The percent by volume is 27.27%
if you put 10 ml mercury 20 ml water and 30 ml kerosene in a container what will it look like
The substances would look as follows;
Kerosene at the topWater at the middleMercury at the lowest layerHow would it look like?Let us recall that just like solids, the density of the solids is important in the determination of how the mixture of the substances would appear. The substances that are denser would tend to appear below while the substances that are less dense would tend to appear above.
Let us remind ourselves the densities of each of the substances as a hep to where we are going;
Water - 1 g/cm³
Mercury - 5.43 g/cm³
Kerosene - 0.82 g/cm³
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which of the following statements is true?
just look at the picture
c
Explanation:
compounds are combine from two or more elements
If NaCl has a mass of 3.2g, what is the volume of chlorine gas at STP?
Hey there!
Molar mass NaCl = 58.44 g/mol
58.44 g ----------------- 22.4 ( at STP )
3.2 g -------------------- Volume ??
Volume = ( 3.2 x 22.4 ) / 58.44
Volume = 71.68 / 58.44
Volume = 1.226 L
Hope this helps!
Answer:
V = 0.56 L
Explanation:
Given data:
Mass of NaCl = 3.2 g
Volume of chlorine gas = ?
Pressure and temperature = standard
Solution:
Chemical equation:
2NaCl → 2Na + Cl₂
Number of moles of NaCl:
Number of moles = mass/molar mass
Number of moles = 3.2 g/ 58.44 g/mol
Number of moles = 0.05 mol
Now we will compare the moles of NaCl with chlorine;
NaCl : Cl₂
2 : 1
0.05 : 1/2×0.05 = 0.025 mol
Volume of chlorine:
PV = nRT
V = nRT/P
V = 0.025 mol × 0.0821 atm.L/mol.K × 273 K / 1 atm
V = 0.56 L
How many moles of ammonia are needed to react completely with 3 moles of phosphoric acid
The number of moles of ammonia, NH₃ needed to react with 3 moles of phosphoric acid, H₃PO₄ is 9 moles
We'll begin by writing the balanced equation for the reaction. THis is illustratd below:
H₃PO₄ + 3NH₃ --> (NH₄)₃PO₄
From the balanced equation above,
1 mole of H₃PO₄ reacted with 3 moles of NH₃
How to determine the mole of NH₃ neededFrom the balanced equation above,
1 mole of H₃PO₄ reacted with 3 moles of NH₃
Therefore,
3 moles of H₃PO₄ will react with = 3 × 3 = 9 moles of NH₃
Thus, 9 moles of NH₃ is needed for the reaction
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Answer:
6
Explanation:
A 52gram sample of water that has an initial temperature of 10C absorbs 4130 joules. If the specific heat of water is 4.184 j what is the final temperature of the water?
A 52gram sample of water that has an initial temperature of 10C absorbs 4130 joules. If the specific heat of water is 4.184 j. 25°C is the final temperature of the water.
The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using several temperature scales, which traditionally drew on different reference locations.
The most popular scales include the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.
q = m×c×ΔT
4130 = 52×4.184×(T2- 10C)
T2= 25°C
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calculate the number of moles of chloride needed to form 14.0 moles of iron lll chloride. 2Fe+3Cl2=2FeCl3 ?
Explanation:
The reaction is
2Fe+3Cl2
→2FeCl3
So the mol ratio
Cl2÷FeCl3=3÷2
So for 14 mols of F
eCl3
we need 32×14=21
mols of Cl2
14. Which block in the periodic table contains the metalloids?
O A. p block
OB. s block
O C. d block
D. f block
Answer
the answer is p block
How much O2 could be produced from 2.59 g of KO2 and 4.56 g of CO2?
Answer:
This is a limiting reagent problem. the way to figure it out is to do the stoichiometry for each amount given, calculating the amount of Oxygen produced. The smallest amount is the answer because that reactant "ran out".
for KO2
2.49g KO2 x 1 mole KO2 x 3 mole O2 x 32.00 g O2 = 0.841 g O2
71.10 g KO2 4 mole KO2 1 mole O2
for CO2
4.44g CO2 x 1 mole CO2 x 3 mole O2 x 32.00g O2 = 4.84 g O2
44.01 g CO2 2 mole CO2 1 mole O2
Therefore the answer is 0.841g O2 since it is the smallest amount produced meaning KO2 is the limiting reagent.
If 62.1 grams of magnesium react with 100.0 grams of magnesium, how many grams of product are produced?
Which is the Limiting reactant?
Which is the Excess reactant?
How many grams of excess reactant remain?
pls help me with homework
The limiting and excess reactant can be obtained as follow:
2Mg + O₂ -> 2MgO
Molar mass of Mg = 24 g/molMass of Mg from the balanced equation = 2 × 24 = 48 g Molar mass of O₂ = 32 g/molMass of O₂ from the balanced equation = 1 × 32 = 32 gFrom the balanced equation above,
48 g of Mg reacted with 32 g of O₂
Therefore,
62.1 g of Mg will react with = (62.1 × 32) / 48 = 41.4 g of O₂
We can see from the above that only 41.4 g of O₂ is required to react completely with 62.1 g of Mg.
Thus, the limiting reactant is magnesium, Mg and the excess reactant is oxygen, O₂
How do i determine the mass of the excess reactant remaining?The mass of the excess reactant remaining can be obtained as shown below:
Mass of excess reactant, O₂ given = 100 gMass of excess reactant, O₂ that reacted = 41.4 gMass of excess reactant, O₂ remaining =?Mass of excess reactant remaining = Mass given - mass reacted
Mass of excess reactant remaining = 100 - 41.4
Mass of excess reactant remaining = 58.6 g
How do i determine the mass of product produced?The mass of H₂SO₄ produced can be obtained as illustrated below:
Mg + O₂ -> 2MgO
Molar mass of Mg = 24 g/molMass of Mg from the balanced equation = 2 × 24 = 48 g Molar mass of MgO = 40 g/molMass of MgO from the balanced equation = 2 × 40 = 80 gFrom the balanced equation above,
48 g of Mg reacted to produce 80 g of MgO
Therefore,
62.1 g of Mg will react to produce = (62.1 × 80) / 48 = 103.5 g of MgO
Thus, the mass of product, MgO produced is 103.5 g
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Complete question:
If 62.1 grams of magnesium react with 100.0 grams of oxygen, how many grams of product are produced?
Which is the Limiting reactant?
Which is the Excess reactant?
How many grams of excess reactant remain?
Use the dichotomous key below to identify the cell type.
Animal cell
Fungal cell
Bacterial cell
Plant cell
The dichotomous key is not given here, however, the correct dichotomous key is as follows:
step- 1a cell has a nucleus and organelles - go to step 2
1b cell has no nucleus or organelles - bacterial cell
step- 2a cell has a cell wall - go to step 3
2b cell has no cell wall - animal cell
step- 3a cell has chloroplasts - plant cell
3b cell has no chloroplasts - fungal cell
Using this dichotomous key the cell can be identified as - Fungal cell.
A dichotomous key is an essential scientific tool that is used to find out the various kinds of organisms on their observable traits. Dichotomous keys have a series of statements with two different choices in each step that will take the student or user to the correct identification.
Identification of the given cell:
1. Follow step 1.
If cells have a nucleus and organelles - yes then go to step 22. follow step 2.
2a. if cell has a cell wall - yes go to step 33. follow step 3.
3a. if cell has chloroplasts - no then fungal cellFungal cells have a nucleus and cell organelles enclosed with a cell wall around the plasma membrane but do not have chloroplast.
Thus, Using this dichotomous key the cell can be identified as - Fungal cell.
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Answer:
its a i took the test
Explanation:
PLEASE HELP! DUE TONIGHT!
A 42-g piece of metal was heated to 200 *C and placed in 100.0 g of water at 20 *C. in a calorimeter. The water's temperature rose to 31 *C. What is the specific heat of the metal?
A) 1.52 J/g*C
B) 0.452 J/g*C
C) 0.385 J/g*C
D) 0.648 J/g*C
Answer:d 0.648 J/g*C
Explanation:
-4602/(42.0g x -169)
Formula Q/m^t=C
How much heat (in joules) does it take to heat 180 g of water from 24 °C to 66 °C? The heat capacity of water is 4.184 J/(g · °C). You may round your answer to the nearest 100 J
Answer:31,631.04
Explanation: multiply final temp with initial temp = 42 then multiplied by grams = 7,560 then multiplied by J = 31,631.04
0.350g of an organic compound gave 100ml of Nitrogen collected at
250K temperature and 700mm pressure. Calculate the percentage
composition of Nitrogen in the compound.
