.75

T = 301.96 K

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The optimum temperature for sucrase activity is 37 °C. The hydrolysis of sucrose is slowest at 0 °C.

The optimum temperature for sucrase activity is 37 °C, which means that the enzyme functions most efficiently at this temperature. As the temperature deviates from the optimum, the enzyme activity decreases. Therefore, the hydrolysis of sucrose would be slowest at a temperature that is significantly lower or higher than 37 °C.

Among the given choices, the temperature that is significantly lower than 37 °C is 0 °C (choice e). Enzyme activity is typically greatly reduced or completely halted at very low temperatures, as the enzyme molecules become less active or may even denature. Therefore, the hydrolysis of sucrose would be slowest at 0 °C.

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The enthalpy change for this reaction will be different from the original reaction, as the enthalpy of vaporization of water needs to be taken into account. However, the value of ΔHΔ will remain the same, as it is a property of the reaction and not dependent on the physical state of the products.

(a) If the equation is multiplied throughout by 2, the coefficients of all the species in the reaction will be doubled. Therefore, the new balanced equation will be:
4CH3OH(g) + 6O2(g) ⇀⇀ 4CO2(g) + 8H2O(l)
The value of ΔHΔ will remain the same, as it is a property of the reaction and not dependent on the coefficients.

(b) If the direction of the reaction is reversed, the reactants will become the products and vice versa. Therefore, the new balanced equation will be:
2CO2(g) + 4H2O(l) ⇀⇀ 2CH3OH(g) + 3O2(g)
The value of ΔHΔ will also be reversed in sign, as the enthalpy change is defined as the energy released or absorbed when the reaction occurs in a specific direction. Therefore, ΔHΔ will be +1452.8 kJ/mol.

(c) If water vapor instead of liquid water is formed as the product, the balanced equation will be:
2CH3OH(g) + 3O2(g) ⇀⇀ 2CO2(g) + 4H2O(g)
The enthalpy change for this reaction will be different from the original reaction, as the enthalpy of vaporization of water needs to be taken into account. However, the value of ΔHΔ will remain the same, as it is a property of the reaction and not dependent on the physical state of the products.

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Answer:

When you are in the laboratory and take a direct sniff the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs. When its necessary to smell chemicals in the lab, the proper technique is to cup your hand above the container and waft the air towards your face.

Gas is a naturally odourless substance, but the completely harmless artificial smell is added to make it more detectable. The substance is called mercaptan and gives off a strong sulphur like smell.

Answer:

Method: Measure out 25 cm3 of 0.5 mol dm3 lead(II)nitrate solution and add it to a small beaker. Measure out 25 cm3 of 0.5 mol dm3 of potassium sulfate add it to the beaker and mix together using a stirring rod.

Answer:

c

Explanation:

Answer:

A. a best guess explanation

Explanation:

A scientific theory explains why something behaves the way it does and is usually backed up by different sources. They are not speculations and can be proven. Those which are speculations and are not proven are called hypothesis. A scientific theory can also be replaced, if it is found that it does not produce valid results, or if a better theory is proposed which is made of one or more old theories.

In C4 (Carbon 4) pants, phosphenolpyruvate (PEP) reacts with carbon dioxide to directly generate oxaloacetate in mesophyll cell. The correct answer is option d.

C4 photosynthesis is a mechanism for carbon fixation in which carbon dioxide is first fixed into a four-carbon molecule and then transported to specialized cells (bundle sheath cells) in plant leaves. The pathway was discovered in 1967 in the family Amaranthaceae (Chenopodiaceae), but it is now known to exist in at least 19 plant families, including many important crop species such as maize, sorghum, and sugarcane.

In C4 photosynthesis, phosphenolpyruvate (PEP) reacts with carbon dioxide to produce oxaloacetate in mesophyll cell. The mesophyll cell is a kind of photosynthetic cell in the leaves of vascular plants that are responsible for photosynthesis.

The compound is then converted to malate or aspartate and transported to the bundle sheath cell, where carbon dioxide is released and fixed by the enzyme Rubisco (ribulose-1,5-bisphosphate carboxylase/oxygenase). Therefore, the correct answer is option D.

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I Hope this will Help You:-

Organisms need to detect and respond to changes in their internal and external environment. This is because the conditions inside our body must be carefully controlled for it to function effectively and survive. The control systems that allow organisms to respond to changes are incredibly important.

Answer:

molecule

Explanation:

The stroke volume in the next few cardiac cycles will be 100 ml if the end-diastolic volume is increased from 135ml to 165m.

The formula for stroke volume is given as;

SV = EDV - ESV

Here SV represents stroke volume, EDV represents end-diastolic volume and ESV represents end-systolic volume.

First, we calculate this person's end-systolic volume as follows;

If the person’s stroke volume was 70ml and his initial diastolic volume was 135 ml, then:

70 = 135 - ESV

70 - 135 = -ESV

-65 = -ESV

ESV = 65ml

Now the stroke volume in the next few cycles if the end-diastolic volume increase to 165 ml can be calculated as follows;

SV = 165 - 65

SV = 100ml

Therefore, the stroke volume in the next few cardiac cycles is calculated to be 100ml.

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The temperature of a given volume of water changes as heat is added at a consistent pace, as shown by the water heating curve. The temperature of the water does not vary throughout a phase shift, creating a plateau on the graph.

When a substance is heated to a material-specific phase-change temperature, the phase transition from solid to liquid occurs immediately.

Water has a specific heat capacity of 4.18 J/g/°C. The amount of heat, or Q, is what we want to know. To do this, we would apply the formula Q = m•C•T. Knowing the m and C allows for the calculation of the T.

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Answer:

28

Explanation:

it states that the atom is neutral, meaning the number of electrons and protons are the same. so if there are 13 electrons, there are 13 protons. And the mass number is neutrons plus protons. So 13+15 is 28

Answer:

c

Explanation:

im pretty sure this is correct if not plz comment the correct answer so i can b sure how to find it =)

Answer:

C. To work on the mechanics of a pitchers throw
or... A. To design a stadium with the maximum number of seats

Explanation:

The molecular formula of the compound is PCl₃ if the molecular mass of the compound is 137.32 g/mol.

An empirical formula can be described as a formula that tells about the relative ratios of different atoms in a compound.

The empirical formula for this compound containing phosphorus and chlorine can be calculated as follows;

As the compound is composed of 22.5% phosphorous and 77.5% chlorine, therefore;

Phosphorus = (22.5/100) × 137.32 = 0.225 × 137.32 = 30.897

Chlorine = (77.5/100) × 137.32 = 0.775 × 137.32 = 106.423

Now we can find the moles of each atom by using their molar mass as follows;

Phosphorus = 30.897 ÷ 30.97 = 0.998 moles

Chlorine = 106.423 ÷ 35.453 = 3.002 moles

Now dividing each mole value by the smallest determined number of moles (0.998) as follows;

Phosphorus = 0.998 / 0.998 = 1 mole

Chlorine = 3.002 / 0.998 = 3.008 ≈ 3 moles

Therefore the molecular formula of the compound will be PCl₃.

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Answer:

b

Explanation: