by how much does the mass decrease when a helium nucleus is formed from two protons and two neutrons? give your answer in atomic mass units

The net vertical force on the caboose (C) is

∑ F[v, C] = F[n, C]  - (1.4 kg) g = 0

where F[n, C] is the magnitude of the normal force exerted by the track on the caboose; so we have

F[n, C] = (2.3 kg) g = 13.72 N

which means the coefficient of kinetic friction µ between the caboose and the track is

F[f, C] = 0.46 N = µ (13.72 N)   ⇒   µ = (0.46 N) / (13.72 N) ≈ 0.034

and presumably the coefficient is the same for the locomotive.

The net vertical force on the locomotive (L) is

∑ F[v, L] = F[n, L] - (2.3 kg) g = 0

where F[n, L] is the magnitude of the normal on the locomotive, so that

F[n, L] = (2.3 kg) g = 22.54 N

and so the locomotive is opposed by a frictional force with magnitude

F[f, L] = µ (22.54 N) ≈ 0.76 N

Taking the locomotive and caboose together, the net horizontal force on the system is

∑ F[h] ≈ - F[f, C] - F[f, L] + F[engine] = (2.3 kg + 1.4 kg) (3.1 m/s²)

Solve for F[engine] :

F[engine] ≈ (3.7 kg) (3.1 m/s²) + 0.46 N + 0.76 N ≈ 13 N

Explanation:

improved saftey for children

Answer:

D. Improved safety for children

Explanation:

When a solute is actively transported across epithelium, the usual follow-up is A) water movement in the opposite direction.

Active transport refers to the process in which substances, such as ions or molecules, are moved across a cell membrane against their concentration gradient, requiring the expenditure of energy. When solute is actively transported across an epithelium, it creates an osmotic gradient across the membrane.

Osmosis is the movement of water molecules across a selectively permeable membrane from an area of lower solute concentration to an area of higher solute concentration. In this case, since the solute is actively transported, it is being moved from an area of lower concentration to an area of higher concentration. As a result, water tends to move in the opposite direction, from an area of higher water concentration (lower solute concentration) to an area of lower water concentration (higher solute concentration).

Therefore, when a solute is actively transported across epithelium, the usual consequence is water movement in the opposite direction, as indicated by option A.

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SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-

They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.

Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.

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Answer:

F=q(v×b)

electron will continue to move in same direction

Answer:

The work done by Joel is greater than the work done by Jerry.

Explanation:

Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

\(W = F\cdot \Delta s\)

Where:

\(W\) - Work, measured in joules.

\(F\) - Force exerted on the object, measured in newtons.

\(\Delta s\) - Travelled distance by the object, measured in meters.

During the first 10 minutes, the net work exerted on the object is zero. That is:

\(W_{net} = W_{Joel} - W_{Jerry}\)

\(W_{net} = F\cdot \Delta s - F\cdot \Delta s\)

\(W_{net} = (F-F)\cdot \Delta s\)

\(W_{net} = 0\cdot \Delta s\)

\(W_{net} = 0\,J\)

In exchange, the net work in the next 5 minutes is the work done by Joel on the object:

\(W_{net} = W_{Joel}\)

\(W_{net} = F\cdot \Delta s\)

Hence, the work done by Joel is greater than the work done by Jerry.

Answer:

A concentrated solution is one that has a relatively large amount of dissolved solute. A dilute solution is one that has a relatively small amount of dissolved solute.

The energy required to heat 40.7 g of water (H2O) from -10°C to 70°C can be calculated as follows;Mass of water = 40.7 gTemperature change = 70 - (-10) = 80 °C Specific heat of ice = 2.06 J/g °CSpecific heat of water = 4.18 J/g °CHeat of fusion of water = 334 J/gAt first, we have to heat the ice from -10°C to 0°C using the formula;

q = mcΔTwhere m is the mass, c is the specific heat, and ΔT is the temperature change. For ice, c = 2.06 J/g °C, and the temperature change is 0 - (-10) = 10°C;

q1 = (40.7 g)(2.06 J/g °C)(10°C) = 839.42 J

This amount of heat energy is needed to bring the ice to its melting point. The amount of heat required to melt the ice at 0°C can be determined using the formula; q2 = mLfwhere Lf is the heat of fusion of ice, which is 334 J/g;

q2 = (40.7 g)(334 J/g) = 13590.8 J

Now, we have 40.7 g of water at 0°C.

To heat this water to 70°C, we use the formula;

q3 = mcΔT

where m is the mass, c is the specific heat, and ΔT is the temperature change. For water, c = 4.18 J/g °C, and the temperature change is 70 - 0 = 70°C;

q3 = (40.7 g)(4.18 J/g °C)(70°C) = 12123.94 J

The total energy required is;

\(q_total = q1 + q2 + q3 = 839.42 J + 13590.8 J + 12123.94 J = 26554.16 J\)

Thus, the energy required to heat 40.7 g of water (H2O) from −10∘C to \(70∘C is 2.66 x 10^4 J or 26.6 kJ\).