Use Dumas method
The percentage composition of Nitrogen in the compound is 35.71%
How to determine the mole of nitrogenVolume (V) = 100 mL = 100 / 1000 = 0.1 LPressure (P) = 700 mmHg Temperature (T) = 250 KGas constant (R) = 62.364 torr.L/Kmol Number of mole (n) =?Using the ideal gas equation, the mole of nitrogen can be obtained as follow
PV = nRT
n = PV / RT
n = (700 × 0.1) / ( 62.364 × 250)
n = 0.00448 mole
How to determine the mass of nitrogenMole of nitrogen = 0.00448 moleMolar mass of nitrogen = 28 g/molMass of nitrogen = ?Mass = mole × molar mass
Mass of nitrogen = 0.00448 × 28
Mass of nitrogen = 0.125 g
How to determine the percentage of nitrogenMass of nitrogen = 0.125 gMass of compound = 0.35 gPercentage of nitrogen =?Percentage = (mass of element / mass of compound) × 100
Percentage of nitrogen = (0.125 / 0.35) × 100
Percentage of nitrogen = 35.71%
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Which part of the fuel cell does A represent?
O anode
O cathode
An unknown compound is analyzed gravimetrically and found to contain 77.6 ± 0.1 % of bromine. You know the initial compound could be the bromide salt of sodium, potassium or calcium. Determine the molecular formula of the initial unknown salt. Show your work.
I will will name brainliest to whoever answers quickly and correctly
An unknown compound is analyzed gravimetrically and found to contain 77.6 ± 0.1 % of bromine. Molecular formula is NaBr (sodium bromide)
This is further explained below.
What is the Molecular formula?Generally, Here given the 77.6+1-0.1 \%bromine Mass percentage of \($\mathrm{Br}$ in $\mathrm{NaBr}=\frac{79.9}{102.89} \times 100$\)
=0.776 *100
=77.6%
Therefore the mass percentage of Br in NaBr is 77.6 % matched with the given bromine mass percentage 77.6 \(\pm\)0.1 %
Mass percentage of
\($$\begin{aligned}\mathrm{Br} \text { in } \mathrm{KBr} &=\frac{79.9}{119} \times 100 \\&=0.671 \times 100 \\&=67.1 \%\end{aligned}$$\)
Mass percentage of Br in CaBr_2\(=\frac{159.8}{199.8} \times 100$$=79.9 \%$\)
Therefore, the mass % of B_r in k B r on d CaBr_2 is a hot match with the given mass % $77.6\(\pm\) 0.10%
Therefore, the Molecular formula of an unknown salt is NaBr
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According to the Foliated Metamorphic Rock Chart slate, phyllite, schist, and gneiss can all have the same parent rock (shale). If this is true, what determines the difference between a slate and a gneiss rock that both are formed from shale? What role does the parent rock play in determining the type of metamorphic rock that will be formed?
According to the Foliated Metamorphic Rock Chart slate, phyllite, schist, and gneiss can all have the same parent rock (shale) is a true statement.
The parent rock, in this case shale, plays a significant role in determining the type of metamorphic rock that will be formed. The minerals and structure of the parent rock provide the starting material for the metamorphic rock, and the specific conditions under which the rock undergoes metamorphism determine the final characteristics of the metamorphic rock.What determines the difference between a slate and a gneiss rock that both are formed from shale?Slate, phyllite, schist, and gneiss are all types of metamorphic rocks that can be formed from shale, which is a sedimentary rock composed of clay and other fine-grained minerals. The specific type of metamorphic rock that is formed from shale depends on the conditions under which the shale undergoes metamorphism, including the temperature, pressure, and presence of fluids.
Slate is a fine-grained metamorphic rock with a uniform, flat surface and a layered structure. It is formed when shale undergoes low-grade metamorphism, which occurs at relatively low temperatures and pressures.
Therefore, Gneiss, on the other hand, is a medium- to coarse-grained metamorphic rock with a banded or wavy texture. It is formed when shale undergoes high-grade metamorphism, which occurs at higher temperatures and pressures.
