To calculate the order of magnitude for each value, we need to determine the power of 10 that represents the value.
1. The mass of Earth's atmosphere: 5.1 × 10^18 kg. The order of magnitude is 18.
2. The mass of the Moon's atmosphere: 25,000 kg. The order of magnitude is 4.
3. The mass of Earth's hydrosphere: 1.4 × 10^21 kg. The order of magnitude is 21.
4. The mass of Earth: 5.97 × 10^24 kg. The order of magnitude is 24.
5. The mass of the Moon: 7.34 × 10^22 kg. The order of magnitude is 22.
6. The Earth-Moon distance (semimajor axis): 3.84 × 10^8 m. The order of magnitude is 8.
7. The mean Earth-Sun distance: 1.5 × 10^11 m. The order of magnitude is 11.
8. The equatorial radius of Earth: 6.38 × 10^6 m. The order of magnitude is 6.
9. The mass of an electron: 9.11 × 10^-31 kg. The order of magnitude is -31.
10. The mass of a proton: 1.67 × 10^-27 kg. The order of magnitude is -27.
11. The mass of the Sun: 1.99 × 10^30 kg. The order of magnitude is 30.
The order of magnitude represents the power of 10 in a value. It helps us understand the scale of the quantity and compare it to other values.
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A body of mass 0.1 kg is moving in a uniform horizontal circular path with a speed of 2 m/s, so the magnitude of change in its momentum after completing half a revolution equals (a) zero (b)60.2 kg.m/s (c) 0.4 kg.m/s (d)0.8 kg.m/s
The magnitude of the change in momentum after completing half a revolution is zero,The correct answer is option(a).
To determine the magnitude of the change in momentum after completing half a revolution, we need to consider the principles of circular motion and conservation of momentum.
The change in momentum of an object is given by the equation Δp = mΔv, where Δp represents the change in momentum, m is the mass of the object, and Δv is the change in velocity.
In this scenario, the body of mass 0.1 kg is moving in a uniform circular path with a speed of 2 m/s. Since the speed remains constant, there is no change in velocity during the circular motion. Therefore, Δv is equal to zero.
Applying the equation Δp = mΔv, we find that Δp = (0.1 kg)(0) = 0 kg·m/s.
It's important to note that while the body is continuously changing its direction during the circular motion, the magnitude of its velocity remains constant. As a result, there is no change in momentum, as indicated by the answer (a) zero.
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Is this right. Please help me ITS SOCIOLOGY
Answer:
Yes
Explanation:
sorry if im wrong
What is the wavelength in nanometers of light when the energy is 3. 29 × 10-19 j for a single photon?.
The wavelength is 6.04 nm.
since
λ=hc/E
λ=6.626×10^ −34×3×10 ^8/(3.29×10−19)
λ=6.04nm
The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or down a wire is defined as the wavelength. This length is often defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).
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For a stirred tank that is cooled by a water coil, what is the consequences of neglecting coll dynamics? a • Thermal capacitance of the collis neglected with respect to the tank wall and the tank liquid • Energy balance is done only on the tank wall Ob • Thermal capacitance of the collis neglected with respect to the tank wall and the tank liquid • Energy balance is done only on the tank liquid oc • Thermal capacitance of the collis neglected with respect to the tank wall and the tank liquid
The thermal capacitance of the coil is neglected with respect to the tank wall and the tank liquid. Energy balance is done only on the tank liquid. Option C is the correct answer.
The consequence of neglecting the thermal dynamics of the cooling coil in a stirred tank can vary depending on the specific situation and the magnitude of the neglected effects. However, in general, neglecting the thermal capacitance of the cooling coil in relation to the tank wall and the tank liquid can have the following consequences:
Inaccurate temperature predictions: Neglecting the thermal capacitance of the cooling coil means that the cooling effect provided by the coil will not be properly accounted for in the energy balance of the system. This can lead to inaccurate temperature predictions within the tank. The coil may cool the tank contents faster or slower than anticipated, leading to deviations from the desired temperature profile.Inefficient cooling: Neglecting the thermal capacitance of the coil implies that the cooling coil is assumed to have an instantaneous cooling effect, without considering its own thermal inertia. This can result in inefficient cooling as the coil may not be able to transfer heat effectively to the cooling water due to the lack of thermal capacitance consideration. Consequently, the cooling process may be slower or less efficient than expected.Risk of equipment failure: If the cooling coil is subjected to rapid temperature changes due to neglecting its thermal capacitance, it can potentially lead to thermal stress and mechanical failure of the coil. The coil may not be designed to handle abrupt temperature variations, which can result in damage or reduced lifespan of the equipment.Energy consumption discrepancies: Neglecting the thermal capacitance of the coil can affect the overall energy balance calculations for the system. The energy required to operate the cooling coil may be underestimated, leading to discrepancies in energy consumption estimations. This can have implications for energy management and cost considerations.Learn more about capacitance at
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An electron of mass m and charge -e is moving through a uniform magnetic field B=(B2,0,0) in vacuum. (Figure 1)At the origin, it has velocity v = (vx, Vy, 0), where vx >0 and Vy > 0. A screen is mounted perpendicular to the x axis at a distance D from the origin. Throughout, you can assume that the effect of gravity is negligible. First, suppose B, = 0. Find the y coordinate y of the point at which the electron strikes the screen. Express your answer in terms of D and the velocity components V, and Vy. View Available Hint(s) Figure 1 of 1 Now suppose B > 0, and another electron is projected in the same manner. Which of the following is the most accurate qualitative description of the electron's motion once it enters the region of nonzero magnetic field? O The electron decelerates before coming to a halt and turning around while always moving along a straight line. O The electron's motion will be unaffected. (It will continue moving in a straight line with the same constant velocity.) O The electron moves in a circle in the xy plane. screen O The electron moves along a helical path about an axis parallel to the field lines with constant radius and constant velocity in the x direction.
C:The electron moves in a circle in the xy plane.
What is electron ?
Electron is a free and open-source framework created by GitHub that helps developers build cross-platform desktop applications with HTML, CSS, and JavaScript. Electron is based on Node.js and Chromium, making it a powerful tool for creating native applications with web technologies. Electron enables developers to build desktop applications that can run on Windows, Mac, and Linux, as well as Android and iOS devices.
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(b) What is the probability that the electron can be detected in the middle one third of well, region (b)
In order to determine the probability that an electron can be detected in the middle one-third of a well region, we need to take into account the wave function and the boundary conditions.The wave function represents the probability density of finding the electron in a particular location within the well. The boundary conditions are determined by the geometry of the well, which can be rectangular, triangular, or other shapes.
The Schrodinger equation is used to calculate the wave function and determine the probability density of finding the electron in a particular location. The wave function is a complex function that describes the position and momentum of the electron. It is also used to calculate the energy of the electron in the well.The probability of finding the electron in the middle one-third of the well can be determined by integrating the probability density over the middle one-third of the well region. This will give us the probability of finding the electron in that region. The integral can be evaluated using numerical methods or analytical methods, depending on the complexity of the wave function and the boundary conditions.In general, the probability of finding the electron in the middle one-third of the well will depend on the shape of the well, the energy of the electron, and the boundary conditions. For example, if the well is rectangular and the electron is in the ground state, then the probability of finding the electron in the middle one-third of the well will be high. However, if the well is triangular and the electron is in an excited state, then the probability of finding the electron in the middle one-third of the well will be lower.For such more question on probability
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When a marble is at rest what happened
Answer: the marble will remain in place at a constant velocity of zero
Explanation:
Newton's first law states that a body at rest will remain at rest, and a body in motion will remain in motion in a straight line at a constant velocityunless acted upon by an outside force
A brick is sitting motionless on top of a wall. What type of energy does it have? (1 point)
A) geothermal energy
B) electromagnetic energy
C) potential energy
D) kinetic energy
The block that is sitting motionless on top of a wall contains potential energy.
What is energy?Energy is the ability to do work. There are several forms of energy. For the block that is sitting motionless on top of a wall, the block contains potential energy.
The potential energy is the block is used to do work when the block falls. The block can break a piece of glass on the floor due to the energy that it contains.
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does this actual case require the lens to be stronger or weaker than if there were only air in our eyes?
In the actual case where there is water inside the eye, the lens needs to be stronger than if there were only air in our eyes.
This is because the refractive index of water is higher than that of air, meaning that light will bend more when it passes through water than when it passes through air. This makes it harder for the eye to focus light onto the retina, and so a stronger lens is needed to compensate for this increased bending.
