What is the value of X?
Enter your answer in the box

Answer:

1,005.3 cm

Step-by-step explanation:

The radius: r = diameter/2 = 80/2 = 40 mm = 4 cm. The height: h = 20 cm. Conclusion: The volume is 1,005.3 cubic cm (approximately)

Answer:

\(\frac{5}{y^2}\)

Step-by-step explanation:

So you have the following expression: \(5y^_-2}\)

There is no parenthesis, so the -2 exponent is only applied to the y, and not the 5.

To rewrite a negative exponent, you can use the property: \((\frac{a}{b})^{-x}=(\frac{b}{a})^x\)

You can derive this property from the exponent property: \(\frac{x^a}{x^b}=x^{a-b}\)

which essentially consists of just cancelling out the x's from the numerator and the denominator, but in some cases you're "cancelling" out more x's in the denominator, than there are in the numerator.

Take for example: \(\frac{x^2}{x^5}\), using the quotient of exponents, we can simplify it to: \(x^{2-5}=x^{-3}\)

And to see why this happening, let's expand out the fraction: \(\frac{x^2}{x^5}\implies \frac{x*x}{x*x*x*x*x}\), as you can see in this fraction there are two x's in the numerator and there are also 2 in the denominator (more than 2, but there are at least 2 in the denominator), thus we can cancel out two of the x's leading to the fraction: \(\frac{1}{x*x*x}\)

So by definition: \(x^{-3}=\frac{1}{x*x*x}=\frac{1}{x^3}\)

So negative exponents are just the reciprocal in a way, or more formally: \((\frac{a}{b})^{-x}=(\frac{b}{a})^x\)

So in your case specifically we can rewrite y^(-2) as: \(5 * y^{-2}\implies5*\frac{1}{y^2}\implies \frac{5}{y^2}\)

Answer:

34

Step-by-step explanation:

The sum of the angles of a triangle is 180

26x+6 + 21x-1 +11x+1 = 180

Combine like terms

58x +6 = 180

Subtract 6 from each side

58x = 180-6

58x = 174

Divide by 58

58x/58 =174/58

x=3

We want <C

<C = 11x+1 = 11*3+1 = 33+1 = 34

Using the simple interest formula, the interest charge on his next month's bill if he has a remaining balance of $8,000 is $53.6.

In the given question we have to find the interest charge on his next month's bill if he has a remaining balance of $8,000.

So the principal amount = $8000

Preston credit card has a 8% A.P.R.

As we know that 1 year = 12 months

So the rate for one month is

R= 8/12%=0.67%

time(T) = 1

The formula of simple interest is

I=PRT/100

where I=interest

P=principal amount

R=rate of interest

T=time

Now putting the value

I=8000*0.67*1/100

I=5360/100

I=53.6

Hence, the interest charge on his next month's bill if he has a remaining balance of $8,000 is $53.6.

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Answer:

Step-by-step explanation:

Step 1:First Make 3/4 and 5/6 into like fractions.Find the L.C.M of 4 and  

            6,which is 12.

            3*3/4*3=9/12

             5*2/6*2=10/12

Step 2:Subtract 9/12 from 10/12,which is 1/12.

Based on the description provided, the section of the chart that represents the point where a bill is first debated in subcommittees is: C and D

In the given chart, the parallel lines represent the progression of a bill through various stages in the legislative process. The boxes on the top line represent one set of actions or steps, while the boxes on the bottom line represent another set of actions or steps.

Moving from left to right on the chart, the boxes A and B are paired, representing a particular stage in the process. Similarly, the boxes C and D are paired, indicating another stage in the process.

In the context of the question, the stage where a bill is first debated in subcommittees is represented by the boxes C and D.

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The transformation of f(x) to g(x) is :

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = x

g(x) = 1/9x - 2

The graph of the functions f(x) and g(x) are added as an attachment

And we have the transformations to be:

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Answer:

68 is the maximum

Step-by-step explanation:

look at the greatest number

We divide the sum of products by the sum of inverse variances to get the weighted mean:

To find the weighted mean of the experimental measurements of the mean lifetime of the K_s meson listed in the Particle Data Tables, we need to calculate the sum of the product of each measurement and its inverse variance, and divide it by the sum of the inverse variances. The inverse variance is the square of the inverse of the uncertainty.