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Combustion of ethane gas is an exothermic reaction. Which of the following best describes the temperature conditions that are likely to make the combustion of ethane gas a spontaneous change?
A. Any temperature, because combustion of ethane leads to an increase in entropy.
B. Any temperature, because combustion of ethane leads to a decrease in entropy.
C. Low temperature only, because combustion of ethane leads to an increase in entropy.
D. High temperature only, because combustion of ethane leads to a decrease in entropy.
Conditions that are likely to make the combustion of ethane gas a spontaneous change are any temperature, because combustion of ethane leads to an increase in entropy. Hence the correct option is A.
When ethane undergoes combustion, it reacts with oxygen to produce carbon dioxide and water vapor, which are in a more disordered state than the initial reactants. This results in an increase in the overall entropy of the system, making the process spontaneous.
According to the second law of thermodynamics, a spontaneous process is one that leads to an increase in the entropy of the system and/or the surroundings.
Therefore, regardless of the temperature conditions, the combustion of ethane will always be a spontaneous change because it leads to an increase in entropy. Hence the correct option is A.
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Sort the numbers based on the number of significant figures they have.
Drag each tile to the correct location.
One Significant
Figure
Two Significant
Figures
Three Significant
Figures
Four Significant
Figures
Answer:
I think one significant figure??
the solubilites of some copper compounds are shown
which method is used to make copper sulfate
The mass of copper sulfate obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid is 50.27 grams.
The balanced chemical equation for the reaction between copper oxide and sulfuric acid is:
\(CuO + H_2SO_4\ - > CuSO_4 + H_2O\)
First, we need to calculate the number of moles of CuO:
n(CuO) = m/M = 25 g / 79.55 g/mol = 0.314 mol
Therefore, the number of moles \(CuSO_4\) produced is also 0.314 mol.
Finally, we can calculate mass \(CuSO_4\) produced:
m(\(CuSO_4\)) = n(\(CuSO_4\)) x M(\(CuSO_4\)) = 0.314 mol x 159.61 g/mol = 50.27 g
Therefore, assuming the reaction proceeds to completion, the mass of copper sulfate obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid is 50.27 grams.
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--The complete question is, What mass of copper sulfate can be obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid, assuming the reaction proceeds to completion?--
Which of the following is an example of an electric force acting at a distance?
Answer:
The electric force acting at a distance can be observed when someone rubs a glass rod with something woolen then the rod is taken away from the woolen material. The piece of paper leaps into air and sticks on to the rod. This is due to the electrostatic force of attraction that the paper sticks on the glass rod.
Explanation:
Answer:
Pam rubs a glass rod with wool, then moves the rod over a pile of small paper scraps. The scraps leap into the air and stick to the rod.
Discuss the large-scale environmental impacts of soil pollution caused by industrial wastes.
Answer: Industrial processes including mining and manufacturing historically have been leading causes of soil pollution. Industrial areas typically have much higher levels of trace elements and organic contaminants. This is due to intentional and unintentional releases from industrial processes directly into the environment, including to the soil, adjacent water bodies, and the atmosphere.
Explanation:
In an aqueous chloride solution cobalt(II) exists in equilibrium with the complex ion CoCl42-. Co2 (aq) is pink and CoCl42-(aq) is blue. At Low Temperature the pink color pre-dominates. At High Temperature the blue color is strong. If we represent the equilibrium as:
CoCl4^2-(aq) <--> Co2+(aq) + 4Cl-(aq)
We can conclude that:___.
1. This reaction is:___.
A. Exothermic
B. Endothermic
C. Neutral
2. When the temperature is decreased the equilibrium constant, K:____.
A. Increases
B. Decreases
C. Remains the same.
3. When the temperature is decreased the equilibrium concentration of Co2:______.
A. Increases
B. Decreases
C. Remains the same.
Answer:
1. This reaction is (A) Exothermic .
2. When the temperature is decreased the equilibrium constant, K: (A) Increases
3.When the temperature is decreased the equilibrium concentration of Co2: (A) Increases
Explanation:
\(CoCl4^2-(aq) <--> Co_2+(aq) + 4Cl^-(aq)\)
1. The pink color predominates at low temperatures, indicating that the commodity is preferred.
This is a reaction that is exothermic.