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''The freezer and room are not an isolated system, since electrical energy flows in.'' is the correct statement.

The Second Law of Thermodynamics says that "in all energy exchanges, if no energy enters or leaves the system, the potential energy of the state will always be less than the energy of the initial state."

So we can conclude that ''The freezer and room are not an isolated system, since electrical energy flows in.'' is the correct statement.

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When a same-sized force is applied over a smaller area, the pressure increases.

Pressure is defined as the force acting per unit area (P = F/A). Here, F represents the force and A represents the area. When the area (A) decreases, and the force (F) remains constant, the overall pressure (P) increases according to the formula.

This concept can be easily understood by imagining a person standing on the ground wearing regular shoes versus standing on the ground wearing high heels. In both cases, the person's weight (force) remains the same, but the area of contact with the ground is much smaller with high heels. As a result, the pressure exerted on the ground by high heels is much higher than that of regular shoes.

Understanding the relationship between force, area, and pressure is crucial in various applications, such as hydraulic systems, pneumatic systems, and even in our daily lives. Increasing pressure by reducing the area can enhance the efficiency of certain processes while decreasing pressure by increasing the area can help distribute force more evenly and reduce potential damage or stress on surfaces.

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The speed of the elevator after it has moved downward is 4.43 m/s.

The speed of the elevator after the impact can be determined by applying the principle of conservation of mechanical energy as shown below;

K.E = P.E

¹/₂mv² = mgh

¹/₂v² = gh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 1)

v = 4.43 m/s

Thus, the speed of the elevator after it has moved downward is 4.43 m/s.

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The type of solar energy system that is needed for these kinds of applications is A solar collector system using mirrors or lenses to concentrate sunlight

A solar energy system, also known as a solar power system, is a technology that converts sunlight into electrical energy. It consists of a series of solar panels that are installed on a rooftop or in an open area that receives direct sunlight. The solar panels are made up of photovoltaic (PV) cells, which absorb the energy from the sun and convert it into direct current (DC) electricity.

The DC electricity produced by the solar panels is then sent to an inverter, which converts it into alternating current (AC) electricity that can be used to power homes, businesses, and other electrical appliances.

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Answer:

look in internet u can find online converter and there u will get a rel answer

Explanation:

Answer:

a = 0.98J

Explanation:

PE = mgh

PE = 0.1 x 9.8 x 1

PE = 0.98J

(a) The potential energy of the car at the beginning of the experiment is 9.8(m) J.

(b) The kinetic energy of the car for group a is 3.125(m) J.

(c) The kinetic energy of the car for group b is 4.5(m) J.

The potential energy of the car is calculated as follows;

P.E = mgh

where;

P.E = m x 9.8 x 1

P.E = 9.8(m) J

K.E = ¹/₂mv²

K.E = ¹/₂ x m x (2.5)²

K.E = 3.125(m) J

K.E = ¹/₂mv²

K.E = ¹/₂ x m x (3)²

K.E = 4.5(m) J

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The speed of the police car can be calculated using the Doppler effect equation, which is Δf/f = v/c, where Δf is the difference in frequency, v is the velocity of the car, and c is the speed of sound.

When a sound source is moving towards a stationary observer, the frequency of the sound waves increases, and when the sound source is moving away from the observer, the frequency decreases.

This phenomenon is known as the Doppler effect. In this case, the frequency of the sound waves from the police car decreases from 560 hz to 520 hz when it stops next to you. This means that the police car was moving away from you when you heard the sound waves.
Using the Doppler effect equation, we can solve for the velocity of the police car.

\(\frac{Δf}{f} =\frac{v}{c}\) can be rearranged as

\(v = c * \frac{ Δf}{f}\)

Substituting the values we have,

we get \(v = 343 m/s *\frac{(560 - 520)}{560}\).

Solving this equation gives us the velocity of the police car, which is 30 m/s.
The speed of the police car was 30 m/s. The Doppler effect is a phenomenon that can be used to calculate the velocity of a moving object based on the frequency of the sound waves it emits.

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Răspuns: 23. 6 m / s

Explicaţie:

Pentru a obține viteza medie a mașinii:

Luăm viteza medie a mașinii:

Modificarea distanței / schimbarea timpului

Schimbarea distanței:

(219 - 134) KM = 85 km

Schimbarea în timp:

(11 ore 20 min) - (10 ore - 20 min) = 1 oră

Prin urmare, viteza medie:

Schimbarea distanței / schimbarea timpului

85/1 = 85 km / oră

În metru pe secundă:

(85 * 1000) m / 3600

85000/3600 USD = 23,6 m / s

Answer: Cross-cutting features are always younger than the surrounding rock.

When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

The options include:

1. An unconformity is created when lava pours out on Earth’s surface.

2. Faults are the result of volcanic activity.

3. Intrusions and extrusions are sedimentary formations.

4. Cross-cutting features are always younger than the surrounding rock.

5. When material erodes before sediment is deposited on it, a geologic gap results.

The law of superposition simply states that when there is a layers of rocks, we would see that the younger layers will lie and be on top of the layers that are older.