First, we calculate the inverse variances for each measurement:

0.0021^-2 = 226757.3696
0.0014^-2 = 510204.0816
0.0016^-2 = 390625
0.0044^-2 = 51612.90323
0.009^-2 = 12345.67901
0.0032^-2 = 97656.25
0.0048^-2 = 43402.77778
0.0045^-2 = 49450.61728

Next, we calculate the product of each measurement and its inverse variance:

0.8971 * 226757.3696 = 203395.4087
0.8941 * 510204.0816 = 456286.5389
0.8929 * 390625 = 348791.5625
0.8920 * 51612.90323 = 46030.23399
0.881 * 12345.67901 = 10866.02305
0.8924 * 97656.25 = 87133.35024
0.8937 * 43402.77778 = 38787.83558
0.8958 * 49450.61728 = 44315.55869

Then, we sum the products and the inverse variances:

Sum of products = 203395.4087 + 456286.5389 + 348791.5625 + 46030.23399 + 10866.02305 + 87133.35024 + 38787.83558 + 44315.55869 = 1248606.5116

Sum of inverse variances = 226757.3696 + 510204.0816 + 390625 + 51612.90323 + 12345.67901 + 97656.25 + 43402.77778 + 49450.61728 = 1471054.6785

Finally, we divide the sum of products by the sum of inverse variances to get the weighted mean:

Weighted mean = 1248606.5116 / 1471054.6785 = 0.848892685

The uncertainty in the mean is the square root of the inverse of the sum of the inverse variances:

Uncertainty in the mean = (1471054.6785)^-0.5 = 0.000822199

Therefore, the weighted mean of the data is 0.848892685 plusminus 0.000822199 in units of 10^-10 s.

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Answer:

there are 120 possible points in the sample space if we select 3 batteries at random from a bag containing 6 batteries of different brands.

Step-by-step explanation:

The counting principle states that if there are n ways to do one thing and m ways to do another, then there are n x m ways to do both.

In this case, we want to determine how many ways we can select 3 batteries out of 6. Using the counting principle, we can break down the selection process into three steps:

Select the first battery. There are 6 choices for the first battery.

Select the second battery. There are 5 choices left for the second battery, since we've already selected one.

Select the third battery. There are 4 choices left for the third battery.

Using the counting principle, we can multiply the number of choices for each step to get the total number of ways to select 3 batteries:

6 x 5 x 4 = 120

Therefore, there are 120 possible points in the sample space if we select 3 batteries at random from a bag containing 6 batteries of different brands.

The problem, we create two equations to describe the relationship between the number of green and blue marbles in the bag and the total number of marbles in the bag. Then we used one of the equations to figure out how many green and blue marbles were in the bag.

In this problem, we have a bag full of green and blue marbles, with a total of 48 marbles in the bag. We are also told that there are 38 more green marbles than blue marbles.

We can set up two equations that describe the relationship between the number of green marbles, the number of blue marbles, and the total number of marbles in the bag to solve for the number of green and blue marbles in the bag.

One method for selecting variables is to have x represent the number of blue marbles in the bag. The total number of green marbles is then x + 38. And the bag contains 48 marbles in total.

As a result, we have two equations:

x + (x + 38) = 48

2x + 38 = 48

By adding the two expressions for the number of green and blue marbles, the second equation is obtained.

Then, subtract 38 from both sides of the second equation to find x:

2x + 38 = 48

2x = 10 \sx = 5

This means the bag contains 5 blue marbles and 5 + 38 = 43 green marbles.

So, in this problem, we create two equations to describe the relationship between the number of green and blue marbles in the bag and the total number of marbles in the bag. Then we used one of the equations to figure out how many green and blue marbles were in the bag.

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Answer: 15.77

Step-by-step explanation: We know that Milans car had 19.57 gallons of fuel, so I subtracted 19.57 - 3.8 to get my answer.

Answer:

The answer for the first one is 1 and the second answer is 12i.

Step-by-step explanation:

The value of the given imaginary number i¹² will be 1 thus option (A) is correct.

A complex number is the sum of a real number and an imaginary number.

The idea of a complex number has come by solving a quadratic equation that has root as negative under root.

If we solve x² + 1 = 0 ⇒ x = √(-1) which is called as iota(i).

The value of iota(i) is given as i = √(-1).

By the law of indices,

i¹² = (i²)⁶

⇒ (-1)⁶

Since the even exponents of a negative number give positive output thus  (-1)⁶ = 1.

Thus, i¹² = 1

Hence "The value of the given imaginary number i¹² will be 1".

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a. The answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. The answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

a. To represent 20 longs in base seven, we need to find the fewest number of multibase blocks required.

In base seven, we have the following conversions:

1 long = 1 unit

1 flat = 10 units

1 block = 10 flats

To represent 20 longs, we can use 2 flats (each flat representing 10 units) and 0 units since there are no remaining units.

So, the fewest number of multibase blocks required would be 2 flats.

Therefore, the answer is: The fewest number of multibase blocks required to represent 20 longs in base seven is 2 flats.

b. To represent 10 longs in base three, we need to find the fewest number of multibase blocks required.