If there is also water outside the eye, such as when we are underwater, we need to wear goggles to provide a layer of air in front of our eyes, which allows light to be refracted less and therefore makes it easier to see clearly.
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What is the mass and weight of an object on the surface of the moon, if on the earth its mass is 12kg.
The mass and weight of object on moon is 0.0138kg and 0.0229kg .
Since force is a vector quantity, we must consider the direction in which it acts. There are two main types of frictional force: static force (Fst) and sliding force (Fsl). Normal forces (FN) produce these forces acting perpendicular to the direction of motion, although they act in the opposite direction to the object's motion.
It is equivalent to the weight of the object plus the extra weight. For example, pushing down on a block of wood on a table increases the normal force and thus the frictional force.
me=12Kg
ge=10
gm=10/6= 1.66
M=?
me ge =M gm
M=me ge/gm
M=120/1.66
M=0.0138kg
W=mg =0.0138 x 10kg
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Question 6 (0.5 points) Using the image below, it can be said that the map must have been made incorrectly since b-cn distance and cn-vg distance do not add up to the b-vg distance and all map distances must add up exactly perfect in all cases. Results Recombination frequencies -9%-9.5%- Chromosome -17%- en vg True False Question 7 (0.5 points) In a three point mapping cross, the most abundant class is the double crossovers followed by the single crossovers followed by the no crossovers. True False Question 8 (0.5 points) A physical map and genetic map utilize the same units but may look very different. True False | M
While physical and genetic maps measure distances between genes, they can look different because physical maps reflect the physical structure of DNA, while genetic maps represent the recombination frequencies and genetic linkage relationships between genes. Therefore, the two types of maps may have different scales and arrangements, even though they measure distances in the same units.
Question 6: The statement that the map must have been made incorrectly because the distances do not add up perfectly is not accurate. Genetic mapping is a technique used to estimate distances between genes or genetic markers based on recombination frequencies. The distances obtained through genetic mapping are statistical estimates and are subject to some degree of error and variation. Therefore, it is expected that the sum of distances between multiple points on a map may not always match the direct distance between those points. This is because the estimation of distances is based on the frequency of recombination events that occur during genetic recombination.
Question 7: The statement that the most abundant class in a three-point mapping cross is the double crossovers followed by single crossovers and then no crossovers is false. In a three-point mapping cross, the most abundant class is typically the non-recombinant progeny (no crossovers), followed by the single crossovers, and then the least abundant class is the double crossovers. This pattern is based on the principle of independent assortment and the occurrence of recombination events during meiosis. Non-recombinant progeny result from chromosomes maintaining their original configuration, while single crossovers occur when one recombination event takes place between two of the three loci. Double crossovers involve recombination events at two locations, resulting in a different chromosome configuration. Double crossovers are relatively less frequent compared to single crossovers and non-recombinant progeny.
Question 8: The statement that a physical map and genetic map utilize the same units but may look very different is true. Physical maps and genetic maps are two different types of maps used in molecular biology and genetics. They measure distances between genes or genetic markers, but they do so using different approaches and units.
A physical map represents the physical distances between genes or markers along a DNA molecule or chromosome. It is based on direct measurement of physical lengths, such as base pairs or kilobases. Physical maps provide information on the actual physical locations of genes or markers.
On the other hand, a genetic map represents the relative distances between genes or markers based on recombination frequencies. Genetic maps are constructed using genetic crosses and analysis of recombination events. The units used in genetic mapping are usually centimorgans (cM) or map units.
While physical and genetic maps measure distances between genes, they can look different because physical maps reflect the physical structure of DNA, while genetic maps represent the recombination frequencies and genetic linkage relationships between genes. Therefore, the two types of maps may have different scales and arrangements, even though they measure distances in the same units.
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Calculate the rms currents for an ac source is given by v(t) = V0 sinÏt, where V0 = 100V and Ï = 200Ï rad/s when connected across
(a) a 20-μF capacitor,
(b) a 20-mH inductor, and
(c) a 50-Ω resistor.
the RMS currents are:/Capacitor: 0.0707 , Inductor: 5.639 and Resistor: 1.414 A
(a) The rms current through the capacitor can be found using the formula IRMS = VRMS/XC, where XC is the capacitive reactance given by XC = 1/(2πfC) = 1/(2π(200)(20×10^-6)) = 39.79Ω. Therefore, IRMS = VRMS/XC = (100V)/39.79Ω = 2.51A.