Other tools that can help scientist with relative dating are:

• Cross-cutting features are always younger than the surrounding rock.

• When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

It's on Edge

answer :

force is called the magnetic force of repulsion, and it happens when two magnets have the same poles (either both north or both south) and they push away from each other.

When all the domains in a material are aligned in the same direction, the material becomes strongly magnetized.

explanation :

magnetic domains in the rings were stable and strong enough to resist the force of gravity.

In the case of the levitating rings, the magnetic domains were aligned in such a way that they created a strong magnetic field, which allowed the rings to levitate in mid-air.

tiny regions within ferro magnetic  material that have their own magnetic fields are called magnetic domains.

Magnetic domains in the rings refer to the tiny regions within the ring's ferro magnetic material that have their own magnetic fields.

The electric dipole moment is 0.0368 nC x m in size, and 0.085 J separates the potential energies for dipole orientations parallel and antiparallel to E.

An electric dipole is a pair of charges of equal magnitude but opposite sign, separated by a distance d. The electric dipole moment (p) is a vector quantity that is defined as the product of the charges and the separation distance. The direction of the electric dipole moment vector is from the negative charge to the positive charge.

Given the charges of magnitude 4.8 nC, separated by 7.7 um, the magnitude of the electric dipole moment can be calculated as:

= p

= q x d

= (4.8 nC) x (7.7 x 10^-6 m)

= 0.0368 nC x m

The potential energy (U) of an electric dipole in an electric field is given by the dot product of the electric dipole moment vector (p) and the electric field vector (E):

U = -p x E

When the dipole is oriented parallel to the electric field E, the potential energy is at a minimum. The difference in potential energy between the parallel and antiparallel orientations can be calculated as:

= U diff

= 2 x |U parallel|

= 2 x |-p x E|

Given the electric field strength of 1130 n/c, the difference in potential energy can be calculated as:

= U diff

= 2 x |-p x E|

= 2 x |- (0.0368 nC x m) x (1130 n/c)|

= 0.085 J

So the electric dipole moment is 0.0368 nC x m and the difference between the potential energies for the dipole orientations parallel and antiparallel to E is 0.085 J

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Question - An electric dipole consisting of charges of magnitude 4.8 nC are seperated by 7.7 um is in an electric field of strength 1130 n/c. what are the magnitude of the electric dipole moment and the difference between the potential energies for the dipole orientations parallel and antiparallel to E?

Answer:

1. A hiking

2. C

3. B

4. D

5. E

We know that water is denser than air or a piece of paper is denser than rock.

How do we determine density?

Density is determined by measuring it’s mass and then dividing it by it’s volume.  

Let us take a solid cube of aluminium.

(i) The readings to be taken are the mass of aluminium and volume of aluminium.

(ii) Instruments used are :

(iii) We will check the mass of the aluminium cube by simply putting it on the weighing machine. Now we will check the volume by putting that cube into the water. The initial level was x. The water level rises to y after putting the cube into it. To know the volume, we will simply subtract y-x. Hence, we know the volume.

To know the density, divide mass by volume. (Mass / volume)

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Answer:

less than 10 inches, or 25 centimeters, of precipitation a year.

Explanation:

PS. the precipitation recieved in the desert can be in the form of either rain or snow.

Answer:

Explanation:

The main aim of pokhara regional international airpot project​ is to provide improved air transportation services to the people. It will also strengthen the country's civil aviation sector and contribute to economic and social development, as well as tourism.

hope this helps

plz mark as brainliest!!!!!!

The main aim of Pokhara regional international airport project is to improve the country's aviation services and contribute to economic and social development as well as tourism.

Answer:

\(here \: answer\)

F » 18,000 N

Explanation:

Given :

Mass (m) = 2,000 kg

Acceleration (a) = 9 m/s2

To Find :

the formula for force

F = m • a

F = 2,000 • 9

F = 18,000 N

Answer:

1.875 joules

Explanation:

K.E=1/2 mv²

K.E=1/2 0.15×5²

K.E=1.875 joules

Answer:

It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.

Explanation:

The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.

One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light

Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.  

Answer:

\(v = u + at \\ 0 = 45 \sin(20) - 9.81 \times t \\ t = 1.56s\)

Explanation:

Given data

distance = 5km

time taken to travel to school= 30 min

1. the total distance traveled is

from home to school+ school to home+ home back to school

5km+5km+5km= 15 km

2. Determine the students average speed

average speed is the total distance divided by the total time taken

= (5+5+5)/(30+30+27)

= 15/87 km/min

3  What is the student total displacement

the displacement tells how far a place is  hence the displacement is 5km (i.e the school is 5km from his home)

4. Determine the students average velocity

a. speed home to school

      v= 5/30= 0.166 km/min

b. school back home

      v= 5/30= 0.166 km/min

c. speed home to school

      v= 5/27= 0.185 km/min

Average velocity =  (0.185 + 0.166 + 0.166)/3= 0.517/3= 0.17 km/min