In base three, we have the following conversions:

1 long = 1 unit

1 flat = 3 units

1 block = 3 flats

To represent 10 longs, we can use 3 flats (each flat representing 3 units) and 1 unit since there is one remaining unit.

So, the fewest number of multibase blocks required would be 3 flats and 1 unit.

Therefore, the answer is: The fewest number of multibase blocks required to represent 10 longs in base three is 3 flats and 1 unit.

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Answer: C

Step-by-step explanation:

The rest of the quadrilaterals provided have 2 pairs of parallel lines.

The choice is:

Explanation:

The quadrilateral that has exactly one pair of parallel lines is called a trapezoid.

Here's what a trapezoid looks like :

\(\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\linethickness{0.3mm}\qbezier(0,0)(0,0)(1,3)\qbezier(5,0)(5,0)(4,3)\qbezier(1,3)(1,3)(4,3)\qbezier(3,0)(8.2,0)(0,0)\put(-0.5,-0.3){$\sf A$}\put(5.3,-0.3){$\sf B$}\put(4.2,3.1){$\sf C$}\put(0.6,3.1){$\sf D$}\end{picture}\)

Answer:

it would be 6 cups I don't know  how to explain though

Step-by-step explanation:

n⁴ - 2n³ - 23n² + 24n + 144 is the standard form of given zeroes.

What is a linear equation in mathematics?

A linear equation is an algebraic equation of the form y=mx+b. m is the slope and b is the y-intercept. The above is sometimes called a "linear equation in two variables" where y and x are variables.

                              A linear equation is an equation that raises a variable to the first power. ax+b = 0 is an example of a 1 variable. x is a variable and a and b are real numbers.  

Roots : -3(mult . 2), 4(mult.2)

the function is given as

     f(n) = (n + 3)² (n - 4)²

         = (n + 3) (n + 3 ) ( n - 4 ) ( n - 4)

        = (n² + 6n + 9) (n² - 8n + 16 )

        = n⁴ - 8n³ + 16n² + 6n³ - 48n² + 96n + 9n² - 72n + 1

collecting like term,

    f(n) = n⁴ - 2n³ - 23n² + 24n + 144

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The value of the variable "x" is 11.

We have a triangle. The vertices of the triangle are K, L, and M. The side KM is extended from point M to point N. The measures of the angles MKL, LMN, and KLM are (3x + 19)°, (7x + 5)°, and (2x + 8)°, respectively. We need to find out the value of the variable "x".

The angles LMK and LMN form a linear pair. It means they are supplementary angles. The sum of the angles is 180°.

∠LMK + ∠LMN = 180°

∠LMK + (7x + 5)° = 180°

∠LMK = 180° - (7x + 5)°

In the triangle KLM, we will use the angle sum property of a triangle. The sum of all the angles in a triangle is equal to 180°.

∠K + ∠L + ∠M = 180°

(3x +19)° + (2x + 8)° + [180° - (7x + 5)°] = 180°

3x +19 + 2x + 8 + 180 - 7x - 5 = 180

-2x + 22 = 0

2x = 22

x = 11

Hence, the value of the variable "x" is 11.

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9514 1404 383

Answer:

  no

Step-by-step explanation:

The angle of the ramp as designed by the planning department is ...

  tan(angle) = (3 ft)/(25 ft)

  angle = arctan(3/25) ≈ 6.84°

This angle exceeds the required 4.75°, so does not meet code.

Answer:

42

Step-by-step explanation:

Answer:

range = 7.87

X = 62.12, X²= 164.3516

mean = 1.2424

variance = 1.779

standard deviation = 1.33379

coefficient of variation = 107.3559%

Step-by-step explanation:

a.) The range =

highest number - lowest number

= 7.89 - 0.02

= 7.87

b.) from the attachment I solved for X and X²

∑X = 62.12

∑X² = 164.3516

c.)

the mean = ∑x/n

n = 50

= 62.12/50

= 1.2424

variance =

σ² = [∑x²-(∑x)²/n] / n-1

= [164.3516 - (62.12)²/50] / 50-1

= 164.3516 - 77.17788/49

= 87.173712/49

= 1.779

standard deviation = √σ

= √1.779

= 1.33379

d. coefficient of variation

= σ/mean * 100

= 1.33379/1.2424 * 100

= 107.3559

This number tells us that the the standard deviation of the time to failure is larger than the average time. option 3 is the correc4 answer here

A) The range of the given values is; 7.87

B) The values of  ∑X and ∑X²  are respectively; 62.12 and 164.3516

C) The values of the sample mean, variance and standard deviation are respectively; 1.24, 1.78 and 1.334

D) The coefficient of variation is; 107.356

A) Formula for range is;

Range = Highest term - Lowest term

Range = 7.89 - 0.02

Range = 7.87

B) Sum of all the given 50 epoxy samples is gotten to be;