(b) The rms current through the inductor can be found using the formula IRMS = VRMS/XL, where XL is the inductive reactance given by XL = 2πfL = 2π(200)(20×10^-3) = 25.13Ω. Therefore, IRMS = VRMS/XL = (100V)/25.13Ω = 3.98A.
(c) The rms current through the resistor can be found using the formula IRMS = VRMS/R = (100V)/50Ω = 2A.
To calculate the RMS currents for each component, we'll first find their impedance (Z) and then use Ohm's law (I = V/Z) to find the current. The RMS voltage (Vrms) is V0/√2.
(a) For a 20-μF capacitor:
Impedance, Zc = 1/(ωC) = 1/(200π * 20 * 10^(-6)) ≈ 795.77 Ω
Irms (capacitor) = Vrms / Zc = (100 / √2) / 795.77 ≈ 0.0707 A
(b) For a 20-mH inductor:
Impedance, Zl = ωL = 200π * 20 * 10^(-3) ≈ 12.57 Ω
Irms (inductor) = Vrms / Zl = (100 / √2) / 12.57 ≈ 5.639 A
(c) For a 50-Ω resistor:
Impedance, Zr = 50 Ω
Irms (resistor) = Vrms / Zr = (100 / √2) / 50 ≈ 1.414 A
So, the RMS currents are:
(a) Capacitor: 0.0707 A
(b) Inductor: 5.639 A
(c) Resistor: 1.414 A
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From earths atmosphere where can the carbon atom go next ?
Answer:
Carbon atoms go from the Earth's atmosphere to the hydrosphere, a layer of water near the Earth's surface.
Explanation:
When carbon reaches the hydrosphere, the greenhouse effect increases which changes the temperature of water and in turn makes thriving for organism difficult.
The atmospheric pressure of a certain area is 380 torr.the pressure in pascal is what?
Answer:
Now that we know what the conversion factor is, we can easily calculate the conversion of 380 torr to pa by multiplying 133.322 by the number of torrs we have, which is 380. So, the answer to the question "what is 380 torrs in pascals?" is 50662.36 pa.
Answer:
Explanation:
One pascal is equivalent to 1 newton (N) of force applied over an area of 1 square meter (m2).
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Evonne does not have a lot of time to work out during the week. She wonders if she spent half a day on the weekend getting is as many different types of exercise as possible if that would help. What is the BEST advice for Evonne?
A.
She has the right idea since variety is more important than intensity.
B.
She can do that, but should have a clear goal in mind to define her exercise.
C.
She should only focus on one type of exercise since she can do it once a week.
D.
She would be better off fitting in 15-20 minutes of exercise several times a week.
PLEASE NO LINKS
She would be better off fitting in 15-20 minutes of exercise several times a week. This t is the BEST advice for Evonne.
What are the benefits of regular exercise?Regular physical activity and exercise have many positive health effects that are difficult to deny. Everyone, regardless of age, sex, or physical ability, benefits from exercise.
Exercise can assist sustain weight loss or prevent excessive weight gain. Calorie burn occurs during physical exertion. You burn more calories when you engage in more vigorous exercise.
Numerous health issues and concerns, such as stroke, the metabolic syndrome, high blood pressure, and type 2 diabetes, can be prevented or managed with regular exercise. It can also help with cognitive improvement and reduce the danger of dying from any cause.
Exercise helps your circulatory system function more effectively and distributes oxygen and nutrients to your tissues. Additionally, you have greater energy to complete daily tasks as your heart and lung health improves.
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A 23.9-kg boy stands 1.67 m from the center of a frictionless playground merry-go-round, which has a moment of inertia of 221.3 kg m2. The boy begins to run in a circular path with a speed of 0.71 m/s relative to the ground. Calculate the angular velocity of the merry-go-round.
1.67 m From the center of a frictionless playground, 23.9-kg boy stands merry-go-round, with a moment of inertia of 221.3 kg m2. The boy begins to run in a circular path with a speed of 0.71 m/s relative to the ground. Then the angular velocity of the merry-go-round is 0.23 rad/s.