2. As the decrease in the temperature , the equilibrium constant , K ;
equilibrium constant = \(\frac{product}{reactant}\) =\(\frac{[CO^2^+][Cl^-^4]}{CoCl^2^-_4}\)
As the temperature drops, the concentration of\(Cl^-\) and \(CO^2^+\) rises, and K rises as well , thus it increases .
3. The equilibrium concentration of \(CO^2^+\) decreases as the temperature decreases:
When the temperature is lowered, the equilibrium shifts to the right , that is it increases.
A researcher is studying gold complexes. She makes
a 125 mL solution of gold(III) chloride by dissolving
0.144 moles of the solute into water. Which of the
following would cause the concentration of the
solution to increase?
Additional gold(III) chloride is added to the
beaker.
Part of the solution is poured into the chemical
waste.
O Water is added to the beaker.
We do not have enough information to answer
this question.
Additional gold(III) chloride is added to the beaker. This would cause the concentration of the solution to increase. Therefore, the correct option is option A.
Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass / unit volume is typically used.
The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume. Although concentration is typically used to describe chemical solutions, it may be computed for any mixture. Additional gold(III) chloride is added to the beaker. This would cause the concentration of the solution to increase.
Therefore, the correct option is option A.
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Heart, 5 stars, and Brainiest to first right answer!
Which layer of the atmosphere reflects radio waves back to Earth?
A. Mesosphere
B. Stratosphere
C. Thermosphere
D. Troposphere
Answer:
Thermosphere
Explanation:
More specifically the ionosphere, since the ionosphere is the lower part of the thermosphere.
Hope this helps!
what protect the contents of the nucleus
Answer:
The nucleus contains all of the genetic material for a eukaryotic cell, but this genetic material needs to be protected.
Explanation:
Hopes this helps
48 grams of MgCl2 is dissolved in 500g of water, DENSITY OF
WATER = 1 kg/1L. What is the MOLALITY of this solution? Please
show your steps.
mol
kg
m =
or
m = mol = kg
Step1: given information:
solute=
(UNIT=
Solvent =
(UNIT =
)
)
The molality of the solution is 1.080 mol/kg of a 48 grams of MgCl2 is dissolved in 500g of water, density of water = 1 kg/1L.
How to calculate molality?Taking the moles of solute and dividing it by the kilograms of solvent yields the molality of a solution.
Molality is calculated as follows: kg of solvent/kg of solute
500 g, or 0.500 kg, is the mass of the solvent.
MgCl2 molecular weight divided by its mass gives the amount of moles.
48 g / 95.2 g m o l 1 equals the quantity of moles of magnesium chloride.
0.504 moles of MgCl2 are present in one mole.
Molality is calculated as 0.504moles per kilogram.
Molality is equal to 1.080 mol k g 1.
As stated in the definition, molality is the "total moles of a solute contained in a kilogram of a solvent." The terms "molality" and "molal concentration" are synonymous. It is a measurement of a solvent.
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what is similar between emission like spectrum and absorption line spectrum?
what charge does sodium have ? Na
Answer:
+1
Explanation:
A sodium atom can lose its outer electron. It will still have 11 positive protons but only 10 negative electrons. So, the overall charge is +1.
Name a liquid substance that could be used in the laboratory for: dissolving dry mortar on floor tiles; (i) removing KMnO, stains; drying acid anhydrides
Explanation:
For dissolving dry mortar on floor tiles, you can use concrete and mortar dissolver. You can find this product at your local hardware store or online12.
For removing KMnO stains, you can use vinegar. Mix vinegar with water and spray or pour it on the tile surface. Let the vinegar water set in for a few minutes, then sponge the entire area to get it as clean as possible. Next, use a razor blade or scraper to peel up the mortar. Be careful not to gouge or scratch the tiles3.
KMnO is potassium permanganate. it makes water drinkable if it's polluted
For drying acid anhydrides, you can use calcium chloride. Calcium chloride is a hygroscopic substance that absorbs moisture from the air and can be used as a desiccant.
desiccants keeps things dry so they last longer like food & clothes
bingAI
1. Which has greater solubility: baking soda or table sugar? Why?
table sugar, because much more of it can be dissolved in water.
baking soda, because it makes a solvent bubble.
table sugar, because it makes a solvent sweet.
baking soda, because much more of it can be dissolved in water.