∑X = 62.12

From online statistics calculator, we have; ∑X² = 164.3516

C) Formula for sample mean here is;

x' = ∑x/n

x' = 62.12/50

x' = 1.24

Formula for variance is;

σ² = [∑x² - [(∑x)²/n]]/(n - 1)

σ² = (164.3516 - (62.12²/50))/(50 - 1)

σ² = 1.78

Formula for the standard deviation is;

σ = √variance = √1.78

σ = 1.334

D) Formula for coefficient of variation is;

CV = (σ/x') * 100

CV = (1.33379/1.2424) * 100

CV = 107.356

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Answer:

To solve this I would multiply both sides by 3

Step-by-step explanation:

i would use the multiplication property of equality

The property that justifies that action x/3=12 is a linear question using reciprocal law.

A linear equation has one or two variables.

explanation:-

x/3= 12

x = 12*3 ( using reciprocal)

hence x = 36

solving this we will get the valve of Y if x is given.

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Answer: x>-1

Step-by-step explanation:i just did that question

Answer:

Step-by-step explanation:

add 4 to -15 then divide that  by 11x the answer should be x=-1.

Answer:

a. For the function:

f(x) = { sin x/3, if x ≤ π

{ x√3/2π, if x > π

I. To find lim f(x) as x approaches π from the negative side, we need to evaluate f(x) for values of x that are slightly less than π. In this case, since sin(x/3) is a continuous function, we can simply evaluate it at x = π:

lim f(x) as x approaches π- = f(π-) = sin(π/3) = √3/2

II. To find lim f(x) as x approaches π from the positive side, we need to evaluate f(x) for values of x that are slightly greater than π. In this case, we can simply evaluate the other part of the piecewise function at x = π:

lim f(x) as x approaches π+ = f(π+) = π√3/2π = √3/2

III. To find lim f(x) as x approaches π, we need to check whether the left-hand and right-hand limits are equal. In this case, since both the left- and right-hand limits exist and are equal, we have:

lim f(x) as x approaches π = √3/2

b. For the function:

f(x) = (x^2 - 36)/√(x^2 - 12x + 36)

I. To find lim f(x) as x approaches 6 from the negative side, we need to evaluate f(x) for values of x that are slightly less than 6. In this case, we can substitute x = 6 - h, where h is a positive number approaching zero, to get:

lim f(x) as x approaches 6- = lim f(6 - h) as h approaches 0

Substituting x = 6 - h into the function, we get:

f(6 - h) = [(6 - h)^2 - 36]/√[(6 - h)^2 - 12(6 - h) + 36]

= [h^2 - 12h]/√[h^2]

Simplifying the numerator and denominator separately, we get:

f(6 - h) = h(h - 12)/|h|

Since h approaches 0 from the positive side, we have:

lim f(6 - h) as h approaches 0+ = lim h(h - 12)/h as h approaches 0+ = lim (h - 12) as h approaches 0+ = -12

II. To find lim f(x) as x approaches 6 from the positive side, we need to evaluate f(x) for values of x that are slightly greater than 6. In this case, we can substitute x = 6 + h, where h is a positive number approaching zero, to get:

lim f(x) as x approaches 6+ = lim f(6 + h) as h approaches 0

Substituting x = 6 + h into the function, we get:

f(6 + h) = [(6 + h)^2 - 36]/√[(6 + h)^2 - 12(6 + h) + 36]

= [h^2 + 12h]/√[h^2]

Simplifying the numerator and denominator separately, we get:

f(6 + h) = h(h + 12)/|h|

Since h approaches 0 from the positive side, we have:

lim f(6 + h) as h approaches 0+ = lim h(h +

Step-by-step explanation:

Answer:

V=a3=33=27

Step-by-step explanation:

sorry if its wrong

A tessellation is a pattern made by repeating geometric shapes without any gaps or overlaps. These shapes, called tiles or polygons, fit together perfectly to cover a plane or a surface. Tessellations can be found in various forms of art, architecture, and design. They are used to create visually appealing patterns and decorations, as well as to explore mathematical concepts.

Tessellations are utilized in various practical applications, such as tiling floors, walls, and pavements, designing mosaics and quilts, and creating computer graphics and textile patterns. They are also studied in mathematics to understand concepts like symmetry, geometry, and transformations.

For polygons to tessellate, certain conditions must be met at their vertices. At each vertex, the angles formed by the polygons must add up to a whole number of degrees, typically 360 degrees. In other words, the sum of the interior angles of each polygon meeting at a vertex must be a multiple of 360 degrees.

This ensures that the polygons can fit together seamlessly without leaving any gaps or overlaps. Examples of polygons that tessellate include equilateral triangles, squares, and hexagons, as their angles add up to 360 degrees at each vertex.

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