Initially, the merry-go-round is at rest, so its angular momentum is zero. The boy's angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Substituting the values given in the problem, we have:
L = (221.3 kg\(m^2\)) ω
When the boy starts running, he also starts rotating around the center of the merry-go-round. Since the playground is frictionless, there is no external torque acting on the system, so the angular momentum is conserved.
At the final state, the boy and the merry-go-round are rotating together, so their angular momentum add up:
Lfinal = (221.3 kg\(m^2\) + mboy\(r^2\)) ωfinal
where mboy is the mass of the boy, r is his distance from the center, and ωfinal is the final angular velocity of the system.
Substituting the values given in the problem, we have:
(221.3 kg\(m^2\)) ω = (221.3 kg \(m^2\)+ (23.9 kg)\((1.67 m)^2\)) ωfinal
Simplifying and solving for ωfinal, we get:
ωfinal = ω (221.3 kg\(m^2\)) / (221.3 kg \(m^2\) + (23.9 kg)\((1.67 m)^2\))
Substituting ω = v / r, where v is the boy's speed relative to the ground and r is his distance from the center, we have:
ωfinal = (0.71 m/s) / 1.67 m (221.3 kg \(m^2\)) / (221.3 kg\(m^2\) + (23.9 kg)\((1.67 m)^2\))
Simplifying and solving, we get:
ωfinal = 0.23 rad/s
Therefore, the angular velocity of the merry-go-round is 0.23 rad/s.
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The SI unit of current is the ampere, which is defined as the flow of charge in units of _____ over a period of time measured in _____.
The SI unit of current is the ampere, which is defined as the flow of charge in units of coulomb over a period of time measured in seconds.
What is Current?Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I is a typical way to represent the current. The ampere, denoted by the letter A, is the common unit. An ampere is a unit of measure of the rate of electron flow or current in an electrical conductor. One coulomb of electrical charge (6.24 x 1018 charge carriers) traveling by a given place in one second is represented by one ampere of current.
Conventional current, also known as Franklin current, is thought by physicists to flow from relatively positive points to comparatively negative locations. The most prevalent charge carriers, electrons, are negatively charged. From somewhat negative to relatively good points, they move.
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A train is traveling N at 45 m/s. After 10s, it is traveling at 90 m/s. What is it's acceleration?
Answer:
The train's acceleration is 4.5 m/s²
Explanation:
The train's speed increased by 45 m/s after 10 seconds, which means that it's speed increased by 4.5 m/s each second, or rather 4.5m/s²
how many molecules are in 3 moles of CO2
Answer:
1.806 x 10^24 molecules
Explanation:
1 mole of CO2 has 6.02 x 10^23 molecules
3 mole of CO2 has 3x6.02x10^23 molecuels = 1.806 x 10^24 molecules
The 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.
One mole of \(CO_{2}\) contains \(6.022*10^{23}\) molecules.
In 3 moles of \(CO_{2}\) ,
\(=3*6.022*10^{23}=1.8066*10^{24}\) molecules.
Hence, the 3 mole of \(CO_{2}\) contains \(1.8066*10^{24}\) molecules.
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The student determined the density of the rock to be 2.55 ± 0.10 g/cm
5
What are the maximum and minimum values for the density of the rock?
Maximum density =
Minimum density =
g/cm³
g/cm³
[1 mark]
The maximum and minimum values for the density of the rock are 2.65 and 2.45 respectively.
Density is the substance's mass consistent with the unit of quantity. The symbol most customarily used for density is ρ, despite the fact that the Latin letter D can also be used. Density is the size of ways tightly a cloth is packed together. it's far defined as the mass consistent with unit quantity.
ρ = m/V, wherein ρ is the density, m is the mass of the item and V is the quantity of the object.
Calculation:-
maximum density = 2.55 + 0.10
= 2.65
minimum density = 2.55 - 0.10
= 2.45
The density is of two types, one is absolute density, and the alternative is relative density. Relative density is also called unique gravity, which is the ratio of the density of a material to the density of a reference material. typically, the reference fabric is water.
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Where does compression often occur?
Answer:
a convergent boundary^^
Explanation:
hope it helped
Express the time spent to daily life activities during holidays as a fraction of whole day 1. Represent the fractions in pictorial form. 2. Write the fractions in simplest form. 3. Arrange them in ascending order.
Answer:
(II). The fractions in simplest form
\(\dfrac{31}{35}\), \(\dfrac{91}{165}\) and \(\dfrac{13}{5}\)
(III). The fractions in ascending order
\(\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}\)
Explanation:
Given that,
(I). Represent the fractions in pictorial form
(II). Write the fractions in simplest form.
(III). Arrange them in ascending order.
Suppose, The fractions in pictorial form
(a). \(\dfrac{3}{5}+\dfrac{2}{7}\)
(b). \(\dfrac{9}{11}-\dfrac{4}{15}\)
(c). \(\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}\)
We need to write in simplest form
Using given fraction
(a). \(\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{3\times7}{5\times7}+\dfrac{2\times5}{7\times5}\)
\(\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21}{35}+\dfrac{10}{35}\)
\(\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}\)
\(\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{31}{35}\)
(b). \(\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{9\times15}{11\times15}-\dfrac{4\times11}{15\times11}\)
\(\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{135-44}{165}\)
\(\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{91}{165}\)
(c). \(\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{2\times2}{5\times2}+\dfrac{3\times5}{5\times2}\)
\(\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{4+15}{10}\)
\(\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7+4+15}{10}\)
\(\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{26}{10}\)
\(\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{13}{5}\)
We need to arrange them in ascending order
Using simplest form
The simplest fraction in ascending order
\(\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}\)
Hence, This is required solution.
Two large parallel metal plates are 6.0 cm apart. The magnitude of the electric field between them is 600 N/C. What work is done when one electron is moved from the positive to the negative plate? Note: the charge of an electron is 1.6 x 10-19 C.
3.36 x 10-20 J
4.98 x 10-17 J
1.6 x 10-19 J
5.76 x 10-18 J
Answer:
Approximately \(5.76 \times 10^{-18}\; {\rm J}\) (by the external force that moved the electron.)
Explanation:
Let \(q\) denote the magnitude of a charge in an electric field of magnitude \(E\). The magnitude of the electrostatic force on that charge would be:
\(F = q\, E\).
In the electric field in this question, the magnitude of the electric force on the electron would be:
\(\begin{aligned}F &= q\, E \\ &= 1.6 \times 10^{-19}\; {\rm C} \times 600\; {\rm N \cdot C^{-1}} \\ &= 9.6 \times 10^{-17} \; {\rm N}\end{aligned}\).
Moving the electron to the other plate would thus require an external force of \(9.6 \times 10^{-17}\; {\rm N}\).
This force needs to be exerted over a distance of \(6.0\; {\rm cm}\) (\(6.0 \times 10^{-2}\; {\rm m}\).) The direction of the motion is the same direction as that of the external force. Thus, the work that needs to be done would be:
\(\begin{aligned}W &= F\, s \\ &\approx 9.6 \times 10^{-17}\; {\rm N} \times 6.0 \times 10^{-2}\; {\rm m} \\ &\approx 5.76 \times 10^{-18}\; {\rm J}\end{aligned}\).
which process is an example of the first law of thermodynamics in action?
An example of the first law of thermodynamics in action is a car engine, that converts chemical energy to mechanical energy to power its motion.
The first law of thermodynamics, also known as the law of conservation of energy, states that the total energy of a closed system remains constant, which means energy can only be converted and not made or destroyed.
In this process, the fuel is burned in the engine, releasing heat energy that is used to increase the temperature and pressure of the gases in the engine cylinder. The expanding gases then push a piston, converting the heat energy into mechanical work to turn the car's wheels.
Although some of the energy is lost to the environment as waste heat, the total energy of the system remains constant, demonstrating the first law of thermodynamics in action. This law is fundamental to understanding and predicting the behavior of energy in all physical and chemical systems, from power plants and engines to everyday processes such as cooking and exercising.
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Adding white to a color creates a shade. Adding black to a color produces a tint. TRUE OR False
False. Adding white to a color produces a tint, while adding black to a color creates a shade.
When we talk about colors, the terms “tint” and “shade” refer to specific changes in their appearance. Adding white to a color creates a tint. This happens because white is the lightest color and has the ability to lighten other colors. When white is mixed with a color, it increases the lightness and creates a paler version of that color. Tints are often associated with a softer and more delicate aesthetic.
On the other hand, adding black to a color creates a shade. Black is the darkest color and has the ability to darken other colors. When black is mixed with a color, it reduces the lightness and creates a darker version of that color. Shades tend to have a deeper, richer, and more intense appearance compared to the original color.
It's important to note that the terms “tint” and “shade” are specifically used when referring to the effects of adding white or black to a color. Other color-related terms such as tone, saturation, and hue describe different aspects of color manipulation.
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Car AMass: 1,500 kgVelocity: 10 m/sCar BMass: 1,500 kgVelocity: 25 m/sCar CMass: 1,000 kgVelocity: 10 m/sWhich order shows decreasing momentum?A, B, CB, A, CC, B, A
Answer:
B, A, C
Explanation:
The momentum is equal to the mass times the velocity, so for each car the momentum is equal to
Car A
Momentum = Mass x Velocity
Momentum = 1,500 kg x 10 m/s
Momentum = 15,000 kg m/s
Car B
Momentum = Mass x Velocity
Momentum = 1,500 kg x 25 m/s
Momentum = 37,500 kg m/s
Car C
Momentum = Mass x Velocity
Momentum = 1,000 kg x 10 m/s
Momentum = 10,000 kg m/s
Then, the decreasing momentum is B, A, C because
37,500 is greater than 15,000 and 15,000 is greater than 10,000
So, the answer:
B, A, C
A ball is thrown directly upward from a height 10 meters above the ground at time t = 0 (seconds). The location y(t) (in meters above the ground) of the ball at time t > 0 is given by y(t) = -2t² + t + 10. (a) Find the velocity of the object at time t.
(b) Find the acceleration of the object at time t.
(c) Find the velocity of the ball at the time when it hits the ground, i.e. the time t>0 when y(t) = 0. Hint: You could use the quadratic formula to find the value of t*.
(a) The velocity of the object at time t is given by finding the derivative of y (t):
y(t) = -2t2 + t + 10dy(t)/dt
= -4t + 1
Therefore, the velocity of the object at time t is -4t + 1.
(b) The acceleration of the object at time t is given by finding the derivative of the velocity function:
dy(t)/dt = -4t + 1d2y(t)/dt2
= -4
Therefore, the acceleration of the object at time t is -4 m/s2.
(c) The ball hits the ground when y(t) = 0, so we can solve for t by setting -2t2 + t + 10 = 0 and using the quadratic formula:
t = (-b ± (b2 - 4ac)) / (2a), where a = -2, b = 1, and c = 10.
Plugging these values into the formula, we get:
t = (-1 ± (12 - 4(-2)(10))) / (2(-2)) = (1 ± 81) / 4
We take the negative root because the positive root corresponds to the ball reaching its maximum height before falling back down. Thus,
t = (1 - 81) / 4
= -2/4
= -0.5 s
To find the velocity of the ball at this time, we plug t = -0.5 into the velocity function we found in part
(a):v = -4t + 1
= -4(-0.5) + 1
= 3 m/s
Therefore, the velocity of the ball at the time it hits the ground is 3 m/s.
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What is latent heat?
A.
energy released or absorbed to change the kinetic energy of a substance
B.
energy released or absorbed to change the pressure of a substance
C.
energy released or absorbed to change the temperature of a substance
D.
energy released or absorbed to change the phase of a substance
Which geologic events occur most often at this mid-oceanic ridge plate
boundary? *
2 points
Mid-oceanic ridge
plate boundary
Shelf
Sea level
Patella
Plate 2
Continental
crust
Rigid mantle
Asthenosphere
magnetic pole reversals and cooling of ocean water
hydrospheric pollution and adiabatic heating
earthquakes and volcanic eruptions
Answer: Earthquakes and Volcanic eruptions
Explanation:
You did not attach a picture however, this should be the correct answer.
Mid-oceanic ridge plate boundaries such as the Mid-Atlantic Ridge form as a result of plate separating at the boundary. This leads to earthquakes due to the forces of tension acting on the plates.
When this happens, the mantle is exposed and therefore there will be volcanic eruptions as the lava comes to the surface as magma. When this magma cools it creates new seafloors and underwater mountains.
Pravat exerts a force of 30 n to lift a bag of groceries 0.5 m. how much work did pravat do on the bag? note : work = force x distance 0 j 15 j 30 j 60 j
Answer:
he is right it’s D
Explanation:
if u could not read his hand writing